Answer:
20 scoops
Step-by-step explanation:
Zack fills two bird feeders with birdseed. Each bird feeder holds 2 1/2 cups of birdseed.
Hence, the two bird feeders would require:
2 × 2 1/2 cups of bird seed.
= 5 cups of bird seed
Zack's scoop holds 1/4 cup. Write an expression for the number of scoops Zack needs to fill both feeders.
The number of scoops zack needs to fill both feeders is:
= 5 ÷ 1/4
= 5 × 4/1
= 20 scoops
Zack would need 20 scoops to fill both feeders.
The answer is simply 20 cups
Step-by-step explanation:
P=-4a^2-2ab+9b^2
Q=-7a^2-3ab+5b^2
P-Q
Answer:
3a² + ab + 4b²
Step-by-step explanation:
P - Q
= - 4a² - 2ab + 9b² - (- 7a² - 3ab + 5b² ) ← distribute parenthesis by - 1
= - 4a² - 2ab + 9b² + 7a² + 3ab - 5b² ← collect like terms
= 3a² + ab + 4b²
Answer:
3a² + ab + 4b²
Step-by-step explanation:
Combine like terms. Like terms have same variable with same power.
P - Q = -4a² - 2ab + 9b² - (-7a² - 3ab + 5b²)
To open the brackets, multiply each term of Q by (-1)
= -4a² - 2ab + 9b² + 7a²+ 3ab - 5b²
-4a² and 7a² are like terms.
(-2ab) and 3ab are like terms.
9b² and (-5b²) are like terms.
= -4a² + 7a² -2ab + 3ab + 9b²- 5b²
= 3a² + ab + 4b²
Write an appropriate and interesting subtracting word sum for: 723 and 189. Solve it
The expression is 723+189 and the solution is 912.
What is expression?Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.
Here the given statement is sum of 723 and 189 then the expression is
The word for sum is '+". Then,
=> 723+189
=> 912
Hence the expression is 723+189 and solution is 912.
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choose the table thst represents g(x) =-2•f(x) when f(x) = x +4
Answer:
c
Step-by-step explanation:
x=1 g(x)=-10
x=2 g(x)=-12
x=3 g(x)=-14
f(x)=x+4
=> g(x)=-2·(x+4)
find slope.
a. 4
b. -1/4
c. 1/4
d-4
Answer:
1/4
Step-by-step explanation:
The area of a rectangle is 38.5 square inches. The base of the rectangle is 4 inches. What is the height of rectangle?
Pls help me on this one. PLSSS :(
Answer:
The answer is 9.625
Step-by-step explanation:
So what you have is the area and the base of the rectangle. To find the height, just divide 4 into 38.5
38.5 / 4 = 9.625
To double check just multiple 9.625 by 4
9.625 x 4 = 38.5
Hope this helps
The point P = (-5/3 squared, y) lies on the unit circle shown below. What is the value of
y in simplest form?
The required value of y for the unit circle is: 2/3
How to find the point on the unit circle ?The circle is defined as the locus of a point whose distance from a fixed point is constant i.e center (h, k).
The equation of the circle is given by:
(x - h)² + (y - k)² = r²
where:
h, k is the coordinate of the center of the circle on coordinate plane.
r is the radius of the circle.
Here,
Equation of the unit circle is given as,
x² + y² = 1
Now substitute the given value in the equation,
5/9 + y² = 1
y² = 1 - 5/9
y² = 4/ 9
y = √(4/9)
y = 2/3
Thus, the required value of y for the unit circle is 2/3
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find the jacobian of the transformation x=3u, y=2uv and sketch the region g: 3<3u<6, 2<2uv<4
It is a rectangular region with u and v values ranging from 1 to 2.
To find the Jacobian of the transformation x = 3u, y = 2uv, we need to compute the partial derivatives ∂x/∂u, ∂x/∂v, ∂y/∂u, and ∂y/∂v.
Given:
x = 3u
y = 2uv
Calculating the partial derivatives:
∂x/∂u = 3
∂x/∂v = 0 (since x does not depend on v)
∂y/∂u = 2v
∂y/∂v = 2u
Now, we can construct the Jacobian matrix J:
J = [∂x/∂u ∂x/∂v]
[∂y/∂u ∂y/∂v]
Substituting the partial derivatives we calculated earlier:
J = [3 0]
[2v 2u]
Therefore, the Jacobian of the transformation is:
J = [3 0]
[2v 2u]
To sketch the region described by the inequalities g: 3 < 3u < 6, 2 < 2uv < 4, we can consider the ranges of u and v that satisfy these conditions.
From the inequality 3 < 3u < 6, we have:
1 < u < 2
From the inequality 2 < 2uv < 4, we can divide both sides by 2:
1 < uv < 2
Since u and v must both be greater than 1, we can determine the range of v:
1 < v < 2
Now, we can sketch the region in the u-v plane bounded by the conditions:
1 < u < 2
1 < v < 2
It is a rectangular region with u and v values ranging from 1 to 2.
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what is the area under the normal curve between z = -1.0 and z = -2.0? 0.0228 0.1359 0.4772 0.3413
The area under the curve between z = −2.0 and z = −1.0 is 0.1359.
We can use tables to find the area under the normal curve between two values of z.
However, tables give areas from z = 0 to z = 3.9 (beyond which there is literally no change). But as the normal curve is symmetric at z = 0, we can use it to find between any two given z values.
For example, for the area under the curve between z = −2.0 and z = −1.0, we can take values for z = 2.0 and z = 1.0; their difference will give the area between z = −2.0 and z = −1.0.
From tables for z = 1.0, we have 0.8413 and for z = 2.0, we have 0.9772 and
Hence, the Area under the curve between z = −2.0 and z = −1.0 is 0.9772−0.8413 = 0.1359.
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Alice's mother wants to wallpaper two adjacent walls in Alice's bedroom. She also wants to put a border along the top of all four walls. The bedroom is 9 ft by 12 ft by 8 ft high. A) If each double roll covers approximately 60 fr and the wallpaper is sold in double rolls only, how many double rolls are needed? B) If the border is sold in rolls of 5 yd each, how many rolls of the border are needed?
Answer:
A) The number of wallpapers needed to cover the walls is 6 double roll wall papers
B) The number of wall paper border rolls needed is 3 rolls
Step-by-step explanation:
A) The given parameters are;
The dimensions of the room are 9 ft. by 12 ft. by 8 ft. high,
The area one double role wallpaper covers = 60 ft.²
Therefore, we have;
The area of the room wall = 12 × 8 × 2 + 9 × 8 × 2 = 336 ft²
The number of double rolls of wallpaper to be used = Area of wall/(area of wallpaper) = 336/60 = 5.6
Therefore, given that the wall papers are sold in single units, we round up to the next whole number of units to get;
The number of wallpapers needed to cover the walls = 6 double roll wall papers
B) The borders of a wallpaper are installed parallel (and installed along) to the ceiling line
Therefore, the amount of wallpaper border required is given as follows;
Wall paper border length required = 2 × Length of the room + 2 × Width of the room
∴ Wall paper border length required = 2 × 9 ft. + 2 × 12 ft. = 42 ft.
The size of each wall paper border sold = 5 yd. = 15 ft.
Therefore;
The number of wall paper border rolls required = 42 ft./(5 yd.) = 42 ft./(15 ft.) = 2.8 rolls
Therefore, we round up to get the number of wall paper border rolls needed as 3 rolls of wall paper borders.
1) Explain the problem of unit root in standard regression and in time-series models and Explain how to use the Dickey-Fuller and augmented Dickey-Fuller tests to detect this. In clearly and detailed . Kindly type your answers . Course Econometrics
The problem of unit root in standard regression and time-series models arises when a variable exhibits a non-stationary behavior, meaning it has a trend or follows a random walk. Unit root tests, such as the Dickey-Fuller and augmented Dickey-Fuller tests, are used to detect the presence of a unit root in a time series. These tests examine whether the coefficient on the lagged value of the variable is significantly different from one, indicating the presence of a unit root.
In standard regression analysis, it is typically assumed that the variables are stationary, meaning they have a constant mean and variance over time. However, many economic and financial variables exhibit non-stationary behavior, where their values are not centered around a fixed mean but instead follow a trend or random walk. This presents a problem because standard regression techniques may produce unreliable results when applied to non-stationary variables.
Time-series models, such as autoregressive integrated moving average (ARIMA) models, are specifically designed to handle non-stationary data. They incorporate differencing techniques to transform the data into a stationary form, allowing for reliable estimation and inference. Differencing involves computing the difference between consecutive observations to remove the trend or random walk component.
The Dickey-Fuller test and augmented Dickey-Fuller test are commonly used to detect the presence of a unit root in a time series. These tests examine the coefficient on the lagged value of the variable in a regression framework. The null hypothesis of the tests is that the variable has a unit root, indicating non-stationarity, while the alternative hypothesis is that the variable is stationary.
The Dickey-Fuller test is a simple version of the test that includes only a single lagged difference of the variable in the regression. The augmented Dickey-Fuller test extends this by including multiple lagged differences to account for potential serial correlation in the data. Both tests provide critical values that can be compared to the test statistic to determine whether the null hypothesis of a unit root can be rejected.
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Circle T is given below. ZUTV and ZXTW are congruent.
What is the measure of chord WX?
cm
Answer:
Step-by-step explanation:
First note that the triangles shown are isosceles triangles due to equality of two of their sides which is radius. So their baseline angles are equal
Since their middle angle are equal too, so their 3 angles are the same. It menas both triangles are similar.
However, we know two of three sides are equal, but the third should be also because of their similarity.
y+4 = 2y - 3
2y - y = 4 - 3
y = 4+3
y = 7
Therefore,
2y-3 = 2.7-3 = 14-3 = 11
Answer is 11 centimeters
PLS HELP
Given the following diagram, find the required measures.
Given:l || m
m∠1=120
m∠3=40
m∠7=
60
40
140
Answer:
40
Step-by-step explanation:
Alternating angels are equal if 3 is equal to 40 then 7 must also be forty (this only applies since the lines are parallel)
Write 11/75 as a decimal
Answer:
0.147
Step-by-step explanation:
This is rounded to the nearest thousandths place. 11 divided by 75 is 0.147.
Answer:
0.14666666 (or put the symbol for a repeating number on the first 6, that way you don't have to write all of the other sixes)
Hope this helps :)
What is the measure (in radians) of central angle o in the circle below? 4 cm o 6 cm
Answer:
the answer it will be 4cm
Answer: 1.5
Step-by-step explanation:
Khan academy
Quadrilateral W X Y Z is a rectangle.
If m∠ZXW = x-11 and m∠WZX = x-9 , find m∠ZXY .
The measure of angle ZXY of the rectangle WXYZ is 46°.
To find the measure of angle ZXY, we need to use the fact that quadrilateral WXYZ is a rectangle.
Given that m∠ZXW = x-11 and m∠WZX = x-9,
We can say that ∠WXZ = ∠XZY (Alternate Interior angles)
∠WZX + ∠XZY = 90 (all four angles of rectangle are equal to 90°)
x-9+x-11= 90
Simplifying the equation, we get:
2x = 90+20
x = 55
Now,
∠ZXY = ∠WZX (Alternate interior angles)
So, m∠ZXY = x-9 = 55-9 = 46
Therefore, the measure of the angle m∠ZXY is 46°.
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A linear function contains the following points. ху 0-1 3 8 What are the slope and y-intercept of this function?
A- The slope is 1/3
The y-intercept is (0,-1).
B- The slope is 3
The y-intercept is (-1,0).
C- The slope is 3
The y-intercept is (0,-1).
D- The slope is -3
The y-intercept is (0,-1).
Answer:
it's c the slop is 3 your welcome
What is the best approximation for the circumference of a circle with a radius of 18 ft? use 3.14 to approximate pi. responses 21.1 ft 21.1 ft 36 ft 36 ft, 56.5 ft 56.5 ft 113.04 ft
The circumference of a circle with a radius of 18 feet is 113.04 ft.
The distance around the circle's edge is referred to as the circumference. It is a basic characteristic of a circle and is incorporated into a number of geometric and trigonometric calculations.
C = 2πr, where C is the circumference, is a mathematical constant, and r is the circle's radius, is the formula for calculating a circle's circumference. An irrational number is one that contains an endless number of decimal places and cannot be stated as a ratio of integers. However, the value of is roughly 3.14 for the majority of practical purposes.
The circle's radius in the provided situation is 18 feet. We can use pi = 3.14 to determine the closest approximation for the circumference of this circle.
C = 2πr = 23.1418 = 113.04 feet.
So ,the circumference of circle is 113.04 feet.
Therefore, 113.04 feet is a circle's circumference with a radius of 18 feet.
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If the two figures are congruent, which statement is true?
A. BCDA ≅ FEHG
B. ABCD ≅ EFGH
C. BADC ≅ EFGH
D. ADCB ≅ HGFE
Answer:
A
Step-by-step explanation:
the order of letter should resemble the same shape
50 points + brainliest PLS HELP ME ASAP. All I need is a right answer and a clear solution. Ty in advance! :)
(anyone who gives absurd answers will be reported right away)
Dimensions of the parallelogram are:
Base is b = 2 ft, Side is a = 5 ft, Height is h = 4 ft.Its perimeter is:
P = 2(2 + 5) = 2(7) = 14 ftIts area is:
A = bh = 2*4 = 8 ft²When the scale factor is 2Perimeter is 2 times greater:
P = 2*14 = 28 ftArea is 2*2 = 4 times greater:
A = 4*8 = 32 ft²When the scale factor is 3Perimeter is 3 times greater:
P = 3*14 = 42 ftArea is 3*3 = 9 times greater:
A = 9*8 = 72 ft²When the scale factor is 1/2Perimeter is 2 times smaller:
P = 14/2 = 7 ftArea is 2*2 = 4 times smaller:
A = 8/4 = 2 ft²Andrew buy 8 pound of apple for $12. 0. He want to know and ue the unit rate of the cot per pound. True or Fale: Two pound of apple cot more than $3. 50
It is false that the cost of two pounds of apple cast is more than $ 3.50.
Finding the cost of a given quantity:Here to find the cost of the given quantity we need to find the cost of 1 unit i.e 1 pound in the given problem so that we can find the cost of given quantities. It is called a unitary method.
Given that
Andrew buy 8 pounds of apples for $ 12.00
Let 'x' be the cost of 1 pound of apples
By the given data,
=> 8x = $ 12
=> x = 12/8
=> x = 1.5
The cost of 1 pound of apples = $ 1.5
Cost of 2 pounds apples = 2 × 1.5 = 3
Therefore,
It is false that the cost of two pounds of apple cast is more than $ 3.50.
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Please help I will mark BRAINLIST
Answer:
Mean:
10.5+9.2+0+9.3+10.4+9.2=48.6
48.6 divded by 6 =8.1
Median is 9.3
Mode is 9.2
Step-by-step explanation:
Solve the following problem using proper numerical methods and time steps (Gerald, Applied numerical analysis). Report your results along with analytical solutions, comparisons, plots and MATLAB scripts. Check the table for your parameters. APP7. A vibrating string, with a damping force-opposing its motion that is proportional to the velocity, fol- lows the equation where B is the magnitude of the damping force. Solve the problem if the length of the string is 5 ft with 7-24 lb, w=0.1 lb/ft, and B= 2.0. Initial conditions are XXX--05x<3, XXX 3≤x≤5, = x(x - 5). Compute a few points of the solution by difference equations. 1/s B TP parameters Newton kg/m T W 140 2.4 14
To solve the problem of a vibrating string with damping using numerical methods and time steps, follow these steps:
1. Discretize the string into a set of points along its length.
2. Use a finite difference method, such as the central difference method, to approximate the derivatives in the equation.
3. Apply the difference equation to each point on the string, considering the damping force and given parameters.
4. Set up the initial conditions for the string's displacement and velocity at each point.
5. Iterate over time steps to update the displacements and velocities at each point using the finite difference equation.
6. Compute and store the values of the solution at selected points for analysis.
7. Compare the numerical solution with the analytical solution, if available, to assess accuracy.
8. Plot the results to visualize the behavior of the vibrating string over time.
9. If using MATLAB, write a script to implement the numerical method and generate plots.
Note: The specific equation and initial conditions are missing from the given question, so adapt the steps accordingly.
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how many decimeters are in 3.6 millimeters
Final Answer:
There are 0.036 decimeters in 3.6 millimeters.
Explanation:
To convert from millimeters to decimeters, we can use the following measurement conversion:
1 millimeter = 0.01 decimeters
So, to find out how many decimeters are in 3.6 millimeters, we can multiply 3.6 by 0.01:
3.6 * 0.01 = 0.036
Therefore, there are 0.036 decimeters in 3.6 millimeters.
Order the steps to solve the equationlog(x2 - 15) = log(2x) form 1 to 5.x2 - 2x - 15 = 0Potential solutions are -3 and 510.00x2 - 15 = 2xX-5 = 0 or x +3=0(x - 5)(x + 3) = 0
To solve the equation \begin{equation}-\log{\left(x^2 - 15\right)} = \log{\left(2x\right)}\end{equation}, the following steps can be taken:
Apply the logarithmic identity log(a) = log(b) if and only if a = b to obtain the equation x^2 - 15 = 2x.
Move all the terms to one side of the equation to get x^2 - 2x - 15 = 0.
Factor the quadratic expression to obtain (x - 5)(x + 3) = 0.
Use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero, to get x - 5 = 0 or x + 3 = 0.
Solve for x in each equation to obtain x = 5 or x = -3.
Therefore, the steps to solve the equation log(x^2 - 15) = log(2x) from 1 to 5 are:
Apply the logarithmic identity to get x^2 - 15 = 2x.
Move all the terms to one side of the equation to get x^2 - 2x - 15 = 0.
Factor the quadratic expression to obtain (x - 5)(x + 3) = 0.
Use the zero product property to get x - 5 = 0 or x + 3 = 0.
Solve for x in each equation to obtain x = 5 or x = -3.
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what is the sum of the infinite geometric series? –288 –216 –144 –72
The sum of the infinite geometric series –288 –216 –144 –72 is -1152.
The sum of an infinite number of terms having a constant ratio between successive terms is called as infinite geometric series.
Given series, -288, -216, -144, -72, ...
The sum of the infinite geometric series can be calculated as:
Sum = \(\dfrac{a}{1 -r}\)
Here, 'a' is the first term of the series and 'r' is the common ratio.
a = -288
The common difference can be calculated as:
r = \(\dfrac{(-216)}{(-288)}\)
= \(\dfrac{3}{4}\)
Substitute the values in the sum formula:
Sum = \(\dfrac{-288}{1 - \dfrac{3}{4}}\)
It can be simplified as:
Sum = -288 \(\times\) 4
= -1152
So, the sum of the infinite geometric series is -1152.
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2x+3
7. Find each value if f(x)=x²-2x-8 and g(x)=-2x+1
(b) f(-3d)
(a) f(3)
(d) g(5)
(e) g(3x)
(e) f(2a-1)
(1) g(-4a+8)
Answer:
Step-by-step explanation:
a. f(-3d) = (-3d)^2 - 2(-3d) - 8 = 9d^2 + 6d - 8
b. f(3) = (3)^2 - 2(3) - 8 = 9 - 8 - 8 = 1 - 8 = -7
c. f(2a - 1) = (2a - 1)^2 - 2(2a - 1) - 8 = 4a^2 - 4a + 1 -4a + 2 - 8 = 4a^2 - 8a - 5
d. g(5)= (2(5)+3)/(5^2 -2(5) + 1) = (10 + 3)/(25 - 10 + 1)= 13/15+1= 13/16
e. g(3x)= (2(3x) + 3))/((3x)^2 - 2(3x) + 1))= (6x + 3)/(9x^2 - 6x + 1)
f. g(-4a + 8) = (2(-4a + 8)) + 3/(-4a + 8)^2 - 2(-4a +8) +1))
(-8a + 16 + 3)/(16a^2 - 32a + 64 + 8a - 16 + 1)
(-8a + 19)/(16a^2 - 24a + 49)
336,765=3,14×0.55×(l+0.55) please help
Answer:
l = 194999.45
Step-by-step explanation:
I'm going to assume that you meant 3.14 by 3,14.
336,765 = 3.14 × 0.55 × (l + 0.55)
336,765 ÷ (3.14 × 0.55) = l + 0.55
(336,765 ÷ (3.14 × 0.55)) - 0.55 = l
l = 194999.45
Use the fundamental identities to simplify the expression. There is more than one correct form of the answer.
From the fundamental identities, we know that
\(csc\varphi=\frac{1}{sin\varphi}\)By substituting this result into the given expression, we have
\(9sin\varphi(\frac{1}{sin\varphi}-sin\varphi)\)Now, by distributing sine of phi into the parentheses, we have
\(9(\frac{sin\varphi}{sin\varphi}-sin^2\varphi)\)or equivalently,
\(9(1-sin^2\varphi)\)Now, from the Pythagorean identity:
\(cos^2\varphi+sin^2\varphi=1\)we can note that
\(cos^2\varphi=1-sin^2\varphi\)Then, by substituting this result into our last result from above, we obtain
\(9(1-sin^2\varphi)=9cos^2\varphi\)Therefore, the answer is:
\(9cos^2\varphi\)Please help guys this is just domain and range
Answer:
domain: x>=0
range: y>=1
Step-by-step explanation:
domain: x>=0
range: y>=1
Alejandro is selling HDMI cables on eBay, and is trying to determine the best price to sell at. For the last 10 weeks, he has adjusted his price slightly each week and tracked the number of cables he sold. He plotted the results, and drew a line he feels fits the data well. 300 250 200 Quantity Sold 250 w 100 50 3 3. 25 3. 5 3. 75 4 4. 25 4. 5 4. 75 5 Price (S) a) The line of best fit passes through the points (3. 50, 270) and (4. 75, 260). Find an equation for the line. Use variables: p for price in dollars, and Q for quantity of cables sold. B) Using this model, predict the number of cables Alejandro would sell at a price of $3. 65, to the nearest whole cable. Cables
A. We have the equation for the line of best fit: Q = -8p + 298, where Q represents the quantity of cables sold and p represents the price in dollars.
B. Rounding to the nearest whole cable, Alejandro would sell approximately 270 cables at a price of $3.65, according to the model.
To find an equation for the line of best fit, we can use the two given points (3.50, 270) and (4.75, 260).
In the first place, how about we decide the slant of the line:
slant = (change in amount)/(change in cost)
= (260 - 270)/(4.75 - 3.50)
= -10 / 1.25
= -8
Using the point-slope form of a linear equation, where (x1, y1) is one of the given points and m is the slope:
y - y1 = m(x - x1)
Plugging in the values (x1 = 3.50, y1 = 270) and the slope (m = -8):
Q - 270 = -8(p - 3.50)
Simplifying the equation:
Q - 270 = -8p + 28
Q = -8p + 298
Now we have the equation for the line of best fit: Q = -8p + 298, where Q represents the quantity of cables sold and p represents the price in dollars.
To predict the number of cables Alejandro would sell at a price of $3.65, we substitute p = 3.65 into the equation:
Q = -8(3.65) + 298
Q = -29.2 + 298
Q ≈ 269.8
Rounding to the nearest whole cable, Alejandro would sell approximately 270 cables at a price of $3.65, according to the model.
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