multiple choice question by a system when it moves an object over a distance. multiple choice question. heat is gained energy is gained work is done energy is destroyed'

The distance and displacement are the two quantities which seem to mean the same but are distinctly different from each other. Here let us assume the speed of a object as 4m/s and time as 10 s, then the distance is 40m.

The distance of an object can be defined as the complete path travelled by an object. It is a scalar quantity. It has both magnitude and direction. The SI unit of distance is meter (m).

The equation connecting distance, speed and time is given as:

Speed = Distance / Time

Distance = Speed × Time

= 4 × 10

= 40 m

Thus the distance is 40m.

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Your question is incomplete, but most probably your full question was.

Calculate the distance covered by a mousetrap car in (m) when the speed of a object is 4m/s and time is 10 seconds.

Given data is, a = 3t - 30, s0 = 5 m, v0 = 2 m/secWe know that, acceleration is the derivative of velocity and velocity is the derivative of displacement.

Thus, if we integrate acceleration twice with respect to time, we get displacement. If we integrate it once, we get velocity. Acceleration (a) = 3t - 30Integrating acceleration to obtain velocity: Acceleration

(a) = dv/dtIntegrating both sides, we get:v

= ∫(3t - 30) dt=> v

= (3/2)t² - 30t + C1Here,

C1 is the constant of integration. We can find the value of C1 using the initial condition that when t = 0, v

= v0

= 2 m/sThus, 2

= (3/2) (0)² - 30(0) + C1C1

= 2Hence

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The speed of the object when t is sqrt((e^(t) * (cos(t) - sin(t)))^2 + (2/(1 + (2t)^2))^2).

To find the speed of an object moving along a curve in the xy-plane, we can use the formula:

speed = sqrt((dx/dt)^2 + (dy/dt)^2)

Where:

dx/dt is the derivative of the x-position with respect to time

dy/dt is the derivative of the y-position with respect to time

In this case, the position vector of the object has two components: e^(t) * cos(t) and arctan(2t). To find the speed of the object, we need to take the derivative of each of these components with respect to time.

The derivative of e^(t) * cos(t) with respect to time is:

e^(t) * cos(t) + e^(t) * (-sin(t))

= e^(t) * (cos(t) - sin(t))

The derivative of arctan(2t) with respect to time is:

1/(1 + (2t)^2) * 2

= 2/(1 + (2t)^2)

To find the speed of the object at time t, we need to substitute these values into the formula:

speed = sqrt((dx/dt)^2 + (dy/dt)^2)

= sqrt((e^(t) * (cos(t) - sin(t)))^2 + (2/(1 + (2t)^2))^2).

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Answer:

Similitudes y diferencias entre los músculos de los peces y los de los animales terrestres.

Explicación:

Los músculos de los peces se diferencian del músculo de los animales terrestres porque los peces tienen músculos rojos, rosados y blancos. También tienen tejido muscular de pescado que se compone de músculo estriado al igual que el músculo de los animales terrestres. La mayor parte del tejido muscular de los peces es de color blanco, pero muchos peces también tienen una cierta cantidad de tejido oscuro de color marrón o rojizo. El músculo oscuro se encuentra justo debajo de la piel a lo largo del costado del cuerpo.

The depth at which the pressure is three times the atmospheric pressure is approximately 29.4 meters.

To find the depth, we can use the formula P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

First, we need to find the total pressure, which is three times the atmospheric pressure (3 * 1.013 x 10^5 Pa = 3.039 x 10^5 Pa).

Next, we rearrange the formula to find the depth: h = P / (ρg). Substituting the values, we get h = (3.039 x 10^5 Pa) / (1025 kg/m^3 * 9.81 m/s^2), which gives us h ≈ 29.4 meters.

Summary: The depth in the ocean at which the pressure is three times the atmospheric pressure, given the provided values for atmospheric pressure, acceleration of gravity, and density of sea water, is approximately 29.4 meters.

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Answer:

it's 2250meters and 2.25km

Explanation:

speed= distance÷time

75=distance÷30

75×30=distance

2250 m= distance

To convert meters into Kilometres we divide by 1000 so,

2250÷1000

2.25 Km

Answer:

Explanation:

To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:

\(tan^{-1}(\frac{11.1}{-43.0})=-14.5\) but since we are in Q2 we have to add 180 degrees to that angle giving us 165.5 degrees

Answer:

definitely top answer

Explanation:

because it make sense

The radius of the circular path followed by the proton is approximately 1.28 mm.

To find the radius of the circular path followed by a proton with a kinetic energy of 0.20 keV in a uniform magnetic field with a magnitude of 60 mT (millitesla), we can use the equation for the magnetic force experienced by a charged particle moving perpendicular to the magnetic field.

The formula for the magnetic force on a charged particle is given by:

F = qvB

Where:

F is the magnetic force,

q is the charge of the particle,

v is the velocity of the particle, and

B is the magnetic field strength.

In this case, the proton has a positive charge, so we can use the elementary charge, e, as the value for q. The velocity of the proton can be determined using the kinetic energy. The kinetic energy of a particle is given by:

KE = (1/2)mv^2

Where:

KE is the kinetic energy,

m is the mass of the particle, and

v is the velocity of the particle.

Since the mass of a proton is approximately 1.67 x 10^-27 kg and the kinetic energy is given as 0.20 keV, we can convert the kinetic energy to joules:

\(KE (J) = 0.20 keV x (1.6 x 10^-19 J/1 keV) = 3.2 x 10^-20 J\)

Now, we can solve for the velocity of the proton using the kinetic energy equation:

\(3.2 x 10^-20 J = (1/2)(1.67 x 10^-27 kg)v^2\)

Solving for v:

\(v^2 = (2 x 3.2 x 10^-20 J) / (1.67 x 10^-27 kg) = 3.82 x 10^7 m^2/s^2\)

\(v ≈ 6.18 x 10^3 m/s\)

Now, we can substitute the values into the magnetic force equation to find the force experienced by the proton:

F = (1.6 x 10^-19 C)(6.18 x 10^3 m/s)(60 x 10^-3 T) = 5.76 x 10^-15 N

The magnetic force is also equal to the centripetal force acting on the proton, which is given by:

F = (mv^2) / r

Where:

m is the mass of the proton,

v is the velocity of the proton, and

r is the radius of the circular path.

Solving for r:

r = (mv^2) / F

Substituting the known values:

r =\([(1.67 x 10^-27 kg)(6.18 x 10^3 m/s)^2] / (5.76 x 10^-15 N)\)

r ≈ \(1.28 x 10^-3 meters or 1.28 mm\)

Therefore, the radius of the circular path followed by the proton is approximately 1.28 mm.

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Answer: It is c

Explanation:

Answer:

\(f = mg \\ = 70 \times 9.8 = |f| \)

Answer:

Option B (350) is the correct answer.

Explanation:

Given:

The temperature is "88°F" i.e., x.

Let number of visitors be "y".

Let the two points will be:

84,225 = (x₁, y₁)

92, 450 = (x₂, y₂)

As we know,

⇒  \(y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})\)

On substituting the values, we get

⇒  \(y-225=\frac{450-225}{92-84}(88-84)\)

⇒  \(y=337.5\)

So that alternative B is the appropriate choice.

Solar panels can be used with a heat pump system to provide auxiliary heat but cannot be used to help heat water for domestic use is a False statement.

Solar panels can not only be used with a heat pump system to provide auxiliary heat, but they can also help heat water for domestic use.

Solar panels can be used not only for generating electricity but also for heating water for domestic use. This is typically achieved using solar thermal collectors, which absorb sunlight and convert it into heat.

The heated water can then be stored in a tank and used for various purposes, including domestic hot water, space heating, and pool heating.

In addition, solar panels can also be used with a heat pump system to provide auxiliary heat. The solar panels can provide electricity to power the heat pump, which can extract heat from the air, ground, or water, and transfer it to the indoor space for heating.

This can help reduce the reliance on conventional heating systems and lower energy costs, while also reducing carbon emissions.

Solar panels can also be used to heat water in addition to providing auxiliary heat to the heat pump system. This is known as a solar hot water system.

So, the statement "solar panels can be used with a heat pump system to provide auxiliary heat but cannot be used to help heat water for domestic use" is incorrect.

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The relative velocity with respect to my friend is 32.7 m/s.

We need to know about relative velocity to solve this problem. The relative velocity depends on the object and observer velocity. It can be written as

v = vo ± v'

where v is relative velocity, vo is object velocity and v' is observer velocity.

From the question above, we know that

vo = 29 m/s

v' = 3.7 m/s

The velocity will be added each other because the direction of the observer is different from the object.

v = vo + v'

v = 29 + 3.7

v = 32.7 m/s

Hence, the relative velocity with respect to my friend is 32.7 m/s.

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The surface area of a cylinder with a radius of 4 and height of 9 is approximately 326.73 square units.

To find the surface area of a cylinder, we need to calculate the area of the circular top and bottom faces and the area of the curved side. The formula for the surface area of a cylinder is 2πr² + 2πrh, where r is the radius and h is the height.

In this case, the radius is given as 4 and the height is 9. Therefore, the surface area of this cylinder can be calculated as 2π(4)² + 2π(4)(9) = 2π(16) + 2π(36) = 32π + 72π = 104π square units.

This means that the surface area of the given cylinder is approximately 326.73 square units. It's important to note that the units in this case are not specified, so the answer is in square units.

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The current flowing through the wire is 3.0 Amperes.

Given information,

F = 0.60 N

L = 1.0 m

B = 0.20 T

θ = 90° (since the wire is perpendicular to the magnetic field)

To determine the current flowing through the wire, the magnetic force experienced by a current-carrying wire in a magnetic field:

F = I × L × B × sin(θ)

Substituting the values into the formula:

0.60 N = I × 1.0 m × 0.20 T × sin(90°)

sin(90°) = 1, so the equation simplifies to:

0.60 N = I × 1.0 m × 0.20 T

I = 0.60 N / (1.0 m × 0.20 T)

I = 0.60 N / 0.20 N/A

I = 3.0 A

Therefore, the current flowing through the wire is 3.0 Amperes.

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Answer:

x = 0.4 m

Explanation:

When a spring is stretched from its equilibrium position. Some energy is stored in the spring. This energy is called the elastic potential energy of the spring. The formula used to calculate the magnitude of this stored energy is given as follows:

P.E = (1/2)kx²

where,

P.E = Elastic Potential Energy Stored in the spring = 45 J

k = Spring Constant = 540 N/m

x = amount of stretching = ?

Therefore,

45 J = (1/2)(540 N/m)x²

x² = (45 J)(2)/(540 N/m)

x = √(0.167 m²)

x = 0.4 m

The anion radius is approximately 0.092 nm

To find the anion radius, we can use Coulomb's law, which states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, the force of attraction between the divalent cation and divalent anion is given as 1.50 x 10^-8 N.

The charge of a divalent cation is 2+, and the charge of a divalent anion is 2-. Therefore, the product of their charges is (2)(2) = 4.

Now, we can use Coulomb's law to calculate the anion radius:

Force of attraction = (k * (charge of cation) * (charge of anion)) / (distance^2)

1.50 x 10^-8 N = (k * 4) / (distance^2)

Now, we need to find the value of the constant k. It is equal to 8.99 x 10^9 Nm^2/C^2.

1.50 x 10^-8 N = (8.99 x 10^9 Nm^2/C^2 * 4) / (distance^2)

To find the anion radius, we need to rearrange the equation to solve for distance:

distance^2 = (8.99 x 10^9 Nm^2/C^2 * 4) / (1.50 x 10^-8 N)

distance^2 = (35.96 x 10^9 Nm^2/C^2) / (1.50 x 10^-8 N)

distance^2 = 2397.33 x 10^17 m^2/C^2/N

Now, we can solve for the anion radius by taking the square root of both sides:

distance = √(2397.33 x 10^17 m^2/C^2/N)

Plugging in the given values, we get:

distance = √(2397.33 x 10^17 m^2/C^2/N)

distance ≈ √(23.97 x 10^18 m^2/C^2/N)

distance ≈ √(2.397 x 10^19 m^2/C^2/N)

distance ≈ √(2.397) x √(10^19) m/C√N

distance ≈ √2.397 x 10^9 m/C√N

Finally, we convert the distance from meters to nanometers:

distance ≈ √2.397 x 10^9 m/C√N

distance ≈ √2.397 x 10^9 m/C√N x (10^9 nm/1 m)

distance ≈ (√2.397 x 10^9 x 10^9) nm/C√N

distance ≈ √(2.397 x 10^18) nm/C√N

distance ≈ √2.397 x 10^9 nm/C√N

Therefore, the anion radius is approximately 0.092 nm.

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Taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × \((q^2)\)).

The force of attraction between a divalent cation and a divalent anion is given as 1.50 x\(10^{-8\) N. We can use Coulomb's Law to solve for the anion radius. Coulomb's Law states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The equation for Coulomb's Law is F = k × (q1 × q2) /\(r^2\), where F is the force of attraction, k is the electrostatic constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

In this case, since the charges of the cation and anion are equal in magnitude, their product can be written as \(q^2\). Also, we can substitute the given force value of 1.50 x \(10^{-8\) N.

Therefore, the equation becomes 1.50 x \(10^{-8\) N = k × \((q^2) / r^2\).

To find the anion radius, we need to rearrange the equation to solve for r. Rearranging, we get \(r^2\) = k × (q^2) / (1.50 x\(10^{-8\) N).

Now, we can substitute the known values into the equation. The electrostatic constant, k, is approximately 8.99 x\(10^9 Nm^2/C^2.\)
Let's assume the radius of the cation is 0.092 nm, which is equal to 0.092 x \(10^{-9\) m.

Substituting the values, we have \(r^2\) = (8.99 x \(10^9 Nm^2/C^2\)) * (\(q^2\)) / (1.50 x\(10^{-8\)N).

Simplifying the equation further, we get \(r^2\) = 599.33 × (\(q^2\)).

Finally, taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × (\(q^2\))).

Therefore, the anion radius is dependent on the charge of the ion, q. To calculate the specific value, we need additional information about the charge of the ion.

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Yes, an astronomer may identify whether a star is a main-sequence star by measuring the wavelength of the peak of the star's spectrum. Using a spectrometer, an astronomer measures the absorption spectra of a star.

An astronomer is a scientist in the discipline of astronomy who concentrates their research on a particular issue or area outside the realm of Earth. Astronomers monitor celestial bodies including stars, planets, moons, comets, and galaxies using either observational (by interpreting the data) or theoretical methods.

A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. It is the separation between adjacent spots on a wave that correspond to the same phase called wavelength.

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Answer:

a graduated cylinder

Explanation:

Graduated cylinders are generally more accurate and precise than laboratory flasks and beakers, but they should not be used to perform volumetric analysis; volumetric glassware, such as a volumetric flask or volumetric pipette, should be used, as it is even more accurate and precise.

I hope it had helped you

Answer:

Graduated Cylinder

Explanation:

Graduated cylinders are generally more accurate and precise than laboratory flasks and beakers, but they should not be used to perform volumetric analysis; volumetric glassware, such as a volumetric flask or volumetric pipette, should be used, as it is even more accurate and precise.

Hopefully this helped!

-✩sandwichchan✩

Answer:

Most energy drinks contain large amounts of caffeine, which can provide a temporary energy boost. Some energy drinks contain sugar and other substances. The boost is short-lived, however, and may be accompanied by other problems.

Explanation:

Answer:

kinda

Explanation:

Most energy drinks contain large amounts of caffeine, which can provide a temporary energy boost. Some energy drinks contain sugar and other substances. The boost is short-lived, however, and may be accompanied by other problems.

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

\(P=60+100\\P=160 [W]\)

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

\(P=V*I\)

where:

P = power [W]

V = voltage [V]

I = current [amp]

\(I = P/V\\I=160/240\\I=0.67 [amp]\)

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

\(V=I*R\)

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

\(P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R\)

\(60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]\)

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

\(R = 133.66 + 225\\R = 358.67 [ohms]\)

Answer:

Reflected

Explanation:

I do not have much context here, but reflection is what happens when the sun sets on the water. The rays hit the surface of the water and bounce off, known as refelction.

Have a nice day!

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- Heather

The time taken by the satellite to orbit the Earth is 1.51 seconds.

Given:

The satellite with mass 1,500 kg and  travels at \(6.8\times 10^3 m/s\)  , 8,500 km above the center of the  Earth.

The mass of the Earth is \(5.97\times 10^{24} kg\).

To find:

The time taken by a satellite to orbit around the Earth.

Solution:

(Under the action of zero gravity, the effect of the mass of the satellite on the orbital time becomes negligible)

\(1 km = 1000 m\\\\r=8,500 km= 8,500\times 1000m=8.5\times 10^6 m\)

The orbital period of a satellite is given by:

\(\frac{T^2}{r^3}=\frac{4 \pi}{GM}\\\\\frac{T^2}{( 8.5\times 10^6 m)^2}=\frac{4\times 3.14}{6.67\times 10^{-11} m^3 kg^{-1}s^{-2}\times 5.97\times 10^{24} kg}\\\\T^2=\frac{4\times 3.14\times ( 8.5\times 10^6 m)^2}{6.67\times 10^{-11} m^3 kg^{-1}s^{-2}\times 5.97\times 10^{24} kg}\\\\T^2=2.28 s^2\\\\T=1.51 s\)

The time taken by the satellite to orbit the Earth is 1.51 seconds.

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Answer: If the charges were opposite

Explanation:

Opposite charges attract, same charges repel (negative repels negative, positive repels negative), neutral charges have no charge

Force lines, also known as electric field lines, connect two charges when they are opposite in sign. Option C is correct.

Charge is a fundamental property of matter that determines how it interacts with electromagnetic fields. Electric charge is a property of subatomic particles such as electrons and protons. It can be either positive or negative, and like charges repel each other while opposite charges attract each other.

Here,
Force lines, also known as electric field lines, connect two charges when they are opposite in sign. If the charges are both positive or both negative, the electric field lines will diverge away from each other, indicating a repulsive force between them. If the charges are opposite in sign, the electric field lines will converge toward each other, indicating an attractive force between them.

If the charges are neutral, there is no net electric field and thus no electric field lines connecting the charges. However, electric dipoles can still be formed between neutral charges, which can create a non-zero electric field in their surroundings.

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\( = \sf \frac{1}{2} m {v}^{2} \)

\( \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4\)

Answer:

The kinetic energies of the bullets are 2.4 J and 9.6 J.

The bullet having greater velocity has more kinetic energy.

The ratio of their kinetic energies is 1 : 4.

Hope you could get an idea from here

Doubt clarification - use comment section.

The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.

The ratio of the kinetic energy of the bullets is 1:4.

The kinetic energy of an object is the energy possessed by the object due to its motion.

The kinetic energy of the two bullets is calculated as follows;

\(K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J\)

Ratio of the kinetic energy of the bullets is calculated as follows;

\(K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4\)

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Answer:

have two or more paths

Explanation:

A parallel circuit is one that has two or more paths for the electricity to flow, the loads are parallel to each other.

The term cell is incorrect because, the average voltage of a cell is 3.40 V and as already mentioned in question, the volt of source is 18 V, so cell couldn't be the appropriate word, actually the source is battery.

Now, the source is most likely related to cell because a battery which is the source here, is made up of a "group of cell".