Which term is a unit of concentration? Select all that apply.
A) liters
B) molarity
C) ppm
D) g/L

Answer:

c

Explanation:

kw=h+bls

The third law of thermodynamics describes the entropy of a: solid.

The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.

The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.

In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.

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The number of moles of the excess reactant that is left over is 0.37 moles

The excess reactant refers to the reactant that is present in a greater quantity than what is required for complete reaction with the other reactant(s). The other reactant is referred to as the limiting reactant.

Number of moles of P = 2.5 moles

Number of moles of bromine = 3.20 moles

We have that the stoichiometry gives that;

2 moles of P reacts with 3 moles of bromine

2.5 moles of P reacts with  2.5 * 3/2

= 3.75 moles

Hence bromine is the limiting reactant

If 2 moles of P reacts with 3 moles of bromine

x moles of P reacts with  3.20 moles of bromine

x = 2.13 moles

Moles of excess reactant left = 2.50 - 2.13 moles

= 0.37 moles

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The answer to the question is "d. Syn addition of hydrogen atoms in a concerted mechanism".

Explanation: Concerted mechanism is a type of reaction mechanism in which a reaction occurs in a single step. Dissolving metal reduction is an example of this type of reaction.Anti-addition is where the hydrogens are added from opposite sides of the double bond, resulting in a trans alkene. While Syn-addition is where both hydrogens are added from the same side of the double bond, resulting in a cis alkene.In this reaction, the syn-addition of hydrogen atoms in a concerted mechanism accounts for the stereochemical outcome of a dissolving metal reduction. It results in a syn-addition of hydrogen atoms across the double bond, which means that both hydrogen atoms add to the same side of the double bond and the product is a cis alkene.

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To determine whether the unknown carbohydrate substance is a monosaccharide or a polysaccharide, the most useful property for the scientist to investigate would be the molecular size and structure of the substance.

Monosaccharides are simple sugars with smaller molecular structures, while polysaccharides are larger and consist of multiple monosaccharide units bonded together.

The combination of two monosaccharides results in a disaccharide, which can be classified as a disaccharide.

These are created through the blending of sugars. Since water is released after the reaction is finished, the process is called hydrolysis.

The glycosidic linkage joins two monosachrrides together. Maltose, sucrose, and lactose are a few prevalent examples.

A big molecule's chemical link is broken by the water molecule in a hydrolysis reaction, resulting in the formation of smaller molecules.

Comparatively speaking, a disaccharide is a larger molecule than a monosaccharide. Or disaccharide is twice as big as monosaccharide in another world. In order to create two smaller monosaccharides, water and disaccharide must react during the hydrolysis process.

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Answer: Yellow

Explanation:

See attached table.

Answer:

Bean Plant

Explanation:

This is because a bean plant produces it's own food.

Based on the sequence provided (FWGALAKGALKLIPSLFS), the following residues are likely to be found on the nonpolar side of amino acid of the amphipathic helix: FWGALAKGALKLIPSLFS

The nonpolar amino acids are typically hydrophobic and tend to cluster together on one side of the helix. In this case, the nonpolar side of the helix is determined by examining the hydrophobic residues in the sequence.

From left to right, the residues on the nonpolar side are:

FWGALAKGALKLIPSLFS

Therefore, the nonpolar side of the amphipathic helix in Pandinin 2 includes the amino acids F, W, G, A, L, K, and L.

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Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of attachment to show what is being referred to in the question. However, the difference in elevation from two points on the same "plane" can be calculated by subtracting the total distance from where the measurement started to point C from the total distance from where the measurement started to point D. Both measurements must have started from the same origin (usually zero).

The autotrophs that have silica incorporated into their cell walls are diatoms. Option(D)

Diatoms are a type of microalgae found in both freshwater and marine environments. They have a unique external skeleton called a frustule, which is composed of silica.

The frustule provides structural support and protection to the diatom cell. Coccolithophorids, dinoflagellates, and radiolarians are other types of marine microorganisms but do not have silica in their cell walls.

Autotrophs are organisms capable of producing their own food using energy from sunlight (photosynthesis) or inorganic chemicals (chemosynthesis). They convert raw materials into organic compounds, serving as the primary producers in ecosystems.

