what is the answer please helppp​

Answer:

The answer is 18

Step-by-step explanation:

4050/225 = 18

Therefore 4050/18 = 225

Step-by-step explanation:

Let,

According to the question,

→ Money received by Jan = $200

→ 4x = $200

→ x = $200 ÷ 4

→ x = 50 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀… ( 1 )

Now,

→ Money received by Jane = 9x

→ Money received by Jane = 9($50)

→ Money received by Jane = $450 [Ans]

And,

→ Money received by Jello = 6x

→ Money received by Jello = 6($50)

→ Money received by Jello = $300 [Ans]

Answer:

Step-by-step explanation:

Remember PEMDAS

2 - 8 : (2^4 : 2) =

2 - 8 : (16 : 2) =

2 - 8 : 8 =

2 - 1 =

Answer:

66mm

Step-by-step explanation:

The circumference of a circle is given by

C =2 pi r

  22/7 * 2( 10.5)

  22/7 * 21

  66

The number of bricks needed to cover the patio is approximately 1811 bricks.

To find the number of bricks needed for the patio in the English system, we follow these steps:

Step 1: Find the total width and length of the patio in inches.

Convert the width and length in meters to inches:

Width: 5 m = 5 x 39.37 = 196.85 in.

Length: 6 m = 6 x 39.37 = 236.22 in.

Add these values to the portion of the width and length of the patio expressed in inches to find totals:

Total width: 196.85 in. + 16 in. = 212.85 in.

Total length: 236.22 in. + 19 in. = 255.22 in.

Step 2: Find the area of each brick in square inches.

Multiply its width by its length:

Brick area: 3.75 in. x 8 in. = 30 in².

Step 3: Find the number of bricks needed by dividing the patio area by the brick area (round up to the nearest whole brick):

Patio area: 212.85 in. x 255.22 in. = 54,318.837 in².

Number of bricks needed: 54,318.837 in² / 30 in² ≈ 1810.63 bricks.

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The graph of line a and line b is shown in the image attached below. The lines do not intersect each other.

To check if both lines intersect, we need to graph the system of equations. First, use the points given to write out the equations.

Line a:

Slope (m) = change in y / change in x = 6 - 4 / 8 - 0 = 2/8

m = 1/4

Find the y-intercept (b) by substituting m = 1/4, x = 0 and y = 4 into y = mx + b:

4 = 1/4(0) + b

b = 4

The equation of line a is: y = 1/4x + 4.

Line b:

Slope (m) = change in y / change in x = 1 - (-2) / 8 - 0

m = 3/8

Find the y-intercept (b) by substituting m = 3/8, x = 0 and y = -2 into y = mx + b:

-2 = 3/8(0) + b

b = -2

The equation of line b is: y = 3/8x - 2.

Both lines are graphed in the image attached below. Line a is the red line and line b is the red line. They do not intersect at any point.

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Answer:

hese prime numbers are 2,3,5,7,11,13,17. To find the prime factorisation of 24, check if 2 divides into 24. It does, because 24=12*2

Step-by-step explanation:

The right triangle in marked question number 3 have the value of u = 2 and v = √2 using the trigonometric ratio of sine and cosine of the angle 45°.

The trigonometric ratios involves the relationship of an angle of a right-angled triangle to ratios of two side lengths. Basic trigonometric ratios includes; sine cosine and tangent.

Considering the angle 45° for the right triangle, recall that sin 45° and cos 45° are generally both equal to √2/2

sin 45° = √2/u {opposite/hypotenuse}

√2/2 = √2/u

u = √2/√2 × 2 {cross multiplication}

u = 2

cos 45° = v/u {adjacent/hypotenuse}

√2/2 = v/2

v = 2/2 × √2

v = √2

Therefore, the value of u = 2 and that of n = 10, using the trigonometric ratio of sine and cosine of the angle 45° for the right triangle.

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Answer: 12.4 + 1.1x + 2.2x^2 + 2.3x^3

Step-by-step explanation:

add the like variables

Answer:

4777

Step-by-step explanation:

Answer:

3. m∠1 = 106° ~ this is because ∠1 and ∠2 together make a straight line and are therefore supplementary, meaning added together, they equal 180° (so I did 180° - 74° = 106°)

4. m∠3 = 74° ~ again, it is supplementary to ∠1. It is also equal to ∠2

5. m∠8 = 114° ~ angles opposite of each other (like 1 and 4) are equal (as we know from question 4). From there, we can use the corresponding angle theorem, so we know 4 and 8 are congruent. (also you can just know 1 and 8 are congruent by using the opposite exterior angles theorem)

6. m∠6 = 124° ~ using same-side interior angle theorem, they are supplementary angles (or the corresponding angles theorem mentioned above, make 4 congruent to 8, and 8 is supplementary to 6)

7. m∠7 = 96° ~ using same side exterior angle theorem, these angles are supplementary

8. m∠2 = 64° ~ again, same side exterior angle theorem

Answer:

D

Step-by-step explanation:

To find a decimal, you need to divide the numerator by the denominator.  

Based on the given data, we can calculate the control limits using 3-sigma for the diameter of the auto pistons.

a) The value of x is 155.56 mm (rounded to two decimal places).

b) The value of R is 4.44 mm (rounded to two decimal places).

c) Using 3-sigma, the Upper Control Limit (UCL) for the diameter is calculated as:

UCL = x + 3R = 155.56 + 34.44 = 156.93 mm (rounded to two decimal places)

The Lower Control Limit (LCL) for the diameter is calculated as:

LCL = x - 3R = 155.56 - 34.44 = 154.19 mm (rounded to two decimal places)

d) Using 3-sigma, the Upper Control Limit for the Range (UCLR) is calculated as:

UCLR = D4 * R = 2.115 * 4.44 = 7.89 mm (rounded to two decimal places)

The Lower Control Limit for the Range (LCLR) is always 0 in this case since negative ranges are not possible.

e) If the true diameter mean should be 155 mm, the new centerline (nominal line) would be 155 mm. In this case, the UCL and LCL would be calculated using 3-sigma as follows:

UCL = Nominal + 3R = 155 + 34.44 = 156.37 mm (rounded to two decimal places)

LCL = Nominal - 3R = 155 - 34.44 = 153.63 mm (rounded to two decimal places)

Please note that the control limits calculated using 3-sigma assume a normal distribution and the data follows the same pattern in the future.

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The complete question is:

What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R= 4.44 mm (round your response to two decimal places). c) What are the UCL, and LCL; using 3-sigma? Upper Control Limit (UCL) = 156.93 mm (round your response to two decimal places). Lower Control Limit (LCL) = 154.19 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCLR)= 7.89 mm (round your response to two decimal places). Lower Control Limit (LCLR)= 0.99 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want this as your center (nominal) line, what are the new UCL and LCL? Upper Control Limit (UCL)= 156.37 mm (round your response to two decimal places). Lower Control Limit (LCL;)= 153.63 mm (round your response to two decimal places). Refer to Table 56.1-Factors for Computing Control Chart Limits (3 sigma) for this problem Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day 1 2 3 4 5 Mean x (mm) 150.9 153.2 153.6 153.5 154.6 Range R (mm) 4.0 4.8 4.1 4.8 4.5

Answer:

7

Step-by-step explanation:

double the other angle 55 * 2 = 110

360 - 110 = 250 subtract from full circle of degrees

250/2 = 125 divide remainder by two

18x - 1 = 125

x = 7

Therefore, the area between the large loop and the small loop of the curve r = 2 + 4cos(3θ) is 70π/3.

To find the area between the large loop and the small loop of the curve, we need to find the points of intersection of the curve with itself.

Setting the equation of the curve equal to itself, we have:

2 + 4cos(3θ) = 2 + 4cos(3(θ + π))

Simplifying and solving for θ, we get:

cos(3θ) = -cos(3θ + 3π)

cos(3θ) + cos(3θ + 3π) = 0

Using the sum to product formula, we get:

2cos(3θ + 3π/2)cos(3π/2) = 0

cos(3θ + 3π/2) = 0

3θ + 3π/2 = π/2, 3π/2, 5π/2, 7π/2, ...

Solving for θ, we get:

θ = -π/6, -π/18, π/6, π/2, 5π/6, 7π/6, 3π/2, 11π/6

We can see that there are two small loops between θ = -π/6 and π/6, and two large loops between θ = π/6 and π/2, and between θ = 5π/6 and 7π/6.

To find the area between the large loop and the small loop, we need to integrate the area between the curve and the x-axis from θ = -π/6 to π/6, and subtract the area between the curve and the x-axis from θ = π/6 to π/2, and from θ = 5π/6 to 7π/6.

Using the formula for the area enclosed by a polar curve, we have:

A = 1/2 ∫[a,b] (r(θ))^2 dθ

where a and b are the angles of intersection.

For the small loops, we have:

A1 = 1/2 ∫[-π/6,π/6] (2 + 4cos(3θ))^2 dθ

Using trigonometric identities, we can simplify this to:

A1 = 1/2 ∫[-π/6,π/6] 20 + 16cos(6θ) + 8cos(3θ) dθ

Evaluating the integral, we get:

A1 = 10π/3

For the large loops, we have:

A2 = 1/2 (∫[π/6,π/2] (2 + 4cos(3θ))^2 dθ + ∫[5π/6,7π/6] (2 + 4cos(3θ))^2 dθ)

Using the same trigonometric identities, we can simplify this to:

A2 = 1/2 (∫[π/6,π/2] 20 + 16cos(6θ) + 8cos(3θ) dθ + ∫[5π/6,7π/6] 20 + 16cos(6θ) + 8cos(3θ) dθ)

Evaluating the integrals, we get:

A2 = 80π/3

Therefore, the area between the large loop and the small loop of the curve r = 2 + 4cos(3θ) is:

A = A2 - A1 = (80π/3) - (10π/3) = 70π/3

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Answer:

If it is parallel:m parallel line=m line given, so:

mparallel=3/4

And it passes through one point given, so we use the formula: y-y0=m(x-x0)

so: y-36=3/4(x+12)

y=3/4x+9+36

y=3/4x+45 is the correct answer.

According to the given figure, minor arc RS, diameter RT, chord PS, central angle QTR, major arc QRS, semicircle QRP, and radius RT

What is a major and minor arc?

An arc is a portion of the circumference of a circle. It is a curve that connects two points on the circumference.  A major arc is an arc that measures more than 180 degrees, which is greater than a semi-circle. It covers more than half of the circumference of the circle. A minor arc is an arc that measures less than 180 degrees, which is less than a semi-circle. It covers less than half of the circumference of the circle.

If the angle formed by the two points and the center is less than 180 degrees, then it is a minor arc. Conversely, if the angle formed is greater than 180 degrees, then it is a major arc.

In summary, a major arc covers more than half of the circumference of the circle and measures more than 180 degrees. A minor arc covers less than half of the circumference of the circle and measures less than 180 degrees.

1. Minor arc RS

2. Diameter RT

3. Chord PS

4. Central angle QTR

5. Major arc QRS

6. Semicircle QRP

7. Radius RT

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The density of the material of mass 200 g and volume 10.4 ml is 19.2 g/ml.

According to the question,

We have the following information:

Density is defined as the mass per unit volume.

So, we have the formula of density:

Density = Mass/volume

Mass of the metal object = 200 g

Volume of the metal object = 10.4 ml

Density = 200/10.4 g/ml

Density = 19.231 g/ml

Now, we will round it off to nearest 1 decimal point.

We know that when the digit is greater than 5 then the number is increased by 1 and when the digit is less than 5 then the number remains same.

So, we have:

Density = 19.2 g/ml

Hence, the density of the metal object is 19.2 g/ml.

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if the number of times you take the test were independent variable of the chance you fail what could that mean the difficulty of the test is consistent and unchanging.

The difficulty of the test is consistent and unchanging, making it so that the chance of failing is solely determined by the individual's performance on the test. Factors such as knowledge of the subject and the ability to focus can play a role in a person's success, but the actual chance of failing is not affected by how many times the test is taken. This means that those who fail the test will have to work harder and prepare better in order to pass it on the next attempt. Taking the test multiple times does not guarantee a higher chance of success, as the difficulty remains the same each time due to independent variable.

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Answer:

Below

Step-by-step explanation:

Similar triangles due to A - A - A

Set up ratios

QR is to RS   as  QP is to TS

(x+2) / (2x-5) = 3/5       Cross multiply to get

5x+10 = 6x-15               subtract 5x from both sides of the equation

10 = x - 15                     add 15 to both sides

25 = x

Answer: Choice B

Step-by-step explanation:

Since there are 5 cases which each hold 12 shells. She already filled in 2 cases and 1 case with 1 shell which is 25 in total.

12x5=60

60-25=35

35 is choice B.

Answer:

a. The number of customers that should a cashier expected till to find a customer is 1.35

b. The probability for helping three customers is 0.013

Step-by-step explanation:

The computation is shown below:

A. The number of customers that should a cashier expected till to find a customer is as follows:

= 1 ÷ 0.74

= 1.35

b. The probability for helping three customers is

= (1 - 0.74)^3 × 0.74

= 0.013

So the same is to be considered and relevant

The quotient of (x² - 3x - 40) divided by (x + 5) is x - 8 with a remainder of 0.

To perform the long division, we divide the polynomial (x² - 3x - 40) by the binomial (x + 5).

We start by dividing the highest degree term of the polynomial (x²) by the leading term of the binomial (x). This gives us x as the first term of the quotient.

Next, we multiply the entire binomial (x + 5) by x, which gives us x² + 5x. We subtract this product from the original polynomial (x² - 3x - 40).

Subtraction: (x² - 3x - 40) - (x² + 5x) = -8x - 40

Now, we bring down the next term of the polynomial, which is -8x. We divide -8x by the leading term of the binomial (x), giving us -8 as the next term of the quotient.

We multiply the entire binomial (x + 5) by -8, resulting in -8x - 40. We subtract this product from the remaining polynomial (-8x - 40).

Subtraction: (-8x - 40) - (-8x - 40) = 0

At this point, we have subtracted the entire polynomial (x² - 3x - 40), and the remainder is 0. Therefore, the quotient of (x² - 3x - 40) divided by (x + 5) is x - 8 with a remainder of 0.

Checking our answer, we can multiply the quotient (x - 8) by the divisor (x + 5) and verify if it equals the original polynomial (x² - 3x - 40).

(x - 8)(x + 5) = x² + 5x - 8x - 40 = x² - 3x - 40

The result matches the original polynomial, confirming that our quotient is correct.

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The number line (d) represents the location of the fraction -3/8 on the number line

A number line is a  vertical or horizontal line that has endpoints and it is used to represent numbers at a constant interval

The fraction is given as

-3/8

The above number is a negative number and it is greater than -1

This means that the location of the number line is between 0 and -1

To plot the number line, we make use of 8 intervals between 0 and -1 ( as represented by the number lines in the options)

The third point to the left of 0 represents -3/8

This means that the number line (d) represents the location of the fraction -3/8 on the number line

Hence, the number line (d) represents the location of the fraction -3/8 on the number line

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Answer:

5. 89

6. 98

7. 90

8. 130

Step-by-step explanation:

they are all equivalent to the one shown

5. 89, angles equal

6. 98, angles equal

7. 90, right angles

8. 130, angles equal

The required simplified value of the given expression is 32.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

here,
Given expression,
= [∛8]⁵
= [∛2³]⁵
= 2⁵
= 32

Thus, the required simplified value of the given expression is 32.

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The perimeter of the new figure is approximately 17.89 inches.

since we are rotating the isosceles right triangle around point a, the new figure will still be an isosceles right triangle with the same length of the long side as the original triangle. however, the vertices of the triangle will have been rearranged by the rotations.

let's start by drawing the original triangle and labeling its sides:

   n

   |

   |     5.66

   |----|-----

   a    a    a

since the long side of the triangle has length 5.66 inches, each of the other sides must have length 5.66/√2 inches, since the triangle is isosceles and right.

now, let's apply the rotations and draw the new triangles:

rotation 1) 90° clockwise around a:

        N

         |

5.66  |

   -----|----

        A    A

         |

        A

rotation 2) 180° clockwise around a:

            n

              |

        -----|----

   5.66   |

             A   A    A

                    I

                   A

rotation 3) 270° clockwise around a:

            n

             |

       -----|----

             |

   5.66   |    A

             A    A    A

              |

in each of the new triangles, we can see that the length of the long side is still 5.66 inches, and each of the other sides has length 5.66/√2 inches. so each new triangle has the same perimeter as the original triangle, which is:

perimeter = 5.66 + 2*(5.66/√2)

         = 5.66 + 2*(5.66/1.414)

         ≈ 17.89 inches

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The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4.

The probability that if you choose 2 people randomly from the 16 in the hospital, exactly one will need an x-ray is as follows:
Firstly, calculate the probability of choosing one person who needs an X-ray and one person who doesn't.

There are 4 people who need an x-ray and 12 who don't, so the probability for this is (4/16) * (12/15).

Now, calculate the probability of choosing one person who doesn't need an X-ray and one person who does. This is (12/16) * (4/15).

Now, add the probabilities to find the total probability.

The probability that exactly one person will need an x-ray is

(4/16) * (12/15) + (12/16) * (4/15) = 2/5

=0.4.

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The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4 or 40%.

If there are 16 people in a hospital and 4 need an xray, the probability that if you choose 2 people randomly, exactly one will need an xray is 0.56.

Total number of people in a hospital = 16

Number of people who need an x-ray = 4

Thus, the probability that if you choose 2 people randomly, exactly one will need an x-ray is given by;

P(one needs an x-ray) = (Number of people who need an x-ray × Number of people who do not need an x-ray) / Total number of people × Total number of people - 1

P(one needs an x-ray) = (4 × 12) / 16 × 15

P(one needs an x-ray) = 0.08

P(one doesn't need an x-ray) = (Number of people who need an x-ray × Number of people who do not need an x-ray) / Total number of people × Total number of people - 1

P(one doesn't need an x-ray) = (12 × 4) / 16 × 15

P(one doesn't need an x-ray) = 0.32

Now, we have to add both the probabilities of exactly one person needing an x-ray and exactly one person not needing an x-ray;

P(exactly one person needs an x-ray) = P(one needs an x-ray) + P(one doesn't need an x-ray)

P(exactly one person needs an x-ray) = 0.08 + 0.32P(exactly one person needs an x-ray) = 0.4

The probability that if you choose 2 people randomly, exactly one will need an x-ray is 0.4 or 40%.

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Answer:

what are the choices?

Step-by-step explanation:

The correct option H0: µD ≥ 0,HA: µD < 0, is used to determine whether the first population's mean is lower than the second population's mean, a set of hypotheses.

Paired testing, commonly referred to as auditing, is a practical and easy technique to determine whether and how discrimination is present.

Thus, µD ≥ 0,HA: µD < 0, is used to determine whether the first population's mean is lower than the second population's mean, a set of hypotheses.

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