10. What do you have to do to the coefficients of equation I below to get to equation II?
i. 2 SnO2 + 4 H2 2 Sn + 4 H2O
ii. SnO2 + 2 H2 Sn + 2 H2O
a) Both equation I and II are balanced, but equation I is the correct way to write the balanced equation.
b) Can you divide equation II by another factor and still have it be correct? Why or why not?
c) In a complete sentence, write down a method you could use to determine if an equation is written in the correct way.
1. We have to divide the coefficient of equation I by 2 to get equation II.
a. Both equations are balanced but equation II is the correct way to write a
balance equation.
b. It will be correct if we divide equation II coefficient by another factor
but we will get fractions as coefficient. For example
\(\frac{1}{2}\)SnO₂ + H₂→ \(\frac{1}{2}\)Sn + H₂O
c. The correct method is checking if the number of moles of element on
the reactant side is same as the those on the product side. And the
conventional way is making sure the coefficients are whole numbers.
i. 2SnO₂ + 4H₂ → 2 Sn + 4H₂O
ii. SnO₂ + 2H₂→ Sn + 2H₂O
We have to divide the coefficient of equation I by 2 to get equation II.
Both equations are balanced but equation II is the correct way to write a
balance equation.
If we divide the coefficients of equation II by another number, we will not
get a whole number coefficients. The coefficient will be fractions , it will
be correct but its not conventional.
The best method to know if equation is written the correct way is checking
if the coefficient are in the lowest whole number factors.
we also have to check if each moles of elements found in the reactant is
the same in the product side.
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Answer:We have to divide the coefficient of equation I by 2 to get equation II.
Explanation:
A severe systemic reaction to an allergen causing serious symptoms that develop very quickly is known as.
Answer: Anaphylaxis
Explanation:
I have a nut allergy, and this has happened to me once. The doctors also told me a lot about anaphylaxis, and I like to learn about myself.
I hope this helps!! :)
given 2 hno3 6 hi→2 no 3 i2 4 h2o, identify which element is oxidized.
In the equation 2HNO3 + 6 HI → 2 NO3 + I2 + 4 H2O, the element that is oxidized is iodine (I).
In the reaction 2HNO3 + 6 HI → 2 NO + 3 I2 + 4 H2O, the element that is oxidized is iodine (I) from HI. The oxidation number of a neutral atom is zero. When the atom is oxidized, it loses electrons (which have a negative charge), so the oxidation number goes up. When the atom is reduced, it gains electron (it gains negative charge), so the oxidation number goes down.
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Answer:
I (iodine)
Explanation:
In this redox reaction, I is oxidized because its oxidation number increases from −1 to 0.
3. How many atoms in 3.91 moles of sodium?
Answer:
Explanation:
The formula for sodium is Na. It does not form a molecule in some way.
1 mol Na = 6.02*10^23 atoms
3.91 mol = x Cross multiply
x = 3.91 * 6.02 * 10^23
x = 23.65 * 10^23
x = 2.365 * 10^24
Scientific notation is always expressed as a number 1 ≤ x < 10
3.4 x 10^23 atoms of potassium to grams
To solve this problem, we must take into account Avogadro's number. Avogadro's number tells us that in one mole of any substance there are 6.022x10^23 atoms. Applying this relationship we have that the moles of potassium (K) are:
\(\begin{gathered} molK=givenatomsK\times\frac{1molK}{6.022\times10^{23}atoms} \\ \end{gathered}\)\(\begin{gathered} molK=3.4\times10^{23}atomsK\times\frac{1molK}{6.022\times10^{23}atoms} \\ molK=0.6molK \end{gathered}\)Now, to go from moles to grams, we must multiply the moles by the molar mass of potassium. The molar mass of potassium is 39.1g/mol. So, the grams of potassium will be:
\(gK=givenmolK\times\frac{MolarMass,gK}{1molK}\)\(\begin{gathered} gK=0.6molK\times\frac{39.1gK}{1molK} \\ gK=22.1gK \end{gathered}\)Answer: In 3.4x10^23 atoms of potassium there are 22.1 grams
HURRY DONT HAVE MUCH TIME LEFT. Vegetarians do not eat animal products but rather derive their protein from plant sources. Which type of protein do vegetarian food sources lack?
Answer:
b12 and d3
Explanation:
Answer with the Matching-match the letter with the correct item
Double replacement or metathesis reaction involves the exchange of ions between two compounds.
What are the types of reaction?Combination or synthesis reaction is a type of reaction that involves two or more reactants combining to form a single product. The general format is A + B → AB.
Decomposition reaction involves a single reactant breaking down into two or more products. The general format is AB → A + B.
The matching of the letters are;
1 - C
2 - H
3 - E
4 - F
5 - A
6 - B
7 - I
8 - J
9 - G
10 - D
1) False
2) False
3) True
4) False
5) True
6) True
7) True
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hydrazine (N2H4) decomposes to produce N2 and NH3. how many molecules of NH3 will be formed if 60 molecules of N2H4 decompose into N2 and NH3?
Hydrazine is a chemical compound with the formula \(N_2H_4\). 120 molecules of\(NH_3\) will be formed if 60 molecules of \(N_2H_4\) decompose into \(N_2\) and \(NH_3\).
It is used as a rocket fuel and as a polymerization catalyst in the production of plastics and when hydrazine decomposes, it produces nitrogen gas (\(N_2\)) and ammonia (\(NH_3\)). If 60 molecules of hydrazine decompose into \(N_2\) and \(NH_3\), the number of molecules of \(NH_3\) that will be formed can be determined using the balanced equation for the reaction: \(N_2H_4 -- > N_2 + 2NH_3\). For every one molecule of hydrazine that decomposes, two molecules of ammonia are formed. Therefore, the number of ammonia molecules produced is twice the number of hydrazine molecules that decompose. Since 60 molecules of hydrazine are decomposing, the number of ammonia molecules formed is: 2 x 60 = 120 molecules of \(NH_3\)
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The most reactive metal groups on the periodic table are...
Groups I & II
Groups II & III
Groups VI & VIII
Group VII & VIII
Answer:
Groups I & II
Explanation:
The most reactive metal groups on the periodic table are metals of group 1 and II.
Group I elements are the alkali metals
Group II elements are the alkali earth metals
The most reactive metallic group of metals are the alkali metals. They are followed by metals in the second group which are the alkali earth metals.Therefore, elements in groups I and II are the most reactive metallic groups.
Group I elements prefers to lose one electron to attain an octet configuration.
Group II elements prefers to lose two electrons.
the empirical formula for a compound used as a green paint pigment is C2H3As3Cu2O8. The molar mass of its molecular formula was found to be 1013 grams. What is the molecular formula?
Answer:
Molecular formula = C₄H₆As₆Cu₄O₁₆
Explanation:
Given data:
Empirical formula = C₂H₃As₃Cu₂O₈
Molar mass of compound = 1013 g/mol
Molecular formula = ?
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass of C₂H₃As₃Cu₂O₈ is 506.897 g/mol
by putting values.
n = 1013 / 506.897
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₃As₃Cu₂O₈)
Molecular formula = C₄H₆As₆Cu₄O₁₆
after the child exhaled all of the gas, it becomes sick
An element belongs to group 17 of the periodic table. This element is most likely a . A solid sample of this element would have a appearance.
The periodic table's group 17 substance is probably a halogen. This element would appear metallic or black in solid form.
What are the elements of the 17th group?The six elements in Group 17 of the periodic table compose the halogen elements. In the periodic table, group 17 is represented by the elements fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and tennessine (Ts).
Why is Group 17 called halogens?From top to bottom, the group 17 elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). They are known as "halogens" because when they interact with metals, they produce salts.
The elements that make up group 17 of the periodic table are the halogens. They are nonmetals that are reactive, such as iodine, bromine, chlorine, and fluorine. Halogens are non-metals that are very reactive. These substances share a lot of characteristics with one another.
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Molecules have Question 18 options: A) neither kinetic nor potential energy. B) only potential energy. C) only kinetic energy. D) both potential and kinetic energy.
Explanation:
i found this I hope it helps
Calculate pH after addition of 25 mL of .1 M NaOH to 50 mL of 0.2 M HF
The initial moles of HF are calculated by multiplying the volume of the solution by the molarity of the solution. The initial moles of NaOH are calculated in the same way. The calculation of the pH after the addition of 25 mL of 0.1 M NaOH to 50 mL of 0.2 M HF
Initial moles of HF = 50 mL * 0.2 M = 10 mmol
Initial moles of NaOH = 25 mL * 0.1 M = 2.5 mmol
After the addition of NaOH, the moles of HF remaining are 10 mmol - 2.5 mmol = 7.5 mmol
The concentration of HF is 7.5 mmol / 75 mL = 0.1 M
The pKa of HF is 3.14
The pH of the solution is pKa + log(1/[HF]) = 3.14 + log(1/0.1) = 4.14
The moles of HF remaining after the addition of NaOH are calculated by subtracting the moles of NaOH from the initial moles of HF. The concentration of HF is calculated by dividing the moles of HF by the volume of the solution. The pKa of HF is a measure of how acidic HF is.
The pH of the solution is calculated by adding the pKa to the log of the reciprocal of the concentration of HF.
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how is an object's speed determined?
Answer:
Divide the distance the object traveled by the time it took to get there.
Explanation:
To calculate the speed on an object, start by determining how far the object has traveled. Next, figure out the amount of time that the object took to cover that distance. Finally, divide the distance the object traveled by the time it took to get there. Don't forget to label the speed with the correct units of measurement.
In a generic reaction A+B ->C+D, 1.00 mol of A and 1.00 mol of B are allowed to react in a 1-L flask until equilibrium is established. If the equilibrium concentration of A is 0.450 mol/L, what is the equilibrium concentration of each of the other substances? What is Keq?
The equilibrium concentrations of the substances in the reaction A+B ->C+D is Keq = [C]x[D]/0.450 x 1.00.
What is equilibrium?Equilibrium is a state of balance between opposing forces. It occurs when two forces are equal and opposite in direction and magnitude, so that no net force exists. This can be seen in physical, chemical, and economic systems. In physical systems, equilibrium occurs when the total energy of the system is at a minimum or maximum, or when the forces in a system are balanced.
The equilibrium concentrations of the substances in the reaction A+B ->C+D can be determined by using the equilibrium expression. The equilibrium expression is given by:
K_eq = [C]x[D]/[A]x[B]
Since we know that the equilibrium concentration of A is 0.450 mol/L, and the initial concentrations of A and B are both 1.00 mol/L, we can solve for the equilibrium concentrations of the other substances using the equilibrium expression.
K_eq = [C]x[D]/0.450 x 1.00
K_eq = [C]x[D]/0.450
The equilibrium concentrations of the other substances can then be calculated by rearranging the equations.
[C] = K_eq x 0.450/[D]
[D] = K_eq x 0.450/[C]
The equilibrium constant, Keq, can then be solved for by substituting the equilibrium concentrations of C and D into the equilibrium expression.
K_eq = [C]x[D]/0.450 x 1.00
K_eq = [C]x[D]/0.450
Therefore, the equilibrium concentrations of C and D can be determined by substituting the value of Keq into the equations above.
[C] = K_eq x 0.450/[D]
[D] = K_eq x 0.450/[C]
The equilibrium constant, Keq, is equal to the product of the equilibrium concentrations of C and D divided by the initial concentrations of A and B.
Keq = [C]x[D]/0.450 x 1.00
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If 2 carbon atoms, underwent fusion. What element would you get?
Answer:
Two Helium atoms
If two carbon atoms underwent fusion (of 600 million kelvin) you would get two helium atoms.
Something that causes a response in an organism is called a(n) _____.
how do two oxygen atoms cancel out each other if they pull in opposite directions and how does the molecule become nonpolar
An even distribution of electron density across the molecule, which means that the molecule has no distinct positive or negative ends. This lack of polarity makes the molecule symmetrical, and the forces of attraction between individual molecules are weak. Consequently, nonpolar molecules tend to have low boiling points and are generally insoluble in polar solvents.
When two oxygen atoms come together to form an oxygen molecule (O2), they share electrons to form a covalent bond. In this bond, each oxygen atom shares two electrons with the other oxygen atom, creating a stable molecule.
While it is true that the oxygen atoms in O2 molecule are electronegative and pull on the shared electrons in opposite directions, the two oxygen atoms are identical in terms of their electronegativity. This means that they pull on the electrons with equal strength, resulting in a balanced distribution of charge across the molecule. As a result, the molecule becomes nonpolar.
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✓ What kind of carbon storages would be the most affected by humans?
Answer: Burning fuels?
Explanation: I’m not very sure actually
The decomposition of N2O5 dissolved in carbon tetra chloride occurs followingly at constant temperature. N2O5(solution)⇌2NO2(solution)+1/2 O2(g)
This reaction is of first order and its rate constant is 5×10^−4 sec^−1? If initial concentration of N2O5 is 0.4 mol litre^−1 then
(i) What will be the initial reaction rate?
(ii) What will be the half-life period of this reaction?
(iii) What time will be taken to complete 75% reaction?
(i) The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1.\)
(ii) The half-life period of the reaction is 1386 seconds.
(iii) The time taken to complete 75% of the reaction is approximately 2772 seconds.
We can use the first-order rate equation:
Rate = k[N2O5]
Where:
Rate is the reaction rate,
k is the rate constant,
[N2O5] is the concentration of N2O5.
Given:
Rate constant (k) = \(5*10^{-4} sec^{-1}\)
Initial concentration of N2O5 =\(0.4 mol litre^{-1}\)
(i) To find the initial reaction rate:
Substitute the given values into the rate equation:
Rate = k[N2O5]
Rate = \((5*10^{-4} sec^{-1})(0.4 mol litre^{-1})\)
Rate = \(2*10^{-4} mol litre^{-1} sec^{-1}\)
The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1}\).
(ii) To find the half-life period:
The half-life of a first-order reaction is given by the equation:
t(1/2) = (0.693 / k)
Substitute the given value of k into the equation:
t(1/2) = \((0.693 / 5*10^{-4} sec^{-1})\)
t(1/2) = 1386 sec
The half-life period of this reaction is 1386 seconds.
(iii) To find the time taken to complete 75% of the reaction:
The time required to complete a certain percentage of a reaction can be found using the equation:
t = (ln(1 / (1 - x)) / k)
Where x is the fraction of the reaction completed (in this case, 75%).
Substitute the given values into the equation:
t =\((ln(1 / (1 - 0.75)) / 5*10^{-4} sec^{-1})\)
t = 2772 sec
The time taken to complete 75% of the reaction is approximately 2772 seconds.
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after your body breaks foood down what are three things that can happen to the atoms from your food
After your body food break down 'proteins, fats and carbohydrates are digested, absorption takes place in the small intestine'
Most of the digestion occurs in the first part of the small intestine while the absorption of broken down nutrients, water, vitamins, and minerals occurs in the rest of it and the small intestine absorbs most of the nutrient in food, and then circulator system passes them into other parts of body to store and use them
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Estimate the value of the equilibrium constant at 610 K for each of the following reactions.2NO2(g)⇋N2O4(g)ΔH∘fforN2O4(g)=9.16kJ/molBr2(g)+Cl2(g)⇋2BrCl(g)ΔH∘fforBrCl(g)=14.6kJ/molΔG∘fforBrCl(g)=−1.0kJ/mol
The estimated equilibrium constant for the reaction Br2(g) + Cl2(g) ⇋ 2BrCl(g) at 610 K is 1.16.
To estimate the equilibrium constant, we can use the equation:
ΔG° = -RTln(K)
where ΔG° is the standard Gibbs free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.
For the reaction 2NO2(g) ⇋ N2O4(g), the given ΔH°f for N2O4(g) is 9.16 kJ/mol. Using this value, we can calculate the standard Gibbs free energy change:
ΔG° = ΔH° - TΔS°
where ΔS° is the standard entropy change. We do not have this value, but we can assume it is roughly constant for this type of reaction. Thus, we can estimate ΔG° to be:
ΔG° ≈ ΔH° = 9.16 kJ/mol
At 610 K, we have:
ΔG° = -RTln(K)
-9100 J/mol = -(8.314 J/mol/K)(610 K)ln(K)
ln(K) ≈ 2.37
K ≈ e^2.37 = 10.7
Therefore, the estimated equilibrium constant for the reaction 2NO2(g) ⇋ N2O4(g) at 610 K is 10.7.
For the reaction Br2(g) + Cl2(g) ⇋ 2BrCl(g), we are given the ΔH°f for BrCl(g) as 14.6 kJ/mol and the ΔG°f for BrCl(g) as -1.0 kJ/mol. Using the same assumptions as before, we can estimate ΔG° to be:
ΔG° ≈ ΔH° = 14.6 kJ/mol
At 610 K, we have:
ΔG° = -RTln(K)
-1000 J/mol = -(8.314 J/mol/K)(610 K)ln(K)
ln(K) ≈ 0.15
K ≈ e^0.15 = 1.16
Therefore, the estimated equilibrium constant for the reaction Br2(g) + Cl2(g) ⇋ 2BrCl(g) at 610 K is 1.16.
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do alpha allylic cleavage fragmentation of 5,5 dimethylhexen-1-ol and determine the ion mass of the product formed
also give reason for the stability of the product formed
The alpha allylic cleavage fragmentation of 5,5 dimethylhexen-1-ol would result in the formation of a 3-methylbut-2-enal fragment and a 2-methylbut-3-en-2-ol fragment. The ion mass of the product formed would be 114 amu (atomic mass units), which corresponds to the 3-methylbut-2-enal fragment.
The stability of the product formed can be attributed to the resonance stabilization of the carbocation intermediate formed during the fragmentation process. The alpha allylic cleavage leads to the formation of a tertiary carbocation, which can undergo resonance stabilization by delocalizing the positive charge over the adjacent carbon atoms. This resonance stabilization increases the stability of the carbocation intermediate, and hence, the overall stability of the product formed.
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what mass of aluminium is produced from 100g of aluminium oxide?
Answer:
This answer is 108g mass of aluminum is produced from 100g of aluminum oxide
How many grams of CO2 are in 2.52 mol of CO2?
Show using demential analysis
Answer:
110.88g
Explanation:
Given parameters:
Mass of CO₂ = 2.52mole
Unknown:
Mass of CO₂ in the given mole = ?
Solution:
To solve this problem, we use the mole concept.
Number of moles (mol) = \(\frac{mass(g)}{molar mass(g/mol)}\)
So;
Mass (g) = Number of moles(mol) x molar mass(g/mol)
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass(g) = 2.52 mole x 44g/mole
Mass(g) = 110.88g
Which of the species below is less basic than acetylide?
a) CH3Li
b) CH3ONa
c) CH3MgBr
d) both a and c
e) all of above
Species CH3ONa and CH3MgBr are less basic than acetylide. The correct option is (d) both a and c.
Acetylide anion is a strong base due to the presence of a highly electronegative sp carbon adjacent to a very electropositive lithium or sodium. The lone pair of electrons on the carbon atom is highly delocalized and can easily abstract a proton from a suitable acid.
On the other hand, both CH3Li and CH3MgBr are weak bases. Although they have negative charges, the carbon atoms are not highly electronegative and they do not stabilize negative charge as effectively as the sp carbon in acetylide anion. Hence, they are less basic than acetylide anion.
CH3ONa is a stronger base than acetylide anion because the oxygen atom in CH3ONa is more electronegative than carbon, and can stabilize negative charge more effectively. The negative charge is localized on the oxygen atom and is not delocalized over a larger region, making it a weaker base than acetylide.
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Which of the following best shows the basic three-step energy transformation for a battery-operated radio?
Responses
Acoustical → Mechanical → Electrical
Acoustical → Mechanical → Electrical
Mechanical → Acoustical → Chemical
Mechanical → Acoustical → Chemical
Chemical → Electrical → Acoustical
Chemical → Electrical → Acoustical
Electrical → Acoustical → Chemical
The energy transformation takes places in a battery operated radio is chemical energy to electrical energy then to sound energy or acoustical. Thus, fifth option is correct.
What is energy transformation?Energy can be transformed from one form to the other, For example, when we produce current from solar cells there occurs the transformation of light energy to electrical energy.
A battery contains two electrodes immersed in a molten electrolyte. When a potential difference is applied between these electrodes one of the electrode undergo reduction and the second one to oxidation.
The chemical energy produced from the electrolyte produce current and thus the energy is transformed to electrical energy. Using this electrical current the radio produces sound energy.
Therefore, the basic three- stage energy transformation for a battery operated radio is chemical energy to electrical energy then to sound energy or acoustical hence, fifth option is correct.
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Write application of isotopes .
Answer:
In the chemical industry.
Isotopes are the atoms of the same element with same atomic no: and different mass numbers. ... ⇒As isotope of uranium is used as a fuel in nuclear reactor. ⇒An isotope of iodine is used in the treatment of goitre. ⇒An isotope of cobalt is used in the treatment of cancer.
What is the∆S° of 0₂
Answer:0
Explanation: zero because it is the most stable form of oxygen in its standard state