Rita is adding 3 + (negative 8) + 1. She rewrites the expression as 3 + (negative 1) + 8.

What is Rita’s error?
PLEASE HURRY BECAUSE I'M ON A QUIZ

Answer:

x = 3/2 - 5y/4

Step-by-step explanation:

5y + 4x = 6

-5y             -5y

4x = 6-5y

/4     /4 /4

x = 6/4 - 5y/4

x = 3/2 - 5y/4

Move all terms that don't contain  x  to the right side and solve.

Answer:........

Step-by-step explanation:

Answer:

the answer to that is 2/20 or for the simplest form 1/10

Answer: 21=3x+9 hope i helped

Answer:

4 is his age

Step-by-step explanation:

Answer:

║∦║Hello :D║∦║

Your answer should be:

31.75%

Step-by-step explanation:

I hope this answered your question! :D

Answer:

0.32

Step-by-step explanation:

trust me

The probability for a data point is less than is 0.8413.

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

The mean(μ)=4

Standard deviation(σ)=1

(P<5)

From the figure, standard normal distribution curve probability which we have to find P<5

It is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

P(x=4)=x-μ/σ

=4-4/1=0

P(x=4)=50%

P(x<5)=P(x=4)+P(x=1)

=50%+34.13%

=0.8413

P(x<5)=0.8413

Therefore, the probability a data point is less than 5 is 0.8413.

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Answer:

sum of digit:2+1+4+4+6+7+6+5+4=39 . Which is not divisible by 9

The point is a solution to the system of linear equations is (3/4, 1/4).

A system of linear equations consists of two or more equations, each of which has two or more variables, all of which are taken into account concurrently. Any ordered pair that satisfies each equation separately is the solution to a system of two-variable linear equations.

Let the equation be

x + y = 1 ------(1)

3x - y = 3 ------(2)

Add equation (1) and (2), we get

x + y + 3x - y = 1 + 2

simplifying the equation, we get

⇒ 4x = 3

⇒ x = 3/4

Put x = 3/4 in equation (1), then

3/4 + y = 1

simplifying the equation

y = 1 - 3/4

y = 1/4

(x, y) = (3/4, 1/4)

The conclusion is that (3/4, 1/4) is the solution to the system of linear equations.

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The probability that a randomly selected carton has a puncture or a smashed corner is 0.05. This means that 5% of the cartons produced by the company will have either a puncture or a smashed corner.

To find the probability that a randomly selected carton has a puncture or a smashed corner, we can use the principle of inclusion-exclusion.

Let's denote the probability of a puncture as P(P), the probability of a smashed corner as P(S), and the probability of both a puncture and a smashed corner as P(P ∩ S).

Given:

P(P) = 10% = 0.10

P(S) = 8% = 0.08

P(P ∩ S) = 13% = 0.13

We can calculate the probability of a puncture or a smashed corner using the formula:

P(P ∪ S) = P(P) + P(S) - P(P ∩ S)

Substituting the values:

P(P ∪ S) = 0.10 + 0.08 - 0.13

Calculating:

P(P ∪ S) = 0.18 - 0.13

P(P ∪ S) = 0.05

Therefore, the probability that a randomly selected carton has a puncture or a smashed corner is 0.05.

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Answer:

x = 29

Step-by-step explanation:

The three angles add to 90 degrees

x+3  + x-1   + x+1 = 90

Combine like terms

3x +3 = 90

Subtract 3 from each side

3x+3-3 = 90-3

3x = 87

Divide by 3

3x/3 = 87-3

x = 29

Answer:

x = 29

Step-by-step explanation:

The 3 angles sum to 90° , that is

x + 3 + x - 1 + x + 1 = 90

3x + 3 = 90 (subtract 3 from both sides )

3x = 87 ( divide both sides by 3 )

x = 29

Answer:

$105

Step-by-step explanation:

0.30×150=45

150-45=105

The graphics tool used to help determine whether a process is in control or out of control is a. control chart.

A graphical tool used to help determine whether a process is in control or out of control is a control chart. A control chart is a chart used to monitor the stability of a process over time and to distinguish between common cause and special cause variation. It displays data points in relation to upper and lower control limits, which are calculated using statistical methods.

The control chart provides a visual representation of the process and enables users to identify trends, shifts, or other patterns that may indicate that the process is out of control.

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Answer:

true

Step-by-step explanation:

a parallelogram has 2 congruent consecutive sides then it is a square

The domain of the function f(x, y) = ln(6 − x^2 − 5y^2) is the set of all (x, y) pairs such that 6 − x^2 − 5y^2 is positive.

The natural logarithmic function ln is defined only for positive arguments. Therefore, for f(x, y) = ln(6 − x^2 − 5y^2) to be defined, the argument 6 − x^2 − 5y^2 must be positive.

To find the domain of the function, we solve the inequality:

6 − x^2 − 5y^2 > 0

Rearranging, we get:

x^2 + 5y^2 < 6

This is the equation of an ellipse centered at the origin with semi-axes lengths a = √6 and b = √(6/5). Therefore, the domain of f(x, y) is the interior of this ellipse. That is, the set of all (x, y) pairs such that x^2 + 5y^2 is less than 6. In interval notation, this can be written as:

{(x, y) | x^2 + 5y^2 < 6}

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It looks like given matrices are supposed to be

\(\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}\)

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

\(\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6\)

\(\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5\)

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

\(\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0\)

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

\(\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0\)

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

\(P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}\)

\(D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}\)

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

\(P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}\)

\(D = \begin{bmatrix}i&0\\0&i\end{bmatrix}\)

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

\(\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0\)

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

\(\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0\)

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

\(\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0\)

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

\(\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0\)

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

\(P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}\)

\(D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}\)

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

\(\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0\)

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

\(\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0\)

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

\(P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}\)

\(D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}\)

The cost of one computer is £600 and the cost of one printer is £800.

Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.

Let the cost of a computer be x and the cost of a printer be y.

Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)

4x + 5y = 6000 ---------------------- (2)

Solving equations (1) and (2) simultaneously:x = 600y = 800

Therefore, the cost of a computer is £600 and the cost of a printer is £800..

:Therefore, the cost of one computer is £600 and the cost of one printer is £800.

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The total number of pots will be 1¹/₄.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that at lunchtime, a cafeteria served a total of 3/8 of a pot of chicken soup and 7/8 of a pot of onion soup.

The total number of pots will be calculated as:-

E = 3/8 + 7/8

E = 10 / 8

E = 5 / 4

E = 1¹/₄

Hence, the total number of pots will be 1¹/₄.

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Answer:

Step-by-step explanation:

Answer:

0.03

Step-by-step explanation:

welcome

The derivative of 2x - 22 with respect to any variable (x, ws, wt) is 2, as it is a linear term and the derivative of a constant is 0. For the expression 3y + 2z, where y = st and z = s - t, the derivative with respect to ws is 3t + 2, and the derivative with respect to wt is 3s - 2.

This is because the derivatives are computed based on the given relationships between the variables

.For the derivatives, we need to differentiate each term with respect to the appropriate variables using the given relationships.

Let's break down each term:

1) 2x - 22:

The derivative of 2x with respect to x is 2 since it is a simple linear term.

The derivative of -22 with respect to any variable is 0 since it is a constant.

Therefore, the derivative of 2x - 22 with respect to x, ws, or wt is 2.

2) 3y + 2z:

Using the given relationships:

y = st

z = s - t

The derivative of 3y with respect to s is 3t since y = st and s is the only variable involved.

The derivative of 3y with respect to t is 3s since y = st and t is the only variable involved.

The derivative of 2z with respect to s is 2 since z = s - t, and s is the only variable involved.

The derivative of 2z with respect to t is -2 since z = s - t, and t is the only variable involved.

Therefore, the derivative of 3y + 2z with respect to ws is 3t + 2, and the derivative with respect to wt is 3s - 2.

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(a) No, the set of positive real numbers is not closed under division as there are cases where division of positive real numbers can result in a non-positive real number. (b) No, the set of negative real numbers is not closed under addition as adding two negative real numbers can result in a non-negative real number. (c) Yes.

(a) No. The set of positive real numbers is not closed under division. For example, if we take 2 and 3 as positive real numbers, the division 2/3 gives a result of 0.666... which is not a positive real number.

(b) No. The set of negative real numbers is not closed under addition. For example, if we take -2 and -3 as negative real numbers, their sum is -5, which is also a negative real number.

(c) Yes.

(d) No. The set {−1,0,1} is not closed under multiplication. For example, if we take -1 and 1 as elements of the set, their product is -1, which is not an element of the set.

Identifying the hypothesis and conclusion for each of the conditional statements:

(a) Hypothesis: r is a rational number and s is an irrational number.

Conclusion: r+3s is an irrational number.

(b) Hypothesis: d is a multiple of 8 or d is a multiple of 20.

Conclusion: d is a multiple of 4.

(c) Hypothesis: x is a multiple of 30.

Conclusion: x is a multiple of 5 and x is a multiple of 6.

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In a genogram, various symbols and lines represent different aspects of a person's familial relationships and attributes. Here's a breakdown of the symbols you mentioned:

1. Square: A square in a genogram indicates a male individual. It represents the person's gender and is used to distinguish between male and female family members.

2. Circle: A circle in a genogram indicates a female individual. It represents the person's gender and is used to distinguish between male and female family members.

3. Solid horizontal line: A solid horizontal line in a genogram represents a marital relationship between two individuals. The line connects a square (male) and a circle (female) to show that they are married or in a committed partnership.

4. Broken line: A broken line in a genogram represents a non-blood relationship, such as an adoptive parent-child relationship or a step-sibling connection. It is used to show relationships that are not based on biological ties.

5. X through a square/circle: An X through a square or a circle indicates that the individual is deceased. This symbol is used to show that the person has passed away and is no longer living.

6. Solid vertical line: A solid vertical line in a genogram represents a parent-child relationship. It connects an individual (either a square or circle) to their parent(s), showing the biological connection between the family members.

These symbols and lines help provide a visual representation of a person's family history and relationships, making it easier to analyze and understand the various connections within a family tree.

Overall, a genogram is a visual representation of a family tree that includes important information about relationships, health issues, and other relevant details. By understanding the various symbols and indicators used in a genogram, it is possible to gain a deeper understanding of family dynamics and relationships, as well as potential risk factors for various health conditions. As such, genograms are an important tool for healthcare providers, therapists, and other professionals working with individuals and families.

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The complete true mathematical statement is 4 4/5 + 3 2/3 < 8 1/2

From the question, we have the following parameters that can be used in our computation:

4 4/5 + 3 2/3 ________ 8 1/2

Evaluate the sum of the integer parts of the fractions

So, we have the following representation

7 4/5 + 2/3 ________ 8 1/2

Next, we take the LCM of 5 and 3 and evaluate the sum

This gives

7 (12 + 10)/15  ________ 8 1/2

Evaluate the sum of 12 and 10

So, we have

7 (22)/15  ________ 8 1/2

Simplify

7 + 1 7/15  ________ 8 1/2

Add 7 and 1

8 7/15  ________ 8 1/2

7/15 is less than 1/2

So, we have

8 7/15  < 8 1/2

Hence, the operator that completes the statement is <

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The Accounting Rate of Return (ARR) for the new expansion project is 44.95%. The Accounting Rate of Return for the project, given the data, is calculated below: The Accounting Rate of Return (ARR) is used by businesses to assess the profitability of a given investment.

The Accounting Rate of Return for the project, given the data, is calculated below: The Accounting Rate of Return (ARR) is used by businesses to assess the profitability of a given investment. ARR is calculated by dividing the average accounting profit (before tax and interest) by the average investment. It is also known as the average rate of return, which is the average net income of the investment over its life, divided by the amount of the initial investment. In other words, ARR is the profit per year, divided by the initial investment, expressed as a percentage. It helps businesses to identify the potential return of their investment and make better decisions about whether to pursue a project or not.

In the given question, Transload Pty Ltd, a haulage company, has tasked you with analyzing and evaluating a new expansion project’s profitability. To calculate the Accounting Rate of Return, the first step is to calculate the average accounting profit of the project. The average accounting profit is the sum of the cash inflows over the life of the project, minus the depreciation expense, divided by the life of the project. In this case, the life of the project is seven years. Using the figures given in the question, we can calculate the average accounting profit:

Year 1: R1 150 000

Year 2: R1 270 000

Year 3: R1 300 000

Year 4: R1 210 000

Year 5: R1 320 000

Year 6: R1 325 000

Year 7: R1 325 000

Total cash inflows over the life of the project = R9 900 000

Average accounting profit = (R9 900 000 - R857 142*) / 7

= R1 348 661*Depreciation:

R6 000 000 / 7 years = R857 142

The next step is to calculate the average investment for the project. In this case, the average investment is the initial investment minus the scrap value, divided by two. The scrap value is assumed to be zero in this case because it was not provided in the question.

Average investment = (R6 000 000 - 0) / 2= R3 000 000

Finally, the Accounting Rate of Return (ARR) can be calculated by dividing the average accounting profit by the average investment, expressed as a percentage:

ARR = (R1 348 661 / R3 000 000) x 100%

ARR = 44.95%

Therefore, the Accounting Rate of Return (ARR) for the new expansion project is 44.95%.

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Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

Given the problem:

Answer:

-20

Step-by-step explanation:

-5-5-5-5=-20

Answer:

Step-by-step explanation: