Answer:
UMMMMMMMMMMMMMMM ]
Explanation:
WHAT
Answer:
dang, he should go see a doctor
In the same liquid, the pressures are equal at all points that are
A. the same distance below the liquid surface.
B. along the vertical walls of the container.
C. not touching any immersed objects.
D. not in the sunlight.
The correct option is A. which states that in the same liquid, the pressures are equal at all points that are at the same distance below the liquid surface.
This is because the pressure is determined by the weight of the liquid column above it, which is the same for all points at the same depth. The pressure along the vertical walls of the container is not equal because the liquid is in hydrostatic equilibrium which means that the pressure is not the same at all points in the liquid, and since the walls are vertical, the pressure is the same along them. The pressure at any point not touching any immersed objects is not equal to the pressure at any other point not touching any immersed objects because the pressure is determined by the weight of the liquid column above it, which is the same for all points not touching any immersed objects. The pressure is not affected by factors such as sunlight since the pressure at any point in the sunlight is equal to the pressure at any other point not in the sunlight.
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5. Elements combine to form
O compounds
O molecules
atoms
mixtures the gen
Elements combine to form compounds. The correct answer is A.
Elements combine with each other in chemical reactions to form compounds. A compound is a substance composed of two or more different elements chemically combined in a fixed ratio by mass. For example, water is a compound composed of hydrogen and oxygen in a fixed ratio of 2:1 by mass.
B. Molecules are formed when two or more atoms combine chemically, but these atoms can be of the same element or different elements. For example, oxygen gas (O2) is a molecule composed of two oxygen atoms.
C. Atoms are the smallest unit of matter that retains the properties of an element. Atoms do not combine to form other atoms or compounds.
D. Mixtures are composed of two or more substances physically mixed together, but the substances retain their individual properties and can be separated by physical means. Mixtures are not formed by the chemical combination of elements. Examples of mixtures include air and saltwater.
Therefore, The correct answer is option A.
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is a computer translucent?
Answer:
no it's opaque
hope this helps
have a good day :)
Explanation:
What is the net force?
60N left
4ON, right
60N, right
0N
Answer:
60n left
Explanation:
Do
Read the definitions then match it with the correct force.
This image is an example of Newton's ___Law of Motion.
Here in this scenario, this image is an example of Newton's first Law of Motion.
What is newton's law of motion?
The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following is a paraphrasing of these laws:
Unless a force acts upon a body, it remains at rest or in continual straight-line motion.When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.When two bodies exert force on one another, the direction and amount of the force are opposed.Isaac Newton first identified the three laws of motion in his 1687 book Philosophies Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).
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Two velocity vectors, one is twice of the other, and separated by 90 Degree angle. If their resultant is calculated 90 m/s, what the magnitude of bigger vector?
Answer:
Vy = 80.5 [m/s]
Explanation:
In order to solve this problem we must use the Pythagorean theorem.
V = 90 [m/s]
The components are Vx and Vy:
Therefore:
\(v=\sqrt{v_{x}^{2} + v_{y}^{2} }\)
where:
Vy = 2*Vx ; because one is twice of the other.
\(90 = \sqrt{v_{x}^{2} +(2*v_{x})^{2} }\\ 90 =\sqrt{v_{x}^{2}+4*v_{x}^{2}} \\90 =\sqrt{5v_{x}^{2}} \\90=2.23*v_{x} \\v_{x}=40.25[m/s]\)
and the bigger vector is:
Vy = 40.25*2
Vy = 80.5 [m/s]
A 232g ball hangs on the end of a spring. When the spring is pulled down it oscillates with a period of .13s. When pull down too far to a point .56m below the equilibrium position, the ball flies off the spring when it reaches its equilibrium position, and flies into the air.
Find the spring constant
Find the height the ball reaches.
The spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
Angular speed of the ball
The angular speed of the ball is calculated as follows;
ω = 2π/T
ω = (2π) / (0.13)
ω = 48.33 rad/s
Spring constantThe spring constant is calculated as follows;
ω = √(k/m)
ω² = k/m
ω²m = k
(48.33² x 0.232) = k
542 N/m
Linear speed of ballv = ωL
v = 48.33 x 0.56 m
v = 27.1 m/s
Height reached by the ballh = v²/2g
h = (27.1²) / (2 x 9.8)
h = 37.5 m
Thus, the spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
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A soccer player kicks a soccer ball (m = 0.42 kg) accelerating from rest to 32.5m/s in 0.21s. Determine the force that sends soccer ball towards the goal.
Plis I need Help:(
Answer:
F=65 N
Explanation:
Uniform Acceleration
When an object changes its velocity at the same rate, the acceleration is constant.
The relation between the initial and final speeds is:
\(v_f=v_o+a.t\)
Solving for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
Where:
vf = Final speed
vo = Initial speed
a = Constant acceleration
t = Elapsed time
The ball is kicked from rest vo=0 to vf=32.5 m/s in t=0.21 s. Computing the acceleration:
\(\displaystyle a=\frac{32.5-0}{0.21}\)
\(a=154.8\ m/s^2\)
Note: We have shown this result rounded to the nearest tenth, but we kept all the decimals in a scientific calculator for further calculations.
The force needed to accelerate the soccer ball is calculated by:
F = ma
The ball has a mass of m=0.42 kg, thus:
F=0.42*154.8
F=65 N
As mentioned, this result can only be obtained by keeping full precision in the above calculations.
The back emf in a motor is 72 V when operating at 1800 rpm. What would be the back emf at 2500 rpm if the magnetic field is unchanged?
The back emf at 2500 rpm if the magnetic field is unchanged is 100 V for the back emf in a motor is 72 V when operating at 1800 rpm.
The back emf in a motor is proportional to the speed of the motor. Therefore, we can use the following formula to determine the back emf at 2500 rpm:
E2 = E1 × (N2 / N1)
where E1 is the back emf at 1800 rpm, N1 is the speed at which the back emf was measured, E2 is the back emf at 2500 rpm, and N2 is a new speed.
Plugging in the values we get:
E2 = 72 V × (2500 rpm / 1800 rpm)
E2 = 100 V
Therefore, the back emf at 2500 rpm of the motor would be 100 V if the magnetic field is unchanged.
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If an airplane is accelerating down a runway at 2.5 m/s^2, how much is it’s velocity changing each second?
If an airplane is is accelerating down a runway at 2.5 m/s². It's velocity changes 2.5 m/s in each second.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Hence, the velocity of the airplane changes 2.5 m/s in each second when it is accelerating down a runway at 2.5 m/s².
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Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
6. A ball is dropped vertically downward with a velocity of 15m/s from te roof of a building that is 22m high. How long does it takes to hit the ground below? How fast was it going when it hit
Answer:
3.03 seconds, 29.51 m/s
Explanation:
To solve this problem, we can use the kinematic equations of motion. The equation we will use is:
y = vi * t + 0.5 * a * t^2
where y is the displacement (height), vi is the initial velocity, a is the acceleration due to gravity (9.81 m/s^2), and t is the time.
At the top of the building, the displacement is 22 m (the height of the building), the initial velocity is 15 m/s (downward), and the acceleration is -9.81 m/s^2 (due to gravity, and negative because it is acting in the opposite direction to the initial velocity).
We can rearrange the equation to solve for time:
y = vi * t + 0.5 * a * t^2
22 = 15t - 0.5 * 9.81 * t^2
0.5 * 9.81 * t^2 - 15t + 22 = 0
Solving for t using the quadratic formula, we get:
t = (-(-15) ± sqrt((-15)^2 - 4 * 0.5 * 9.81 * 22)) / (2 * 0.5 * 9.81)
t = 3.03 s (rounded to two decimal places)
Therefore, it takes approximately 3.03 seconds for the ball to hit the ground.
To find the velocity of the ball when it hits the ground, we can use the equation:
v = vi + a * t
where v is the final velocity (unknown), vi is the initial velocity (15 m/s downward), a is the acceleration due to gravity (-9.81 m/s^2 downward), and t is the time (3.03 s).
Substituting the values, we get:
v = 15 - 9.81 * 3.03
v = -29.51 m/s
The negative sign indicates that the final velocity is in the opposite direction to the initial velocity (upward). However, since we were only asked for the speed (not velocity), we can take the absolute value of the answer to get:
|v| = 29.51 m/s
Therefore, the ball is going approximately 29.51 m/s when it hits the ground below.
When you blow across the top of a soda bottle, it acts like a closed pipe. If the inside of the bottle is 0.150 long, what is the fifth harmonic frequency
Answer:
The fifth harmonic frequency is 2.9 KHz.
Explanation:
For a closed tube, the fifth harmonic frequency is also the second overtone. So that;
fifth harmonic frequency = \(\frac{5V}{4L}\)
where V is the velocity of the sound in air, and L is the length of the tube.
But L = 0.15 m and V = 343 m/s, then:
fifth harmonic frequency = \(\frac{5*343}{4*0.15}\)
= \(\frac{1715}{0.6}\)
= 2858.33 Hertz
fifth harmonic frequency = 2.9 KHz
The fifth harmonic frequency of the soda bottle is approximately 2.9 KHz.
Answer:
2828.33
Explanation:
answer for acellus
A 40 kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hillside? (Formula: PE = mgh)3.9 m4.0 m39.2 m40.0 m
Given:
The mass of the dog is,
\(m=40\text{ kg}\)The potential energy is,
\(PE=1568\text{ J}\)To Find:
The height of the hillside
Explanation:
We know, the potential energy at a height (h), is,
\(PE=mgh\)Here, the acceleration due to gravity is,
\(g=9.8\text{ m/s}^2\)Substituting the values we get,
\(\begin{gathered} 1568=40\times9.8\times h \\ h=\frac{1568}{40\times9.8} \\ h=\frac{39.2}{9.8} \\ h=4.0\text{ m} \end{gathered}\)Hence, the height of the hilltop is 4.0 m.
Answer:b
Explanation:
What three factors account for challenges in the Civil Rights Movement after 1965?
lack of strong leadership
opposition to reforms in Congress
differences of opinion within rights movements
opposition from a majority of the Supreme Court
lack of public support for school desegregation policies
Answer:
differences of opinion within rights movements
opposition to reforms in Congress
lack of public support for school desegregation policies
hope this helps :) !!!
Answer:
Answer: answer A, B and C are correct
Explanation:
Answer: answer A, B and C are correct
A spherical bowling ball of mass 7 kg and radius 0.18 m rolls down a hill that has a vertical height of 7 m. If the ball started from rest at the top, what is its angular momentum at the bottom of the hill? Use two sig figs.
Answer:
er so ue 0.984 kg study your self brhh
10. A 6.0 kg block rests on top of a 7.0 kg block, which rests on a horizontal table. a. What is the force (magnitude and direction) exerted by the 7.0 kg block on the 6.0 kg block? b. What is the force (magnitude and direction) exerted by the 6.0 kg block on the 7.0 kg block?
Answer:
Below
Explanation:
The 7 kg block is pushing UP on the 6kg block to keep it from falling
force = ma = 6 kg * 9.81 m/s = 58.9 N
The 6 kg block is pushing DOWN on the 7 kg block with an equal but opposite force 58.9 N
What happens to a circuit's resistance (R), voltage (V), and current (I) when you increase the length of the wire in the circuit?
A. R is constant.
V increases.
I increases.
B. R increases.
V decreases.
I decreases.
C. R decreases.
V is constant.
I increases.
D. R increases.
V is constant.
I decreases.
Please be careful trying to find the answer here, there are 4 different versions of this same exact question.
R increases, V is constant and I decrease when you increase the length of the wire in the circuit. Option D is correct.
What is ohm’s law?
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
When all physical parameters and temperature are constant, Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically as,
The Equation of Ohm's Law
V=IR
The resistance of the circuit is;
\(\rm R= \rho \frac{L}{A}\)
When you increase the length of the wire in the circuit, R increases, V is constant and I decrease,
Hence, option D is correct.
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I have to make a presentation about ultrasound diagnostic (it's for physics). Does someone know more about that topic? I need to explain how does ultrasound show insides of human body.
*sorry if my english isn't that good, im from Cro
Answer: Okay so I don't know much but from what I do know
Ultrasound emits sound waves into the body and what bounces back is what they can see the grey shape is what is closest. It's all micro sound waves and cannot hurt an unborn baby.
Explanation:
Not sure if this is correct but it is what I remember being told.
Hope this helps!
A 57 kg paratrooper falls through the air. How much force is pulling him down?
Answer:
Explanation:
Force = Mass * acceleration due to gravity.
Given
Mass of the paratrooper = 57kg
Acceleration due to gravity = 9.81m/s²
Required
Force pulling him down
Substitute unto formula;
F = 57 * 9.81
Force = 559.17 N
Hence the force pulling him down is 559.17N
The force pulling the paratrooper as he falls down is 558.6 N.
The given parameters;
mass of the paratrooper, m = 57 kgacceleration due to gravity, g = 9.8 m/s²The force pulling the paratrooper is force of gravity and the magnitude can be determined by applying Newton's second law of motion as shown below;
F = mg
F = 57 x 9.8
F = 558.6 N
Thus, the force pulling the paratrooper as he falls down is 558.6 N.
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A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla. What is the magnitude force (in N) on the molecule?
Answer:
3.591 N
Explanation:
Applying,
F = Bvq................. Equation 1
Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.
From the question,
Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s
Substitute these values into equation 1
F = 0.57×9×10⁻⁸×7×10⁷
F = 35.91×10⁻¹
F = 3.591 N
Hence the force on the molecule is 3.591 N
Ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load.
True
False
Answer: False
Explanation:
Took the test.
Hide question 9 feedback
Rationale:
Ideal mechanical advantage is the ratio of input to output distance moved.
An object sits at rest at some position to the left of the origin. Draw what you expect the position vs time, velocity vs time, and acceleration vs time graphs to look like.
Answer:
see below
Explanation:
The position graph will be a horizontal line (of constant position) located at the negative value representing the position to the left of the origin.
The velocity graph will be a horizontal line at 0, since the object is at rest.
The acceleration graph will be a horizontal line at 0, since the object's velocity is not changing.
until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track , it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train?
Answer:
5
Explanation:
A visible light has a wavelength of 727.3 nm. Determine its frequency, energy per photon, and color.
Answer:
\(f=4.12\times 10^{14}\ Hz\) and \(E=2.73\times 10^{-19}\ J\)
Explanation:
The wavelength of a visible light is 727.3 nm.
\(727.3\ nm=727.3 \times 10^{-9}\ m\)
The formula is as follows :
\(c=f\lambda\)
f is the frequency of the visible light
\(f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{727.3 \times 10^{-9}}\\\\f=4.12\times 10^{14}\ Hz\)
Energy of a photon is given by :
E = hf, h is Planck's constant
\(E=6.63\times 10^{-34}\times 4.12\times 10^{14}\\\\E=2.73\times 10^{-19}\ J\)
Red color has a frequency of \(4.12\times 10^{14}\ Hz\) and energy per photon is \(2.73\times 10^{-19}\ J\).
Need help with questions 46 and 47. Thank you
46)
Since air resistance is ignored, both cannonballs will fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. The horizontal velocity of cannonball A does not affect its vertical motion, so it will fall at the same rate as cannonball B.
The time it takes for an object to fall to the ground from a certain height is given by the formula t = sqrt(2h/g), where t is the time, h is the initial height, and g is the acceleration due to gravity.
For cannonball B, which is dropped from a height of 20 meters, the time it takes to reach the ground is:
t = sqrt(2h/g) = sqrt(2*20/9.8) = 2.02 seconds
For cannonball A, which is fired horizontally with a velocity of 5 m/s, the time it takes to reach the ground is also 2.02 seconds, since the vertical motion is the same as cannonball B.
Therefore, both cannonballs will hit the ground at the same time.
47)
The recoil speed of the cannon can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
Before firing, the total momentum of the system is zero, since the cannon and cannonball A are at rest. After firing, the cannonball A has a momentum of 5 kg * 5 m/s = 25 kg m/s to the right, so the cannon must have an equal and opposite momentum to the left in order to conserve momentum.
The mass of the cannon is 500 kg, so its momentum after firing will be:
p = -25 kg m/s
The velocity of the cannon can be found using the equation:
p = mv
where p is the momentum, m is the mass, and v is the velocity. Solving for v, we get:
v = p/m = (-25 kg m/s) / (500 kg) = -0.05 m/s
Since the momentum of the cannon is negative, the recoil velocity is also negative, indicating that the cannon will move to the left after firing. The magnitude of the recoil velocity is 0.05 m/s, or approximately 0.18 km/h.
3. What particle completes this equation?
235
92
O
1
U+ in n → Rb+
137 Cs
55
141 Ba
58
을
96
37
40 Zr
8 + 3 n
Answer:8+3n
Explanation:
Answer:
Is C
Explanation:
When comparison shopping for a refrigerator, you compare two almost identical options, just varying by power and price:
Cost Power Rating SuperCool Fridge $650 780 W
Ice Cold Fridge $700 675 W
On average the cost of electricity is 13.4¢ per kWh (hint: energy can be expressed in kWh instead of J).
Which is the more cost-effective option if you plan on keeping this fridge for at least 5 years?
To determine which fridge is more cost-effective, we need to calculate the total cost over the 5-year period for each option.For SuperCool Fridge:Total energy used = 780 W × 24 hours/day × 365 days/year × 5 years / 1000 = 341,640 kWh
Total cost of electricity = 341,640 kWh × $0.134/kWh = $45,817.76
Total cost of fridge over 5 years = $650 + $45,817.76 = $46,467.76For Ice Cold Fridge:Total energy used = 675 W × 24 hours/day × 365 days/year × 5 years / 1000 = 296,100 kWh
Total cost of electricity = 296,100 kWh × $0.134/kWh = $39,704.40
Total cost of fridge over 5 years = $700 + $39,704.40 = $40,404.40Therefore, the Ice Cold Fridge is the more cost-effective option over 5 years, even though it has a lower power rating.
Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
What constant acceleration (in ft/s2) is required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds
Answer:
6.746 ft/s^2
Explanation:
v(t)=50
v(0)=27
t=5/3600 = 1/720 hours
v(t)-v(0)= a(t-0)
50-27= a(1/720)
a= 23*720= 16560 mi/h^2
16560mi/h^2 * 5280/3600^2 (ft/s^2) =6.746 ft/s^2
The acceleration required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds is 6.75 ft/s².
Acceleration is given by:
\( a = \frac{\Delta v}{\Delta t} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} \)
Where:
\( v_{f} \): is the final speed of the car = 50 mi/h
\( v_{i}\): is the initial speed of the car = 27 mi/h
\( \Delta t\): is the change in time = 5 seconds
The constant acceleration required is:
\( a = \frac{v_{f} - v_{i}}{\Delta t} \)
\( a = \frac{50 \frac{mi}{h}*\frac{1 h}{3600 s}*\frac{5280 ft}{1 mi} - 27 \frac{mi}{h}*\frac{1 h}{3600 s}*\frac{5280 ft}{1 mi}}{5 s} \)
\( a = 6.75 ft/s^{2} \)
Therefore, the constant acceleration required is 6.75 ft/s².
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