Answer:
16.6 m
Explanation:
Let d be the distance the other person is ahead of you. Since the other person is walking at a speed, v = 1.17 m/s, after picking the wallet, the other person moves a distance , vt in time, t = 10.5 s, the total distance covered by you till catch up is D = d + vt.
Also, you moves with a speed of v' = 2.75 m/s in time t = 10.5 s as you pick up the wallet, you covers a distance d' = v't at catch up.
At catch up, D = d'
d + vt = v't
d = v't - vt
d = (v' - v)t
Substituting the values of the variables into d, we have
d = (2.75 m/s - 1.17 m/s)10.5 s
d = (1.58 m/s)10.5 s
d = 16.59 m
d ≅ 16.6 m
So, the other person was 16.6 m ahead of you when you started running.
compare the times of all sunsets during the same period what do you observe
Answer:
Theres no given?
Explanation:
Well, whatever.
I observed the shift of their sunset time.
Examples like:
January to June = their sunset time increased while
July to December = their sunset time decreased
the surface of a mirror is flat.
Answer:
plane on edge
Explanation:
A flash light has a potential difference of 6 volts and a resistor of 2 Ohms . The current in the flash light is
amps.
Answer:
3 amps
Explanation:
Volts divided by ohms
What is the resistance of a circuit with a current of 48 amps and a voltage of 12 volts?
a: 0.25 ohms
b: 60 ohms
c: 4 ohms
d: 576 ohms
Answer:
a: 0.25 ohms
Explanation:
The resistance of the circuit can be calculated by using Ohm's Law:
\(V = IR\\\\R = \frac{V}{I}\)
where,
R = Resistance of the circuit = ?
V = Voltage = 12 volts
I = Current = 48 A
Therefore,
\(R = \frac{12\ V}{48\ A} \\\\R = 0.25\ ohms\)
Hence, the correct option is:
a: 0.25 ohms
What velocity must a car with a mass of 1370kg have in order to have the same momentum as a 2280kg pickup truck traveling at 21m/s to the east
The velocity of the car along east direction must be 34.94 m/s.
What is momentum?In physics momentum of any object can be defined as product of velocity and mass. As velocity is a vector quantity, momentum is also a vector quantity. So, to define momentum both magnitude and direction are required. SI unit of momentum is kg-m/s.
Mass of the car = 1370 kg.
Mass of the pickup truck a = 2280 kg
Momentum of the pickup truck along east = 2280 kg × 21 m/s
= 47880 kg-m/s.
Hence, velocity of the car along east direction = (47880/1370) m/s
= 34.94 m/s.
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Please help with these 4 questions
The amount of time which the impetus was implemented is 3.04 seconds.
The momentum of the automobile is 34124.26 kg*m/s.
How to calculate the valueIn order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.
Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.
momentum = 2546.9 kg x 13.4 m/s
= 34124.26 kg
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Name the type of component through which current only flows in one direction.
A rod of length Lo moves iwth a speed v along the horizontal direction. The rod makes an angle of (θ)0 with respect to the x' axis.
Required:
a. Show that the length of the rod as measured by a stationary observer is L=L0[1-v^2/c^2 cos^2(θ)0].
b. Show that the angle the rod makes iwth the x-axis is given by the expression tan(theta)=tan(θ)0/(1-v^2/c^2)^.5
Answer:
From the question we are told that
The length of the rod is \(L_o\)
The speed is v
The angle made by the rod is \(\theta\)
Generally the x-component of the rod's length is
\(L_x = L_o cos (\theta )\)
Generally the length of the rod along the x-axis as seen by the observer, is mathematically defined by the theory of relativity as
\(L_xo = L_x \sqrt{1 - \frac{v^2}{c^2} }\)
=> \(L_xo = [L_o cos (\theta )] \sqrt{1 - \frac{v^2}{c^2} }\)
Generally the y-component of the rods length is mathematically represented as
\(L_y = L_o sin (\theta)\)
Generally the length of the rod along the y-axis as seen by the observer, is also equivalent to the actual length of the rod along the y-axis i.e \(L_y \)
Generally the resultant length of the rod as seen by the observer is mathematically represented as
\(L_r = \sqrt{ L_{xo} ^2 + L_y^2}\)
=> \(L_r = \sqrt{[ (L_o cos(\theta) [\sqrt{1 - \frac{v^2}{c^2} }\ \ ]^2+ L_o sin(\theta )^2)}\)
=> \(L_r= \sqrt{ (L_o cos(\theta)^2 * [ \sqrt{1 - \frac{v^2}{c^2} } ]^2 + (L_o sin(\theta))^2}\)
=> \(L_r = \sqrt{(L_o cos(\theta) ^2 [1 - \frac{v^2}{c^2} ] +(L_o sin(\theta))^2}\)
=> \(L_r = \sqrt{L_o^2 * cos^2(\theta) [1 - \frac{v^2 }{c^2} ]+ L_o^2 * sin(\theta)^2}\)
=> \(L_r = \sqrt{ [cos^2\theta +sin^2\theta ]- \frac{v^2 }{c^2}cos^2 \theta }\)
=> \(L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }\)
Hence the length of the rod as measured by a stationary observer is
\( L_r = L_o \sqrt{1 - \frac{v^2}{c^2 } cos^2(\theta ) }\)
Generally the angle made is mathematically represented
\(tan(\theta) = \frac{L_y}{L_x}\)
=> \(tan {\theta } = \frac{L_o sin(\theta )}{ (L_o cos(\theta ))\sqrt{ 1 -\frac{v^2}{c^2} } }\)
=> \(tan(\theta ) = \frac{tan\theta}{\sqrt{1 - \frac{v^2}{c^2} } }\)
Explanation:
The special relativity relations allow to find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: \(L = L_o \sqrt{1 - \frac{v^2}{c^2} \ cos^2\theta_o }\)
b) The angle with respect to the x axis is: \(tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }\)
Special relativity studies the motion of bodies with speeds close to the speed of light, with two fundamental assumptions.
The laws of physics are the same in all inertial systems. The speed of light in vacuum has the same value for all inertial systems.
If we assume that the two systems move in the x-axis, the relationship between the components of the length are:
\(L_x = L_{ox} \ \sqrt{1- \frac{v^2}{c^2} }\)
\(L_y = L_o_y \\L_z = L_{oz}\)
Where the subscript "o" is used for the fixed observed on the rod, that is, it is at rest with respect to the body, v and c are the speed of the system and light, respectively.
a) They indicate that the length of the rod is L₀ and it forms an angle θ with the horizontal.
Let's use trigonometry to find the components of the length of the rod in the system at rest, with respect to it.
sin θ = \(\frac{L_{oy}}{L_o}\)
cos θ = \(\frac{L_{ox}}{L_o}\)
\(L_{oy}\) = L₀ sin θ
L₀ₓ = L₀ cos θ
Let us use the transformation relations of the length of the special relativity rod.
x-axis
\(L_x = (L_o cos \theta_o) \ \sqrt{1- \frac{v^2}{c^2} }\)
y-axis
\(L_y = L_{o} sin \theta_o\)
The length of the rod with respect to the observer using the Pythagorean theorem is:
L² = \(L_x^2 + L_y^2\)
\(L^2 = (L_o cos \theta_o\sqrt{1- \frac{v^2}{c^2} })^2 + (L_o sin \theta_o)^2\)
\(L_2 = L_o^2 ( cos^2 \theta_o - cos^2 \theta_o \frac{v^2}{c^2} + sin^2\theta_o)\)
\(L^2 = L_o^2 ( 1 - \frac{v^2}{c^2} \ cos^2 \theta_o)\)
\(L= Lo \sqrt{1- \frac{v^2}{c^2} cos^2 \theta_o}\)
b) the angle with the x-axis measured by the stationary observer is:
\(tna \theta = \frac{L_y}{L_x}\)
\(tan \ theta = \frac{L_o sin \theta_o}{L_o cos \theta_o \sqrt{1- \frac{v^2}{c^2} } }\)
\(tan \theta = \frac{tan \theta_o}{\sqrt{1-\frac{v^2}{c^2} } }\)
In conclusion, using the special relativity relations we can find the results for the questions about the measurements made by an observed at rest on the rod are:
a) The length of the rod is: \(L = L_o \sqrt{1- \frac{v^2}{c^2} \ cos^2\theta_o }\)
b) The angle to the x axis is: \(tan \theta = \frac{tan \theta_o}{\sqrt{1- \frac{v^2}{c^2} } }\)
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Which pieces of safety equipment should be worn if you are working with sodium hydroxide, a strong base, in a chemistry lab?
A) apron and mask
B) goggles and apron
C) apron and respirator
D) goggles and chest protector
The helium-filled balloons below are carrying negative electric charges, as shown. Attach two of the balloons to the hooks below to show what would happen if a red balloon and a blue balloon were brought near each other. Plzz help
Answer:
these are in the hooks the balloons repel each other if the hooks are isolated.
Explanation:
In electrostatics, charges of the same sign repel and of a different sign attract each other.
With this explanation we analyze the situation presented, they indicate that the balloons have a negative taste, so when these are in the hooks the balloons repel each other if the hooks are isolated.
If the hooks are connected to Earth, the poop of the balloons is neutralized, so there is neither attraction nor repulsion.
Answer:
Here you go : )
Explanation:
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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素 Example three
After an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up How far is it
from the take off point?
Solution
Answer:
Let R be the total distance
R²=10.4²+(8.7+2.1)²
R²=10.4²+10.8²
R²=224.8
You square root both sides
R=14.99km
If an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up, then using the Pythagorean theorem it is 14.99km from its take-off point.
What is Pythagoras' theorem?Pythagoras' theorem is a fundamental theorem in mathematics that relates to the sides of a right-angled triangle. It states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In equation form, the theorem can be written as:
c² = a² + b²
Where
c =the length of the hypotenuse,
a and b = the lengths of the other two sides.
The theorem is named after the ancient Greek mathematician Pythagoras, who is credited with his discovery and proof. Pythagoras' theorem is widely used in mathematics and has many practical applications in fields such as architecture, engineering, and physics.
Here in the question
We can use the Pythagorean theorem to find the distance from the takeoff point:
Distance = √(West)² + (North+Up)²
Plugging in the given values, we get:
Distance = √(10.4)² +( 8.7 + 2.1)²
Distance ≈ 14.99km
Therefore, the airplane is approximately 14.99km away from the takeoff point.
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
The speed limit on some segments of interstate 4 is 70 mph. What is this in km/h?
Answer:
112.63km/hr
Explanation:
The given dimension is :
70mph
We are to convert this to km/hr
1 mile = 1.609km
so;
70mph x 1.609 = 112.63km/hr
So,
The solution is 112.63km/hr
what is the meaning of the word physics
Answer:
the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.
Explanation:
mark as brainliest
Discuss the similarities and differences between the electrical force on a charge and the magnetic force on a charge.
Explanation:
Both are field dependent. Electric force is dependent on charge, while Magnetic force is dependent on current or rate of charge flow
Scientific theories are deductive in nature.?
Answer:
deductive reasoning usually follows steps .
That is, how we predict what the observations should be if the theory were correctIn a block-spring system
m = 0.25kg
and
k = 4N /m
. At
t = 0.15s
, the velocity is
v = −0.174m/s
and
the acceleration
2
a = +0.877m /s
. Write an expression for the displacement as a function of time,
x(t)
Answer:
the answer is b
Explanation:
An expression for the displacement as a function of time is x(t) = a sin wt.
What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude. The spacing between two specified points is represented by displacement, a one-dimensional measure commonly known as length or distance.
Given in the question we have to find the displacement of the as function of time
The equation used of express displacement is.
d = V i t + 1 2 a t 2
Displacement = Final position – initial position = change in position.
so, x = A sin wt is equation where A is amplitude and t is time period.
An expression for the displacement as a function of time is x(t) = a sin wt.
Thus, an expression for the displacement as a function of time is x(t) = a sin wt.
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Please help I only have 2 minutes left
Answer:
I believe it is C
Explanation:
Because salt makes everything taste bitter if you add to much of it.
Which one the answer to this question
If and object undergoes a change in momentum of 12 kg*m/s over a 10
second interval, what was the force exerted?
The magnitude of the force exerted on this object is 1.2 Newton.
Given the following data:
Change in momentum = 12 Kgm/s.Time = 10 seconds.What is impulse?In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.
Mathematically, impulse is given by this formula:
\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)
Substituting the given parameters into the formula, we have:
\(Force \times 10=12\\\\Force =\frac{12}{10}\)
Force = 1.2 Newton.
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What do I know about dance movements?
Answer:
Hi lol
Explanation:
follow me lol
sarivigakarthi this is my account...
5. Great Moments in Science dateline: The _____s. Why are high heels dudes in mud?
Fill in the blank.
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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Besides ethical considerations, what is another reason why Milgram’s experiment may be difficult to duplicate?
which of the following can not happen when a light ray strikes a new medium
Answer:
amplification
Explanation:
reflection can happen
some amount of lighr get absorbed
something gets refracted
but amplification cant
. Suppose that a positive charge is brought near a neutral, insulating piece of material. Is the positive charge attracted, repelled, or indifferent to the neutral object
Answer:
Positive charge is attracted to the neutral object.
Explanation:
Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.
For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.
Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.
The charge will be attracted.
Understanding the force between charges.
As you may know, opposite charges attract (and equal charges repel).
So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).
Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.
Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.
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child in a circular, rotating space station tosses a ball in such a way so that once the station has rotated through one half rotation, the child catches the ball. From the child's point of view, which plot shows the trajectory of the ball? The child is at the bottom of the space station in the diagrams below, but only the initial location of the ball is shown. (A) (B)
Based on the description provided, the diagram that correctly illustrates the movement of the ball from the child's perspective is C.
How is the movement described?Considering the child is rotating and he or she catches the ball some seconds after throwing it, it can be concluded the trajectory is closed, which means the diagram should show the ball returning to the initial point.
Based on the above, diagrams A and B are not possible because the ball is not retruning to the child.
Which diagram correctly illustrates the movement?Considering the child is moving at a constant speed and in a defined circular area, it is expected the movement resembles a circle; however as the ball will be affected by a leftward force in case the child is moving clockwise the movement will not be exactly a circle. Based on the above, the best option is diagram C.
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The uniform beam has a weight W and length L and is supported by a pin at A and cable BC ( figure 1)
Part A
Determine the horizontal and vertical components of reaction at A
Express your answers in terms of some or all of the variables W, R. Φ and θ). Enter your answers separated by a comma.
View Available Hint's)
Aa + Ay = ____
Parts B
Determine the one cable car necessary to hold the beans position shown
Express your answers in terms of some or all of the variables W, R. Φ and θ).
The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).
What is Normal Stress and Strain?In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."
In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,
If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.
Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.
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How does something(the big bang) come from nothing by nothing i mean the first universe although we don't know where the first universe is but we do know that nothing can't come from something.
The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.
It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.
Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.
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