During the formation of the Solar System, the conversion of hydrogen to helium in its core would have required a Jovian planet to become a star. Here option C is the correct answer.
During the formation of the Solar System, the jovian planets, including Jupiter, Saturn, Uranus, and Neptune, formed from the cold gases and icy particles that were present in the outer solar system.
These planets are mostly composed of hydrogen and helium, similar to the composition of the Sun. However, for a jovian planet to become a star, it would need to undergo nuclear fusion, the process of converting hydrogen to helium in its core, which releases a tremendous amount of energy in the form of light and heat.
Jupiter, the largest planet in the Solar System, has a mass that is approximate 1/1000th that of the Sun. In order for it to become a star, it would need to be at least 80 times more massive than it currently is, as this is the minimum mass required for nuclear fusion to occur in its core. Accumulating more rocky material or attracting other planets would not be sufficient to cause a planet to become a star. Formation from hotter gases would also not be necessary, as even cold gas and dust can form a star if it has enough mass to initiate fusion.
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Complete question:
During the formation of the Solar System, what would have been required for a jovian planet to become a star?
A - accumulation of a larger percentage of rocky material
B - attracting at least one planet away from the Sun and having it remain in orbit
C - the conversion of hydrogen to helium in its core
D - formation from hotter gases instead of cold gases and icy particles
Which of the following does Bernoulli's principle help to explain?
A. Flying
B. Surface tension
C. Floating
D. Hydraulics
how does the heat jupiter radiates compare to the energy it receives from the sun?
Jupiter radiates more heat than it receives from the Sun.
Jupiter is a gas giant planet and does not have a solid surface to absorb and retain heat like the Earth. Instead, Jupiter's atmosphere absorbs and then re-radiates the energy it receives from the Sun. However, due to its large size and distance from the Sun, Jupiter receives much less solar radiation per unit area than the Earth does.
Despite this, observations show that Jupiter radiates about 1.6 times more heat than it receives from the Sun. This excess heat is generated by gravitational contraction, as the planet slowly shrinks due to its own gravity. As Jupiter contracts, gravitational potential energy is converted into heat, which is then radiated away into space.
This excess heat is also responsible for Jupiter's intense atmospheric dynamics, including its distinctive belts and zones, powerful storms, and the Great Red Spot.
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if the moment of inertia of the shaded area about the a-a' axis is 18e6mm^4 what is the moment of inertia about the b-b' axis
The moment of inertia about the b-b' axis is 24.6E6 mm^4.
To find the moment of inertia of the shaded area about the B-B' axis, we can use the formula I = ∑m*r^2, where m is the mass of each particle in the shaded area, r is the distance of each particle from the B-B' axis, and the sum is taken over all particles in the shaded area.
We are given that the moment of inertia of the shaded area about the A-A' axis is
18E6 mm^4,and that the area of the shaded region is
A = 6E3 mm^2.We are also given the distances
ds = 50 mm and d₂ = 10 mm,which correspond to the distances of the two particles in the shaded region from the B-B' axis.
The mass of each particle in the shaded region can be calculated by dividing the total mass of the region (which is equal to the product of the area and the density of the material) by the number of particles. Since the density of the material is not given, we cannot calculate the mass of each particle.
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Complete Question:
If the moment of inertia of the shaded area about the A-A' axis is 18E6 mm, what is the moment of inertia about the B-B' axis?
Given: A6E3 mm², ds-50 mm, d₂-10 mm
a. none of these answers
B. 21.2E6 mm^4
C 25.2E6 mm^4
D. 26.3E6 mm^4
E. 24.6E6 mm^4
What is the minimum force required to increase the energy of a car by 92 J over a distance of 19 m? Assume the force is constant.
Group of answer choices
1700 N
110 N
0.21 N
92 N
4.8 N
a tine can collapes if all air inside it is taken out, why
When all the air inside the tin are taken out, the air outside the tin becomes greater than the air inside causing inward pushing of the tin which results in collapse of the tin.
What is unbalanced force?This is a situation when the forces acting on an object are unequal.
A tin will remain firm when air inside it is prevented from escaping. During this time, the forces of air outside the tin balances the forces of air inside the tin, this process creates equilibrium condition that cause the tin to be firm.
When all the air inside the tin are taken out, the air outside the tin becomes greater than the air inside causing inward pushing of the tin which results in collapse of the tin.
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The Weight of an object is more at pole and less at equator of the earth. Give reason
The Weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
A person carries a box of 100 kg. What is the weight of the box? (g= 9.8 m/s2)
Answer:
980 newton
Explanation:
100×9.8 = 980
How much kinetic energy does a baseball with a mass of 0.143 kg have it it is traveling at a velocity of 41.1 m/s?
89.7 Joules
108 3 Joules
156.6 Joules
120.8 Joules
Answer:
E = 120.77 J
Explanation:
Given that,
Mass of a baseball, m = 0.143 kg
Velocity of a baseball, v = 41.1 m/s
We need to find the kinetic energy of the baseball. We know that the kinetic energy of an object is associated with its motion. It can be given by the formula as follow :
\(E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 0.143\ kg\times (41.1\ m/s)^2\\E=120.77\ J\)
So, the kinetic energy of the baseball is 120.77 J.
The kinetic energy of the baseball is 120.8 J.
What is kinetic energy?The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as
K.E = 1/2 mv²
Given is the Mass of a baseball, m = 0.143 kg and Velocity of a baseball, v = 41.1 m/s
substitute the values, we have
K.E = 1/2 x 0.143 x (41.1)²
K.E = 120.77 J
Hence, the kinetic energy of the baseball is 120.8 J.
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All moving objects don’t have momentum
A. True
B. False
Answer:
No
Explanation:
Some objects gain momentum.
Answer:
B. False
Hope you could understand.
If you have any query, feel free to ask.
How do motors use energy? Do they convert electrical energy into mechanical energy OR mechanical energy into electrical energy?
Plz help asap!
Answer:
Motors convert electrical energy into mechanical energy
Explanation:
A motor uses electrical energy to create mechanical energy by creating magnetic fields causing the motor to spin. A generator is the opposite and converts mechanical into electrical by spinning a motor in a magnetic field.
An electric motor can transforms electrical energy into mechanical energy. Therefore, option (1) is correct.
How do motors convert energy?Energy can be described as the ability of an object to do work. Energy can also be transformed to work and the work done on an object can be stored in the form of energy.
The energy contained by the object because of its motion is called kinetic energy. The energy contained by an object due to its position is called its potential energy. Mechanical energy can be defined as the sum between the kinetic energy and potential energy of a body according to the law of conservation of energy.
An electric motor is a machine that receives energy from electricity as electrical energy and transforms it into mechanical energy. Therefore, when electric energy is supplied to an electric motor it converts electrical energy into mechanical energy.
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According to Newton's second law of
motion, what relationship exists between
mass and acceleration if force is constant?
Answer: acceleration is directly proportional to net force when mass is constant… and that acceleration is inversely proportional to mass when net force is constant…
Explanation:
If the force is constant, then the acceleration will be inversely proportional to the mass.
If the force is constant, then the acceleration will be inversely proportional to the mass.
We have Newton's Second law of Motion.
We have to determine the relation between mass and acceleration if force is constant.
What is Newton's Second law of Motion ?Newton's Second law of motion states that the rate of change of momentum is directly proportional to force applied.
According to the question, we have -
Force = Mass x Acceleration
F = ma
if Force is constant, then -
a = \(\frac{F}{a}\)
Hence, if the force is constant, then the acceleration will be inversely proportional to the mass.
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Create an Android App that calculates two physics properties, Force and Density.
Force is given by the equation, F = ma,
where m is mass, and a is acceleration.
The App should have the following components:
TextView (title for the App)
TextField (for the user to enter the mass)
TextField (for the user to enter the acceleration)
Button (the user presses the button to perform the calculation)
TextView (shows the result of the calculation)
This App should include the user interface and the code that performs the calulcations and presents the results to the user interface.
Use the Simplifying User Input App we developed in class as a guide to complete this assignment,
Create the Android App, set up the project, design the user interface, handle user input, perform calculations, and display the results.
Creating an Android App that calculates force and density can be done by following these steps:
Set up the project in Android Studio.
Design the layout of the user interface using XML, including TextViews, EditTexts, and a Button.
Define the necessary variables and views in the Java code.
Set an onClickListener for the button to perform the calculations.
Retrieve the user input from the EditText fields and convert them to appropriate data types.
Calculate the force using the formula F = ma and the entered mass and acceleration.
Display the calculated force in the result TextView.
Repeat steps 5-7 for calculating density if desired.
Run the app on an Android emulator or device to test its functionality.
The Simplifying User Input App developed in class can serve as a guide for implementing the user interface and handling user input.
You would need to modify the code to incorporate the force and density calculations based on the provided equations.
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Seth and Diana were asked to be the leaders for a game of tag during recess at school. Seth and Diana can ensure that all interested students get a chance to participate equally regardless of ability to run fast by having the: Tagged players sit out until the next game starts Tagged players perform a fitness activity then return to the game Two youngest students be the taggers Two fastest students be the taggers
Answer:
B
Explanation:
did this yesterday with my friend
Answer: Tagged players perform a fitness activity
Explanation: Proof of validity is shown below.
a cannonball is fired with a velocity of 551 m/s in the cannon is aimed 12° above the ground , how far away does the cannonball land?
The cannonball lands 12.4 km from the cannon if the cannonball is fired with a velocity of 551 m/s in the cannon is aimed 12° above the ground.
R = u² sin 2θ / g
R = Horizontal range
u = Initial velocity
θ = Angle made with ground
g = Acceleration due to gravity
u = 551 m / s
θ = 12°
g = 9.8 m / s²
R = 551² sin 2 ( 12° ) / 9.8
R = 303601 * 0.4 / 9.8
R = 12392 m
R = 12.4 km
The horizontal range of a projectile is the horizontal distance travelled by the projectile from the point from which it was launched. It is denoted by R.
Therefore, the cannonball lands 12.4 km from the cannon
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PLS HURRY IM TAKING THE TEST! THX
Particles q1 = -75.8 uC, q2 = +90.6 uC, and 93 = -84.2 uC are in a line. Particles q1 and q2 are separated by 0.876 m and particles q2 and q3 are separated by 0.432 m. What is the net force on particle q3?
The net force on particle q3 is -3.49 x 10^-3 N.
What is net force on q3?The net force on particle q3 can be calculated by considering the electric forces between q3 and each of the other particles, and then adding them vectorially. The electric force between two charged particles can be calculated using Coulomb's law:
\(F = k * |q1 * q2| / r^2\)
where k is Coulomb's constant (8.9875 x 10^9 N * m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.
First, let's calculate the electric force between q3 and q2:
\(F12 = k * |-84.2 uC * 90.6 uC| / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 uC^2) / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 x 10^-6 C^2) / (0.432 m)^2\\= 3.05 x 10^-3 N\)
Next, let's calculate the electric force between q3 and q1:
\(F13 = k * |-84.2 uC * -75.8 uC| / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 uC^2) / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 x 10^-6 C^2) / (0.876 m)^2\\= -6.54 x 10^-3 N\)
Finally, the net force on particle q3 is given by the vector sum of the individual forces:
Fnet = \(F12 + F13 = 3.05 x 10^-3 N - 6.54 x 10^-3 N = -3.49 x 10^-3 N\)
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Set the transmitter movement to oscillate, field display type to curve with vectors, and radiated fields. Describewhat is happening in the transmitter and the receiver. As the transmitter moves up the receiver moves down opposite of the moment of the wave. In the transmitter theelectrons rotate up and down and have a larger range.
When the transmitter is set to have movement to oscillate, field display type to curve with vectors, and radiated fields, the oscillations in the transmitter are greater in amplitude than in the receiver.
The above problem is related to the electromagnetic charges caused by oscillating charges, To cause an electromagnetic wave to start to propagate, we must cause a time-changing electromagnetic field. If we have a single charge that can move up or down and it is found at point on the z-axis, at that point the electric field is strongest close and weaker close . If the object is moved to a position , then the electric field gets to be more grounded close and weaker close . Hence, by moving the charge between two areas, adjoining areas encounter a time-changing electric field. Moreover, a magnetic field is made from the moving charge. Accelerating and decelerating the charge to move it Just as swaying charges make electromagnetic areas, electromagnetic fields can moreover cause charges to sway when they proliferate by those charges. Charges being moved by electromagnetic areas are the material science behind a receiving antenna. The movement of the charges caused by the electromagnetic field actuates a current, which can be utilized to sense the passing electromagnetic field.
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An engine using 1 mol of an ideal gas initially at 21.8 L and 387 K performs a cycle consisting of four steps: 1) an isothermal expansion at 387 K from 21.8 L to 44.9 L ; 2) cooling at constant volume to 228 K ; 3) an isothermal compression to its original volume of 21.8 L; and 4) heating at constant volume to its original temperature of 387 K . Find its efficiency. Assume that the heat capacity is 21 J/K and the universal gas constant is 0.08206 L · atm/mol/K = 8.314 J/mol/K.
An engine using 1 mol of an ideal gas initially at 21.8 L and 387 K, the efficiency of the engine is 50%.
Step 1: Isothermal expansion at 387 K from 21.8 L to 44.9 L.
During this step, the temperature is constant at 387 K. Therefore, the ideal gas law can be used to calculate the pressure and volume of the gas. We have: PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature.
P₁V₁ = nRT₁
P₁ = nRT₁/V₁
P₁ = (1 mol x 8.314 J/mol/K x 387 K)/(21.8 L) = 150.2 kPa
P₂V₂ = nRT₂
P₂ = nRT₂/V₂
P₂ = (1 mol x 8.314 J/mol/K x 387 K)/(44.9 L) = 103.3 kPa
The work done during this step is given by:
W₁ = -nRTln(V₂/V₁)
Substituting the values, we get:
W₁ = -(1 mol x 8.314 J/mol/K x 387 K)ln(44.9 L/21.8 L) = -11,827 J
The heat absorbed during this step is given by:
Q₁ = nRTln(V₂/V₁)
Substituting the values, we get:
Q₁ = (1 mol x 8.314 J/mol/K x 387 K)ln(44.9 L/21.8 L) = 11,827 J
Step 2: Cooling at constant volume to 228 K.
During this step, the volume is constant at 44.9 L. Therefore, the ideal gas law can be used to calculate the pressure and temperature of the gas. We have:
PV = nRT
Since the volume is constant, we can simplify this to:
P₁/T₁ = P₂/T₂
where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature.
We are given the initial pressure and temperature, so we can calculate the final pressure:
P₂ = P₁ x T₂/T₁
Substituting the values, we get:
P₂ = 150.2 kPa x 228 K/387 K = 88.4 kPa
The work done during this step is zero, since the volume is constant. The heat released during this step is given by:
Q2 = nCv(T₁ - T₂)
where Cv is the heat capacity at constant volume. Substituting the values, we get:
Q₂ = (1 mol x 21 J/K)(387 K - 228 K) = 3,201 J
Step 3: Isothermal compression to its original volume of 21.8 L.
During this step, the temperature is constant at 228 K. Using the ideal gas law, we can calculate the initial and final pressures:
P₁ = nRT₁/V₁ = (1 mol x 8.314 J/mol/K x 228 K)/(44.9 L) = 42.3 kPa
P₂ = nRT₂/V₂ = (1 mol x 8.314 J/mol/K x 228 K)/(21.8 L) = 88.4 kPa
W₃ = -nRTln(V₁/V₂)
W₃ = -(1 mol x 8.314 J/mol/K x 228 K)ln(21.8 L/44.9 L) = 11,827 J
The heat released during this step is given by:
Q₃ = nRTln(V₁/V₂)
Q₃ = (1 mol x 8.314 J/mol/K x 228 K)ln(21.8 L/44.9 L) = -11,827 J
Step 4: Heating at constant volume to its original temperature of 387 K.
During this step, the volume is constant at 21.8 L. Using the ideal gas law, we can calculate the initial and final pressures:
P₁ = nRT₁/V₁ = (1 mol x 8.314 J/mol/K x 387 K)/(21.8 L) = 550.4 kPa
P₂ = nRT₂/V₂ = (1 mol x 8.314 J/mol/K x 387 K)/(21.8 L) = 550.4 kPa
The work done during this step is zero, since the volume is constant. The heat absorbed during this step is given by:
Q₄ = nCv(T₂ - T₁)
Substituting the values, we get:
Q₄ = (1 mol x 21 J/K)(387 K - 228 K) = 3,201 J
efficiency = (W₁ + W₃)/(Q₁ + Q₂ + Q₃ + Q₄)
efficiency = (-11,827 J + 11,827 J)/(-11,827 J + 3,201 J - 11,827 J + 3,201 J) = 0.5
Therefore, the efficiency of the engine is 50%.
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The state in which the inside of each heart cell is negatively charged and the outside is positively charged is:
Answer:
Resting state
Explanation:
kinatic energy dependes on[statitic/dymamic]condition of body
Answer:
dynamic im pretty sure that's it
(E) Charges flow when there is a difference in potential. Analyzing the other choices: A is wrong
because the charge resides on the surface. For B, E = 0 in a charged conducting sphere. E = kQ/r2 eliminates choice C. And for D, charge separation will occur, but the object will not
acquire any charge.
A positive charge of 10-6 coulomb is placed on an insulated solid conducting sphere. Which of the following is
true?
(A) The charge resides uniformly throughout the sphere.
(B) The electric field inside the sphere is constant in magnitude, but not zero.
(C) The electric field in the region surrounding the sphere increases with increasing distance from the sphere.
(D) An insulated metal object acquires a net positive charge when brought near to, but not in contact with, the sphere.
(E) When a second conducting sphere is connected by a conducting wire to the first sphere, charge is transferred until the electric potentials of the two spheres are equal
The positive charge of 10⁻⁶C is placed on an insulating solid conducting sphere, the charges are acquired by the sphere by using Gauss law. Thus, option E is correct.
When a point charge is placed over the insulated solid sphere, the charges are accumulated uniformly on the outer surface of the sphere by means of Gauss law. It states that the electric flux throughout any closed surface is zero.
From the given option- A) The charges are uniformly distributed on the outer surface of the sphere and not throughout the sphere. From B) The electric field inside the sphere is zero. From C) Electric field increases with the decrease of distance, E= kQ / r². In D) When an insulated metal is brought near to it, it doesn't acquire any charge.
From E) When a second conducting sphere is connected by a conducting wire to the first one, a charge gets transferred. The charges are transferred until the electric potential between the two spheres is the same.
Thus, the ideal solution is option E.
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Which system is used for transporting molecules to the cells?
Answer:
Water, carbon dioxide, and oxygen are among the few simple molecules that can cross the cell membrane by diffusion
Explanation:
An object is 12.0 cm from a
concave mirror with f = 15.0 cm.
Find the image distance.
(Mind your minus signs.)
(Unit = cm)
To find the image distance formed by a concave mirror, we can use the mirror equation:
1/f = 1/di + 1/do
Where:
f is the focal length of the mirror,
di is the image distance,
and do is the object distance.
In this case, the object distance (do) is given as 12.0 cm, and the focal length (f) is given as 15.0 cm. We can rearrange the equation to solve for the image distance (di):
1/di = 1/f - 1/do
Substituting the given values:
1/di = 1/15 - 1/12
To simplify this expression, we need to find a common denominator:
1/di = (12 - 15)/(12 * 15)
1/di = -3/180
Now, we can invert both sides to find di:
di = 180/-3
di = -60 cm
Therefore, the image distance is -60 cm. The negative sign indicates that the image is formed on the same side as the object (in this case, it is a virtual image).
Answer:
60 cm
Explanation:
the U (obj. distance) = 12 as it is a concave mirror then u = -12cm
the f = -15cm
by mirror formula
1/v + 1/u = 1/f
by substituting values
1/v + (1/-12) = 1/-15
1/v = 1/-15 -(1/-12)
1/v = 1/-15 + 1/12
by taking L C M 60
1/v = -(4/60) + 5/60
1/v = 1/60
so V = 60 cm
Which letter shows the position of ultraviolet (UV) radiation within the electromagnetic spectrum?
Answer:
usebs
Explanation:
sbnsjssbxnendnjddnejzbjseknxkiekuejss
Answer:
R
Explanation:
on the figure UV is to the right of visible light
What is a transverse wave like?
Answer:
a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation
Explanation:
wave oscillate along paths at right angles to the direction of the wave’s advance.
Explanation:
An object falls freely from rest near the surface of earth how far has the object fallen after 5 seconds
An atom’s emission of light with a specific amount of energy confirms that
Answer: An atom's emission of light with a specific amount of energy confirms that atoms must have a dense central mass surrounded by electrons at a distance
plz mark brainliest
Answer:
It's B, electrons emit and absorb energy based on their position around the nucleus.
describe two potential advantages, other than reducing the negative consequences fromusing nuclear power, of generating electricity using wind turbines
The two potential advantages of generating electricity using wind turbines are:
They are renewable and clean energy sources.They require less operating costs.What is renewable energy?Renewable energy is energy generated from naturally replenished sources such as the sun and wind. Renewable energy may be used to generate power, heat, cool buildings, and move people.
Renewable energy has several benefits that influence the economy, ecology, national security, and human health. The following are some of the advantages of adopting renewable energy in the United States:
Improved the nation's electrical grid's dependability, security, and resilienceJob creation in the renewable energy industryCarbon emissions and air pollution from energy generation are reduced.Increased energy independence for the United StatesTo know more about renewable energy, visit:
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Renewable energy source: One of the biggest advantages of wind energy is that it is a renewable energy source, meaning it will never run out, unlike fossil fuels. This makes it a sustainable and environmentally friendly option for electricity generation.
Cost-effective: Wind energy can be more cost-effective than other traditional forms of energy generation over the long term, especially as technology improves and the cost of wind turbines decreases. Additionally, wind energy has low operational costs once the turbines are installed and running, since there are no fuel costs like there are for fossil fuel power plants.
What are two potential advantage ?Diverse energy mix: Wind energy can complement other forms of renewable energy such as solar and hydro, providing a more diverse and secure energy mix for a given region or country.
Job creation: The installation and maintenance of wind turbines can create jobs, both in the manufacturing and installation of the turbines, as well as in the ongoing operation and maintenance of wind farms. This can help to boost local economies and provide employment opportunities in rural areas.
Reduced greenhouse gas emissions: Generating electricity from wind turbines produces no direct greenhouse gas emissions, helping to reduce the overall carbon footprint of a given region or country and contribute to mitigating the effects of climate change.
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A 60.-kilogram physics student would weigh 1560
newtons on the surface of planet X. What is the
magnitude of the acceleration due to gravity on the
surface of planet X?
Answer:
26m/s²
Explanation:
Given parameters:
Mass of the student = 60kg
Weight = 1560N
Unknown:
Acceleration due to gravity = ?
Solution:
Weight is a force on a body due to gravity;
Weight = mass x gravity
Insert the given parameters and solve;
1560 = 60 x gravity
Gravity = \(\frac{1560}{60}\) = 26m/s²
A car accelerates from rest to 32 m/s in four seconds. What is the car’s acceleration?
Answer:
A)24m B)17.6m
Explanation: Explanation: 1. From t=2 to t=3 ,. First, we'll find the velocity at time 2s. v=u+at =32ms+(−3.2)ms2⋅2s =25.6ms.
summarize how many methods can be used to determine the index of refraction of an optical material
Accurate determination of the index of refraction is important for many applications in optics and photonics, including lens design, fiber optics, and semiconductor processing.
There are several methods that can be used to determine the index of refraction of an optical material. One common method is to use a spectrometer to measure the angle of refraction as light passes through the material at various wavelengths. Another method involves measuring the critical angle at which total internal reflection occurs, which can be used to calculate the index of refraction. A third method is to use a prism to separate the different wavelengths of light and measure the angle at which each color is refracted. Other techniques include ellipsometry, interferometry, and polarimetry.
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