please help growth and decay problem

A formula without free variables is a formula that does not contain any variables that are not quantified.

Sentences are commonly referred to as formulas devoid of any unrestricted variables. These statements hold a truth value independent of the variable values, hence the reason.

Open formulas are frequently referred to as formulas with free variables. These are not actually declarations; instead, they are arrangements that can transform into declarations by allotting definite values to the independent variables.

Formulas without free variables are often easier to work with than formulas with free variables.

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The correct statement that F: "I agree. The ratios of consecutive x-values are constant, and the y-values are increasing at a constant rate."

To determine whether the function shown in the table is exponential, we need to analyze the relationship between the x-values and y-values.

The table shows x-values that are increasing by a power of 2 (1, 2, 4, 8, 16, 32, 64) and y-values that are increasing by a constant rate of 1 (0, 1, 2, 3, 4, 5, 6).

The constant ratio between consecutive x-values indicates exponential growth or decay.

In this case, the function is growing exponentially because the y-values are increasing at a constant rate.

Based on this information, we can conclude that the function is exponential.

Therefore, we agree with statement F: "I agree. The ratios of consecutive x-values are constant, and the y-values are increasing at a constant rate."

The other statements are incorrect because they do not accurately describe the relationship between the x-values and y-values in an exponential function.

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Answer:

See picture

Step-by-step explanation:

They asked you to graph to line segments.  You need to plot the four points and then they wanted you to connect AB and CD.

Ordered pairs are in the order (x,y)  The x tells you how far away the point is left or right from the center of the graph (0,0).  The y tells you how far away the point is up for down from the center.

For example, A(6,-8).  Is 6 spaces to the right of zero and then 8 units down.

B(6,1)  Is 6 units to the right of zero and 1 unit up.

C(7,-2)  Is 7 units to the right of zero and 2 units down.

D(-2,-2) is 2 units left of zero and 2 units down.

Answer:

A

Step-by-step explanation:

I think it is A because that measures the height of the triangle

Answer:

Option A shows the height of the triangle

Hope this helps!

Hello...! :)

\(\: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow-9x+5= -13 \)

\( \: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow- 9x = - 13 - 5\)

\( \: \: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow - 9x = - 18\)

\( \: \: \: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow \: x = \dfrac{ - 18}{ - 9} \)

\( \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow \: x = \dfrac{18}{9} \)

\( \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \dashrightarrow \: x = 2\)

To solve we take into account that we must solve it with the law of signs in this case is:

\( \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - × - = +\)

So, we will add (13 + 5) which should give us 19 once we have done that we know that in the fraction two minus signs give a plus sign once that is done we divide 18 divided by 9 gives us two.

So the Result is 2

¿Doubts? On the comments. Greetings :D

Answer:

3 feet 10 inches

or

46 inches

Step-by-step explanation:

In order to determine the total length of the wood, convert 11 feet to inches

1 feet = 12 inches

11 x 12 = 132 inches

132 + 6 = 138 inches

If the length of each shelve is equal,

length of each shelve = 138 / 3 = 46 inches

or 46/12 = 3 feet 10 inches

Answer:

32x-96

Step-by-step explanation:

8 · 4x = 32x

8 · 12 = 96

Answer:

6

Step-by-step explanation:

Since this is a right angle, it will ultimately equal 90 degrees. So right there, you can take away 72 from 90 to see what you have left to work with. This gives you 18. You also have 3y, and the angle it's at is 18 degrees, so you can write this as 18=3y. Next, you have to isolate y, so you divide both sides   to get 6=y.

Hope this helped!

Answer:

Omg this so ez, 35

Step-by-step explanation:

105 divided by 3 duh, -_-

Answer:

m

Step-by-step explanation:

vfmjj vdzaazb knkuvggb

8/21 of the lawn still needs to be mowed.

To compare fractions, we need a common denominator. The least common multiple of 7 and 3 is 21.

Miss Lianto's fraction: (2/7) x (3/3) = 6/21

Son's fraction: (1/3) x (7/7) = 7/21

To calculate how much of the lawn still needs to be mowed, we can subtract the combined fractions mowed from the total:

Combined fractions mowed: 6/21 + 7/21 = 13/21

So, Remaining fraction: 1 - 13/21 = 8/21

Therefore, 8/21 of the lawn still needs to be mowed.

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Answer:

The company charged $500 for its services,and Mia gives the movers a 16% tip. Now, we can add the tip amount to the cost of the service to find the total amount Mia paid: Total amount = Cost of service + Tip amount = $500 + $80 = $580

Step-by-step explanation:

Answer:

Step-by-step explanation:

Initial number is 64 players

Number of players reduce twice every run and will be equal to 2 to reach the grand final

Number of runs is 5

64 > 32 > 16 > 8 > 4 > 2

Answer:

19.8 units

Step-by-step explanation:

BC = 5

AD = 8

CD = 1²+3²=c²

1+9=c²

√10=c

c=3.1627766

AB = 2²+3²=c²

4+9=c²

√13=c

c=3.6

5+8+3.6+3.16=19.76

The general solution of the partial differential equation is:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

The partial differential equation (PDE) is given as:

Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)

Assume that the solution can be written as a product of two functions:

U(x, t) = X(x)T(t)

Substituting this into the PDE, we have:

X''(x)T(t) = (1/2)X(x)T'(t)

Dividing both sides by X(x)T(t), we get:

(X''(x))/X(x) = (1/2)(T'(t))/T(t)

Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:

(X''(x))/X(x) = -λ²

(1/2)(T'(t))/T(t) = -λ²

Simplifying the second equation, we have:

T'(t)/T(t) = -2λ²

Solving the second equation, we find:

T(t) = Ce^(-2λ²t)

Applying the boundary condition U(0, t) = 0, we have:

U(0, t) = X(0)T(t) = 0

Since T(t) ≠ 0, we must have X(0) = 0.

Applying the boundary condition U(3, t) = 0, we have:

U(3, t) = X(3)T(t) = 0

Again, since T(t) ≠ 0, we must have X(3) = 0.

Therefore, we can conclude that X(x) must satisfy the following boundary value problem:

X''(x)/X(x) = -λ²

X(0) = 0

X(3) = 0

The general solution to this ordinary differential equation is given by:

X(x) = Asin(λx) + Bcos(λx)

Applying the initial condition U(x, 0) = 5*sin(4πx), we have:

U(x, 0) = X(x)T(0) = X(x)C

Comparing this with the given initial condition, we can conclude that T(0) = C = 5.

Therefore, the complete solution for U(x, t) is given by:

U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)

where:

Σ represents the summation over all values of n

λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).

To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):

X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0

X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0

From the first equation, we have Bₙ = 0.

From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.

This implies that 3λₙ = nπ, where n is an integer.

Therefore, λₙ = (nπ)/3.

Substituting the eigenvalues into the general solution, we have:

U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)

where Aₙ are the coefficients that can be determined from the initial condition.

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Answer:

1/24

Step-by-step explanation:

8x + 1/3 = 2/3

    - 1/3   - 1/3

8x = 1/3

8x/8 = (1/3)/8

x = 1/24

Answer:

its 11

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Answer:

The probability that a manufactured ball will be rejected is 0.99, to two decimal places.

Step-by-step explanation:

The mean weight is 16 Ibs. The standard deviation of the weights of all manufactured balls from the mean weight is 25. The distribution is normal. With a standard deviation this large, it is already obvious that there is a high probability of producing or having rejected balls. The weights of the balls produced here ranges from (16-25)Ibs to (16+25)Ibs.

That's -9Ibs to 41Ibs.

The minimum permissible weight is 15.68. Any ball with a lesser weight gets kicked out!

So the distance or difference between this figure and the mean is (16-15.68) = 0.32

So the probability of obtaining less than 15.68Ibs or the probability of having balls between the lower boundary of -9Ibs and 15.68 is:

25-0.32 = 24.68

24.68 ÷ 25 = 0.9872 ~ 0.99 to two decimal places.

Answer:

-4/3

Step-by-step explanation:

slope is rise/run

we go down 4 hence the negative four, and over 3

-4/3

There is no whole number by which you can multiply or divide 16087 to make it a perfect square.

To determine by which number you should multiply or divide 16087 to make it a perfect square, we can analyze its prime factorization. The prime factorization of 16087 is 13 × 1237.

In order to make 16087 a perfect square, we need each prime factor to have an even exponent. However, when we examine the prime factors of 16087, we find that both 13 and 1237 have an exponent of 1.

To make the exponents even, we need to multiply or divide 16087 by additional prime factors and their respective exponents. However, since 16087 is a product of two prime numbers (13 and 1237), we cannot introduce any additional prime factors to make the exponents even.

A perfect square is a number that can be expressed as the product of two equal factors. In the case of 16087, it cannot be transformed into a perfect square by multiplying or dividing by any whole number. The prime factors 13 and 1237 remain with an exponent of 1 each, indicating that there is no integer that can be applied to make them equal and convert 16087 into a perfect square.

Therefore, there is no whole number by which you can multiply or divide 16087 to make it a perfect square.

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The graph of the function \(f(x) = (9/4)x^2\) is a symmetric upward-opening parabola.

Overall, the graph represents a quadratic function with a positive leading coefficient, resulting in an upward-opening parabolic curve. The graph has been attached.

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Answer:

Domain : (-∞,∞)

Range : (-∞,∞)

Step-by-step explanation:

Domain is how many x-values the graph touches and Range is how many y-values the graph touches. And this graph has no point on which it stops nor any asymptotes, so both domain and range are all real numbers.

Answer:

if FB gxjxjdjdjhgdjjdidjqjdjjdid

Answer: 3 11/15  please mark brainliest If I helped you.

the question is kayar and 12 by 5 miles on Monday and 21 by three miles on Tuesday what is the total distance in miles kayuren during those two days first phone on Monday how much run that was 12 by 5 miles on Tuesday Shirin to 1 by 3 minus now this whole part and fractional part are written separately so this can be converted into a mixed fraction like when a number is of the form of p by see that is one whole number and fraction then it is written as a + b by c so we can write Monday that was 12 by 5 miles that is

12 by 1 + 2 by 5 that will be 5 will be LCM of 5 + 2 will be 7 by 5 MI and Tuesday it will be 21 by 3 that is 2 + 1 by 3 3 will be the LCM of 3 and 22 will be 6 plus one that is 7 by 3 minus in question is asked that what was the total distance kayar and thus during today's so Monday plus Tuesday will be the total total 27 by 5 + 7 by 3 that will be equal to LCM will be 15 this will be X 307 into 3 + 7 and 25 that

is 21 + 45 upon 15 that will be equal to 56 upon 15 Now since we have to give answer in mixed fraction in whole number and fraction this a bi bi can be divided into a whole number and fraction part when divided by be the remainder is remainder is written here b is written here and question is written here so 56 by 15 can be written as 15 and 23 is 45 three years question remainder will be 11:00 that is 56 - 45 and below will be the denominator will be 15 so this is our answer and the correct

The value that will be in the blank would be = 165

The percentage that will like to run that prefer summer = 60%

On the given table, the total amount of individuals in each column should be the same.

Therefore, for the bike column = 231 + 87 = 318

Therefore the number of people that will like to home and also prefer the winter weather would be = 318-153 = 165.

To find the percentage that will like to run that prefers summer, the following is carried out;

The number of people that will like to run = 231

The number of people that will like to bike = 153

Total = 153+231 = 384

Therefore percent = 231/384×100/1

= 23100/384

= 60%

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Answer:

x = 4, -2

Step-by-step explanation:

x^2-2x=8

Move the constant term to the right side of the equation.

x^2 - 2x = 8

Take half of the coefficient of x and square it.

(-2/2)^2 = 1

Add the square to both sides of the equation.

x^2 - 2x + 1 = 8 + 1

Factor the perfect square trinomial.

(x - 1)^2 = 9

Take the square root of both sides of the equation.

x-1=\(\sqrt{9}\)
x-1=±3

Isolate x to find the solutions.

Taking positive

x=3+1=4

x=4

Taking negative

x=-3+1

x=-2

The solutions are:

x = 4, -2

Answer:

\(x = -2,\;\;x=4\)

Step-by-step explanation:

To solve the quadratic equation x² - 2x = 8 by factoring, subtract 8 from both sides of the equation so that it is in the form ax² + bx + c = 0:

\(x^2-2x-8=8-8\)

\(x^2-2x-8=0\)

Find two numbers whose product is equal to the product of the coefficient of the x²-term and the constant term, and whose sum is equal to the coefficient of the x-term.

The two numbers whose product is -8 and sum is -2 are -4 and 2.

Rewrite the coefficient of the middle term as the sum of these two numbers:

\(x^2-4x+2x-8=0\)

Factor the first two terms and the last two terms separately:

\(x(x-4)+2(x-4)=0\)

Factor out the common term (x - 4):

\((x+2)(x-4)=0\)

Apply the zero-product property:

\(x+2=0 \implies x=-2\)

\(x-4=0 \implies x=4\)

Therefore, the solutions to the given quadratic equation are:

\(\boxed{x = -2,\;\;x=4}\)

i) The profit/loss when no cars are produced is a loss of 6600 Rupees.

II) The break even point is at 20 cars

III) The profit/loss if 400 cars are produced is;  a loss of 13400Rupees.

(i) When no cars are produced, x = 0.

Thus, plugging this value into the function p(x) = -x² + 350x - 6600, we have;

p(0) = -0² + 350(0) - 6600 = -6600.

Therefore, the profit/loss when no cars are produced is a loss of 6600 thousand Rupees.

(ii) The break-even point is the point at which the profit is zero, i.e., p(x) = 0. Setting p(x) = 0 and solving for x, we find that;

-x² + 350x - 6600 = 0

x = 20

Therefore, the break-even point is x = 20 cars. T

(iii) If 400 cars are produced, the profit can be found by plugging this value into the function p(x) = -x² + 350x - 6600.

We find that p(400) = -400² + 350(400) - 6600

= -160000 + 140000 + 6600 = -13400. Therefore, the profit/loss if 400 cars are produced is a loss of 13400 Rupees.

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Answer:

can you post the question but more clear I didn't understand

Step-by-step explanation:

post it again I didn't understand

Answer:

Are there answer options or is it just a solid answer?