Answer:
x = \(\frac{9}{4}\)
Step-by-step explanation:
Given
\(\frac{4x}{x+1}\) - \(\frac{5}{x}\) = \(\frac{4}{x^2+x}\) ← factor denominator
\(\frac{4x}{x+1}\) - \(\frac{5}{x}\) = \(\frac{4}{x(x+1)}\)
[ x ≠ 0, x ≠ - 1 as these would make the terms undefined ]
Multiply through by x(x + 1)
4x² - 5(x + 1) = 4
4x² - 5x - 4 = 4 ( subtract 4 from both sides )
4x² - 5x - 9 = 0 ← in standard form
(x + 1)(4x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
4x - 9 = 0 ⇒ 4x = 9 ⇒ x = \(\frac{9}{4}\)
However, x ≠ - 1 for reason given above, then
solution is x = \(\frac{9}{4}\)
Consider x >5 and 2.x > 2.5. Identify a solution to the first
inequality. Show that this solution also makes the second
inequality true.
answer=
step by step:
2 x 6 =12
6 > 5
What is a counterexample for the conjecture?
If the area of a rectangle is 80 square units, the perimeter must be greater than 35.9 units.
A) A rectangle with length 39.5 units and width 0.5 unit has a perimeter of 80 units and an area of 19.75 square units.
B) A rectangle with length 8 units and width 10 units has a perimeter of 36 units and an area of 80 square units.
C) A rectangle with length 8 units and width 9 units has a perimeter of 34 units and an area of 72 square units.
D) A square with a side length of √80 units has a perimeter of approximately 35.8 units and an area of 80 square units.
The argument against the conjecture The area of a rectangle with a perimeter of 40 units must be at least one square unit. A rectangle with dimensions of 19.99 units long and 0.1 units wide has a 40 unit perimeter and an area of 0.1999 square units.
What is counterexample?An instance or example that refutes the proposition is referred to as a counterexample. To determine if a statement is true or not, logic uses this. Counterexamples typically offer strong arguments in opposition to the assertion under discussion.The goal of the inquiry is to demonstrate any possible relationship between the area and perimeter of a rectangle.acc to our question-
The goal of the inquiry is to illustrate any potential connections between a rectangle's perimeter and area.
The counterexample presented dimensions that revealed the perimeter, which is 40, but omitted to provide the area, which is 1 square unit.
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use tukey’s procedure on the data in example 10.3 to identify differences in true average bond strengths among the five protocols
Tukey's procedure, also known as the Tukey-Kramer test, a statistical method used to compare multiple groups and identify significant differences in their means. Tukey's procedure is used to identify differences in the true average bond strengths among the five protocols in Example 10.3.
Tukey's procedure, also known as the Tukey-Kramer test, a statistical method used to compare multiple groups and identify significant differences in their means. In this case, we are applying Tukey's procedure to the data in Example 10.3, which consists of bond strengths measured under five different protocols.
To perform Tukey's procedure, we first calculate the mean bond strength for each protocol. Next, we compute the standard error of the mean for each protocol. Then, we calculate the Tukey's test statistic for pairwise comparisons between the protocols. The test statistic takes into account the means, standard errors, and sample sizes of the groups.
By comparing the Tukey's test statistic to the critical value from the studentized range distribution, we can determine if there are statistically significant differences in the true average bond strengths among the protocols. If the test statistic exceeds the critical value, it indicates that there is a significant difference between the means of the compared protocols.
Using Tukey's procedure on the data in Example 10.3 will allow us to identify which pairs of protocols have significantly different average bond strengths and provide insights into the relative performance of the protocols in terms of bond strength.
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The long jump pit was recently rebuilt to make it level with the runway. Volunteers provided pieces of wood to frame the pit. Each piece of wood provided measures 6 feet, which is approximately 1.8287 meters. 2.75 meters 9.54 meters.
Determine the amount of wood, in meters, needed to rebuild the frame.
The long jump pit was recently rebuilt to make it level with the runway. the amount of wood, in meters, is 12.29 meters.
What is the amount of wood, in meters, needed to rebuild the frame.?Generally, To determine the amount of wood needed in meters, you will need to convert the length of each piece of wood from feet to meters. You can use the conversion factor that 1 foot is equal to approximately 0.3048 meters.
To convert the length of the wood from feet to meters, you can use the formula:
length in meters = length in feet * 0.3048
Using this formula, you can calculate that 2.75 meters is equal to approximately 9 feet, and 9.54 meters is equal to approximately 31.25 feet.
Therefore, the total amount of wood needed in meters is 2.75 meters + 9.54 meters = 12.29 meters.
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could you explain to me how to do this ? I do not understand at all
Answer:
I believe this is how you do it
Step-by-step explanation:
csc∅tan∅
(1/sin∅)(sin∅/cos∅)
(sin∅)/(sin∅cos∅)
1/(cos∅)
sec∅
csc²∅tan²∅sin∅
1/(sin²∅) * tan²∅ * sin∅
tan²∅/sin²∅ * sin∅
tan²∅/sin∅
Yesterday, Sam had 149 baseball cards. Today, he gave m away. Using m, write an expression for the number of cards Sam has left.
Answer: 149 - m
He gave some away so we subtract
Here is a system of equations: 6.2 -y= 18 4x + 2y = 26 Select all the steps that would help to eliminate a variable and enable solving. Divide the second equation by 2. then add the result to the first equation. Multiply the first equation by 2. then add the result to the second equation. Multiply the first equation by 4 and the second equation by 6, then subtract the resulting equations. O Multiply the second equation by 6, then subtract the result from the first equation. Multiply the first equation by 2. then subtract the second equation from the result.
to eliminate the variable y
we have steps are,
1) Divide the second equation by 2. then add the result to the first equation
or
2) Multiply the first equation by 2. then add the result to the second equation
or
3) Multiply the first equation by 4 and the second equation by 6, then subtract the resulting equations.
so the answer is the first three options.
Find and classify the critical points of f(x,y)=8r³+ y² + 6xy
The critical points of the function are (0, 0) and (3/4, -9/4), To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point
To find the critical points of the function f(x, y) = 8x^3 + y^2 + 6xy, we need to find the values of (x, y) where the partial derivatives with respect to x and y are equal to zero.
Taking the partial derivative with respect to x, we have:
∂f/∂x = 24x^2 + 6y = 0.
Taking the partial derivative with respect to y, we have:
∂f/∂y = 2y + 6x = 0.
Solving these two equations simultaneously, we get:
24x^2 + 6y = 0,
2y + 6x = 0.
From the second equation, we can solve for y in terms of x:
Y = -3x.
Substituting this into the first equation:
24x^2 + 6(-3x) = 0,
24x^2 – 18x = 0,
6x(4x – 3) = 0.
Therefore, we have two possibilities for x:
1. x = 0,
2. 4x – 3 = 0, which gives x = ¾.
Substituting these values back into y = -3x, we get the corresponding y-values:
1. x = 0 ⇒ y = 0,
2. x = ¾ ⇒ y = -9/4.
Hence, the critical points of the function are (0, 0) and (3/4, -9/4).
To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point. However, since the original function does not provide any information about the second partial derivatives, further analysis is required to classify the critical points.
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What is the domain of the linear function
graphed below?
Answer:
C
Step-by-step explanation:
Divide. (-1/5) divided by (-4/5) what is the quotient
Answer:
I believe it's 1/4
Step-by-step explanation:
i think -1/4
not entirely sure
Please help!!! Needs done by tomorrow
The population of the small town in 2025 is 22234
How to determine the population in 2025?The given parameters in the question are
Initial population =24597Rate of decay = 2%These parameters can be represented as
a = 24597
r = 2%
The equation of the function can be represented as
P(t) = a(1 - r)^t
So, we have
P(t) = 24597 * (1 - 2%)^t
In 2025, we have
Year = 2025
This means that
t = 2025 - 2020
So, we have
t = 5
Substitute t = 5 in P(t) = 24597 * (1 - 2%)^t
P(5) = 24597 * (1 - 2%)^5
Evaluate the expression
P(5) = 22234
Hence, the population is 22234
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twice the sum of -17 and a number is -14
After thoroughly calculating we have come to find that, a number twice the sum of -17 and -14 is −62
How to find sum of two numbers?To sum and complete mathematical operations, numerical values are needed. Numbers are used to represent numerical values, and they can also be used to represent them alphabetically. For instance, the number 22 can be expressed in writing or by using the alphabet 22. One more example is the number 3, which can be written as 3.
Numbers can take many different forms. Examples of opposites include odd and even, fraction and integer, rational and irrational, natural and whole, and many more. A few of the operations include arithmetic, algebra, and trigonometry.
Twice the sum of -17 and -14 is
2((-17) + (-14))
⇒ 2(-17 -14)
⇒ 2 × (-31)
⇒ −62
So, a number twice the sum of -17 and -14 is −62.
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If m < DAB = 3.6x ^ 2 then what is the value of x?
We have;70° < DAB = 3.6x²70/3.6 < x²19.4 < x²√19.4 < x Hence, the value of x is approximately equal to 4.4 (rounded to one decimal place).
The given equation is m < DAB = 3.6x². We are to find the value of x. Given that m < DAB, the value of angle m is less than the value of angle DAB.Since, the sum of the angles in a triangle is equal to 180°.
Therefore, we have; m + A + B = 180°Substituting the given angle measures in the above equation, we get;m + 65° + 45° = 180°m + 110° = 180°m = 180° - 110° = 70°Now, m < DAB.
Therefore, we have;70° < DABFor any triangle, the length of the side opposite to an angle is equal to the product of the other two sides and the sine of the angle opposite to it.i.e.,
Opposite side of angle m = AB sinC = AB sin 65°
Opposite side of angle B = ACsinA = Ac sin45°Opposite side of angle DAB = BC sin70°We have the relationship between the sides of a right angled triangle as,
AB² + BC² = AC²Substituting the values of the opposite sides of the angles in the above equation,
we get;
AB² + AC²sin²45°
= BC²sin²70° + AC²sin²65° ⇒ AB² + AC²/2
= BC²/2 + AC²×(1-sin²70°)/2 + AC²×(1-sin²65°)/2⇒ 2AB² + AC²
= BC² + AC²×(cos²70° + cos²65°)Now,
we are given that;m < DAB = 3.6x²
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Last Friday David rented 4 movies from the video store. This Friday he rented 2 movies. Let x represent the cost of renting each movie. Write and simplify an expression for how much more David spent last week renting movies.
Expression:
4x - 2x
Simplified:
2x
Anita está asiendo pan de calabaza y tiene medio galón de masa ella planea verter la masa en un molde de vidrio con longitud de 9 pulgadas un ancho de 4 y una profundidad de cuatro determine si toda la masa cabra en el sartén
All the batter would fit into the pan as it has more volume than half a gallon.
What is a cuboid?A cuboid is a three-dimensional closed figure which has volume along with surface area.
The volume of a cuboid is the product of its length, width, and height.
The total surface area of a cuboid is 2(lw + wh + wl) and the lateral surface area is 2(l + w)×h.
We know, One gallon is equal to 231 cubic inches.
Therefore, Half a gallon is equal to 231/2 cubic inches.
The volume of the pan is (9×4×4) cubic inches.
= 144 cubic inches.
Now, 144 > 231/2, so it would fit.
Q. Anita is baking pumpkin bread and has a half gallon of batter. She plans to pour the batter into a glass pan with a length of 9 inches, a width of 4 inches, and a depth of four. Determine if all the batter will fit in the pan.
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Adam had some candy to give to his three children. He first took seven pieces for himself and then evenly divided the rest among his children. Write an expression for how many pieces each child received. A. 7−c3 B. C−73 C. C−73 D. 7−c3
Answer : The expression will be
( c - 7 ) / 3
Step-by-step explanation:
Let's say Adam has c pieces of candy
He took ten pieces for himself which means we can write this as c-7
He then divided this amount between his 3 children (c-7)/3
5. The length of two sides of a right triangle are leg: 9
m and hypotenuse: 16 m. Find the length of the
third side. Round to the nearest tenth if necessary.
A. 28.8 m
B. 13.2 m
C. 104 m
D. 14.4 m
Answer:
B. 13.2 m
Step-by-step explanation:
Using the Pythagorean theorem, which is a^2 + b^2 = c^2, you can substitute in 9 for a and 16 for c. This puts it at 9^2 + b^2 = 16^2, which equals 81 + b^2 = 256. Subtract 81 from both sides to get b^2 = 175. Take the square root of both sides to get b = sqrt 175. The sqrt of 175 rounded to the nearest tenth is 13.2
Find the area of the shaded regions:
The pink is the shaded region
Answer: 5184.
Step-by-step explanation:
You do 72 x 72.
Find f[g(x)] and g[f(x)] for the given functions. 3 f(x) = -x³ +3, g(x) = 4x+7 (Simplify your answer. Do not factor.) (Simplify your answer. Do not factor.) f[g(x)] = g[f(x)] =
The value of f[g(x)] is - 64x³ - 336x² - 588x - 340 and the value of g[f(x)] is -4x³ + 19
The functions are as follows; f(x) = -x³ +3 and g(x) = 4x+7
The value of f[g(x)] is obtained by replacing every x in f(x) with the value of g(x) as given below
f[g(x)] = f(4x + 7) = - (4x + 7)³ + 3
When we expand (4x + 7)³, it gives us 64x³ + 336x² + 588x + 343
Then
f[g(x)] = - 64x³ - 336x² - 588x - 340
Similarly, g[f(x)] is obtained by replacing every x in g(x) with the value of f(x) as shown below;
g[f(x)] = g(-x³ + 3) = 4(-x³ + 3) + 7g
[f(x)] = -4x³ + 19
Therefore,
f[g(x)] = - 64x³ - 336x² - 588x - 340
g[f(x)] = -4x³ + 19
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A student states that the lengths of 3, 2, and 1 can be the sides of a triangle because 3 plus 2 is greater than 1. Determine if the student is correct. Explain your reasoning
Answer: The student is incorrect
Step-by-step explanation: A triangle may be possible if its two longest sides have a difference less than the length of the shortest side, otherwise the last side won't enclose the area of the triangle. We cannot join lengths of 3, 2, and 1 units without forming a straight line, which does not classify as a triangle.
The school that Jenny goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 14 adult tickets and 14 child tickets for a total of $322. The school took in $188 on the second day by selling 12 adult tickets and 1 child ticket. What is the price of each of one adult ticket and one child ticket?A. Adult Tickets: $17, Child Ticket: $12B. Adult Tickets: $15, Child Ticket: $8C. Adult Tickets: $9, Child Ticket: $3D. Adult Tickets: $24, Child Ticket: $13
The price of one adult ticket is $15 and the price of one child ticket is $8.
Two sets of equations can be derived from this question:
14a + 14c = 322 equation 1
12a + c = 188 equation 2
These equations are known as simultaneous equations and they can be solved to determine the cost of each ticket using the elimination method.
In order to determine the cost of the adult's ticket multiply equation 2 by 14
168a + 14c = 2632 equation 3
Subtract equation 1 from 3
2310 = 154a
Divide both sides by 154
a = $15
To determine the cost of the children's ticket substitute for a in equation 1
14(15) + 14c = 322
210 + 14c = 322
322 - 210 = 14c
112 = 14c
c = $8
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Question is below!!! 9 and 10!!!! Pls help
Answer:
9. 1.75 m/s²; 8 s
10. (12 6/7) °/s; (10 5/7) kt/s
Step-by-step explanation:
Acceleration is the change in velocity divided by the change in time.
__
9.(22 m/s -15 m/s)/(4 s) = 7/4 m/s² = 1.75 m/s²
The eagle's average acceleration is 1.75 m/s².
__
The relation can also be used to find the time for a given change:
a = Δv/Δt ⇒ Δt = Δv/a
Δt = (22 m/s -8 m/s)/(1.75 m/s²) = 8 s
It would take the eagle 8 seconds to go from 8 m/s to 22 m/s.
