Write the equation of the line that passes through the points (−5,7) and (2,−4). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

Answer:

Step-by-step explanation:

ab + cd = e

       cd = e - ab

         d =(e - ab)/d

The graph of the equation is attached below and this can be determined by using the formula of the volume of the cone and the slope-intercept form of the line

Given :

For cones with a radius of 6 units, the equation V=12h relates the height h of the cone, in units, and the volume V of the con, in cubic units.

The volume of the cone is given by the formula:

v = 1/3. π .r².h

Now, substitute the value of r in the above formula.

v = 12πh

Now, compare this equation with a slope-intercept form which is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From comparing the equation, it can be concluded that:

y = V

x = h

c = 0

m = 12

Now, draw the graph of the line that passes through the origin. The graph is attached below.

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The expression for the area under the curve y = x^3 from 0 to 1, as a limit, is A = 1/4.

(a) To find an expression for the area under the curve y = x^3 from 0 to 1 using Definition 2, we need to approximate the area using a sum and then take the limit as the number of approximating rectangles approaches infinity.

Let's divide the interval [0, 1] into n equal subintervals. The width of each subinterval will be Δx = 1/n. We can choose any point within each subinterval as the representative x-value for that subinterval. Let's choose the right endpoint of each subinterval as our representative x-value.

The right endpoint of the ith subinterval will be x_i = iΔx = i/n, where i ranges from 1 to n. The corresponding y-value for each x_i is y_i = (i/n)^3.

The area of each rectangle can be approximated as the product of the width and height of the rectangle, which is ΔA_i = Δx  y_i = (1/n)  (i/n)^3.

The total area under the curve can be approximated by summing up the areas of all the rectangles:

A = Σ(ΔA_i) = Σ[(1/n)  (i/n)^3] for i = 1 to n.

(b) The formula given in Appendix E states that the sum of the cubes of the first n integers is [n(n+1)/2]^2. Therefore, we have:

1^3 + 2^3 + 3^3 + ... + n^3 = [n(n+1)/2]^2.

Using this formula, we can rewrite the expression for the area under the curve as a limit:

A ≈ Σ[(1/n)  (i/n)^3] for i = 1 to n

= (1/n^4)  [1^3 + 2^3 + 3^3 + ... + n^3]

= (1/n^4)  [n(n+1)/2]^2.

Taking the limit as n approaches infinity, we have:

A = lim(n→∞) [(1/n^4) [n(n+1)/2]^2]

= lim(n→∞) [(n^2(n+1)/2)^2 / n^4]

= lim(n→∞) [(n^4 + 2n^3 + n^2) / 4n^2]

= lim(n→∞) [(1 + 2/n + 1/n^2) / 4]

= (1 + 0 + 0) / 4

= 1/4.

Therefore, the expression for the area under the curve y = x^3 from 0 to 1, as a limit, is A = 1/4.

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Answer:

3 out of 5

Step-by-step explanation:

it says it in the question so say the max games is 6 one part 1 less as max witch is the motorcycle-racing games if it only has 3 then its really just 3 out of 5 so really that should be it. im not 100% sure so if im wrong please tell meme

Answer:

80,94º

Step-by-step explanation:

What I've done is, first draw a triangle with a 90º angle and write down the height (324m) and the tourist's distance (100m).

So I calculated the tangent of the angle of the tourist.

The formula is tan=Oposite side/adjacent

\(tan=\frac{opposite side}{adjacent}\)

\(tan=\frac{324}{100} =3.24\)

And now with your calculator you press "shift" and "tan". Then introduce 3,24 and it will give you the result (80,94º).

I hope it helped.

Answer: 16.81

All the side lengths of the square are equal. And squares have 4 sides so if we just divide the perimeter by 4 then we can know how much each side length is.

16.4 / 4

4.1

Ok so each side length is 4.1 ! Now to find the area we just multiply the number twice.

4.1 * 4.1

16.81

There you go! We did it.

Now, make sure to hit the Brainliest button if I am correct!

Answer:

Step-by-step explanation:

The dimension of the basis is {[1 0 0 2], [-1 1 0 0]}.

To find a basis for the subspace S = span {[1 -1 0 2], [3 -5 4 8], [0 1 -2 -1]}, we can use the same method as in the example. First, we put the vectors in a matrix and row-reduce it:

[1 -1 0 2]
[3 -5 4 8]
[0 1 -2 -1]

R2 - 3R1 -> R2
R3 -> R3 + 2R1

[1 -1 0 2]
[0 -2 4 2]
[0 1 -2 -1]

-1/2R2 -> R2

[1 -1 0 2]
[0 1 -2 -1]
[0 1 -2 -1]

R3 - R2 -> R3

[1 -1 0 2]
[0 1 -2 -1]
[0 0 0 0]

We can see that the last row is all zeros, so we have only two pivots and one free variable. This means that the dimension of the subspace S is 2. To find a basis, we can write the pivots as linear combinations of the original vectors:

[1 -1 0 2] = [1 0 0 2] + [-1 1 0 0]
[0 1 -2 -1] = [0 1 -2 -1]

Therefore, a basis for S is {[1 0 0 2], [-1 1 0 0]}.

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a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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We can use the following identity to solve the exercise:

In this case, we have:

Therefore, the exact value of the given expression is -1.

Answer:

v = 200 m/s

Step-by-step explanation:

The formula for the speed of a tsunami in deep water is given by :

\(v=\sqrt{gh}\)

Here,

g is acceleration due to gravity

h is the depth of the ocean in meters.

We need to find the speed at which the tsunami that started with an earthquake in Sumatra struck Sri Lanka about 1550 km away. The Bay of Bengal is 4 km (4000 m) deep.

It means we need to find v if h = 4000 m

So,

\(v=\sqrt{10\times 4000}\\\\v=200\ m/s\)

So, the speed of the tsunami is 200 m/s.

Answer:

its ASA

Step-by-step explanation:

can someone please answer my question from my profile?

Answer:

AAS

Step-by-step explanation:

In addition to the side and angle given, there is another angle shared, which are the vertical angles. .

By AAS, (non-included side) they are congruent

Constants : 1 (the only constant term is 2)

Variables : 2 (x and y)

Terms : 3 ( x, y and 2)

Degree of term : 1

Total surface area of cylinder is 303.34 \(cm^{2}\)

A cylinder is a 3D solid shape made up of two bases that are parallel and identical and are connected by a curved surface. These bases resemble spherical disks. The axis of the cylinder shape is a line drawn through the center or connecting the centers of two circular bases.

The surface area of a cylinder is

SA = \(2\pi r^{2}\) + 2πrh

where:

r = radius

h = height

This formula comes from adding the areas of the surfaces of the cylinder.  It has two flat circular faces and a rounded face.

If we cut the cylinder from the circular face symmetrically, the surface area for one piece will be

SA = 2[\(\frac{\pi r^{2} }{2}\)]  +  (\(\frac{2\pi r}{2}\))h  +  2rh

We will have 2-half flat circular faces, a flat rectangular surface, and half of the rounded surface.

Simplify the SA formula.

SA = \(\pi r^{2}\) + πrh + 2rh

SA = r(πr + πh + 2h)

Substitute the values into this formula.

SA = 3(3π + 8π + (2×8))

SA = 3(11π + 16)

SA = 33π + 48

SA = 151.67\(cm^{2}\)

Since we have 2 pieces, multiply this result by 2.

2(151.67\(cm^{2}\)) = 303.34\(cm^{2}\)

Total surface area is 303.34\(cm^{2}\)

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No, there is only one outlier at 58 minutes.

An observation that differs abnormally from other values in a population-based random sample is referred to as an outlier. In a way, this definition defers to the analyst's (or a consensus process') judgment as to what constitutes aberrant behavior. It is vital to define typical observations before distinguishing aberrant ones.

A data point is considered an outlier if it is more than 1.5 times the IQR below the first quartile or more than 1.5 times the IQR above the third quartile, according to the general criterion for utilizing it to compute outliers. The first and third quartile percentiles must be known in order to compute the IQR.

The time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list.

9, 17, 20, 21, 27, 29, 30, 31, 32, 35, 58

One of the students who completed the puzzle claimed that there were two outliers in the data set. Based on the 1.5×IQR rule for outliers, is there evidence to support the student's claim?

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An equation that mode the relationship between thee two variable is y=2x+3 .

Let x represent the number of 6-month period worked

Let y represent the total number of paid vacation day

According to the question,

When he started work, he was given three paid day of vacation. For each six-month period he pay at the job, his vacation is increased by two day.

Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed. x=8 y=2*8+3 y=19

An equation that mode the relationship between thee two variable is y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start).

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Answer:

the x coordinate is 5

the y coordinate is 4

Step-by-step explanation:

the x coordinate would be wherever the dot is on the horizontal line

the y coordinate would be wherever the dot is on the vertical line

Answer:

1. y= 3x+1, 2. y= x+6, 3. car A

Step-by-step explanation:

the equation is the rule that is followed to find y (the distance the car traveled)

Car A

find a rule to get from x= 2 to y= 7 that also works to get from x= 3 to y =10 and so on... and will find that 3x +1 works for all.

the rule ( the equation) is y= 3x + 1 ; (because 7= 3*2 +1, 10 = 3*3 +1,...)

Car B

y= x+6; (because 6= 0+6, 11= 5+6, ...)

faster means speed so a higher miles per hour rate so that will be represented by the slope of the line the equation gives

y=mx +b is the equation of a line where m -is the slope

y=3x+1 has the slope 3 (car A)

y= x+6 has the slope 1 (car B)

3 > 1 so car A is faster

The number of combinations by a TV and a VCR can select is 28 thus option (d) is correct.

When the order of the arrangements counts, a permutation is a numerical approach that establishes the total number of alternative arrangements in a collection.

The number of alternative configurations in a collection of things when the order of the selection is irrelevant is determined by combination.

As per the given,

Number of types of TV = 7

Number of types of VCR = 4

Number of possible combination = 7 x 4 = 28

Hence "There are 28 possible combinations that a TV and a VCR can choose from".

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Answer:

f=1.5⋅d or equivalent. The bag will last 140 days since 210÷1.5=140.

Step-by-step explanation:

The ratio of corresponding sides for the given similar triangles is 2/5.

In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:

a. 10

This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.

b. 4/5

This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.

To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.

Dividing 4 and 5 by 1, we get:

4 ÷ 1 = 4

5 ÷ 1 = 5

Therefore, the simplified ratio is 4/5.

c. 10/85

This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.

Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.

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The data provide convincing statistical evidence that there is an association between age group and consumption of fruits and vegetables for adults in the United States.

To determine if the data provide convincing statistical evidence that there is an association between age group and consumption of fruits and vegetables, we can perform a chi-squared test of independence. This test assesses whether there is a statistically significant association between two categorical variables.

The null hypothesis for this test is that there is no association between age group and consumption of fruits and vegetables, and the alternative hypothesis is that there is an association between the two variables.

Using the given data, we can calculate the expected frequencies for each cell under the assumption that there is no association between age group and consumption of fruits and vegetables. We can then use these expected frequencies to calculate the chi-squared test statistic and determine the p-value.

Performing the chi-squared test of independence with the given data yields a test statistic of 300.96 and a p-value of less than 0.0001. This indicates that there is a statistically significant association between age group and consumption of fruits and vegetables.

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The image of the complete question is given in the attachment.

An equation in reference to a circle refers to the mathematical expression that defines the set of points that form the circle in a coordinate plane.

The standard form of a circle's equation is (x-h)² + (y-k)² = r², where (h, k) represents the coordinates of the circle's center and r is the radius.

The equation is derived from the Pythagorean theorem, as the distance between any point (x, y) on the circle and the center (h, k) is equal to the radius.

By solving for the distance using the distance formula, we arrive at the circle's equation. In the special case where the center lies at the origin (0, 0), the equation simplifies to x² + y² = r².

Using this equation, we can determine various properties of the circle, such as diameter, its area and circumference. Additionally, we can analyze the relationship between the circle and other geometric shapes, including lines and other circles, by examining the intersections of their respective equations.

In summary, a circle's equation is a powerful tool in understanding its geometric characteristics and relationships with other shapes in the coordinate plane.

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Answer:

403

Step-by-step explanation:

divide 2.75 and 1,1109 and you will get your answer

Answer:

Step-by-step explanation:

Is the equation y=(6/5)*2?  

Or y=(6/5)x^2?

=====

For y=(6/5)*2

      y = 12/5, or

      y = 2+(2/5)

------------

For  y=(6/5)x^2

    There is no one answer unless either y or x are identified.

Answer:

f(-2)=31

Step-by-step explanation:

f(x)=-x²-8x+19

f(-2)=-(-2)²-8(-2)+19

=-(-2*-2)+16+19

=-4+35

=31

f(-2)=31√

Answer:

$300

Step-by-step explanation:

15x5=75

75x4=300

The money i started with would be 300 dollars.

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We have been given that After I had spent 1/4 of my money and then spent 1/5 of what was left, I had £15 remaining.

Let the total money we have will be x.

1/4 x = y

Then;

y (1/5) = 15

Substitute;

1/4 x (1/5) = 15

x = 15 (20)

x = 300

Therefore, the money i started with would be 300 dollars.

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If speed is important and the array is large, the a. Binary search algorithm should be used. This algorithm is designed to efficiently search through sorted arrays by repeatedly dividing the search interval in half.

It has a time complexity of O(log n), which means that as the size of the array increases, the time it takes to search for an item will not increase at the same rate.
On the other hand, ascending bubble sort and other sorting algorithms such as selection sort and insertion sort have a time complexity of O(n^2), which means that as the size of the array increases, the time it takes to sort the array will increase exponentially. Therefore, these algorithms are not efficient for large arrays and should not be used if speed is important.
In summary, when dealing with large arrays and speed is important, binary search is the best algorithm to use for searching, while ascending bubble sort and other sorting algorithms with a time complexity of O(n^2) should be avoided.

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