Chromium forms a crystalline solid with a body-centered cubic unit cell. The edge length of its unit cell is 291 pm. Calculate the density of chromium metal in g/cm^3.

a. 7.84 g/cm^3
b. 6.33 g/cm^3
c. 7.01 g/cm^3
d. 8.23 g/cm^3
e. 5.08 g/cm^3

Uniform circular motion is the most basic form of circular motion, in which an item moves in a circle while maintaining a constant speed.

Thus, Keep in mind that, unlike speed, the linear velocity of an object moving in a circle changes constantly since the item is always changing its direction and circular motion.

Kinematics has taught us that acceleration is a change in velocity, whether it be in speed, direction, or both. Because of this, even if the magnitude of an object moving uniformly in a circle accelerates constantly.

Every time a car rounds a corner, you personally experience this acceleration. When you make a turn while maintaining a constant speed, you are moving in a uniform circular motion.

Thus, Uniform circular motion is the most basic form of circular motion, in which an item moves in a circle while maintaining a constant speed.

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Answer:

b-  sediment

Explanation:

the remains of plants and animals are known as sediments. It can be as small as a grain of sand or as large as a boulder. Sediment moves from one place to another through the process of erosion.

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Answer:

First, we need to convert 0.750 g of lidocaine into milligrams (mg):

0.750 g = 750 mg

Next, we can calculate the total volume of the solution needed to administer 750 mg of lidocaine. Since each 150 mL of the solution contains 500 mg of lidocaine, we can set up the following proportion:

(750 mg) / (500 mg) = (x mL) / (150 mL)

Cross-multiplying:

500x = 750 * 150

500x = 112,500

x = 112,500 / 500

x = 225 mL

Now, we know that it will take 225 mL of the solution to administer 750 mg of lidocaine.

To find the time it takes to infuse 225 mL at a rate of 300 mL/hr, we can set up another proportion:

(225 mL) / (300 mL/hr) = (y min) / (60 min)

Cross-multiplying:

300y = 225 * 60

300y = 13,500

y = 13,500 / 300

y = 45 min

Therefore, it will take 45 minutes to administer 0.750 g (or 750 mg) of lidocaine at a rate of infusion of 300 mL/hr.

It will take approximately 75 minutes for 0.750 g of lidocaine to be administered through the IV at a rate of 300 mL/hr.

To calculate the time it takes to administer 0.750 g of lidocaine, we need to use the information provided.

Given:

Each 150 mL of the solution contains 500 mg of lidocaine.

The rate of infusion is set at 300 mL/hr.

First, we need to determine the amount of lidocaine administered per mL of the solution:

500 mg of lidocaine per 150 mL of solution = 500 mg / 150 mL ≈ 3.33 mg/mL

Next, we can convert the amount of lidocaine to be administered (0.750 g) to milligrams:

0.750 g * 1000 mg/g = 750 mg

Now, we can calculate the total volume of the solution needed to administer 750 mg of lidocaine:

750 mg / 3.33 mg/mL ≈ 225.23 mL

Finally, we can find the time it takes to administer 225.23 mL of the solution at a rate of 300 mL/hr.:

Time (in hours) = Volume (mL) / Rate (mL/hr.)

Time (in hours) = 225.23 mL / 300 mL/hr ≈ 0.75077 hr.

Converting hours to minutes:

Time (in minutes) ≈ 0.75077 hr * 60 min/hr ≈ 45.05 min

Therefore, it will take approximately 75 minutes for 0.750 g of lidocaine to be administered.

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Answer: physical

Explanation: you have not cooked them so nothing has happened

Mixing nuts and bananas and raisins without cooking them is a physical change.

WHAT IS A PHYSICAL CHANGE?

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The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Answer:

a. SOLUTION:

Step 1: Write the balanced chemical equation.

C₂H₄ + 3O₂ → 2CO₂ + 2H₂O

Step 2: Calculate the number of moles of CO₂ formed by each reactant.

• Using C₂H₄

Based on the balanced chemical equation, 1 mole of C₂H₄ is stoichiometrically equivalent to 2 moles of CO₂.

The molar mass of C₂H₄ is 28.054 g/mol.

• Using O₂

Based on the balanced chemical equation, 3 moles of O₂ is stoichiometrically equivalent to 2 mole of CO₂.

The molar mass of O₂ is 31.998 g/mol.

Step 3: Determine the limiting reagent.

Since O₂ produced less amount of CO₂ than C₂H₄, O₂ is the limiting reagent.

Step 4: Determine the mass of CO₂ formed.

Note that the (maximum) mass of a product that can be formed is dictated by the limiting reagent. In this case, we will start at the number of moles of CO₂ formed from the limiting reagent (O₂) which is equal to 0.11022 mol.

The molar mass of CO₂ is 44.009 g.

Hence, 4.85 g of CO₂ can be formed.

------------------------------------------------------------

b. ANSWER:

The LR is O₂ and the ER is C₂H₄.

------------------------------------------------------------

c. SOLUTION:

The theoretical yield of the reaction is 4.85 g.

Hence, the percent yield of the reaction is 87.6%.

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Explanation:

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1.Surround the area with absorbent material, then cover the spill.

2.Scoop up the material and place it in a container.

3.Place the bagged waste in a hazardous waste disposal container.

4.Wipe down the area with a suitable cleaning agent

proper liquid spill cleanup procedures are essential to minimize the risk of harm to individuals and the environment. The steps involved in the cleanup process include surrounding the area with absorbent material, covering the spill, scooping up the material and placing it in a container, and disposing of the hazardous waste container in accordance with local regulations. It is also important to clean and disinfect the container used to collect the spilled material, inspect the area to ensure no hazardous materials remain, train personnel on proper spill cleanup procedures, conduct periodic spill cleanup drills, and update the facility's emergency response plan to include spill cleanup procedures. By following these steps, individuals can ensure that liquid spills are handled safely and effectively.

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A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

A helium-filled balloon has a volume of 4.50 L when the temperature is 22.5 degrees C and the barometric pressure is 747.3 mmHg.

Barometric pressure is the measurement of air pressure in the atmosphere, specifically the measurement of the weight exerted by air molecules at a given point on Earth.

The pressure of the helium gas is the force that the gas exerts on the container boundaries, in this case, the balloon.

We know that the balloon’s volume is neither increasing nor decreasing. This means that the barometric pressure and the pressure of the helium gas are at equilibrium. That is, the pressure of the gas is 747.3 mmHg as well.

A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

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Answer:

Physical

Explanation:

No new substance is formed.

The process can be reversed using evaporation to separate the sugar from the water

So the change is physical

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Answer:

Explanations:

Given the length of copper sulfate expressed as 0.180 inches long. The question asked to convert the length to millimeters.

Using the conversion rate:

Answer: specialized body structures of Snakes

Explanation:

Snakes have many adaptations that allow them to move, hunt, eat and survive in their environments. Many animals have developed specific parts of the body adapted to survival in a certain environment. Among them are webbed feet, sharp claws, whiskers, sharp teeth, large beaks, wings, and hooves. In most aquatic animals, swimming is a must. To aid swimming, many animals have adapted and evolved with webbed feet.

Answer: Ancwer C or #3

Explanation:

Energy is transferred to an object when work(mechanics) is done on the object.  Work is the transfer of energy that occurs when a force is applied to an object that causes it to move some distance.  Notice that work(mechanics) is done on the object only if the object moves; if the object does not move, no work was done.  If you try to pick up the box of books, but are unable to lift it because it is too heavy, no matter how much effort you exert, you perform no work on the box and no energy is transferred.  