Coccolithophorids are a group of single-celled algae found in marine environments. They are characterized by tiny calcified plates called coccoliths that cover their cell surface. These coccoliths play a role in carbon cycling and are significant contributors to marine sediment and biogeochemical processes.

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Explanation:

We have a 63.9 g sample of calcium hydroxide. First we have to convert those grams into moles. To do that we have to use the molar mass of calcium hydroxide.

Calcium hydroxide = Ca(OH)₂

molar mass of Ca = 40.08 g/mol

molar mass of O = 16.00 g/mol

molar mass of H = 1.01 g/mol

molar mass of Ca(OH)₂ = 1 * 40.08 g/mol + 2 * 16.00 g/mol + 2 * 1.01 g/mol

molar mass of Ca(OH)₂ = 74.10 g/mol

mass of Ca(OH)₂ = 63.9 g

moles of Ca(OH)₂ = 63.9 g /(74.10 g/mol)

moles of Ca(OH)₂ = 0.862 moles

In 1 molecule of Ca we have 2 atoms of O. So in 1 mol of Ca(OH)₂ we will have 2 moles of O atoms.

1 mol of Ca(OH)₂ = 2 moles of O atoms

moles of O atoms = 0.862 moles of Ca(OH)₂ * 2 moles of O /1 mol of Ca(OH)₂

moles of O atoms = 1.724 moles

One mol is similar to a dozen. When we say that we need a dozen eggs we know that we need 12 eggs. If we want a mol of eggs, we want 6.022*10^23 eggs. So one mol of something is 6.022 * 10^23 of that.

1 mol of O atoms = 6.022 * 10^23 atoms

n° of O atoms = 1.724 moles * 6.022 * 10^23 atoms/1 mol

n° of O atoms = 1.04 * 10^24 atoms

Answer: In a 63.9 g sample of Ca(OH)₂ we have 1.04 *10^24 atoms of oxygen.

Protons and neutrons are found in  nucleus part of an atom.

The nucleus or the center of an atom is made up of the protons and the neutrons. The number of the protons in the nucleus and it is  known as the atomic number. This primarily will determines where that atom will fits on the Periodic Table.

The nucleus is the small and the dense region that is consisting of the protons and the neutrons at the center of the atom. Protons are the type of the subatomic particle with the positive charge. Protons is bound together in the atom's nucleus as the result of the strong nuclear force.

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As there is no non polar bond in the given molecule, the answer is

(e) None of the above

Electronegativity is an elements affinity to receive electrons.

Some elements form compounds by sharing the number of electrons present. Such type of a bond is known as Covalent bonds.

The Covalent bonds are further divided into Polar and Non-Polar bonds. One can differentiate between polar and Non polar bonds on the basis of electronegativity of the elements.

In polar bonds there is an unequal sharing of electrons that is determined by the difference of the electronegativity of both the elements. If the difference then falls in the range of 0.4 to 1.7 it is considered a polar bond while non polar bonds have electronegativity difference of less than 0.4.    

On differentiating among the given options we get

(a) h2o : 3.5-2.1= 1.4

(b) nh3: 3.0-2.1= 0.9

(c) ph3: 2.1-2.1= 0

As there is no non polar bond in the given molecule, the answer is

(e) None of the above

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Answer:

The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Explanation:

yw <3

Answer:

energy cannot be created or destroyed. it is instead transferred from one form to another

Explanation:

The major organic product of the bimolecular substitution is (CH3)2CO-Na+ + I-. The curved-arrow notation shows the transfer of electrons from the negatively charged oxygen to the carbon, as well as the breaking of the C-O bond in the hydroxyl group, resulting in the leaving group (I-).

To draw the major organic product of the bimolecular substitution and the mechanism using curved-arrow notation, follow these steps:

Step 1: Draw curved arrows
Starting with the reactants: Na+ :O:, (CH3)2CHOH, and NaI, the first step involves the nucleophilic attack of the negatively charged oxygen on the carbon attached to the hydroxyl group in (CH3)2CHOH. The curved arrow starts from the lone pair of electrons on the oxygen and goes to the carbon atom. The second curved arrow starts from the bond between the carbon and oxygen of the hydroxyl group and goes to the oxygen, indicating that the bond is breaking and forming a leaving group (I-).

Step 2: Draw the product with electrons
As a result of the bimolecular substitution, the oxygen from the Na+ :O: will form a bond with the carbon, and the iodide will leave, forming the final product:

(CH3)2CO-Na+ + I-

Be sure to draw any non-bonding electrons on the oxygen and the leaving iodide ion.

In conclusion, the major organic product of the bimolecular substitution is (CH3)2CO-Na+ + I-. The curved-arrow notation shows the transfer of electrons from the negatively charged oxygen to the carbon, as well as the breaking of the C-O bond in the hydroxyl group, resulting in the leaving group (I-).

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The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the

Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.

James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.

This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.

Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.

Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.

In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.

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The correct answer about redox reaction is option (c). A reduced compound becomes oxidized only when it transfers an electron to an oxidized compound.

A redox reaction, commonly referred to as an oxidation-reduction reaction, is characterised by a change in the oxidation number of the substances involved in the process. A redox reaction often involves the reduction of one reactant while the oxidation of other reactants. During reduction, one molecule obtains electrons, causing its oxidation state (or number) to decrease, whilst another molecule loses electrons, causing its oxidation number to rise. Consequently, electrons are taken away from a substance during oxidation, whereas electrons are added to a substance during reduction. As a result, reduction results in an increase in the total number of electrons in a reaction, whereas oxidation results in a drop. When there is a redox reaction, also known as an oxidation-reduction reaction, a reduced compound only becomes oxidised when it loses or transfers an electron to an oxidised compound that gets reduced, while the reduced compound becomes oxidised after transferring an electron to an oxidised compound. Since there is a change in the number of electrons, this results in a change in the oxidation state of a substance (compound), with no change in the number of carbon.

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Answer:the plants received more sunlight

Explanation:

The balanced chemical equation for the neutralization reaction between sulfuric acid and potassium hydroxide is:

H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)

From the equation, we can see that one mole of sulfuric acid reacts with two moles of potassium hydroxide. Therefore, we need to calculate the number of moles of potassium hydroxide present in the 30.0 mL of 0.260 M solution:

0.260 mol/L x 0.0300 L = 0.00780 mol KOH

Since the stoichiometric ratio of sulfuric acid to potassium hydroxide is 1:2, we need twice as many moles of sulfuric acid to neutralize the potassium hydroxide:

2 x 0.00780 mol = 0.0156 mol H2SO4

Finally, we can calculate the volume of the 0.235 M sulfuric acid solution required to provide 0.0156 moles of H2SO4:

0.0156 mol / 0.235 mol/L = 0.0664 L = 66.4 mL

Therefore, 66.4 mL of the 0.235 M sulfuric acid solution is required to neutralize 30.0 mL of 0.260 M potassium hydroxide.

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Answer:

All, i think?

Explanation:

The rate of reaction is sped up with: higher reactant concentration, higher temperature, higher pressure, greater surface area, catalysts and when the reactants are in the same phase.

The change that wilL occur is that the the reaction shifts to the right (products) to produce fewer moles of gas.

option C is correct.

The balanced equation is:

\(51.8 kJ + H_2(g) + 12(g) = 2HI(g)\)

From the left, there are 1 mole of H2 gas and 1 mole of I2 gas, which gives a total of 2 moles of gas.

In the right,  there are 2 moles of HI gas.

We can tell that there are more moles of gas on the left side than on the right side by comparing the amount of moles on each side.

According to Le Chatelier's principle, a decrease in volume will favor the side with fewer moles of gas.

In our scenario, the reaction will shift to the right  to produce fewer moles of gas.

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Answer:

there is no change

Explanation:

acellus correct

Answer:

a. 2H2 + O2--> 2H2O

b. 2ZnS +3O2-->2ZnO +2SO2

Explanation:

a.

note:

(when you put coefficients before the elements or the compounds you should multiply it by each element and the number that's on its right...

so if it's 2H2O

that is 2xH2 which is 4 hydrogen atoms

and 2 x O which is 2 oxygen atoms )

......

on the left side of the equation

there are two atoms of oxygen

but on the right side there's only one atom

so in order to balance them you have to put 2 as a coefficient for H2O

H2+O2 ->2H2O

so now you have 2 hydrogen atoms on the left side and 4 on the right side

you put 2 as a coefficient for H2

and now

there's 4 hydrogen atoms on both sides

and 2 oxygen atoms on both sides

b.

you do the same here

ZnS + O2 -> ZnO + SO2

2 oxygen atoms ---> 3 oxygen atoms

ZnS + 2O2 -> ZnO + SO2

4 oxygen atoms ---> 3 oxygen atoms

ZnS + 2O2 -> 2ZnO + SO2

4 oxygen atoms ---> 4 oxygen atoms

but

1 Zn ---> 2Zn

2ZnS + 2O2 -> 2ZnO + SO2

2S --> 1S

2ZnS + 2O2 -> 2ZnO + 2SO2

2S--> 2S

but

4O---> 6O

2ZnS + 3O2 -> 2ZnO + 2SO2

The volume that the white power will take, given it has a density of 2.16 g/cm³ and a mass of 50 grams is 23.15 cm³

We understood that density is defined as mass per unit volume i.e

Density = mass / volume

If we make volume the subject, we shall have:

Density = mass / volume

Cross multiply

Density × volume = mass

Divide both sides by density

Volume = mass / density

With the above formula, we can obtain the volume of the pentane as follow:

Volume = mass / density

Volume of white powder = 50 / 2.16

Volume of white powder = 23.15 cm³

Thus, the volume of the white powder is 23.15 cm³

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The 68.4 grams of sucrose would be required to make 400 cm³ of a 0.500 molar (mol/L) sucrose solution.

To calculate the mass of sucrose required to make a specific volume and concentration of sucrose solution, we can use the formula:

Mass = Concentration × Volume × Molecular Weight

Concentration = 0.500 mol/L

Volume = 400 cm³

Molecular Weight of sucrose = 342 g/mol

First, we need to convert the volume from cm³ to liters:

Volume = 400 cm³ / 1000 cm³/L = 0.4 L

Now we can calculate the mass of sucrose required:

Mass = 0.500 mol/L × 0.4 L × 342 g/mol

Mass = 68.4 grams

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The partial pressure of gas B in the mixture of two gases is 4.60 atm.

The partial pressure of gas B can be calculated by subtracting the partial pressure of gas A from the total pressure of the mixture of gases.

Partial pressure of gas B = Total pressure of mixture of gases - Partial pressure of gas A

= 5.20 atm - 0.60 atm

= 4.60 atm

So, the partial pressure of gas B in the mixture of two gases is 4.60 atm.

The partial pressure of each gas in a mixture of gases is proportional to the concentration of that gas in the mixture. This relationship is described by Dalton's Law of Partial Pressures. The partial pressure of each gas is equal to the pressure that the gas would have if it were present alone in the container at the same temperature. The total pressure of the mixture of gases is equal to the sum of the partial pressures of the individual gases. So, when the partial pressure of gas A is known, the partial pressure of gas B can be calculated by subtracting the partial pressure of gas A from the total pressure of the mixture of gases.

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The value of Ka constant for acetic acid is 1.75 × 10⁻⁵.

Generally, the acid dissociation constant (Ka) is used to distinguish strong acids from weak acids. Strong acids generally have exceptionally high Ka values. The Ka value is obtained by looking at the equilibrium constant for the dissociation of the acid. The higher is the Ka, the more the acid dissociates into its ions.

Ka is defined as the acid dissociation constant whereas pKa is simply the -log of the constant Ka. Similarly, Kb is defined as the base dissociation constant, whereas pKb is the -log of the constant Kb.

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Moles of CO are produced when 2.0 moles C reacts is 14 mole

Moles is the SI unit of amount of substance of a specified elementary entity

Here given data is

2.0 moles C reacts

We have to find moles of CO are produced =?

So number of moles = mass of substances/mass of 1 mole

Number of moles = 28/2.0

Number of moles = 14 mole

14 mole of CO are produced when 2.0 moles C reacts

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