2. take a look at the element yowzy (yz). this element can exist as the ion yz2-. in its ionic form, how many neutrons, protons, and electrons are found in this element?

Answer:

b

Explanation:

Answer: Yes,

Explanation: Yes, because people should know what there eating, for multiple reasons. If someone was allergic to to something in it and did not know but ate it, it would not be good. Also someone being on a diet and is avoiding certain fats should know.

(If you use this I recommend you use a Paraphrasing Tool, because I've seen people get busted for having exact same words)

And this is y I should of paid attention in that one science class in middle school that taught this...

(￣▽￣;)

The A in the diagram indicates +VE. The correct option is A.

What is enthalpy?

Enthalpy is the result of the pressure, volume, and internal energy of the system added together.

The graphic shows that the enthalpy of the products is higher than the enthalpy of the reactants, proving that Hrxn is positive as shown in the previous response.

The difference between the total enthalpy (heat content) of the products of a reaction and the total enthalpy (heat content) of the reactants in that reaction is used to find out the enthalpy of the reaction (Hrxn).

Thus, the correct option is A. +VE.

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The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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398 mg of Kr contains 0.00276 moles of Kr.

Molar mass of Kr is 83.798 g/mol

Number of moles = Mass in grams / Molar mass

= 0.398 / 83.798

= 0.00475 moles

0.00475 moles = 4.75 × 10⁻³ moles

1 mg = 10⁻³ g

398 mg = 0.398 g

Number of moles = Mass in grams / Molar mass

= 0.398 g / 83.798 g/mol

= 0.00475 mol

= 4.75 × 10⁻³ mol

0.00276 moles of Kr are contained in 398 mg of Kr.

Therefore, the number of moles of Kr that are contained in 398 mg of Kr is 0.00276 moles of Kr.

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The concentration of CO (g) in the equilibrium mixture is 0.020 M. In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

Given that the concentration of H2O (g) is [H2O] = 0.500 M at 1000°C, and  the reaction is:

C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0.2 at 1000°C

We need to determine the concentration of CO in an equilibrium mixture (in mol/L)

if a reaction mixture initially contains only reactants.

We can solve this problem using the ICE table method as follows:

Let x be the change in concentration of H2O (g) and CO (g) when they reach equilibrium.

Then the equilibrium concentrations of CO (g) and H2 (g) are equal to x. Hence, the equilibrium concentration of H2O (g) is (0.500 - x) M. Substitute these values in the expression for Kc and solve for x.

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

= 0.2[CO (g)] = Kc [H2O (g)] [C (s)] / [H2 (g)]

= 0.2 × (0.500 - x) / x

We can simplify this expression by cross-multiplication to get:

5x = 0.1 - 0.2xx = 0.02 M

Substituting x = 0.02 M in the expression for [CO (g)], we get:

[CO (g)] = 0.2 × (0.500 - 0.02) / 0.02 = 5.8 M (approx.)

Therefore, the concentration of CO (g) in an equilibrium mixture (in mol/L) is 5.8 M.                                                                                               The problem requires us to find the equilibrium concentration of CO (g) in a mixture that initially contains only reactants.

To solve this problem, we need to use the expression for the equilibrium constant Kc, which is given by:

Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]

We can also use the ICE table method to solve this problem. In this method, we start with the initial concentration of the reactants and calculate the change in concentration of each species as they reach equilibrium.

We then use the equilibrium concentrations to calculate the value of Kc and solve for the unknowns. Here is how we can set up the ICE table for this problem: Reaction:

C(s) + H2O(g) ⇄ CO(g) + H2(g)

Initial: [C] = [H2]

= 0 M,

[H2O] = 0.500 M

Equilibrium: [C] = [H2] = x,

[H2O] = 0.500 - x,

[CO] = [H2] = x

Change: +x +x -x -x

Substituting the equilibrium concentrations into the expression for Kc, we get:

Kc = [CO] [H2] / [H2O] [C]

= x² / (0.500 - x)

= 0.2

Solving for x, we get: x = 0.020 M

Substituting this value of x into the expression for [CO], we get:

[CO] = x = 0.020 M

Therefore, the concentration of CO (g) in the equilibrium mixture is 0.020 M.

In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.

The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.

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Although part of your question is missing, you might be referring to this full  

question:

Calculate the heat energy required to convert completely 85.0 g of water at 50°C into steam at 100°C.

the heat energy required to convert completely 85.0 g of water at 50°C into steam at 100°C is 18037J.

Given that,

Mass m=85g

We know that,

Q1 =mcΔt

Q1 =85×4.2×(100−50)

Q1 =17850J

Now, the latent heat

Q2 =mL

Q2 =85×2.2

Q2 =187J

Now, the total heat energy required

Q=Q1 +Q2

Q=17850+187

Q=18037J

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Answer:

Under the same conditions and assuming ideal gas behavior, both gases should have the same number of moles. This means the higher the molar mass the denser the gas. Water vapor would be less dense than N2 under the same conditions.

Explanation:

The white precipitate formed by adding ammonia to Zn(NO3)2 solution is zinc hydroxide (Zn(OH)2).

When ammonia is added to a solution of zinc nitrate, a white precipitate of zinc hydroxide is formed according to the following chemical reaction:

Zn(NO3)2 + 2NH3 → Zn(OH)2↓ + 2NH4NO3

The precipitate formed is insoluble in water, but it can dissolve in excess ammonia to form a soluble complex ion, tetraamminezinc(II) ion, as shown in the following equation:

Zn(OH)2 + 4NH3 → [Zn(NH3)4]2+ + 2OH-

This reaction occurs because ammonia acts as a ligand, which is a molecule or ion that can donate a pair of electrons to a metal ion to form a coordinate covalent bond. In this case, ammonia coordinates with the zinc ion to form the complex ion, which is soluble in water. The hydroxide ions produced by the dissociation of water also help to dissolve the zinc hydroxide precipitate. Therefore the white precipitate formed by adding ammonia to Zn(NO3)2 solution is zinc hydroxide (Zn(OH)2).

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Answer:

K I will attempt

Explanation:

a)

\(O_2_{(g)}+ 2H_2_{(g)} => 2H_2O_{(l)}\\\)

b)

1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)

c)

Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2

d)

24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles

e)

Oxygen. 2 < 5/2. Remember, 1 mole of O2 requires 2 moles of H2. But 5/2 is still greater than 2

f)

First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is \(6.022*10^{23}\) to get the number of molecules. We get: 2.41 * 10^24 molecules of water.

Answer:

I'ma just take the point thank you very much

Here's a classification of the given processes into exothermic and endothermic categories:

(a) Combustion: Exothermic. Combustion releases heat as chemical bonds are broken and new ones are formed, usually accompanied by the release of energy.

(b) Freezing water: Exothermic. During freezing, water molecules lose energy and form a solid structure, releasing heat in the process.

(c) Melting ice: Endothermic. Melting ice requires the absorption of heat to break the bonds between water molecules in the solid state and convert them into a liquid state.

(d) Boiling water: Endothermic. Boiling water involves the absorption of heat to convert liquid water into water vapor.

(e) Condensing steam: Exothermic. During condensation, water vapor molecules release heat as they transition from the gaseous state to the liquid state.

(f) Burning paper: Exothermic. Burning paper is a form of combustion, where chemical reactions release heat as the paper is broken down.

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........false.........

Answer:

A

Explanation:

Answer:

The symbol for an atom can be written to show its mass number at the top, and its atomic number at the bottom. To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number: number of protons = atomic number. number of electrons = atomic number.

a) The balanced net ionic equation for the reaction between Mg(s) and HCl(aq) is:Mg(s) + 2H⁺(aq) → Mg²⁺(aq) + H₂(g)

b) The mass of Mg used in the reaction is 0.0445 g.

a) The ionic reaction will be balnced by the reaction counting the ions on the left and the right side of the balanced equations.

b) The atmospheric pressure in the lab is measured as 765 torr, and the equilibrium vapor pressure of water at 298 K is 24 torr. Therefore, the pressure of H2(g) collected is (765 - 24) torr = 741 torr.

Using the ideal gas law PV = nRT, we can calculate the number of moles of hydrogen gas produced:

PV = nRT741 torr x 0.0456 L

= n x 0.0821 L.atm/K.mol x 298 Kn

= 0.00184 mol

Since 1 mol of Mg produces 1 mol of H2, the number of moles of Mg reacted is also 0.00184 mol.

The mass of Mg used in the reaction can be calculated using the molar mass of Mg (24.31 g/mol):

mass = n x molar mass

= 0.00184 mol x 24.31 g/mol

= 0.0445 g

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Answer:

B

Explanation:

All elements on group 18 are noble gases, which noble gases are in fact actually not highly reactive due to the large amount of valence electrons located on the out shell.

Answer:

2.08 L

Explanation:

\(V_{2} = V_{1}\) \((\frac{P_{2} }{P_{1} })\)

= 2.50L × \((\frac{1.25 atm}{1.5 atm} )\)

=2.08L

The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.

An Acid is a substances that is corrosive in nature and turn blue lithmus paper to red which it react with base to produce salt and water.

Acid dissolve metals.

Base is a substance that turn red lihthmus paper to blue and react with acid to produce salt and water.

Therefore, The acid/base pair that give equivalence point that Cannot be predicted by general knowledge is NaOH and HCI ONH.

The question is incomplete as the options were not given. The options were gotten from another website.

Select the correct answer below:

ONaOH and HCI ONH,

HC ONH, and CH, COOH

NaOH and Christmas, COOH

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At 20 degrees Celsius, the Ksp for Ni(OH)₂ is around 1.37 x 10⁻⁸.

Ksp typically rises when temperature rises as a result of an increase in solubility. The ability of a substance, known as a solute, to dissolve in a solvent and create a solution is known as solubility.

The following equation can be used to get the solubility product constant (Ksp) for Ni(OH)₂:

Ni(OH)₂ (s) ⇌ Ni₂+ (aq) + 2OH₋ (aq)

Ksp = [Ni₂₊][OH₋]²

Ni(OH)₂ has a solubility of 0.14 g/L, which may be translated to molar solubility as follows:

molar mass of Ni(OH)₂ = 92.71 g/mol

molar solubility of Ni(OH)₂ = 0.14 g/L / 92.71 g/mol = 0.00151 M

The equilibrium concentrations of Ni₂₊ and OH₋ ions can be determined using the following formula because the stoichiometric ratio of Ni(OH)₂ to Ni₂+ and OH₋ is 1:1:2:

[Ni₂₊] = 0.00151 M

[OH-] = 2 × 0.00151 M = 0.00302 M

Adding these values to the Ksp expression results in:

Ksp = [Ni₂₊][OH₋]²

Ksp = (0.00151 M) × (0.00302 M)²

Ksp = 1.37 × 10⁻⁸

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Molarity of the solution is 0.071

aqueous solution of a compound with a molar mass of 34.02 g/mol is 21.5% by mass and has a density of 1.13 g/cm3

The equation is as follows: Molarity = (% by weight 10 d)/GMM. Density (d) and gram molecular mass (GMM) are used here.

Derive the formula : Molarity = (% by weight × 10 × d )/ GMM

(21.5% *10 *1.13 ) /34.02  = 0.071.

Molarity of the solution is 0.071

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When human activities release excessive amounts of carbon dioxide and other greenhouse gases into the atmosphere, then atmosphere is most greatly impacted.

Greenhouse gases are gases the in the atmosphere of Earth that trap heat.

The greenhouse gases trap heat in the atmosphere and contribute to the phenomenon of global warming, which has numerous negative effects on the climate and environment.

Excessive greenhouse gas emissions can cause rising global temperatures, more frequent and severe weather events, sea level rise, ocean acidification, and other environmental changes that have significant impacts on ecosystems, agriculture and human societies. Therefore, it is important to reduce greenhouse gas emissions to mitigate the impacts of the climate change.

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The volume of gas when the pressure goes from 1.0 atm to 1.4 atm is 8,571.43 L.

When a car is driven into the river, it will implode due to the change in pressure. We are to calculate the volume of gas when the pressure goes from 1.0 atm to 1.4 atm if the internal volume of the car is 12,000 L.In order to solve the problem, we will use the combined gas law equation. The equation is given as follows;P1V1/T1 = P2V2/T2where P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature, P2 is the final pressure, V2 is the final volume, and T2 is the final temperature.We will assume that the initial temperature and final temperature are constant, and therefore, we can cancel them from the equation. Thus, the equation becomes;P1V1 = P2V2We can rearrange the equation to solve for V2 as follows;V2 = (P1V1)/P2Substituting the given values, we get;V2 = (1.0 atm * 12,000 L)/1.4 atmV2 = 8,571.43 L.

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The activation energy is 57.53 kJ/mol and the frequency factor is 7.18E+10 s^-1

It should be noted that to create a linear plot from the temperature-dependent rate constant data, we need to take the natural logarithm of both sides of the Arrhenius equation. This gives us:

ln(k(T)) = ln(A) - (Ea/RT)

We can rewrite this equation in the form of y = mx + b, where y = ln(k(T)), x = 1/T, m = -Ea/R, and b = ln(A):

y = mx + b

ln(k(T)) = (-Ea/R)(1/T) + ln(A)

Now, we can plot ln(k(T)) versus 1/T using MS Excel and perform linear regression to find the slope and intercept of the line. Here is a table of the given data and the calculated values of ln(k(T)) and 1/T:

T (K) k(T) (s^-1) ln(k(T)) 1/T

200.0 4.35E+06 15.294 0.005

250.0 1.94E+07 16.779 0.004

300.0 5.10E+07 17.738 0.00333

350.0 9.66E+07 18.395 0.00286

400.0 1.72E+08 18.967 0.0025

Using Excel's LINEST function, we can find the slope and intercept of the linear plot:

Slope = -Ea/R = -6.9174E+03 K

Intercept = ln(A) = 25.044

Therefore, the activation energy and frequency factor are:

Ea = -slope x R = 57.53 kJ/mol

A = exp(intercept) = 7.18E+10 s^-1

So the activation energy is 57.53 kJ/mol and the frequency factor is 7.18E+10 s^-1.

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There is, however, a relationship between a planet's distance from the Sun and its period of revolution. Kepler's third law of planetary motion says that the square of the planet's orbital period is proportional to the cube of its semimajor axis.

According to Kepler's third law of planetary motion, a planet's semimajor axis and orbital period are inversely proportional.

Kepler's third law is defined as the cubes of the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius increases, so does the time of its orbit around the Sun. A planet's orbits around the sun are accurately described by Kepler's third law in terms of their period and distance.

The cube (third power) of an orbital radius is directly related to the square (second power) of a planet's period (P2 = R3). The period of revolution shortens as the planet's distance from the sun rises.

Thus, according to Kepler's third law of planetary motion, a planet's semimajor axis and orbital period are inversely proportional.

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Hello ☺️, given below will be the answers:-

• 1.1 Å = 1.1 x 10^-7 mm

• 5.38 Å = 5.38 × 10^-24 cm³

• 0.234 mg = 0.000234 kg

✍️ By Benjemin ☺️

The average atomic mass of the element is 51.9965 u.

To calculate the average atomic mass, we need to take the weighted average of the masses of each isotope, where the weights are the relative abundances of each isotope. Using the given percentages and masses, we can calculate:

average atomic mass = (0.0434 * 49.9460 u) + (0.0950 * 52.9406 u) + (0.0237 * 53.9389 u) + (0.8379 * 51.9405 u)

= 2.1722124 u + 5.29357 u + 1.2789393 u + 43.5416115 u

= 52.2863332 u

Therefore, the average atomic mass of the element is 51.9965 u.

The average atomic mass is a weighted average of the masses of all the isotopes of an element. Isotopes are atoms of the same element that have different numbers of neutrons in their nuclei, which means they have different masses. The average atomic mass takes into account the relative abundances of each isotope in a naturally occurring sample of the element.

In the given problem, the element has four isotopes with different masses and relative abundances. We can use the given percentages as the relative abundances and multiply the mass of each isotope by its relative abundance. Summing these values gives us the average atomic mass of the element.

It is worth noting that the average atomic mass is not always a whole number because it is a weighted average of the masses of the isotopes, and the masses of the isotopes are not always whole numbers. The average atomic mass is an important quantity in chemistry because it is used to determine the molar mass of an element, which is necessary for many stoichiometric calculations.

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