xample: For Li2+ ion, calculate a) the radius of the electron in the second orbit (n=2), then b) the velocity and c) the energy of the electron. a) r2==0.705A˚ A hydrogen-like atom or hydrogen. and only one electron. b) v2==3.28×106 m/s c) =−4.90×10−18 J
Answers
A) The radius of the electron in the second orbit (n=2) of Li2+ ion is 0.705 Å.
b) The velocity of the electron in the second orbit (n=2) of Li2+ ion is 3.28×10⁶ m/s.
c) The energy of the electron in the second orbit (n=2) of Li2+ ion is -4.90×10⁻¹⁸ J.
A) The radius of the electron in the second orbit (n=2) of Li2+ ion can be calculated using the formula r=n²h²/4π²me²,
Substituting the values, we get:
r2 = (2² x (6.626 x 10⁻³⁴ J s)²) / (4 x π² x (9.109 x 10⁻³¹ kg) x (1.602 x 10⁻¹⁹ C)²)
r2 = 0.705 Å
b) The velocity of the electron in the second orbit (n=2) of Li2+ ion can be calculated using the formula v=Ze²/2ε₀mr, where Z is the atomic number, e is the charge of the electron, ε₀ is the permittivity of free space, m is the mass of the electron, and r is the radius of the orbit.
Substituting the values, we get:
v2 = (3 x (1.602 x 10⁻¹⁹ C)²) / (2 x (8.854 x 10⁻¹² F/m) x (9.109 x 10⁻³¹ kg) x (0.705 x 10⁻¹⁰ m))
v2 = 3.28×10⁶ m/s
c) The energy of the electron in the second orbit (n=2) of Li2+ ion can be calculated using the formula E=(-me⁴Z²)/(8ε₀²h²n²),
Substituting the values, we get:
E2 = (- (9.109 x 10⁻³¹ kg) x (1.602 x 10⁻¹⁹ C)⁴ x 3²) / (8 x (8.854 x 10⁻¹² F/m)² x (6.626 x 10⁻³⁴ J s)² x 2²)
E2 = -4.90
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Related Questions
6c.Calculate the maximum volume, in dm3, of chlorine gas at Stp that can be obtained from 23.4 tonnes of molten sodium chloride. 1 tonne= 10^6 Mr of NaCl=58.5 molar volume of chlorine at stp= 24dm3 Give your answer in standard format.
Answers
Answer:
4.48×10⁶ dm³
Explanation:
We'll begin by converting 23.4 tonnes to grams (g). This can be obtained as follow:
1 tonne = 10⁶ g
Therefore,
23.4 tonnes = 23.4 × 10⁶
23.4 tonnes = 2.34×10⁷ g
Thus, 23.4 tonnes is equivalent to 2.34×10⁷ g
Next, we shall determine the number of mole in 2.34×10⁷ g of NaCl. This can be obtained as follow:
Mass NaCl = 2.34×10⁷ g
Molar mass of NaCl = 58.5 g/mol
Mole of NaCl =?
Mole = mass / molar mass
Mole of NaCl = 2.34×10⁷ / 58.5
Mole of NaCl = 4×10⁵ moles
Next, we shall determine the number of mole of chlorine, Cl₂ produced from the reaction. This can be obtained as follow:
2NaCl —> 2Na + Cl₂
From the balanced equation above,
2 moles of NaCl reacted to produce 1 mole of Cl₂.
Therefore, 4×10⁵ moles of NaCl will react to produce = (4×10⁵ × 1)/2 = 2×10⁵ moles of Cl₂.
Thus, 2×10⁵ moles of Cl₂ were obtained from the reaction.
Finally, we shall determine the volume of Cl₂ produced. This can be obtained as follow:
1 mole of Cl₂ at stp = 22.4 dm³
Therefore,
2×10⁵ moles of Cl₂ at stp = 2×10⁵ 22.4
2×10⁵ moles of Cl₂ at stp = 4.48×10⁶ dm³
Thus, the volume of chlorine obtained from the reaction is 4.48×10⁶ dm³
The diagrams below are illustrations of some farm tools. Study them carefully and use
them to answer the questions that follow.
1)
iii)
M
Die
N
P
T.
Q
Identify each of the tools labelled M, N, P and Q.
Mention one use each of the tools labelled M, N, P and Q.
[4 marks]
[4 marks]
State two precautions that must be taken when using the labelled P. [2 marks].
Answers
According to the information we can infer that these tools are: P.aspersor, Q. sword, M. manual drill, N. blind. According to the above, these tools are used to build and sprinkle crops.
What tools do we see in the image?According to the image we can infer that the different tools are:
P. sprinkler.Q. sword.M. hand drill.N. blind.On the other hand, the functions of these tools are:
P. apply substances on crops.Q. Cut crops.M. Make holes.N. Make cuts.The precautions that we must take with these tools (P) are:
Good handling.Use personal protection elements.Note: This question is incomplete. Here is the complete information:
Attached image
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Which property would cesium most likely have? It is hard. It is ductile. It is a gas. It has low reactivity.
Answers
Answer:
it is ductile
Explanation:
i took the test
Answer:
b
Explanation:
A chemist found a 60.00 gram sample containing copper and oxygen. Given the following percent composition, what is the mass of copper in the sample?
Copper- 57.08 %
Oxygen- 42.9296
choose an answer:
O 0.5708 g Cu
o 25.02 g Cu
34.25 g cu
63.5 g Cu
Answers
an engine that has been configured to run on propane (c 3h8) combusts with 20% excess air. a. write the balanced stoichiometric reaction and calculate the stoichiometric air/fuel ratio. b. write the balanced reaction with 20% excess air and calculate the actual air/fuel ratio at which the engine is operating. c. calculate the equivalence ratio and discuss the result
Answers
When an air and fuel mixture has more gas than what is required for efficient combustion, a lean burn results.The ideal combustion ratio for burning propane entirely is 1 part propane (4%) to 24 parts air (96%).
If the area has a cold snap while your propane tank is much less than 20% full, you may run out of propane faster than you expect.If there isn't any propane, your house won't be warm.Without heat, your home is dangerous and uncomfortably cold.Additionally, it's possible for your pipes to freeze or explode.
A 20 pound gas tank can it explode?Yes, they could, although this usually only applies to the portable, 20-lb grilling tanks, not the larger ones.A warm summer day can easily raise temperatures.Even as the portable propane tank warms up, the pressure will rise.
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please tell me if i did it right. did i put the right electric charge
Answers
Answer:
its good but your answer
what is the electronic configuration of all the elements
Answers
Answer:
1 Hydrogen 1s1
2 Helium 1s2
3 Lithium [He]2s1
4 Beryllium [He]2s2
5 Boron [He]2s22p1
6 Carbon [He]2s22p2
7 Nitrogen [He]2s22p3
8 Oxygen [He]2s22p4
9 Fluorine [He]2s22p5
10 Neon [He]2s22p6
11 Sodium [Ne]3s1
12 Magnesium [Ne]3s2
13 Aluminum [Ne]3s23p1
14 Silicon [Ne]3s23p2
15 Phosphorus [Ne]3s23p3
16 Sulfur [Ne]3s23p4
17 Chlorine [Ne]3s23p5
18 Argon [Ne]3s23p6
19 Potassium [Ar]4s1
20 Calcium [Ar]4s2
21 Scandium [Ar]3d14s2
22 Titanium [Ar]3d24s2
23 Vanadium [Ar]3d34s2
24 Chromium [Ar]3d54s1
25 Manganese [Ar]3d54s2
26 Iron [Ar]3d64s2
27 Cobalt [Ar]3d74s2
28 Nickel [Ar]3d84s2
29 Copper [Ar]3d104s1
30 Zinc [Ar]3d104s2
31 Gallium [Ar]3d104s24p1
32 Germanium [Ar]3d104s24p2
33 Arsenic [Ar]3d104s24p3
34 Selenium [Ar]3d104s24p4
35 Bromine [Ar]3d104s24p5
36 Krypton [Ar]3d104s24p6
37 Rubidium [Kr]5s1
38 Strontium [Kr]5s2
39 Yttrium [Kr]4d15s2
40 Zirconium [Kr]4d25s2
41 Niobium [Kr]4d45s1
42 Molybdenum [Kr]4d55s1
43 Technetium [Kr]4d55s2
44 Ruthenium [Kr]4d75s1
45 Rhodium [Kr]4d85s1
46 Palladium [Kr]4d10
47 Silver [Kr]4d105s1
48 Cadmium [Kr]4d105s2
49 Indium [Kr]4d105s25p1
50 Tin [Kr]4d105s25p2
51 Antimony [Kr]4d105s25p3
52 Tellurium [Kr]4d105s25p4
53 Iodine [Kr]4d105s25p5
54 Xenon [Kr]4d105s25p6
55 Cesium [Xe]6s1
56 Barium [Xe]6s2
57 Lanthanum [Xe]5d16s2
58 Cerium [Xe]4f15d16s2
59 Praseodymium [Xe]4f36s2
60 Neodymium [Xe]4f46s2
61 Promethium [Xe]4f56s2
62 Samarium [Xe]4f66s2
63 Europium [Xe]4f76s2
64 Gadolinium [Xe]4f75d16s2
65 Terbium [Xe]4f96s2
66 Dysprosium [Xe]4f106s2
67 Holmium [Xe]4f116s2
68 Erbium [Xe]4f126s2
69 Thulium [Xe]4f136s2
70 Ytterbium [Xe]4f146s2
71 Lutetium [Xe]4f145d16s2
72 Hafnium [Xe]4f145d26s2
73 Tantalum [Xe]4f145d36s2
74 Tungsten [Xe]4f145d46s2
75 Rhenium [Xe]4f145d56s2
76 Osmium [Xe]4f145d66s2
77 Iridium [Xe]4f145d76s2
78 Platinum [Xe]4f145d96s1
79 Gold [Xe]4f145d106s1
80 Mercury [Xe]4f145d106s2
81 Thallium [Xe]4f145d106s26p1
82 Lead [Xe]4f145d106s26p2
83 Bismuth [Xe]4f145d106s26p3
84 Polonium [Xe]4f145d106s26p4
85 Astatine [Xe]4f145d106s26p5
86 Radon [Xe]4f145d106s26p6
87 Francium [Rn]7s1
88 Radium [Rn]7s2
89 Actinium [Rn]6d17s2
90 Thorium [Rn]6d27s2
91 Protactinium [Rn]5f26d17s2
92 Uranium [Rn]5f36d17s2
93 Neptunium [Rn]5f46d17s2
94 Plutonium [Rn]5f67s2
95 Americium [Rn]5f77s2
96 Curium [Rn]5f76d17s2
97 Berkelium [Rn]5f97s2
98 Californium [Rn]5f107s2
99 Einsteinium [Rn]5f117s2
100 Fermium [Rn]5f127s2
101 Mendelevium [Rn]5f137s2
102 Nobelium [Rn]5f147s2
103 Lawrencium [Rn]5f147s27p1
104 Rutherfordium [Rn]5f146d27s2
105 Dubnium *[Rn]5f146d37s2
106 Seaborgium *[Rn]5f146d47s2
107 Bohrium *[Rn]5f146d57s2
108 Hassium *[Rn]5f146d67s2
109 Meitnerium *[Rn]5f146d77s2
110 Darmstadtium *[Rn]5f146d97s1
111 Roentgenium *[Rn]5f146d107s1
112 Copernium *[Rn]5f146d107s2
113 Nihonium *[Rn]5f146d107s27p1
114 Flerovium *[Rn]5f146d107s27p2
115 Moscovium *[Rn]5f146d107s27p3
116 Livermorium *[Rn]5f146d107s27p4
117 Tennessine *[Rn]5f146d107s27p5
118 Oganesson *[Rn]5f146d107s27p6
Explanation:
Example #2: Ajet is traveling at 80 m/s when it starts to approach
a runway. It is able to land and park in 10 s. What is its
acceleration?
Answers
Answer:
-8 m/s^2
Explanation:
The formula for acceleration is:
a= v^2 - v^1/t
a= acceleration
v^2- final velocity which in this case would be 0 since the jet comes to a stop.
v^1= original velocity which is 80 m/s.
t=time or 10s
Substitute the letters for the numbers and you get this:
a= 0 - 80/10
0 - 80= -80
-80 divided by 10 is -8.
Hope this helps! :)
strontium-90 has a half-life of 29 years. given that you begin with a 12 mg sample, determine a model that represents the amount of the sample still remaining after 34 years.
Answers
There will be 5.3241 mg of the sample still remaining after 34 years.
What does an element's half-life mean?A radioactive isotope's half-life is the amount of time it takes for one half of it to decay. The half-life of a particular radioactive isotope is independent of its surroundings or initial concentration.
The half-life is the amount of time required for a quantity (of substance) to reduce to half of its initial value.
Now, the value of N( t ) is given by the formula ,
N( t ) = N₀ ( 1/2 )^ t/ t½
Where,
The value of t½ = 29 years
The initial amount of strontium-90 (N₀) = 12 mg
The number of days (t) = 34 years
The amount of strontium-90 left after 34 years = N( t )
Substituting the values in the equation , we get
N( t ) = 12 mg( 1/2 )^34/29
N( t ) = 12 mg ( 1/2 )¹ ¹⁷²⁴
N( t ) = 12 mg x 0.4436
N( t ) = 5.3241 mg
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h = Planck's constant = 6.63 x 10-34 J-s
An ultraviolet wave has a frequency of 8.00 x 1015 Hz. If a photon of this frequency collides with an electron, how much energy
could be transferred to the electron?
OA. 3.75 x 10-8 J
OB. 1.20 x 1049 J
OC. 5.30 x 10-18 J
OD. 1.89 x 1017 J
Answers
When you use the formula E=hv you will get the amount in choice C.
Tính phân tử khối của chất
Al(OH3)
Answers
Answer:
78g/mol
hope its helps u
estion 2
Where are the non-metals on the periodic table?
Answers
Answer: nonmetals are located on the upper right
Explanation:
easy ones! giving brainly if correct. answering both questions would be nice
Answers
I wish I am correct
2. In 1804, almost a century before the nucleus was discovered, the English scientist John Dalton provided evidence for the existence of the atom. Dalton thought that atoms were the smallest particles of matter, which couldn't be divided into smaller particles. He modeled atoms with solid wooden balls. In 1897, another English scientist, named J. J. Thomson, discovered the electron. It was first subatomic particle to be identified. Because atoms are neutral in electric charge, Thomson assumed that atoms must also contain areas of positive charge to cancel out the negatively charged electrons. He thought that an atom was like a plum pudding, consisting mostly of positively charged matter with negative electrons scattered through it.
The nucleus of the atom was discovered next. It was discovered in 1911 by a scientist from New Zealand named Ernest Rutherford, who is pictured in Figure below. Through his clever research, Rutherford showed that the positive charge of an atom is confined to a tiny massive region at the center of the atom, rather than being spread evenly throughout the “pudding” of the atom as Thomson had suggested.
Question: Why did Thomson think that the atom also had to have a positive charge?
Question: What two particles are found in the nucleus?
3.Question: What particle did Rutherford discover in the nucleus?
4.Question: What did Rutherford predict was also in the nucleus?
5.Question: How did Rutherford describe the size of the nucleus?
6.Question: According to Rutherford, how was Thomson's model of the atom incorrect?
7.Question: How are all atoms of an element identical?
Answers
2 atoms and electrons
3 atoms
4 the positive charge of an atom was confined to a tiny massive region at the center of the atom instead of being evenly distributed like a “pudding” as Thomson had suggested
5 the size of the nucleus was a “tiny massive region at the center of the atom”
6 Thomson proposed that the charge of the atom was evenly distributed in the nucleus, like a “pudding” which Rutherford proved false.
7 They all have a neutral charge
Of the original 695 color additives how many are still used today?
Answers
The compressibility of a gas is defined by the relationship between which two measurements of the gas?
Answers
The compressibility of a gas is determined by the relationship between its volume and pressure measurements, with the compressibility factor providing a quantitative measure of this relationship and deviations from ideal gas behavior.
The compressibility of a gas is defined by the relationship between its volume and pressure measurements. Compressibility is a property that describes how easily a gas can be compressed or expanded under the influence of external pressure.
When a gas is subjected to an increase in pressure, its volume tends to decrease, indicating compressibility. On the other hand, when the pressure on a gas is reduced, its volume tends to increase, indicating expansibility. The compressibility factor (Z) is commonly used to quantify the compressibility of a gas.
Mathematically, compressibility is expressed by the equation:
Z = PV/RT,
where Z is the compressibility factor, P is the pressure, V is the volume, R is the ideal gas constant, and T is the absolute temperature.
The compressibility factor provides information about deviations from ideal gas behavior. For an ideal gas, Z equals 1 at all pressures and temperatures. However, real gases often deviate from ideal behavior due to intermolecular interactions and non-ideal conditions.
At low pressures and high temperatures, most gases behave close to ideal gas behavior and have a compressibility factor close to 1. However, at high pressures and/or low temperatures, gas molecules come closer together, and intermolecular interactions become significant, causing deviations from ideal behavior and resulting in a compressibility factor different from 1.
By studying the compressibility factor as a function of pressure and temperature, one can gain insights into the behavior of gases under various conditions, including phase transitions, critical points, and the presence of attractive or repulsive intermolecular forces.
In summary, the compressibility of a gas is determined by the relationship between its volume and pressure measurements, with the compressibility factor providing a quantitative measure of this relationship and deviations from ideal gas behavior.
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What is the major organic product obtained from the following reaction?Br2 H20 Br Br OH Br OH OH Br
a. 1
b. 3
c. 4
d. 2
Answers
The major organic product obtained from the following reaction 2.
What is the organic ?Organic refers to the use of natural, sustainable farming practices and the avoidance of synthetic inputs such as pesticides, antibiotics, and hormones. Organic production is designed to support the health of soil, ecosystems, and people. Organic farmers use methods such as crop rotation, green manure, and composting to maintain soil fertility, control pests, and reduce pollution. Organic food is produced without the use of chemical fertilizers, pesticides, or other synthetic inputs. Organic food is generally higher in nutrients and lower in contaminants than conventionally-grown food.
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Calculate the mass of 488 moles of calcium carbonate, CaCO3
Help please!
Answers
Answer:
≅ 4.88 grams (3 sig. figs.)
Explanation:
to convert from ...
grams to moles => divide by formula wt.
moles to grams => multiply by formula wt.
this problem:
mass in grams = 488moles / 100.09g/mol = 4.875612 grams (calculator)
≅ 4.88 grams (3 sig. figs.)
What's the actual size of an atom?
Why does the amount of protons change the atom but not the neutrons?
Are we able to "edit atoms" and create new elements
what happens when an atom becomes too positively charged or negatively charged
Answers
Answer:
1.An atom is the smallest constituent unit of ordinary matter that constitutes a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small; typical sizes are around 100 picometers ( 1 × 10−10 m, a ten-millionth of a millimeter, or 1/254,000,000 of an inch).
3.New elements aren't exactly discovered anymore. However, they can be made, using particle accelerators and nuclear reactions. A new element is made by adding a proton (or more than one) to a pre-existing element. This can be done by smashing protons into atoms or by colliding atoms with each other.
4.If an atom gains an electron, it becomes negatively charged.
If an atom loses an electron, it becomes positively charged.
what is a mixture of elements and compounds
Answers
The substance in the image above would be classified as a mixture of elements (option E).
What is a compound and mixture?A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.
On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.
According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.
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4. For each of the following reactions, indicate whether you would expect the entropy of the
system to increase or decrease, and explain why. If you cannot tell just by inspecting the
equation, explain why.
(a) CH3OH() → CH3OH(g)
(b) N204(g) + 2NO2(g)
(c) 2KCIO3(s) → 2KCI(s) + 302
(d) 2NH3(g) + H2SO4(aq) →(NH4)2SO4(aq)
Answers
(a) The entropy of the system would increase. The transition from a liquid to a gas state involves an increase in the number of microstates, which leads to an increase in entropy. Therefore, the entropy of the system will increase as \(CH3OH\) transitions from a liquid state to a gas state.
(b) The entropy of the system would increase. The reaction involves the formation of three molecules of gas from one molecule of gas and another molecule that contains two molecules of gas. The increase in the number of molecules leads to an increase in the number of microstates, which results in an increase in entropy.
(c) The entropy of the system would increase. The transition from a solid to a liquid or gas state involves an increase in the number of microstates, which leads to an increase in entropy. Therefore, the entropy of the system will increase as \(2KCIO3\) transitions from a solid state to a liquid or gas state.
(d) The entropy of the system would increase. The reaction involves the formation of two molecules of gas from three molecules of gas and one molecule of aqueous substance. The increase in the number of molecules leads to an increase in the number of microstates, which results in an increase in entropy.
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What type of weather is typically associated with the air pressure system located
near Salem?
Answers
According to common weather maps of the region surrounding Salem, Massachusets, the weather typically associated with the air pressure system is rain.
Air pressure systems define areas where the interaction between temperatures and air currents creates weather. Air pressure systems can be of two types:
Low-pressure systemsHigh-pressure systemsGiven the nature of warm air and its tendency to rise, warmer regions tend to fall under the low-pressure system category. These systems, due to the movement of the warm air, have lower pressure at their center than in the areas surrounding them.
As the wind blows towards the low-pressure air systems, the cooler and warmer air meet within the atmosphere, which causes the water vapor to condense and form clouds. Oftentimes, these clouds then precipitate, causing rain.
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Why do metals have a positive charge?
Because they lose protons.
Because they gain protons.
Because they gain electrons.
Because they lose electrons.
Answers
Answer:
D. Because they lose electrons
Explanation:
In neutral state the numbers of proton (+) = numbers of electrons (-)
if there are less electrons, there will be more protons than electrons => positive charge
if there are more electrons, there will be more electrons than protons => negative charge
How many pairs of chromosomes do dogs have in their somatic (body) cells?
Answers
Answer:
78 pairs of chromosomes
Explanation:
In reaction 1, if we had used 4 grams of NaOH instead of 2 grams, would the heat gained by the solution [#6] have been larger, smaller or the same? Explain Briefly!
Answers
If we had used 4 grams of NaOH instead of 2 grams, the heat gained by the solution would have been higher.
What is the enthalpy?The term enthalpy has to do with the heat that could be emitted or evolved in a given reaction. We know that in a neutralization reaction, there is an evolution of heat and as such the reaction vessel would feel warm at the end of the reaction.
Also, the enthalpy would depend on the amount of the limiting reactant. In this case, the limiting reactant would be the sodium hydroxide and as such the enthalpy would affected by a change in the amount of the sodium hydroxide.
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Please help me I don’t know!!!!!!!
Answers
Answer: The answer is 1004.53242
Explanation:
Answer:
4.532421×10^-3
Explanation:
4.532×10^-3 + 0.000421
4.532421×10^-3
in descriptive scientific investigations scientis often make observations to understand the interacting parts of a complex
Answers
The answer is System.
When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.
Best of Luck!
Answer:
The answer is System.
Explanation:
When a scientific investigation is in progress, its used to perform and understand the natural phenomenon that goes on using the scientific method. Since this is a descriptive investigation, it provides a descriptive account of any system by looking at it without any prior knowledge to that subject. This method of investigation does not use a hypothesis. Thus, proves our answer correct.
Write each formula to solve for density, volume and mass.
Answers
V= M/D
M= D x V
hope it helps!!
How different foods affect glucose levels in the body virtual lab.
Carry out the procedures outlined in the virtual lab. In your own words, summarize the steps you used to complete the virtual assignment. Explain what the test (independent) variable was, and what the outcome (dependent) variable was.
What is independent variable and dependent variable? In your own words.
Answers
Answer: this might have something to do with the pancreas
Explanation:
the pancreas produces insulin if subject a produces more insulin than subject b the reaction to the glucose will be different the pancreas breaks down the glucose into sugar and protiens hope this helps
100 cm³ of a gas at 27°C is cooled to 20°C at constant pressure .Calculate the volume of gas at 20°C.
Answers
According to Charle's law, the volume of the given mass of a gas is directly proportional to its absolute temperature provided that the pressure is constant. Mathemically;
\(\begin{gathered} V\alpha T \\ V=kT \\ k=\frac{V}{T} \\ k=\frac{V_1}{T_1}=\frac{V_2}{T_2} \end{gathered}\)where;
V1 and V2 are the initial and final volume of the gas
T1 and T2 are the initial and final temperatures of the gas (in Kelvin)
Given the following parameters:
\(\begin{gathered} V_1=100\operatorname{cm}^3 \\ T_1=27^0C=27+273=300K \\ T_2=20^0C=20+273=293K \\ V_2=\text{?} \end{gathered}\)Substitute the given parameters into the formula;
\(\begin{gathered} V_2=\frac{V_1T_2}{T_1}^{} \\ V_2=\frac{100\times293}{300} \\ V_2=\frac{29300}{300} \\ V_2=\frac{293}{3} \\ V_2=97.67\operatorname{cm}^3 \end{gathered}\)Therefore the volume of the gas at 20°C is approximately 97.67cm³