Find the measure of the missing angle using the triangle angle sum theorem

Answer:

c=(f-4m)/2y

Step-by-step explanation:

2cy = 2f -8m

divde both sides by 26

c=(2f-8m)/2y

simplify

c=(f-4m)/y

Answer:

Angles B and H= Alt exterior angles

Angles D and C= Adjacent angles

Angles B and F= Corresponding angles

Angles C and E= Alt interior angles

Answer:

14, which is B.

Step-by-step explanation:

Plug in -2 in your function.

f(-2) = 8-3(-2)

= 8 - (-6)

= 8 + 6 = 14

Answer:

A

Step-by-step explanation:

on Edge 2020

the graph with U and 40 degrees in quadrant 4

Answer:

A) the first graph

Step-by-step explanation:

got it right on edge :)

Answer:

x = 1.

4+1×6=30

Step-by-step explanation:

thats about right

Answer:

6(x+4)=30

6x+24=30

6x=30-24

6x=6

x=1

The answer is A. One / 1

Answer:

The answer is C. -1

Answer:

100

Step-by-step explanation:

Multiply 40 by 3 because 40 is 1/3 and find the answer for 3/3.

I got 120, subtract 20 from 120 beacause there is 20 silver cards. The answer is 100

Answer:

answer will come soon pls wait

Step-by-step explanation:

also try solving it by yourself

be independent

Answer:

C 3.5t + 15, where t is the number

of days

A) Serial correlation is often present in time series data because it arises from the inherent nature of the data

B) The presence of serial correlation in the residual is a problem because it violates one of the assumptions of linear regression analysis, which is the assumption of independent and identically distributed (IID) errors.

I. Serial correlation is often present in time series data because it arises from the inherent nature of the data. Time series data refers to observations collected over time, where each observation is dependent on previous observations. This dependence can result in a pattern of correlation or relationship between consecutive data points.

One common reason for serial correlation in time series data is seasonality. Seasonality refers to the repetitive pattern or trend that occurs within a specific time period. For example, sales of ice cream may increase during the summer months and decrease during the winter months. This pattern of seasonality can create a correlation between consecutive observations within the same season.

Another reason for serial correlation is autocorrelation. Autocorrelation occurs when there is a correlation between an observation and its lagged values, meaning the previous observations. For example, if the stock price of a company is increasing over time, it is likely to exhibit positive serial correlation as each observation is influenced by the previous price.

II. The presence of serial correlation in the residual is a problem because it violates one of the assumptions of linear regression analysis, which is the assumption of independent and identically distributed (IID) errors. In linear regression, the residuals represent the unexplained variation in the dependent variable after accounting for the effects of the independent variables.

When serial correlation exists in the residuals, it means that the errors in the model are not independent and are related to each other. This violates the IID assumption and can lead to biased and inefficient estimates of the regression coefficients. In other words, the estimated coefficients may not accurately represent the true relationship between the independent and dependent variables.

Additionally, serial correlation in the residuals can affect the statistical significance of the regression model. If the residuals are serially correlated, the standard errors of the regression coefficients may be underestimated, leading to inflated t-values and p-values. As a result, variables that are actually not significant may appear to be significant in the presence of serial correlation.

To address the problem of serial correlation in the residuals, various techniques can be applied, such as transforming the data, including lagged variables in the model, or using time series analysis methods. These techniques aim to account for the dependence structure in the data and produce reliable estimates of the regression coefficients.

In summary, serial correlation is often present in time series data due to the inherent dependence between consecutive observations. However, its presence in the residuals of a regression model can be problematic as it violates the assumption of IID errors and can lead to biased estimates and incorrect statistical inferences. Proper techniques should be employed to address serial correlation and ensure the validity of the regression analysis.

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Answer:

Quadratic function and cubic function

Step-by-step explanation:

A relation is a function such that there are no input values that are paired with more than one output values. Thus, if a graph contains two or more different points with the same x-coordinate, then that graph is not a representation of a function. A great way to test whether a given graph represents a function is through the Vertical Line Test.

In order to perform the Vertical Line Test, simply draw vertical lines across the graph. If each vertical line drawn intersects the graph in at most once, then it means that the given graph represents a function.  

The parent graphs of quadratic function, f(x) = x², and cubic function, f(x) = x³, are not straight lines.  Attached are screenshots of the graphed quadratic function and cubic function which shows that these graphs pass the Vertical Line Test.

The number of fish in the lake is an illustration of arithmetic sequence

The value of f(2) is 7800, and it represents the number of fish in the lake, the second year

The model is given as:

\(\mathbf{f(n+1) = f(n) - 400}\)

Where \(\mathbf{f(1) = 8200}\)

To calculate f(2), we simply take n as 1.

i.e. n = 1

Substitute 1 for n in \(\mathbf{f(n+1) = f(n) - 400}\)

So, we have:

\(\mathbf{f(1+1) = f(1) - 400}\)

Add 1 and 1

\(\mathbf{f(2) = f(1) - 400}\)

Substitute 8200 for f(1)

\(\mathbf{f(2) = 8200 - 400}\)

Subtract

\(\mathbf{f(2) = 7800}\)

Hence, the value of f(2) is 7800

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The probability of getting a prime number of heads given that heads occurs on at least 6 of the tosses is 0.0078

The number of observations n is 7

Here the success is heads

The probability of heads is 1/2

We need to find the the probability of getting a prime number of heads.

Heads occurs on at least 6 of the tosses

prime number greater than equal to 6 and less than equal to 7 is 7

So, X = 7

P(X = 7) = 7C7(1/2)⁷(1/2)⁰

P(X = 7) =  1 x (1/2)⁷ x

P(X =7 ) = 1/128

= 0.0078

Therefore, the probability of getting a prime number of heads given that heads occurs on at least 6 of the tosses is 0.0078

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Ratio compares two things. The length of the trail, in reality, is 6.75 km.

A scaling ratio helps us to compare two things.

Given to us

The scale on the map states that 2 centimeters represent 3 kilometers.

Length of the trail on the map, L = 4.5 cm = 0.045 m

As we know that 2 centimeters represent 3 kilometers. therefore,

\(\rm \dfrac{Map}{Real} = \dfrac{0.02\ m}{3000\ m}\)

We know that the Length of the trail on the map is 0.045 m,

\(\rm \dfrac{L}{L'} = \dfrac{0.02\ m}{3000\ m}\)

Substitute the value,

\(\rm \dfrac{0.045}{L'} = \dfrac{0.02\ m}{3000\ m}\\\\L' = 6750\ m\\\\L' = 6.750\ km\)

Hence, the length of the trail, in reality, is 6.75 km.

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Answer:

1) A. Add/subtract a quantity to/from only one side  

2) B. No

Step-by-step explanation:

Answer two questions about Equations A and B:  

1) How can we get Equation B from Equation A?

2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?  

=================================

1) As we see left sides of the equations are different but right sides are same.

To make them equal we need to remove the difference.

We need to add 2 to the left side of equation A to get Equation B.

The answer choice for this case is:

2) Since the equations are not same, they will have different solutions.

Answer choice is:

Equivalent equations are equations that have the same value.

The equations are given as:

\(A:\ 5x-2+x = x-4\)

\(B: 5x+x = x-4\)

(a) How to get equation (B) from (A)

By comparing equations (A) and (B), we have the following observations

This means that, only the left-hand side of equation A will be altered to get equation B.

Hence, the solution is:

A. Add/subtract a quantity to/from only one side

(b) Are they equivalent?

No, they are not.

This is so, because only one side of equation A is altered to get equation B.

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Answer:

-13

Step-by-step explanation:

3x-5x+10=35

-2x+10=36

-2x=36-10

-2x\-2=26\-2

x=-13

Answer:

B

Step-by-step explanation:

B

a) To calculate the concentration of A at the outlet (CA) in mol/L, we need to use the conversion formula. The conversion of A is given as 90%, which means 90% of A is consumed in the reactions. Therefore, the remaining concentration of A at the outlet can be calculated as follows:

CA = CAo * (1 - conversion)
CA = 3 mol/L * (1 - 0.9)
CA = 3 mol/L * 0.1
CA = 0.3 mol/L

b) The rate law equations for the reactions can be determined by considering the stoichiometry of the reactions and the given specific rate constants.

For the first reaction: 2A + 3X → 2B
The rate law equation for this reaction can be written as:
Rate = k1A * CA^2 * CX^3

For the second reaction: 2A - B
The rate law equation for this reaction can be written as:
Rate = k2A * CA^2

c) The instantaneous selectivity of B with respect to X (Sex) can be calculated as the ratio of the rate of formation of B to the rate of formation of X.

Sex = (Rate of formation of B) / (Rate of formation of X)
Sex = (k1A * CA^2 * CX^3) / (k1A * CA^2)
Sex = CX^3

d) The instantaneous yield of B can be calculated as the ratio of the rate of formation of B to the rate of consumption of A.

Yield = (Rate of formation of B) / (Rate of consumption of A)
Yield = (k1A * CA^2 * CX^3) / (k2A * CA^2)

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The statement suggests that the worst-case time complexity of Insertion Sort is approximately proportional to n²/2, while the average-case time complexity is approximately proportional to n²/4.

The worst-case and average-case time complexities of Insertion Sort indicate that the algorithm's performance is quadratic, with the average case being more efficient than the worst case due to a smaller constant factor.

The worst-case time complexity refers to the scenario where the input array is in reverse order or nearly sorted in reverse order. While the average-case time complexity represents the average performance of the algorithm over all possible inputs.

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Answer:

The perpendicular slope is 3.

Explanation:

\(\sf slope\:intercept\:form :y = mx + b\)

where:

Given equation:

divide both sides by -6

simplify

when simplified more:

Here the slope is -1/3

- - - - - - - - - - - - - - - - - - - - - - - -

\(\sf m_1 \times m_2 = -1\)

where:

Find perpendicular slope:

\(\sf -\dfrac{1}{3} \times m_2 = -1\)

\(\sf m_2 = 3\)

270 people enter the line for the escalator during" the time interval 0 < / < 300 and  80 people are at Mn Line at time 300. 414.285714 sec. is the first time that there are no people in line for the escalator and 33. 0133 time is the number of people in line minimum.

X(t) = 44 ( t/100)³ * (1-t/300)⁷

for 0≤t≤300

for t≥ 300

a) Total number of people = ∫³⁰⁰₀ r(t)*dt

∫³⁰⁰₀ 44(t/100)³ * (1-t/300)⁷ * dt

∫³⁰⁰₀ (11 (1-t/300)⁷ / 250000 * t³) * dt

∫³⁰⁰₀ -11 / 250000 * (t-300)⁷ * t³ * (1/300)⁷ dt

= -11 (1/300)⁷ / 250000 ∫³⁰⁰₀ (t-300)⁷ * t³ * dt

Now Integrate with respect to 't'

using substitution

Let  u = t-300

du = dt

∫ u⁷ * (u + 300)³ * du

∫ (u¹⁰ + 900 u⁹ +270000 u⁸ + 27000000 u⁷) * du

= u¹¹/11 + 90 u¹⁰ + 30000 u⁹ + 3375000 u⁸

Undo the substitution

u= (t-300)

= [ (t-300)¹¹ / 11 + 90 (t-300)¹⁰ + 30000(t-300)⁹ + 337500(t-300)⁸]³⁰⁰₀

Substitutes the limits

= [0- ((-300)¹¹/ 11 + 90 * (-300)¹⁰ + 30000 * (-300)⁹ + 3375000 * (-300)⁸]

= 270 people

b) Constant rate of 0.7 people per second

This is the rate of exit

at t = 0.20 people in line

People in a line at t = 300 is = 20+ ∫³⁰⁰₀ ((r(t) - 0.7 ) * dt

= 20 + ∫³⁰⁰₀ 44(t/100)³ * (1-t/300)⁷- 0.7 dt

= 20 + 270 - 0.7 * 300

= 80 people

c) t = 300 sec

people = 80

when t>300 , r(t) = 0

rate of exit remains the same

= 80 + ∫ ( 0-0.7) * dx

= 80 + [-0.7x] = 0

= 80 - [0.7x] = 0

= 80 - 0.7 t + 0.7 * 300 = 0

= 80 - 0.7t + 210 = 0

= - 0.7 t = -290

t = 414.285714 sec.

d) f(t) = 20 + ∫⁶₀ (r(x) - 0.7) * dx

f(t) = r(t) - 0.7

f(t) = 0       (for critical point)

r(x) = 44 (t/100)³ * (1-t/300)⁷

r(t) = 0

we get t= 33.0133 sec.

t = 166.575 sec.

Now check for the value

when t=0

f(t) 20

when t= 33.0133

f(t) = 3.803 ≈ 4

when t = 166.575

f(t) = 158.07 ≈ 158

when t= 300

f(t) = 80

so the minimum number of people is 4 at the time t= 33. 0133

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Answer:

Y Axis

Step-by-step explanation:

The y axis is the best so it reflects off of both sides of the best axis in the world.

They have the same slope, the lines are parallel to one another.

If two non-vertical lines that are in the same plane has the same slope, then they are said to be parallel. Two parallel lines won't ever intersect.

The slopes of two perpendicular lines are negative reciprocals. The product of the slopes of two perpendicular lines is -1

We need to put these equations into y=mx+b format.

3x-5y=20

-5y=-3x+20. (take 5x from both sides)

y=3/5 x -4 ( divide both sides by -3)

The slope is 3/5

y=3/5x-1

The slope is 3/5

Therefore, we can conclude that the lines are parallel to each other as they have same slope.

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The correct answer is option B which is a circle that can not be circumscribed on the given quadrilateral.

The circle is defined as the locus of the point traces around a fixed point called the centre and is equidistant from the outer trace.

In the image we have a quadrilateral having different angles so the vertices of the quadrilateral are also at different positions if we form the circumscribed circle over a given quadrilateral it will not pass through all the vertices of the quadrilateral.

Therefore the correct answer is option B which is a circle that can not be circumscribed on the given quadrilateral.

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Answer:

Everything except y=ex^2

Step-by-step explanation:

Answer: 1st 4th and  5th are polynomials

Step-by-step explanation:

Any polynomial is something with addition subraction multiplication and non negative powers and/or exponents

The probability of randomly selecting a doctor who is either a General Practitioner or under the age of 40 from a small hospital is 9/19, given 6 out of 19 are General Practitioners, 5 out of 19 are under 40, and 2 are both.

To find the probability of randomly selecting a doctor who is either a General Practitioner or under the age of 40, we need to add the probabilities of these two events and subtract the probability of selecting a doctor who is both a General Practitioner and under the age of 40, since we don't want to count that case twice:

P(General Practitioner or under 40) = P(General Practitioner) + P(Under 40) - P(General Practitioner and under 40)

we know 6 out of 19 doctors are General Practitioners, 5 out of 19 doctors are under the age of 40, 2 doctors are both General Practitioners and under the age of 40.

Therefore:

P(General Practitioner) = 6/19

P(Under 40) = 5/19

P(General Practitioner and under 40) = 2/19

Substituting these values into the formula:

P(General Practitioner or under 40) = 6/19 + 5/19 - 2/19

= 9/19

Therefore, the probability of randomly selecting a doctor who is either a General Practitioner or under the age of 40 is 9/19.

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Answer:

\(sum = (n - 2) \times {180}^{0} \\ {1980}^{0} = (n - 2) \times {180}^{0} \\ (n - 2) = \frac{1980}{180} \\ (n - 2) = 11 \\ n = 11 + 2 \\ n = 13 \: sides\)

let other one be (x,y)

We know midpoint formula

\(\boxed{\sf (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)}\)

\(\\ \sf\longmapsto (6,-4)=\left(\dfrac{13+x}{2},\dfrac{-2+y}{2}\right)\)

\(\\ \sf\longmapsto \dfrac{13+x}{2}=6\)

\(\\ \sf\longmapsto 13+x=12\)

\(\\ \sf\longmapsto x=12-13\)

\(\\ \sf\longmapsto x=-1\)

And

\(\\ \sf\longmapsto \dfrac{-2+y}{2}=-4\)

\(\\ \sf\longmapsto -2+y=-8\)

\(\\ \sf\longmapsto y=-8+2\)

\(\\ \sf\longmapsto y=-6\)

Answer:

(- 1, - 6 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \(\frac{x_{1}+x_{2} }{2}\) , \(\frac{y_{1}+y_{2} }{2}\) ) ← midpoint formula

Use this formula on the endpoints and equate to the coordinates of the midpoint.

let the other endpoint = (x, y) , then

\(\frac{13+x}{2}\) = 6 ( multiply both sides by 2 )

13 + x = 12 ( subtract 13 from both sides )

x = - 1

\(\frac{-2+y}{2}\) = - 4 ( multiply both sides by 2 )

- 2 + y = - 8 ( add 2 to both sides )

y = - 6

The coordinates of the other endpoint are (- 1, - 6 )