Problem 2 More Basketballs Use these values of initial position and initial velocity in the following questions.
Initial position: ___1.0___ m above ground
Initial velocity: ___6.3 __ m/s, up

Problem Try to answer the following questions:

(a) What is the maximum height above ground reached by the ball?

(b) What are the magnitude and the direction of the velocity of the ball just before it hits the ground?

Show Your Problem Solving
Steps: Show these below:
1) Draw a Sketch
2) Choose origin, coordinate direction
3) Inventory List – What is known?
4) Write the kinematics equation(s) and solution of Part (a):
5) Write the kinematics equation(s) and solution of Part (b):

Answer:

Hey dear

Explanation:

Its option C

As Wavelength increases frequency decreases

In other case,

When Wavelength decreases frequency increases

its opposite

Tq

The weight of the rover vehicle on Earth, given that it weighs 37 N on Mars is 99.5 N

We'll begin by obtaining the mass of the rover vehicle. This is shown below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

W = mg

Divide both sides by g

m = W /g

m = 37 / 3.72

m = 9.95 Kg

Now, we shall determin the weight of the rover vehicle on Earth. Details below:

Weight (W) = mass (m) × Acceleration due to gravity (g)

Weight (W) = 9.95 × 10

Weight = 99.5 N

Thus, we can conclude that the weight on Erath is 99.5 N

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The relationship between total energy, kinetic energy, and potential energy can be described as follows:

Kinetic energy is the energy an object has due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: KE = 1/2 mv2. Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass. The higher the mass and the faster the object or particle is moving, the greater its kinetic energy will be.

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This question involves the concept of the centripetal force.

The largest value that r can have is "2.16 m".

In order for the car to remain in contact with the track all the time, the weight of the car must be equal to the centripetal force acting on the car.

\(Weight = Centripetal\ Force\\\\mg = \frac{mv^2}{r}\\\\g = \frac{v^2}{r}\\\\r = \frac{v^2}{g}\)

where,

r = radius = ?

v = speed = 4.6 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

\(r = \frac{(4.6\ m/s)^2}{9.81\ m/s^2}\)

r = 2.16 m

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The attached picture illustrates the centripetal force.

Answer:

Momentum  P is 840000kgm/s or 8.4 × 10^6

Explanation:

Data :

        Mass = 21000 kg

        Velocity = 400 m/s

So momentum is given as

      P = mv

      P = 21000×400

    P = 8400000 kgm/s

       P = 8.4 × 10^6

The organ system is made to connect with the organ and it does the job for the organ by the connection.

What is organ system?

An organ is a group of tissues that work together for the overall function of the organ, and an organ i hain system is a group of organs are  that work together to the  perform a specific function. The human organism of consists of eleven organ system.

An organ system is a group of the organs that work together in the body to perform a  complex function, such as the  pumping blood or the  processing and utilizing the  nutrients. There are 11 of  major organ systems in the human body: The circulatory system. The lymphatic system. In The respiratory system.

Cell can adapt themselves by undergoing 5 different condition

-hyperplasia

-hypertrophy

-atrophy

-metaplsia

-dysplasia

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Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.

Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:

1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.

2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.

3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.

4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.

These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.

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Answer:

a. 6.41 m/s

b. 120.85 m/s^2

Explanation:

The computation is shown below:

a. Pebble speed is

As we know that according to the tangential speed,

\(v = r \times \omega\)

\(= \frac{0.68}{2} \times 18.84\)

= 6.41 m/s

The 18.84 come from

\(= 2 \times 3.14 \times 3\)

= 18.84

b. The pebble acceleration is

\(a = \frac{v^2}{r}\)

\(= \frac{6.41^2}{0.34}\)

= 120.85 m/s^2

We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered

Answer:

The  value is   \(\alpha =  0.002 Np/m\)

Explanation:

From the question we are told that

  The first amplitude of the wave is  \(E_{max}1 =  98.02 \  V/m\)

  The first  depth  is  \(D_1 =  10 \  m\)

   The second amplitude is  \(E_{max}2 =  81.87 \  (V/m)\)

   The second depth is \(D_2 = 100 \ m\)

Generally from the spatial wave equation we have

   \(v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)\)

=>       \(\frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}\)

So considering the ratio of the equation for the  two depth

\(\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}\)

=>   \(\frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}\)

=>   \(\alpha  =  \frac{0.18}{90}\)

=>    \(\alpha =  0.002 Np/m\)

We will have that they are:

Equal in magnitude and point in opposite directions. {Option B]

Answer:

\(-5.0\frac{m}{s}\) or \(5.0\frac{m}{s}\) to the left

Explanation:

The equation for an elastic collision is \((m_1v_1)_i+(m_2v_2)_i=(m_1v_1)_f+(m_2v_2)_f\). Rearrange the equation for an elastic collision to solve for \((v_2)_f\):

\(\frac{[(m_1v_1)_i+(m_2v_2)_i-(m_1v_1)_f]}{m_2}\)

For this problem, let

\(m_1=1\ kg\\m_2=0.2\ kg\\(v_1)_i=0.0\ \frac{m}{s}\\(v_2)_i=10.0\ \frac{m}{s}\\(v_1)_f=3.0\ \frac{m}{s}\)

So,

\(\frac{[(1\ kg*0.0\ \frac{m}{s})+(0.2\ kg*10.0\frac{m}{s})-(1\ kg*3.0\ \frac{m}{s})]}{0.2\ kg}\\\frac{(0.0\ \frac{kg*m}{s})+(2.0\ \frac{kg*m}{s})-(3.0\ \frac{kg*m}{s})}{0.2\ kg}\\\frac{-1.0\ \frac{kg*m}{s}}{0.2\ kg}\\-5.0\ \frac{m}{s}\)

This result indicates that cart B will move to the left after the collision.

Answer:

101 meters

Explanation:

Distance traveled by the tourist:

d = 3.60 m/s × t

Distance traveled by the bear:

d + 39.3 m = 5.00 m/s × t

Substitute:

3.6 t + 39.3 = 5 t

39.3 = 1.4 t

t = 28.1

d = 101

Answer:

Leading among the causes of unsustainable agriculture are inadequate or inappropriate policies which include pricing, subsidy and tax policies which have encouraged the excessive, and often uneconomic, use of inputs such as fertilizers and pesticides, and the overexploitation of land.

Explanation:

good question! I have no idea. I swear I'm getting dumber with zoom

The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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The initial velocity of Philip was 7.66 m/s

Given data:

The vertical height is h=3 m.

Considering ground as the reference, then the initial potential energy of Philip is zero, i.e., PEi=0

The formula for the kinetic energy is given by,

Here, m is mass and v is the velocity.

After reaching the height of 3 m Philip comes to a stop. It means the final kinetic energy is zero, i.e. KEf=0.

The final potential energy is given by,

Here, g is the gravitational acceleration.

Applying the conservation of energy between initial position and final position.

Thus, the initial velocity of Philip was 7.66 m/s.

Answer:

19.5 m/s

87.8 m

Explanation:

The acceleration of block one is:

∑F = ma

-m₁gμ = m₁a

a = -gμ

a = -(9.8 m/s²) (0.22)

a = -2.16 m/s²

The velocity of block one just before the collision is:

v² = v₀² + 2aΔx

v² = (8.25 m/s)² + 2 (-2.16 m/s²) (2.3 m)

v = 7.63 m/s

Momentum is conserved, so the velocity of block two just after the collision is:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ = m₂v₂

(18.5 kg) (7.63 m/s) = (7.25 kg) v

v = 19.5 m/s

The acceleration of block two is also -2.16 m/s², so the distance is:

v² = v₀² + 2aΔx

(0 m/s)² = (19.5 m/s)² + 2 (-2.16 m/s²) Δx

Δx = 87.8 m

Explanation:

By using conservation of linear momentum and also by equating work done to kinetic energy,  \(V_{2}\)  = 15.36 m/s and \(d_{2}\) = 4.32 meters

Parameters given are :

\(m_{1}\) = 19.5 kg

friction, μk = 0.35

distance d = 2.6 m

mass \(m_{2}\) = 8.25 kg.

initial velocity of \(U_{1}\) = 6.5 m/s.

a.) Since we assumed that the block one stops after it collides with block two, the final velocity for block one will be zero. That is, \(V_{1}\) = 0 so its final momentum = 0

Let us also assume that block two was initially at rest. Therefore, it initial velocity and its momentum will be equal to zero.

The formula to use will be :

\(m_{1}U_{1} = m_{2}V_{2}\)

Substitute all the parameters into the formula above

19.5 x 6.5 = 8.25\(V_{2}\)

Make \(V_{2}\) the subject of formula

\(V_{2}\) = 126.75/8.25

\(V_{2}\) = 15.36 m/s

b.) Let us first calculate the work done in by block one.

The K.E = \(1/2mU^{2}\)

substitute its mass and velocity into the formula

K.E = 1/2 x 19.5 x \(6.5^{2}\)

K.E = 411.94 Joule

The work done = Kinetic energy

But the resultant Force F = force f - friction

where Frictional force = 0.35 x 19.5 x 9.8

Frictional force = 66.89N

Work done will be the product of resultant Force F and the distance travelled

(F - 66.89) x 2.6 = 411.94

F - 66.89 = 411.94/2.6

F - 66.89 = 158.44

F = 225.3 N

The second block will experience the same force which is equal to 225.3N

Find the kinetic energy of the second block.

K.E =  \(1/2mV^{2}\)

K.E = 0.5 x 8.25 x 15.36^2

K.E = 973.2

Using The work done = Kinetic energy

225.3\(d_{2}\) = 973.2

\(d_{2}\) = 973.2/225.3

\(d_{2}\) = 4.32 meters

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Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.

According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.

As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.

As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.

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Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

Answer:

d.  11.5 m/s²

Explanation:

s = ½at²

a = 2s/t²

a = 2(92)/4.0²

a = 11.5 m/s²

There are just two factors that matter when discussing the gravitational pull of one item on another: the mass of each object and the distance between them.

This is further explained below.

Generally, According to Newton's global law of gravitation, the amount of force exerted by the attraction between any two bodies is directly related to the sum of their masses and inversely related to the square of the distance that separates them from one another.

In conclusion, The magnitude of the gravitational pull between two objects is proportional to the product of their respective masses and the square of the distance that separates them.

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Answer:

Thunderbird has fallen behind the Mercedes Benz by 1017.49 m

Explanation:

Given the data in question;

initial speed of the ford u1 = 73.5 m/s

distance d1 = 250 m

t1 = 5.00 s

d2 = 400 m

Now, let the time taken to stop be t2 and deceleration is a1

so,

a1 = u1² / (2 × d1)

a1 = (73.5)² / (2 × 250)

a1 = 10.8045 m/s²

Now , for acceleration is a2

a2 = v² / (2 × d2)

a2 = (73.5)² / (2 × 400)

a2 = 6.7528 m/s²

total time spend = 5 + u/a1 + u/a2

total time spend = 5 + (73.5/10.8045) + (73.5/6.7528)

total time spend = 22.687 sec

Now, distance Mercedes is ahead = 22.687 × 73.5 - 400 - 250

= 1667.4945 - 400 - 250

= 1017.49 m

Therefore, Thunderbird has fallen behind the Mercedes Benz by 1017.49 m

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

Answer:

Freddy is participating in a pumpkin lifting contest. The 68 kg pumpkin starts at rest on the ground. If Freddy exerts a 720N force on the pumpkin, what is the acceleration of the pumpkin as he lifts it off the ground?

Explanation:

The three ways a car can accelerate are change in velocity, change in direction, or both.

The rate of velocity change concerning time is known as acceleration. The acceleration of the object is;

\(\rm a = \frac{v-u}{t}\)

Here,

a is the acceleration

v is the final velocity

u is the initial velocity

t is the period

The three ways a car can accelerate are as follows;

a)Change in velocity.

b)Change in direction

c)Change in both velocity and direction.

Hence, the three ways a car can accelerate are change in velocity, change in direction, or both.

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