Consider a house with a floor space of 200 m2and anaverage height of 3 m at sea level, where thestandard atmosphericpressure is 101.3 kPa.Initially the house is at a uniformtemperature of 10°C.Now the electric heater is turned on, andthe heater runs until the air temperature in the house risesto anaverage value of 22°C. Determine how much heat is absorbedby the air assuming some airescapes through the cracks asthe heated air in the house expands at constant pressure. Also,determine the cost of this heat if the unit cost of electricity inthat area is $0.075/kWh.

Answer:

363

Explanation:

80g of kerosene was burned to raise the temperature

k = 90+273

= 363

The graph that best represents the skydiver's kinetic energy during her dive is a graph that starts at 0 at the beginning of the dive, increases to a peak at 15 seconds when the skydiver reaches terminal velocity, and then decreases rapidly after 40 seconds when the parachute is opened.

After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The given parameters;

The position function of the ball after time t, is calculated as follows;

\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

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Answer:

The answer is below

Explanation:

NSPT is an acronym for the National Service Training Program. It deals with the individual's role in society building. Most specifically, the youths in areas such as physical, ethical, virtuous, intellectual, and social well-being.

One can serve the community through the NSTP subject, by involving in creating awareness in literacy and social welfare undertakings, mostly during emergencies and mishaps, or be part of the Citizen Armed Force.

ANSWER

Upright

EXPLANATION

The image formed by a plane mirror is always behind the mirror - so it is a virtual image. Also, the image and the object are the same sizes and the same distance from the mirror and the image is upright.

Hence, all images in plane mirrors are upright.

Roll a skateboard on sand, then roll it on gravel. - this experiment could answer this question. Hence, option (B) is correct.

An experiment is a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before. Experiments show what happens when a specific factor is modified, which sheds light on cause-and-effect relationships.

The purpose and scope of experiments vary widely, but they all rely on a repeatable process and a logical examination of the outcomes. Natural experimental experiments are also a thing.

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(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

I beleive the answer is d

Explanation:

This is beause theball starts going back down because the velocity slows down.

Answer:

d

Explanation:

the velocity changes as it goes down

(a) The initial velocity in component vector form is (14.38 i + 10.83 j), m/s.

(b) The velocity of the ball as it lands in component vector form is (14.38 i + 10.88 j), m/s.

(c) The range of the ball is 31.78 m.

(d)  The assumption made about frame of reference is that the frame of reference is ground level and the ball returned to the ground level after projection.

The component vector form of the initial velocity if written as;

Vx = V cosθ

Vy = V sinθ

where;

Vx = 18 m/s  x  cos(37) = 14.38 i, m/s

Vy = 18 m/s x sin(37) = 10.83 j, m/s

Vi = (14.38 i + 10.83 j), m/s

The time of motion of the ball to reach maximum height is calculated as follows;

t = (Vsinθ)/g

t = (18 x sin37)/g

t = (10.83)/9.8

t = 1.11 s

The final vertical velocity of the ball is calculated as;

Vyf = Vh + gt

where;

Vfy = 0 + 1.11 x 9.8

Vyf = 10.88 m/s

The final horizontal velocity will be equal to initial horizontal velocity since horizontal motion is not affected by gravity.

The velocity of the ball when it lands in component vector form is;

Vf = (Vxf + Vyf), m/s

Vf = (14.38 i   +   10.88 j), m/s

The range of the ball is calculated as;

R = (V²sin2θ)/g

R = (18² x sin(2 x 37))/9.8

R = 31.78 m

The assumption made of about frame of reference;

Thus, the assumption that have been made about the frame of reference is that is was projected from a ground level and returned to the same ground level.

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Writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online (option B).

A journal is a newspaper or magazine dealing with a particular subject.

A journal is an efficient medium to communicate the findings or results of an investigation to the public.

However, a journal can be virtual (online) or paper (hard copy). In this 21st century, it is easier to communicate to the masses online because more audience will be captured.

Therefore, writing in an online journal is different from writing in a paper one in the following way: it is easier to communicate online.

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Answer:

pretty sure its kinetic

Explanation:

Answer:

Kinetic

Explanation:

The stored chemical potential energy of a battery converts to electrical kinetic energy to transport electricity to a light bulb, which radiates thermal kinetic energy.

The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            \(N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}\)

Let's analyze the forces on the student.

          \(N_{student} - W_{student} = 0 \\N_{student} = W _{student}\)

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

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Answer:600N

Explanation:

An athlete can jump a horizontal distance of 6.54 m in the broad jump. All else being equal (same launch speed, same launch angle), acceleration due to gravity has a value of 4.94 m/S² is = 32.3076 m.

To find the Height jumped by athlete on the planet, (y₂) the given data's are:

Height jumped by athlete on Earth (y₁) = 6.54 m

Acceleration on the planet = 4.94 m/s².

We know that, equation of motion can be defined as the displacement is directly proportional to the gravitational acceleration keeping the remaining quantities constant.

So, y ∝ g

Using the proportion equation for the planet and the Earth, then,

y₁ / gE = y₂ / gm

where as,

gm = gE × 4.94 m/s².

Substituting the values, we get,

y₂ = y₁ / gE ×  gm

y₂ = 6.54 ×  4.94

   = 32.3076 m.

Therefore, the height of the athlete can move is 32.3076 m.

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The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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Answer:

Explanation:

There is no acceleration in vertical direction

Fn = mg + Fp sin 35

Frictional force = 99.7 N

Net force in forward direction = Fp cos 35 - 99.7

= 168 cos 35 - 99.7

= 137.61-99.7

= 37.91 N

net acceleration of chair = net force / mass

= 37.91 / 50

= .7582 m / s² .

Attribute conformity is one that classifies each item in the sample as either having some attribute or not having it.

Variation present in your measurement system will affect the quality of the product and can damage your company's brand.

Purpose of Attribute measurement system analysis:

Accuracy check:

To access the customer standard, need to fulfill the customer's requirement, which means MSA performs to identify how good is our measurement system with our masters.

Precision check:

To determine that, the inspector can measure correctly. Is he checking with the same criteria across all shifts, machines, etc… to measure and evaluate parts and also called Repeatability

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In a parallel circuit of resistors the total current of the circuit is the sum of the current in each branch. Which means that:

where n is the number of branches on the circuit.

Answer:

The work is done by the truck pulling the car 1 km is 1,212,436 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

The work is done by the truck pulling the car 1 km is 1,212,436 J

Answer:

The ball has a velocity upwards but the acceleration is downwards. Gravity is giving the ball a downwards acceleration from the moment the ball leaves the hands.

Here’s my work to your question. I used kinematic equations to solve. :)

Answer:

it is 3

Explanation:

because the crack will be open for the magma to come out

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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(a) The speed of the student at the bottom of the hill is 15.34 m/s.

(b) The speed of the student at the presence of friction force is 11.88 m/s.

The speed of the student at the bottom of the hill is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy at the bottom hill = potential energy at maximum height

¹/₂mv² = mgh

where;

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

The speed of the student at the presence of friction force is calculated as;

Kinetic energy at the bottom hill + work done against friction  = potential energy at maximum height

¹/₂mv² + μmgh = mgh

¹/₂v² + μgh = gh

v²  +  2μgh = 2gh

v² = 2gh - 2μgh

v² = (2 x 9.8 x 12) - (2 x 0.4 x 9.8 x 12)

v² = 141.12

v = √141.12

v = 11.88 m/s

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Average force acting on Purley is -1749m/\(s^{2}\).

What is Newton's second law of motion?

According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.

Given,

According to newton's second law of motion:

F =ma

Purley's initial speed = 173km/h

Final speed = 0

Distance traveled = 0.66 m

So, \(v_{i}\) = 172 km/h × 1 hr/3600 s × 1000m/1km

\(v_{i}\) = 48.1 m/s

By using kinematics

\(v^{2} f\) = \(v^{2} i\) + 2ad

\(0^{2}\) = 48.\(1^{2}\) + 2a(0.66)

-1.32a = 2309

a= -1749 m/\(s^{2}\)

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From the given figure, we have a force-displacement curve.

Let's determine what the area of the region enclosed by the curve represents.

Given that the curve is a force-displacement curve, the area of the region under the curve represents the work done by the force on the object.

Here, the distance of the distance of the object is displaced by the force.

Thus, we can say the displacement(x) is represented on the x-axis, while the force(f) is represented on the y-axis.

Therefore, the area of the region enclosed by the curve represents the work done on the object by the force.

ANSWER:

The work done on the object by the force

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

A. 1,000

Explanation:

Kilo is the prefix for thousands, thus, the multiplier that kilo represents is 1,000

A. 1,000

Answer:

B. 1,000

Explanation:

plato