what do you get if you drop a grand piano down a mine shaft answers
According to the question, If you drop a grand piano down a mine shaft, you would get a flat note.
This humorous response plays on the double meaning of the word "note." In the context of music, a "flat note" refers to a musical tone that is lower in pitch than the corresponding natural note. However, in this context, the phrase "flat note" is used to suggest that the grand piano would be damaged or destroyed upon impact with the ground at the bottom of the mine shaft. It is a lighthearted play on words rather than a literal answer.
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What observational evidence supports the conclusion that most of the mass of the milky way is in the form of dark matter?.
Surprisingly fast orbital speeds of stars and gas clouds located far from the galactic center indicate that these objects are subject to gravitational influences.
What is gravitational effects?The moon is maintained in its orbit around Earth by gravity, as are the planets in their orbits around the sun. Ocean tides are a result of the moon's gravitational effect on the oceans. The stuff that stars and planets are comprised of is pulled together by gravity to form them.
involving or pertaining to the attraction between two masses: Ocean tides rise and fall due to the moon's gravitational pull. of or pertaining to a strong inclination or movement in the direction of something or someone: There has been a lot of research on why they gravitate toward destructive behavior.
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which of the following compounds has signals in its 13c nmr spectrum at 25.9 ppm (ch 3), 51.1 ppm (ch), 125.9 ppm (ch), 126.6 ppm (ch), 128.3 ppm (ch), and 148.5 ppm (c)?
To know which the following compounds has signals in its 13c nmr spectrum at 25.9 ppm (ch 3), 51.1 ppm (ch), 125.9 ppm (ch), 126.6 ppm (ch), 128.3 ppm (ch), and 148.5 ppm (c) is as follow:
The given carbon NMR spectrum consists of six signals, at the following chemical shifts: 25.9 ppm (CH3), 51.1 ppm (CH), 125.9 ppm (CH), 126.6 ppm (CH), 128.3 ppm (CH), and 148.5 ppm (C).
The possible organic compound that fits with these chemical shifts in carbon NMR spectrum is 2-chloro-4-methylpentane.
This is due to the protons, which are connected to sp3 carbons, have values between 20 and 50 ppm. 2-chloro-4-methylpentane has the following structure:
CH3- 25.9 ppm
CH- 51.1 ppm
CH2- 125.9 ppm
CH- 126.6 ppm
CH- 128.3 ppm
C- 148.5 ppm
Thus, 2-chloro-4-methylpentane has signals in its 13C NMR spectrum at 25.9 ppm (CH3), 51.1 ppm (CH), 125.9 ppm (CH), 126.6 ppm (CH), 128.3 ppm (CH), and 148.5 ppm (C).
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Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by dEdt=q2a26πϵ0c3 where c is the speed of light.Part AIf a proton with a kinetic energy of 5.0 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.530 m , what fraction of its energy does it radiate per second?(dE/dt)⋅1sE =
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
\(\frac{dE}{dt}\) = \(\frac{q^{2} a^{2} }{6\pi \epsilon_{o} c^{2} }\)
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
What is the frequency of a light wave if its wavelength is 4.70 x 10-7 meters?
A. 1.57 x 10-15 Hz
B. 1.57 x 10-8 Hz
O
C. 6.32 x 107 HZ
O
D. 6.38 x 1014 Hz
Answer:
6.38 * 10^14 Hz
Explanation:
Given that r is the radius of a conductor with resistivity p
a length L and a resistance of R, which of the following is
an equivalent expression to the ratio: p/m?
For a conductor with radius r, resistivity p, length L and resistance R; \([(R\pi r^2)/L]/m\) is an equivalent expression to the ratio \(p/m\).
What is resistance?Resistance refers to the property of a material or an object to resist the flow of electrical current through it. The given information about a conductor indicates that it has a radius r, a length L, and a resistance R.
The resistance R of the conductor can be expressed as:
\(R = (p*L)/A\)
where p is the resistivity of the conductor, L is the length of the conductor, and A is the cross-sectional area of the conductor given by:
\(A = \pi *r^2\)
Therefore,
\(R = (pL)/(\pi r^2)\)
Solving for p, we get:
\(p = (R\pi r^2)/L\)
We can now express the ratio p/m as:
\(p/m = [(R\pi r^2)/L]/m\)
where m is the mass of the conductor.
Since we do not have information about the mass of the conductor, we cannot simplify this expression any further.
Hence, \([(R\pi r^2)/L]/m\) is an equivalent expression to the ratio p/m.
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what happens to the molecules when carbon dioxide is heated
When the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.
CO2 → CO + O
This is the basic reaction expected to happen by carbon dioxide molecules are heated. However it may also disintegrate into C2, O2, C, etc.
Since heat is absorbed in this reaction, it is an example of endothermic reaction. In an exothermic reaction heat is released. These are the basic two types of chemical reactions on basis of heat.
Therefore, when the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.
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A dog is tied to a post in the ground by Alicia violet of 2 m if the dog runs at a concert velocity of 4M/S and a circle around the post find the dogss centripetal acceleration
Answer:
Centripetal acceleration = 8m/s²
Explanation:
Given the following data;
Radius, r = 2m
Velocity = 4m/s
To find the centripetal acceleration;
Centripetal acceleration = V²/r
Substituting into the equation, we have;
Centripetal acceleration = 4²/2
Centripetal acceleration = 16/2
Centripetal acceleration = 8m/s²
Therefore, the dog's centripetal acceleration is 8 meters per seconds square.
Wood frogs have camouflaged skin so they blend into the background very well.
They also have a layer of mucous on their skin so they can slip away from
predators. What type(s) of adaptations are these?
Answer:
Anti-predator adaptation.
Explanation:
Their habitat is the forest and woodland. Their way of life fits into the anti-predator adaptation but I'm not 100% sure that I'm correct.
Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 1.50 m/s2
The main answer to the problem is:T = m(g + a)where T is the tension force, m is the mass of the object, g is the acceleration due to gravity (9.8 m/s2) and a is the upward acceleration of the object (1.50 m/s2).
The tension force in a rope or cable is the force that is transmitted through the rope when a force is applied at one end of the rope. In this problem, the gymnast is climbing up the rope with an upward acceleration of magnitude 1.50 m/s2. We can use the equation T = m(g + a) to calculate the tension force in the rope
.To use the equation, we need to know the mass of the gymnast. Let's assume that the mass of the gymnast is 60 kg. We also know that the acceleration due to gravity is 9.8 m/s2.Substituting the values into the equation:T = m(g + a)T = 60 kg (9.8 m/s2 + 1.50 m/s2)T = 60 kg (11.3 m/s2)T = 678 NTherefore, the tension force in the rope is 678 N.
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a) How far did the vehicle travel in total?
I need help on how to count each distance please
The total distance travelled during the vehicle's journey as found from the speed-time graph is 6.125 m
V = d / t
V = ( u + v ) / 2
V = Average Speed
d = Distance
t = Time
u = Initial velocity
v = Final velocity
During the first 0.5 s, u = 0 and v = 1 m / s.
d = ( 0 + 1 ) * 0.5 / 2
d = 0.25 m
During the next 0.5 s, u and v are equal meaning constant velocity ( V = 1 m / s ).
d = 1 * 0.5
d = 0.5 m
During the next 1 s, u = 1 m / s and v = 1.5 m / s.
d = ( 1 + 1.5 ) * 1 / 2
d = 1.25 m
During the next 2.5 s, u and v are equal meaning constant velocity ( V = 1.5 m / s ).
d = 1.5 * 2.5
d = 3.75 m
During the next 0.5 s, u = 1.5 m / s and v = 0.
d = ( 1.5 + 0 ) * 0.5 / 2
d = 0.375 m
Total distance travelled is the sum of all the individual distances calculated.
Total distance travelled = 0.25 + 0.5 + 1.25 + 3.75 + 0.375
Total distance travelled = 6.125 m
Therefore, the total distance travelled during the vehicle's journey as found from the speed-time graph is 6.125 m
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An electron and a proton are held on an x axis, with the electron at x = + 1.000 m
and the proton at x = - 1.000 m . If a second electron is initially at x = + 20.00 m on the x axis and is given an initial velocity of 450 m/s towards the origin, will it reach and origin? And how close will it get to the origin if it doesn't?
Answer:
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Explanation:
For this exercise we must use conservation of energy
the electric potential energy is
U = \(k \frac{q_1q_2}{r_{12}}\)
for the proton at x = -1 m
U₁ =\(- k \frac{e^2 }{r+1}\)
for the electron at x = 1 m
U₂ = \(k \frac{e^2 }{r-1}\)
starting point.
Em₀ = K + U₁ + U₂
Em₀ = \(\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}\)
final point
Em_f = \(k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})\)
energy is conserved
Em₀ = Em_f
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})
\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²( \(\frac{2}{(r_2+1)(r_2-1)}\) )
we substitute the values
½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ \(- \frac{1}{20+1} + \frac{1}{20-1}\) ) = 9 109 (1.6 10-19) ²( \(\frac{2}{r_2^2 -1}\) )
2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( \(\frac{1}{r_2^2 -1}\) )
2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷ \(\frac{1}{r_2^2 -1}\)
\(\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}\)
r₂² -1 = (4.443 10⁸)⁻¹
r2 = \(\sqrt{1 + 2.25 10^{-9}}\)
r2 = 1 m
therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m
Use the picture to answer the question. Name at least three physical properties of the bowling ball.
