Identify the segments that are parallel, if any, if ∠EDA≅∠HCB.

Answer:

r = -20

Step-by-step explanation:

–7r= –8r−20

Add 8r to both sides

r = -20

Answer:

\( \boxed{r = -20} \)

Step-by-step explanation:

\( = > - 7r = - 8r - 20 \\ \\ = > - 7r + 8r = - 20 \\ \\ = > 8r - 7r = - 20 \\ \\ = > r = - 20\)

The ANOVA produced 21 degrees of freedom within three treatment conditions with equal sample sizes. Therefore, each sample contains 8 individuals. So, the correct answer is D).

The formula for calculating degrees of freedom within a one-way ANOVA is

dfwithin = (N - k)

where N is the total number of observations (across all groups) and k is the number of groups being compared.

In this case, we know that dfwithin = 21, and since there are three treatment conditions being compared, k = 3

So, we can rearrange the formula to solve for N:

N = dfwithin + k

N = 21 + 3

N = 24

Since we are told that the sample sizes are all the same, we can divide the total number of observations by the number of groups to get the size of each sample

n = N/k

n = 24/3

n = 8

Therefore, there are 8 individuals in each sample. The answer is (d) 8.

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Answer:

0.1 8 17

Step-by-step explanation:

Answer: 20

Step-by-step explanation: 7x+40=180

40-180=140

7x=140

140/70.

Using simultaneous equations, the number of adults who attended the amusement park is B. 8.

Simultaneous equations are two or more equations solved concurrently.

Simultaneous equations are also called a system of equations.

The total number of people who are going to an amusement park = 21

The cost per adult ticket = $48.50

The cost per child ticket = $32.25

The total cost for the 21 persons = $807.25

Let a = number of adult tickets and c the number of children tickets.

a + c = 21 ... Equation 1

a = 21 - c ... Equation 2

48.50a + 32.25c = 807.25 ... Equation 3

Substitute Equation 2 in Equation 3:

48.50(21 - c) + 32.25c = 807.25

1,018.5 - 48.50c + 32.25c = 807.25

-16.25c = -211.25

c = 13

In Equation 2, Substitute c = 13:

a = 21 - 13

a = 8

Thus, we can conclude that 8 adults attended, based on a system of equations.

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Answer:

7.6 is greater then -8.5 its a negative

Step-by-step explanation:

If earth days merely 2 hours long, which means the rotation period of the earth is 2 hours, your weight will become 1/144 of your actual weight.

The weight or gravitational force on a mass can also be considered as centripetal force.

The formula for the centripetal force is:

F = m v²/R

In this case,

m = your mass

v = tangential velocity or earth's rotation speed

R = earth's radius

Recall that speed = distance / time. In the problem, the distance is the circumference of the earth and the travelled time is the rotation period.

v = C/t

t₁ = 24 hours

t₂ = 2 hours

Since the units are the same, we do not need to convert the unit when comparing them.

Notice that the centripetal force is directly proportional to the square of rotation speed.

F ∝ v²

Hence,

F₁ : F₂ = v₁² : v₂²

But v is inversely proportional to rotation period. Hence,

F₁ : F₂ = t₂² :  t₁²

F₁ / F₂ = (t₂ /t₁)²

F₁ / F₂ = (2 /24)²

F₁ / F₂ = (1 /12)²

F₁ / F₂ = 1/144

Hence, your weight will be 1/144 of your actual weight.

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\(\large{\underline {\underline {\frak {SolutioN:-}}}}\)

➝ -4 × (-2) [2 × (-6)+ 3×(2×6-4-4) ]

➝ -4 × (-2) [2 × (-6) + 3 × (12-4-4) ]

➝ -4 × (-2) [2 × (-6) + 3 × (12-8) ]

➝ -4 × (-2) [2 × (-6) + 3 × (4) ]

➝ -4 × (-2) [2 × (-6) + 12 ]

➝ -4 × (-2) [(-12) + 12 ]

➝ -4 × (-2) [0]

➝ -4 × 0

➝ 0

Answer:

-4*-2

Step-by-step explanation:

the multiple of both side is 4*2*,26+*32*--=6 44

Answer:

D. 1

Step-by-step explanation:

Distribute the -1

5x - 4x +1 = 2

1x = 1

x=1

Marilyn has $75 to spend on two Series EE savings bonds as graduation gifts. The face values of the bonds she can buy are $50, $75, and $100. Therefore, she could buy two $50 bonds.

Since Marilyn has $75 to spend and she needs to buy two bonds, the total face value of the bonds she can purchase must be equal to $75.

Let x be the face value of the first bond, then the face value of the second bond must be 75 - x.

The face values of the bonds are $50, $75, and $100, so we can set up the following three equations

x + (75 - x) = 75 (since the total face value must be $75)

x = 50 (since the face value must be $50, $75, or $100)

x = 100 (since the face value must be $50, $75, or $100)

Solving these equations, we find that the possible face values for each bond are $50 and $25, $75 and $0, or $100 and $-25 (which is not a valid option).

Therefore, Marilyn could buy two bonds with face values of $50 each, or one bond with a face value of $75 and the other with a face value of $0 (which essentially means she would only be buying one bond).

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To compute the gradient of the function \(\(f(x, y) = x^{13} + 11y\)\) , we differentiate the function with respect to \(\(x\)\) and \(\(y\)\) separately.

\(\(\frac{\partial f}{\partial x} = 13x^{12}\)\)

\(\(\frac{\partial f}{\partial y} = 11\)\)

So, the gradient of \(\(f(x, y)\)\) is given by \(\(\nabla f(x, y) = (13x^{12}, 11)\).\)

To evaluate the gradient at point \(\(P(0, -3)\),\) we substitute the values of \(\(x\)\) and \(\(y\)\) into the gradient:

\(\(\nabla f(0, -3) = (13(0)^{12}, 11) = (0, 11)\).\)

The gradient at point \(\(P\) is \((0, 11)\).\)

To find the directional derivative at point \(\(P\)\) in the direction of vector \(\(u = (2, 2)\),\) we compute the dot product of the gradient and the unit vector in the direction of \(\(u\):\)

\(\(D_u(f)(P) = \nabla f(P) \cdot \frac{u}{\|u\|}\),\)

where \(\(\|u\|\)\)  is the magnitude of vector \(\(u\).\)

The magnitude of vector  \(\(u\) is \(\|u\| = \sqrt{2^2 + 2^2} = \sqrt{8} = 2\sqrt{2}\).\)

Substituting the values into the formula, we have:

\(\(D_u(f)(P) = (0, 11) \cdot \frac{(2, 2)}{2\sqrt{2}} = \frac{0 + 22}{2\sqrt{2}} = \frac{22}{2\sqrt{2}}\).\)

Simplifying, we get:

\(\(D_u(f)(P) = \frac{11}{\sqrt{2}}\).\)

Therefore, the directional derivative at point \(\(P\)\) in the direction of vector \(\(u\) is \(\frac{11}{\sqrt{2}}\).\)

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Answer:

I believe it's false

Step-by-step explanation:

In a function, the x's can not be the same

Answer: 81,000

Step-by-step explanation:

We can solve this by using the formula given.

If f(1)=1000x3^1, then 1,000x3=3,000

If f(2)=1000x3^2, then 3^2=9 and 1000x9=9000,

and so on,

Now, f(4) will equal 1000x3^4, and 3^4 is 3x3x3x3, which is 9x9 or 9^2, which would be equal to 81, and 81x1000=81,000

To complete the table of values for the exponential function f(x) = 1000*3^x, we can evaluate the function for x = 0, 1, 2, 3, and 4, since we are interested in the number of bacteria on the phone after 4 hours.

x f(x)

0 1000

1 3000

2 9000

3 27,000

4 81,000

Therefore, after 4 hours, there will be 81,000 bacteria on the surface of the phone, assuming the number of bacteria triples every hour and can be described by the exponential function f(x) = 1000*3^x.

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Answer:

the answer is x>17 I hope it helps you and next time use mathpapa

In the XY plane, the circles with equations (x-3) + y = 11 and (x+2) + y = r are externally tangent. the value of r is -6.

Generally, To find the value of r, we can start by solving for the centers and radii of the two circles.

The equation of the first circle is of the form (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius. We can rewrite the equation of the first circle as (x - 3)² + y² = 11², so the center of the circle is (3, 0) and the radius is 11.

The equation of the second circle is also of the form (x - h)₂ + (y - k)₂ = r². We can rewrite the equation of the second circle as (x + 2)² + y² = r², so the center of the circle is (-2, 0) and the radius is r.

Since the two circles are externally tangent, the distance between their centers is equal to the sum of their radii. Therefore, the distance between the centers is equal to 11 + r. We can use the distance formula to find the distance between the centers:

distance = √((h₂ - h₁)^2 + (k₂ - k₁)²)

Plugging in the coordinates of the centers, we get:

distance = √((-2 - 3)^2 + (0 - 0)^2) = √(5^2 + 0^2) = √(25) = 5

Since the distance between the centers is equal to the sum of the radii, we can set up the equation:

5 = 11 + r

Solving for r, we get:

r = 5 - 11 = -6

Therefore, the value of r is -6.

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Answer:

B

Step-by-step explanation:

It 4 3/8 is 4.375 which would round down

The estimated standard error for a sample of n = 9 scores with ss = 288 is 2. Among your choices, it should be B; s2 = 36 and sM  = 2.

Hope that helps!

The area of the shaded sector is 4π square units.

To find the area of the shaded sector, we need to calculate the central angle formed by the sector. In this case, we are given that the angle JIK is 90 degrees, which means it forms a quarter of a full circle.

Since a full circle has 360 degrees, the central angle of the shaded sector is 90 degrees.

Next, we need to determine the radius of the circle. The line segment IJ represents the radius of the circle, and it is given as 4 units.

The formula to calculate the area of a sector is A = (θ/360) * π * r², where θ is the central angle and r is the radius of the circle.

Plugging in the values, we have A = (90/360) * π * 4².

Simplifying, A = (1/4) * π * 16.

Further simplifying, A = (1/4) * π * 16.

Canceling out the common factors, A = π * 4.

Hence, the area of the shaded sector is 4π square units.

Therefore, the area of the shaded sector, expressed as a fraction times π, is 4π/1.

In summary, the area of the shaded sector is 4π square units, or 4π/1 when expressed as a fraction times π.

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If the chi-square test's expected frequencies rule is broken, either the row or the column is combined to provide a higher frequency that can be used to run the independence test.

Generally speaking, if more than 20% of the anticipated frequencies have a value of less than 5, Chi-Square should not be used (it does not matter what the observed frequencies are).

Both the chi-square test and Fisher's exact test are inappropriate if the sampled values' independence is broken. This presumption will be broken if the same subject results in more than one observation in the contingency table.

There are distinct assumptions for each non-parametric test as well. The data in the cells should represent frequencies or counts of cases rather than percentages or other data transformations, according to the Chi-presumptions. square's The variables' levels are mutually exclusive.

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Answer:

1882

fnbgjdgfhhghhhhhhhhhhh

Answer:

y= 7

Step-by-step explanation:

Plug in values into y=mx+b

m= slope

b= y intercept

Since slope is 0, y will always be at 7.

y= 0(x) +7

y= 7

Answer:

-66

Step-by-step explanation:

y = 4

3(5y - 42)

3(5(4) - 42)

3(20 - 42)

3(-22) = -66

Answer:

-66

Step-by-step explanation:

3(5×4-42)

(5×4)=20

3(20-42)

(20-42)=22

3(22)=66

so it's -66

Website A

$5 rental fee + $12registration fee

Website B

$2 rental fee + $24 registration fee

Let x represent the number of videogames you have to rent, tyou can calculate the total cost for renting videogames at each website as:

To calculate the number of videogames you have to rent for the total cost to be the same regardless the web site, you have to equal both expressions:

And now what's left is to calculate for x:

You have to rent 4 videogames in each website for the total cost to be the same.

Answer:

a. 6.48 miles   b. 9.54 miles

Step-by-step explanation:

a. 7/x=x/6

x^2=42

x=6.48

b. 13/x=x/7

x^2=91

x=9.54

Answer:

A. 6.48 miles  

B. 9.54 miles

Step-by-step explanation:

hope this helps :-)

The required scale factor  for the given line segment is 2.

In math, a line segment  is limited by two unmistakable focuses on a line. Or on the other hand we can say a line portion is essential for the line that interfaces two focuses. A line has no endpoints and broadens endlessly in both the bearing yet a line fragment has two fixed or positive endpoints.

Scale factor is the number used to duplicate one item by to get another item that appears to be identical however is an alternate size. It makes a precise duplicate just bigger or more modest than the first. Scale Variable increases the image or item similarly as though you broadened or shrank it on a copier.

We have,

QS : QS' = 4 : 8 = QU : QU' = 5 : 10 = 1 : 2

Then the scale factor is of the dilation is 2 (magnification)

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Answer:

Step-by-step explanation:

Pedometer