At what temperature does a process with [delta]h = 20. kj and [delta]s = 300. j become spontaneous? (give the answer in 3 sig figs)

One reason that electromagnetic waves are used in long-distance communication is, that they do not lose energy over long distances. So Option C   is correct

Electromagnetic waves are a type of wave that consists of oscillating electric and magnetic fields. They are propagated through space or through a material medium, and they have the ability to travel through a vacuum, which is the absence of matter. Electromagnetic waves have a wide range of frequencies, which determines the type of electromagnetic wave. The most familiar types of electromagnetic waves include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

One of the property of the electromagnetic waves is that they do not lose energy over long distances.

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We know, formula of capacitance in parallel plate capacitor is given by :

\(C = \dfrac{\epsilon_o A}{d}\)

Here, \(\epsilon_o = 8.85 \times 10^{-12} \ F.m^{-1}\)

So,

\(A = \dfrac{Cd}{\epsilon_o}\\\\A = \dfrac{1.11 \times 10^{-9}\times 8.89 \times 10^{-7}}{8.85\times 10^{-12}}\\\\A = 1.11 \times 10^{-4}\ m^2 \ or \ 1.11 \ cm^2\)

Hence, this is the required solution.

Answer:

7.09797297 • 10^-7

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 8.89 • 10^-7

D = 1.11• 10 ^-9

So:

C = (8.85 • 10^-12)(8.89• 10^-4)/1.11 • 10 ^-9 = 7.09797297 • 10^-7

Good Luck!  :)

The horizontal displacement from the firing position to the point of impact is approximately 2,425 meters. The projectile hits the ground with a speed of approximately 230.4 meters/second.

To calculate the horizontal displacement of the projectile, we need to find the time of flight and then multiply it by the horizontal component of the initial velocity.

Step 1: Find the time of flight

Using the given initial muzzle speed and launch angle, we can find the time of flight. The vertical component of the initial velocity can be determined by multiplying the initial speed by the sine of the launch angle. Since the projectile is launched from a height of 4 meters, the time it takes for the projectile to reach the ground can be calculated using the equation h = ut + (1/2)gt^2, where h is the height, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight. Plugging in the known values, we get 4 = (370 * sin(40))t - (1/2)(9.8)t^2. Solving this equation yields t ≈ 7.28 seconds.

Step 2: Calculate the horizontal displacement

The horizontal component of the initial velocity can be found by multiplying the initial speed by the cosine of the launch angle. The horizontal displacement is then given by multiplying the horizontal component of the initial velocity by the time of flight. Therefore, the horizontal displacement is approximately 370 * cos(40) * 7.28 ≈ 2,425 meters.

Step 3: Determine the speed at impact

To find the speed at which the projectile hits the ground, we need to calculate the vertical component of the velocity at the time of impact. The vertical component of the velocity can be determined by multiplying the initial speed by the sine of the launch angle and subtracting the product of the acceleration due to gravity and the time of flight.

Thus, the vertical component of the velocity at impact is given by 370 * sin(40) - 9.8 * 7.28 ≈ -230.4 meters/second. The negative sign indicates that the velocity is directed downwards. Therefore, the speed at which the projectile hits the ground is approximately 230.4 meters/second.

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Answer: 660 N.

Explanation: Force on a free falling body is F=mg.

Therefore, Force =66×10 =660

(g is gravitational acceleration, taking it as 10)

Answer:

Explanation:

Given:

V₀ = 3.0 m/s

H = 5.2 m

__________

L - ?

Time for the ball to fall vertically:

H = g·t²/2;    ⇒    t = √ (2·H / g) = √ (2·5.2 / 9.8) ≈ 1.0 c

Move the ball horizontally:

L = V₀·t = 3.0·1.0 = 3.0 m

If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground , then the horizontal displacement of the ball is 3.09 meters.

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem If a boy throws a ball with a horizontal velocity of 3.0 m/s, from a height of 5.2 m over the ground

S = ut + 1/2 × a × t²

5.2 = 0 + 0.5 × 9.8 ×  t²

t² = 5.2 / 4.9

t = 1.03 seconds

The horizontal displacement of the ball = 1.03 × 3

                                                                  = 3.09 meters

Thus, the horizontal displacement of the ball is 3.09 meters.

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A client diagnosed with atrial fibrillation may undergo a procedure called catheter ablation.

This procedure involves the use of radiofrequency energy or heat to create small scars on the heart tissue that block the abnormal electrical signals responsible for the atrial fibrillation.

The procedure is performed using a long, thin tube called a catheter, which is inserted into a blood vessel in the leg or arm and threaded to the heart. Once the catheter is in place, the energy is delivered through the tip of the catheter to the specific areas of the heart where the abnormal electrical signals are coming from. The heat generated by the energy creates small scars in the tissue that block the signals, preventing them from reaching the rest of the heart.

Catheter ablation is a minimally invasive procedure that is typically performed under local anesthesia and sedation. It is an effective treatment option for atrial fibrillation and has a high success rate in eliminating the symptoms of the condition.

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The sound intensity level at 20 m from the ambulance siren is:x = 2.5 dB

The given problem states that the sound intensity level at a distance of 200 m from an ambulance siren is 65 dB and we need to calculate the sound intensity level at 20 m from the siren. Let us assume that the sound intensity level at a distance of 20 m from the siren be x dB.

Now we know that the sound intensity level at any point is given by the following formula: IL = 10log(I/I0), where I is the sound intensity and I0 is the threshold of hearing, which is equal to 10^-12 W/m^2.

So the sound intensity level 200 m away from the ambulance siren, which is 65 dB, can be written as:

65 = 10log(I/10^-12)

65/10 = log(I/10^-12)

6.5 = log(I/10^-12)I/10^-12 = antilog(6.5)I/10^-12 = 3.162 * 10^-7 W/m^2

Similarly, the sound intensity level at a distance of 20 m from the ambulance siren, which is x dB, can be written as:x = 10log(I/10^-12)x/10 = log(I/10^-12)x/10 = log(I) - log(10^-12)x/10 = log(I) + 12/10x/10 - 12 = log(I)I/10^-12 = antilog(x/10 - 12)I/10^-12 = 10^(x/10) * 10^-12 W/m^2

Since the sound intensity level remains constant, the sound intensity at a distance of 200 m and 20 m is the same. Therefore, equating the above two expressions, we get:3.162 * 10^-7 = 10^(x/10) * 10^-12 3.162 = 10^(x/10)10^(x/10) = 3.162

Taking the logarithm of both sides, we get:x/10 = log(3.162)x/10 = 0.5x = 5log(3.162)x = 5 * 0.5x = 2.5

Therefore, the sound intensity level at 20 m from the ambulance siren is:x = 2.5 dB

Sound intensity level at 20 m from the ambulance siren is 2.5 dB.

Answer: 2.5 dB

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Answer:

Kindly check explanation

Explanation:

Given the following information :

Distance between Angela and Blake = 15m

Angela's speed = 5m/s at t = 0

Angela's direction = Right = positive

Blake's speed = 3m/s at t = 0

Blake's direction = left = negative

Position or distance = speed × time

Hence,

Combined speed = (3 + 5) = 8m/s

Distance = 15m

Time = distance / speed

Time = 15 / 8

Time they meet = 1.875 seconds

Distance covered by Angela :

Speed × time

= 5 × 1.875 = 9.375 meters

The equation for the distance traveled by Angela is 5t and the distance covered by Angela  is 9.375 m.

The given parameter:

let the time at which Angela and Blake meet = t

The equation for the distance traveled by Angela = 5t

The time (t) at which Angela and Blake meet will be calculated using relative velocity concept:

since they are closing the distance together, we will add their velocities

(i.e they are working together and not against each other)

\((V_A +V_B) t = 15\\\\(5 + 3) t = 15\\\\8t = 15\\\\t = \frac{15}{8} \\\\t = 1.875 \ s\)

The distance covered by Angela = 1.875 s x 5 m/s = 9.375 m

The distance covered by Blake = 1.875 x 3 m/s = 5.625 m

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The amount of energy that must be absorbed by the 150g sample of ice at 0.0°C is 131,873.55 J.

To calculate the amount of energy that must be absorbed by a 150g sample of ice at 0.0°C, we need to consider two processes: heating the ice from -273.15°C to 0.0°C and melting the ice at 0.0°C.

1. Heating the ice:

The specific heat capacity of ice is 2.09 \(\frac{J}{g ^\circ C}\), and the temperature change is 0.0 - (-273.15) = 273.15°C.

\(Q_1\) = (mass) × (specific heat capacity) × (temperature change)

\(Q_1\) = 150g × 2.09 × 273.15°C

\(Q_1\) =81,773.55 J

2. Melting the ice:

The heat of fusion (enthalpy of fusion) for ice is 334 J/g.

\(Q_2\) = (mass) × (heat of fusion)

\(Q_2\) = 150g × 334 J/g

\(Q_2\) = 50,100 J

The total energy required is the sum of Q1 and Q2:

Total energy = \(Q_1\) + \(Q_2\)

Total energy = 81,773.55 J + 50,100 J

Total energy = 131,873.55 J

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Answer:

it should be right it's from go.ogle hm!!!

Explanation:

Anterior or ventral - front (example, the kneecap is located on the anterior side of the leg). Posterior or dorsal - back (example, the shoulder blades are located on the posterior side of the body). Medial - toward the midline of the body (example, the middle toe is located at the medial side of the foot).

Answer:

Anterior refers to the side of the structure facing up in the standard anatomical position while posterior refers to the bottom side. ... Dorsal and ventral are sometimes used in place of anterior and posterior, respectively. Dorsal means the back side or upper side, while ventral means the frontal or lower side.

The Kookaburra did 9.274 joules of work on the snake. To calculate the work done by the kookaburra on the snake, we can use the formula: Work = Force x Distance x cos(theta)

Where Force is the upward force exerted by the bird on the snake, Distance is the vertical distance through which the snake is raised, and theta is the angle between the force and the displacement, which is 0 degrees in this case because the force and displacement are in the same direction.

First, we need to calculate the force exerted by the bird on the snake. Since the bird is lifting both its own weight and the weight of the snake, we need to find the total weight being lifted: Total weight = Weight of bird + Weight of snake; Total weight = 350 g + 79.6 g; Total weight = 429.6 g

The force required to lift this weight is equal to the weight multiplied by the acceleration due to gravity (g), which is approximately 9.81 m/s^2:

Force = 429.6 g x 9.81 m/s^2

Force = 4.216 N

Next, we need to calculate the distance the bird lifted the snake, which is given as 2.20 m in the problem. Now we can plug these values into the formula for work:

Work = Force x Distance x cos(theta)

Work = 4.216 N x 2.20 m x cos(0 degrees)

Work = 9.274 J

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The longest wavelength λ water of the light in water that is transmitted most easily to the diver is 475 nm.


When light travels from a denser medium to a rarer medium, it bends away from the normal.

According to Snell's law, it can be expressed as follows:

n1sinθ1 = n2sinθ2

where n1 is the refractive index of the first medium,

θ1 is the angle of incidence,

n2 is the refractive index of the second medium,

and θ2 is the angle of refraction.

Here, n1 = 1.33 (refractive index of water),

n2 = 1.5 (refractive index of oil), and θ1 = 0

(since the light is traveling perpendicular to the surface).

Using the formula, we get θ2 = 0.869 radians.

Also, since the wavelength of the light is smaller than the thickness of the oil, we can ignore the reflection from the upper surface of the oil.

The wavelength of the light that will be transmitted most easily can be calculated using the formula

λwater = λoil / n2. Substituting the values, we get λ water = (632.8 nm / 1.5) = 421.9 nm.

However, since this is the shortest wavelength, we need to calculate the longest wavelength, which will be transmitted most easily.

Thus, we get λwater = 2 * λoil / n2 = 2 * 632.8 nm / 1.5 = 475 nm.

Therefore, the longest wavelength λwater of the light in water that is transmitted most easily to the diver is 475 nm.

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ANSWER

2304 mg

EXPLANATION

The rate is given in mg per minute. To find how much the brain's mass increases in one day we have to find how many minutes are in a day.

Assuming that a day has 24 hours and 1 hour has 60 minutes:

One day has 1440 minutes. Then, in one day the brain's mass increases:

The newborn baby's brain's mass increases 2304 mg in one day.

Answer:

VR = \(\frac{Radius of the wheel}{Radius of the axle}\)

Explanation:

Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.

A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:

VR = \(\frac{Radius of the wheel}{Radius of the axle}\)

For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.

Answer:

You can use a block and an inclined plane (just a tilted board)

Place the block on the plane and gradually increase the angle the plane makes with the horizontal.

Static friction will keep the block in place (no sliding) until the angle between the plane and the horizontal is large enough. The block will now slide but is still under the influence of kinetic friction. Thus static friction is greater than sliding friction.

The correct order of increasing impedance is:

C. PZT, gel, skin, matching layer

Impedance is a measure of the opposition to the flow of sound waves in a medium. It depends on the density and speed of sound in the material. In the given options, the order of increasing impedance can be determined by considering the properties of the materials involved.

PZT (lead zirconate titanate) has a higher impedance than gel, skin, and the matching layer. PZT is a piezoelectric material commonly used in ultrasound transducers and has a higher density and speed of sound, leading to higher impedance.

Gel has a lower impedance compared to PZT but higher impedance than skin and the matching layer. Gel is used as a coupling medium between the transducer and the skin to enhance acoustic coupling and minimize impedance mismatch.

Skin has a lower impedance than both gel and the matching layer. It is the outermost layer and acts as an interface between the transducer and the biological tissue.

The matching layer has the lowest impedance among the given options. It is designed to match the impedance of the PZT to the impedance of the tissue being imaged, facilitating efficient sound transmission.

Therefore, the correct order is C.

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Answer:

b

Explanation:

Answer:

1 km

Explanation:

Bob travels at one km/h and it takes him one hour to get there.

The bed slope required to produce the same tractive force on the bed with a discharge of 365 million m³/day can be determined using the given equation for mean velocity variation.

Bed width (B) = 600 m

Initial discharge (Q1) = 120 million m³/day

Initial bed slope (S1) = 7.5 cm/km

The equation for mean velocity (v) = 120 y^(2/3), where y is the water depth.

To find the bed slope (S2) for a new discharge (Q2) of 365 million m³/day, we need to equate the tractive force on the bed for both scenarios.

The tractive force on the bed can be represented as:

Tractive force =\((Rho * g * S * B * v^2) / (R * D50)\)

where:

Rho is the density of water,

g is the acceleration due to gravity,

S is the bed slope,

B is the bed width,

v is the mean velocity, and

R and D50 are constants.

Since we are comparing two scenarios with the same tractive force, the following equation can be formed:

\((Rho * g * S1 * B * v1^2) / (R * D50) = (Rho * g * S2 * B * v2^2) / (R * D50)\)

Simplifying the equation:

\(S1 * v1^2 = S2 * v2^2\)

Substituting the given values:

\(S_1 * (120 y_1^{(2/3))^2 = S_2 * (120 y_2^{(2/3))^2\)

Rearranging the equation:

\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)

We know that Q = B * v * y, where Q is the discharge. Rearranging this equation gives:

\(v = Q / (B * y)\)

Substituting the values for Q1 and Q2, we have:

\(v1 = 120 million / (B * y1)\)

\(v2 = 365 million / (B * y2)\)

Substituting the expressions for v1 and v2 in the equation from step 7:

\(S_2 = S_1 * (120 y_1^{(2/3)})^2 / (120 y_2^{(2/3)})^2\)

\(= S_1 * (120^2 * y_1^{(4/3)}) / (120^2 * y_2^{(4/3)})\)

\(= S_1 * (y_1^{(4/3)} / y2^{(4/3)})\)

Since the bed material just begins to move when Q = 120 million m³/day, the velocity can be expressed as \(v = v_1 = 120 y1^{(2/3)}.\)

Therefore, the equation for S2 becomes:

\(S_2 = S_1 * (y_1^{(4/3)} / y_2^{(4/3)})\)

=\(S_1 * (120^{(4/3)} * y_1^{(4/3) }/ (120 y_2^{(2/3)})^{(4/3))\)

\(= S_1 * (120^{(4/3)} * y1^{(4/3)} / (120^{(4/3)} * y2^{(4/3)}))\)

\(= S_{1 * (y_1^{(4/3)} / y_2^{(4/3)})\)

Finally, substituting the values for y1 and y2:

\(S_2 = S_1 * (y_1^{(4/3) }/ y_2^{(4/3)})\)

= \(S_1 * (y_1^{(4/3)} / (365 / 120)^{(4/3)})\)

Now, you can substitute the values for y1, and S1, and calculate S2 accordingly.

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Answer:

It improves mental clarity allowing you to think better

it allows you to take a break from studying and provides a healthy destressor

Alleviates feelings of stress

Explanation:

When you display the voltage across the variable resistance R in a circuit, you indirectly observe the current flowing in the circuit.

The relationship between current (I), voltage (V), and resistance (R) is described by Ohm's Law, which states:
V = I * R
In this case, the voltage across the variable resistance 'r' gives you information about the current flowing through that resistor. By knowing the voltage (V) and resistance (R), we can calculate the current (I) using the formula:
I = V / R
So, when you display the voltage across the variable resistance 'r,' you indirectly observe the current flowing in the circuit by using Ohm's Law to relate the voltage and resistance to the current.

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Answer:

Work is said to be done when there is change in the position of the object due to the force applied on it.

Explanation:

Hope this helped! Nya~ :3

To calculate the electric field magnitude, we need to know the charge distribution of the system and the distance from the center of the sphere or the charge distribution.

Assuming that the system is spherically symmetric and the charge distribution is uniform, the electric field magnitude can be calculated using Coulomb's law and the formula for the electric field due to a charged sphere. If the system is not spherically symmetric, we need to use integration to calculate the electric field magnitude.

In general, the electric field magnitude decreases as we move away from the charged object or the charge distribution. The electric field magnitude also depends on the distance from the charged object or the charge distribution and the amount of charge present in the system. The constant ε0, known as the permittivity of free space, also plays a crucial role in determining the electric field magnitude. It is a fundamental constant of nature that relates the electric field to the charge density of the system.

To summarize, the magnitude of the electric field for r>d depends on the charge distribution of the system, the distance from the center of the charge distribution, and the permittivity of free space.

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momentum depends on mass (m) and velocity (v) of object

momentum (p) = m × v

we can get the same value of momentum (m) by different pair values of m and v, for example if a truch has more mass and less velocity and the bike has less mass but more velocity then there must be a case when their momentum is same.

correct answer

3-) One had less mass but greater velocity

Answer:

Originally Sonu and image is 8 m (4 m to mirror and 4 m to image)

If he moves 1 m towards the mirror the image distance will be reduced to  (c) 6 m

Answer:

The answer is below

Explanation:

Using the equation of newton law of motion for an object thrown vertially upwards:

v = u - gt

where u is the initial velocity, g = acceleration due to gravity and t is the time taken to reach maximum height.

Given that u = 30 m/s, at maximum height, v = 0, g = 10 m/s². Therefore:

0 == 30 - 10t

10t = 30

t = 30/10

t = 3 seconds

b) The time taken to reach the highest point = 3 seconds. Therefore the total time before it returns back to its original height = 2t = 2(3) = 6 seconds

The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts