a sample of gas has a volume of 135 ml at 0.600 atm. what would be the volume if the pressure is decreased to 0.200 atm while temperature is held constant?

If the student incorrectly orients the cuvette of the spectrophotometer so that the path of the light is through the frosted sides of the cuvette, the measured absorbance of the FeSCN solution will be higher than the actual absorbance.

A spectrophotometer is an instrument used to measure the concentration of a solution by means of the absorbance according to Beer-Lambert's law. The absorbance of recorded by the detector reflects the concentration of the analyte specie in the solution.

If the cuvette of the spectrophotometer is wrongly oriented such that light is scattered by the frosted cuvette of the spectrophotometer, a higher absorbance is recorded by the detector hence  the measured absorbance of the FeSCN solution will be higher than the actual absorbance.

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Answer:

0.530 g.

Explanation:

The express the measurement 0.530060 g we need to remember first that:

- The zeros to the left of the amount do not count as significant figures

- All non-zero numbers count as significant figures

- The zeros that are between digits significants are significant figures

Hence, the three significant figures of the measurement 0.530060 g are:

0.530060 g = 0.530 g            

Therefore, the three significant figures of the measurement 0.530060 g are 0.530 g.

I hope it helps you!

Answer:

Molar Mass: 138.9818 g/mol

Explanation:

Answer:

2.5 silly = 0.00025 kilosilly

Explanation:

To convert: \(2.5\) silly to kilosilly

Solution:

Relation between \(2.5\) silly and kilosilly is given as follows:

1 silly = \(\frac{1}{1000}\) kilosilly

Now use this formula to convert \(2.5\) silly to kilosilly.

\(2.5\) silly\(=\) \(\frac{2.5}{1000}\) kilosilly

Here, \(\frac{2.5}{1000} =0.00025\)

So,

2.5 silly = 0.00025 kilosilly

The energy level associated with the red photon in the bright line spectrum of hydrogen gas is approximately n = 2.68.

The energy levels in the bright line spectrum of hydrogen gas are quantized and can be calculated using the equation:

E = -13.6 eV/n^2

where E is the energy level, -13.6 eV is the ionization energy of hydrogen, and n is the principal quantum number.

To determine the energy level associated with a red photon in the hydrogen spectrum with an energy of 3.02 x 10^-19 joule, we need to convert the energy from joules to electron volts (eV). The conversion factor is 1 eV = 1.6 x 10^-19 joule.

Energy in eV = (3.02 x 10^-19 joule) / (1.6 x 10^-19 joule/eV) = 1.89 eV

Next, we can equate the energy level equation with the calculated energy:

1.89 eV = -13.6 eV/n^2

To solve for n, we rearrange the equation:

n^2 = -13.6 eV / 1.89 eV

n^2 = 7.19

Taking the square root of both sides, we find:

n = √7.19

n ≈ 2.68

The energy level associated with the red photon in the bright line spectrum of hydrogen gas is approximately n = 2.68. This corresponds to the transition of the electron from a higher energy level to the second energy level (n = 2).

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Answer:

chemical energy is the energy of a chemical substance that is stored in the bonds of chemical compounds and is released when they undergo a chemical reaction and transform into another substance

The reaction for the formation of HI, at the given time, has a reaction quotient of 613.

What is the reaction quotient?

Reaction quotient is the ratio of the concentration of product and reactant raised to the stoichiometric power at a given time interval.

The chemical reaction for the formation of HI is given as:

\(\rm H_2\;+\;I_2\;\rightarrow\;2\;HI\)

The reaction quotient is given as:

\(\rm Q=\dfrac{[HI]^2}{[H_2]\;[I_2]}\)

The concentration of system at the time, t has been:

Hydrogen = 0.1 M

Iodine = 0.2 M

HI = 3.5 M

Substituting the values for reaction quotient:

\(\rm Q=\dfrac{(3.5)^2}{(0.1)(0.2)}\\ Q=613\)

The reaction quotient for the reaction is 613. Thus, option D is correct.

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Two categories of mechanical waves exist: The movement of the particles in a longitudinal wave is parallel to the motion of the energy,

Only through matter can a mechanical wave's energy travel. The medium is the substance through which the wave travels (plural, media). Water, a liquid, serves as the wave's medium in the illustration above. Yet, any state of matter, including a solid, can act as the medium for a mechanical wave.

Radiant energy that moves in waves at the speed of light is known as electromagnetic energy. Radiant energy, electromagnetic radiation, electromagnetic waves, light, or the movement of radiation are other names for it.

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The integumentary system functions to retain body fluids, protect against disease, eliminate waste products, and regulate body temperature. Cell membrane performs the same function as the integumentary system. Therefore, option A is correct.

The cell membrane performs a function that is similar to the integumentary system. The cell membrane is a thin, flexible layer that surrounds the cell and acts as a barrier between the cell and its external environment.

It helps to regulate the movement of substances in and out of the cell, maintain the balance of fluids and electrolytes, and protect the cell from harmful substances.

The cell membrane can also play a role in temperature regulation, as it helps to maintain the proper internal environment of the cell.

Thus, option A is correct.

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When the concentration of nitrogen monoxide is doubled and the concentration of chlorine is cut in half, the reaction is second order in nitrogen monoxide, NO.

Is NOx equivalent to NO2?

Nitric oxide (NO), an odorless, colorless gas, and nitrogen dioxide (NO2), a reddish-brown gas with an offensive odor, are the two gases that are typically referred to as "nitrogen oxides" (NOx). Nitrogen dioxide is created when nitric oxide combines with oxygen or ozone in the atmosphere.

N2O is a laughing gas, right?

A non-flammable, colorless, and odorless gas is nitrous oxide. Despite not being flammable, nitrous oxide will nonetheless facilitate combustion to the same degree as oxygen. It produces a mood of exhilaration, therefore the moniker "laughing gas." The least effective inhalational anesthetic is nitrous oxide.

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The radius of a tantalum atom if its crystal structure is a BCC with a density of 16. 6 g/cm3 and its atomic mass is 180. 9 amu is 1.456 Å.

The radius of a tantalum atom can be calculated using the formula:

r = (3Vc/4πn)\(^\frac{1}{3}\)

where Vc is the unit cell volume, n is the number of atoms in the unit cell, and r is the radius of the atom.

For a BCC structure, there are 2 atoms per unit cell, so n = 2. The unit cell volume for a BCC crystal structure is given as:

Vc = (64/3√3)a³

where a is the length of the edge of the cube.

To solve for the radius of the tantalum atom, we need to first calculate the length of the edge of the cube. We can use the density of tantalum to calculate its atomic mass density:

ρ = m/V

where ρ is the density, m is the mass of the unit cell, and V is the volume of the unit cell. For a BCC unit cell, the mass of the unit cell can be calculated as:

m = n × atomic mass

where n is the number of atoms per unit cell and atomic mass is the atomic mass of the element. Substituting the values given, we get:

ρ = m/V = n × atomic mass / Vc

Rearranging the equation and solving for a, we get:

a = (4ρVc/2n×atomic mass)^⁰⁵

Substituting the given values and solving for a, we get:

a = [(4 × 16.6 g/cm³ × (64/3√3)a³) / (2 × 2 × 180.9 g/mol)]\(^\frac{1}{2}\)

Simplifying the expression, we get:

a = 3.307 Å

Now, we can calculate the radius of the tantalum atom using the formula:

r = (3Vc/4πn)\(^\frac{1}{3}\)

Substituting the values we have calculated, we get:

r = [(3 × (64/3√3)a³) / (4π × 2)]\(^\frac{1}{3}\) = 1.456 Å

Therefore, the radius of a tantalum atom in a BCC crystal structure with a density of 16.6 g/cm3 and an atomic mass of 180.9 amu is approximately 1.456 Å.

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Answer:

(d)

Explanation:

The correct statement is the density of ice is less than that of water. Therefore, option D is correct.

Water has a higher density than ice because its molecules are more tightly packed. Don't be fooled by the fact that ice is a solid. Water expands as it freezes. As a result, ice has a higher volume than water.

Because the orientation of hydrogen bonds causes molecules to push farther apart, ice is less dense than water.

Other liquids' solid states are denser because the molecules pack together tightly as the kinetic energy (temperature) decreases. Although the hydrogen bonds in water ice are strong, their orientation causes molecules to push apart, lowering density.

Thus, option D is correct.

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Answer:

carbon dioxide hope I helped please mark brainliest

Answer:

The second answer. Fish hide within the coral. Hope this helps!!!!

Answer:

0. 261

Explanation:

Use ideal gas formula: PV = nRT, meaning that constant R = \(0.08206\frac{(L)(atm)}{(K)(mol)}\)

\((1 atm)(6.28L) = n(0.08206\frac{(L)(atm)}{(K)(mol)})(293 K) \\n = \frac{(1 atm)(6.28L)}{(0.08206\frac{(L)(atm)}{(K)(mol)})(293 K)} \\n = 0.26119...\\n = 0.261\)

In this case, the primary structure forms hydrogen bonds to fold itself.

The answer is primary structure.

When the hybridization occur molecules have a linear arrangement of the atoms with a bond angle of 180 degree.

Hybrid orbitals are formed by combining the valence orbital on an atom. These hybrid orbitals either form sigma (σ) bonds directed toward other atoms of the molecule or contain lone pairs of electrons. We can determine the type of hybridization around a central atom from the geometry of the regions of electron density about it. Two such regions imply sp hybridization, three, sp2 hybridization, four, sp3 hybridization five, sp3d hybridization and six, sp3d2 hybridization. Pi (π) bonds are formed from unhybridized atomic orbitals that is p or d orbitals. The geometry and bond angle for the molecules can be identified by the VSEPR model from the molecule central atom which is enclosed by the electron pairs.

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Answer:

N3-

Explanation:

Answer: No, the speed of propagation is constant in a given medium; only the wavelength changes as the frequency changes.

Explanation:

2.03 mol  of H₂S contain 2.03 mol of S. A mole is exactly  6.022×10²³ , which equals Avogadro's number of particles.

A mole must be specified or be based on something repeatable, like all other units. The amount of atoms in a sample of the isotope carbon-12 was formerly the basis for the current definition of the mole, which is now based on other factors.

Today, a mole is exactly  6.022×10²³ , which equals Avogadro's number of particles. For all intents and purposes, the weight with one mole of a given substance in grams and the weight of one molecule in Daltons are essentially equivalent.  2.03 mol  of H₂S contain 2.03 mol of S.

Therefore, 2.03 mol  of H₂S contain 2.03 mol of S.

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The synthesis of aromatic 1,2-amino alcohols using a bienzymatic dynamic kinetic asymmetric transformation (bienzymatic DKAT) is a 3 step process involving synthesis of ketones, enantioselective reduction of lactols and synthesis of aromatic 1,2-amino alcohols

Step-by-step method :

Step 1: Synthesis of ketones

Starting with a ketone as the substrate, add the enzyme galactose oxidase (GOx) and an oxidant such as sodium periodate (NaIO4) to convert the ketone to a lactol. This transformation takes place at room temperature in a mixture of water and tetrahydrofuran (THF). The reaction mixture was then filtered to remove any precipitate, and the aqueous phase was extracted with ethyl acetate (EtOAc) to give the product in good yield.

Step 2: Enantioselective reduction of lactols

Use the enzyme alcohol dehydrogenase (ADH) and an NADH cofactor to perform an enantioselective reduction of lactols. This transformation takes place at room temperature in a mixture of water and isopropanol (IPA). The product is a chiral alcohol with high enantioselectivity.

Step 3: Synthesis of aromatic 1,2-amino alcohols

The chiral alcohol can be transformed into an amino alcohol using a reductive amination reaction with ammonia or an amine. This transformation takes place at room temperature in a mixture of water and ethanol (EtOH) or isopropanol (IPA). The resulting product is a 1,2-amino alcohol with high diastereoselectivity and enantioselectivity. This bienzymatic DKAT method is an effective and efficient way to synthesize aromatic 1,2-amino alcohols.

Thus, the step-by-step method of synthesis of aromatic 1,2-amino alcohols using a bienzymatic dynamic kinetic asymmetric transformation is explained above.

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The density of the osmium is 22.59 g/mL.

To calculate the density of the osmium, we need to use the formula:

Density = Mass / Volume

First, we need to calculate the volume of the osmium that was added to the graduated cylinder. We can do this by subtracting the initial volume of the water from the final volume of the water:

Volume of osmium = Final volume - Initial volume
Volume of osmium = 31.6 mL - 25.1 mL
Volume of osmium = 6.5 mL

Next, we need to calculate the mass of the osmium:

Mass of osmium = 145.8820 g

Now we can use the formula to calculate the density:

Density = Mass / Volume
Density = 145.8820 g / 6.5 mL
Density = 22.59 g/mL


The density of the osmium is 22.59 g/mL.

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In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

Answer:

Explanation:This unequal distribution of electrons is known as a polar covalent bond, characterized by a partial positive charge on one atom and a partial negative charge on the other. The atom that attracts the electrons more strongly acquires the partial negative charge and vice versa.

The thermal energy of one system must be the same as the thermal energy of the other system. Therefore, the correct option is option D.

A pan heats up when you place it on the flame. It's because heat is transferred from the burner to the pan. Additionally, it allows any other utensil or pan to heat up. But after a while, the vessel cools down when you remove it from the heat. It happens because the vessel's heat is dissipated onto the surrounding area. It enables the vessel to cool.

Heat that flows by conduction is the transfer of thermal energy between substances in contact. The thermal energy of one system must be the same as the thermal energy of the other system.

Therefore, the correct option is option D.

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Answer:

Energy costs are high for many school districts. Therefore, unlimited free power generated by the sun can deliver huge cost savings when compared to grid-generated power. With a modestly sized solar array, cost savings are alike modest.

Explanation: