Mars appears to have long branching channels with the appearance of having been formed by a flowing liquid. Yet we know that liquids would not stay liquid in the very thin atmosphere of the Martian surface.How can we explain the channels?Pilihan jawabanThey were made by wind-blown dust during the great Martian dust storms.They are made by plate tectonics (by separation of plates in the crust).Mars may have had a thicker atmosphere long ago when the channels formed.They were formed by volcanic lava from Olympus Mons.The channels are artificial, made by a race of Martians that died out recently.

The acceleration of the aircraft in SI units is 11.6 m/s². This is calculated using the kinematic equation that relates distance, acceleration, and final velocity, assuming an initial velocity of 0 m/s since the aircraft is starting from rest.

First, let's convert the take-off speed from miles per hour to meters per second, which are the units we will use for acceleration in SI units.

93.0 miles/hour = 41.47 meters/second (using the conversion factor 1 mile = 1.60934 kilometers and 1 hour = 3600 seconds)

Now we can use the kinematic equation that relates distance, acceleration, and final velocity, assuming an initial velocity of 0 m/s since the aircraft is starting from rest.

Final velocity squared = initial velocity squared + 2 x acceleration x distance

Plugging in the given values, we get:

(41.47 m/s)² = 0 + 2 x acceleration x 230 m

Simplifying and solving for acceleration, we get:

acceleration = (41.47 m/s)² / (2 x 230 m) = 11.6 m/s²

Therefore, the acceleration of the aircraft in SI units is 11.6 m/s².

Learn more about speed here: brainly.com/question/28224010

#SPJ4

Answer:

2.125 m/s^2

Explanation:

Use Newton's second law: Force equals mass times acceleration, F = ma. You know the force (51 N) and you know the mass of the mower (24 kg). Remembering that a Newton is the same as kg-m/s2, solve for acceleration:

F = ma

51 kg-m/s2 = 24 kg * a

2.125 m/s2 =a

If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

Given the data in the question;

Net External Force; \(F = 51N\)

Mass of the Mower; \(m = 24kg\)

Acceleration; \(a = ?\)

To determine the acceleration of the mower, we make use of the equation from the Newton's Second Law of Motion:

\(F = m\ * \ a\)

Where F is the force exerted, m is the mass and a is the acceleration.

But then, we know that; ( A newton is the same thing as  \(1 kg.m/s^2\) )

Hence, Our Net External Force; \(F = 51kg.m/s^2\)

We substitute our values into the equation to find acceleration "a"

\(51kg.m/s^2 = 24kg\ *\ a\\\\a = \frac{51kg.m/s^2}{24kg} \\\\a = 2.125 m/s^2\)

Therefore, If a net external force of 51N is extorted on a 24kg lawnmower parallel to the ground, the acceleration of the mower will be 2.125 m/s².

Learn more; https://brainly.com/question/12887896

Answer:

12 joules

Explanation:

I'm assuming you're looking for kinetic energy?? Kinetic energy is 1/2 mv^2. 4 squared is 16, 16 times 1.5 = 24. 24/2 = 12.

There are several factors that can influence the detectability of a planet. However, one type of planet that would be relatively easier to detect is a Jupiter-like gas giant planet. This is because gas giants are much larger than Earth-like rocky planets and have a more significant gravitational pull on their host star, causing the star to wobble or oscillate.

Astronomers can detect this wobbling motion using the radial velocity method, which measures the slight variations in the star's spectrum caused by the planet's gravitational pull.

Additionally, gas giants are more likely to have a thick atmosphere, which can also make them easier to detect through transit observations. When a planet passes in front of its star, it blocks a tiny fraction of the star's light, causing a dip in the star's brightness. The amount of light blocked depends on the planet's size and the thickness of its atmosphere. Therefore, a gas giant with a thick atmosphere would cause a more significant dip in the star's brightness, making it easier to detect.

In summary, Jupiter-like gas giants are relatively easier to detect due to their larger size, stronger gravitational pull, and thick atmosphere.

To Know more about star's spectrum visit:

brainly.com/question/14965583

#SPJ11

Answer:

the mass of one sun

Explanation:

its really heavy

Answer:

vibrates, and they carry energy from one place to another. Look at the sound wave and the water wave. vibrating electric charges and can travel through space where matter is not present. to particle, electromagnetic waves travel by transferring energy between vibrating electric and magnetic fields.

The magnitude of the force that the charged sphere exerts on the line of charge is 3.78 × 10⁻⁶ N.

Given:

The length of the uniform line of charge = 20 cm = 0.20 m

Charge per length = λ = 6.30 nC/m = 6.30 × 10⁻⁹ C/m

The small sphere with charge q = -4.00 μC = -4.00 × 10⁻⁶ C is located at x = 0, y = 5.00 cm = 0.05 m.

Magnitude of force is to be calculated.

We know that the electric field created by a uniformly charged line is given by:

E = λ / (2πε₀r)

Where,

ε₀ is the permittivity of free space and it has the value of 8.85 × 10⁻¹² F/m

Then, the electric field created by the uniformly charged line at a point P located at a distance y from it along the y-axis is:

E = λ / (2πε₀y)

The electric field vector is directed along the x-axis in the positive direction as the charge on the line is positive.

Now, the force experienced by a charge q placed in an electric field E is given by:

F = qE

The force is directed in the direction of the electric field vector as the charge is negative.

Thus, the force on the sphere is:

F = -qλ / (2πε₀y) = -[(4.00 × 10⁻⁶ C)(6.30 × 10⁻⁹ C/m)] / (2π(8.85 × 10⁻¹² F/m)(0.05 m)) = -3.78 × 10⁻⁶ N

Taking magnitude, we get:

|F| = 3.78 × 10⁻⁶ N

Therefore, the magnitude of the force that the charged sphere exerts on the line of charge is 3.78 × 10⁻⁶ N.

Learn more about charged sphere  here :-

https://brainly.com/question/31836782

#SPJ11

The intensity reflection coefficient (irc) is 1.

The ratio of the intensity of the reflected wave to the incident (transmitted) wave is known as the intensity reflection coefficient.

Intensity of incident (transmitted) sound wave = 50 W/cm².

As it  is totally reflected,  intensity of the reflected sound  wave = 50 W/cm².

Hence,  intensity reflection coefficient =

intensity of the reflected sound wave ÷ Intensity of incident sound wave

= 50  W/cm² /  50 W/cm².

= 1.

Learn more about reflection coefficient here:

https://brainly.com/question/28145974

#SPJ4

Answer:

Assume that the air resistance on the supplies is negligible, and that \(g = 9.8 \; {\rm m\cdot s^{-2}}\).

The plane need to drop the supplies when it is horizontally approximately \(700\; {\rm m}\) away from the hill.

The supplies will hit the tree.

Explanation:

Let \(u_{y}\) and \(v_{y}\) denote the initial and final vertical velocity of the supply; \(u_{y} = 0\; {\rm m\cdot s^{-1}}\) since the plane was flying horizontally.

Let \(x_{y}\) denote the vertical displacement of the supply; \(x_{y} = 350\; {\rm m} - 810\; {\rm m} = (-460)\; {\rm m}\).

Let \(a_{y}\) denote the vertical acceleration of the supply; \(a = (-g) = (-9.8)\; {\rm m\cdot s^{-2}}\).

Make use of the SUVAT equation \({v_{y}}^{2} - {u_{y}}^{2} = 2\, a_{y}\, x_{y}\) to find \(v_{y}\), the final vertical velocity of the supply:

\(\begin{aligned} {v_{y}}^{2} &= {u_{y}}^{2} + 2\, a_{y}\, x_{y} \end{aligned}\).

\(\begin{aligned} v_{y} &= -\sqrt{{u_{y}}^{2} + 2\, a_{y}\, x_{y}} \\ &= -\sqrt{0^{2} + 2\, (-9.8)\, (-460)}\; {\rm m\cdot s^{-1}} \\ &\approx (-94.953)\; {\rm m\cdot s^{-1}} \end{aligned}\).

(Negative since the supply would be travelling downwards.)

Let \(t\) denote time it takes for the supply to land on the hill after being dropped from the plane. Make use of the SUVAT equation \(t = (v_{y} - u_{y}) / (a)\) to find the value of \(t\!\):

\(\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-94.953) - 0}{(-9.8)} \; {\rm s}\\ &\approx 9.6890 \; {\rm s} \end{aligned}\).

Apply unit conversion and ensure that \(v_{x}\), the horizontal speed of the plane is in the standard unit \({\rm m\cdot s^{-1}}\):

\(\begin{aligned} v_{x} &= \frac{260\; {\rm km}}{1\; {\rm h}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 72.222\; {\rm m\cdot s^{-1}}\end{aligned}\).

Under the assumptions, the horizontal speed of the supply will be the same as that of the plane- \(v_{x} \approx 72.222\; {\rm m\cdot s^{-1}}\)- until it lands.

While in the air, the supply will travel a horizontal distance of:

\(\begin{aligned}x_{x} &= v_{x}\, t \\ &\approx 72.222\; {\rm m\cdot s^{-1}} \times 9.6890\; {\rm s} \\ &\approx 699.76\; {\rm m}\end{aligned}\).

Hence, for the supply to land exactly at the top of the hill, the plane need to drop the supply while at a horizontal distance of approximately \(700\; {\rm m}\) away from the hill.

The horizontal distance between the trees and the location where the plane dropped the supply would be approximately \((700\; {\rm m} - 30\; {\rm m}) = 670\; {\rm m}\). The time required for the the supply to reach that horizontal position would be:

\(\begin{aligned} t &= \frac{x_{x}}{v_{x}} \approx \frac{669.76\; {\rm m}}{72.222\; {\rm m\cdot s^{-1}}} \approx 9.2736\; {\rm s}\end{aligned}\).

Let \(h_{0}\) denote the initial height of the supply (relative to the sea level.) In this question, \(h_{0} = 810\; {\rm m}\).

Let \(h(t)\) denote the height of the supply (relative to the sea level) after being dropped from the plane for time \(t\).

The SUVAT equation \(h(t) = (1/2)\, a\, t^{2} + u_{y}\, t + h_{0}\) gives an expression for \(h(t)\). Make use of this equation to find the height of the supply (relative to the sea level) when the supply reach the horizontal position of the trees at \(t \approx 9.2736\; {\rm s}\):

\(\begin{aligned} h(t) &= \frac{1}{2}\, a\, t^{2} + u_{y}\, t + h_{0} \\ &= \frac{1}{2}\times (-9.8)\, (9.2736)^{2} + 0\times 9.2736 + 810 \\ &\approx 388.60\; {\rm m} \end{aligned}\).

Note that the altitude of the top of the trees is \(350\; {\rm m} + 40\; {\rm m} = 390\; {\rm m}\) relative to the sea level. Since \(388.90\; {\rm m} < 390\; {\rm m}\), the supplies will run into the trees.

Answer:

The amount of thermal energy needed is 626.6 J

Explanation:

When a certain amount of heat energy Q is supplied to a substance, the temperature of the substance increases according to the equation

where m is the mass of the substance is the specific heat capacity of the substance is the change in temperature

Answer:

642.6 kJ

Explanation:

Using the formula for heat energy required:

\(Q = mc \Delta T\) ,

where:

C   → specific heat capacity  =  1.68 kJ/kg°C

Q   → heat energy required  =  ?

m   → mass of the object  =  4.5 kg

ΔT → change in temperature  =  97°C - 12°C  =  85°C,

Q = 4.5  x  1.68  x  85

   = 642.6 kJ

Saturn has a satellite called enceladus, enceladus is just a little over 500 km in diameter, the shape enceladus to be  round or spherical shape

Saturn is one of the most fascinating planets in our solar system, and it has many satellites. Enceladus is one of these satellites, and it has a diameter of just over 500 km. Based on this information, it is reasonable to assume that Enceladus is a round or spherical shape. However, it's not quite as simple as that. Enceladus is indeed round, but it has not formed into a perfectly spherical shape, it has some noticeable irregularities, which is due to its composition.

Enceladus is made up of a rocky core with a water ice crust and an icy mantle, because of this, it has different densities, which have resulted in some significant variations in its shape. Enceladus is a very intriguing satellite because of its many peculiar features, it has active water geysers that have been observed shooting out from its south pole, and it has a subsurface ocean that may contain the necessary conditions to support life. This makes Enceladus an excellent target for further study and exploration. So therefore Enceladus shape is a round or spherical shape.

To know more about Enceladus visit:

https://brainly.com/question/31646213

#SPJ11

gravity does help the ball since gravity pulls down objects, it causes more friction on the ball therefore causing the ball to slow down faster.

Answer:

The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules

Explanation:

The given spring constant of the of the spring, k = 88.0 N/m

The length by which the hose is stretched, x = 4.20 m

For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose

The elastic potential energy, P.E., of a compressed spring is given as follows;

P.E. = 1/2·k·x²

∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²

1/2 × 88.0 N/m × (4.20 m)² = 776.16 J

The work done on the hose = The potential energy given to hose, P.E. = 776.16 J

Answer:

Option C.

Now give the other dude brainliest. He deserves it. :)

A statement that is a feature of the Rutherford’s model of the atom is; "the atom is mostly empty space".

According to Rutherford's model of the atom, the atom is composed mostly of empty space and there is a positive nucleus that contains  dense positive particles. This led to the planetary model of the atom.

In his legendary experiment, alpha particles were focused on a thin gold foil. Some of the alpha particles were deflected through large angles. Some were renounced and some went through without deflection.

Learn more:https://brainly.com/question/730256

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

Learn more about occluded fronts, here:

https://brainly.com/question/11718564

#SPJ4

The correct answer is a. 10 km/h.

b. The boat would move at 10 km/h at a 37-degree upstream angle to cross straight (into the current)

To be more precise, the rate of change in an object's position relative to a frame of reference and time is another way to describe velocity. It determines how quickly or slowly something is going. Consider a scenario in which there are two moving items. If both items are going in the same direction, it is simple to determine which one is moving faster than the other.

v = √v_x^2 +v_y^2

v = √((8 km/h)^2 + (6 km/h)^2)

=10 km/h

direction = θ = tan^-1 (opposite / adacrent)

= tan^-1 (6/8)

= tan^-1 (37)

= 37 degree down stream.

To learn more about velocities refer the link:

https://brainly.com/question/28390853

#SPJ9

This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.

One method to separate a mixture of colored inks is chromatography. Chromatography is a physical separation technique used to separate mixtures based on their molecular properties. In the case of colored inks, paper chromatography is a commonly used technique.

In paper chromatography, a small amount of the ink mixture is spotted onto a piece of chromatography paper, and the paper is placed in a container with a small amount of solvent (e.g. water, alcohol, or acetone). The solvent moves up the paper by capillary action, carrying the ink mixture with it. As the solvent moves up the paper, different components of the ink mixture are separated and are visible as colored bands.

The separation occurs because different components of the mixture have different affinities for the paper and the solvent. Components that are more soluble in the solvent will move up the paper more quickly, while those that are more attracted to the paper will move up more slowly. This results in a separation of the components based on their physical and chemical properties.

By comparing the separated bands of the ink mixture to those of known pure inks, the identity of each component in the mixture can be determined. This technique is often used in forensic science to identify inks used in forged documents or other types of evidence.

To learn more about chromatography visit:

https://brainly.com/question/30907934

#SPJ11

A likely method to separate a mixture of colored inks is through chromatography, a technique used to separate components of a mixture. It separates the ink into its constituent colors by allowing a solvent to travel up a stationary phase like paper, carrying the ink mixture with it.

A method that would likely be used to separate a mixture of colored inks is chromatography. Chromatography is a method used in chemistry to separate components of a mixture. It works by using a stationary phase and a mobile phase. In the case of ink separation, the ink mixture would be placed on a stationary phase (like paper), and a solvent (the mobile phase) would be allowed to travel up the paper. As the solvent travels, it moves the mixture along its path. Each component of the ink by their size, chemical properties, and interaction with the solvent and paper will move at different rates, thereby separating the ink into its constituent colors. This method is particularly useful in analyzing the chemical composition of inks and other similar mixtures.

https://brainly.com/question/34281753

#SPJ12

Answer:

Stars i think

Explanation:

Answer:

C. The facial feedback theory

Explanation:

The facial feedback theory as postulated by William James and connects back to the famous Charles Darwin talks about how facial expressions stimulate our emotional state of being. Based on this theory, the emotional experiences we have are determined by the looks on our faces.

According to the question, smiling at an event makes you enjoy it is an example of what the The facial feedback theory is explaining. Furthermore, smiling, which is a facial expression causes or stimulates an emotional state of enjoyment in that event.

Answer:a 1 10th  

b89 10

Explanation:

thats all i know so thank me when yoiu get them right:)

(a) The tension in the nearer cable is 941 N, and (b) the tension in the farther cable is 1373 N.

We need to find the tension in both the nearer and farther cables supporting the scaffold with a window washer on it.

a) To find the tension in the nearer cable, we must first calculate the total torque acting on the system, keeping in mind that the torque must be zero for the system to be in equilibrium. The torque contributions are:

1. The torque due to the window washer's weight (80 kg * 9.81 m/s²) acting at a distance of 1.5 m from the nearer cable.

2. The torque due to the scaffold's weight (60 kg * 9.81 m/s²) acting at the midpoint of the scaffold, which is 2.5 m from each cable.

Now, we can set up the torque equation:

T_near * 5.0 m = (80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)

Solve for T_near:

T_near = ((80 kg * 9.81 m/s² * 1.5 m) + (60 kg * 9.81 m/s² * 2.5 m)) / 5.0 m
T_near ≈ 941 N

b) To find the tension in the farther cable, we can use the fact that the sum of the tensions in both cables must equal the total weight of the system (scaffold + window washer):

T_far + T_near = (80 kg + 60 kg) * 9.81 m/s²

Solve for T_far:

T_far = (140 kg * 9.81 m/s²) - T_near
T_far ≈ 1373 N

Therefore,  the tension in the nearer cable (a) is approximately 941 N, and the tension in the farther cable (b) is approximately 1373 N.

Know more about tension here:

https://brainly.com/question/138724

#SPJ11

Answer:

do it have a picture.

Explanation:

There are 161  grams of calcium in a sample of calcium-containing 2.42 × 10²⁴ atoms of calcium.

To find the mass of calcium in the sample, we'll use the following steps:

The atomic mass of calcium is 40.078 g/mol. Using Avogadro's number (6.022 × 10²³), we can convert the number of atoms to moles:
2.42 × 10²⁴ atoms / 6.022 × 10²³ atoms/mol = 4.02 mol

Then, we can use the molar mass of calcium to convert moles to grams:
4.02 mol * 40.078 g/mol = 161. 11356 g

Therefore, there are 161.11356  grams of calcium in the sample. Expressing this with three significant figures gives us the final answer of 161 g.

The complete question could be as follows:

A sample of calcium contains 2.42 × 10²⁴ atoms of calcium. How many grams of calcium are there in the sample? Express with three significant figures.

learn more about significant figures

https://brainly.com/question/24630099

#SPJ11

Answer:

Explanation:

Formula

KE = 1/2 m v^3

Givens

m  = 54 kg

v = 30 m/s

Solution

KE = 1/2 54 * 30^2

KE = 1/2 54 * 900

KE = 27 * 900

KE = 24300 Joules

Answer:

A

Explanation:

If left to rest it will separate.  

The collapse of a stellar core of about 2 solar masses in a supernova explosion can result in the formation of a neutron star or a black hole.

This collapse creates an intense burst of energy that expels the outer layers of the star into space, leaving behind a highly compressed core. If the remaining core mass is below a certain threshold, it will form a neutron star, a highly dense object composed mostly of neutrons. However, if the remaining core mass is above the threshold, it will continue collapsing into a singularity, forming a black hole, an object with gravity so strong that nothing can escape it, not even light.

More on supernova: https://brainly.com/question/31521973

#SPJ11

Hello,

I hope you and your family are doing well!

To find the velocity of the dart and apple just after the dart is embedded, we can use the principle of conservation of momentum. According to this principle, the total momentum of a closed system (such as the dart and apple) is constant, meaning that the total momentum before and after an interaction (such as the dart being thrown) must be the same.

The momentum of an object is equal to its mass times its velocity, so the total momentum of the dart and apple before the dart is thrown is:

p1 = (0.6 kg)(10.8 m/s) + (1.9 kg)(0 m/s) = 6.48 kg*m/s

After the dart is thrown, the total momentum of the dart and apple is:

p2 = (0.6 kg)(v) + (1.9 kg)(v) = 2.5v kg*m/s

Since the total momentum before and after the interaction must be the same, we can set p1 equal to p2 and solve for v:

6.48 kgm/s = 2.5v kgm/s

v = 6.48 kgm/s / 2.5 kgm/s

v = 2.592 m/s

The answer is 2.592 m/s.

Please consider leaving 5 stars and brainliest if you find this answer helpful.

Happy Holidays!

Answer: To find the velocity of the dart and apple after the dart is embedded, you can use the principle of conservation of momentum. This principle states that the total momentum of an isolated system remains constant, unless acted upon by an external force.

In this case, the dart and apple form an isolated system, so their total momentum must remain constant.

The momentum of the dart before it is embedded is given by the formula p = mv, where p is momentum, m is mass, and v is velocity. The momentum of the dart is therefore 0.6 kg * 10.8 m/s = 6.48 kg*m/s.

After the dart is embedded, the total momentum of the dart and apple is also 6.48 kg*m/s. We can find the velocity of the combined system using the same formula, p = mv. The mass of the combined system is the sum of the masses of the dart and apple, or 1.9 kg + 0.6 kg = 2.5 kg.

Substituting these values into the formula, we get:

p = mv

6.48 kg*m/s = 2.5 kg * v

v = 2.592 m/s

This is the velocity of the dart and apple after the dart is embedded.

Answer:

Time taken for the car to travel a distance of 4.50 m = 1.40 seconds

Explanation:

velocity of toy car = 3.21 m/s

distance travelled by toy car = 4.50 m

Time = ?

\(Velocity = \frac{Distance}{Time} \\Time =\frac{Distance}{Velocity}\)

\(Time = \frac{4.50}{3.21} \\Time = 1.40s\)

Therefore, the time taken for the car to travel a distance of 4.50 m = 1.40 seconds