how do you know where to put the decimal point in problem 6?

6. 4 × 1.18 ​

The required explicit formula for the given sequence to determine the nth term is given as nth term = 8 + (n - 1)3.

Arithmetic progression is the series of numbers that have common differences between adjacent values.

here,
The Sequences 8, 11, 14,...

first term a = 8
common difference = 11 - 8 = 3

Now,
The explicit formula is given as,
nth terms = a + (n - 1)d
nth term = 8 + (n - 1)3

Thus, the required explicit formula for the given sequence to determine the nth term is given as nth term = 8 + (n - 1)3.

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Answer:

No he's too poor

Step-by-step explanation:

Answer:

10  yd

Step-by-step explanation:

The answer is:

5/4

Work/explanation:

Let's work out the slope of the line.

The equation is in y = mx + b form where m = slope; b = y intercept.

Similarly, in y=5/4x - 7/4, the slope is 5/4.

The -value of the test is 1.90. This indicates that the mean processing time is significantly greater than 5.5 hours, supporting the manufacturer's desire to set a standard time required by employees to complete a certain process

The t-value will be equal to 1.39 for the given statistics.

To test if the mean processing time exceeds 5.5 hours, we can use a one-sample t-test.

The null hypothesis is that the mean processing time is less than or equal to 5.5 hours:

H0: µ ≤ 5.5

The alternative hypothesis is that the mean processing time is greater than 5.5 hours:

Ha: µ > 5.5

We will use a significance level of 0.05.

The formula for the t-test statistic is:

t = (X - µ) / (s / √n)

Where:

X = sample mean

µ = hypothesized population mean

s = sample standard deviation

n = sample size

Substituting the given values, we get:

t = (6 - 5.5) / (2 / √21) = 1.386

The degree of freedom for the t-test is n-1 = 20.

Using a t-table or calculator, the p-value associated with a t-value of 1.386 and 20 degrees of freedom is 0.093.

Since the p-value (0.093) is greater than the significance level (0.05), we fail to reject the null hypothesis. Therefore, there is not enough evidence to suggest that the mean processing time exceeds 5.5 hours.

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Answer:

0.325 hits per bat

Step-by-step explanation:

13/40=0.325

As n = 18, We need at least 18 terms in the Taylor series for f(x) = ln x expanded about x = 1 to guarantee an accuracy of at least 1x10^-10 in the approximation of ln 1.055.

To find the number of terms in the Taylor series for f(x) = ln x expanded about x = 1 that will guarantee an accuracy of at least 1x10^-10 in the approximation of ln 1.055, we need to use the Taylor series formula:

f(x) = f(a) + f'(a)(x-a) + (1/2)f''(a)(x-a)^2 + ...

For ln x expanded about x = 1, we have:

f(x) = ln x
f(a) = ln 1 = 0
f'(x) = 1/x
f'(a) = 1
f''(x) = -1/x^2
f''(a) = -1

Substituting these values into the formula, we get:

ln x = 0 + 1(x-1) - (1/2)(-1)(x-1)^2 + ...

Simplifying, we get:

ln x = (x-1) + (1/2)(x-1)^2 - (1/3)(x-1)^3 + ...

To find the number of terms needed for an accuracy of at least 1x10^-10 in the approximation of ln 1.055, we can use the remainder formula:

Rn(x) = (1/(n+1))f^(n+1)(c)(x-a)^(n+1)

Where c is some value between x and a. In this case, we have:

Rn(1.055) = (1/(n+1))(-1/c^2)(1.055-1)^(n+1)

To guarantee an accuracy of at least 1x10^-10, we need:

|Rn(1.055)| ≤ 1x10^-10

Substituting in the values, we get:

|(1/(n+1))(-1/c^2)(0.055)^(n+1)| ≤ 1x10^-10

Taking the absolute value, we get

(1/(n+1))(0.055)^(n+1)/(c^2) ≤ 1x10^-10

Since c is some value between 1 and 1.055, we can take c = 1.055 to get the maximum value of the remainder. Substituting in the values, we get:

(1/(n+1))(0.055)^(n+1)/(1.055^2) ≤ 1x10^-10

Simplifying, we get:

n ≥ 17.21

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When we have a normal model for the sampling distribution, we cannot say that a sample mean or sample proportion is approximately 2 standard errors (ses) away from the population mean or the true proportion.

Instead, we can say that 95% of the sample proportions fall within two standard errors of the population proportion. Similar to this, the percentage of sample proportions decreases as the standard error distance decreases and increases as the standard error distance increases.

Therefore, the standard error distance will be greater than 2 standard errors (ses) if 99% of the sample proportions are within a given standard error distance of the population proportion.

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Answer:

12

Step-by-step explanation:

She can host the greatest amount of people will be 12, such that there are no leftovers and each person will receive the same number of sandwiches and scones, respectively.

Factorization, also known as factoring, is the breakdown of one element into a product of other objects, or factors, which when multiplied together generate the original.

Given that She has 60 tea sandwiches and 48 scones to serve

We have to determine the Greatest Common Factor (GCF) between 60 and 48

We need to write 60 and 48 as the product of their prime factors,

⇒ 2 × 2 × 3 × 5.

⇒ 3 ×2 × 2 × 2 × 2.

Here the Greatest Common Factor (GCF) is 12.

Thus, she can host the greatest amount of people will be 12, such that there are no leftovers and each person will receive the same number of sandwiches and scones, respectively.

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The power set in roster notation requires listing all the possible subsets of a set, including the empty set and the set itself. The number of subsets in a power set can be calculated using the formula 2^n, where n is the number of elements in the original set.

The power set of a set is the set of all its subsets, including the empty set and the set itself. To write out the power set in roster notation, we need to list all the possible subsets of a given set.
(a) The set {a} has two subsets: {a} and {}. Therefore, the power set of {a} in roster notation is {{}, {a}}.
(b) The set {1,2} has four subsets: {1,2}, {1}, {2}, and {}. Therefore, the power set of {1,2} in roster notation is {{}, {1}, {2}, {1,2}}.
It is important to note that the cardinality (number of elements) of the power set of a set with n elements is 2^n. For example, the set {1,2} has two elements, so its power set has 2^2 = 4 subsets. Similarly, the set {a} has one element, so its power set has 2^1 = 2 subsets.
In conclusion, writing out the power set in roster notation requires listing all the possible subsets of a set, including the empty set and the set itself. The number of subsets in a power set can be calculated using the formula 2^n, where n is the number of elements in the original set.

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Answer:

C

Step-by-step explanation:

Short explanation:

Using the unit circle, the answer is C.

If you want a full in depth, answer:

The unit circle has a radius of 1.

3pi/4 is located in the 2nd quadrant.

That radian measures 135 degrees.

The 2nd quadrant start after 90 degrees.

To find the terminal angle, subtract 90 from 135.

Which gives you 45.

This means we are dealing with a 45-45-90 triangle.

Since our hypotenuse is 1, our y and x have to be

\( \frac{ \sqrt{2} }{2} \)

Sin is positve in the 2nd quadrant so C is the answer.

Answer:

Equations made up of multiple variables like formulas.

Step-by-step explanation:

Similar to how y = mx+b has many letters in it but we can input known values to solve for the values that we want.

For the function f(x) = cx, where c is a nonzero real number:

A vertical asymptote occurs when the function approaches infinity or negative infinity as the input approaches a certain value. For the function f(x) = cx, this does not happen as the input can be any real number and the output will always be a real number multiplied by a constant factor.

The horizontal asymptote is the value that the function approaches as the input becomes very large or very small. For the function f(x) = cx, as x becomes larger and larger in magnitude, the value of cx becomes closer and closer to 0, regardless of the value of c. So, the horizontal asymptote is y = 0.

The domain of a function is the set of all input values for which the function produces a valid output. For the function f(x) = cx, the input can be any real number, so the domain is all real numbers.

The range of a function is the set of all output values for which the function produces a valid output. For the function f(x) = cx, the output will always be a real number multiplied by a constant factor. If c is nonzero, the output will always be a non-zero real number, so the range is all real numbers. However, if c = 0, the function will output y = 0 for every x and thus the range would be only {0}

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In Excel, the "frequency" function calculates the count of values that are greater than the previous bin and equal to or less than the bin number to the left of the frequency.

This means that it includes the values that fall within the current bin range. The "frequency" function is commonly used in data analysis to create a frequency distribution. The function takes two arguments: the data range and the bin range.

The data range specifies the values you want to analyze, while the bin range specifies the intervals or categories for the frequency distribution. By using the "frequency" function, you can easily determine the number of values that fall within each bin of your distribution.

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\(\large\underline{\sf{Solution-}}\)

\(\sf \longmapsto x + y = 7 \: \: - - - (i)\)

\(\sf \longmapsto 3x - 2y = 11 \: \: - - - (ii)\)

By first equation,

\(\sf \longmapsto x + y = 7\)

\(\sf \longmapsto x = 7 - y\)

Now, we can find the original value of y.

\(\sf \longmapsto 3x - 2y = 11\)

\(\sf \longmapsto 3(7 - y) - 2y = 11\)

\(\sf \longmapsto 21 - 3y - 2y = 11\)

\(\sf \longmapsto 21 - 5y = 11\)

\(\sf \longmapsto - 5y = 11 - 21\)

\(\sf \longmapsto - 5y = - 10\)

\(\sf \longmapsto y = \dfrac{ - 10}{ - 5} \)

\(\sf \longmapsto y = 2\)

Now, we can find the original value of x.

\(\sf \longmapsto x + y = 7\)

\(\sf \longmapsto x + 2 = 7\)

\(\sf \longmapsto x = 7 - 2\)

\(\sf \longmapsto x = 5\)

Therefore, the values of x and y are 5 and 2 respectively.

Answer:

There are 2 solutions to square root x = 9

They are 3, and -3

Step-by-step explanation:

The square root of x=9 has 2 solutions,

The square root means, for a given number, (in our case 9) what number times itself equals the given number,

Or, squaring (i.e multiplying with itself) what number would give the given number,

so, we have to find the solutions to \(\sqrt{9}\)

since we know that,

\((3)(3) = 9\\and,\\(-3)(-3) = 9\)

hence if we square either 3 or -3, we get 9

Hence the solutions are 3, and -3

There are some disadvantages to using this type of data collection is:

"Information available from the question"

In the question:

After gathering data on the effectiveness of company meetings, you decide to conduct a survey to obtain measurable qualitative and quantitative feedback. you will mail a survey to several companies.

To write the disadvantages to using this type of data collection.

Now, According to the question:

There are some disadvantages to using this type of data collection is:

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Answer:

y = 2x + 1

Step-by-step explanation:

The equation that models this situation is

y = 2x + 1.

The slope represents the amount of pages he completes every hour and the y-intercept represents how many papers George has already done.

Answer:

  Emille's soccer team

Step-by-step explanation:

You want to know the higher win/loss ratio of Emille's 9/12 or Grant's 10/15.

One way to compare the fractions is to subtract one from the other:

  9/12 -10/15 = (9·15 -12·10)/(12·15) = (135 -120)/(12·15) = 1/12

This is a positive number, so the fraction 9/12 is higher.

Emille's team's win/loss ratio is higher because subtracting the win/loss ratio of Grant's team gives a positive result.

__

Additional comment

Grant's team's ratio reduces to 2/3, which can be expressed as 8/12. This is clearly lower than 9/12.

The chocolate for 140 bon-bons would cost approximately $6.13.

1. Calculate the volume of each chocolate bon-bon using the formula for the volume of a sphere: V = (4/3)πr³, where r is the radius.

  V = (4/3)π(0.7 cm)³

  V ≈ 1.437 cm³

2. Determine the mass of each chocolate bon-bon using the density formula: density = mass/volume.

  density = 1.27 g/cm³

  mass = density * volume

  mass ≈ 1.27 g/cm³ * 1.437 cm³

  mass ≈ 1.826 g

3. Calculate the total mass of chocolate needed for 140 bon-bons.

  total mass = mass per bon-bon * number of bon-bons

  total mass ≈ 1.826 g * 140

  total mass ≈ 255.64 g

4. Determine the cost of the chocolate by multiplying the total mass by the cost per gram.

  cost = total mass * cost per gram

  cost ≈ 255.64 g * $0.04/g

  cost ≈ $10.2256

5. Round the cost to the nearest cent.

  cost ≈ $10.23

Therefore, the chocolate for 140 bon-bons would cost approximately $6.13.

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Answer:

9ft

Step-by-step explanation:

I'm not sure, sorry if this didn't help you have a good day

The binormal vector B is sqrt(2)(sin(t) - cos(t)), and the torsion is -(2sin(t) - 2cos(t)) * (sin(t) + cos(t)).

To find the binormal vector and torsion for the given space curve, we first need to compute the cross product of the tangent vector T and normal vector N. Then, we can use this cross product to determine the binormal vector B. Lastly, we can compute the torsion using the formula:

torsion (t) = (dot product of B and dN/dt) / |T|

Given information:

T = cos(t) - sin(t) i + sin(t) + cos(t) j

N = 12 i + cos(t) - sin(t) j

|T| = sqrt((cos(t) - sin(t))^2 + (sin(t) + cos(t))^2) = sqrt(2)

dN/dt = -sin(t) - cos(t) i - cos(t) - sin(t) j

Step 1: Compute the cross product of T and N:

T x N = (cos(t) - sin(t)) * (cos(t) - sin(t)) - (sin(t) + cos(t)) * (cos(t) - sin(t)) = 2sin(t) - 2cos(t)

Step 2: Normalize the cross product to find the binormal vector B:

B = (2sin(t) - 2cos(t)) / sqrt(2) = sqrt(2)(sin(t) - cos(t))

Step 3: Compute the torsion:

torsion (t) = (dot product of B and dN/dt) / |T|

= [(2sin(t) - 2cos(t)) * (-sin(t) - cos(t))] / sqrt(2) / sqrt(2)

= -(2sin(t) - 2cos(t)) * (sin(t) + cos(t))

Therefore, the binormal vector B is sqrt(2)(sin(t) - cos(t)), and the torsion is -(2sin(t) - 2cos(t)) * (sin(t) + cos(t)).

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\(\displaystyle |\Omega|=\binom{n}{2}=\dfrac{n!}{2!(n-2)!}=\dfrac{n(n-1)}{2}\\|A|=\binom{3}{2}=3\\\\P(A)=\dfrac{3}{\dfrac{n(n-1)}{2}}=\dfrac{6}{n(n-1)}\)

Answer:

6

Step-by-step explanation:

5AM said he had no plans for a new one is the difference is that you are a little too busy and the differences

Answer:

o ok what i cant see it

Step-by-step explanation:

Answer:

c because a and b and d does not make since

Step-by-step explanation:

Answer:

C, vertically compressed by a factor of 4 and shifted 11 units down

Step-by-step explanation:

We can use Stokes' theorem to evaluate the line integral of the curl of a vector field F around a closed curve C, by integrating the dot product of the curl of F and the unit normal vector to the surface S that is bounded by the curve C.

Mathematically, this can be written as:

∫∫(curl F) · dS = ∫C F · dr

where dS is the differential surface element of S, and dr is the differential vector element of C.

In this problem, we are given the vector field F = (2y cos z, ex sin z, xey), and we need to evaluate the line integral of the curl of F around the hemisphere x^2 + y^2 + z^2 = 9, z ≥ 0, oriented upward.

First, we need to find the curl of F:

curl F = (∂Q/∂y - ∂P/∂z, ∂R/∂z - ∂Q/∂x, ∂P/∂x - ∂R/∂y)

where P = 2y cos z, Q = ex sin z, and R = xey. Taking partial derivatives with respect to x, y, and z, we get:

∂P/∂x = 0

∂Q/∂x = 0

∂R/∂x = ey

∂P/∂y = 2 cos z

∂Q/∂y = 0

∂R/∂y = x e^y

∂P/∂z = -2y sin z

∂Q/∂z = ex cos z

∂R/∂z = 0

Substituting these partial derivatives into the curl formula, we get:

curl F = (x e^y, 2 cos z, 2y sin z - ex cos z)

Next, we need to find the unit normal vector to the surface S that is bounded by the hemisphere x^2 + y^2 + z^2 = 9, z ≥ 0, oriented upward. Since S is a closed surface, its boundary curve C is the circle x^2 + y^2 = 9, z = 0, oriented counterclockwise when viewed from above. Therefore, the unit normal vector to S is:

n = (0, 0, 1)

Now we can apply Stokes' theorem:

∫∫(curl F) · dS = ∫C F · dr

The left-hand side is the surface integral of the curl of F over S. Since S is the hemisphere x^2 + y^2 + z^2 = 9, z ≥ 0, we can use spherical coordinates to parameterize S as:

x = 3 sin θ cos φ

y = 3 sin θ sin φ

z = 3 cos θ

0 ≤ θ ≤ π/2

0 ≤ φ ≤ 2π

The differential surface element dS is then:

dS = (∂x/∂θ x ∂x/∂φ, ∂y/∂θ x ∂y/∂φ, ∂z/∂θ x ∂z/∂φ) dθ dφ

= (9 sin θ cos φ, 9 sin θ sin φ, 9 cos θ) dθ dφ

Substituting the parameterization and the differential surface element into the surface integral, we get:

∫∫(curl F) · dS = ∫C F ·

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Consequently, 119,143 votes were cast in all. Bill received 53,130 votes and Corrine received 66,013 votes.

Consequently, 119,143 votes were cast in all.

The result is: 119,143 - 12,883 = 106,260

if we deduct the sum from what Corrine received. The result is 106,260 divided by 2

106,260 / 2 = 53,130

which equals 53,130.

53,130 plus the additional 12,883 votes

Corrine received equals 66,013.

Bill received 53,130 votes and Corrine received 66,013 votes.

For instance, if a property is damaged, three insurers who each provide $60,000 in coverage are each given 50% of the claim. Real estate, workers' compensation, and the distribution of financial advantages are further examples of allocation. Establish the appropriate representational threshold for each representative. Calculate this by dividing the total number of representatives by the combined population of all the states.

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Answer:

x=13/3

Step-by-step explanation:

Answer:

y=-6x+1

Step-by-step explanation:

Answer:

y=-3x+2

Step-by-step explanation: