what is the momentum of a 1550kg car that is traveling 38.0 m/s?

Answer:

A

Explanation:

Amplitude = height of the wave = 1

Wavelength = 3

They are slightly shifted.

The first statement is the correct one.  Don't make me type the whole thing out.

The angle θ0 at which the electron is incident between the two plates, we can use the relationship θ0 = arctan(E * L / (2d)).

determine the angle θ0 at which the electron is incident between the two plates, we can consider the forces acting on the electron due to the electric field.

The electric field between the plates is directed from left to right. The force experienced by the electron due to the electric field is given by the equation:

F = q * E

where F is the force, q is the charge of the electron, and E is the electric field strength.

Since the electron is negatively charged, it experiences a force in the opposite direction to the electric field. This force will cause the electron to accelerate in the opposite direction.

When the electron enters the region between the plates:

The force due to the electric field will act on the electron in the opposite direction to its initial motion, causing it to decelerate. The electron will follow a curved path due to this deceleration.

When the electron exits the region between the plates:

The force due to the electric field will act on the electron in the same direction as its final motion, causing it to accelerate. The electron will follow a curved path due to this acceleration.

Since the situation is symmetrical, the angle at which the electron exits the region between the plates will be the same as the angle at which it enters.

We need to determine the angle θ0 at which the electron enters the region between the plates.

Consider a small portion of the path between the plates and assume that the electric field is constant within this small region.

In this small region, the net force acting on the electron can be expressed as:

F_net = F_electric - F_centrifugal

where F_electric is the force due to the electric field, and F_centrifugal is the centrifugal force.

The force due to the electric field can be calculated as:

F_electric = q * E

The centrifugal force can be calculated as:

F_centrifugal = m * \(v^2 / r\)

where m is the mass of the electron, v is its velocity, and r is the radius of the curved path.

The electron is moving in a curved path, the net force acting on it is responsible for the centripetal force required to maintain this curved path.

Setting the net force equal to the centripetal force, we have:

F_electric - F_centrifugal = m * \(v^2 / r\)

Substituting the expressions for F_electric and F_centrifugal, we get:

q * E - m * v^2 / r = m * \(v^2 / r\)

Simplifying the equation, we have:

q * E = 2 * m * \(v^2 / r\)

Since the electron enters and exits the region between the plates with the same speed v, we can simplify further:

q * E = 2 * m *\(v^2 / r\)

The forces acting on the electron when it enters the region between the plates:

The force due to the electric field is acting in the opposite direction to the initial motion, causing deceleration.

The centrifugal force is acting in the same direction as the initial motion, opposing the deceleration.

For the electron to enter the region between the plates, the force due to the electric field must be greater than the centrifugal force.

We have:

q * E > m * \(v^2 / r\)

Since the electron is moving perpendicular to the electric field, the electric force can be expressed as:

q * E = q * (V/d)

where V is the voltage between the plates, and d is the spacing between the plates

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To determine the magnitudes of the velocity and acceleration when x = 20 ft, we need to find the derivative of the given equation with respect to time (t). The magnitudes of the velocity and acceleration when x = 20 ft are 2.69 ft/s and 0.02 ft/s2, respectively.

plug in the given values.
The equation of the curve is: y = x - (x2/400)
Taking the derivative with respect to time (t) gives us:
dy/dt = dx/dt - (2x/400)(dx/dt)
Since the velocity component in the x direction is constant at 2 ft/s, we can plug in dx/dt = 2:
dy/dt = 2 - (2x/400)(2)
Simplifying gives us:
dy/dt = 2 - (x/100)
Now we can plug in the given value of x = 20 ft:
dy/dt = 2 - (20/100) = 1.8 ft/s

This is the velocity component in the y direction. To find the magnitude of the velocity, we use the Pythagorean theorem:
v = √((dx/dt)2 + (dy/dt)2) = √(22 + 1.82) = √(4 + 3.24) = √7.24 = 2.69 ft/s
To find the magnitude of the acceleration, we take the second derivative of the equation with respect to time:
d2y/dt2 = d/dt(dy/dt) = d/dt(2 - (x/100)) = -(1/100)(dx/dt)
Plugging in the given value of dx/dt = 2 gives us:
d2y/dt2 = -(1/100)(2) = -0.02 ft/s2
Since the acceleration in the x direction is zero, the magnitude of the acceleration is simply the absolute value of the acceleration in the y direction:
a = |-0.02| = 0.02 ft/s2

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The horizontal distance traveled by the football is determined as 25.33 m.

The horizontal distance traveled by the football is calculated as follows;

X = u²sin(2θ)/g

where;

X = (18² x sin(2 x 65))/9.8

X = 25.33 m

Thus, the horizontal distance traveled by the football is determined as 25.33 m.

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The relationship between the size of the particles and the velocity of the particles is that smaller particles move faster than larger particles. In other words, as the size of the particle decreases, the velocity of the particle increases. Therefore, the kinetic energy of each particle is directly proportional to the velocity of the particle.

The kinetic energy of each particle is the energy that it possesses due to its motion. When the size of the particle is small, its velocity is high, and thus, it has a higher kinetic energy compared to a larger particle. Therefore, smaller particles have more kinetic energy than larger particles. The relationship between particle size and velocity can be explained by the following equation:

KE = 1/2 mv²

Where, KE is the kinetic energy of the particle, m is the mass of the particle, and v is the velocity of the particle. From the equation, it can be seen that the kinetic energy of a particle is directly proportional to the square of its velocity. This means that if the velocity of a particle is doubled, its kinetic energy will increase by a factor of four. Hence, as the size of the particle decreases, its velocity increases, leading to a higher kinetic energy. This conclusion is in line with the basic laws of physics.

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Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

Answer:

Momento = 170.8 Kgm/s

Explanation:

Dados los siguientes datos;

Masa = 3,05 kg

Velocidad = 56 m/s

Para encontrar el impulso;

El momento se puede definir como la multiplicación (producto) de la masa que posee un objeto y su velocidad. El momento se considera una cantidad vectorial porque tiene magnitud y dirección.

Matemáticamente, el momento viene dado por la fórmula;

\( Momento = masa * velocidad \)

Sustituyendo en la fórmula, tenemos;

\( Momento = 3.05 * 56 \)

Momento = 170.8 Kgm/s

Answer:

you didnt show a picture i need to see the problem sorry

Answer:

The Correct answer is A a taut guitar string.

Their electrical potential energy will decrease, their kinetic energy will increase, and they will travel towards each other.

When two negative charges are released and constrained to remain close together, the charges will be repelled by each other due to their opposite electrical charges.

This repelling force causes the charges to move away from each other, increasing their kinetic energy and decreasing their electrical potential energy.

Since they are constrained to remain close together, they will travel towards each other until they come into contact. At that point, the electrical potential energy will reach its minimum, and the kinetic energy will reach its maximum.

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The following formula may be used to determine how large the electric field is within the aluminium wire:

E = J/σ

E, J, and are the electric field, the current density, and the conductivity of aluminium, respectively.

where A is the wire's cross-sectional area and I is the current.

The following formula may be used to get the cross-sectional area of the wire:

A = πr^2

where r is the wire's radius.

We obtain the following by substituting the aluminum's electrical conductivity value from the problem:

E = J/σ

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Velocity is a vector quantity. The velocities of the two players will not be the same.

Speed is a scalar quantity. That is, it has magnitude but no direction. While velocity is a vector quantity. That is, it has both magnitude and direction.

Given that after a tennis match the two players dash to the net to shake hands. If they both run with a speed of 3 m/s, That means they both have the same speed but their velocities are not equal.

Their velocities are not equal in the sense that the two players are moving in opposite directions to each other.

Since they are moving in different direction, they will have two different velocities of 3m/s and - 3 m/s

Therefore, the two players moving in different velocities of 3m/s and - 3 m/s

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Answer:

Explanation:

C

In charging by induction, a charged object is brought near an object without touching it. The presence of the charge object induces electron movement and a polarization of the object. Then conducting pathway to ground is established and electron movement occurs between the object and the ground. During the process, the charged object is never touched to the object being charged.

Answer:

A. True it's right solids have a definite shape and volume.

Answer:

t = 2.7 seconds

Explanation:

Given that,

Initial speed, u = 3.8 m/s

Final speed, v = 4.2 m/s

Acceleration of Michael, a = 0.15 m/s²

(a) Let t is the time taken by him to catch Robert. It can be calculated as follows :

\(a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{4.2-3.8}{0.15}\\\\t=2.7\ s\)

So, the time taken is 2.7 seconds.

Given :

A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m

this wrecking ball is released from an angle of 40 degrees.

To Find :

The height  from the lowest point of the arc.

Solution :

From the attached image we have to find the value of  h.

So,

\(cos \ 40^o = \dfrac{L-h}{L}\\\\0.76=\dfrac{25-h}{25}\\\\h = 25( 1- 0.76)\\\\h = 6 \ m\)

Hence, this is the required solution.

The luminosity of a star is directly proportional to its brightness and the square of its distance from Earth. In this scenario, let's assume the closer star has a luminosity of 1 unit.

Since the second star is three times farther away, its distance from Earth would be 3^2 = 9 times greater than the closer star. Given that the second star is also twice as bright, its total luminosity would be 9 x 2 = 18 units. The second star's luminosity would be 18 times greater than that of the first star. This is because luminosity depends on both the brightness and the square of the distance from Earth. The second star is three times farther away and twice as bright, resulting in a luminosity that is 18 times higher compared to the first star.

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The length of the pendulum is 3.3 m.

The given parameters:

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

g(L - Lcosθ) = ¹/₂v²

gL(1 - cosθ) = ¹/₂v²

\(L = \frac{v^2}{2g(1- cos\theta)} \\\\L = \frac{(3.4)^2}{2\times 9.8(1 - cos35)} \\\\L = 3.28 \ m\\\\L = 3.3 \ m\)

Thus, the length of the pendulum is 3.3 m.

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Answer:

Option B

Explanation:

As we know

Frequency (F) * wavelength (W) = C (speed of light - can also be taken as constant)

Hence,

\(F1 W1 = C\\F2W2 = C\)

Or \(F1W1 = F2W2\)

Substituting the given values, we get -

\(840 *2.5 = 500 *XX = 4.2\) m

Hence, option B is correct

The flux of the electric field through the spherical surface due to the two charges is approximately 2.26 x 10^4 N·m²/C.

To find the flux of the electric field through a spherical surface of radius R due to two charges, one at the center and another at a point 2R away from the center, we can use Gauss's Law.

Gauss's Law states that the flux (Φ) of the electric field through a closed surface is equal to the total enclosed charge divided by the permittivity of free space (ε₀).

Given:

Charge at the center (Q₁) = 10^(-7) C

Charge at a point 2R away from the center (Q₂) = 10^(-7) C

Radius of the spherical surface (R) = R

First, let's calculate the total enclosed charge by adding the two charges:

Q = Q₁ + Q₂

Q = (10^(-7) C) + (10^(-7) C)

Q = 2 * 10^(-7) C

Now, we can calculate the flux using Gauss's Law:

Φ = Q / ε₀

The permittivity of free space (ε₀) is approximately 8.85 x 10^(-12) C²/(N·m²). Substituting the values:

Φ = (2 * 10^(-7) C) / (8.85 x 10^(-12) C²/(N·m²))

Simplifying:

Φ = 2 * 10^(-7) C * (1 / (8.85 x 10^(-12) C²/(N·m²)))

Φ = (2 * 10^(-7) C) * (1.13 x 10^11 N·m²/C²)

Φ ≈ 2.26 x 10^4 N·m²/C

Therefore, the flux of the electric field through the spherical surface due to the two charges is approximately 2.26 x 10^4 N·m²/C.

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≈ 0.47 m/s²

Hi there !

Acceleration formula

a = (v₂ - v₁)/t

a = (26.8m/s - 24.8m/s)/4.3s

= (2m/s)/4.3s

≈ 0.47 m/s²

Good luck !

Out of the four students looking in the mirror, Max is the one who makes the correct statement about the light reflected in the mirror. Max says that neither the speed nor the direction of the light is changing (Statement D).

This is because the light that reflects off an object and into a mirror does not change its speed or direction. It simply bounces off the object and into the mirror, where it is reflected back to the observer's eyes.
Alex's statement is incorrect because the angle of incidence and angle of reflection determine the direction of the reflected light.

Ansley's statement is incorrect because the speed of light is constant and does not change when it reflects off an object and into a mirror. Katherine's statement is also incorrect because the speed of light is constant and does not change when it reflects off an object and into a mirror.
In summary, Max is correct in saying that neither the speed nor the direction of the light is changing when it is reflected off an object and into a mirror. This is due to the laws of reflection that dictate how light interacts with a mirror.

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The total energy in the LC circuit is approximately 1.3333 × 10^(-6) J. Among the given options, the closest value to this is 1.3 × 10^(-6) J, so the correct answer is (b) 1.3 × 10^(-6) J.

To find the total energy in an LC circuit, we can use the formula:

E = (1/2) * C * V^2

Where:

E is the total energy,

C is the capacitance, and

V is the voltage across the capacitor.

Given:

L = 30 mH = 30 × 10^(-3) H (inductance)

C = 6.0 uF = 6.0 × 10^(-6) F (capacitance)

q = 40 C (charge on the capacitor)

I = 6.0 mA = 6.0 × 10^(-3) A (current)

At time t = 0, the energy in the circuit is stored entirely in the capacitor, and there is no energy stored in the inductor. Therefore, the total energy can be calculated by finding the energy stored in the capacitor alone.

The voltage across the capacitor is given by:

V = (1/C) * q

Substituting the given values:

V = (1/(6.0 × 10^(-6))) * 40

V = 6.67 × 10^6 V

Now, we can calculate the total energy using the formula:

E = (1/2) * C * V^2

E = (1/2) * (6.0 × 10^(-6)) * (6.67 × 10^6)^2

E = (1/2) * (6.0 × 10^(-6)) * (4.4489 × 10^(13))

E ≈ 1.3333 × 10^(-6) J

Therefore, the total energy in the LC circuit is approximately 1.3333 × 10^(-6) J.

Among the given options, the closest value to this is 1.3 × 10^(-6) J, so the correct answer is (b) 1.3 × 10^(-6) J.

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Answer:

about 301 mph 5.7 west of north

Explanation:

The resultant velocity of the jet is 301.496 m/s which is a resultant of two velocities in north direction and west direction.

The resultant velocity of an object is the sum total of its individual vector velocity components.

The formula for the calculation of resultant velocity in the straight line is:

V = V₁ + V₂+....

In the given condition, a jet begins a flight along north at 300 miles per hour and 30 miles per hour due west.

The resultant velocity of the jet can be calculated through Pythagoras theorem:

Resultant velocity = \(\sqrt{(V1)^{2} + (V2)^{2}\)

where, V1 = Velocity due North

V2 = Velocity due West

Resultant velocity = \(\sqrt{(300)^{2} + (30)^{2}\)

Resultant velocity = \(\sqrt{90000 + 900\)

Resultant velocity = \(\sqrt{90900\)

Resultant velocity = 301.496m/s

Therefore, the resultant velocity of the jet is 301.496m/s.

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Answer:

b

Explanation:

Answer:

The answer is A) 29 meters

Explanation:

I got this question right on the test! :)

The central region of the Milky Way, specifically the galactic bulge and halo, contains mostly old (Population II) stars and globular clusters. Population II stars are older, metal-poor stars that formed early in the universe's history, primarily consisting of hydrogen and helium.

These stars have lower masses and are typically found in globular clusters, which are densely packed, spherical collections of stars that orbit the galactic center.

The galactic bulge is the central, elongated region of the Milky Way, characterized by its high concentration of stars, gas, and dust. Population II stars are more abundant in this area due to their age and the early formation of the Milky Way. Similarly, globular clusters are often found in the bulge due to their strong gravitational pull towards the center of the galaxy.

In contrast, the galactic halo is the outermost region of the Milky Way, encompassing both the galactic disk and the bulge. While the halo is relatively sparse compared to the bulge, it is still home to a significant number of Population II stars and globular clusters. These ancient stars and clusters in the halo provide crucial insights into the formation and evolution of our galaxy.

In summary, the central region of the Milky Way, including the galactic bulge and halo, contains a majority of the old (Population II) stars and globular clusters, reflecting the early history and development of our galaxy.

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Answer: Hydrogen is a chemical element with atomic number 1 which means there are 1 protons in its nucleus. Total number of protons in the nucleus is called the atomic number of the atom and is given the symbol Z.

Explanation: hope this helps

The wavenumber, represented as 1/λ, is directly related to the energy of a photon. The relationship between the two can be described by the equation E = hc(1/λ), where E is the energy of a photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. As the wavelength of a photon decreases, its wavenumber increases, and its energy also increases.

This relationship is important in various fields, including spectroscopy, where it is used to determine the energy levels of atoms and molecules by analyzing the wavelengths of the light they emit or absorb.


Since frequency is related to the speed of light (c) and wavelength (λ) through the equation ν = c / λ, we can substitute this into the Planck's equation to get E = h(c / λ).

Now, the wavenumber (1 / λ) can be denoted as k. So, k = 1 / λ. By rearranging the equation, we get λ = 1 / k. Substituting this into the energy equation, we have E = h(c / (1 / k)), which simplifies to E = hck.

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Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s