Select the statement that best represents the relationship between engineering ethics and engineering design problems.

a. One main difference is that ethical problems rarely result in some solutions that are better than others are.

b. One key difference is that clearly wrong solutions rarely result in design problems.

c. One main similarity is that both involve solutions bounded by background conditions and constraints.

d. One key similarity is that both commonly result in one unique, correct solution.

A decibel is a dimensionless unit to express physical intensity or sound pressure levels.

A decibel is a dimensionless unit to express physical intensity or sound pressure levels. The decibel, in turn, measures the power of the sound, its energy, and the stronger or weaker it is emitted. Measures the volume of the sound.  It is a logarithmic scale that quantifies the relative loudness or softness of a sound compared to a reference level. The decibel scale is based on powers of 10, where an increase of 10 dB represents a tenfold increase in sound intensity. The reference level for the decibel scale varies depending on the context. In the field of acoustics, the commonly used reference level is 0 dB, which corresponds to the threshold of human hearing. Positive decibel values indicate increasing sound levels, while negative values indicate decreasing sound levels or the absence of sound.

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Answer:

they will increase why because they go from warm cold warm meaning they have to adapt back to the previous location

Explanation:

Answer:

1. Pioneer

2. Primary

Explanation:

Pioneer Species are the first organisms to colonize barren environments.

Primary Succession is the development of an ecosystem of a barren environments!

I hope this helped! :)

Answer:

The first answer is Pioneer and I think the second is Primary

Explanation:

After extensive, detailed calculation, contemplation, investigation, and consideration, my tentative guess is that the second choice is the correct one.

Measuring the change in a star's position in the sky in order to detect a planet orbiting that star is called the astrometric method.

Astrometry is a method of finding exoplanets (planets outside our Solar System) that are orbiting another star. This method consists of measuring a start's position in the sky precisely, observing the changes in position over time.

If a star has a planet orbiting it, the gravitational influence of the planet will cause the star to move in a very tiny elliptical or circular orbit (hence the need of precision). That's because both star and planet each orbit around their mutual centre of mass.

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Answer:

Explanation:

Given:

m = 5·10⁻²⁷ kg

V₁ = 2·10⁵ m/s

V₂ = 4·10⁵ m/s

D = 10cm = 0.10m

_______________

a - ?

The change in kinetic energy is equal to the work:

Ek₂ - Ek₁ = F·D

m·V₂² / 2 - m·V₁² / 2 = F·D

(m/2)·(V₂² - V₁²)  = F·D

Force:

F = (m/2)·(V₂² - V₁²) / D

F =   m·(V₂² - V₁²) / (2·D)

F = (5·10⁻²⁷)·( (4·10⁵)² - (2·10⁵))/ (2·0.10) ≈ 3·10⁻¹⁴ N

Answer:

Length -> meter

Mass -> kilogram

Time -> second

g for gram

mg for milligram

t for time

μm for micrometer

ms for millisecond

300cm = 3m

500g = 0.5kg

1500m = 1.5km

250ms = 0.25s

3.65×10^4g = 36.5kg

The amount of thermal energy inside a protostar increases with time, We will degree radiative power without delay and infer thermal energy from models: type will we infer from the law of conservation of energy

A protostar is a very younger big name that is nonetheless accumulating mass from its parent molecular cloud. The protostellar phase is the earliest one within the system of stellar evolution. for a low-mass superstar, it lasts about 500,000 years.

A protostar is formed as gravity starts offevolved to pull the gases collectively into a ball. This technique is referred to as accretion. As gravity pulls the gasses toward the center of the ball, gravitational strength begins to warmness them, inflicting the gasses to emit radiation. in the beginning, the radiation simply escapes into space.

Protostar is an early degree in the evolution of a celebrity that generally grows to the factor of beginning nuclear fusion and becoming a star through gathering mass. it's miles made from a contracting cloud of bloodless and dark interstellar medium (often hydrogen gas).

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The correct statements from the following list about how Uranus is different from Jupiter, and how its rings and moons formed and evolved includes the following:

Describe Uranus?

Uranus is described as the seventh planet from the Sun. The name Uranus  is a reference to the Greek god of the sky, Uranus, who, according to Greek mythology, was the great-grandfather of Ares, grandfather of Zeus and father of Cronus.

Some known facts about Uranus includes the following:

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If you were to observe a steady stream of X-rays emitted from a central void in space, you would most likely be observing an active galactic nucleus (AGN) or a supermassive black hole.

If you were to observe a steady stream of X-rays emitted from a central void in space, you would most likely be observing an active galactic nucleus (AGN) or a supermassive black hole. AGNs are powered by the accretion of matter onto a supermassive black hole at the center of a galaxy. As matter falls into the black hole, it forms an accretion disk, generating intense gravitational forces and emitting high-energy X-rays. These X-rays can be detected by observing instruments in space, such as X-ray telescopes. The presence of a central void emitting a steady stream of X-rays indicates the presence of a highly energetic and active region associated with AGNs or supermassive black holes.

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Explanation:

I assume the polls of the 2 magnets are +/+ and -/- aligned, so that both magnets repel each other.

when we add weight, it will be lower, as more weight (more pressure, more power) forces the magnets to get closer, as their repelling force is constant per distance.

