You take a spectrum of this galaxy and notice that its absorption and emission lines are redshifted. An emission line of hydrogen that should have a wavelength of 656.3 nm (nanometer (Links to an external site.)) has an observed wavelength of 660.4 nm. What is the velocity of the galaxy

If the ice extended right around the earth, forming a loop that the puck could go around in circles, the puck would not keep going forever. The laws of physics would eventually cause the puck to come to a stop. This is because of two factors: air resistance and gravity.

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The wavelength emitted in the transition from level U to level L is 1615 A°, a four-level laser system.

The energy level between the energy levels U 0.820 eV to level L 0.051 eV,

E = E₂ - E₁

  = 0.820 - 0.051

 = 0.769 eV

The difference between energy levels, E is 0.769 eV.

The energy,

E = hc / λ

Energy (E) = 0.769 eV

h (Planck's constant) = 6.626 ×10⁻³⁴

c (speed of the light) = 3×10⁸ m/s

λ (wavelength) =?

λ = hc / E

 = (6.626 ×10⁻³⁴ × 3×10⁸ m/s) / 0.769 eV

 = (6.626 ×10⁻³⁴ × 3×10⁸ m/s) / (0.769×1.6×10⁻¹⁹)

 = (1.9878×10⁻²⁵) / (1.2304×10⁻¹⁹)

 = 1.6155×10⁻⁶

= 1615 ×10⁻¹⁰

= 1615 A°

The wavelength of radiation emitted in the transition from level U to

level L, 1615 A°.

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If we have the volume, mass, or material, we can use the diameter of the wire to calculate the length.

To determine the length of the filament, we need more information, such as the volume or mass of the filament, or the specific material it is made from.

Here's a general explanation assuming we have the necessary information:    
1. Obtain the volume, mass, or material of the filament.
2. If you have the mass and material, find the density of the material.

Density can be found using reference sources or online databases.
3. If you have the mass and density, calculate the volume of the filament using the formula:

Volume = Mass / Density.
4. Calculate the cross-sectional area of the wire using the diameter.

The cross-sectional area (A) can be found using the formula: A = π\((D/2)^2\),

where D is the diameter of the wire.
5. Determine the length (L) of the filament by dividing the volume (V) by the cross-sectional area (A): L = V / A.
Please provide more information about the filament, such as the volume, mass, or material, so we can help you calculate the length.

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Answer:

Possibly shape.

Explanation:

Because it is ripped in half. As you guys and the questioner can see that there is a wiggly strip down the middle. That also cause of a shape change.

I really hope my answer is right ^_^  

The characteristic of matter which is undergoing change in the picture is it's shape as it is being teared apart.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.Matter possesses both particle and wave characteristics.Phase is a form of matter having uniform composition as well as physical properties.

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The partial pressure of gas x will be lower than gas y after 2.25 hours (2 hours and 15 minutes).Therefore, option C is correct.

Yes, the partial pressure of gas x will be lower than gas y after 2.25 hours (2 hours and 15 minutes).\(What is the given information in the problem\)?The following information is given in the problem:Two gases x and y are found in the atmosphere in only trace amounts because they decompose quickly.The half-life of x is 0.75 hThe half-life of y is 90 min (1.5 h)The initial partial pressure of x is 3 times greater than yThe total volume of the flask is 5.0 L.\(How can we approach the problem?\)We will use the half-life formula and the partial pressure formula to solve the problem.The half-life formula is:t1/2 = 0.693/kHere, k is the first-order rate constant.The partial pressure formula is:P = nRT/VHere,P is the partial pressuren is the number of molesR is the universal gas constantT is the temperatureV is the volume of the flask.Method:First, we will find the first-order rate constant k for both gases using the half-life formula.Then, we will use the partial pressure formula to find the number of moles of both gases x and y in the flask using the given partial pressure and the total volume of the flask.Finally, we will use the first-order rate constant and the number of moles to find the partial pressure of gases x and y at a given time.Let's solve the problem.Steps:1. Find the first-order rate constant k for gas x.t1/2 (x) = 0.75 hUsing the half-life formula,t1/2 = 0.693/kk(x) = 0.693/t1/2 (x)k(x) = 0.693/0.75k(x) = 0.924 h-12. Find the first-order rate constant k for gas y.t1/2 (y) = 90 min = 1.5 hUsing the half-life formula,t1/2 = 0.693/kk(y) = 0.693/t1/2 (y)k(y) = 0.693/1.5k(y) = 0.462 h-13. Find the initial number of moles of gas x in the flask.Partial pressure of x = 3 * Partial pressure of yP(x) = 3 * P(y)P(x) = (3/4) * Total pressure of x and yP(y) = Total pressure of x and yP(x) + P(y) = Total pressure of x and yLet's assume that the total pressure of x and y is P0.P0 = P(x) + P(y)P(x) = (3/4) * P0P(y) = (1/4) * P04. Find the initial number of moles of gas y in the flask.P(y) = n(y)RT/Vn(y) = P(y) * V/RTn(y) = [(1/4) * P0 * 5.0 L] / [(0.0821 L atm K-1 mol-1) * (298 K)]n(y) = 0.062 mol5. Find the initial number of moles of gas x in the flask.P(x) = n(x)RT/Vn(x) = P(x) * V/RTn(x) = [(3/4) * P0 * 5.0 L] / [(0.0821 L atm K-1 mol-1) * (298 K)]n(x) = 0.186 mol6. Find the partial pressure of gas x after 1 hour.P(x, 1 h) = n(x)k(x)tP(x, 1 h) = (0.186 mol) * (0.924 h-1) * (1 h)P(x, 1 h) = 0.171 atm7. Find the partial pressure of gas y after 1 hour.P(y, 1 h) = n(y)k(y)tP(y, 1 h) = (0.062 mol) * (0.462 h-1) * (1 h)P(y, 1 h) = 0.028 atm8. Find the partial pressure of gas x after 2 hours.P(x, 2 h) = n(x)k(x)tP(x, 2 h) = (0.186 mol) * (0.924 h-1) * (2 h)P(x, 2 h) = 0.342 atm9. Find the partial pressure of gas y after 2 hours.P(y, 2 h) = n(y)k(y)tP(y, 2 h) = (0.062 mol) * (0.462 h-1) * (2 h)P(y, 2 h) = 0.049 atm10. Find the partial pressure of gas x after 2.25 hours.P(x, 2.25 h) = n(x)k(x)tP(x, 2.25 h) = (0.186 mol) * (0.924 h-1) * (2.25 h)P(x, 2.25 h) = 0.383 atm11. Find the partial pressure of gas y after 2.25 hours.P(y, 2.25 h) = n(y)k(y)tP(y, 2.25 h) = (0.062 mol) * (0.462 h-1) * (2.25 h)P(y, 2.25 h) = 0.052 atmConclusion:Yes.

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F = 20 N

m = 250 g = 0.25 Kg

a = ?

Using Newton's 2nd Law

a = F/m

a = 20/0.25

a = 80 m/s²

The acceleration of an object with a mass of 250 grams or 0.250 kg and force applied of 20N is 80m/s².

Acceleration is the rate of change of velocity of an object. Acceleration means the speed of the object is changing, but not always. When an object moves in a circular path at a constant speed rather than variable, it is still accelerating, because the direction of its velocity is changing. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second (m/s²).

According to the formula,

f = m × a

f = force,

m = mass of the body,

a = acceleration of the body

f = 20N

m = 250 grams = 0.250kg (1kg = 1000grams)

f = m × a

a = f/ m

a = 20N/ 0.250kg

a = 80m/s²

The acceleration of the body is 80m/s².

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As you speed up while driving through the rain, the angle of the rain relative to the horizontal that you observe from inside the car will become more perpendicular. This is because the raindrops are being deflected by your car's movement, making them appear to be coming straight down.

When you're driving through the rain, the raindrops are initially hitting the windshield of your car at an angle. If you speed up, the velocity of your car increases, and this increases the deflection of the raindrops as they hit your windshield. The result is that the angle at which the raindrops hit the windshield appears to be more perpendicular, making it appear as though the rain is falling straight down. This is simply an optical illusion caused by the increased deflection of the raindrops due to your car's movement.

It's important to note that the actual angle of the rain relative to the horizontal hasn't changed. Rather, it's just the angle that you perceive from inside the car that has changed due to the increased deflection of the raindrops caused by your car's movement.

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As a result, it splits into two smaller nuclei, krypton-92 and barium-141. The reaction also releases three neutrons and a great deal of energy. It can be represented by this nuclear equation:

92235 U + 1 neutron → 36 92 K r + 56 141 B a + 3 neutrons + energy

Answer:

I don't know if I can help you with that

Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

def force(mass, acceleration):

force_val = mass*acceleration

return force_val

10 is assigned to mass and 9.81 is assigned to acceleration

def force(10, 9.81)

So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

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The speed that a fly with a mass of 0.65 g would need in order to have the same kinetic energy as a 1250 kg automobile traveling at a speed of 11 m/s is 2133.97 m/s.

Given:mass of fly, m1 = 0.65 g = 0.00065 kg

speed of automobile, v2 = 11 m/smass of automobile, m2 = 1250 kg

To find: Speed of fly with kinetic energy same as automobile

Formula:Kinetic energy = 0.5 * mass * speed²

Solution:Let v1 be the speed of the fly

Kinetic energy of automobile = Kinetic energy of fly0.5 * m2 * v2² = 0.5 * m1 * v1²

Substituting given values0.5 * 1250 * 11² = 0.5 * 0.00065 * v1²v1² = (0.5 * 1250 * 11²)/0.00065v1² = 4545454.55v1 = √(4545454.55)v1 = 2133.97 m/s

Therefore, the speed that a fly with a mass of 0.65 g would need in order to have the same kinetic energy as a 1250 kg automobile traveling at a speed of 11 m/s is 2133.97 m/s.

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Answer:

22500 Ns

Explanation:

Given,

Mass ( m ) = 1500 kg

Velocity ( v ) = 15 m/s

Formula : -

Impulse = mv

Impulse

= 1500 x 15

= 22500 Ns

Therefore,

22500 Ns is the impulse experienced by the car.

Note : -

Ns is the unit of impulse.

The pressure transmitted in the hydraulic fluid is 4000 Pa and the mass of the load is 40.82 kg.

To determine the pressure transmitted in the hydraulic fluid, we can use the formula:

Pressure = Force / Area

Given that a force of 20 N is applied to the small piston and the cross-sectional area of the small piston is 0.005 m², we can calculate the pressure as follows:

Pressure = 20 N / 0.005 m²

Pressure = 4000 Pa

Therefore, the pressure transmitted in the hydraulic fluid is 4000 Pa.

To determine the mass of the load, we need to consider the equilibrium of forces in the hydraulic system. The force applied to the small piston is transmitted to the larger piston. Since the system is in equilibrium, the force exerted by the larger piston must balance the force applied to the small piston.

Using the formula:

Force = Pressure × Area

The force exerted by the larger piston can be calculated as follows:

Force = Pressure × Area (large piston)

Force = 4000 Pa × 0.1 m²

Force = 400 N

Therefore, the force exerted by the larger piston is 400 N.

Since force is equal to mass multiplied by acceleration (F = m × a), and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the mass of the load:

400 N = mass × 9.8 m/s²

Solving for the mass:

mass = 400 N / 9.8 m/s²

mass ≈ 40.82 kg

Therefore, the mass of the load is approximately 40.82 kg.

The question was incomplete. find the full content below:

The diagram shows a basic hydraulic system which has a small piston and a large piston with cross-sectional areas of 0.005m² and 0.1m² respectively. A force of 20 N is applied to the small piston. Determine (a) the pressure transmitted in the hydraulic fluid (b) the mass of the load​

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Answer:

a. 40.0 N

b. 0.41

Explanation:

By the second law of Newton, the net force is equal to the mass times the acceleration. In this case, the net force is the applied force less the frictional force, so

Where F is the applied force, Ff is the friction force, m is the mass and a is the acceleration.

Solving for Ff, we get

Now, we can replace the values

So, the frictional force is 40N

On the other hand, the force of friction is equal to the normal force times the coefficient of friction. Where the normal is equal to its weight, so

Where μ is the coefficient of friction and g is the gravity and it is equal to 9.8 m/s². Solving for μ

Now, we can replace the values to get

Therefore, the coefficient of friction is 0.41

Then, the answers are

a. 40.0 N

b. 0.41

The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.

Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A

Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A

Therefore, the current through resistor R3 is 0.33 A.

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Answer:

Sink

Explanation:

The normal density of water is 1 g/cm3.  Since the rock has a higher density of 1.72g/cm3, it will sink in water.

The highlighted vessel  given below in the image attached:

What is the function of the coronary arteries and cardiac veins?

The movement of blood through the blood arteries that nourish the heart muscle is known as coronary circulation (myocardium). The heart muscle receives oxygenated blood from the coronary arteries. After the blood has been deoxygenated, cardiac veins remove it.

The heart muscle receives blood from coronary arteries. The heart muscle need oxygen-rich blood in order to operate, just like all other bodily components do. Blood that lacks oxygen must also be transported away. Outside of the heart, the coronary arteries encircle the organ.

Therefore, Your heart receives blood through the coronary arteries and their branches. In order to pump blood through your heart and the rest of your body, your heart muscles require the oxygen and nutrients found in blood.

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To convert the ideal-gas equation to relate Ppsig, Vft³, nlb-mole, and T°F and the total amount of gas is calculated by converting the moles of CO and N to lb-mole and to estimate the temperature needed to increase the gas pressure to 3000 psig, Convert the obtained temperature in K to °F.

The equation relating P (psig), V (ft³), n (lb-mole), and T* (°F) is:

P = 14.7 * P(atm), V = 28.3168 * V(L), n

= 2.20462 * n(mol), and T*

= (9/5) * T(K) - 459.67 and to calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass and convert to lb-mole and to estimate the temperature in °F required to increase the gas pressure to 3000 psig.

(a) To convert the equation, we need to apply the following conversions:
- To convert P from atm to psig, multiply by 14.7 (since 1 atm = 14.7 psig).
- To convert V from liters to ft³, multiply by 28.3168 (since 1 liter = 0.0353 ft³).
- To convert n from mol to lb-mole, multiply by 2.20462 (since 1 mol = 2.20462 lb-mole).
- To convert T from K to °F, use the conversion formula:

T* = (9/5) * T(K) - 459.67.

(b) To calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass (using the periodic table) and convert to lb-mole by multiplying by the molar mass of CO (28.01 lb/lb-mol). To calculate the mass of CO in lb, multiply the number of moles of CO by its molar mass (28.01 g/mol) and convert to lb by dividing by 453.59237 g/lb.

(c) To estimate the temperature in °F required to increase the gas pressure to 3000 psig, rearrange the ideal gas equation to solve for T*. Substitute the known values: P = 3000 psig (pressure limit), V = 3.5 ft³ (volume), n = 30.0 mole (number of moles), and solve for T*. Note that this estimate may not be accurate at high pressures.

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Answer:

a on edge

Explanation:

The Euler acceleration: Magnitude  will be 0.0674 m/s² and the Coriolis acceleration: Magnitude  will be 0.161 m/s²

To calculate the exact values, we need to plug in the appropriate formulas and perform the calculations.

Euler acceleration:

Radius of the star (r) = 4 km = 4,000 m

Period of rotation (T) = 36 min = 36 * 60 = 2,160 s

First, let's calculate the angular velocity (ω):

ω = (2π / T) = (2π / 2,160) ≈ 0.002908 rad/s

Next, we can calculate the Euler acceleration (aE) using the formula:

aE = 2 * ω * v

Let's assume the velocity (v) of the star is at its surface and is equal to the tangential velocity at the equator:

v = ω * r = 0.002908 * 4,000 = 11.632 m/s

Substituting the values into the Euler acceleration formula:

aE = 2 * 0.002908 * 11.632 = 0.0674 m/s²

Therefore, the magnitude of the Euler acceleration for this spherical rotating star is approximately 0.0674 m/s².

Coriolis acceleration:

Latitude (φ) = 54°

Velocity (v) = 24 m/s

First, let's convert the latitude from degrees to radians:

φ = 54° * (π/180) = 0.9425 rad

Next, we can calculate the Coriolis acceleration (aC) using the formula:

aC = 2 * ω * v * sin(φ)

Substituting the values into the Coriolis acceleration formula:

aC = 2 * 0.002908 * 24 * sin(0.9425) = 0.161 m/s²

Therefore, the magnitude of the Coriolis acceleration for the object located on the star at 47E, 54N, heading at a speed of 24 m/s N is approximately 0.161 m/s².

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a) To raise the elevator at 35.0 cm/s, the disk must turn at approximately 0.044 rpm.

b) To accelerate the elevator at 18g, the angular acceleration of the disk must be approximately 141.4 rad/s^2.

c) The angle through which the disk has turned when it has raised the elevator 2.55 m between floors is approximately 2.04 radians.

To find the rpm of the disk required to raise the elevator at a speed of 35.0 cm/s, we can start by finding the speed at which the cable is moving over the disk. The circumference of the disk is

C = πd = π(2.50 m) = 7.85 m

The distance traveled by the cable in one revolution of the disk is equal to the circumference of the disk. Therefore, the speed of the cable is

v = C × rpm

To find the rpm required to raise the elevator at 35.0 cm/s, we can solve for rpm

35.0 cm/s = 0.35 m/s

0.35 m/s = 7.85 m × rpm

rpm = 0.35 m/s ÷ 7.85 m = 0.044 rpm

Therefore, the disk must turn at approximately 0.044 rpm to raise the elevator at a speed of 35.0 cm/s.

To accelerate the elevator at 18g, we need to find the force required:

F = ma = (18g)(m)

where m is the mass of the elevator. We can rearrange this equation to solve for m

m = F ÷ (18g)

To find the angular acceleration of the disk required to accelerate the elevator, we can use the equation

α = a ÷ r

where α is the angular acceleration, a is the linear acceleration, and r is the radius of the disk. The radius of the disk is half the diameter, or 1.25 m.

α = (18g) ÷ (1.25 m)

α ≈ 141.4 rad/s^2

Therefore, the angular acceleration of the disk must be approximately 141.4 rad/s^2 to accelerate the elevator at 18g.

To find the angle through which the disk has turned when it has raised the elevator 2.55 m between floors, we can use the equation

θ = s ÷ r

where θ is the angle in radians, s is the distance traveled by the cable, and r is the radius of the disk.

The distance traveled by the cable is equal to the difference in height between the floors, or 2.55 m.

θ = 2.55 m ÷ 1.25 m

θ ≈ 2.04 radians

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Answer:

Liquid water is essential for life to exist. Water can occur in a liquid state only within a specific temperature range, so knowing the temperature range on a planet will help astronomers predict whether life exists on that planet.

The person who first proposed that electrons exhibit the properties of a wave was French physicist Louis de Broglie in 1924. De Broglie introduced the concept of wave-particle duality, suggesting that particles, such as electrons, could also have wave-like properties.

We have heard about the nature of light and the characters it displays. Interference, reflection, refraction and diffraction are some of the characteristics. Wave-Particle Duality helps us to understand the particle and wave nature of light. Based on the idea that light and all other electromagnetic radiation may be considered a particle or a wave nature, in 1923 physicists Louis De Broglie suggested that the same kind of duality must apply to the matter.

So, The person who first proposed that electrons exhibit the properties of a wave was French physicist Louis de Broglie in 1924.

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The energy that has been used is 0.24 kWh

Answer:

5 years

Explanation:

\(\frac{1}{8}(40)\\\\= 5\)

Answer:

The amount of charge increases.

Explanation:

For a capacitor that has its plates still connected to a battery, the voltage on the capacitor remains constant. If the distance between the two plates of this capacitor is decreased, the capacitance will increase, and then the charge on the plate will increase in accordance with the relationship

Q =CV

From this relationship, if V is held constant, then Q has to increase for C to increase also.

B

Explanation:

I not sure try to solve I am sorry

Centrifugal force is a term often used to describe the apparent force pulling an object away from the center of rotation during circular motion.

Centrifugal force is a term often used to describe the apparent force pulling an object away from the center of rotation during circular motion.

However, it is important to note that centrifugal force is not a fundamental force of nature but rather a perceived force experienced in a rotating reference frame. It is a result of inertia and the tendency of objects to continue moving in a straight line.

The concept of centrifugal force can be useful in understanding certain phenomena, such as the feeling of being pushed outward in a turning car. However, it does not actually enhance a car's ability to turn. In reality, the car's tires and friction between them and the road provide the necessary forces for turning.

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Answer:

The scale read 1280 N.

Explanation:

Given that,

The mass of a person, m = 80 kg

We need to find the scale reading when the elevator is moving upward at 6.2 m/s².

We know that, when an elevator moves up, the reading on the scale is given by :

N-mg=ma

N=m(a+g)

Put all the values,

N = 80(6.2+9.8)

= 80(16)

= 1280 N

Hence, the scale read 1280 N.