How do we meet the needs of humanity in a sustainable way

Answer:True. The number of calories in a food is a measure of how much potential energy that food possesses.

Explanation:

Answer:

\( \huge\mathfrak\pink{Hope \: it \: helps}\ \)

The angle θ between P and Q vector is 18.43°.

In physics, a vector is a quantity that has both magnitude and direction. It is typically represented by an arrow with the same direction as the quantity and a length proportional to the magnitude of the quantity.

A vector, while having magnitude and direction, does not have position. A vector quantity is any physical quantity that has both directions and magnitude.

According to given parameters:

PQ sinθ = (1/3) PQ cosθ

tanθ = 1/3

θ = 18.43°

Hence, the angle θ between P and Q vector is 18.43°

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Answer:

  Eₓ = -4,187 N / C,       E_y = 6,937 N / C

Explanation:

To solve this exercise we will calculate the electric field at the desired point (0, 0) and then add it vectorially

                 E = \(k \frac{q}{r^2}\)

charge 1

the value of q₁ = - 2,600 nC = -2,600 10⁻⁹ C

                 r₁ = \(\sqrt{ (x_1-x_o)^2 + (y_1-y_o)^2}\)

                 r₁ = \(\sqrt{0 +(1.04-0)^2}\)RA 0 + (1.04 - 0) 2

                 r₁ = 1.04 m

we substitute

                 E₁ = k q1 / r12

                 E₁ = 9 10⁹   2.6 10⁻⁹ / 1.04²

                 E₁ = 21.635 N / C

This electric field is directed towards the negative charge and is in the direction of the y axis.

                 E₁ = 21.635 j ^   N / C

charge 2

the value of q₂ = 3,600 nC = 3,600 10-9 C

                 r₂ = Ra (1.4 -0) 2 + (0.4 -0) 2

                 r₂ = 1.4560 m

we substitute

                 E₂ = k q₂ / r₂²

                 E₂ = 9 10⁹ 3,600 10⁻⁹ / 1.4560²

                  E₂ = 15.283 N / C

This field leaves the charge since the charge is positive, let's find the angle

               tan θ = y / x

               θ = tan⁻¹ y / x

               θ = tan⁻¹ 0.400 / 1.400

               θ = 15.9º

let's decompose the electric field

               sin 15.9 = E_{2y} / E2

               cos 15.9 = E₂ₓ / E2

               E_{2y} = E2 sin 15.9

               E₂ₓ = E2 cos 15.9

                E_{2y} = 15.283 sin 15.9 = 4.187 N / C

               E₂ₓ = 15.283 cos 15.9 = 14.698 N / C

the field lines leave the positive charge and are directed to the left, therefore

               E_{2y} = - 4.187 N / C

               E₂ₙ = -14.698N / C

the total field on each axis is

               Eₓ = E_{1x} + E_{2x}

               Eₓ = 0 -4,187

                Eₓ = -4,187 N / C

                E_y = 21.635 - 14.698

                 E_y = 6,937 N / C

Answer:

40N in either direction is the answer

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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An open cluster is a group of up to a few thousand stars that were formed from the same giant molecular cloud, and are still loosely gravitationally bound to each other. In contrast, globular clusters are very tightly bound by gravity. ... Open clusters are very important objects in the study of stellar evolution.

Hans Oersteds works with electricity and magnetism is that he developed electromagnetism when he observed compass needle that was deflected when electric current flow through it.

Electromagnetism is a type of electromagnetic force that occur between electric field and magnetic field and the interaction that exhaust between them and charged particles.

Therefore, Hans Oersteds works with electricity and magnetism is that he developed electromagnetism.

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Answer:

wait, wont the balloon pop if there is gas inside?

Explanation:

Jack speed as he hits the water is 14.13m/s

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s².  Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.

If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).  
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).  
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)

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The expression \(X^{N} + Y^{N}\)is not divisible by X - Y (where Y is not equal to 0).

To determine whether the expression \(X^{N} + Y^{N}\) is divisible by X - Y (where Y is not equal to 0), we can use the factor theorem and the property of binomial expansion.

The factor theorem states that if a polynomial P(x) is divisible by (x - a), then P(a) equals zero. In our case, if \(X^{N} + Y^{N}\) is divisible by (X - Y), then when we substitute X = Y into the expression, the result should be zero.

Let's substitute X = Y into the expression:

\(Y^{N} + Y^{N}\)

Since \(Y^{N}\) is equivalent to \(Y^{N}\) , the expression becomes:

2(\(Y^{N}\))

We can see that the expression 2(\(Y^{N}\)) is not equal to zero unless Y is equal to zero. Therefore, if Y is not equal to zero, \(X^{N} + Y^{N}\) is not divisible by X - Y.

In summary, unless Y is equal to zero, the expression \(X^{N} + Y^{N}\) is not divisible by X - Y according to the factor theorem and the given condition.

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Answer:

57.98 °Fahrenheit =

14.4333 °Celsius

Explanation:

(rounded to 6 digits)

Answer:

false

Explanation:

it cant defined the messy and clean states

Answer:

Explanation:

Angle:

β = - 23°

( From the symmetry condition)

Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

Answer:

Explanation:

I hope this helped

Hi there!

We can use Ohm's law to solve for the resistance of the lamp.

\(V = IR\)

V = Voltage (V)
I = Current (A)
R = Resistance (Ω)

We can rearrange to solve for resistance.

\(R = \frac{V}{I}\\\)

Plug in the given values:

\(R = \frac{120}{0.5} = \boxed{240 \Omega}\)

The acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.

The  acceleration of the crate is calculated from the net force acting on the crate as shown below;

F(net) = applied force - frictional force

F(net) = 10 N - 5N

F(net) = 5 N

Apply Newton's second law of motion to calculate the acceleration of the crate.

F(net) = ma

where;

a = F(net) / m

a = 5/5

a = 1 m/s²

Thus, the acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

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This question is incomplete, the complete question is;

Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.

Which of the following is NOT one of the lowest three energy levels of an electron in this model?

a. 283 eV

b. 339 eV

c. 113   eV  

d. 226 eV        

Answer:

the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Explanation:

Given the data in the question;

Three dimension cube or particle in a cubic box

the energy value is given by;

\(E_{nx,ny,nz\) = \(( n_x^2 + n_y^2 + n_z^2 )\) × π²h"² / 2ml²

where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )

m is mass of electron ( 9.1 × 10⁻³¹ kg )

l is length of side of box ( 1.0 × 10⁻¹⁰ m )

for ground level ( \(n_x = n_y = n_z = 1\) )

so

\(( n_x^2 + n_y^2 + n_z^2 )\) ×  π²h"² / 2ml²

since h" = h/2π

\(( n_x^2 + n_y^2 + n_z^2 )\) × π²h² / (2π)²2ml²

so we substitute

\(E_{111\) = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]

\(E_{111\) = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]    

\(E_{111\) = 3 × [ 6.03082165 × 10⁻¹⁸ ]

Now, we know that electric charge = 1.602 x 10⁻¹⁹

so

\(E_{111\) = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]

\(E_{111\) = 3 × [ 37.645578 ]

\(E_{111\) = 112.9 ≈ 113 eV

\(E_{211\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{211\) = ( 1² + 1² + 2² ) × [ 37.645578 ]

\(E_{211\) = 6 × [ 37.645578 ]

\(E_{211\) = 225.87 ≈ 226 eV

\(E_{221\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{221\) = ( 2² + 2² + 1² ) × [ 37.645578 ]

\(E_{211\) = 9 × [ 37.645578 ]

\(E_{211\) = 338.8 ≈ 339 eV

Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

a) The evidence that lead to the development of the principle of mass-energy equivalence is During nuclear fission and fusion reactions, mass is not conserved, but energy is released. So, correct option is A.

b) The particles that make up the atomic mass are protons and neutrons. So, correct option is D.

a) The principle of mass-energy equivalence, which states that mass and energy are interchangeable, was developed based on the observation of nuclear reactions, particularly during nuclear fission and fusion.

During these reactions, the total mass of the products is slightly less than the mass of the reactants, and this difference is converted into energy according to the famous equation E=mc², where E is energy, m is mass, and c is the speed of light.

This equation showed that a small amount of mass can be converted into a large amount of energy, which was confirmed by experiments involving nuclear reactions. The principle of mass-energy equivalence revolutionized physics and provided a new understanding of the relationship between mass and energy.

So, correct option is A.

b) The atomic mass of an atom is primarily determined by the number of protons and neutrons in its nucleus. Protons are positively charged particles and are responsible for determining the atomic number, which defines the element.

Neutrons, on the other hand, are neutral particles that contribute to the stability of the nucleus by balancing the electrostatic repulsion between protons. Electrons, which orbit the nucleus, have negligible mass compared to protons and neutrons and therefore do not significantly contribute to the atomic mass.

The sum of the number of protons and neutrons in the nucleus is known as the mass number, and it determines the atomic mass of an atom.

Therefore, correct option is D.

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The points in order of increasing value of the velocity can be ranked as:

B < C < A ≡ F < E < D.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

According to the figure:

The points in order of increasing value of the velocity can be written as:

B < C < A ≡ F < E < D.

As the displacement becomes from positive to negative near point B, it has the lowest velocity and  as the displacement becomes from negative to positive near point D, it has the highest velocity

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Answer:

a) 2250 J

b) 0 J

c) 2250 J

Explanation:

a) Since, the process is isochoric

the change in internal energy

\(\Delta U = n C_v(T_f-T_i)\)

Here, n = 0.2 moles

Cv = 12.5 J/mole.K

We have to find T_f so we can use gas equation as

\(\frac{P_1V_1}{P_2V_2} =\frac{T_i}{T_f}\\Since, V_1=V_2 [isochoric/process]\\\Rightarrow \frac{P_{atm}}{4P_{atm}} = \frac{300}{T_f} \\\Rightarrow T_f = 1200 K\)

So,  \(\Delta U= 0.2\times12.5(1200-300)\\=2250 J\)

b) Since, the process is isochoric no work shall be done.

c) By first law of thermodynamics we have

\(\Delta U = Q-W\\Since, W = 0\\\Delta U = Q\\Therefore, Q = 2250 J\)

Since, Q is positive 2250 J of heat will flow into the system.

The energy needed to vaporize 100 grams of ice at starting at 0°C is  300.83 kJ.

When the temperature is increased , the body or particle is said to be heating.

Given is the mass of water =100g =0.1 kg, Latent heat of fusion L = 333.7 kJ/kg,

Energy required to melt ice into water at 0°C.

Q₁ = mL

Q₁ = 0.1 x 333.7

Q₁ = 33.37 kJ

Energy required to heat water from  0°C to 100°C is

Q₂ = mCΔT

Q₂ = 0.1 x 4.186 x 100

Q₂ = 41.86 J

Energy required to vaporize at 100°C is

Q₃ = m Lv

Q₃ = 0.1 x 2256

Q₃ = 225.6 kJ

Total heat to vaporize 100 grams of ice at starting at 0°C is

Q = Q₁ +Q₂ +Q₃

Q = 33.37 +41.86 +225.6

Q = 300.83 kJ

Thus, the energy needed to vaporize 100 grams of ice at starting at 0°C is  300.83 kJ

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The new potential energy you will have, given that your height is doubled is 114 J

The following data were obtained from the question:

The new potential energy can be obtained as illustrated below:

PE₁ / h₁ = PE₂ / h₂

57 / H = PE₂ / 2H

Cross multiply

57 × 2H = PE₂ × H

Divide both sides by H

PE₂ = (57 × 2H) / H

PE₂ = 57 × 2

PE₂ = 114 J

Thus, from the above calculation, we can conclude that the new potential energy is 114 J

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The three characteristics of an object which are represented by a motion map are the position, acceleration, velocity and is therefore denoted as option D.

This is a term which is referred to as a one-dimensional plots built off of a position line and is denoted by a horizontal axis which makes it possible to mark the position of a body or a vehicle at any point in time.

It contains arrows which are specifically used to record its velocity and acceleration and is therefore the reason why option D was chosen as the most appropriate choice.

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Answer: option D.

Explanation:

Answer:

Where's the graph?

Explanation:

The magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.

When describing the effect of an applied force on an object's motion, two important factors to consider are:

Magnitude of the Force: The magnitude or strength of the applied force determines the amount of acceleration or deceleration experienced by the object. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. A greater force will result in a greater acceleration, while a smaller force will result in a smaller acceleration. Additionally, the direction of the force relative to the object's initial motion will determine if it speeds up, slows down, or changes direction.

Mass of the Object: The mass of the object being acted upon is another crucial factor. As mentioned earlier, according to Newton's second law, the acceleration of an object is inversely proportional to its mass. This means that for a given force, an object with a larger mass will experience a smaller acceleration compared to an object with a smaller mass. In simpler terms, it requires more force to accelerate a heavier object compared to a lighter object.

These two factors, the magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.

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The stone moves at a linear speed of 9.42 m/s.

Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).

The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.

C = 2πr

where r is the rope's length. If we substitute r = 30 cm, we obtain:

C = 2π(30 cm) ≈ 188.5 cm

As a result, one revolution of the stone moves it approximately 188.5 cm.

The stone moves a total of five times, covering the following distance:

d = 5(188.5 cm) = 942.5 cm

v = d/t

Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:

v = d/t = 942.5 cm/t

To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:

v = 9.425 m/t

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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