Answer:

An element is a pure substance and is found on the periodic table. If you have more than one element chemically bonded, it is a compound. ... H2O is a compound

Explanation:

Answer:

this is just and example of how to solve it

Explanation:

need brainliest

Answer:

V= 125volts

Explanation:

R =25ohms

I = 5 amp

V = ?

t = 36seconds

V = IR

V = 5× 25

V= 125volts

Q = It

Q = 5×36

Q = 180 coulombs

Q is the amount of charge.

Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.

Using the equation of motion to determine the velocity at the end of the fall

Where v is velocity at the end of fall

u is initial velocity = 0

g is acceleration due to gravity = 9.81 m/s^2

h is height = 20

v^2 = 0 + 2 (9.81)(20)

v^2 = 392.4

v = - 19.8 m/s

The velocity, v after bouncing is calculated also:

u = 0

g = 9.81 m/s^2

h = 5.0 m

v^2 = 0 + 2(9.81)(5)

v^2 = 98.1

v = 9.904 m/s

Impulse = 2.0 × (9.9 -(-19.8)

Impulse = 59.4 Ns

Therefore, the impulse of the floor on the ball is 59.4 Ns.

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Answer:

\(m = \frac{-2}{3}\)

Explanation:

Given

Points: (1,-1) and (-5,3)

Required

Determine the slope

The slope of a line is represented by m and is calculated as thus;

\(m = \frac{y_1 - y_2}{x_1 - x_2}\)

Where

\((x_1,y_1) = (1,-1)\)

\((x_2,y_2) = (-5,3)\)

Substitute these values in the given formula

\(m = \frac{-1 - 3}{1 - (-5)}\)

\(m = \frac{-1 - 3}{1 +5}\)

\(m = \frac{-4}{6}\)

Simplify fraction

\(m = \frac{-2}{3}\)

Hence, the slope of the line is \(m = \frac{-2}{3}\)

Answer:

The answer is 1/3

Explanation:

Change in y/Change in x

-2/-6=1/3

The force exerted on the car when motorist is pulling on the midpoint of the 3.0-m rope is 400 N.

The question involves the determination of the force exerted on the car when one end of a 3.0-m rope is tied to a tree; the other end is tied to a car stuck in the mud.

The motorist pulls sideways on the midpoint of the rope, displacing it a distance of 0.25 m. If he exerts a force of 200.0 N. Under these conditions, the force exerted on the car can be calculated as follows;

Since the displacement of the rope is perpendicular to the direction of the applied force, the component of the force perpendicular to the rope's direction must be considered. We can calculate the force perpendicular to the direction of the applied force as follows;

F_perpendicular = F x sinθ

where, F is the force exerted, and θ is the angle between the force and the direction of the rope (90°).

Therefore,

F_perpendicular = 200 x sin(90°) = 200 x 1 = 200 N

The force acting on the car is the force in the direction of the rope, which is equal to two times the force perpendicular to the rope direction. Therefore,

F_car = 2 x F_perpendicular

F_car = 2 x 200 N = 400 N

Therefore, the force exerted on the car is 400 N.

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Answer:

for the first time in the future of our games are based on your car advertising

Explanation:

for the first time in the fhgvhbgj tire and wheel drive automatic captions and subtitles for the first time in the future of our games of

Answer:

Fnet = 16.98204316 N will point right

Explanation:

q₁ and q₂ both positive ⇒ F₁₂ will point right, repel

q₂ pos and q₃ neg        ⇒ F₂₃ will point right, attract

Fnet = F₁₂ + F₂₃

Fnet = k.q₁.q₂/r₁₂² + k.q₂.q₃/r₂₃²

Fnet = 9x10⁹x 9.33x10⁻⁶x4.22x10⁻⁶/(0.18)² +  9x10⁹x 4.22x10⁻⁶x8.42x10⁻⁶/(0.23)²

Fnet = 0.3543534/(0.18)² +  0.3197916/(0.23)²

Fnet = 10.93683333 + 6.04520983

Fnet = 16.98204316 N

The magnitude of acceleration of object A be 10226.93 m/s^2.

Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

Given parameters:

Let, Mass of object A be = m kg.

Mass of object B be= M =  4.21 x 10^21 kg.

Distance between the two objects = r = 5.24 x 10^3 m.

G = 6.67 x 10^-11 N (m/kg) ^2.

So, attraction force acting on object A be: F = GMm/r²

Hence, acceleration of object A be = F/m = GM/r².

After putting the given numerical values , we get:

acceleration of object A be = 10226.93 m/s^2

Hence, acceleration of object A be  10226.93 m/s^2.

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According to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

option B is the correct answer.

Newton's first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will continue in motion with a constant velocity unless acted upon by an external force.

In other words, an object will maintain its state of motion (whether it is at rest or moving in a straight line at a constant speed) unless a force acts upon it.

Thus, according to Newton’s first law of motion, an object at rest will begin to move, when an unbalanced force acts upon it.

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Answer:

its B

Explanation:

Answer:

\(3 m/s^{2}\)

Explanation:

ΣF=ma

The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.

