An inscribed circle is the largest circle contained in the polygon (triangle):
• Bisects two angles of the triangle.
,• The angle bisector will intersect at the intercenter.
Procedure
To draw the inscribed circle, we have to use the intercenter (O, in our case) as the center, pointing one of the compass points in O, and draw the circle touching the edges.
what is the maximum vertical distance between the line y = x 6 and the parabola y = x2 for −2 ≤ x ≤ 3? 6.25 correct: your answer is correct.
Answer is correct. Maximum vertical distance between the line y = x + 6 and the parabola y = x² for -2 ≤ x ≤ 3 is 6.25.
How to find max distance between parabola?Follow these steps:
1. Subtract the equation of the line from the equation of the parabola to find the difference between their y-values: (x²) - (x + 6).
2. Simplify the expression: x² - x - 6.
3. Now we need to find the maximum value of this expression in the given interval. To do this, find the vertex of the parabola formed by the expression.
4. The vertex of a parabola with the form y = ax² + bx + c is given by the formula x = -b/(2a). In this case, a = 1 and b = -1, so the x-coordinate of the vertex is x = 1/2.
5. Since 1/2 is within the interval -2 ≤ x ≤ 3, the maximum vertical distance occurs at this x-coordinate.
6. Substitute x = 1/2 into the expression x² - x - 6 to find the maximum vertical distance: (1/2)² - (1/2) - 6 = 1/4 - 1/2 - 6 = -6.25.
7. Since we're looking for the maximum vertical distance, we need to consider the absolute value of the difference: |-6.25| = 6.25.
So, the maximum vertical distance between the line y = x + 6 and the parabola y = x² for -2 ≤ x ≤ 3 is 6.25.
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please help it’s urgent ..
Answer:
1=2 5=6 6=7 8=9 is the answer
If the area of △PQR is A, give the expressions that complete the equation for the measure of ∠R
In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown. Then the measure of ∠R = 30.4 degrees.
Measures of Angle:
An angle is formed when two lines or rays meet at a common point. Common points are called vertices.
Angles are measured using basic geometric tools such as protractors and compasses. This tool allows you to find precise measurements of angles. A protractor helps provide accurate measurements of angles, while compasses help construct angles.
Angles are measured in three ways: degrees, radians, and revolutions. In geometry, an angular measure can be defined as the measure of the angle formed by two rays or two arms at a common vertex.
Given that:
QR = 33.8 and PQ = 57.6, and
Q is the right angle, then
tan R = opposite / adjacent
= QR / PQ = 33.8 / 57.6 = 0.586.
Therefore,
tan R = 0.586
Angle R = tan⁻¹ (0.586) = 30.4 degrees.
Complete Question:
How would you solve the following geometry problem?: ∆PQR, find the measure of ∡P. In Triangle PQR where angle Q is a right angle. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown. Answers: 30.4° 35.9° 54.1° 59.6° What I did: equation: tan(x) = 33.8/57.6 tan(x)=0.56 But I know that isn't correct.
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IF AB = 6x-9 BC = 3x+17 and AC = 5x+16, find BC
Since the point B is between points A and C, the length BC is 22.25 units
How to determine the numerical length of BC?From the question, we have the following parameters that can be used in our computation:
Length AB = 6x - 9
Length BC = 3x + 17
Length AC = 5x + 16
The above implies that the point B is between points A and C
So, we have the following equation
AC = AB + BC
Substitute the known values in the above equation
So, we have the following equation
5x + 16 = 6x - 9 + 3x + 17
Collect the like terms
So, we have the following equation
5x - 6x - 3x = -9 + 18 - 16
Evaluate the like terms
So, we have the following equation
-4x = -7
Divide by -4
x = 7/4
Substitute x = 7/4 in the equation BC = 3x + 17
So, we have the following equation
BC = 3 x 7/4 + 17
Evaluate
BC = 22.25
Hence, the numerical length of BC is 22.25 units
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What additional information is needed to prove that the
triangles are similar?
To prove AXYZ - AMNO using SSS, you need to
know that
Now that you know the length of XZ, you need to know
that angle O is congruent to v to prove AXYZ- AMNO using SAS.
Can someone explain please!!!
Answer:
Step-by-step explanation:
To prove ΔXYZ ~ ΔMNO using the property of SSS, we need to know that All corresponding sides of these triangles are proportional.
Similarly, If we know the length of side XZ then addition information we need to know that angle O is congruent to angle Z and length of sides YZ, MO and NO to prove ΔXYZ ~ ΔMNO by SAS property.
Angle O is the contained angle between the sides MO and NO.
Answer:
1. MN = 6 and XZ = 17.5
2. angle Z
Step-by-step explanation:
Sorry if this is a late answer but I hope this helps :)
find the area (in square feet) of a trapezoid with height $h$h and bases $b_1$b1 and $b_2$b2 . h=6
b1=9
b2=12
The area is
square feet.
Given, the height \($h=6$, the base $b_1=9$ and $b_2=12$.\)
The area of the trapezoid is given by the formula,
\(\[A = \frac{1}{2}h(b_1+b_2)\]\)
Substitute the given values,
\(\[A = \frac{1}{2} \times 6 \times (9+12)\]\\\)
Simplifying the above expression,
\(\[A = 45 \text{ square feet}\]\)
Therefore, the area of the trapezoid is $45$ square feet.
The perimeter of a two-dimensional geometric shape is the entire length of the boundary or outer edge. It is the sum of the lengths of all the shape's sides or edges.
The perimeter of a square, for example, is calculated by adding the lengths of all four sides of the square.
Similarly, to find the perimeter of a rectangle, sum the lengths of two adjacent sides and then double the result because there are two pairs of adjacent sides.
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In a class of students, the following data table summarizes how many students passed a test and complete the homework due the day of the test. What is the probability that a student chosen randomly from the class passed the test and completed the homework? Passed the test Failed the test Completed the homework 11 3 Did not complete the homework 2 5
The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.
What is the probability?The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:
Let the probability that a student completed the homework be P(B).
Also, let the probability that a student passed the test be P(A)
P(A or B) = P(A) + P(B) - P(A * B)
From the data table:
The number of students who passed the test = 18
The number of students who completed the homework = 17
The number of students who both passed the test and completed the homework = 15.
Total number of students = 27
P(A) = 18/27
P(B) = 17/27
P(A*B) = 15/27
Therefore,
P(A or B) = 18/27 + 17/27 - 15/27
P(A or B) = 20/27
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Graph y = 4x-3.
How do I graph 4x-3 ? What would the coordinates be
Arianna is going to use a computer at an internet cafe. The cafe charges an initial fee to use the computer and then an additional price per minute of usage. Let
C
C represent the total cost of using a computer for
t
t minutes at the internet cafe. The table below has select values showing the linear relationship between
t
t and
C
.
C. Determine the number of minutes Arianna can use a computer if she only has $15.75 available to pay.
The linear relationship between the total cost C and the time at the Cafe, t indicates that Ariana can use the computer for 7.5 minutes if she only has $15.75
What is a linear relationship?A linear relationship is used to describe relationships between variables that form a straight line when ordered pairs are plotted as a graph on the coordinate plane.
The ordered pair of points for the linear relationship from the table are; (1, 9.9) and (7, 15.30)
The equation of a linear function is of the form, y = m·x + c
Where;
m = The slope of the function
c = the y-intercept
The slope of the function from the given pair of points is therefore;
\(m= \dfrac{15.30 - 9.90}{7 - 1} = 0.9\)
The equation of the function in point-slope form is therefore;
C - 9.9 = 0.9·(t - 1)
y = 0.9·x - 0.9 + 9.9 = 0.9·x + 9
The equation for the function in slope-intercept form is; C = 0.9·t + 9
Where;
C = The total cost the computer for t minutes
t = The duration of using the computer in minutes
When C = $15.75, we have;
15.75 = 0.9·t + 9
\(t = \dfrac{15.75-9}{0.9} = 7.5\)
The number of minutes Ariana can use the computer if she only has $15.75 is 7.5 minutes
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Helllppp. Read the attached pictures and answer the question. I'm so stuck. :))
The solution for the system of equtaions is (57/11, 42/11)
How to solve the system of equations?Here we have the system of equations:
x/3 = 6 - y/3
3x/4 - 3 = 2y
We can isolate x on the first equation to get:
x = 18 - 3*y/3
x = 18 - y
Replacing that on the other equation we will get
3*(18 - y)/4 - 3 = 2y
We can solve this for y.
3*(18 - y)/4 = 2y + 3
54 - 3y = 4*(2y + 3) = 8y + 12
54 - 12 = 8y + 3y
42 = 11y
42/11 =y
And the value of x will be:
x = 9 - 42/11
x = 99/11 - 42/11 = 57/11
That is the solution of the system.
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Tìm X
3x2-3x×(x-2)-12=0
Answer:
\(3x^2-3x\left(x-2\right)-12=0\)
\(3x^2-3x\left(x-2\right)-12+12=0+12 \longleftarrow (\mathrm{Add\:}12\mathrm{\:to\:both\:sides})\)
\(3x^2-3x\left(x-2\right)=12\)
\(-3x\left(x-2\right)=-3xx-\left(-3x\right)\cdot \:2\)
\(=-3xx+3\cdot \:2x\)
\(-3xx+3x^{2}\)
\(=3x^{1+1}\)
\(=3x^2\)
\(3\cdot \:2x=6x\)
\(=-3x^2+6x\)
\(3x^2-3x^2+6x=12\Longleftarrow Add\:similar\:elements\)
\(6x=12\)
\(\frac{6x}{6}=\frac{12}{6} \Longleftarrow Divide\)
\(x=2\)
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Can anyone help out?
The diagram shows a pattern using four identical rhombuses.
Diagram NOT
accurately drawn
25
25
25
Work out the size of the angle marked a.
You must show your working,
Answer:
There isnt a diagram
Step-by-step explanation:
Find the next three terms in the following arithmetic sequence: 2,13,24,35
Answer: 46, 57, 68
Step-by-step explanation:
If you look at the sequence, you see that every time, it goes up by 11, so just add 11 three more times after the last number
Help please thank you
Which document does one need to get permission to use a specific location for a project gmetrix.
A permit is a legal document that enables a person or a business to utilize a specific area for a project or other activity.
To obtain permission to use a specific location for a project, you may need to submit a request in writing or fill out a permission form. The exact document that you need to obtain permission will depend on the specific location and the requirements of the owner or manager of the location.
You may also need to provide information about your project, including the purpose, duration, and any potential impact on the location. Depending on the location and the nature of your project, you may also need to obtain other approvals or permits, such as building permits or environmental permits.
It is a good idea to research the requirements for using the specific location that you are interested in and to contact the appropriate authorities or individuals to find out what documents you need to obtain permission.
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What is the common ratio for this geometric sequence?
16, 8, 4, 2, ...
O A. 2
O B.
1
4
OC.
C.
1
2
O D. 4
Answer:
The common ratio is 1/2
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
8/16 = 1/2
We can check by the third term by the second term
4/8 = 1/2
Answer:
1/2 for APX
Step-by-step explanation:
The top one I need help with
What is the domain of this relation?
(-4,4)
(8,−1)
(9,-9)
(1,2)
(1,8)
Answer:
domain (-4,8,9,1)
range. (4,-1,-9,2,8)
Step-by-step explanation:
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The areas of the composite figures are, respectively:
Case A: A = 104 m²
Case B: A = 174 m²
Case C: A = 321.461 cm²
Case D: A = 20 m²
How to determine the area of a composite figure
In this problem we need to determine four case of composite figures, the area of each composite figure is the result of adding or subtracting the areas of different figures. The area formulas to be used below are introduced below:
Rectangle
A = w · l
Triangle
A = 0.5 · w · l
Quarter of a circle
A = 0.25π · r²
Where:
w - Widthl - Lengthr - RadiusA - AreaFinally we determine the area of the composite figures:
Case A
A = (10 m) · (8 m) + 0.5 · (8 m) · (6 m)
A = 80 m² + 24 m²
A = 104 m²
Case B
A = (12 m)² + 0.5 · (12 m) · √[(13 m)² - (12 m)²]
A = 174 m²
Case C
A = (20 cm)² - 0.25π · (10 cm)²
A = 321.461 cm²
Case D
A = (4 m) · (6 m) - 0.5 · (4 m) · (2 m)
A = 24 m² - 4 m²
A = 20 m²
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the lengths of pregnancies in a small rural village are normally distributed with a mean of 260 days and a standard deviation of 15 days. in what range would you expect to find the middle 50% of most pregnancies? between and .
The range is ( 290, 230).
In statistics, the standard deviation is a measure of the amount of variation. The low standard deviation indicates that the values tend to be close to the expected value of the set, while a high standard deviation indicates that the values are spread out over a wide range.
According to the question,
The middle 50% of the pregnancies are within two standard deviations of the mean: 260 ± 2*15
= ( 260 + 2*15 , 260 - 2*15)
= ( 260 + 30, 260-30)
= ( 290, 230)
Hence the range is ( 290, 230).
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Given the following numbers:
π,2√5,√8,√3,√27
part A. Approximate the square root terms using the perfect squares approximation method. Your answer should be a mixed fraction. Make sure to show your work.
Please note pi does not need to be approximated by the perfect squares approximation method as it is not a square root.
part B. Order the numbers from least to greatest. Please show your answer using the original symbols and radicals provided. You may use decimals or fractions as part of your work for figuring it out.
Henna plans to buy a used car today. She can afford to make payments of $350 each month for a maximum of 4 years. The best interest rate she can find is 6.2%/a compounded monthly. What is the most she can spend on buying her car today?
With a monthly payment of $350 and a maximum repayment period of 4 years, and interest rate of 6.2% per year compounded monthly, Henna can afford to spend approximately $16,324.20 on buying her car.
To calculate the maximum amount Henna can spend on buying her car, we can use the present value formula for a loan or annuity:
PV = PMT * [(1 - (1 + r)^(-n)) / r],
where PV is the present value or the maximum amount Henna can spend on the car, PMT is the monthly payment, r is the monthly interest rate (converted from the annual interest rate), and n is the total number of months for the repayment period.
First, we need to convert the annual interest rate of 6.2% to a monthly interest rate. Dividing 6.2% by 12, we get 0.062/12 = 0.00517, which is the monthly interest rate.
Next, we substitute the values into the formula:
PV = $350 * [(1 - (1 + 0.00517)^(-48)) / 0.00517],
where 48 months (4 years * 12 months) is the total number of months for the repayment period.
Evaluating the formula, we find:
PV ≈ $350 * [(1 - (1.00517)^(-48)) / 0.00517]
≈ $350 * [(1 - 0.70370) / 0.00517]
≈ $350 * [0.29630 / 0.00517]
≈ $350 * 57.27813
≈ $16,324.20.
Therefore, the most Henna can spend on buying her car today, considering her monthly payment limit and the best available interest rate, is approximately $16,324.20.
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a poker hand consists of 5 cards dealth from a deck of 52 cards. let x and y be the number of aces and kings in a poker hand. find the joint distribution of x and uy
Joint Distribution of x and y is 25.
Joint Distribution is based on joint probability, which can be simply defined as the probability of two events happening together.
We know the formula for joint distribution
F(x,y) = P(X ≤ x and Y ≤ y) = ∑∑p(xi,yi)
Here x is the number of aces and y is the number of kings in a poker hand.
That means x can take values from 0 to 4 and y can take values from 0 to 4.
∴ F(x,y) = P(X ≤ 4 and Y ≤ 4)
⇒ F(x,y) = p(0,0) + p(0,1) + p(0,2) + p(0,3) + p(0,4) + p(1,0) + p(1,1) + p(1,2) + p(1,3) + p(1,4) + p(2,0) + p(2,1) + p(2,2) + p(2,3) + p(2,4) + p(3,0) + p(3,1) + p(3,2) + p(3,3) + p(3,4) + p(4,0) + p(4,1) + p(4,2) + p(4,3) + p(4,4).
To find all these values we will construct a table as follows;
P(x,y) Y=0 Y=1 Y=2 Y=3 Y=4
X=0 0 1/4 1/2 3/4 1
X=1 1/4 1/2 3/4 1 5/4
X=2 1/2 3/4 1 5/4 3/2
X=3 3/4 1 5/4 3/2 7/4
X=4 1 5/4 3/2 7/4 2
Now the joint distribution will become,
F(x,y) = 0 + 1/4 + 1/2 + 3/4 + 1 + 1/4 + 1/2 + 3/4 +1 + 5/4 + 1/2 + 3/4 + 1 + 5/4 + 3/2 + 3/4 + 1 + 5/4 + 3/2 + 7/4 + 1 + 5/4 + 3/2 + 7/4 + 2
F(x,y) = 25
Therefore the joint distribution of x and y is 25.
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a cheetah travels at a rate of 90 feet per second. the distance d traveled by the cheetah is a function of seconds traveled t. write a rule for the function.
The function rule for this question is d = 90t.
The rate of the cheetah is given as 90 feet per second. The distance travelled by the cheetah is a function of seconds travelled. Let the distance be denoted as d and the time be denoted as t. The function is therefore a linear function of the form y = mx + b.
The equation can be expressed as d = 90t + b. The constant b is the initial distance travelled at time zero since the rate is constant. Therefore, b is zero when the time is zero. The final equation is given as follows: d = 90t, where d is the distance travelled, t is the time and 90 is the rate or speed of the cheetah.
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Find sec 0, sin 0, and tan 0, where is the angle shown in the figure.
Give exact values, not decimal approximations.
Answer:
Secθ = 11 / 9.22 or sec33°
Sinθ = 6 / 11 or Sin33°
Tanθ = 6 / 9.22 or Tan33°
θ = 33°
Step-by-step explanation:
Given:
Hypotenuse = 11 unit
Perpendicular = 6 unit
Find:
Secθ
Sinθ
Tanθ
Computation:
Base = √Hypotenuse² - Perpendicular²
Base = √11² - 6²
Base = √121 - 36
Base = √85
Base = 9.22 unit (Approx.)
Secθ = Hypotenuse / Base
Secθ = 11 / 9.22 or sec33°
Sinθ = Perpendicular / Hypotenuse
Sinθ = 6 / 11 or Sin33°
Tanθ = Perpendicular / Base
Tanθ = 6 / 9.22 or Tan33°
So value of θ = 33°
What is the area of the triangle? (-5,-2) (-3,5) (1.-2) 0 square units
Answer
Area = 21 Sq units
Step-by-step explanation:
Area= 1/2[(x1y2 + x2y3 + x3y1) - (x2y1 + x3y2 + x1y3)]
Area = 1/2[(-5×5 +-3×-2+1×-2) - (-3×-2+1×5+-5×-2)]
Area = 1/2(-42)
Area = -21 sq units
Area = 21 sq units (The area is negative because it is below the x-axis.)
b). Kirchoff has more money than Maxi. If Kirchoff gave Maxi $20, they would have the
same amount. While it Maxi gave Kirchoff $22, Kirchoff would then have twice as much as
Maxi. How much does each one actually have?
Answer:
k = 146
m= 106
Kirchoff has $146
Maxi has $106
Step-by-step explanation:
For the purpose of the equations, I’ll call Kirchoff and Maxi a and b respectively.
a - 20 = b + 20 (equation 1)
2(b - 22) = a + 22 (equation 2)
We can juggle those around for
a = b +40 (equation 1r (re-arranged)) and
2b - 44 = a + 22 so 2b - 66 = a (equation 2r (rearranged))
The equations are now:
a = b + 40 (new equation 1) and
a = 2b - 66 (new equation 2)
Substitute from new equation 1 to new equation 2:
b + 40 = 2b - 66 so 40 = b - 66 making b = 106.
Plug b = 106 into new equations 1 and 2 for:
a = 106 + 40 (new equation 1) and
a = 212 - 66 (new equation 2)
This gives a = 146 and b = 106
TEST: There’s a gap of $40, so giving $20 from a to b makes them equal.
SECOND TEST: Subtracting $22 from b makes it $84 and giving that sum to a makes it $168, twice as much. The tests work.
Kirchoff has $146 and Maxi has $106.
Pls help me with this work
Answer:
Step-by-step explanation:
To the 4th power means that all the items in the parenthesis is mulitplied 4 times
(9m)⁴
=9*9*9*9*m*m*m*m*m or
= (9m)(9m)(9m)(9m)
Your answer 6 points Dawn has 3 1/4 cups of cinnamon. She uses 1/2 cup of cinnamon in each batch of rolls she bakes. How many batches of rolls can Dawn make with the cinnamon she has? 1 5/8.3 7/866 1/2
She uses 1/2 cup in each batch.
So, if she has 3 1/4 cups in total, we have to divide this total by 1/2 to know how many batchs she can make:
\(\frac{\text{Total}}{\text{Batch}}=\frac{3+\frac{1}{4}}{\frac{1}{2}}=\frac{\frac{3\cdot4}{4}+\frac{1}{4}}{\frac{1}{2}}=\frac{12+1}{4}\cdot2=\frac{13}{2}=\frac{12}{2}+\frac{1}{2}=6+\frac{1}{2}\)She can make 6 1/2 batches.