Answer:thing chang into different thing

Explanation:

Answer:

Positive charged

Explanation:

Answer:

Complex I:  (1) NADH-ubiquinone(NADH-coenzyme Q oxidoreductase), (8) Electron transfer from NADH to ubiquinone (coenzyme Q)

Complex II:  (3) Electron transfer from succinate to ubiquinone (coenzyme Q) (5) Succinate-coenzyme Q Oxidoreductase (succinate dehydrogenase)

Complex III:  (2) Coenzyme Q-cytochrome c oxidoreductase, (7) Electron transfer from ubiquinol (QH2) to cytochrome c

Complex IV: (4) Electron transfer from cytochrome c to O2, (6) Cytochrome c oxidase

Explanation:

The electron transport chain (ETC) in the mitochondria provides a pathway by which electrons are transferred from NADH and FADH₂ through a series of membrane-bound carriers to  molecular oxygen reducing it to water.

The electron transport chain electron carriers are organized into four complexes, Complexes I - IV.

Complex I : It is also called NADH:ubiquinone reductase. It transfers electrons from NADH to ubiquinone (also known as coenzyme Q)

Complex II : It is also called succinate dehydrogenase. It functions to tranfer electrons from succinate to FAD and then to ubiquinone.

Complex III : It is also called ubiquinone:cytochrome c oxidoreductase. It functions to transfer electrons from ubiquinol (reduced ubiquinone) to cytochrome c.

Complex IV : It is also called cytochrome oxidase. It functions to transfer electrons from cytochrome c to molecular oxygen reducing it to water.

The electron transporter chain is a series of enzymatic reactions to produce and store energy for the organism’s correct functioning. Complex I: 1 and 8. Complex II: 3 and 5. Complex III: 2 and 7. Complex IV: 4 and 6.

---------------------------------

Electron transporter chain

The electron transporter chain is located in the internal mitochondrial membrane. It constitutes a series of enzymatic reactions to release and save energy for the organism’s correct functioning.  

Along the chain, there are four proteinic complexes in the membrane, I, II, III, and IV, that contain the electrons transporters and the enzymes necessary to catalyze the electrons' transference from one complex to the other.  

Different redox reactions occur to pass electrons along the chain.  

Released energy creates a proton concentration gradient used to synthesize ATP.  

1)  NADH provides electrons to the first complex, Complex I (NADH-  

   ubiquinone or NADH-coenzyme Q oxidoreductase).

From there, electrons go to the coenzyme Q (Ubiquinone) that carries them to complex II and III. Meanwhile, complex I pomp four protons to the intermembrane space.  

2) Complex II (succinate-dehydrogenase) receives electrons from CoQ and also receives electrons from FADH2. Electrons are sent from complex II to ubiquinone Q that carries these electrons to complex III.

3) Complex III (Cytochrome C-reductase) receives electrons from ubiquinone Q and pomps protons to the intermembrane space.

Electrons are transferred to Cytochrome c.  

Electrons travel from cytochrome c to complex IV.

4) Complex IV (Cytochrome C-oxidase)  is the last complex that pomps protons to the intermembrane space. It takes electrons from cytochrome C and sends them to oxygen.

5) Electrons are sent to O₂ molecules, which also receive protons in the matrix to create water molecules.

Four electrons are needed to produce two water molecules from one O₂ molecule.  

The proton gradient is used to produce ATP molecules.

Now, we can join the complexes with the phrases.

Complex I:

1) NADH-ubiquinone (NADH-coenzyme Q oxidoreductase)

8) Electron transfer from NADH to ubiquinone (coenzyme Q)

Complex II:

3) Electron transfer from succinate to ubiquinone (coenzyme Q)

5) Succinate-coenzyme Q Oxidoreductase (succinate dehydrogenase)

Complex III:

2) Coenzyme Q - cytochrome c oxidoreductase

7) Electron transfer from ubiquinol (QH₂) to cytochrom c

Complex IV:

6) Cytochrome C oxidase

4) Electron transfer from cytochrome c to O₂

-----------------------------------

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Determining the exact time of death based solely on the condition of a body can be challenging and imprecise. However, several factors can provide some insight into the estimated time since death.

In the given scenario, the body has lost its nails and its tissues have died, indicating some level of decomposition.During mild temperatures in the spring, the rate of decomposition is typically faster compared to colder or hotter conditions. Under such circumstances, and assuming no significant external factors affecting decomposition (e.g., burial or covering), a rough estimate suggests that the person may have been deceased for several weeks to a few months.The loss of nails and tissue death suggest the progression of decomposition beyond the early stages. In the initial days following death, the body undergoes autolysis, where enzymes within the body's cells begin breaking them down.

This is followed by putrefaction, the breakdown of tissues by bacteria and other microorganisms. During putrefaction, nails and other keratinous structures can detach.However, it's important to note that various factors such as body size, health conditions, humidity, and exposure to insects and scavengers can influence the rate of decomposition. Therefore, the estimated time since death should be considered approximate, and a forensic examination conducted by professionals would provide a more accurate determination.

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The statement that is true:

Tastants are pleasant stimuli and odorants are unpleasant stimuli.

It is accurate to say that taste receptor cells can react to any flavor in any location of the tongue.

Chemicals dissolved in water or other liquids act as taste triggers. The four basic flavors of taste—sweet, sour, salty, and bitter—can be combined in a variety of ways to create all other taste sensations.

Whereas smell creates perceptions by stimulating receptors in the olfactory mucosa of the nose, taste creates perceptions by stimulating receptors in the tongue. The dominating sense we experience when eating or drinking is flavor, which is created when taste and smell work together.

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Answer:

Phosphorus

Explanation:

The volume in cubic centimeters is 25251.17cm³

Volume measures capacity. So the unit of volume is basically a unit for measuring the capacity or the extent of an object or space. The unit is mostly used to specify the volume of goods or a liquid (fluids).

In this problem, volume of the box is given by the formula:

V = l x w x h

Solving the problem

First, let us convert every dimension to centimeter.

l = 8.54 ft x 12 inches x 2.54 cm  = 260.29 cm

w = 0.0455 yd x 3ft  x 12 inch x 2.54 cm  = 4.16052cm

h = 9.18 in x 2.54 cm = 23.3172 cm

Now, we can solve for the volume of the box using the given formula above.

V = l x w x h

Then substitute the given data

V = (260.29 cm) x (4.16052 cm) x (23.3172 cm)

V = 25251.17cm³

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The volume of the gas at STP would be 23.93 liters.

The volume of gas at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature. First, we need to calculate the number of moles of gas in the initial sample. We can use the formula n = PV/RT, where P is the initial pressure, V is the initial volume, R is the gas constant, and T is the initial temperature.
n = (2.31 atm) x (25.15 L) / [(0.0821 L atm/mol K) x (201 + 273.15 K)]
n = 1.067 moles

Now, we can use the molar volume of gas at STP, which is 22.4 L/mol, to calculate the volume of gas at STP.
V = n x 22.4 L/mol
V = 1.067 moles x 22.4 L/mol
V = 23.93 L
Therefore, the volume of the gas at STP would be 23.93 liters.

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A mixture can be defined as a physical blend of two or more substances that are not chemically combined.

They retain their own properties and can be separated by physical means like filtration, distillation, evaporation, or magnetism. The various types of mixtures include homogeneous mixtures, heterogeneous mixtures, and colloids.Homogeneous mixtures, also known as solutions, are uniform mixtures where the composition is the same throughout. They are not visibly different and consist of a solute (the substance being dissolved) and a solvent (the substance doing the dissolving). For example, salt water is a homogeneous mixture because the salt is dissolved uniformly throughout the water.Heterogeneous mixtures are non-uniform mixtures that consist of two or more phases, each with its own distinct properties. They can be seen with the eye, and the different components can be separated using physical means. An example of a heterogeneous mixture is oil and water. They can be mixed together, but they will eventually separate.Colloids are mixtures where the particle size is intermediate between that of a solution and a suspension. The particles are small enough to not be visible to the eye, but they are large enough to scatter light. Milk is an example of a colloid because it appears homogeneous but is actually made up of small particles of fat and protein dispersed throughout the liquid.In conclusion, a mixture is a physical blend of two or more substances that are not chemically combined. They can be separated by physical means and consist of homogeneous mixtures, heterogeneous mixtures, and colloids.

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One measure of solubility is concentration in grams per liter concentration of copper(II) ions, in grams per liter, measured in a 0.200 L sample of water in which 0.00026 g of copper(II) ions are present is 0.0013 g/L means 1.3×10⁻³g/L

Concentration is defined as mass per unit volume

Here given data is

Volume = 0.200 L

Mass = 0.00026 g

We have to calculate concentration = ?

Concentration = mass/volume

Concentration =  0.00026 g/0.200 L

Concentration = 0.0013g/L = 1.3×10⁻³g/L

1.3×10⁻³g/L concentration of copper(II) ions, in grams per liter, measured in a 0.200 L sample of water in which 0.00026 g of copper(II) ions are present

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Answer:

0.521 moles still present in the container.

Explanation:

It is possible to answer this question by using the general gas law, that is:

PV = nRT

Where P represents pressure of the gas, v its volume, n moles, R gas constant law and T absolute temperature (21.7°C + 273.15 = 294.85K)

Replacing with values of the initial conditions of the container, its volume is:

V = nRT / P

V = 2.00mol*0.082atmL/molK*294.85K / 3.75atm

V = 12.9L

When some gas is released, absolute temperature is 28.1°C + 273.15 = 301.25K, the pressure is 0.998atm and the volume of the container still constant. Again, using general gas law:

PV / RT = n

0.998atm*12.9L / 0.082atmL/molK*301.25K = n

0.521 moles = n

Ideal gas law is the hypothetical equation in which the pressure, volume, and temperature of the gas are directly related. It can be denoted as:

PV = nRT

The number of moles still present in the container is 0.521.

The ideal gas law is:

PV = nRT

where,

P = Pressure

V = Volume

R = Gas constant

T =Temperature

n = moles

Given:

Moles in container = 2.00

Temperture = 294.85 K

Pressure = 3.75 atm

Volume =?

Substituting the values:

V = nRT/P

\(\text V&=\dfrac{2\times0.082 \times294}{3.75}\)

Volume = 12.9 L

Now, the condition when changed, such that temperature is 301.25 K, pressure is 0.998 atm, and Volume is 12.9 L, then moles will be equal to:

\(\begin{aligned}\dfrac{\text{PV}}{\text{RT}}&=\text n\\\\\dfrac{0.998 \times 12.9} {0.082 \times 301.25}&=\text n\end\)

n = 0.521 moles

Therefore, 0.521 moles is still present in the container.

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Answer: (A,B,D) [1, 2, 4]

Explanation:

Answer:

E = 7.11 × \(10^{-7}\)  Cal

Explanation:

given data

efficiency = 25 %

solution

first we get here E by the power that is express as

p = \(\frac{E}{t}\)     ...........1

E = p × t

E = 1 ×  2 × \(\frac{1hp}{746w} \times \frac{1hr}{3600 s}\)  

E = 7.447 × \(10^{-7}\) J

and

Ein is get by efficiency

Ein = \(\frac{Eout}{\eta }\)        ..................2

Ein = \(\frac{7.447 \times 10^{-7}}{.25 }\)

Ein = 29.788 × \(10^{-7}\)  J

so required energy is

E = 29.788 × \(10^{-7}\)  ×  \(\frac{1Cal}{4.184J}\)

E = 7.11 × \(10^{-7}\)  Cal

Answer:

Ratio = 2 : 3 (Approx.)

Explanation:

Given:

Compound A = 1.278 g

Compound B = 1.904

Find:

Ratio

Computation:

Ratio = Compound A / Compound B

Ratio = 1.278 / 1.904

Ratio = 2 : 3 (Approx.)

Answer

Therefore, an azimuth of 90° corresponds to a quarter of the way clockwise from 0° or 360°, which is east. Similarly, 180° is south, and 270° is west. You can get azimuths corresponding to NE, SE, SW and NW by adding or subtracting 45° to the appropriate N, E, S or W azimuth.Explanation: