how many movements are there in a classical sonata?
Answers
In a classical sonata, there are typically four movements. Each movement serves a distinct purpose and has its own musical structure, character, and tempo.
These movements are arranged in a specific order and contribute to the overall narrative and emotional journey of the piece.The first movement of a classical sonata is usually in sonata-allegro form.
characterized by contrasting themes, development, and a recapitulation. It sets the stage for the entire composition and establishes the main musical ideas.
The second movement is often a slower and more lyrical piece, such as an adagio or andante. It provides a contrast to the energetic first movement, allowing for introspection and emotional depth.
The third movement is usually a minuet and trio or scherzo and trio. It serves as a lively and rhythmic interlude, often with a dance-like quality, adding a touch of lightness and playfulness to the sonata.
The final movement, known as the fourth movement, is typically a fast and spirited piece, such as an allegro or presto. It showcases virtuosity, excitement, and brings the sonata to a thrilling conclusion.
Overall, these four movements in a classical sonata provide a diverse and well-balanced musical experience, showcasing the range of emotions, technical skill, and compositional craftsmanship of the era.
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Related Questions
The following circuit contains three capacitors C₁ = 16 µF, C₂ 6μF, and C3 = 10µF connected to a battery with an unknown emf &. The charge on capacitor C₁is Q₁ = 12 uc. 1. What is the equivalent capacitance Ceq of the circuit? H₁₂ A. 75 x 10-6 F B. 8. 0 x 10-6 F C. 10. 0 x 10-6 F D. 12. 0 x 10-6 F E 2. How much energy is stored on capacitor C₁? A. 49 x 10-6 J C. 25 x 10-5) B. 3. 0 x 10-6/ C₂ tha C₂
Answers
The equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.
equivalent capacitance Ceq of a circuit with three capacitors in parallel can be found by adding the individual capacitances. In this case, C₁ = 16 µF, C₂ = 6 µ
F, and C₃ = 10 µ
F. So, Ceq = C₁ + C₂ + C₃
= 16 µ
F + 6 µ
F + 10 µ
F = 32 µF. Therefore, the answer to the first question is A. 75 x 10⁻⁶ F.
The energy stored on a capacitor can be calculated using the formula
E = 1/2 ×C ×V²
where E is the energy, C is the capacitance, and V is the voltage across the capacitor. Since the charge Q₁ on capacitor C₁ is given as 12 µC and the capacitance C₁ is 16 µF, we can calculate the voltage V₁ across capacitor C₁ using the formula Q = C ×V.
Thus, V₁ = Q₁ / C₁
= 12 µC / 16 µ
F = 0.75 V.
Now, we can calculate the energy stored on capacitor C₁ using the formula E₁ = 1/2 ×C₁ ×V₁²
= 1/2 ×16 µF ×(0.75 V)²
= 9 µJ.
Therefore, the answer to the second question is A. 49 x 10⁻⁶ J.
In conclusion, the equivalent capacitance Ceq of the circuit is 75 x 10⁻⁶ F, and the energy stored on capacitor C₁ is 49 x 10⁻⁶ J.
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A cross-country skier moves 36 meters eastward, then 44
meters westward, and finally 22 meters eastward.
For this motion, what is the distance moved?
Tap button at left to enter
Distance = 102
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number pad.
What is the magnitude and direction of the
displacement?
Magnitude =
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answer using our built-in
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Dir'n =
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Answer:
a) 102 meters
b) 14 meters
c) The direction is eastward.
Explanation:
Distance is said to be the length between two points. It is a scalar quantity.
a) The distance moved = 36 + 44 + 22
= 102 meters
b) Displacement is the distance moved in a specified direction.
Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22
/Displacement/ = +36 -44 +22
= +58-44
= 14
The magnitude of the displacement is 14 meters.
c) The direction is eastward.
So that the magnitude of displacement and his direction is 14 meters eastward.
what is the correct sequence of flow of electrical current in the cardiac conduction system? A. Purkinje fibers, AV nodes, SA node, bundle of His
B. AV node, SA node, bundle of His, Purkinje fibers
C. SA node, bundle of his, AV node, Purkinje fibers
D. SA node, AV node, Purkinje fibers, bundle of His
E. SA node, AV node, bundle of His, Purkinje fibers
Answers
The correct sequence of flow of electrical current in the cardiac conduction system is SA node, AV node, bundle of His, Purkinje fibers. This sequence can be found in option E.
Here is a brief explanation: The SA (sinoatrial) node initiates the electrical impulses that regulate the rhythm of the heartbeat. The electrical impulses from the SA node spread across the atria, causing them to contract. The AV (atrioventricular) node is the next point of the electrical conduction system, which slows the electrical signal as it passes through. The bundle of His is the pathway that conducts the impulses from the AV node to the ventricles, causing them to contract. The bundle of His divides into right and left branches, which travel along the interventricular septum towards the apex of the heart. The Purkinje fibers then carry the electrical impulses throughout the ventricles, causing them to contract in a coordinated manner.
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what happens when a jet breaks the sound barrier
Answers
Hello :)
Answer:
Sonic booms
Explanation:
When a jet breaks the sound barrier, most sonic booms can be heard as a short but loud clap of thunder. The intensity of a sonic boom does not change with higher or lower acceleration, rather, it is affected by the size of the airplane, e.g., a larger aircraft will displace a larger amount of air, resulting in a larger boom.
hope this helps :) !!!
which of the following is a basic method for single field transformation
Answers
One of the basic methods for a single field transformation is the arithmetic transformation method. In this method, a mathematical expression is used to transform data from one field into another.
Field transformation is the process of converting data in a field into a different form that meets the user's needs. It's critical to ensure that all of the data's critical elements are preserved during field transformations, and that the transformed data retains its integrity and meaning.
A single field transformation is a type of field transformation in which a single data field is transformed into a different form using a variety of methods. To transform data, the most popular techniques include arithmetic, bitwise, case, and date/time transformations.
These transformations allow the user to perform certain actions on the data within the field, such as swapping data bits, modifying data case, or converting a date/time format.The arithmetic transformation method is a basic technique for transforming data in a single field.
In this method, data is transformed using a mathematical expression that can add, subtract, multiply, or divide the values in a field. This transformation method is ideal for simple data manipulation, such as converting between units or scaling data, as well as more complex mathematical operations like averages and logarithms.
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the drag force from air resistance is given by F= pACv2/2. where p is the density of air, A is the cross-sectional area (assume to be a circle), C is the drag coefficient based on shape and v is the speed. You may guess that larger raindrops may have a larger terminal speed, but let's see if this is true. Assume a spherical raindrop of radius r and density p.. I) Derive an expression for the terminal speed of the raindrop in terms of r, C, g. pw and p. (where p, is the density of air that is in the drag force expression). Mass cannot be in your expression. il) From your expression, if you double the radius, what happens to the terminal speed?
Answers
The terminal speed of a raindrop is proportional to the square of the radius.
If the radius is doubled, the terminal speed will quadruple.
The terminal speed of a raindrop is the speed at which the drag force from air resistance balances the force of gravity. The drag force is given by F = pACv^2/2, where p is the density of air, A is the cross-sectional area, C is the drag coefficient, and v is the speed.
The cross-sectional area of a spherical raindrop is A = πr^2, where r is the radius of the raindrop.
The force of gravity is given by F = mg, where m is the mass of the raindrop and g is the acceleration due to gravity.
For a raindrop to reach its terminal speed, the drag force must equal the force of gravity. This means that pACv^2/2 = mg.
Solving for v, we get v = (2mg)/(pCπr^2).
The terminal speed is proportional to the square of the radius. This means that if the radius is doubled, the terminal speed will quadruple.
v = (2mg)/(pCπr^2)
If r = 2r, then v = (2mg)/(pCπ(2r)^2) = 4 * (2mg)/(pCπr^2) = 4v
Therefore, the terminal speed will quadruple.
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true or false: clear fluid leaking out of your car is usually coolant and means you should check the water pump.truefalse
Answers
False. Clear fluid leaking from a car is not necessarily coolant, and it does not necessarily indicate a problem with the water pump.
Cars can have multiple fluids that are clear or nearly clear in color, such as water, windshield washer fluid, or even condensation from the air conditioning system. Therefore, without further information, it is not possible to determine the exact fluid leaking based solely on its color.
To properly diagnose the issue, it is important to identify the specific location of the leak and consider other factors such as the fluid's smell, consistency, and the vehicle's symptoms or warning lights. If there is a coolant leak, it could be due to various reasons such as a damaged radiator, a leaking hose, a faulty coolant reservoir, or a malfunctioning water pump. However, it is not accurate to conclude that a clear fluid leak always indicates a problem with the water pump.
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Question 7.
When can a mouse have the same momentum as an elephant?
د ن ه ه
A. when the mouse has a large velocity and the elephant has a small velocity
when the mouse has a small velocity and the elephant has a large velocity
a mouse cannot have the same momentum as an elephant
D. when they both have the same velocity
Answers
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity. The correct option is A.
What is momentum?The momentum is the product of the mass of the object and its velocity.
Mouse has mass very less than the elephant. In order to make their momentum same, the velocity of the mouse must be greater than the elephant.
Mm x Vm = Me x Ve
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity.
Thus, the correct option is A.
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If the air pressure measures is 3 atm. How many mb of pressure is in the air?
Answers
Answer:
3
Explanation:
If there is 3 at the moment (atm) is the same as might be (mb) in the air.
Q1. How much gravitational potential energy do you gain when youwalk up the CN Tower stairs (346 m)?What type of energy/energies transformed into GPE in this scenario?
Answers
Given data:
* The distance traveled is 346 m.
Solution:
Let m be the mass of the body.
Then, the gravitational potential energy of the body on reaching the top of the tower is,
\(U=\text{mgh}\)where g is the acceleration due to gravity, and h is the height of the tower,
As mg is the weight of the body.
Substituting the known value,
\(U=w\times346\)where w is the weight of the body,
When a person walks to the certain height, the internal energy of the person's body is converted into the gravitational potential energy.
which one of the following is not equivalent to 2.50 miles? (1 mi = 1.609 km = 5280 ft, 1 ft = 12 in.)
a.1.32 times 104 ft
b.1.58 times 105 in.
c.4.02 times 103 km
d.4.40 times 103 yd
e.1.58 times 105 in.
Answers
4.40 times 103 yd is not equivalent to 2.50 miles.
So, the correct answer is D.
To determine which of the given options is not equivalent to 2.50 miles, we need to convert 2.50 miles to the respective units given in the options.
2.50 miles is equivalent to 4.02 times 103 km, which rules out option (c).
Now, we need to convert 2.50 miles to ft and in to compare with options (a), (b), and (e). 2.50 miles = 1.32 times 104 ft, which matches option (a), so it is equivalent to 2.50 miles.
Finally,
2.50 miles = 1.32 times 104 ft = 1.58 times 105 in, which matches option (e).
Therefore, the answer is option (D), 4.40 times 103 yd, as it is not equivalent to 2.50 miles.
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Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
Answers
Answer:
300 Newtons
Explanation:
Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.
The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have
Force = 12 × 25 = 300 Newtons or 300 N for short.
A rectangular box of negligible mass measures 5.0 m long, 1.0 m wide, and 0.50 m high. How many kilograms of mass can be loaded onto the box before it sinks in a lake having water of density 1000 kg/m3?
Answers
The box can hold a maximum of 2505 kg of mass before it sinks in the lake.
To determine the maximum mass that can be loaded onto the box before it sinks, we need to calculate the buoyant force exerted by the water on the box, which is equal in magnitude to the weight of the water displaced by the box.
The volume of water displaced by the box is given by:
Volume = length x width x height = 5.0 m x 1.0 m x 0.50 m = \(2.5 m^3\)
The weight of water displaced by the box is given by:
Weight = density x volume x gravity = \(1000 kg/m^3 x 2.5 m^3 x 9.81 m/s^2 = 24,525 N\)
Therefore, the maximum mass that can be loaded onto the box before it sinks is:
Maximum mass = weight / gravity = \(24,525 N / 9.81 m/s^2 = 2505 kg\)
So, the box can hold a maximum of 2505 kg of mass before it sinks in the lake.
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The rate at which a certain balloon travels is inversely proportional to the amount of weight attached to it if the balloon travels at 10 in./s and then there is a 2nd g weight attached to it approximately how much weight must be attached to the balloon for it to travel 18 in./s
Answers
The rate at which a certain balloon travels is inversely proportional to the amount of weight attached to it if the balloon travels at 10 in./s and then there is a 2nd g weight attached to it approximately the weight must be attached to the balloon for it to travel 18 in./s is 1.1 grams.
When 2 grams are added, the rate moves at 10 in/sec.
Since the weight and the distance traveled are inversely proportional, the expression can be written as
d= k/W
10 =k/2
k= 20
When 2 grams are attached, the rate moves at a speed of 10 in/second.
Given that the relationship between the weight and the traveled distance is inverse, this can be expressed as,
d= k/W
18= k/w
w= k/18
Substitute value of k in the above expression.
W= 20/18
W=1.11 gram
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a guitar string is 90.0 cm long and has a mass of 3.00 g . from the bridge to the support post (=ℓ) is 60.0 cm and the string is under a tension of 533 n . What are the fre-
quencies of the fundamental and ?rst two overtones?
what does it mean by fundamental and overtones and how would youstart doing this problem
Answers
The frequencies of the fundamental and first two overtones of the guitar string are approximately 63.333 Hz, 126.666 Hz, and 190 Hz, respectively.
The fundamental frequency of a vibrating guitar string refers to the lowest frequency at which the string can vibrate, producing the basic tone or pitch. Overtones, also known as harmonics, are higher frequencies that resonate simultaneously with the fundamental frequency, creating a richer sound.
To solve this problem step by step, we can start by calculating the linear density (μ) of the string using the given mass and length:
μ = mass/length
= 3.00 g / 90.0 cm
= 0.0333 g/cm
Next, we can calculate the fundamental frequency (\(f_1\)) using the following formula:
\(f_1\) = (1/2L) × √(T/μ)
Substituting the given values:
L = 90.0 cm
T = 533 N
μ = 0.0333 g/cm (convert to kg/m by dividing by 1000)
\(f_1\) = (1/2 × 0.9 m) × √(533 N / (0.0333 kg/m))
= 0.5 × √(16036.04)
= 0.5 × 126.6667
= 63.333 Hz
So, the fundamental frequency (\(f_1\)) of the guitar string is approximately 63.333 Hz.
To calculate the frequencies of the first two overtones (\(f_2\) and \(f_3\)), we can use the formula \(f_n\) = n\(f_1\), where n is the harmonic number.
\(f_2\) = 2 × \(f_1\)
= 2 × 63.333 Hz
= 126.666 Hz
\(f_3\) = 3 × \(f_1\)
= 3 × 63.333 Hz
= 190 Hz
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What is health literacy?
Answers
Health literacy is knowing about health and knowledge of of right healthcare and services, taking care of diseases or just knowledge or taking care of your own health.
So what is 27+22? Is it
A 8338
B 8282
C 8228
D 8234
Answers
Answer:
You put the add sign, so it would be 49. I don't believe that is what you meant to put though.
Explanation:
i gotchu, 27+22 so you take the 8 and multiply that by the number of times you blink every 2 minutes and then divide that by 0×1 and carry the 3 and that gives you -7
accelerates uniformly from rest, reaching a speed of 36 meters per second in 6.0 seconds
Answers
Answer:
What's the question?
Explanation:
Please help, I have no idea what story I can make out of these..
Make up a short story that uses these three constellations: Orion, Taurus, and Canis Major
Thank you!
Answers
Constellation is a group of stars that appears to form a pattern or picture. Some of the constellations include Orion, Taurus, Canis Major etc.
Orion is located on the celestial equator and it can be seen throughout the world. This constellation is named after the hunter, in Greek mythology. It is one of the most obvious and recognizable constellations in the sky. Orion is most visible in the evening sky from January to April, during winter season in the Northern Hemisphere, and summer season in the Southern Hemisphere. In the tropics, the constellation moves at the zenith. Orion is bordered by Taurus to the northwest, and by other constellations in other directions.
Taurus is one of the constellations of the 12 zodiac signs. It is a large and prominent constellation in the Northern Hemisphere during winter. It is one of the oldest constellations. The International Astronomical Union gave a three-letter abbreviation for the constellation, as "Tau". During late November-early December, Taurus occupies a furthest point from the Sun and is visible the entire night. By late March, it sets at sunset and completely disappears behind the Sun's glare from May to July.
Canis Major is a constellation in the southern celestial hemisphere. It is a Latin name, which means 'greater dog' in contrast to 'Canis Minor' meaning 'lesser dog'. These both figures are commonly represented as following the constellation of Orion, the hunter, through the sky. Canis Major contains Sirius, the brightest star in the night sky, known as the "dog star". It is bright because of its proximity to the Solar System.
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A boat uses its motor to increase its speed from 5 m/s to 7 m/s. If the boat has a mass of
250 kg, what was the impulse applied by the motor?
Answers
Answer:
J = 500 kg-m/s
Explanation:
Given that,
Initial speed of the motor, u = 5 m/s
Final speed of the motor, v = 7 m/s
Mass of the boat, m = 250 kg
We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.
J = m(v-u)
J = 250 (7-5)
J = 500 kg-m/s
Hence, the impulse applied by the motor is 500 kg-m/s.
Suppose 900 kg satellite is orbiting the earth one earth radius above the surface: Q1) Find the force of gravity between the earth and the satellite Q2) Find the orbital period of the satellite_ Q3) Find the tangential velocity required to keep the satellite in orbit: Q4) Find the angular velocity of the satellite:
Answers
(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.
(2) The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.
(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.
(4) The angular velocity of the satellite is 0.0011 radians per second.
(1) The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)
(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.
(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.
(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.
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10. A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?
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A resistor of 10.0 M2 is in series with a capacitor of 4 yF, and a power source of 5 V. A switch in the circuit is open and the capacitor has no charge. At t=0, the switch is closed, completing the circuit and the capacitor begins to charge. Recall that vc(t) = Vsource ((1 - e^(-t/t)). a) What is the voltage across the capacitor at time zero? b) What is the significance of the time at which the voltage is 63% of the maximum voltage on the capacitor? c) Calculate the time constant for this circuit. d) What is the voltage across the capacitor at 15 s? e) How long will it take the capacitor to reach 4.5 V?
Answers
a) The voltage across the capacitor at time zero is zero. b) The significance of the time at which the voltage is 63% of the maximum voltage on the capacitor is that it is equal to the time constant of the circuit. c) The time constant for this circuit is given by the formula RC. d) vc(15 s) = 3.22 V. e) t = 92 s.
When the switch is open, there is no current flow in the circuit and the capacitor is uncharged. When the switch is closed, current begins to flow and the capacitor starts to charge. The voltage across the capacitor rises over time until it reaches its maximum value, which is equal to the voltage of the power source.
The time constant of the circuit determines how quickly the capacitor charges and how quickly the voltage across it rises to its maximum value. In this circuit, the time constant is 40 seconds.
To find the voltage across the capacitor at any time t, we use the formula for voltage across a charging capacitor:
vc(t) = Vsource((1 - e^(-t/RC)).
We can use this formula to find the voltage across the capacitor at 15 s, which is 3.22 V.
To find how long it will take the capacitor to reach a certain voltage, we set vc(t) equal to that voltage and solve for t.
In this case, it will take 92 s for the capacitor to reach 4.5 V.
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Where is a proton located within an atom?
A. Anywhere within the atom
B. In the cloud around the nucleus
C. Attached to an electron
D. In the nucleus of the atom
Answers
Answer:
in the nucleus of the atom
Explanation:
a p 3 x
Frank pushes with a force of 620 N on a filing cabinet with a mass of 60 g. The cabinet doesn’t move.
What can be inferred?
Answers
When Frank exerts push with a force of 620 N over a filing cabinet with a mass of 60 g. The cabinet doesn’t move. it can be inferred that The static friction force of the floor and cabinet is greater than 620 N.
What is static friction?A type of force which holds an object at the state of rest is termed as static friction. we can define the static friction as The resistance person feel when he attempts to move a stationary object over a surface without actually causing any relative motion between his body and the surface they are moving the object across.To know more about static friction visit
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The complete question is :
Frank pushes with a force of 620 N on a filing cabinet with a mass of 60 g. The cabinet doesn't move.
What can be inferred?
A. There are no other forces acting on the filing cabinet.
B. The static friction force of the floor and cabinet is greater than 620 N.
C. The net force of the cabinet is greater than 620 N.
D. The friction force of the floor and cabinet is less than 620 N.
A beaker containing 400g of water has 1200J of work done on it by stirring and 200cal of heat added to it from a hot plate.8.What is the temperature change of the water?A.1.2°C B.2.1°C C.1.4°C D.4.1°C
Answers
A.1.2°C
ExplanationThe First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy.
To find internal energy, you have to add the heat added in the system and work done in the system because the work done is not lost but rather it is added in the system.
\(\begin{gathered} \Delta U=q+W \\ where\Delta U\text{ is the change in the internal energy} \\ q\text{ the heat added to the system} \\ W\text{ is the work done by the systeme} \end{gathered}\)Step 1
a)let
\(q=200\text{ cal}\)to add the energy it must have the same measure unit, so let's convert calories into Julies
remember that
\(\begin{gathered} 1\text{ cal}\Rightarrow4.184\text{ J} \\ so \\ 200\text{ cal}\Rightarrow200(4.814\text{ J})\Rightarrow836.8\text{ J} \end{gathered}\)b) now, replace in the formula
\(\begin{gathered} \Delta U= q+W \\ \Delta U=836.8\text{ J+1200 J} \\ \Delta U=2036.8\text{ J} \end{gathered}\)now, we have the change of internal energy
Step 2
now, let's find the change in temperature
Use the calorimetry formula.
\(\begin{gathered} Q=mc∆T \\ \end{gathered}\)where m is the mass, Q = heat energy, c = specific heat capacity, and ∆T = change in temperature
a)
let
\(mass=\text{ 0.4 kg}\)now,
\(\begin{gathered} Q=mC\Delta T \\ 2036.8\text{ j=0.4 kg*4184 }\frac{J}{Kg}|C*\Delta T \\ 2036.8=1673.6\Delta T \\ divide\text{ both sides by 1673.6} \\ \frac{2,036.8}{1673.6}=\frac{1,673.6\text{ }\Delta T}{1673.6} \\ 1.21=\Delta T \\ rounded \\ \Delta T=1.2\text{ \degree C} \end{gathered}\)so, the answer is
A.1.2°C
Thirteen resistors are connected across points A and B as shown in the figure. If all the resistors are
accurate to 2 significant figures, what is the equivalent resistance between points A and B?
Answers
The equivalent resistance between points A and B in the diagram is 22 Ω
How do I determine the equivalent resistance?We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:
Resistor 1 (R₁) = 6 ΩResistor 2 (R₂) = 6 ΩResistor 3 (R₃) = 6 ΩEquivalent resistance (Rₜ) = ?1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₜ = 1/6 + 1/6 + 1/6
1/Rₜ = 3/6
1/Rₜ = 1/2
Rₜ = 2 Ω
Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:
Resistor 1 (R₁) = Resistor 2 (R₂) = ... = Resistor (R₁₁) = 2 ΩEquivalent resistance (R) =?R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁
R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
R = 22Ω
Thus, we can conclude that the equivalent resistance is 22 Ω
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A cat pushes a 0.25 kg toy across the floor, causing it to accelerate at 32 m/s?. What
net force would the cat have had to apply to the toy in order to cause this acceleration?
Answers
Answer:
8 N
Explanation:
F = ma, therefore F = 0.25 kg * 32m/s^2.
a 2.0 kg block is forced against a horizontal spring of negligible mass, compressing the spring by 15 cm. when the block is released from the compressed spring, it moves 60 cm across a horizontal tabletop before coming to rest. the force constant of the spring is 200 n/m. calculate the coefficient of sliding friction between the block and the table
Answers
The block and table have a sliding friction coefficient of 0.083.
What leads to conflict?Although friction is assumed to be created by the interaction between the microscopic bumps on surfaces when they brush against each other, scientists are not entirely sure what causes it. It is challenging for the surface to slide over one another because the spikes on each surface flex and exert stress on one another.
What can lessen abrasion?The friction between both the edges can be decreased by using lubricants like oil or grease. Friction can be decreased by cleaning the surface, which makes it smooth.
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What is the answer for y = 4cos(5x)?
Answers
Maybe this graph can help?