Answer:
Density, Color, and Luster.
Explanation:
Density, describes how compact the matter is in a substance. A bowling ball is more dense than a beach ball. Color - Describes how light reflects off a substance. Luster - Describes how shiny a substance is.
Answer:
The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different shape. That is the physical properties of a bowling ball.
Explanation:
:)
What symbol is in the middle of the chemical equation?
an equal sign
an arrow
Answer:
the answer is An Arrow
5. The East Campus Provost decides to order a new rope for the flagpole. To find out what length of rope is needed, the provost observes that the pole casts a shadow 14.6 meters long. The angle the su
The length of the rope required for the flagpole is approximately 16.8 meters.
Let 'l' be the length of the rope required for the flagpole, 'h' be the height of the flagpole, and 'θ' be the angle between the flagpole and the ground. It is given that the shadow cast by the flagpole is 14.6 meters long. Hence, using trigonometry, we get:tan θ = h/ltan θ = (14.6/l)l = 14.6/tan θHere, θ = 55° (approx). Hence,l = 14.6/tan 55°= 16.8 meters (approx).Therefore, the length of the rope required for the flagpole is approximately 16.8 meters. The angle that the sun makes with the ground is 35 degrees since it is given that the pole casts a shadow 14.6 meters long.
Distance is measured in length. A quantity with the dimension distance is length in the International System of Units of Measurement. The majority of measurement systems have a base unit for length from which all other units are derived. The meter is the base unit for length in the International System of Units (SI).
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What is the name of the force that is acting upwards on the bag of bananas?
ANSWER- I GUESS IT SHOULD BE GRAVITATIONAL FORCE.......
Answer:
GRAVITATIONAL FORCE
9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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Select the correct answer.
Which outcome does the big crunch scenario predict?
A. the matter in the universe will slow the expansion to the pointwhere it would finally come to a halt and then start to retract
B. the universe will keep expanding and growing ever larger and galaxies will grow farther apart
C. the universe will finally extinguish itself with a violent expansion similar to the one with which it began
D. the gravity in the universe will grow very weak, resulting in the planets drifting into stars
Answer:
A. the matter in the universe will slow the expansion to the point where it would finally come to a halt and then start to retract
Explanation:
Answer:
the matter in the universe will slow the expansion to the point where it would finally come to a halt and then start to retract
Explanation:
Plato/Edmentum
Which of the following lines of reasoning involves proving a event occurs, and assuming
something about the mechanisms leading to that conclusion?
O productive reasoning
O inductive reasoning
O deductive reasoning
O reductive reasoning
Correct option is C, deductive reasoning involves proving a event occurs, and assuming something about the mechanisms leading to that conclusion.
Deductive reasoning -In deductive reasoning, a conclusion is drawn from the agreement of multiple premises that are frequently assumed to be true. Deductive reasoning is also referred to as top-down reasoning. Deductive reasoning is built on making logical assumptions and drawing conclusions from them.
It is predicated on a broad assertion or hypothesis that is assumed to be true (sometimes referred to as a premise). In order to arrive at a clear, logical conclusion, the premise is used. The if/then statement is a typical illustration. Deductive reasoning informs us that A Equals C if A = B and B = C.
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The arrow is pointing to sodium’s
number of neutrons.
chemical symbol
atomic mass
combined number of electrons and protons.
Answer atomic mass
Explanation:
i took the test and got 100
which of the following explains why positively charged potassium ions are attracted to the negatively charged interior of a cell?
The term that is defined as the entire set of surrounding parts of the world with which the user interacts is the user interface (UI).
The user interface encompasses all the elements and components that enable users to interact with a system, device, or application. It includes the visual, auditory, and tactile elements that facilitate communication and interaction between the user and the technology. The UI serves as the bridge between the user and the underlying system, allowing users to input commands, receive feedback, and access the functionality of the system.
The user interface can take various forms, including graphical user interfaces (GUIs), command-line interfaces (CLIs), voice-activated interfaces, touchscreens, and more. It involves the design and arrangement of buttons, menus, icons, text fields, and other interactive elements that enable users to navigate, input data, and perform tasks within the system.
The main purpose of a user interface is to create a user-friendly and intuitive environment that facilitates efficient and effective interaction. It should present information in a clear and organized manner, provide appropriate feedback to user actions, and ensure that users can easily access the desired features and functions of the system.
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Need help pls. It is for acellus
Answer:
The height of the water column = 1.62405\(\overline{30}\) × 10⁻¹ m
Explanation:
The air cavity in the Coke bottle = 0.220 m deep
The fundamental (frequency) it plays when water is added to shorten the column and it is blown across the top, f = 528 Hz
The given speed of sound in air, v = 343 m/s
We note that the air cavity in the coke bottle is equivalent to a tube closed at one end
The fundamental frequency for a tube closed at one end, 'f', is given as follows;
f = v/(4·L) = v/λ
Where;
L = The height of the water column
λ = The wavelength of the wave
∴ 4·L = v/f = (343 m/s)/(528 Hz) = 0.6496\(\overline{21}\) m
∴ L = 0.6496\(\overline{21}\) m/4 = 0.162405\(\overline{30}\) m
The height of the water column = 1.62405\(\overline{30}\) × 10⁻¹ m.
Answer:
0.058
Explanation:
got it right on acellus
You are carrying a 6.00 kg
bag at a height of 3.20 m
above the level floor of a 4.220
mlong room at a constant
velocity of 0.60 m s'. How
much work do you do on the
bag in moving across the
room?
OA. 247J
O B. 182J
Oc.0J
OD.
318 J
O E. 34J
Answer:
The answer is A) 247 J, which is the closest to the calculated value.
Explanation:
To calculate the work done on the bag, we need to use the formula:
work = force x distance x cos(theta)
where force is the weight of the bag (mg), distance is the length of the room, and theta is the angle between the force and the displacement (which is zero since the force and displacement are in the same direction).
First, let's calculate the force:
force = weight of the bag = mg = (6.00 kg) x (9.81 m/s^2) = 58.86 N
Next, let's calculate the distance:
distance = length of the room = 4.220 m
Now, we can calculate the work done:
work = (58.86 N) x (4.220 m) x cos(0) = 247.68 J
Please help!! I need this asap I will mark brainliest!!
Answer:
50N to the right
Explanation:
You would find net force by adding the 20 and the 30 together since they are being pushed to the same side (the right). Therefore, the answer will be 50N to the right.
People cut down a forest to build a housing development. Which of the following describes how this action will likely affect the water cycle for this region?
Hi there! So among the options, there are:
Organisms will lose their habitat
Groundwater in the area will be reduced
More wood will be available for building homes
Runoff will be reduced once the streets are paved
Think about it. This is asking how the water cycle will be affected.
It wouldn't have anything to do with organisms, this is about water. It wouldn't be involving wood, since we're talking about water.
A and C are no longer options.
The answer is B, Groundwater in the area will be reduced. It took me a bit on this one, too, since it's a bit tricky. I also got it right on my exam and I do FLVS, this is in Earth Space Science.
Have a lovely rest of your day!
I WILL GIVE BRAIN LIST PLS HELP
Answer:
C is corret answer okay
when using the pass technique with a fire extinguisher, how far should you stand from the flames?
When using the PASS technique with a fire extinguisher, it is important to ensure you stand far enough away from the flames in order to be safe. As a general rule, it is best to stand at least 8-10 feet away from the fire.
This is to ensure that you do not come too close to the heat or flames and to also ensure you are not in danger of being burned. Additionally, standing further away provides you with better access to the fire in terms of directing the extinguisher towards the source of the fire. When spraying the fire, make sure you keep the nozzle pointed towards the base of the fire.
This will ensure you are able to put the fire out quickly and effectively. Lastly, if the fire is too large or close, back away and wait for the fire department to arrive.
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what types of forces can move an object?
What does the law of conservation of energy state?
A. that energy cannot be created or destroyed B. that energy cannot be transformed from one form to another
C. that one form of energy cannot be transformed into two other forms at the same time
D. that energy can be created or destroyed only during energy transformations
Which type of wave can be transmitted through the vacuum of space
A)
sound waves
B)
radio waves
C)
pressure waves
D)
compression waves
Answer:
B
Explanation:
When they put astronauts into orbit how do they communicate through radio
Radio waves are a type of wave that can be transmitted through the vacuum of space option (B) radio waves are correct.
What is a sound wave?It is defined as the pressure waves when an object started to vibrate it produces sound and vibration which leads to causes a sound wave.
As we know,
Light and sound are the two types of energy that move in waves.
Sound travels as compression waves whereas light travels as transverse waves. A vacuum may be traversed by light waves.
The radio spectrum is thought to span from 3 kilohertz to 300 gigahertz. A transmitter produces a radio wave, which a receiver subsequently picks up.
Thus, radio waves are a type of wave that can be transmitted through the vacuum of space option (B) radio waves are correct.
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