A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M and positive charge Q hovers motionless above the center of the disk, suspended by the Coulomb repulsion due to the charged disk.

Required:
a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?
b. At what height h does the sphere hover?

Answers

Answer 1

Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b.  h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]


Related Questions

If the current leaving the cell in a parallel circuit is 0.3 A, what is the sum of the currents through all the branches in the parallel circuit?

Answers

The sum of the currents through all the branches in the parallel circuit is 0.3 A.

What is a parallel circuit?

A parallel circuit is a type of circuit which comprises branches so that the current divides and only part of it flows through any branch.

The voltage, or potential difference, across each branch of a parallel circuit is the same, but the currents may vary.

The sum of the current flowing in any branch of a parallel circuit is determined by applying Ohms law as follows;

I = V/R₁ + V/R₂ + V/R₃

where;

V is the voltage across the circuitR₁ is the resistance of the first component of the circuitR₂ is the resistance of the second component of the circuitR₃ is the resistance of the third component of the circuit

Thus, If the current leaving the cell in a parallel circuit is 0.3 A, then it implies that the resultant current or total current in the parallel circuit is 0.3 A.

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What is the period of a water wave with a frequency of 0.5 Hz?

Answers

The period of a water wave with a frequency of 0.5 Hz is 2 seconds. Frequency is the inverse of the period (t) and it is the number of oscillations per unit time or is the number of repetitions of an event by an object per unit time. Frequency can also be calculated in terms of wavelength and speed of light.

during an experiment , students placed a small polyester Ball over a PVC pipe, where it is observed to remain at rest 55 cm from the pipe. The mass of the polyester ball is 0.75 grams. Determine the charge on the ball. Assume that the ball and the pipe have the same charge

Answers

Therefore, the charge on the ball is \(2.35 x 10^-8\)coulombs.

How to calculate force between two charges?

To determine the charge on the ball, we can use Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

\(F = k * (q1 * q2) / r^2\)

where:

F = force between the charges

k = Coulomb's constant \((9 x 10^9 N m^2 / C^2)\)

q1, q2 = charges on the two objects

r = distance between the objects

In this case, the ball and the pipe have the same charge, so we can let q1 = q2 = q, and the force between them is simply the weight of the ball:

F = m  g

where:

m = mass of the ball (0.75 grams = 0.00075 kg)

g = acceleration due to gravity \((9.8 m/s^2)\)

\(F = 0.00075 kg * 9.8 m/s^2 = 0.00735 N\)

We also know that the ball is 55 cm = 0.55 m away from the pipe. So we can use Coulomb's law to find the charge on the ball:

\(0.00735 N = k * (q^2) / (0.55 m)^2\)

Solving for q, we get:

\(q = \sqrt((0.00735 N * (0.55 m)^2) / k)\\q =\sqrt((0.00735 N * (0.55 m)^2) / (9 x 10^9 N m^2 / C^2))\\q = 2.35 x 10^-^8 C\)

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Which gives off more heat, a potato heated to 375°F or a 20-lb turkey heated to the same temperature? Explain your answer.

Answers

Answer:

the heat emitted by potatoes is much less than the heat emitted by turkey

Explanation:

The heat transfer is given by

        Q = m \(c_{e}\) ΔT

where m is the mass of the body, c_e is the specific heat and ΔT is the change in temperature of the body

in this case they ask us to appear the heat emitted by the potatoes and the turkey.

From the tables found the specious colors of both

potato     c_e = 0.82 Kcal / kg ºC

turkey      c_e = 0.72 Kcal / kg ºC

Since the two bodies have the same initial temperature and we assume that they reach the same final (ambient) temperature, the ratio of the heat emitted is

          Q₁ / Q₂ =  \(\frac{ m_1 \ c_{e1} }{m_2 \ c_{e2} }\)

where we use the rise 1 for the potatoes and the su index 2 for the turkey

the mass of the potatoes can be estimated at approximately m = 1 ka

we substitute

          Q₁ / Q₂ =  \(\frac{1 \ 0.82}{ 20 0.72}\)

           Q₁ /Q₂ = 0.0569

           Q₁ = 0.0569 Q₂

therefore the heat emitted by potatoes is much less than the heat emitted by turkey

Does wavelength affect the energy of a wave?

Answers

Answer:

Not quite

Explanation:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength

What determines the strength of a wave?

Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.

So,

As Wavelength increases, The energy of the wave spreads and it decreases

What is a step down transformer

Answers

Answer:

A step down transformer is a device that can be connected to the switch and the appliance. There are two types of transformers that you should know about: step up and step down transformers. Step up transformers generally produce a higher output voltage than the input voltage.

Explanation:

1) Using only astronomical data, calculate the speed of the planet Venus in its essentially circular orbit around the sun.
Venus = 4.87x10^24
2) Using only astronomical data, calculate the gravitational force that the sun must be exerting on Venus.

Answers

Answer:

1)     v_orbit = 3.49*10^4 m/s

2)    F = 5.51*10^22 N

Explanation:

1) In order to calculate the speed of Venus in its orbit, you use the following formula:

\(v_{orbit}=\sqrt{\frac{GM_s}{R}}\)         (1)

v_orbit: speed of Venus = ?

G: Cavendish's constant = 6.674*10^-11.m^3kg^-1s^-2

Ms: mass of the sun = 1.98*10^30 kg

R: distance between the center of Sun and the center of Venus = 1.08*10^11m

You replace the values of the parameters in the equation (1):

\(v_{orbit}=\sqrt{\frac{(6.674*10^{-11}m^3kg^{-1}s^{-2})(1.98*10^{30})}{1.08*10^{11}m}}\\\\v_{orbit}=3.49*10^4\frac{m}{s}\)

The speed of Venus in its orbit around the Sun is 3.49*10^4 m/s

2) The force is given by the following formula:

\(F=G\frac{M_vM_s}{R^2}\)

Ms: mass of Venus = 4.87*10^24 kg

\(F=(6.674*10^{-11}m^3kg^{-1}s-2})\frac{(4.87*10^{24}kg)(1.98*10^{30}kg)}{(1.08*10^{11}m)^2}\\\\F=5.51*10^{22}N\)

The Sun exertes on Venus a force of 5.51*10^22 N

What is the electric field strength at a distance of 0.9 m from a charge of 5.71 x 10^-6 C?

Answers

Given:

\(\begin{gathered} Q=5.71\times10^{-6}\text{ C} \\ r=0.9\text{ m} \end{gathered}\)

The electric field strength is given as,

\(E=\frac{KQ}{r}\)

Here, K is the electrostatic constant.

Putting the values,

\(\begin{gathered} E=\frac{9\times10^9\times5.71\times10^{-6}}{(0.9)^2} \\ =63444.44\text{ N/C} \end{gathered}\)

Therefore, the electric field strength is 63444.44 N/C.

What happens to the force applied by the person pushing the crate (Fapplied
) as the frictional force increases? What can they do to change this force?

Answers

The force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.

What is friction?

Friction is defined as the force resisting the relative motion of an object when moving on the surface of another object. This force slow  down the speed of a moving object.

So we can conclude that the force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.

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A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-tobe-discovered planet Retah, which is 20 lighthours away from Earth. It takes 25 h (according to an Earth observer) for a spacecraft to reach this planet. Assuming that the clocks are synchronized at the beginning of the journey, compare the time elapsed in the spacecraft’s frame for this one-way journey with the time elapsed as measured by an Earth-based clock.

Answers

Answer:

The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

Explanation:

From the question we are told that

The distance between earth and Retah is  \(d = 20 \ light \ hours = 20 * 3600 * c = 72000c \ m\)

Here c is the peed of light with value \(c = 3.0*10^8 m/s\)

The time taken to reach Retah from earth is  \(t = 25 \ hours = 25 * 3600 =90000 \ sec\)

The velocity of the spacecraft is mathematically evaluated  as

     \(v_s = \frac{d }{t}\)

substituting values

   \(v_s = \frac{72000 * 3.0*10^{8} }{90000}\)

    \(v_s = 2.40*10^{8} \ m/s\)

The time elapsed in the spacecraft’s frame is mathematically evaluated as

      \(T = t * \sqrt{ 1 - \frac{v^2}{c^2} }\)

substituting value

       \(T = 90000 * \sqrt{ 1 - \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }\)

        \(T = 54000 \ s\)

=>    \(T = 15 \ hours\)

So  The  time elapsed at the spacecraft’s frame is less that the time elapsed at earth's  frame

       

Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?

Answers

The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.

What is the gravitational force on both planets?

The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.

F = GmM/r²

where;

G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planet

The gravitational force on planet X is written as;

F_X = Gm(mt) / r²

where;

m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet x

The gravitational force on planet Y is written as;

F_y = G(½m)(mt) / (¼r)²

F_y = ½(Gm(mt) / (¹/₁₆ r²)

F_y = (16 Gm mt)/(2r²)

F_y = 8(G m(mt) ) / r²

F_y = 8(F_X)

F_X = ¹/₈(F_Y)

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Can anyone please help me with the following problems? I’ve tried but I just don’t get the answers.

Can anyone please help me with the following problems? Ive tried but I just dont get the answers.

Answers

Answer:

Explanation:

2) Draw a horizontal line below the squiggle and call it your reference origin.

Highest potential energy is farthest above the origin.

I would suggest for highest to lowest

GACE(D = F)B

3) I have no way of knowing how to compare kinetic and potential energies because we are given no reference levels for either.

IF we ASSUME it is a typo and they want highest to lowest KINETIC energies, then the values will be the reverse of #2 because, in the lack of friction, Kinetic and Potential energies will always be swapping keeping the total mechanical energy constant.

B(D = F)ECAG

Using the Left Hand Rule, if motion is away from you and the current is left, which way is the field?
A. Down
B. Left
C. Up
D. Right

Answers

C. Up

Explanation:

To apply the Left Hand Rule, point your left thumb in the direction of the current and your left fingers in the direction of the motion. The direction in which your left palm faces is the direction of the magnetic field. In this case, if the motion is away from you (i.e., in the direction of your eyes), and the current is left, then the magnetic field will be directed upwards.

A bald eagle is flying to the left with a speed of 34 meters
per second when a gust of wind blows back against the
eagle causing it to slow down with a constant acceleration
of a magnitude 8 meters per second squared.
What will the speed of the bald eagle be after the wind has
blown for 3 seconds?​

Answers

Answer:

the speed after 3 seconds is 10 m/s

Explanation:

The computation of the speed is shown below:

As we know that

V = U  + at

Here,

U = 34 m/s

a =  - 8 m/s²

t = 3 Sec

V = velocity after 3 sec

V  = 34 + (-8)3

 = 34 - 24

 V = 10 m/s

Hence, the speed after 3 seconds is 10 m/s

4. A hot air balloon of mass 250.00 kg at a height of 150.0 m descends slowly into a field. What is the
GPE of the balloon before the descent, in kilojoules?

Answers

The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.

What is Gravitational Potential Energy (GPE)?

To calculate the GPE of the balloon, we use the formula below.

Formula:

GPE = mgh........... Equation 1

Where:

m = Mass of the balloong = acceleration due to gravityh = HeightGPE = Gravitational potential energy.

From the question,

Given:

m = 250 kgh = 150 mg = 9.8 m/s²

Substitute these values into equation 1

GPE = 250×150×9.8GPE = 367500 J

Hence, the GPE of the balloon is 367500 J.

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A car is behind a truck going 25 m/s on the highway the car driver looks for an opportunity to pass guessing that his car can accelerate at 1 m/s squared he gauge that he has to cover the 20 m length of the truck +10 m to clear room at the rear of the truck and 10 m more at the front of the truck in the upcoming lane he sees a car approaching probably also traveling at 25 mi./s he has made the car is about 4.0×10 to the 2nd m away should he attempt to pass

Answers

The car will travel only distance of 25.92 m.In order to overtake it needs to travel 40m. So don't attempt to pass the truck.

Vehicle speed is 25 m/s.

40m is the distance the automobile must go to pass the truck.Distance between the car approaching from the opposite direction and the passing location is 400-40, or 360 meters.

Time allowed for a car to pass a truck of 20 meters in length is equal to the distance between the automobile coming from the other direction and the relative speed of the two cars.

Time equals 360/50, or 7.2 seconds.

Let's assume that the truck is going at the same rate as the car.

The expression "distance traveled by car in comparison to truck"

S is the distance traveled, u is the initial velocity, an is the acceleration, and t is the amount of time spent, where S = ut +\(\frac{1}{2}at^{2}\)

Here, u = 0, t = 7.2 s, and a = 1 m/\(s^{2}\)

hence, the distance driven in 7.2 seconds

So,     S = 0+ 25.92 = 25.92 m

So car will travel only travel 25.92 m

In order to overtake it needs to travel 40m. So don't attempt to pass the truck.

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In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

Curran is testing out a newly waxed hallway floor by sliding in his socks.
He runs from one end of the hallway and starts sliding midway going all
the way to the right. The forces acting on Curran as he is sliding are
represented in the diagram below. Identify the forces and match them
correctly to the numbers.

Curran is testing out a newly waxed hallway floor by sliding in his socks.He runs from one end of the

Answers

Answer:

Curran is testing out a newly waxed hallway floor by sliding in his socks.

He runs from one end of the hallway and starts sliding midway going all

the way to the right. The forces acting on Curran as he is sliding are

represented in the diagram below. Identify the forces and match them

correctly to the n

Consider a hydraulic lift that uses an input piston with an area of 0.5m2. An input force of 15N is exerted on this piston. If the output piston has an area of 3.5m? What is the output force?

Answers

Answer:

The output force of the piston is 105 N.

Explanation:

Given;

the area of the input piston, A₁ = 0.5 m²

the input force of the piston, F₁ = 15 N

the area of the output piston, A₀ = 3.5 m²

the output force of the piston, F₀ = ?

The pressure of the  hydraulic lift is given by;

\(P = \frac{F}{A}\)

where;

P is the hydraulic pressure

F is the piston force

A is the area of the piston

\(P = \frac{F}{A} \\\\\frac{F_o}{A_o} = \frac{F_i}{A_i} \\\\F_o = \frac{F_iA_o}{A_i} \\\\F_o = \frac{15*3.5}{0.5} \\\\F_o = 105 \ N\)

Therefore,  the output force of the piston is 105 N.

A car travels 36 km in 30 minutes. The speed of the car is

Answers

Answer:

72km/hr

Explanation:

Speed in Km is usually represented in hours. so if the car is in constant velocity, and if the car travels 36km in 30 min then it travels 72km in 1 hour.

so the speed of the car is 72km/hr

why fur coats would keep their owners warmer if they were worn inside out?​

Answers

Answer:

The reason why this is, is because:

Explanation:

According to Jones, fur serves as an insulator for the body during cold weather and regulates the process of heat absorption during warm weather. It acts as a thermal regulator, preventing the body from taking on excessive heat. Dogs and cats shed their fur in hot weather to make their coats more appropriate for heat protection rather than warmth.

Answer:

Insulation

Explanation:

The reason for this is insulation, which describes the process of an object absorbing heat and harboring heat. It works as such: Fur protects you from the cold by forming what’s called a “boundary layer.” This happens as cold air hits the surface of your coat and the molecules cause friction.

Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that the maximum absolute temperature in the cycle is twice the minimum absolute temperature, and the net work output of the cycle is 60 kJ. If the steam changes from saturated vapor to saturated liquid during heat rejection, determine the temperature of the steam during the heat rejection process. The temperature of the steam during the heat rejection process is

Answers

Answer:

The temperature of the steam during the heat rejection process is 42.5°C

Explanation:

Given the data in the question;

the maximum temperature T\(_H\) in the cycle is twice the minimum absolute temperature T\(_L\) in the cycle

T\(_H\)  = 0.5T\(_L\)

now, we find the efficiency of the Carnot cycle engine

η\(_{th\) = 1 - T\(_L\)/T\(_H\)

η\(_{th\) = 1 - T\(_L\)/0.5T\(_L\)

η\(_{th\) = 0.5

the efficiency of the Carnot heat engine can be expressed as;

η\(_{th\) = 1 - W\(_{net\)/Q\(_H\)

where W\(_{net\) is net work done, Q\(_H\) is is the heat supplied

we substitute

0.5 = 60 / Q\(_H\)

Q\(_H\) = 60 / 0.5

Q\(_H\) = 120 kJ

Now, we apply the first law of thermodynamics to the system

W\(_{net\) = Q\(_H\) - Q\(_L\)

60 = 120 -  Q\(_L\)

Q\(_L\) = 60 kJ

now, the amount of heat rejection per kg of steam is;

q\(_L\) = Q\(_L\)/m

we substitute

q\(_L\) = 60/0.025

q\(_L\) = 2400 kJ/kg

which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)

q\(_L\) = h\(_{fg\) = 2400 kJ/kg

now, at  h\(_{fg\)  = 2400 kJ/kg from saturated water tables;

T\(_L\) = 40 + ( 45 - 40 ) ( \(\frac{2400-2406.0}{2394.0-2406.0}\\}\) )

T\(_L\) = 40 + (5) × (0.5)

T\(_L\) = 40 + 2.5

T\(_L\) = 42.5°C  

Therefore, The temperature of the steam during the heat rejection process is 42.5°C  

what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass. critical angle=42° please help me i need it right now:( ​

what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass.

Answers

Answer: TIR (total internal reflection) occurs

Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.

I agree with this tip comment I have solved this equation and I have gotten what the top comment says

An object has a mass of 4kg. What is its weight (in Newton) on Earth?​

Answers

Answer:

mass of an object = 4kg

acceleration due to gravity on earth = 9.8 m/s²

therefore , weight of an object on earth = Mass × gravity

=> weight = 4×9.8 => 39.2 N

since , weight is a force we measure it in newtons

1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

1. A ball is at rest on the top of a hill (see the figure).At the top of the hill, the ball will have

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

Find the Peukert constants n and λ for Peukert’s equation for following two measurements available from a constant current discharge experiment of a battery : (i) (t1, I1) = (10, 25) (ii) (t2, I2) = (4,45)

Answers

The battery Peukert constants, n and, are around 1.223 and 2.486, respectively.

How many Peukerts can fit?

Wilhelm Peukert, a German physicist, proposed Peukert's law in 1897, which quantifies a battery's capacity in terms of the rate of discharge. The battery's useful capacity reduces as the rate of discharge rises. The supplied capacity decreases as discharge rate increases.

C = I⁽⁻ⁿ⁾ * t * λ

log(C) = -n * log(I) + log(λ) + log(t)

log(C1) = -n * log(I1) + log(λ) + log(t1)

log(C1) = -n * log(25) + log(λ) + log(10)

Similarly, for the second measurement, we have:

log(C2) = -n * log(I2) + log(λ) + log(t2)

log(C2) = -n * log(45) + log(λ) + log(4)

log(C1) - log(C2) = -n * (log(25) - log(45)) + log(10/4)

Simplifying, we get:

log(C1/C2) = n * log(45/25) + log(2.5)

Substituting the values, we get:

log(25/45) = n * log(45/25) + log(2.5)

Solving for n, we get:

n = (log(25/45) - log(2.5)) / log(45/25)

n = 1.223

log(C1) = -1.223 * log(25) + log(λ) + log(10)

log(C1) = -1.223 * 1.39794 + log(λ) + 1

Solving for log(λ), we get:

log(λ) = log(C1) + 1.223 * 1.39794 - 1

log(λ) = log(25) + 1.223 * 1.39794 - 1

log(λ) = 0.39794

Therefore, λ = 2.486.

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The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?

Answers

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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Artists can create emphasis in a competition using

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Answer:

Microphone and speaker

When looking at a sample of potatoes, what biomolecule would there be a lot of?

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Potatoes mostly consist of starch, a complex carbohydrate produced by plants as a means of storing energy.

Are potatoes proteins or lipids?

As starch accounts for the majority of potatoes' calories, they are categorised as a carbohydrate vegetable rather than a lipid. Potatoes, like the majority of foods, are a balance of fat, protein, and carbohydrates.

What biomolecule is the most prevalent in living things?

The most prevalent biomolecules on earth are carbohydrates, which include cellulose, starch, creatine, glucose, fructose, and others. Through the process of photosynthesis, carbohydrates are created by reducing the carbon dioxide in the atmosphere with the aid of light energy.

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Convert using chain link method 5.3 MIN/m² to N/mm²​

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Answer:

hohdoqjqwfojiqjwiojdq

Explanation:

huehqofjoiqjdoiwjqiojfiwjfiojeqojefiqjojeqiojoiewqdqwwqdwqd

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