Find the value of z such that 0.03 of the area lies to the right of z. Round your answer to two decimal places.

The value of piecewise function at x = -1 is f(-1) = 11, and the value of piecewise function at x = 9 is f(9) = 1.

what is piecewise function?

A piecewise-defined function in mathematics is one that is composed of several smaller functions, each of which has a specific interval of the domain it applies to. Instead of being a property of the function itself, piecewise definition is a way to express the function.

We have to evaluate the piecewise function for x = -1 and x = 9.

Let, function has value for x = -1 in the domain x ≤ 5 which is 11.

And function has value for x = 9  in the domain 6 < x which is 1.

⇒  f(-1) = 11 and f(9) = 1

Hence, the value of piecewise function at x = -1 is f(-1) = 11, and the value of piecewise function at x = 9 is f(9) = 1.

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Answer:

250

Step-by-step explanation:

Answer:

Step-by-step explanation:

The domain and range of a linear function is always real numbers (T or F)

It is True. This is because of a couple of reasons.

    1.) You cannot divide by 0.

     2. A negative number cannot have its square root taken.

The range is determined by the domain in a linear function, and thus it must always consist of real numbers.

9514 1404 393

Answer:

  20√2

Step-by-step explanation:

It is helpful to know your multiplication facts. For simplifying the radicals, you remove the perfect squares:

  \(\sqrt{a^2\cdot b}=a\sqrt{b}\)

__

  \(-3\sqrt{18}+5\sqrt{72}-\sqrt{2}=-3\sqrt{3^2\cdot2}+5\sqrt{6^2\cdot2}-\sqrt{2}\\\\=-3\cdot3\sqrt{2}+5\cdot6\sqrt{2}-\sqrt{2}=(-9+30-1)\sqrt{2}\\\\=\boxed{20\sqrt{2}}\)

Answer:

Every triangle has three medians, just like it has three altitudes, angle bisectors, and perpendicular bisectors. The medians of a triangle are the segments drawn from the vertices to the midpoints of the opposite sides. The point of intersection of all three medians is called the centroid of the triangle.

Step-by-step explanation:

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The area of the square is given as 100 square unit

You should be aware that the square has all its sides equal

The perpendicular from opposite vertices represent distance

The given vertices are

(2,2) and (10,8)

Using the formula for distance between two points

d=√(10-2)²+(8-2)²

d=√8²+6²

d = √64+36

d=√100

This implies that d=10

The area of a square is given as s²

Area = 10²

Atrea = 100 square units

In conclusion, the area of the square is 100 square units

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Translated question:

The vertices of a square ABCD are A(2,2) and B(10,8), Find the area of the square

There are 9,000 numbers that have 7 in the thousands of places and are less than 54,000.

Consider the possible digits in the hundreds, tens, and one's places.

Thousands of places: There is only one possibility, which is 7.

Hundreds place: Any digit from 0 to 9 is possible.

Tens place: Any digit from 0 to 9 is possible.

One place: Any digit from 0 to 9 is possible.

Since the number is less than 54,000, the digit in the hundreds place cannot be 5.

So, there are 9 possible digits (0 to 9, except 5) for the hundreds place, and 10 possible digits (0 to 9) for the tens and one's places.

So, the total number of such numbers is:

9 x 10 x 10 x 10 = 9,000

Therefore, there are 9,000 numbers that satisfy the given condition.

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Answer:

Define a sequence of random variables B, Does the sequence of random variables Bre n converge in probability to a constant b? If yes, enter the value of b below, if no, enter "DNE". (Enter e for the constant e)

B6- As above, let a be the limit in probability of An, ie. An a, and b be the limit in probabiity of Bn = 4, i.e. Br*b, if these limits exist. Does the sequence of random variables (Br-b) converge in distribution? Choose the correct characterization of the limit distribution: O N (0,1) O N 0, "Var (X2) O N (0, "Var (x2)) O N (0, 24Var (X²)) O N 0, e?Var (An)) O Does not converge in distribution

Step-by-step explanation:

Define a sequence of random variables B, Does the sequence of random variables Bre n converge in probability to a constant b? If yes, enter the value of b below, if no, enter "DNE". (Enter e for the constant e)

B6- As above, let a be the limit in probability of An, ie. An a, and b be the limit in probabiity of Bn = 4, i.e. Br*b, if these limits exist. Does the sequence of random variables (Br-b) converge in distribution? Choose the correct characterization of the limit distribution: O N (0,1) O N 0, "Var (X2) O N (0, "Var (x2)) O N (0, 24Var (X²)) O N 0, e?Var (An)) O Does not converge in distribution

The correct characterization of the limit distribution and other Questions are answered in the following steps.

For the first question, the distribution of (An-a) is approximated best by N(0, n) because the variance of the sample mean of i.i.d. standard normal variables is 1/n.

For the second question, since An converges in probability to a constant, Bn = 4An also converges in probability to 4a. Therefore, the sequence of random variables (Bn-b) does converge in distribution.

For the third question, the limit distribution of (Bn-b) is N(0, 4^2 * n) because the variance of the product of a random variable and a constant is the constant squared times the variance of the random variable.

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To determine when the total cost of each health club will be the same, we can set up an equation and solve for the number of months.

Let's assume the number of months is represented by 'x'.

For Club A, the total cost is given by:

Total cost of Club A = $13 (one-time fee) + $28x (monthly fee)

For Club B, the total cost is given by:

Total cost of Club B = $19 (one-time fee) + $27x (monthly fee)

To find the number of months when the total cost is the same, we set the two equations equal to each other:

$13 + $28x = $19 + $27x

Simplifying the equation, we get:

$28x - $27x = $19 - $13

$x = 6

Therefore, after 6 months, the total cost of each health club will be the same.

To find the total cost for each club after 6 months, we substitute the value of 'x' back into the equations:

Total cost of Club A after 6 months = $13 + $28(6) = $13 + $168 = $181

Total cost of Club B after 6 months = $19 + $27(6) = $19 + $162 = $181

So, the total cost for both Club A and Club B will be $181 after 6 months.

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The expression that will represent the volume of the identical rectangular base pyramid is: 2[One-third (5) (0.25) (2)] cubic units.

To calculate for the volume of a rectangular base pyramid, we use the formula:

volume = 1/3 × area of base rectangle × height

volume of one identical pyramid = (1/3 × 5 × 0.5 × 2)cubic units

volume of the two identical pyramid = 2(1/3 × 5 × 0.5 × 2)cubic units.

Therefore, the expression that will represent the volume of the identical rectangular base pyramid is: 2[One-third (5) (0.25) (2)] cubic units.

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Answer:

2.8

Step-by-step explanation:

On a particular day, our technician completed six jobs and accumulated the following hours:

The total number of hours points directly to an addition. The total number of hours he accumulated (T) was:

Our desired answer is 7.2.

Answer: e

Step-by-step explanation:

Answer:Valid

Step-by-step explanation:

Answer:

Step-by-step explanation:

The text is a statistics problem that asks to find the probability of a certain range of values in a normal distribution. A normal distribution is a bell-shaped curve that shows how data values are spread around the mean. The mean is the average of all the data values, and the standard deviation is a measure of how much the data values vary from the mean. To solve this problem, we can use the following steps:

Convert the given range of values to standard scores or z-scores. A z-score tells us how many standard deviations a value is away from the mean. To find the z-score, we use the formula: z=σx−μ​

where x is the value, μ is the mean, and σ is the standard deviation. For example, to find the z-score for 33.5 psi, we plug in the values: z=233.5−35​=−0.75

This means that 33.5 psi is 0.75 standard deviations below the mean. Similarly, to find the z-score for 36 psi, we plug in the values: z=236−35​=0.5

This means that 36 psi is 0.5 standard deviations above the mean.

Use a z-table to find the area under the curve for each z-score. A z-table is a table that shows the probability of getting a z-score less than or equal to a given value. For example, to find the area under the curve for -0.75, we look up the row for -0.7 and the column for 0.05 in the z-table and get 0.2266. This means that there is a 22.66% chance of getting a z-score less than or equal to -0.75. Similarly, to find the area under the curve for 0.5, we look up the row for 0.5 and the column for 0 in the z-table and get 0.6915. This means that there is a 69.15% chance of getting a z-score less than or equal to 0.5.

Subtract the smaller area from the larger area to find the area between the two z-scores. This area represents the probability of getting a value between 33.5 and 36 psi in the normal distribution. For example, to find the area between -0.75 and 0.5, we subtract: 0.6915−0.2266=0.4649

This means that there is a 46.49% chance of getting a value between 33.5 and 36 psi in the normal distribution.

Multiply the area by 100 to convert it to a percentage and write it with the appropriate units: The percentage of tires that are inflated to a pressure between 33.5 and 36 psi is 0.4649×100=46.49%

a) Angle of line of sightFrom a point O in the school compound, Adeolu is 100 m away on a bearing N 35° E and Ibrahim is 80 m away on a bearing S 55° E. (a) How far apart are both boys? (b) (c) What is the bearing of Adeolu from point O, in three-figure bearings? What is the bearing of Ibrahim from point O, in three-figure bearings?The angle of the line of sight of Adeolu from the point O is given by:α = 90 - 35α = 55°.The angle of the line of sight of Ibrahim from the point O is given by:β = 90 - 55β = 35°.a) By using the Sine Rule, we can determine the distance between Adeolu and Ibrahim as follows:$

\frac{100}{sin55^{\circ}} = \frac{80}{sin35^{\circ}

100 sin 35° = 80 sin 55°=57.73 mT

herefore, both boys are 57.73 m apart. b) The bearing of Adeolu from the point O can be determined as follows:OAN is a right-angled triangle with α = 55° and OA = 100. Therefore, the sine function is used to determine the side opposite the angle in order to determine AN.

Thus:$$sin55^{\circ} = \frac{AN}{100}$$AN = 80.71 m.

To find the bearing, OAD is used as a reference angle. Since α = 55°, the bearing is 055°.

Therefore, the bearing of Adeolu from the point O is N55°E. c) Similarly, the bearing of Ibrahim from the point O can be determined as follows:OBS is a right-angled triangle with β = 35° and OB = 80. Therefore, the sine function is used to determine the side opposite the angle in order to determine BS.

Thus:$$sin35^{\circ} = \frac{BS}{80}$$BS = 46.40 m.

To find the bearing, OCD is used as a reference angle. Since β = 35°, the bearing is 035°.Therefore, the bearing of Ibrahim from the point O is S35°E. A boy walks 5 km due North and then 4 km due East. (a) Find the bearing of his current posi- tion from the starting point.

(b) How far is the boy now from the start- ing point?The boy's position is 5 km North and 4 km East from his starting position. The Pythagorean Theorem is used to determine the distance between the two points, which are joined to form a right-angled triangle. Thus

:$$c^2 = a^2 + b^2$$

where c is the hypotenuse, and a and b are the other two sides of the triangle. Therefore, the distance between the starting position and the boy's current position is:$$

c^2 = 5^2 + 4^2$$$$c^2 = 25 + 16$$$$c^2 = 41$$$$c = \sqrt{41} = 6.4 km$$

Therefore, the boy is 6.4 km from his starting point. (a) The bearing of the boy's current position from the starting point is given by the tangent function.

Thus:$$\tan{\theta} = \frac{opposite}{adjacent}$$$$\tan{\theta} = \frac{5}{4}$$$$\theta = \tan^{-1}{\left(\frac{5}{4}\right)}$$$$\theta = 51.34^{\circ}$$

Therefore, the bearing of the boy's current position from the starting point is N51°E.

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You can use collections of objects such as blocks to model a number. Each type of block can be used to show the value of each digit in the number

The values of adjacent places in base-ten representations of numbers are related as each place is always 10 times the value represented by the place to its imme- diate right

Unit blocks, rods, flats, and cubes are the names of base ten block types. The digit in the ones place is represented by the unit blocks. To demonstrate how many tens are in a number, rods are each worth one ten, i.e., ten rods equal one flat, which is worth one hundred each.

Students use base ten blocks, also referred to as multibase arithmetic blocks or Dienes blocks, as a type of math manipulative to learn the basics of addition, subtraction, number sense, place value, and counting.

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The true statement is "the line that can be drawn through points D and E is contained in plane Y".

option B is the correct answer

The points x and y and points C,D,E and f are shown in the figure, the true statement is determined as follows;

We know that, if two points lie in a plane, then the line drawn through the points will contained in the same plane.

The points C lies outside the plane Y and the point D lies on the plane Y, so the line drawn through the points C and D will not contained in plane Y.

So, option (A) is NOT correct.

The points D and E, both lie in the plane Y, so the line drawn through the points D and E will also contained in plane Y.

So, option (B) is CORRECT.

Since the plane X contain infinitely many points, so F is not the only point that can lie in plane X.

So, option (C) is NOT correct.

Similarly, there are infinitely many points in the plane Y, so the points D and E are not the only points that can lie in plane Y.

So, option (D) is NOT correct.  

Thus, the correct option is;

The line that can be drawn through points D and E is contained in plane Y.

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The complete question is below:

Points x and y and points C,D,E and f are shown what is true about points

(A) The line that can be drawn through points C and D is contained in plane Y.

(B) The line that can be drawn through points D and E is contained in plane Y.

(C) The only point that can lie in plane X is point F.

(D) The only points that can lie in plane Y are points D and E

The general solution to the given differential equation is:

y = (x/12) - (1/288)

How to solve the Differential Equation?

We want to solve the differential equation given as: y' - 24xy = -2x

The integrating factor is given by the exponential of the integral of the coefficient of y, which in this case is -24x. Therefore, the integrating factor is e^(-24x).

Multiplying the entire equation by the integrating factor, we get:

e^(-24x)y' - 24xe^(-24x)y = -2xe^(-24x)

The left side of the equation is the derivative of (e^(-24x)y) with respect to x:

(d/dx)(e^(-24x)y) = -2xe^(-24x)

Integrating both sides with respect to x, we have:

e^(-24x)y = ∫(-2xe^(-24x))dx

Integrating the right side, we get:

e^(-24x)y = -∫(2xe^(-24x))dx

To evaluate the integral on the right side, we can use integration by parts. Let's differentiate -2x and integrate e^(-24x):

u = -2x (differential of u = -2dx)

dv = e^(-24x) (integral of dv = -1/24e^(-24x)dx)

Using the integration by parts formula:

∫uv dx = uv - ∫v du

We can compute the integral as follows:

-∫(2xe^(-24x))dx = -[(-2x)(-1/24e^(-24x)) - ∫(-1/24e^(-24x))(-2dx)]

= -[x/12e^(-24x) + 1/12∫e^(-24x)dx]

= -[x/12e^(-24x) + 1/12(-1/24)e^(-24x)]

= -[x/12e^(-24x) - 1/(12*24)e^(-24x)]

= -[x/12e^(-24x) - 1/(288e^(-24x))]

= -[x/12 - 1/288]e^(-24x)

Substituting this back into the previous equation, we have:

e^(-24x)y = -[-(x/12 - 1/288)e^(-24x)]

Simplifying further:

e^(-24x)y = (x/12 - 1/288)e^(-24x)

Canceling out e^(-24x) on both sides:

y = x/12 - 1/288

Therefore, the general solution to the given differential equation is:

y = x/12 - 1/288

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The given measures made up a scalene triangle. Therefore, option C is the correct answer.

A triangle is a three-sided polygon, which has three vertices. The three sides are connected with each other end to end at a point, which forms the angles of the triangle. The sum of all three angles of the triangle is equal to 180 degrees.

Given that, a triangle has one side that measures 4 ft, one side that measures 6 ft and one side that measures 9 ft.

A. All the sides are not equal, then it is not an equilateral triangle.

B. Any two sides are not equal, then it is not an isosceles triangle.

C. All the sides are equal, then it is a scalene triangle.

D. By using Pythagoras theorem,

9²=6²+4²

81≠52

So, the given measure does made up right triangle.

Therefore, option C is the correct answer.

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Answer:

  5/10

Step-by-step explanation:

An equivalent fraction will have the numerator and denominator multiplied by the same value.

The denominator of 2 must be multiplied by 5 to get a denominator of 10. Then the equivalent fraction is ...

  \(\dfrac{1}{2}=\dfrac{1}{2}\cdot\dfrac{5}{5}=\dfrac{1\cdot5}{2\cdot5}=\boxed{\dfrac{5}{10}}\)

Using exponential properties, it is found that the equivalent expression to the frequency of any pitch is given by:

\(f = 440\sqrt[12]{2^{10}}\)

It happens according to the following rule, with the denominator as the root and the numerator as the exponent:

\(a^{\frac{n}{m}} = \sqrt[m]{a^n}\)

The rule for the frequency is given by:

\(f = 440(2)^{\frac{10}{12}}\)

Hence the equivalent expression to f is given by:

\(f = 440\sqrt[12]{2^{10}}\)

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To calculate the circumference of a circle using its radius you have to calculate twice its radius multiplied by pi, following the formula:

The given radius has a radius of r=9m, you can calculate the circumference as:

The circumference of the circle is 18π m or aproximatelly 56.55m

Answer:

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Step-by-step explanation:

(a) The vector field \(\vec F\) is conservative if it is a gradient field. So we try to find a scalar function \(f\) such that

\(\nabla f(x,y) = \dfrac{\partial f}{\partial x} \, \vec\imath + \dfrac{\partial f}{\partial y} = \vec F(x,y)\)

Given the field

\(\vec F(x,y) = y\,\vec\imath+x\,\vec\jmath\)

we need to have

\(\dfrac{\partial f}{\partial x} = y\)

\(\dfrac{\partial f}{\partial y} = x\)

Integrate both sides of the first equation with respect to \(x\).

\(\displaystyle \int \frac{\partial f}{\partial x} \, dx = \int y \, dx \implies f(x,y) = xy + g(y)\)

Differentiate both sides with respect to \(y\).

\(\dfrac{\partial f}{\partial y} = x + \dfrac{dg}{dy} = x \implies \dfrac{dg}{dy} = 0 \implies g(y) = C\)

So we have

\(f(x,y) = xy + C \implies \nabla f = \vec F\)

is indeed conservative.

(b) By the gradient theorem, the integral is path-independent and

\(\displaystyle \int_C \vec F \cdot d\vec r = f(5,4) - f(0,2) = \boxed{20}\)

for any path \(C\) that starts at (0, 2) and ends at (5, 4).

Answer:

Let the number of boys and number of girls be 2x and 3x respectively.

Then,

According to question,

Number of girls = 18

or, 3x = 18

or, x = 6

Number of boys = 2x = 12

Therefore, the total number of boys is 12

Using properties of square,

a. Equation for total area = 2x² - 16x + 64

b. Area will be minimum for the value of x = 0

c. Minimum area will be 64cm².

With four equal sides, a square is a quadrilateral. There are numerous square-shaped objects in our immediate environment. The equal sides and 90° internal angles of each square form serve as indicators of its identity.

Total length of wire = 32cm.

Now side of one square is given as x.

Perimeter of big square will be = 4x.

Now perimeter of small square = 32- 4x.

Side of small square = (32-4x)/4

= 4(8-x)/4

= 8-x

Area of big square = x × x

= x².

Area of small square = (8-x) ².

Now Total area, A(x) = x² + (8-x) ²

= x² + 64 + x² - 16x

= 2x² - 16x + 64

The side length that will minimize the area will be, x = 0.

Minimum area of the total figure will be = 64cm²

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