If John Glenn weighed 640 N on Earth's surface, a) how much would he haveweighed if his Mercury spacecraft had (hypothetically) remained at twice thedistance from the center of Earth? b) Why is it said that an astronaut is nevertruly "weightless?"

Answers

Answer 1

Given:

The weight of John Glenn, w=640 N

To find:

a) The weight if the distance was twice that of the initial value.

b) Why is an astronaut never weightless.

Explanation:

a)

Let the distance between the spacecraft and the earth be r.

If it becomes twice, then the distance is 2r.

The initial gravitational force on John Glenn is,

\(F=w=\frac{GMm}{r^2}\)

Where G is the gravitational constant, M is the mass of the earth and m is the mass of John Glenn.

The force when the distance is twice,

\(\begin{gathered} w_n=\frac{GMm}{(2r)^2} \\ =\frac{GMm}{4r^2} \\ =\frac{w}{4} \end{gathered}\)

On substituting the known values,

\(\begin{gathered} w_n=\frac{640}{4} \\ =160\text{ N} \end{gathered}\)

b)

Even when the astronaut is in space they still have the mass and so does the earth. Thus there will always be a gravitational force of attraction between the earth and the astronaut. The astronaut does not feel the weight because there will be nothing in space that pushes them back. That is why an astronaut is never truly weightless.

Final answer:

a) Thus the weight of John Glenn will be 160 N


Related Questions

If a proton is traveling north directly above the wire, what is the direction of the magnetic force on the proton due to the wire?

Answers

Answer:

Direction is downwards

Explanation:

This is by employing Flemings Right hand rule which says If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.

A 24.4-N force is applied to a cord wrapped around a pulley of mass M = 4.58-kg and radius R = 30.2-cm The pulley accelerates uniformly from rest to an angular speed of 26.8 rad/s in 2.23-s. If there is a frictional torque \tau = 1.48-mN at the axle,

(a) determine the moment of inertia of the pulley,

(b) determine the rough estimate of the moment of inertia.

(The pulley rotates about its center)

What is the difference be (a) and (b)?

Answers

a) The moment of inertia of the pulley can be determined by dividing the net torque by the angular acceleration: 0.4 kgm²

b) Using the given values of the mass (M = 4.58 kg) and radius (R = 30.2 cm = 0.302 m), we can calculate the rough estimate of the moment of inertia.

(a) To determine the moment of inertia of the pulley, we can use the principles of rotational dynamics. The net torque acting on the pulley is given by the difference between the applied torque and the frictional torque.

The applied torque can be calculated using the force applied to the cord and the radius of the pulley. The torque is given by the equation:

τ_applied = F * R

Substituting the given values, F = 24.4 N and R = 30.2 cm = 0.302 m, we can find τ_applied.

The frictional torque is given as τ_friction = -τ = -1.48 mN.

The net torque acting on the pulley is the sum of the applied and frictional torques:

τ_net = τ_applied + τ_friction

The angular acceleration α can be calculated using the relationship between angular acceleration, final angular velocity, initial angular velocity, and time:

α = (ω_final - ω_initial) / t

Substituting the given values, ω_initial = 0 rad/s, ω_final = 26.8 rad/s, and t = 2.23 s, we can find α = 12.8

Using the formula for net torque and angular acceleration:

τ_net = I * α

we can solve for the moment of inertia I:

I = τ_net / α= 0.4

Substituting the calculated values of τ_net and α, we can determine the moment of inertia of the pulley.

(b) The rough estimate of the moment of inertia can be obtained by considering the pulley as a uniform disk. The moment of inertia of a uniform disk rotating about its center is given by the formula:

I_disk = (1/2) * M * R^2

where M is the mass of the pulley and R is the radius.

Using the given values of the mass (M = 4.58 kg) and radius (R = 30.2 cm = 0.302 m), we can calculate the rough estimate of the moment of inertia.

The difference between (a) and (b) is the deviation caused by considering the actual situation with friction (taking into account the frictional torque at the axle) compared to the simplified assumption of a uniform disk without friction.

The inclusion of friction affects the net torque acting on the pulley, resulting in a different moment of inertia value compared to the rough estimate. The difference between the two values indicates the impact of friction on the rotational motion of the pulley.

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A 1 meter wide door is initially open at an angle of 30o as shown (top view). You push with 20 N force in the middle of the door as shown and the door rotates around the hinge on the left. The door has a rotational inertia =3.0 kg m2. The angular acceleration of the door will be:

Answers

Answer:

angular acceleration = 1.67 rad/s²

Explanation:

given data

door wide = 1 m

initially ope angle = 30°

push force = 20 N

rotational inertia = 3.0 kg m²

solution

we apply force at middle so length will be here r1 = \(\frac{1}{2}\)  = 0.5 m

and

now we get here torque that is express as

torque τ = Force × r1 × sin30   ......................1

put her value and we get

torque τ = 20 × 0.5 × sin30

torque τ = 5 Nm

and  we know

torque = rotational inertia × angular acceleration   .......................2

put her value and we get angular acceleration

angular acceleration = \(\frac{5}{3}\)  

angular acceleration = 1.67 rad/s²

6. The two ends of an iron rod are maintained at different temperatures. The amount of heat thatflows through the rod by conduction during a given time interval does notdepend uponA) the length of the iron rod.B) the thermal conductivity of iron.C) the temperature difference between the ends of the rod.D) the mass of the iron rod.E) the duration of the time interval.Ans: DDifficulty: MediumSectionDef: Section 13-27. The ends of a cylindrical steel rod are maintained at two different temperatures. The rod conducts heat from one end to the other at a rate of 10 cal/s. At what rate would a steel rod twiceas long and twice the diameter conduct heat between the same two temperatures

Answers

Answer:

20cal/s

Explanation:

Question:

There are two questions. The first one has been answered:

From the formular, Power = Q/t = (kA∆T)/l

the amount heat depends on the duration of time interval, length of the iron rod, the thermal conductivity of iron and the temperature difference between the ends of the rod.

The amount of heat that flows through the rod by conduction during a given time interval does not depend upon the mass of the iron rod (D).

Second question:

The ends of a cylindrical steel rod are maintained at two different temperatures. The rod conducts heat from one end to the other at a rate of 10 cal/s. At what rate would a steel rod twice as long and twice the diameter conduct heat between the same two temperatures?

Solution:

Power = 10cal/s

Power = energy per unit time = Q/t

Where Q = energy

Power = (kA∆T)/l

k = thermal conductivity of iron

A = area

Area = πr^2

r = radius

Diameter = d = 2r

r = d/2

Area = (πd^2)/4

Length = l

∆T = change in temperature

10 = (kA∆T)/l

For a steel rod with length doubled and diameter doubled:

Let Length (L) = 2l

Diameter (D)= 2d

Area = π [(2d)^2]/4 = (π4d^2)/4

Area = 4(πd^2)/4

Using the formula Power = (kA∆T)/l, insert the new values for A and l

Power = [k × 4(πd^2)/4 × ∆T]/2l

Power = [4k((πd^2)/4) ∆T]/2l

Power = [(4/2)×k((πd^2)/4) ∆T]/l

Power = [2k(A) ×∆T]/l = 2(kA∆T)/l

Power of a steel that has its length doubled and diameter doubled = 2(kA∆T)/l

Recall initial Power = (kA∆T)/l = 10cal/s

And ∆T is the same

2[(kA∆T)/l] = 2 × 10

Power of a steel that has its length doubled and diameter doubled = 20cal/s

1. How many valence electrons does each atom of arsenic (As) have? Arsenic is element 33. It is in period 4 and family 15 (5A or the Nitrogen family).

2.Two representative elements are in the same period of the periodic table. Which statement correctly describes the atoms of the two elements?

3. Helium is in group 18 of the periodic table. How is helium different from the other elements in this group?

4. Which element has atoms with valence electrons in a higher energy level than those of calcium (Ca)

5.Which statement best describes the arrangement of electrons in an atom of fluorine (F)?

Answers

A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls.

What is a representative element?

A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls. Now we will try to answer each of the questions.

1) The atoms of arsenic and nitrogen have five valence electrons

2) The statement that correctly describes the two representative elements are in the same period of the periodic table is that they belong to the same period and have the same number of shells.

3) Helium is different from the other members of group 18 because it has 2 and not eight valence electrons

4) The element that has  atoms with valence electrons in a higher energy level than those of calcium (Ca) is barium

5) The statements that best describes the arrangement of electrons in fluorine is that the the electronic configuration is [He] 2s2 2p5.

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Imagine that the satellite described in the problem introduction is used to transmit television signals. You have a satellite TV reciever consisting of a circular dish of radius RRR which focuses the electromagnetic energy incident from the satellite onto a receiver which has a surface area of 5 cm2cm2. How large does the radius RRR of the dish have to be to achieve an electric field vector amplitude of 0.1 mV/mmV/m at the receiver

Answers

Answer:

R₁ = 0.126 m

Explanation:

Let's use the definition of intensity which is the power per unit area

          I = P / A

the generated power is constant

          P = I A

power is

         P = E / t

if we perform the calculations for a given time, the wave energy is

        E = q V

we substitute

        P = \(\frac{q V\ A}{t}\)

we can write this equation for two points, point 1 the antenna and point 2 the receiver

         V₁A₁ = V₂A₂

          A₁ = \(\frac{V_2}{V_1} \ A_2\)

          A₁ = 0.1 10⁻³  5 10⁻⁴ /V₁

          A₁ = 5 10⁻⁸ /V₁

In general, the electric field on the antenna is very small on the order of micro volts, suppose V₁ = 1 10⁻⁶ V

           

let's calculate

          A₁ = 5 10⁻⁸ / 1 10⁻⁶

         A₁ = 5 10⁻² m²

the area of ​​a circle is

          A = π r²

we substitute

         π R1₁²= 5 10⁻²

         R₁ = \(\sqrt{ \frac{5 \ 10^{-2} }{\pi } }}\)

         R₁ = 0.126 m

What force pushes the plane upwards

Answers

Answer: The force that pushes a plane upwards is the lift generated by the wings as the plane moves through the air. The lift force is created by the difference in air pressure above and below the wings, which creates an upward force that opposes the weight of the plane.

If we wanted to use some brain-mapping techniques to identify anatomical functioning, but did not want to use any type of dye or tracer, which method below would be the best choice?
A. MRI
B. EEG
C. PET
D. SPECT

In PET scans, the breakdown of ___________ materials in the body and the release of gamma rays produce a functional view of the brain.
A. organic
B. radioactive
C. toxic
D. metallic

Answers

Since you wanted to use some brain-mapping techniques to identify anatomical functioning, the method that would be the best choice is option A. MRI.

In PET scans, the breakdown of option B:  radioactive materials in the body and the release of gamma rays produce a functional view of the brain.

What substance is employed in a PET scan?

FDG, which stands for "fluorodeoxyglucose," is a simple sugar (like glucose) that is frequently employed in PET scanning. It is injected into the bloodstream and builds up inside the body, where it emits gamma rays as energy.

Note that without injecting any kind of dye or tracer, brain mapping techniques like magnetoencephalography (MEG) and functional magnetic resonance imaging (fMRI) scans can be used to detect the anatomical functioning of the brain. The diagnosis and treatment of neurodegenerative illnesses can both benefit greatly from these techniques.

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1) How psychology is a science?

Answers

Psychology is a science because it makes use of scientific method such as observation, asking question, making prediction, etc to study the mind and behavior.

What is Psychology?

Psychology is the scientific study of mind and behavior.

The different types of Psychology include;

Abnormal PsychologyBiopsychologySocial PsychologyCognitive PsychologyDevelopmental PsychologyPersonality PsychologyForensic PsychologyIndustrial-Organizational Psychology

So we can conclude that Psychology is science because it uses scientific method to study the mind and behavior.

Scientific method entails the process of observing, asking questions, and seeking answers through tests and experiments is not unique to any one field of science.

The characteristics of scientific method include;

Making observation.Asking question.Forming a hypothesis, or testable explanation.Making a prediction based on the hypothesis.Testing the prediction.Iterate or repeating the process

Psychology applies such scientific method to arrive to a conclusion, hence we can conclude that Psychology is a science.

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NEED HELP ON QUESTION ASAP! !

If answer is correct I'll rate you five stars a thanks and maybe even brainliest!

Please can you explain what this paragraph is trying to say. Also what does it mean in the sentence 'the difference in charge across the battery provides push for current' and what is the difference in charge.



Here's paragraph I need to have a simple definition of:


A high waterfall is also like a large voltage. It will transfer a lot of energy to the water (charge), making the river flow very fast (a large current) the difference in height makes the river flow. In a circuit , the difference in charge across battery provides push for the current.

Answers

This paragraph is drawing an analogy between a high waterfall and an electric circuit to explain the concept of voltage and current.

It is saying that a high waterfall has a lot of potential energy that can transfer to the water and cause it to flow very fast, which is similar to how a large voltage in an electric circuit can create a large current. The difference in height of the waterfall causes the water to flow, just as the difference in charge across a battery provides the push or force for the current to flow in a circuit.

In an electric circuit, voltage is the measure of the electric potential difference between two points, and it is measured in volts. Current is the flow of electric charge through the circuit, and it is measured in amperes or amps. The difference in charge across the battery refers to the potential difference or voltage between the positive and negative terminals of the battery, which creates an electric field and provides the force or push for the current to flow through the circuit.

Grace is playing with her dolls and decides to give them a ride on a merry-go-round. She places one of them on an old record player turntable and sets the angular speed at 33.3 rpm. What is their angular speed in rad/s

Answers

Answer: \(3.48\ rad/s\)

Explanation:

Given

Angular speed in rpm is 33.3 rpm

To convert it into rad/s, multiply it with \(\frac{2\pi}{60}\)

Angular speed(rad/s)

\(\Rightarrow \dfrac{2\pi \times 33.3}{60}\\\\\Rightarrow 3.48\ rad/s\)

Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced human society as a whole.

Write a short essay describing the six key features of Mesopotamia. Be sure to include how it advanced

Answers

Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.

Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.

Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.

Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.

Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.

Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.

Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.

Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.

Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.

Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.

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A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.

Answers

The distance travelled by the vehicle around the circular track is 1,052.4 m.

What is the distance travelled by the vehicle in one complete cycle?

The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.

d = 2πr

d = πd

Where;

r is the radius of the circular trackd is the diameter of the circular track

In one complete cycle, the  vehicle will travel the circular track only once.

d = π(335 m)

d = 1,052.4 m

Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.

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The complete question is below:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?

An 8.0 Kg mass is placed at = 3 where should a 10 Kg mass be placed along the − so that the center of mass will be located ay = 4.5?

Answers

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

A 1020 kg car is pulling a 365 kg trailer. Together, the car and trailer have an acceleration of 2.21 m/s2 directly forward. (a) Determine the net force on the car. N forward (b) Determine the net force on the trailer. N forward

Answers

Answer:

a. 2936.2 N b. 773.8 N

Explanation:

Let m = mass of car = 1020 kg and m' = mass of trailer and a = acceleration = 2.12 m/s².

a. Determine the net force on the car. N forward

Since the car pulls both itself and the trailer, the combined mass is m + m' and the net force F on the car is F = (m + m')a

= (1020 kg + 365 kg)2.12 m/s²

= 1385 kg × 2.12 m/s²

= 2936.2 N

b. Determine the net force on the trailer. N forward

The net force F' on the trailer is F = m'a

= 365 kg × 2.12 m/s²

= 773.8 N

If the instantaneous voltage at a given moment in the circuit RL is V=VmaxSIN(150), then the instantaneous current at the...... same instant I=Imaxsin​

Answers

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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can someone please help me​

can someone please help me

Answers

Answer:

F = ma

10+15-5=2×a

20=2a

a = 10ms^-2

Review what you learned in the unit about attribution theory. Explain in your own words what it is. Describe how attributions affect the way we explain behavior. In what way can attribution theory be harmful? In what way can it be helpful?

Answers

Attribution theory describes how an individual says or thinks that something is a as a result of a person's deed or an action of an external factor.

The cause of behavior is attributed to some internal characteristic of a person rather than external forces.

It can be harmful because attributing a person's character to a mistake can lead to underestimation of an individual.

Attribution helps an individual to understand the reason behind another person's behavior and thinking.

What is Attribution theory?

Attribution theory is related to how ordinary people explain the causes of behavior and events that follow it. This helps them understand how they receive, interpret action, and how they give form an opinion of them.

When an person displays certain behaviors, they are usually attributed to certain internal characteristics. This theory can be harmful to explaining behavior because mistakes are attributed to character instead of external factors leading to underestimating people. On the other hand, it is beneficial to understanding people.

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A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2

Answers

As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.

Identify the body's starting velocity:

We may use the equation of motion to get the body's initial velocity (u)

\(v^2 = u^2 + 2as\)

\(0 = u^2 + 2(-9.8)m/s^2 * h\)

\(u^2 = 19.6h\)

u = √(19.6h)

Determine the coefficient of restitution (e):

The body's initial velocity (u) and initial relative velocity (u_rel) are the same.

The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).

\(e = v_{rel }/ u_{rel}\)

e = 0 / u_rel = 0 / u

Now, one can investigate the forces affecting the body: When a body is on an inclined plane.

There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).

The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).

Determine the conditions for the body to stop:

μ * N = m * g * sin(45°)

μ * (m * g * cos(45°)) = m * g * sin(45°)

μ * cos(45°) = sin(45°)

(1/2) * cos(45°) = sin(45°)

Simplifying further, we have:

√2 / 4 = √2 / 2

Thus, the body will come to rest following the collision if the equation is valid.

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Hand pushes on a table with a force of 35n forward.reaction force

Answers

Answer:

como  ías

Explanation:

Bonus Points. A ball was thrown straight up in the air from 1.2 meter above the grouind. After 3 seconds the ball returnes to the ground. Determine the maximum height it reached.

Answers

Answer:

Explanation:

given that

Distance above the ground, s = 1.2 m

Time taken by the ball, t = 3 s

Velocity of the ball, v = 1.2/3 = 0.4 m/s

Maximum height reached by the ball is then given by the formula

H = v² / 2g

H = 0.4² / 2 * 9.8

H = 0.16 / 19.6

H = 0.0082 m or rather, 0.82 cm

Use the following information to answer questions 6 and 7:
A61.0 kg grocery cart is sitting at rest. In order to change the cart's state of motion, Xavier must apply 72.1
Newtons of force on the cart.
6. How much magnitude of force does the cart exert back on Xavier's hand?
A. 4400 N
B. 1.20 N
C. 72.1 N
D. 0.00 N
After 10 seconds, the dirt has achieved a velocity of +3.62 m/s. Xavier is still applying 72.1 Not force on the
cart.
7. Xavier's sister Maria claims that the cart is in dynamic equilibrium. Is Maria correct?
A Maria is correct because the cart is traveling at a constant velocity while experiencing balanced
forces.
B. Maria is correct because the cart's velocity has changed.
C. Maria is incorrect because the cart is traveling at a constant velocity while experiencing
unbalanced forces.
D. Maria is incorrect because the cart's velocity has changed

Use the following information to answer questions 6 and 7:A61.0 kg grocery cart is sitting at rest. In

Answers

Question 6

C. 72.1 N

Its simply the newton Third law, whenever two objects interact, they exert equal and opposite forces on each other.

Question 7

D. Maria is incorrect because the cart's velocity has changed

The car is accelerating so, It is not in dynamic equilibrium. Remember that by the Newton Second Law:

F = ma

The cart is in dynamic equilibrium. The correct options for the two question are:

6. C

7. A

6.) Given that a 61.0 kg grocery cart is sitting at rest. And Xavier applied 72.1 Newtons of force on the cart.

According to Newton's third law of motion which state that, in every action, there will be equal and opposite reaction. The magnitude of force That the cart exert back on Xavier's hand will be opposite and equal to the force applied. which is negative 72.1 N

7.) If the grocery cart is moving in a constant velocity, then it will achieve a dynamic equilibrium. In this scenario, the air resistance force balances with the applied force.

Therefore,  Maria is correct because the cart is traveling at a constant velocity while experiencing balanced forces.

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A space station in the form of a large wheel,
356 m in diameter, rotates to provide an “artificial gravity” of 5.1 m/s2 for people
located at the outer rim.
What is the frequency of the rotational mo-
tion for the wheel to produce this effect? Answer in units of rev/min.

Answers

The frequency of the rotational motion for the wheel to produce this effect 1.62 rev/min.

What is the angular speed of the wheel?

The angular speed of the wheel is calculated by applying the formula for centripetal acceleration of the wheel.

a = v²/r = ω²r

where;

ω is the angular speed of the wheel in radian per secondsr is the radius of the wheel

The radius of the wheel = 356 m / 2 = 178 m

ω = √a/r

ω = √(5.1/178)

ω = 0.17 rad/s

The angular speed in revolution per minute is calculated as follows;

ω = 0.17 rad/s x 1 rev/2π rad x 60 s/1min

ω = 1.62 rev/min

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Which feature of a heating curve indicates a change of state

Answers

Answer:

The diagonal or the inclined lines shows the changes in terms of temperature, and the horizontal lines shows the changing of phases.

Explanation:

hope it is useful

what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k

Answers

The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.

To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:

C = A × B

Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.

Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:

C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)

Now, let's expand the cross product using the properties of vector products:

C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +

   (3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +

   (1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)

Now, let's calculate each of these cross products:

C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +

   (3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +

   (1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)

Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:

C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k

Combining like terms, we get:

C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)

Simplifying further:

C = 6.00i - 12.00j + k

Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.

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Final answer:

The vector product of A and B is -3i - 5j - 9k.

Explanation:

The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.

In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.

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Draw a free body diagram of an object with a mass of 2kg falling down with a constant velocity.

Use the object’s mass to determine its weight and add the information to the FBD.

Answers

The weight of the object is mg(mass•gravitational acceleration constant), which is 2•9.8=19.6
Draw a free body diagram of an object with a mass of 2kg falling down with a constant velocity.Use the

A 514 turn solenoid , 21 cm long has a diameter of 2.6 cm. A 14 turn coil is tightly wound around the center of the solenoid. If the current in the solenoid increases uniformly from 0.3 A to 2.79 A in 0.8 s, what will be the induced emf in the short coil during this time

Answers

Answer:

Explanation:

no of turns per unit length n = 514 / .21 = 2447.62 per meter .

magnetic field in solenoid = μ₀ nI

= 4π x 10⁻⁷ x 2447.62 x I = 3.07 x 10⁻³ I  T

magnetic flux through the small coil = 14 x 3.07 x 10⁻³ x π x 1.3² x10⁻⁴ I

φ= 72.63 x 10⁻⁷ I  Web

emf induced in it

= dφ / dt = 72.63 x 10⁻⁷ dI / dt

= 72.63 x 10⁻⁷ x ( 2.79 - .3) / .8

= 226 x 10⁻⁷ V

= 22.6 x10⁻⁶ V

= 22.6 μ V .

HELP PLS
3 paragraph summary/essay due today for science. I need a 3 paragraph summary with at least 7 sentences on Waves ! pls help.

Answers

There are a variety of waves from light waves to mechanical waves. Waves can exhibit different effects like the Doppler Effect.

All light waves behave in a similar manner. They either get  transmitted, reflected, absorbed, refracted, polarized, diffracted, or scattered based off of the composition of the object and the wavelength of the light.

According to Wikipedia, “One important property of mechanical waves is that their amplitudes are measured in an unusual way, displacement divided by (reduced) wavelength. When this gets comparable to unity, significant nonlinear effects such as harmonic generation may occur, and, if large enough, may result in chaotic effects.” Mechanical waves are chaotic and its “amplitudes” are measured unusually.

Diffraction is when light bends around objects and spread after passing out through small openings. “Diffraction occurs with all waves, including sound waves, water waves, and electromagnetic waves such as light that the eye can see.”-Wikipedia. Here is the formula to Diffraction: d sin θ =

Doppler effect can occur for any type of wave like sound or water waves. An example of this is when we hear a police car with its sirens on, coming towards us. The closer you are to the police car, the higher the wavelength, but the farther away you are, the lower the wavelength.

What is the magnitude of the resultant vector? Round
your answer to the nearest tenth.
m
R
5 m
13 m
Intro
Done

What is the magnitude of the resultant vector? Roundyour answer to the nearest tenth.mR5 m13 mIntroDone

Answers

Answer: 13.9 m

Explanation:

Answer:

13.9m

Explanation:

Answer on Edge

Abram lifts an 8.0 kilogram carton of milk straight up from the table, causing it to accelerate at a rate of 5.0 meters/seconds^2. how much force must he exert to accelerate the carton vertically from the table?

Answers

40 Newtons force must he exert to accelerate the carton vertically from the table.

What is accelaration?

Acceleration is a change in the velocity or speed of an object over a given period of time. It is the rate of change of an object's velocity, or the rate of change of its speed in a particular direction.

In order to calculate the force required to accelerate the carton of milk vertically from the table, we must use Newton's Second Law of Motion which states that the force (F) applied to an object is equal to its mass (m) multiplied by its acceleration (a). Therefore, the equation for calculating the force required for Abram to lift the carton of milk is given by:

F = ma

Where F is the force, m is the mass of the carton (8.0 kilograms) and a is the acceleration (5.0 meters/seconds^2).

Thus, the force required for Abram to lift the carton of milk vertically from the table is 8.0 kilograms x 5.0 meters/seconds^2 = 40 Newtons.

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