aplicando a lei das proporcoes definidas,calcule a massa do elemento sodio existente em 10 g de sulfato de sodio

Answer:

A)

Explanation:

It estimates the probability of extinction.

Answer:

Calcium carbonate is an ionically bonded compound.

Covalent Bond: This bond is formed because atoms share a pair of electrons through an orbital.

Answer:

they're

Explanation:

solid, liquid and gas

The mass of copper deposited is approximately \(1.32 * 10^{(-3) }g\), and the mass of silver deposited is approximately \(2.23 * 10^{(-3)} g\).

To calculate the masses of copper and silver deposited, we need to use the concept of Faraday's law of electrolysis, which states that the amount of substance deposited during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte.

First, we need to calculate the total charge (Q) passed through the circuit using the equation:

Q = I * t

where I is the current (0.4 A) and t is the time (5 hours). Therefore,

Q = 0.4 A * 5 hours = 2 C (Coulombs)

Next, we need to determine the amount of substance deposited using the equation:

n = Q / F

where n is the number of moles of the substance and F is the Faraday constant. The Faraday constant represents the charge of one mole of electrons and is approximately 96,485 C/mol.

For copper (Cu), the molar mass is approximately 63.55 g/mol, and for silver (Ag), the molar mass is approximately 107.87 g/mol.

Using the molar mass and the number of moles, we can calculate the mass of the substance deposited using the equation:

Mass = n * molar mass

Let's calculate the masses of copper and silver deposited:

For copper (Cu):

n(Cu) = Q / F = 2 C / 96485 C/mol ≈ \(2.07 * 10^{(-5)\) mol

Mass(Cu) = n(Cu) * molar mass(Cu) = \(2.07 * 10^{(-5)\) mol * 63.55 g/mol ≈ \(1.32 * 10^{(-3)} g\)

For silver (Ag):

n(Ag) = Q / F = 2 C / 96485 C/mol ≈ \(2.07 * 10^{(-5)\) mol

Mass(Ag) = n(Ag) * molar mass(Ag) = \(2.07 * 10^{(-5)\)mol * 107.87 g/mol ≈ \(2.23 * 10^{(-3)\\}g\)

Therefore, the mass of copper deposited is approximately \(1.32 * 10^{(-3)} g\), and the mass of silver deposited is approximately \(2.23 * 10^{(-3)\\}g\)

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The increasing order of the density of the given objects is :

Ping pong ball <  Bottled cap < Marble

The density of an object can be determined by the mass per unit volume. The average density of the material will be equal to the total mass divided by its total volume.

The mathematical formula for the calculation of the density of the material can be written as follows:

Density = Mass/Volume

The density has the S.I. unit of Kg/m³ and is an intrinsic property as it is independent of its size. The mass increases, if the size of the object increases, but the density remains constant.

The density of the marble lies between 2.5 to 2.7 g/cm³. The density of the ping pong ball is around 0.084 g/cm³. The material used to make ping pong balls new type of ABS plastic. A bottle cap is made of polypropylene and has a density of 0.92g/cm³.

Therefore, marble has the highest density and ping pong ball has least density.

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Answer:

11.1 cm

Explanation:

First we convert 58.1 pounds into grams:

Then we calculate the volume of the gold cube, using the given density:

26353.69 g ÷ 19.3 g/mL = 1365.48 mL

With the volume of a cube we can calculate the side length:

Answer:

1500ml

Explanation:

molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1

The general method/rule/formula for calculating where a ball will land depends on various factors such as the initial velocity, angle of projection, air resistance, and gravity.

In general, the most common method to calculate the landing position of a projectile is to use the kinematic equations of motion, which relate the position, velocity, and acceleration of an object. These equations can be used to determine the time it takes for the ball to hit the ground and the horizontal distance it travels during that time.

However, the calculation can become more complex when considering factors like air resistance and varying conditions, and may require more advanced mathematical models.

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Answer:weather

Explanation:

Answer:

the molarity of the solution is 0.25 M.

Explanation:

To calculate the molarity of a solution, we need to know the amount of solute in moles and the volume of the solution in liters.

The first step is to calculate the amount of KOH in moles using its molar mass. The molar mass of KOH is the sum of the atomic weights of potassium (39.1 g/mol), oxygen (16.0 g/mol), and hydrogen (1.0 g/mol):

Molar mass of KOH = 39.1 g/mol + 16.0 g/mol + 1.0 g/mol = 56.1 g/mol

The amount of KOH in moles is:

moles of KOH = mass of KOH / molar mass of KOH

moles of KOH = 42.1 g / 56.1 g/mol

moles of KOH = 0.750 moles

Now that we know the amount of KOH in moles, we can calculate the molarity of the solution:

Molarity = moles of solute / liters of solution

Molarity = 0.750 moles / 3.0 L

Molarity = 0.25 M

Therefore, the molarity of the solution is 0.25 M.

Answer: 9.23 moles of solute

Explanation: It's a hard explanation so you can just have the answer.

I would say Phenolphthalein

Answer:

hydrochloric acid

Explanation:

chemical compound any substance composed of identical molecules consisting of atoms

Answer:

Kinetic energy

Explanation:

Answer:

1s

not allowed

3d

not allowed

not allowed

4d

5f

Explanation:

Coefficient = n

l = n-1, where 0=s, 1=p, 2=d, 3=f

ml = -l to +l

The quantum numbers are used to show the arrangement of electrons in orbitals in an atom.

There are four sets of quantum numbers;

Now we are going to assign orbitals to each arrangement of quantum numbers as shown below;

n        l         ml          orbital

1         0        0            1s

3        -3        2           not allowed

3        2        -2           3d

2        0        -1           not allowed

0        0        0           not allowed

4        2         1           4d

5        3         0          5f

We can see that s p d f corresponds to l = 0 1 2 3.

Also note that;

When l = 0 then m= 0

When l= 1, m = -1, 0, 1

When l= 2  m = -2, -1, 0, 1, 2

When l =3  m = -3, -2, -1, 0, 1, 2, 3

Note that n must take positive integer values greater than zero.

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First, we have to remember the equation to calculate the heat of evaporation:

Q is the heat, ΔH is the vaporization heat of the substance, and m is the mass.

If we have the vaporation heat in terms of moles (as in this case), we have to multiply it by the number of moles instead of the mass. For that purpose, we have to calculate the molecular weight of the water:

Then, we can pass the grams to moles:

And we can finally calculate the heat:

The answer is that the necessary heat to evaporate the water is 63.9894 kJ approx.

Significant figures correspond to the number of digits that a number contains. Zeros at the beginning and end of the number are not counted, only zeros are counted if they are in an intermediate position.

For this case, the number is written in scientific notation, the corresponding 10 of the scientific notation is not taken into account during the digit count, therefore the significant figures of this number will be:

Answer: So, in the number 4.150 x10^-4, there are 3 significant figures

ANSWER

The vertical difference between line 1 and 2

EXPLANATION;

According to Arrheniu's theory, before the reactants can be converted to products, the reacting particles must possess an energy greater than the activation energy.

Hence, the vertical difference between line 1 and 2 best describe the activation energy.

Therefore, the correct answer is option B

The observation made by Ernest Rutherford and his students refuted the plum pudding model was Alpha Partical deflection. Hence the correct option is (B).

Rutherford, in his experiment, directed high energy streams of α-particles from a radioactive source at a thin sheet (100 nm thickness) of gold.

In order to study the deflection caused to the α-particles, he placed a fluorescent zinc sulphide screen around the thin gold foil.

It was observed that many alpha particles passed through the gold foil but one out of every 20,000 reflected back at small angles. a.

As many of the rays are going the foil undeflected most of the atom must be hollow.

Therefore, The observation made by Ernest Rutherford and his students refuted the plum pudding model was Alpha Partical deflection. Hence the correct option is (B).

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The mass, in grams, of 532.0 atoms of cadmium is 9.93 × 10⁻²⁰ g

From the question, we are to determine the mass of the given atoms of cadmium

First, we will calculate the number of moles of cadmium present

Using the formula,

\(Number\ of\ moles = \frac{Number\ of\ atoms}{Avogadro's\ constant}\)

Then,

Number of moles of Cd present = \(\frac{532.0}{6.022 \times 10^{23} }\)

Number of moles of Cd present = 8.83427 × 10⁻²² moles

From the given information,

1 mole of Cd has a mass of 112.41 g

Therefore,

8.83427 × 10⁻²² moles will have a mass of 8.83427 × 10⁻²² × 112.41 g

8.83427 × 10⁻²² × 112.41 = 9.9306 × 10⁻²⁰ g

≅ 9.93 × 10⁻²⁰ g

Hence, the mass, in grams, of 532.0 atoms of cadmium is 9.93 × 10⁻²⁰ g

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Answer:

NADH is formed

Explanation:

If oxygen exists in the system, pyruvate goes into mitochondrial matrix in order to perform kreb's cycle and forms NADH

Otherwise, pyruvate forms into lactate acid.

Good luck on your final exam

Not enough information man

Answer:

An allele that is dominant is always shown to be a capital letter and a recessive allele is shown to be the lowercase version of that same letter. In a simple dominant/recessive relationship, any organism that receives a dominant allele will only visibly express that allele.

Explanation:

Hope this helps :D

The most likely formula for the compound between sulfur and aluminum predicted by Lewis theory is Al₂S₃. Option C is correct.

According to Lewis theory, atoms tend to form compounds by sharing electrons to achieve a stable electron configuration. Sulfur has six valence electrons and can form two covalent bonds with aluminum, which has three valence electrons.

Aluminum can donate its three electrons to sulfur, forming three covalent bonds. The resulting compound is Al₂S₃, where two aluminum atoms are bonded with three sulfur atoms through covalent bonds. Therefore, Al₂S₃ is the most likely formula for the compound between sulfur and aluminum predicted by Lewis theory. Option C is correct.

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According to the problem, we need to determine whether new catalyst B would give higher yields than old catalyst A. The given data is a paired sample, because both the catalysts were experimented on 6 different batches of raw materials.

(a) Explain the experimental design.

Here the data collected is from 6 different raw materials, which were divided into two portions. Therefore, two data were obtained for each of the 6 raw materials, which implies in scientific terms that repeated data was obtained for each of the 6 raw materials. Thus, this type of design is known as Repeated-Measures Design.

(b) Carry out the appropriate t test.

For testing whether the new catalyst B will give higher yields than old catalyst A, a Paired-Sample t-test needs to be performed. The test will be performed using R Studio. The R codes and output are as below.

R CODE

# Load the Data A <- c(9,19,28,22,18,8) B <- c(10,22,30,21,23,12)  # Paired Sample t-test t.test(A,B,paired = TRUE,alternative = "less")

R OUTPUT

# Paired Sample t-test > t.test(A, B, paired = TRUE, alternative = less) Paired t-test = data: A and B t = -2.6458, df = ">

The decision rule for this test is: "If the p-value < 0.05, then reject the null hypothesis, under 0.05 level of significance; otherwise accept the null hypothesis".

Decision: As p-value (= 0.02283) < 0.05, so we decide to REJECT the null hypothesis, under 0.05 level of significance.

Conclusion: As the null hypothesis is to be rejected, so we can conclude that "there is sufficient evidence conclude that the new catalyst B gives a higher yield than old catalyst A".

(c) Construct a 95% confidence interval for the difference between catalysts A and B.

From part (b),

we have obtained the R output about the 95% confidence interval for the difference between catalysts A and B as:

Therefore, the 95% confidence interval for the difference between catalysts A and B is (-∞, -0.56).

In frequency statistics, the confidence interval (CI) is the range of estimated values ​​for an unknown parameter. Confidence intervals are computed at the specified confidence level. A 95% confidence level is the most common, but other levels such as 90% and 99% are sometimes used . The confidence level represents the proportion of corresponding CIs over time that contain the true value of the parameter. For example, 95% of all intervals computed at the 95% level must contain the true value of the parameter.

Factors that affect the width of the CI include confidence level, sample size, and within-sample variability.  All other things being equal, the larger the sample, the narrower the confidence interval. Similarly, the more varied the sample, the wider the confidence interval, and the higher the confidence level, the wider the confidence interval.

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Answer:The physical changes that are endothermic are melting, vaporization and sublimation.

Explanation:

Answer:

Below

Explanation:

Number of seconds in one year

  3600 s/hr * 24hr/day * 365.25 day/yr = 31 557 600 s/yr

1.10 s / 31 557 600 s/yr = 3.49 x 10^-8  yr

One mole of carbon dioxide would require 84.01 grams of NaHCO₃.

It is discovered that the ratio of moles of CO₂ generated to moles of NaHCO₃ reacted is 1:2.

We can observe from this equation that 1 mole of NaHCO₃ results in 1 mole of CO₂. As a result, NaHCO₃ and CO₂ have a molar ratio of 1:1.

Na2CO₃(s) + H₂O(g) + CO₂ = 2 NaHCO₃(s)(g)

CO₂ has a molar mass of about 44.01 g/mol. As a result, we must determine how much NaHCO₃ weighs in relation to one mole of CO₂. Using the molar mass of NaHCO₃, the following can be calculated:

Molar mass of NaHCO₃ is 84.01 g/mol.

The mass of NaHCO₃ needed to create one mole of CO₂ is as follows:

(84.01 g NaHCO₃/1 mole NaHCO₃) = 84.01 g CO₂/mol for 1 mole of NaHCO₃.

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One mole of the compound Al₂ (SO₄)₃ contains 2 moles of Al, 3 moles of sulphur atoms and 6 moles of O₂ gas.

Aluminum sulphate is an ionic compound formed by the donation of electrons from the Al metal to the sulphate group. In the sulphate group, the oxygen and sulphur are covalently bonded.

The reaction of the formation of aluminum sulphate can be written as follows:

\(\rm 2Al + 3 SO_{4} \rightarrow Al_{2}(SO_{4})_{3}\)

Here, one mole of this compound is formed by 2 moles of Al and 3 moles of sulphate group. 3 moles of sulphate group contains 3 moles of S and 6 moles of O₂.

Then, 6 moles of Al₂ (SO₄)₃ contains 12 moles of Al, 18 moles of  S and 36 moles of oxygen gas.

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