__
10.From north to south is a direction change of 180°. Then the rate of change is ...
a = 180°/(14 s) = 12 6/7 °/s
__
From 75 knots north to 75 knots south (-75 knots, using north as a reference) the magnitude of the average acceleration is ...
|-75 kt -75 kt|/(14 s) = 150/14 kt/s = 10 5/7 kt/s
The slope of the line containing the points (-2, 3) and (-3,1) is
a.02 b.1/2 c.0 -2/5
Step-by-step explanation:
the slope is always the ratio "y coordinate change / x coordinate change" when going from one point of the line to another.
so, when going from (-2, 3) to (-3, 1)
x changes by -1 (from -2 to -3).
y changes by -2 (from 3 to 1).
therefore, the slope is
-2/-1 = 2/1 = 2
In trend projection, a negative regression slope is mathematically impossible.
True
False
The statement "in trend projection, a negative regression slope is mathematically impossible" is false.
In trend projection, a negative regression slope is mathematically possible. Trend projection, also known as linear regression, is a statistical technique used to forecast future values based on past trends. It assumes a linear relationship between the independent variable (time) and the dependent variable (the variable being forecasted).
The regression slope represents the direction and magnitude of the relationship between the variables. A positive slope indicates an upward trend, while a negative slope indicates a downward trend. Therefore, a negative regression slope is indeed possible in trend projection.
However, it's important to note that the validity of the trend projection depends on the underlying data and assumptions made. If the data and assumptions are not appropriate, the trend projection may not accurately represent the relationship between the variables.
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Set both given equations equal to zero, then combine them into one standard form equation. Simplify if possible.
7x + 3 = 5 and y - 1 = 6
Equation 1 -
Equation 2 -
Combined Equation -
Answers:
a. 7x - 2 = 0
b. 7x - y = 1
c. 7x + 8 = 0
d. y - 7 = 0
e. 7x - y = -5
f. y + 7 = 0
The standard equation is 7x + y = 9
layoff Ax + By = C is the usual form for two-variable direct equations. A standard form direct equation is, for case, 2x + 3y = 5. When an equation is given in this format, chancing both intercepts is rather simple( x and y). When trying to break systems involving two direct equations, this form is also relatively helpful.
Given
7x + 3 = 5 and y - 1 = 6
Add the bottoms from the two given equations to produce a single standard-form equation.
By shifting the constant fromR.H.S. toL.H.S., the equations are reset to zero.
7x + 3 - 5 = 0
7x - 2 = 0----( 1)
y - 1 = 6
y - 1 - 6 = 0
y - 7 = 0-----( 2)
Equation 1 and equation 2 must be combined.
7x - 2 + y - 7 = 0
7x + y - 9 = 0
layoff Ax + By = C is the equation's conventional form.
A, B, and C are integers and x and y are variables in this type of equation.
Accordingly, the common equation is
7x + y - 9 = 0
7x + y = 9
therefore the standard equation is 7x + y = 9
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0.25 divided by 2.65
Answer:
0.09433962264
Step-by-step explanation:
Which of these sets of ordered pairs would define a line with a negative slope?
A. (5, 5) and (0, 1)
B. (2, 3) and (-4, -1)
C. (3, 6) and (5, 1)
D. (2, 3) and (76)
From the following sets of ordered pairs, line c, (3, 6) and (5, 1), has a negative slope.
To determine the slope of a line given two points, we can use the formula:
slope = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
If the slope is negative, it means the line is decreasing as we move from left to right, or in other words, it has a negative slope.
Let's apply the formula to each set of ordered pairs:
A. slope = (1 - 5) / (0 - 5) = -4 / -5 = 4/5 (positive slope)
B. slope = (-1 - 3) / (-4 - 2) = -4 / -6 = 2/3 (positive slope)
C. slope = (1 - 6) / (5 - 3) = -5 / 2. (negative slope)
D. This set has only one point (2, 3) and is therefore not sufficient to define a line.
Therefore, only option C has a negative slope. Option B has a positive slope. Option A has a positive slope. Option D is not sufficient to define a line.
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A grocery store chain introduces a new brand of cereal in several of its stores. The function B(w)=120w150+w2 for w≥0 models the number of boxes, B, in thousands, of the cereal sold after w weeks. The graph of this function is shown below.
Select the THREE true statements regarding the graph of B(w).
A
Based on the zeros of the function, the number of boxes of cereal sold is 0 after 0 weeks.
B
Based on the zeros of the function, the number of boxes of cereal sold is 0 after 1,250 weeks.
C
Based on the end behavior of the function, the number of boxes of cereal sold will keep falling after reaching the maximum.
D
Based on the asymptote of the function, the number of boxes of cereal sold will never fall below 800 after reaching the maximum.
E
Based on the asymptote of the function, the number of boxes of cereal sold will never reach 0 after the cereal is introduced in the store.
The THREE true statements regarding the graph of B(w) are;
A) Based on the zeros of the function, the number of boxes of cereal sold is 0 after 0 weeks.
C) Based on the end behavior of the function, the number of boxes of cereal sold will keep falling after reaching the maximum.
E) Based on the asymptote of the function, the number of boxes of cereal sold will never reach 0 after the cereal is introduced in the store.
How to Interpret Quadratic Graph?
We are given the graph represented by the quadratic function;
B(w) = 120w/(150 + w²) for w ≥ 0 that models;
the number of boxes, B, in thousands, of the cereal sold after w weeks
From the graph, we can see that at the origin which is the coordinate (0, 0) that it remains so and as such the number of boxes of cereal sold is 0 after 0 weeks. Thus, option A is correct
Secondly, from the given graph, we see that the graph starts rising from zero to a maximum after which it keeps falling. Thus, we can say that option C is correct
Lastly, we see that the graph asymptote approaches 500 thousand boxes but never gets to zero and as such we can say that option E is correct.
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selecting players how many ways can 5 baseball players and 3 basketball players be selected from 12 baseball players and 13 basketball players?
There are 1078 different combinational methods to choose five baseball players and four basketball players from a pool of twelve baseball players and thirteen basketball players.
5 baseball players and 4 basketball players are chosen from a pool of 12 baseball players and 13 basketball players.
This is an issue of combination.
The combination is a way of estimating an event's total outcome when the sequence of the outcomes is irrelevant.
The formula is as follows: \({}^{n}C_{r}\) = n! ÷ (r! × (n - r)!)
Where n is the total number of things and r is the number of items picked at one time.
Let us first compute 5 baseball players from a total of 12 baseball players.
In this case, n = 12 and r = 5.
\({}^{12}C_{5}\) = 12! ÷ (5! × (12 - 5)!)
\({}^{12}C_{5}\) = 12! ÷ (5! × 7!)
The factorial of n for a number n is expressed as:
n! = n × (n-1) × (n-2) × (n-3) × .... × 2 × 1
Therefore,
\({}^{12}C_{5}\) = 12! ÷ (5! × 7!)
\({}^{12}C_{5}\) = 792
Similarly, 3 basketball players are chosen from a pool of 13 basketball players (n = 13 and r = 3).
\({}^{13}C_{3}\) = 13! ÷ (3! × (13 - 3)!)
\({}^{13}C_{3}\) = 13! ÷ (3! × 10!)
The factorial of n for a number n is expressed as:
n! = n × (n-1) × (n-2) × (n-3) × .... × 2 × 1
Therefore,
\({}^{13}C_{3}\) = 13! ÷ (3! × 10!)
\({}^{13}C_{3}\) = 286
As a result, the total number of methods is as follows:
\({}^{12}C_{5}\) + \({}^{13}C_{3}\) = 792 + 286
\({}^{12}C_{5}\) + \({}^{13}C_{3}\) = 1078
As a result, there are 1078 distinct methods.
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Max has 8 8 boxes of cans for a food drive. Each box has 17 17 cans. Max gives half of the boxes to his teacher. Write an expression that represents the total number of cans in all the boxes that his teacher has.
Answer:
Total cans = 17 (4)
Step-by-step explanation:
If Max has 8 boxes and gives half of the boxes to his teacher, then the teacher has 4 boxes.
Now, the teacher has 4 boxes but each box has 17 cans inside. To represent how many cans the teacher has, we will need to multiply the number of boxes by the number of cans each box has,
Then, the Total number of cans = \(17(4)\) = 68.
Thus, the expression that represents the total number of cans in all the boxes that the teacher has would be: Total cans = 17 (4)