Besides U-235, another isotope that can undergo nuclear fission is Pu-239. U-235 and Pu-239 are the two isotopes that can sustain a chain reaction, which is necessary for nuclear power generation or nuclear weapons.

Nuclear fission is the process of splitting the nucleus of an atom into smaller fragments, releasing energy in the process.  The splitting of a uranium-235 or plutonium-239 nucleus releases a tremendous amount of energy. This energy is used to generate electricity in nuclear power plants and to propel nuclear submarines and aircraft carriers. Nuclear fission is also used in nuclear weapons, where the energy release is used to cause an explosion. Besides U-235 and Pu-239, other isotopes can undergo nuclear fission but are not suitable for nuclear power generation or weapons development because they either do not release enough energy or are too difficult to produce.

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Every magnet consists of two poles one is the south pole other one is the north pole. All magnets have two poles. This statement is correct.

The area at either end of a magnet where the external magnetic field is strongest is known as a magnetic pole.

Every magnet consists of two poles one is the south pole other one is the north pole like poles attracts each other while unlike poles repel each other.

Hence option (a) is correct. All magnets have two poles.

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The magnitude of the magnetic field experienced by the charge of -2 c with instantaneous velocity v = (- i 3 j ) 106 m/s is 2.89 x 10⁻⁵ T.

The magnetic force experienced by a charged particle moving with a velocity v in a magnetic field B is given by the formula F = q(v x B), where q is the charge of the particle and x represents the cross product. The direction of the force is perpendicular both to the direction of motion of the particle and the direction of the magnetic field.

In this case, the charge of the particle is -2 c, where c is the charge of an electron, so q = -2e, where e is the charge of an electron.

The velocity of the particle is given as v = (- i 3 j ) 106 m/s, so we have v x B = |v| |B| sin(θ) n, where θ is the angle between v and B and n is the unit vector perpendicular to the plane containing v and B. Since v and B are perpendicular in this case, sin(θ) = 1, and we have |v| |B| n = |q| |v| |B| n = 2e (3 x 10⁶) B n, where we have substituted the values of q and |v|.

The magnitude of the force is given as F = |F| = |2i - 6j| x 10⁻¹³ N. Equating the expressions for F, we get 2e (3 x 10⁶) B = |2i - 6j| x 10⁻¹³ N, which gives B = (|2i - 6j| x 10⁻¹³ N) / (2e (3 x 10⁶)). Substituting the values, we get B = 2.89 x 10⁻⁵ T.

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If a 6.0cm tall object is placed 20cm in front of a convex mirror with focal length -100cm, then the size of the image formed is 7.5cm. Therefore, the correct option is option 5.

To find the size of the image formed, we can use the mirror formula and magnification formula for a convex mirror. The mirror formula is:

1/f = 1/d + 1/di

where f is the focal length (-100cm), d is the object distance (20cm), and di is the image distance. Solving for di, we get:

1/di = 1/f - 1/d

1/di = 1/(-100) - 1/20

1/di = -1/100 + 5/100

1/di = 4/100

di = 100/4 = 25cm

Now that we have the image distance, we can use the magnification formula:

M = hi/h = -di/d

where M is the magnification, hi is the image height, and h is the object height (6.0cm). We can now solve for hi:

hi = M * h = (-di/do) * h

hi = (-25/20) * 6.0

hi = (-5/4) * 6.0

hi = -7.5cm

The negative sign indicates that the image is inverted. So, the size of the image formed is 7.5cm which corresponds to option 5.

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Answer:

A force is a push or pull on an object. Forces usually cannot be seen but their effects can.

Nothing moves, changes speed, stops or changes direction without force. Heavier objects need more

force to get them to move or change direction.

Explanation:

Answer:

does

Explanation:

The forces exerted on the ladder by the wall and the ground is 937.2 N.

To calculate the wall's and the ground's pressures on the ladder, we need to consider the weight of the ladder and the firefighter.

The weight of the ladder can be calculated using the formula:

Weight = mass * gravity

Weight = 45 kg * 9.8 m/s² ≈ 441 N

The weight of the firefighter can be calculated in the same way:

Weight = mass * gravity

Weight = 72 kg * 9.8 m/s² = 705.6 N

The normal force exerted by the wall balances the weight of the ladder and the firefighter. Since the ladder is in equilibrium, the normal force is equal to the combined weight:

Normal force (wall) = Weight of the ladder + Weight of the firefighter

Normal force (wall) = 441 N + 705.6 N = 1146.6 N

The normal force exerted by the ground supports the weight of the ladder and the firefighter. Since the center of mass is one-third of the way up the ladder, the normal force is distributed accordingly:

Normal force (ground) = (2/3) * Weight of the ladder + Weight of the firefighter

Normal force (ground) = (2/3) * 441 N + 705.6 N = 937.2 N

The frictional force opposes the tendency of motion along the ground. It depends on the coefficient of friction and the normal force. Without the coefficient of friction given, we cannot calculate the exact value of the frictional force.

Therefore, the ladder experiences a normal force from both the wall and the ground, while the ground also exerts a frictional force whose value requires the coefficient of friction.

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