Your silver watchband has a mass of 326 g. How many moles of Ag do you have?

The amount of HCl that can be made from 110.0 g of H2S in the reaction 3 H2S + 2 FeCl3 → 6 HCl + Fe2S3 is 144.0 g.
To determine the amount of HCl produced, we need to use the given amount of H2S and the stoichiometry of the reaction.

Calculate the molar mass of H2S.
H2S has a molar mass of approximately 34.08 g/mol (1 mol of H = 1.01 g/mol, 1 mol of S = 32.07 g/mol).
Convert the given mass of H2S to moles.
110.0 g of H2S ÷ 34.08 g/mol = 3.23 mol of H2S.
Use the stoichiometry of the reaction to determine the moles of HCl produced.
From the balanced equation, we can see that 3 moles of H2S react to form 6 moles of HCl. Therefore, for every 3.23 mol of H2S, we will produce 6.46 mol of HCl.
Convert moles of HCl to grams.
6.46 mol of HCl × 36.46 g/mol (molar mass of HCl) = 235.75 g of HCl.
Therefore, the amount of HCl that can be made from 110.0 g of H2S is 144.0 g (rounded to three significant figures).

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Arsenic, hydraulic fracturing, lead, and PFAS present chemical threats to global drinking water supplies in different ways.

Let's discuss each of them in detail:

(a) Arsenic - The origin of arsenic exposure is natural deposits or contamination from agricultural or industrial practices. Human health consequences include skin, lung, liver, and bladder cancers. It can also lead to cardiovascular diseases, skin lesions, and neurodevelopmental effects. Drivers of continued exposure include poor regulation and monitoring. Modern solutions include rainwater harvesting and treatment.

(b) Hydraulic fracturing - Hydraulic fracturing involves using a mixture of chemicals, water, and sand to extract natural gas and oil from shale rock formations. The origin of exposure is contaminated surface and groundwater due to the release of chemicals from fracking fluids and other sources. Human health consequences include skin, eye, and respiratory irritation, headaches, dizziness, and reproductive and developmental problems. Drivers of continued exposure include lack of regulation and poor oversight. Modern solutions include alternative energy sources and regulation of the industry.

(c) Lead - Lead contamination in drinking water can occur due to corrosion of plumbing materials. Human health consequences include neurological damage, developmental delays, anemia, and hypertension. Drivers of continued exposure include aging infrastructure and poor maintenance. Modern solutions include replacing lead service lines, testing for lead levels, and implementing corrosion control.

(d) PFAS - PFAS (per- and polyfluoroalkyl substances) are human-made chemicals used in a variety of consumer and industrial products. They can enter the water supply through wastewater discharges, firefighting foams, and other sources. Human health consequences include developmental effects, immune system damage, cancer, and thyroid hormone disruption. Drivers of continued exposure include the continued use of PFAS in consumer and industrial products. Modern solutions include reducing the use of PFAS in products and treatment methods such as granular activated carbon.

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Horner-Wadsworth-Emmons (HWE) reaction is an important synthetic reaction in organic chemistry. It is widely used for synthesizing various compounds. The reaction is between an aldehyde or ketone and a phosphonate or phosphonate ester in the presence of a strong base.

The Horner-Wadsworth-Emmons reaction is one of the most convenient and well-known methods of constructing carbon-carbon double bonds. The reaction proceeds via the formation of an ylide intermediate. The HWE reaction is particularly useful for the synthesis of compounds with a Z-configuration.

The mechanism for the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, can be explained in the following steps:

Step 1: Formation of the ylide intermediate

The reaction starts with the formation of an ylide intermediate. This is achieved by the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of a strong base like NaOH or KOH. In this reaction, a deprotonated species called an ylide intermediate is generated.

Step 2: Addition of the ylide intermediate to the aldehyde

The ylide intermediate then attacks the aldehyde, leading to the formation of a betaine intermediate.

Step 3: Formation of the phosphonate ester

The betaine intermediate undergoes elimination to form the final product, 3,4-methylenedioxystilbene, and the by-product phosphonate ester.

The mechanism of the Horner-Wadsworth-Emmons (HWE) reaction between diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, is complete. This reaction is significant in organic chemistry and finds applications in the pharmaceutical industry.

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The likely identity of compound that caused the cloudiness is because the triphenylphone oxide is the by product in the witting reaction . the likely identity was HCl.

The ethanol does not allow the DNA to dissolve in it.  so, the more cold the ethanol the less soluble will be the DNA.  the isopropanol is the simplest secondary alcohol. The likely identity is HCl and some of the other gas. The hot iso propanol was use instead of cold isopropanol because of the hot gravity filtration is produce more consistence crystal.

The iso propanol is the colorless and the flammable organic compound.

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Answer:

irregular galaxy

pls give brainliest :)

Answer:

irregular galaxy

it is undefined shape

Answer:

its B

Explanation:

i did the test yesterday

The configuration for the selenium subatomic particle with the maximum energy content is 4 s 2 followed by 4 p 4 point.

Explain electron configuration of selenium.

For selenium, the fundamental notation is [Ar]3d104s24p4. It has a Lewis structure. Due to the fact that they are not in the outer shell, which is the primary energy level 4, the ten 3d electrons of selenium are not visible. Selenium is paramagnetic because it possesses two unpaired electrons in the 4p-orbital.

Tellurium and polonium are also members of the sulfur family, which includes selenium. This family's outermost shell has six electrons. The electron configuration of selenium particularly is 2-8-18-6. Selenium can have a range of valence values thanks to the six electrons in its outermost shell.

Two electrons are present in the selenium atom's filled "4s" subshell. A "3d" subshell filled with 10 electrons. A "4p" subshell with four empty electrons. Selenium has an atomic number of 34. Thus, it possesses 34 electrons in total. With 6 valence electrons, the Se element needs 2 additional electrons to become stable, or we may say to complete its octet. Se's ion has a +2 charge as a result.

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The formula for PPM  =100 /1,000,000=0.01 PPM = 100 / 1 , 000 , 000 = 0.01 . i.e concentrations of arsenic should be less than 0.01 *1000 therefore it should be less than 10 ml for 1000ml of water.

This stands for "parts per million" and can alternatively be written as mg/L (milligrams per liter). The mass of a chemical or contamination per volume of water is the unit of measurement here. On a lab report, ppm or mg/L both signify the same thing. It provides information about a substance's density when it is dissolved in water. Examples include total alkalinity, calcium hardness, and free chlorine. A substance has a PPM of 1 if it makes up one millionth of the entire amount of water.

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A. Buffering, The ability of a solution to minimise significant pH changes after the addition of a basic or acid is referred to as buffering capability.

The right response is A, or buffering capacity. When an acid or base is introduced to a solution, its buffering capacity determines how well it can withstand pH variations. This characteristic plays a crucial role in keeping biological systems' pH levels stable as well as in industrial operations that demand a constant pH. In order to prevent significant variations in pH, buffers react with extra hydrogen ions (H+) or hydroxide ions (OH-). When an amount of additional acid or base is neutralised by a solution with a high buffering capacity, the pH is little affected.

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#1

Heterogenous mixture mean unsimilar substances .

#2

An element is a substance made of only one type of atoms

The mass of the excess reagent (iron) that remains after the reaction is complete is 12.1 grams.

The maximum mass of Iron(III) oxide that can be formed is 74.8 grams.

The formula for the limiting reactant is O₂, which is oxygen gas.

Calculate the number of moles of each reactant:

Number of moles of iron = 38.2 g / 55.845 g/mol = 0.683 moles

Number of moles of oxygen = 14.9 g / 32.00 g/mol = 0.466 moles

The balanced equation shows that the stoichiometric ratio between iron and oxygen is 4:3. Therefore, the mole ratio of iron to oxygen is 4:3.

Since the mole ratio of iron to oxygen is greater than 4:3, it means that there is an excess of iron and oxygen is the limiting reactant. So we need to use the number of moles of oxygen to calculate the maximum mass of Iron(III) oxide that can be formed.

The balanced equation shows that 1 mole of iron reacts with 1 mole of oxygen to produce 1 mole of Iron(III) oxide. The molar mass of Iron(III) oxide is 159.69 g/mol.

Number of moles of Iron(III) oxide = 0.466 moles (which is equal to the number of moles of oxygen)

The maximum mass of Iron(III) oxide = Number of moles of Iron(III) oxide x molar mass of Iron(III) oxide

Maximum mass of Iron(III) oxide = 0.466 moles x 159.69 g/mol = 74.8 grams

The maximum mass of Iron(III) oxide that can be formed is 74.8 grams.

The formula for the limiting reactant is O₂, which is oxygen gas.

To calculate the mass of the excess reagent (iron) that remains after the reaction is complete, we need to first calculate the mass of iron that reacted with the oxygen:

Mass of iron reacted = 0.466 moles x 55.845 g/mol = 26.1 grams

The initial mass of iron was 38.2 grams, so the mass of excess iron that remains after the reaction is complete is:

Mass of excess iron = initial mass of iron - a mass of iron reacted

Mass of excess iron = 38.2 g - 26.1 g = 12.1 grams

The mass of the excess reagent (iron) that remains after the reaction is complete is 12.1 grams.

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Answer:

1.VOLUME– The amount of space an object takes up. Basic Unit (SI Unit) for Solids – Cubic Meter, m3. LENGTH/DISTANCE – The measurement between two points.

2.one particle per cubic meter.

3.it means it is heavier

4.In a liquid the particles are still close together but a little further apart than in a solid.

5.In gases the particles are much further apart than in solids or liquids.

Explanation:

thats all i can type lol

EXPLANATION:

Firstly, we need to define a base and alkali

A base is a substance that can neutralize the acid by reacting with hydrogen or hydroxonium ions

An alkali is a soluble base. This implies that alkali is a base that dissolves in water

Hence, all Akali are bases and all bases are not alkali

When the base neutralizes acid by reacting with a hydrogen ion, the resulting ions will be negatively charged which is the Hydroxyl ion

Answer:

227 pm

Explanation:

The correct answer is when electrons bump into atoms and other electrons.

Because of how tightly packed their particles are, metals are particularly good heat conductors because vibrations are transferred very fast. Additionally, they have a lot of free electrons.

Metals get their strength and other qualities from these when they gently float through the framework. The free electrons that are nearest to the heat source are heated as the metal warms up. As a result, they move more quickly through the metal, crashing into other electrons as well as atoms. They naturally vibrate more quickly as a result (or move through the metal faster in the case of collisions with other free electrons). As a result, the metal swiftly dissipates the heat.

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The standard Gibbs energy change for the following reaction is 23 kj mol-1 at 298 k what are the concentrations of ca2 and so42- at equilibrium is 3032K.

What is Gibbs energy ?

The Gibbs free energy, also referred to as the Gibbs function, Gibbs energy, or free enthalpy, is a unit of measurement used to determine the maximum amount of work that can be accomplished in a thermodynamic system when the temperature and pressure are held constant.

What is equilibrium ?

Chemical equilibrium is characterized as a dynamic condition in which the concentration of each reactant remains constant. Even if they aren't equal, they aren't altering. An equilibrium state in a chemical reaction is denoted by a double arrow. Left are reactants, and right are products.

ΔG∘=−1486kJ/mol

T=3032K

ΔG∘=ΔH∘−TΔS∘

Under standard conditions T=298K

∴ΔG∘=−1648.4×10³−(298×−543.7)

ΔG∘=−1486 kJ/mol

At equilibrium ΔG=0

∴0=ΔH∘−TΔS∘

assuming the enthalpy and entropy changes don't change much with temperature we can use the standard values.

∴T=ΔH∘ΔS∘

T=−1648.4×10³−543.7K

T=3032K

Therefore, standard Gibbs energy change for the following reaction is 23 kj mol-1 at 298 k what are the concentrations of ca2 and so42- at equilibrium is 3032K.

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Answer:

Hello!!! Princess Sakura here ^^

Explanation:

The precipitate forms when one of the compounds is insoluble. In double replacement reactions, the positive ions and the negative ions are dissolved reactants that switch places to form the precipitation reaction.

Answer:

because one of the compounds in insoluble

Explanation:

a p e x :)

An example of how engineers have contributed to society is option D. The seven-mile bridge that spans across the Gulf of Mexico to connect two cities of the Florida Keys.

It is an example of how engineers have contributed to society. Engineers played a crucial role in designing, planning, and constructing the bridge, which provides an essential transportation link between the two cities.

The bridge enables efficient and safe travel, connecting communities, promoting economic development, and improving accessibility for residents and visitors. Engineering expertise is necessary to address various challenges such as designing a structure capable of withstanding environmental conditions, ensuring structural integrity, and incorporating appropriate safety measures.

This example showcases how engineers contribute to society by creating infrastructure that enhances connectivity and supports the growth and well-being of communities. The correct answer is option d.

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Answer:

142.04 g/mol  is the answer to your question.

He gas therefore has a pressure of **3.47 atm** at a volume of 0.505L and a temperature of 20.0°C.

The force created when gas particles strike the container wall is known as a gas's pressure. It is a gauge for a gas's moving molecules' typical linear momentum. The pressure exerted on the wall is normal to it and acts perpendicularly; the viscosity of the gas influences the force's tangential (shear) component.

Equation PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature, expresses the ideal gas law. The pressure of He gas can be calculated by using this equation and the given values as replacements as follows:

P = nRT/V

in which n = 0.108 mol

The universal gas constant is R, which equals 0.08206 L atm mol K-1.

T (temperature in Kelvin) = 20.0 + 273.15 K

V = 0.505 L

By replacing these values in the previous equation, we obtain:

P is calculated as follows:

(0.108 mol) x (0.08206 L atm mol-1 K⁻¹) x (20.0 + 273.15 K) / (0.505 L).

P = 3.47 atm

He gas therefore has a pressure of **3.47 atm**1 at a volume of 0.505L and a temperature of 20.0°C.

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A) CH3NH2

This is because CH3NH2 recieved H from CH3COOH

Answer:

D

Explanation:

water is used to delude just about anything

Answer:

B) Shape

Explanation:

The property of shape provides the best evidence that both samples are liquids and not solids because liquids do not have a definite shape, in contrast to solids, which do.

There are 7.2 moles of oxygen in the given sample of MTBE. This is calculated based on the fact that each mole of MTBE contains 3 moles of oxygen and 4 moles of hydrogen.

Based on the chemical formula for methyl tert-butyl ether (MTBE), we can see that there are 3 atoms of oxygen in each molecule of MTBE. Therefore, if we have 9.6 moles of hydrogen in a sample of MTBE, we can calculate the number of moles of oxygen in the sample as follows: For every mole of MTBE, there are 3 moles of oxygen. So, if we have 9.6 moles of hydrogen, we must have consumed 9.6/4 = 2.4 moles of MTBE (since each mole of MTBE contains 4 moles of hydrogen).
Therefore, the number of moles of oxygen in the sample is:
2.4 moles MTBE x 3 moles oxygen/mole MTBE = 7.2 moles oxygen
So, there are 7.2 moles of oxygen in the sample of MTBE.

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Answer:

15.1025 I your answer okayyyyy

If a person has the values for an object's density and volume, they can calculate the object's mass. Hence option B) is correct.

If a person has the values for an object's density and volume, they can calculate the object's mass. Density is defined as the mass per unit volume of an object. Mathematically, density is calculated by dividing the mass of an object by its volume. Rearranging the equation, we find that mass is equal to the product of density and volume. Therefore, if the density and volume of an object are known, multiplying them together will yield the object's mass. The other options mentioned in the question are not directly calculated using density and volume. The object's size is a broader term that encompasses various dimensions and may not be specifically derived from density and volume alone. The shape the object forms in a container and the amount of space the object takes up are influenced by both the object's mass and its dimensions, which are not solely determined by density and volume. Therefore option B) is correct.

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The five scientists who contributed to the discovery of the cell are Robert Hooke, Antonie van Leeuwenhoek, Matthias Schleiden, Theodor Schwann, and Rudolf Virchow.

The discovery of the cell as the fundamental unit of life involved the collective efforts of several scientists. Robert Hooke, an English physicist, was the first to observe and name cells while examining cork under a microscope in 1665.

Around the same time, Antonie van Leeuwenhoek, a Dutch scientist, improved microscopes and made detailed observations of various microorganisms, further advancing our understanding of cells.

In the mid-19th century, Matthias Schleiden, a German botanist, proposed that all plants are composed of cells, and Theodor Schwann, a German zoologist, extended this concept to animals.

Their combined work led to the formulation of the Cell Theory, which states that cells are the basic building blocks of all living organisms.

Rudolf Virchow, a German physician, later contributed to the development of the Cell Theory by emphasizing the idea that cells arise only from pre-existing cells, rejecting the notion of spontaneous generation. Virchow's work highlighted the significance of cell division and its role in growth, development, and disease.

Through their cumulative efforts, Hooke, van Leeuwenhoek, Schleiden, Schwann, and Virchow made significant contributions to our understanding of cells, paving the way for modern cell biology and numerous advancements in the field of life sciences.

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Given below is an essay on Yuan T. Lee.

Yuan T. Lee, whose full name is Yuan Tseh Lee, was born in Hsin-chu, Taiwan, on November 29, 1936. He is a Taiwanese-American chemist who shared the 1986 Nobel Prize in Chemistry with Dudley R. Herschbach and John C. Polanyi for his contributions to the study of chemical-reaction kinetics.

Lee completed his education at the University of California, Berkeley and in Taiwan (Ph.D., 1965). After completing postdoctoral studies at Harvard and Berkeley, he taught at the University of Chicago from 1968 until 1974. He relocated from Chicago to Berkeley after becoming a citizen in 1974, where he continued his research.

As a postdoctoral researcher, Lee experimented with and improved Herschbach's invention of the "crossed molecular beam technique," which brings together beams of molecules at supersonic speeds under controlled circumstances to enable close observation of the events that take place during chemical reactions. This method is derived from elementary particle physics. In order to further develop Herschbach's method, Lee used mass spectroscopy. This allowed him to recognize the byproducts of the reactions between oxygen and fluorine atoms and intricate organic molecules.

References:

https://www.britannica.com/biography/Yuan-T-Lee

https://www.infoplease.com/biographies/science-technology/yuan-t-lee

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Answer: b

Explanation:

Answer:A mixture of water and nutrients can replace the need for sunlight.

Explanation: