Answer:
a. F = Qs/2ε₀[1 - z/√(z² + R²)] b. h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]
Explanation:
a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?
The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by
E = s/2ε₀[1 - z/√(z² + R²)]
So, the net force on the small plastic sphere of mass M and charge Q is
F = QE
F = Qs/2ε₀[1 - z/√(z² + R²)]
b. At what height h does the sphere hover?
The sphere hovers at height z = h when the electric force equals the weight of the sphere.
So, F = mg
Qs/2ε₀[1 - z/√(z² + R²)] = mg
when z = h, we have
Qs/2ε₀[1 - h/√(h² + R²)] = mg
[1 - h/√(h² + R²)] = 2mgε₀/Qs
h/√(h² + R²) = 1 - 2mgε₀/Qs
squaring both sides, we have
[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²
h²/(h² + R²) = (1 - 2mgε₀/Qs)²
cross-multiplying, we have
h² = (1 - 2mgε₀/Qs)²(h² + R²)
expanding the bracket, we have
h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²
collecting like terms, we have
h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²
Factorizing, we have
[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²
So, h² = (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]
taking square-root of both sides, we have
√h² = √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]
h = (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]
If the current leaving the cell in a parallel circuit is 0.3 A, what is the sum of the currents through all the branches in the parallel circuit?
The sum of the currents through all the branches in the parallel circuit is 0.3 A.
What is a parallel circuit?A parallel circuit is a type of circuit which comprises branches so that the current divides and only part of it flows through any branch.
The voltage, or potential difference, across each branch of a parallel circuit is the same, but the currents may vary.
The sum of the current flowing in any branch of a parallel circuit is determined by applying Ohms law as follows;
I = V/R₁ + V/R₂ + V/R₃
where;
V is the voltage across the circuitR₁ is the resistance of the first component of the circuitR₂ is the resistance of the second component of the circuitR₃ is the resistance of the third component of the circuitThus, If the current leaving the cell in a parallel circuit is 0.3 A, then it implies that the resultant current or total current in the parallel circuit is 0.3 A.
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What is the period of a water wave with a frequency of 0.5 Hz?
during an experiment , students placed a small polyester Ball over a PVC pipe, where it is observed to remain at rest 55 cm from the pipe. The mass of the polyester ball is 0.75 grams. Determine the charge on the ball. Assume that the ball and the pipe have the same charge
Therefore, the charge on the ball is \(2.35 x 10^-8\)coulombs.
How to calculate force between two charges?To determine the charge on the ball, we can use Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
\(F = k * (q1 * q2) / r^2\)
where:
F = force between the charges
k = Coulomb's constant \((9 x 10^9 N m^2 / C^2)\)
q1, q2 = charges on the two objects
r = distance between the objects
In this case, the ball and the pipe have the same charge, so we can let q1 = q2 = q, and the force between them is simply the weight of the ball:
F = m g
where:
m = mass of the ball (0.75 grams = 0.00075 kg)
g = acceleration due to gravity \((9.8 m/s^2)\)
\(F = 0.00075 kg * 9.8 m/s^2 = 0.00735 N\)
We also know that the ball is 55 cm = 0.55 m away from the pipe. So we can use Coulomb's law to find the charge on the ball:
\(0.00735 N = k * (q^2) / (0.55 m)^2\)
Solving for q, we get:
\(q = \sqrt((0.00735 N * (0.55 m)^2) / k)\\q =\sqrt((0.00735 N * (0.55 m)^2) / (9 x 10^9 N m^2 / C^2))\\q = 2.35 x 10^-^8 C\)
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Which gives off more heat, a potato heated to 375°F or a 20-lb turkey heated to the same temperature? Explain your answer.
Answer:
the heat emitted by potatoes is much less than the heat emitted by turkey
Explanation:
The heat transfer is given by
Q = m \(c_{e}\) ΔT
where m is the mass of the body, c_e is the specific heat and ΔT is the change in temperature of the body
in this case they ask us to appear the heat emitted by the potatoes and the turkey.
From the tables found the specious colors of both
potato c_e = 0.82 Kcal / kg ºC
turkey c_e = 0.72 Kcal / kg ºC
Since the two bodies have the same initial temperature and we assume that they reach the same final (ambient) temperature, the ratio of the heat emitted is
Q₁ / Q₂ = \(\frac{ m_1 \ c_{e1} }{m_2 \ c_{e2} }\)
where we use the rise 1 for the potatoes and the su index 2 for the turkey
the mass of the potatoes can be estimated at approximately m = 1 ka
we substitute
Q₁ / Q₂ = \(\frac{1 \ 0.82}{ 20 0.72}\)
Q₁ /Q₂ = 0.0569
Q₁ = 0.0569 Q₂
therefore the heat emitted by potatoes is much less than the heat emitted by turkey
Does wavelength affect the energy of a wave?
Answer:
Not quite
Explanation:
The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength
What determines the strength of a wave?
Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.
So,
As Wavelength increases, The energy of the wave spreads and it decreases
What is a step down transformer
Answer:
A step down transformer is a device that can be connected to the switch and the appliance. There are two types of transformers that you should know about: step up and step down transformers. Step up transformers generally produce a higher output voltage than the input voltage.
Explanation:
1) Using only astronomical data, calculate the speed of the planet Venus in its essentially circular orbit around the sun.
Venus = 4.87x10^24
2) Using only astronomical data, calculate the gravitational force that the sun must be exerting on Venus.
Answer:
1) v_orbit = 3.49*10^4 m/s
2) F = 5.51*10^22 N
Explanation:
1) In order to calculate the speed of Venus in its orbit, you use the following formula:
\(v_{orbit}=\sqrt{\frac{GM_s}{R}}\) (1)
v_orbit: speed of Venus = ?
G: Cavendish's constant = 6.674*10^-11.m^3kg^-1s^-2
Ms: mass of the sun = 1.98*10^30 kg
R: distance between the center of Sun and the center of Venus = 1.08*10^11m
You replace the values of the parameters in the equation (1):
\(v_{orbit}=\sqrt{\frac{(6.674*10^{-11}m^3kg^{-1}s^{-2})(1.98*10^{30})}{1.08*10^{11}m}}\\\\v_{orbit}=3.49*10^4\frac{m}{s}\)
The speed of Venus in its orbit around the Sun is 3.49*10^4 m/s
2) The force is given by the following formula:
\(F=G\frac{M_vM_s}{R^2}\)
Ms: mass of Venus = 4.87*10^24 kg
\(F=(6.674*10^{-11}m^3kg^{-1}s-2})\frac{(4.87*10^{24}kg)(1.98*10^{30}kg)}{(1.08*10^{11}m)^2}\\\\F=5.51*10^{22}N\)
The Sun exertes on Venus a force of 5.51*10^22 N
What is the electric field strength at a distance of 0.9 m from a charge of 5.71 x 10^-6 C?
Given:
\(\begin{gathered} Q=5.71\times10^{-6}\text{ C} \\ r=0.9\text{ m} \end{gathered}\)The electric field strength is given as,
\(E=\frac{KQ}{r}\)Here, K is the electrostatic constant.
Putting the values,
\(\begin{gathered} E=\frac{9\times10^9\times5.71\times10^{-6}}{(0.9)^2} \\ =63444.44\text{ N/C} \end{gathered}\)Therefore, the electric field strength is 63444.44 N/C.
What happens to the force applied by the person pushing the crate (Fapplied
) as the frictional force increases? What can they do to change this force?
The force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
What is friction?Friction is defined as the force resisting the relative motion of an object when moving on the surface of another object. This force slow down the speed of a moving object.
So we can conclude that the force applied by the person pushing the crate is not enough as the frictional force increases because more friction causes slowing of moving object.
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A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-tobe-discovered planet Retah, which is 20 lighthours away from Earth. It takes 25 h (according to an Earth observer) for a spacecraft to reach this planet. Assuming that the clocks are synchronized at the beginning of the journey, compare the time elapsed in the spacecraft’s frame for this one-way journey with the time elapsed as measured by an Earth-based clock.
Answer:
The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame
Explanation:
From the question we are told that
The distance between earth and Retah is \(d = 20 \ light \ hours = 20 * 3600 * c = 72000c \ m\)
Here c is the peed of light with value \(c = 3.0*10^8 m/s\)
The time taken to reach Retah from earth is \(t = 25 \ hours = 25 * 3600 =90000 \ sec\)
The velocity of the spacecraft is mathematically evaluated as
\(v_s = \frac{d }{t}\)
substituting values
\(v_s = \frac{72000 * 3.0*10^{8} }{90000}\)
\(v_s = 2.40*10^{8} \ m/s\)
The time elapsed in the spacecraft’s frame is mathematically evaluated as
\(T = t * \sqrt{ 1 - \frac{v^2}{c^2} }\)
substituting value
\(T = 90000 * \sqrt{ 1 - \frac{[2.4*10^{8}]^2}{[3.0*10^{8}]^2} }\)
\(T = 54000 \ s\)
=> \(T = 15 \ hours\)
So The time elapsed at the spacecraft’s frame is less that the time elapsed at earth's frame
Planet X has a mass m and a radius r. Planet Y has a mass ½ m and a radius ¼ r. An identical tennis ball of mass mt sits on both planets’ surfaces. How does the magnitude of the gravitational force on planet X compare to the magnitude of the gravitational force on planet Y?
The gravitational force on planet X is one-eight (¹/₈) of the magnitude of gravitational force on planet Y.
What is the gravitational force on both planets?
The gravitational force on each planet is directly proportional to the product of mass of the planet and the tennis ball and inversely proportional to the square of the radius of the planets.
F = GmM/r²
where;
G is universal gravitation constantm is the mass of the tennis ballM is the mass of the planetsr is the radius of the planetThe gravitational force on planet X is written as;
F_X = Gm(mt) / r²
where;
m is the mass of planet Xmt is the mass of the tennis ballr is the radius of the planet xThe gravitational force on planet Y is written as;
F_y = G(½m)(mt) / (¼r)²
F_y = ½(Gm(mt) / (¹/₁₆ r²)
F_y = (16 Gm mt)/(2r²)
F_y = 8(G m(mt) ) / r²
F_y = 8(F_X)
F_X = ¹/₈(F_Y)
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Can anyone please help me with the following problems? I’ve tried but I just don’t get the answers.
Answer:
Explanation:
2) Draw a horizontal line below the squiggle and call it your reference origin.
Highest potential energy is farthest above the origin.
I would suggest for highest to lowest
GACE(D = F)B
3) I have no way of knowing how to compare kinetic and potential energies because we are given no reference levels for either.
IF we ASSUME it is a typo and they want highest to lowest KINETIC energies, then the values will be the reverse of #2 because, in the lack of friction, Kinetic and Potential energies will always be swapping keeping the total mechanical energy constant.
B(D = F)ECAG
Using the Left Hand Rule, if motion is away from you and the current is left, which way is the field?
A. Down
B. Left
C. Up
D. Right
Explanation:
To apply the Left Hand Rule, point your left thumb in the direction of the current and your left fingers in the direction of the motion. The direction in which your left palm faces is the direction of the magnetic field. In this case, if the motion is away from you (i.e., in the direction of your eyes), and the current is left, then the magnetic field will be directed upwards.A bald eagle is flying to the left with a speed of 34 meters
per second when a gust of wind blows back against the
eagle causing it to slow down with a constant acceleration
of a magnitude 8 meters per second squared.
What will the speed of the bald eagle be after the wind has
blown for 3 seconds?
Answer:
the speed after 3 seconds is 10 m/s
Explanation:
The computation of the speed is shown below:
As we know that
V = U + at
Here,
U = 34 m/s
a = - 8 m/s²
t = 3 Sec
V = velocity after 3 sec
V = 34 + (-8)3
= 34 - 24
V = 10 m/s
Hence, the speed after 3 seconds is 10 m/s
4. A hot air balloon of mass 250.00 kg at a height of 150.0 m descends slowly into a field. What is the
GPE of the balloon before the descent, in kilojoules?
The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.
What is Gravitational Potential Energy (GPE)?To calculate the GPE of the balloon, we use the formula below.
Formula:
GPE = mgh........... Equation 1Where:
m = Mass of the balloong = acceleration due to gravityh = HeightGPE = Gravitational potential energy.From the question,
Given:
m = 250 kgh = 150 mg = 9.8 m/s²Substitute these values into equation 1
GPE = 250×150×9.8GPE = 367500 JHence, the GPE of the balloon is 367500 J.
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A car is behind a truck going 25 m/s on the highway the car driver looks for an opportunity to pass guessing that his car can accelerate at 1 m/s squared he gauge that he has to cover the 20 m length of the truck +10 m to clear room at the rear of the truck and 10 m more at the front of the truck in the upcoming lane he sees a car approaching probably also traveling at 25 mi./s he has made the car is about 4.0×10 to the 2nd m away should he attempt to pass
The car will travel only distance of 25.92 m.In order to overtake it needs to travel 40m. So don't attempt to pass the truck.
Vehicle speed is 25 m/s.
40m is the distance the automobile must go to pass the truck.Distance between the car approaching from the opposite direction and the passing location is 400-40, or 360 meters.
Time allowed for a car to pass a truck of 20 meters in length is equal to the distance between the automobile coming from the other direction and the relative speed of the two cars.
Time equals 360/50, or 7.2 seconds.
Let's assume that the truck is going at the same rate as the car.
The expression "distance traveled by car in comparison to truck"
S is the distance traveled, u is the initial velocity, an is the acceleration, and t is the amount of time spent, where S = ut +\(\frac{1}{2}at^{2}\)
Here, u = 0, t = 7.2 s, and a = 1 m/\(s^{2}\)
hence, the distance driven in 7.2 seconds
So, S = 0+ 25.92 = 25.92 m
So car will travel only travel 25.92 m
In order to overtake it needs to travel 40m. So don't attempt to pass the truck.
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In hiking, what fitness component is required of you
Curran is testing out a newly waxed hallway floor by sliding in his socks.
He runs from one end of the hallway and starts sliding midway going all
the way to the right. The forces acting on Curran as he is sliding are
represented in the diagram below. Identify the forces and match them
correctly to the numbers.
Answer:
Curran is testing out a newly waxed hallway floor by sliding in his socks.
He runs from one end of the hallway and starts sliding midway going all
the way to the right. The forces acting on Curran as he is sliding are
represented in the diagram below. Identify the forces and match them
correctly to the n
Consider a hydraulic lift that uses an input piston with an area of 0.5m2. An input force of 15N is exerted on this piston. If the output piston has an area of 3.5m? What is the output force?
Answer:
The output force of the piston is 105 N.
Explanation:
Given;
the area of the input piston, A₁ = 0.5 m²
the input force of the piston, F₁ = 15 N
the area of the output piston, A₀ = 3.5 m²
the output force of the piston, F₀ = ?
The pressure of the hydraulic lift is given by;
\(P = \frac{F}{A}\)
where;
P is the hydraulic pressure
F is the piston force
A is the area of the piston
\(P = \frac{F}{A} \\\\\frac{F_o}{A_o} = \frac{F_i}{A_i} \\\\F_o = \frac{F_iA_o}{A_i} \\\\F_o = \frac{15*3.5}{0.5} \\\\F_o = 105 \ N\)
Therefore, the output force of the piston is 105 N.
A car travels 36 km in 30 minutes. The speed of the car is
Answer:
72km/hr
Explanation:
Speed in Km is usually represented in hours. so if the car is in constant velocity, and if the car travels 36km in 30 min then it travels 72km in 1 hour.
so the speed of the car is 72km/hr
why fur coats would keep their owners warmer if they were worn inside out?
Answer:
The reason why this is, is because:
Explanation:
According to Jones, fur serves as an insulator for the body during cold weather and regulates the process of heat absorption during warm weather. It acts as a thermal regulator, preventing the body from taking on excessive heat. Dogs and cats shed their fur in hot weather to make their coats more appropriate for heat protection rather than warmth.
Answer:
Insulation
Explanation:
The reason for this is insulation, which describes the process of an object absorbing heat and harboring heat. It works as such: Fur protects you from the cold by forming what’s called a “boundary layer.” This happens as cold air hits the surface of your coat and the molecules cause friction.
Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that the maximum absolute temperature in the cycle is twice the minimum absolute temperature, and the net work output of the cycle is 60 kJ. If the steam changes from saturated vapor to saturated liquid during heat rejection, determine the temperature of the steam during the heat rejection process. The temperature of the steam during the heat rejection process is
Answer:
The temperature of the steam during the heat rejection process is 42.5°C
Explanation:
Given the data in the question;
the maximum temperature T\(_H\) in the cycle is twice the minimum absolute temperature T\(_L\) in the cycle
T\(_H\) = 0.5T\(_L\)
now, we find the efficiency of the Carnot cycle engine
η\(_{th\) = 1 - T\(_L\)/T\(_H\)
η\(_{th\) = 1 - T\(_L\)/0.5T\(_L\)
η\(_{th\) = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η\(_{th\) = 1 - W\(_{net\)/Q\(_H\)
where W\(_{net\) is net work done, Q\(_H\) is is the heat supplied
we substitute
0.5 = 60 / Q\(_H\)
Q\(_H\) = 60 / 0.5
Q\(_H\) = 120 kJ
Now, we apply the first law of thermodynamics to the system
W\(_{net\) = Q\(_H\) - Q\(_L\)
60 = 120 - Q\(_L\)
Q\(_L\) = 60 kJ
now, the amount of heat rejection per kg of steam is;
q\(_L\) = Q\(_L\)/m
we substitute
q\(_L\) = 60/0.025
q\(_L\) = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q\(_L\) = h\(_{fg\) = 2400 kJ/kg
now, at h\(_{fg\) = 2400 kJ/kg from saturated water tables;
T\(_L\) = 40 + ( 45 - 40 ) ( \(\frac{2400-2406.0}{2394.0-2406.0}\\}\) )
T\(_L\) = 40 + (5) × (0.5)
T\(_L\) = 40 + 2.5
T\(_L\) = 42.5°C
Therefore, The temperature of the steam during the heat rejection process is 42.5°C
what happens to the reflection when it hits the triangular prisms? the reflection is from air to glass. critical angle=42° please help me i need it right now:(
Answer: TIR (total internal reflection) occurs
Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.
An object has a mass of 4kg. What is its weight (in Newton) on Earth?
Answer:
mass of an object = 4kg
acceleration due to gravity on earth = 9.8 m/s²
therefore , weight of an object on earth = Mass × gravity
=> weight = 4×9.8 => 39.2 N
since , weight is a force we measure it in newtons
1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
Find the Peukert constants n and λ for Peukert’s equation for following two measurements available from a constant current discharge experiment of a battery : (i) (t1, I1) = (10, 25) (ii) (t2, I2) = (4,45)
The battery Peukert constants, n and, are around 1.223 and 2.486, respectively.
How many Peukerts can fit?Wilhelm Peukert, a German physicist, proposed Peukert's law in 1897, which quantifies a battery's capacity in terms of the rate of discharge. The battery's useful capacity reduces as the rate of discharge rises. The supplied capacity decreases as discharge rate increases.
C = I⁽⁻ⁿ⁾ * t * λ
log(C) = -n * log(I) + log(λ) + log(t)
log(C1) = -n * log(I1) + log(λ) + log(t1)
log(C1) = -n * log(25) + log(λ) + log(10)
Similarly, for the second measurement, we have:
log(C2) = -n * log(I2) + log(λ) + log(t2)
log(C2) = -n * log(45) + log(λ) + log(4)
log(C1) - log(C2) = -n * (log(25) - log(45)) + log(10/4)
Simplifying, we get:
log(C1/C2) = n * log(45/25) + log(2.5)
Substituting the values, we get:
log(25/45) = n * log(45/25) + log(2.5)
Solving for n, we get:
n = (log(25/45) - log(2.5)) / log(45/25)
n = 1.223
log(C1) = -1.223 * log(25) + log(λ) + log(10)
log(C1) = -1.223 * 1.39794 + log(λ) + 1
Solving for log(λ), we get:
log(λ) = log(C1) + 1.223 * 1.39794 - 1
log(λ) = log(25) + 1.223 * 1.39794 - 1
log(λ) = 0.39794
Therefore, λ = 2.486.
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The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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Artists can create emphasis in a competition using
Answer:
Microphone and speaker
When looking at a sample of potatoes, what biomolecule would there be a lot of?
Potatoes mostly consist of starch, a complex carbohydrate produced by plants as a means of storing energy.
Are potatoes proteins or lipids?As starch accounts for the majority of potatoes' calories, they are categorised as a carbohydrate vegetable rather than a lipid. Potatoes, like the majority of foods, are a balance of fat, protein, and carbohydrates.
What biomolecule is the most prevalent in living things?The most prevalent biomolecules on earth are carbohydrates, which include cellulose, starch, creatine, glucose, fructose, and others. Through the process of photosynthesis, carbohydrates are created by reducing the carbon dioxide in the atmosphere with the aid of light energy.
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Convert using chain link method 5.3 MIN/m² to N/mm²
Answer:
hohdoqjqwfojiqjwiojdq
Explanation:
huehqofjoiqjdoiwjqiojfiwjfiojeqojefiqjojeqiojoiewqdqwwqdwqd