What is the slope of a line that passes through the points (13,0) and (-2,12) please help no links

The line plot, histogram, and box plot provide different visual representations of the reading time data. By analyzing these plots, we can observe the distribution and characteristics of the data, such as central tendency, spread, and outliers.

Line Plot:

A line plot displays data points on a number line, representing the frequency or count of each value.

In this case, the line plot will show the minutes spent reading on the x-axis and the count of students on the y-axis.

For the given data, the line plot will show 10, 20, 30, 40, and 60 on the x-axis, with the corresponding counts displayed above each value.

Histogram:

A histogram displays data distribution by dividing the range of values into intervals or bins and representing the frequency of values falling into each bin.

The histogram will have the minutes spent reading on the x-axis and the count or frequency of students on the y-axis.

The intervals will be 10-19, 20-29, 30-39, 40-49, and 50-59, with the last interval being 60+.

The height of each bar in the histogram will represent the number of students falling into each interval.

Box Plot:

A box plot (also known as a box-and-whisker plot) provides a visual representation of the distribution of data, including measures of central tendency and variability.

The box plot will show a horizontal line inside a box, with whiskers extending from the box, and possibly individual data points beyond the whiskers.

The box will represent the interquartile range (IQR), showing the middle 50% of the data.

The line within the box will represent the median value.

The whiskers will indicate the minimum and maximum values, excluding outliers.

By analyzing these plots, you can observe the central tendency, spread, and distribution of the reading time data. For example, you can identify any outliers, notice the most common reading durations, and observe any patterns or trends within the dataset.

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a. The interpretation of b = -0.150 is that for every increase of 1 unit in horsepower (x), the fuel efficiency (y) decreases

by 0.150 mpg.

b. 1. The model predicts that increasing the horsepower to 100 results in a fuel efficiency of 14 mpg.

2. A car with 100 horsepower is expected to have a fuel efficiency of 14 mpg, according to this model.

c. This result is not realistic because fuel efficiency cannot be negative.

d.  This indicates a moderately strong relationship between horsepower and fuel efficiency in the given data.

e. The se value of 3.0 in this context means that the typical difference between the observed fuel efficiency values and

the predicted fuel efficiency values from the model is about 3 mpg.

a. The interpretation of b = -0.150 is that for every increase of 1 unit in horsepower (x), the fuel efficiency (y) decreases

by 0.150 mpg. This indicates a negative relationship between horsepower and fuel efficiency.

b. Substituting x = 100 in the regression equation y = 29.0 - 0.150x, we get y = 29.0 - 0.150(100) = 29.0 - 15 = 14.0. This

means that a car with 100 horsepower is predicted to have a fuel efficiency of 14 mpg. Two interpretations of this

number could be:

1. The model predicts that increasing the horsepower to 100 results in a fuel efficiency of 14 mpg.

2. A car with 100 horsepower is expected to have a fuel efficiency of 14 mpg, according to this model.

c. Predicting efficiency for a car with a 300-horsepower engine would give: y = 29.0 - 0.150(300) = 29.0 - 45 = -16.0.

This result is not realistic because fuel efficiency cannot be negative. This might have occurred because the linear

regression model does not accurately represent the relationship between horsepower and fuel efficiency for very high

horsepower values or it might be due to the extrapolation beyond the range of the sample data.

d. The r2 value of 0.680 in this context means that 68% of the variability in fuel efficiency can be explained by the

horsepower variable. This indicates a moderately strong relationship between horsepower and fuel efficiency in the

given data.

e. The se value of 3.0 in this context means that the typical difference between the observed fuel efficiency values and

the predicted fuel efficiency values from the model is about 3 mpg. This gives us an idea of the accuracy of the model's

predictions.

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The length of the side of the square is given as follows:

20 cm.

In the figure, there are two expressions used to give the side length to each square, as follows:

In a square, all the four side lengths have the same length, hence the value of x is obtained as follows:

6x - 1 = 4x + 6

2x = 7

x = 3.5 cm.

Then the side length of the square is obtained as follows:

6(3.5) - 1 = 20 cm.

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Answer:

0.6522

Step-by-step explanation:

From the given information:

The probability of success i.e P(Success) = The probability of failure i.e. P(failure)

∴

P(Success) = P(failure) = 50% = 0.50

The probability P(additional information | successful) = 75%

The probability P(additional information | unsuccessful) = 40%

Hence, the probability that the bid will be successful = 0.5

The probability that the additional info| successful = 0.75

The probability that the bid will be successful provided that there is a request for additional information can be determined by using the Naive Bayes Theorem.

\(= \dfrac{P(success) *P(additional \ info \ | \ success) }{P(additional \ info)}\)

\(= \dfrac{0.5 \times 0.75}{(0.50 \times 0.75) +(0.50 \times 0.4)}\)

\(= \dfrac{15}{23}\)

\(\mathbf{= 0.6522}\)

Answer:

a=3, c=-4, x=8

Step-by-step explanation:

5=4a-7

4a-7=5

4a=5+7

=12

a=12÷4

=3

3-8c=35

-8c=35-3

=32

c=-32÷8

=-4

-1/2x-7=-11

-1/2x=-11+7

=-4

x=4÷1/2

=4/1×2/1

=8

Answer:

its the first one

Step-by-step explanation:

The value of a is 71°, and the value of b is 109°.

A parallel lines is defined as those type of line that are equidistant to each other which are on the same plane and they doesn't meet each other till infinity.

When two parallel lines are being intersected by another line called the transverse line, the following relationship is bound to occur such as;

From model 4, the pair of alternate exterior angles are equal in measure. That is 71° = angle opposite b°.

That is 180 - 71 = 109°

Also in model 4, the pair of alternate interior angles are equal in measure. a = 71°.

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Answer:

In order to answer this question, you have to import and attachment to be more clear

Answer:

BP =(0) while B = bacteria

P= population

BP is = 545

Answer:

Author's craft

Step-by-step explanation:

f dcsdfsxadszcdxsfaczdsadzxsaddesdxxedrdrdsqxd

The total resistance of the circuit is  1.313 x 10⁷ ohms.

We have,

The total resistance of the series circuit is the sum of all the resistance of the circuit.

The total resistance of the circuit is calculated by summing all the individual component of the circuit.

Rt = R₁   +  R₂     +   R₃

where;

R₁ is the first resistance = 5.6 MΩ

R₂ is the second resistance = ?

R₃ is the third resistance = ?

P = V²/Rt

where;

P is the power of the circuit

V is the voltage of the circuit

Rt is the total resistance

Rt  =  V²/P

Rt = (12 + 4.8)² / (21.5 x 10⁻⁶)

Rt = 1.313 x 10⁷ ohms

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complete question;

Can someone help me with this question with complete steps....thank you

attached

The perimeter of triangle will be Option c) 14.15 units .

Using distance formula between 2 points

Distance - Formula : The distance formula which is used to find the distance between two points in a two-dimensional plane is also known as the Euclidean distance formula.

d = \(\sqrt{(X1 - X2)^2 + (Y1 - Y2)^2}\)

Since , we have to find the perimeter of triangle , we will find the distance  from one vertex of triangle to the other for all the 3 sides and add them up .

Substituting values in the above formula ,

AB = \(\sqrt{5}\) units

BC = \(\sqrt{34}\) units

CA = \(\sqrt{37}\) units

Distance = AB + BC + CA = 14.15 units

Hence , the perimeter of triangle will be Option c) 14.15 units .

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The woman weighing 123 pound can take 1005.9 mg of medicine

An equation is an expression that shows the relationship between two or more numbers and variables using mathematical operations. An equation can be linear, quadratic, cubic and so on, depending on the degree of the variable.

If a 123 pound man can have 1213 mg of a medicine in a day. Hence:

Unit rate = 1213 mg / 123 pound = (1213/123) mg per pound

For a 102 pound:

Amount of medicine = (1213/123) mg per pound * 102 pound = 1005.9 mg

The woman can take 1005.9 mg of medicine

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Due to the symmetry of the paraboloid about the z-axis, you can treat this is a surface of revolution. Consider the curve \(y=x^2\), with \(1\le x\le2\), and revolve it about the y-axis. The area of the resulting surface is then

\(\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6\)

But perhaps you'd like the surface integral treatment. Parameterize the surface by

\(\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k\)

with \(1\le u\le2\) and \(0\le v\le2\pi\), where the third component follows from

\(z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2\)

Take the normal vector to the surface to be

\(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k\)

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

\(\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}\)

Then the area of the surface is

\(\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv\)

which reduces to the integral used in the surface-of-revolution setup.

a'' sec(2z) + b'' tan(2z) - 4c' sec(2z) - 4d' tan(2z) + 4a sec^2(2z) + 4b sec(2z)tan(2z) = 0  and c'' sec(2z) + d'' tan(2z) + 4a' sec are the required differential equation by variation of parameters.

a) The associated homogeneous differential equation is y" + 4y = 0. The characteristic equation is r{power}2 + 4 = 0, which has roots r = ±2i. Therefore, the general solution to the associated homogeneous differential equation is y_h = c1 cos(2z) + c2 sin(2z), where c1 and c2 are arbitrary constants.

b) To find a particular solution to the nonhomogeneous differential equation, we assume a solution of the form y_p = u1(z)cos(2z) + u2(z)sin(2z), where u1(z) and u2(z) are functions to be determined. Taking the first and second derivatives of y_p, we get:

y_p' = u1'(z)cos(2z) + u2'(z)sin(2z) - 2u1(z)sin(2z) + 2u2(z)cos(2z)

y_p'' = u1''(z)cos(2z) + u2''(z)sin(2z) - 4u1'(z)sin(2z) - 4u2'(z)cos(2z) - 4u1(z)cos(2z) + 4u2(z)sin(2z)

Substituting y_p, y_p', and y_p'' into the nonhomogeneous differential equation, we get:

u1''(z)cos(2z) + u2''(z)sin(2z) - 4u1'(z)sin(2z) - 4u2'(z)cos(2z) - 4u1(z)cos(2z) + 4u2(z)sin(2z) + 4(u1(z)cos(2z) + u2(z)sin(2z))sec(2z) = 0

Collecting like terms, we get:

(u1''(z) - 4u2'(z) + 4u1(z)sec(2z))cos(2z) + (u2''(z) + 4u1'(z) + 4u2(z)sec(2z))sin(2z) = 0

Since cos(2z) and sin(2z) are linearly independent, we must have:

u1''(z) - 4u2'(z) + 4u1(z)sec(2z) = 0

u2''(z) + 4u1'(z) + 4u2(z)sec(2z) = 0

To solve these equations, we can use the method of undetermined coefficients. We assume that u1(z) and u2(z) are linear combinations of sec(2z) and tan(2z), that is, u1(z) = a sec(2z) + b tan(2z) and u2(z) = c sec(2z) + d tan(2z), where a, b, c, and d are constants to be determined.

Substituting u1(z) and u2(z) into the equations above, we get:

a'' sec(2z) + b'' tan(2z) - 4c' sec(2z) - 4d' tan(2z) + 4a sec{power}2(2z) + 4b sec(2z)tan(2z) = 0

c'' sec(2z) + d'' tan(2z) + 4a' sec.

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Answer:

Wait...

Step-by-step explanation:

The value of x in the angles is 12 degrees

The figure that completes the question and the required parameters is added as an attachment

From the figure, we have the following parameters and angles

A = 5x - 15

B = 2x + 21

Also from the figure, we can see that the angles A and B are vertical angles

As a general rule, vertical angles have the same measure

This in other words mean that they are congruent angles

So, we have

A = B

Substitute the known values in the above equation

So, we have the following equation

5x - 15 = 2x + 21

Collect the like terms

5x - 2x = 15 + 21

Evaluate the like terms

3x = 36

Divide both sides by 3

x = 12

Hence, the solution of x in the lines is 12 degrees

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Step-by-step explanation:

5/6+1/4

3/12+10/12=13/12=

well You need to find number which can divide into six and four and the smallest to make finding It easy. 12 is the smallest

Answer:

1 1/12

Step-by-step explanation:

find lcm

lcm of 6,4 = 12

10+3/12

13/12

1 1/12

Answer:

300 km

Step-by-step explanation:

100 mm = 10 km

100 mm * 3 km

Answer:

$12.50

Step-by-step explanation:

take $250 and divide by 20

Each step of this theorem is proved below.

Given that,

S is finite,

Now enumerate all of its elements as x₁, x₂,..., x\(_{n}\).

According to the cancellation rule,

This product is independent of the order of the factors.

As a result, we can define the identity element e as this product.

It is simple to demonstrate that e meets the criteria of an identity element.

Now, let's show that every element of S has an inverse.

Let a be any element of S. Consider the set {a, a, a, ...}.

Since S is finite,

There exist positive integers m and n such that

am = an   for some m > n.

By the cancellation law,

We can cancel a power of a from both sides to get a\({(m-n)}\) = e.

This means that a has an inverse, and we can conclude that S is a group.

Consider the set of all positive integers under addition, except 1, as an example of an infinite semigroup in which the cancellation laws hold but which is not a group.

This set clearly meets the cancellation laws, but it does not have an inverse for every element, because the inverse of 2, for example, is not an integer.

As a result, this is not a group.

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Answer:

\(x=\frac{37}{6} \\\)

Step-by-step explanation:

Since A and b are complimentary angles There sum is equal to 90°

In other words:

We know A = (7x+18)  and b = (5x-12)

Next, insert these values into the equation (A+ b = 90°):

\((7x+18) + (5x-12)=90\)

Drop the () since we are not multiplying anything

\(7x+18 + 5x-12=90\)

Combine like terms: 7x and 5x, 18 and-12

\(7x +5x +18-12=90\\\\12x+ 16=90\\\)

Subtract 16 from both sides of the equation

\(12x=74\\\)

Divide by 12 and get:

\(x=\frac{37}{6} \\\) or \(x=6.16666...\)

Hope this helps :)

Answer: C

Step-by-step explanation:132/6=22

Answer:

Step-by-step explanation:

132-6t=0

-6t=-132

t=22 minutes

Answer:

Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

Answer:

false

Step-by-step explanation:

The Incircle, Circumcircle, and Centroid of a triangle are the three points which define a triangle, each with its own unique properties. In this case, we are looking for the area of a triangle whose vertices are the incenter, circumcenter, and centroid of our original triangle.

To find the area of this triangle, we will use Heron's Formula. This formula allows us to calculate the area of a triangle given its three side lengths. The three side lengths of our triangle are 13, 14, and 15. We can plug these values into Heron's Formula to find the area of our triangle.

The area of our triangle is approximately 54.47 units squared. This means that the area of our triangle, whose vertices are the incenter, circumcenter, and centroid of the original triangle, is 54.47 units squared. This can be verified by plugging in the side lengths into Heron's Formula and solving for the area.

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9514 1404 393

Answer:

Step-by-step explanation:

The given parallel lines mean that the two triangles are similar:

  ∆FDE ~ ∆FLK

That means corresponding sides are proportional.

  FE/FK = ED/KL

  FE = FK(ED/KL) = 4(15/6) = 10

and

  FL/FD = KL/ED

  FL = FD·KL/ED = 12(6/15) = 12(2/5) = 4.8

_____

Additional comment

Each of the diagonal lines, LD and KE, can be considered to be transversals between the parallel lines DE and KL. This means the interior angles at either end of those diagonals will be congruent. Hence the triangles are similar by the AA postulate.