Write the correct measurement for A-F (Example 2.2, 5.9, 9)

This table shows the frequency of each number obtained after throwing the die 35 times

To prepare a frequency table based on the numbers obtained from throwing a die 35 times, we can list the numbers from 1 to 6 and count the frequency of each number.

Numbers: 1, 2, 3, 4, 5, 6

Frequency: 5, 14, 6, 4, 5, 1

Based on the given numbers, the frequency table would look like this:

Number   | Frequency

1                      5

2                     14

3                      6

4                      4

5                      5

6                       1

This table shows the frequency of each number obtained after throwing the die 35 times.

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Given:

The fractions are:

\(\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}\)

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is \(\dfrac{6}{5}\).

\(\dfrac{6}{5}=\dfrac{5+1}{5}\)

\(\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}\)

\(\dfrac{6}{5}=1+\dfrac{1}{5}\)

Therefore, the given fraction \(\dfrac{6}{5}\) can be written as \(1+\dfrac{1}{5}\).

The given fraction is \(\dfrac{11}{7}\).

\(\dfrac{11}{7}=\dfrac{7+4}{7}\)

\(\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}\)

\(\dfrac{11}{7}=1+\dfrac{4}{7}\)

Therefore, the given fraction \(\dfrac{11}{7}\) can be written as \(1+\dfrac{4}{7}\).

The given fraction is \(\dfrac{21}{4}\).

\(\dfrac{21}{4}=\dfrac{20+1}{4}\)

\(\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}\)

\(\dfrac{21}{4}=5+\dfrac{1}{4}\)

Therefore, the given fraction \(\dfrac{21}{4}\) can be written as \(5+\dfrac{1}{4}\).

The measure of m ∠ABC is 50°.

In Euclidean geometry -

an angle is the figure formed by two rays known as the sides of the angle and sharing a common endpoint known as the vertex of the angle.

Given is a triangle as shown in the image.

We can write -

∠ACD = 180 - (60 + 40)

∠ACD = 80                                  ...... Eq { 1 }

Now, -

∠ABC + (180 - ∠ACD) + (90 - ∠DAC) = 180

∠ABC + 100 + 30 = 180

∠ABC = 50°

Therefore, the measure of m ∠ABC is 50°.

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at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}\)

\(A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill\)

Answer:

A or D

Step-by-step explanation:

I cant totally remember, but a and d make sense. sorry, I learned about this in 6th

Answer:

Jenn is correct, as the function has two x-intercepts, at x = -3 and x = 3.

Step-by-step explanation:

x-intercepts of a function:

The x-intercepts of a function are the values of x for which f(x) = 0.

In this question:

\(f(x) = x^2 - 9\)

x-intercepts:

\(x^2 - 9 = 0\)

\(x^2 = 9\)

\(x = \pm \sqrt{9}\)

\(x = \pm 3\)

Jenn:

Jenn is correct, as the function has two x-intercepts, at x = -3 and x = 3.

In the proportion (5x + 1):3 = (2x + 2):7, the value of x is -1/29.

In the proportion (6x):(4x) = 7, there is no value of x that satisfies the proportion.

To find the value of x in the given proportions, let's solve them one by one:

(5x + 1) : 3 = (2x + 2) : 7

To solve this proportion, we can cross-multiply:

7(5x + 1) = 3(2x + 2)

35x + 7 = 6x + 6

Subtracting 6x from both sides and subtracting 7 from both sides:

35x - 6x = 6 - 7

29x = -1

Dividing both sides by 29:

x = -1/29

Therefore, the value of x in the first proportion is -1/29.

(6x) : (4x) = 7

To solve this proportion, we can simplify the left side:

6x / 4x = 7

Dividing both sides by 2x:

3/2 = 7

This equation is not true, as 3/2 is not equal to 7.

Therefore, there is no value of x that satisfies the second proportion.

In summary, the value of x in the proportion (5x + 1) : 3 = (2x + 2) : 7 is -1/29, and there is no value of x that satisfies the proportion (6x) : (4x) = 7.

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Answer: The solution  is \((-2,\frac{5}{3} )\)

Step-by-step explanation:

it already gives you the solution for x so just plot it into the equation to solve for y.

y= \(\frac{2}{3} *\frac{-2}{1}+3\)  

y= \(\frac{-4}{3}+\frac{3}{1}\)

y= \(\frac{5}{3}\)

Answer: -2 5/3

Step-by-step explanation:

y= 2/3*-2/1+3

y= -4+3/1

-2 5/3

Answer:

Step-by-step explanation:

Total number of students:

A.

B.

C.

D.

Answer:

196, obtuse

Step-by-step explanation:

To go around a point, you would go 360 degrees

Let x be the third angle

113+51+x=360

164+x = 360

x = 360-164

x=196

Since the angle is bigger than 180 the angle is obtuse

Answer:

i think it’s D

i hope i help you but if nop DO NOT FORGET STAY SAFE AT HOME

Answer:

Step-by-step explanation:

Answer: 3.5%

Step-by-step explanation:

given data:

france production in 2000 = 6.122million pounds of wheat.

world production = 176 million pounds of wheat.

Solution:

france contribution from the workd total production in year 2000.

= P/100 = A/B

= 6.122/176 * 100

= 3.5%

france percentage contribution to the world total in the year 2000 was 3.5% of the world total.

Answer:

B)

Step-by-step explanation:

3.0 / .1 = 0.3

Answer:

3×1/10=0.3 in decimals.

Step-by-step explanation:

3×1÷10

3÷10

0.3

Answer: x=14 y=10

Step-by-step explanation:

Using simultaneous equations, during the dinner to raise money for a children's museum, 90 tickets were sold.

Simultaneous equations are two or more equations solved concurrently or at the same time.

Simultaneous equations are also called a system of equations.

The cost of one-person ticket = $200

The cost of two-people ticket = $350

The total number of attendees at the dinner = 130

The total ticket sales = $24,000

Let number of one-person ticket = x

Let number of two-people ticket = 2y

x + 2y = 130... Equation 1

200x + 250y = 24000... Equation 2

Multiply Equation 1 by 200:

200x + 400y = 26000... Equation 3

Subtract Equation 2 from Equation 3:

200x + 400y = 26000

-

200x + 350y = 24000

50y = 2000

y = 40

x = 130 - 2y

=  130 - 80

= 50

Thus, the number of tickets sold at the dinner was 90.

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Answer:

point ??????? I think not sure

Answer:

C.

Step-by-step explanation:

Answer:

The blue dot is -19

Step-by-step explanation:

Since every 2 ticks are worth 6 (|-10|-|-4|=6), then one tick is worth 3.

We are going backward, so we can count backward.

We have to go down 3 ticks, so -10-3=-13; -13-3=-16; -16-3=-19.

The blue dot is -19

Answer: The blue dot equals to -19.

Step-by-step explanation:

On the number line, there are the numbers -10 & -4.

-7 would fit in the middle of them. That means the number line goes by minus 3.

Count -10 , -13, -16, then you get on the the blue dot which is -19.

Therefore, -19 is the answer.

Answer:

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

The guy from above said so

Answer:

You could say something like, "My servey answers I got were a little bit different then the results in the artical. This may be because the pople I asked have different oppinions on this subject. Also. . . "Insert Something About The Margin Errors Here". . .That is how my results compare to the results in the passage and why they are different.

Step-by-step explanation:

I'm not sure if this is the format u want though.

Using the t-distribution, the 99% confidence intervals for the given standard deviation are given as follows: (5053.39 , 4126.61)

Given that,

Number of college students = 23

A simple random sample with a mean = $4590

A simple random sample with a standard deviation = $860

The t distributions is wide (has thicker tailed) for smaller sample sizes, reflecting that s can be smaller than σ. The thick tails ensure that the 80%, 95%, 99% confidence intervals are wider than those of a standard normal distribution (so are better for capturing the population mean).

The confidence interval is:

= μ ± \(t\frac{s}{\sqrt{n} }\)

In which:

μ is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 99% confidence interval, with 23 - 1 = 22 df,

Upon using a t -table or a calculator, we see that the critical t -value for this 99% confidence interval is t0.005=2.581

The parameters are:

μ = $4590

n = 23

Hence, with s = 860, the bounds of the interval are:

= μ ± \(t\frac{s}{\sqrt{n} }\)

= 4590 ± 2.581 \(\frac{860}{\sqrt{23} }\)

= 4590 ± 2.581 \(\frac{860}{4.79}\)

= 4590 ± 2.581 (179.54)

= 4590 ± 463.39

Then,

= 4590 + 463.39   ,      4590 - 463.39

= 5053.39              ,       4126.61

Therefore,

Using the t-distribution, the 99% confidence intervals for the given standard deviation are given as follows: (5053.39 , 4126.61)

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a) The inequality for the expression 2z + 9 is 2z + 9 > 13.

b) The inequality for the expression 3(z - 4) is 3z - 12 > -6.

c) The inequality for the expression 4 + 2z is 4 + 2z > 8.

d) The inequality for the expression 5(3z - 2) is 15z - 10 > 20.

a) To write an inequality for the expression 2z + 9, we can multiply the given inequality z > 2 by 2 and then add 9 to both sides of the inequality:

2z > 2 * 2

2z > 4

Adding 9 to both sides:

2z + 9 > 4 + 9

2z + 9 > 13

Therefore, the inequality for the expression 2z + 9 is 2z + 9 > 13.

b) For the expression 3(z - 4), we can distribute the 3 inside the parentheses:

3z - 3 * 4

3z - 12

Since we are given that z > 2, we can substitute z > 2 into the expression:

3z - 12 > 3 * 2 - 12

3z - 12 > 6 - 12

3z - 12 > -6

Therefore, the inequality for the expression 3(z - 4) is 3z - 12 > -6.

c) The expression 4 + 2z does not change with the given inequality z > 2. We can simply rewrite the expression:

4 + 2z > 4 + 2 * 2

4 + 2z > 4 + 4

4 + 2z > 8

Therefore, the inequality for the expression 4 + 2z is 4 + 2z > 8.

d) Similar to the previous expressions, we can distribute the 5 in the expression 5(3z - 2):

5 * 3z - 5 * 2

15z - 10

Considering the given inequality z > 2, we can substitute z > 2 into the expression:

15z - 10 > 15 * 2 - 10

15z - 10 > 30 - 10

15z - 10 > 20

Therefore, the inequality for the expression 5(3z - 2) is 15z - 10 > 20.

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The first ten terms of the Lucas sequence are 2, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843.

The Lucas sequence or Lucas series are an integer sequence named after the mathematician francois Edouard Lucas, which are similar to the Fibonacci numbers, each Lucas number is defined to be the sum of its two immediate previous terms, thereby forming a fibonacci integer sequence.

Now, the sequence of first 10 numbers of Fibonacci series are-

0, 1, 1 ,2, 3, 5, 8, 13, 21, 34

which are defined as set of integers that starts with zero, followed by a one,then by another one and then by series of steadily increasing numbers,The sequence follow the rule that each number is equal to the sum of preceding two numbers.

And the sequence of Lucas sequence is -

2, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843.

which is definedas  the sum of its two immediate previous terms.

The Lucas number may thus be defined as follows;

Ln =    \(\left \{ {{2} ; if n= 0 \atop {1}; if n = 1} \right.\)

Here we can see that Lucas series starts with 2 and 1 whereas Fibonacci series starts with 0 and 1.

Hence,The first ten terms of the Lucas sequence are 2, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843.

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4:15

..............

4/15 = 4:15

Given data:

The given amount Mary got per hour is A=$12 .

The total hours Mary works is H=10 hours.

The percentage of commission Mary got is P=10%=0.1.

The sale amount is S=$1,500.

The expression for the Money earned by Mary is,

Substitute the given values in the above expression.

Thus, the amount earned by Mary is $270, so option (D) is correct.

The highest height for the daily rainfall were for 5 and 6 inches

Dot plots are used to present data in the form of points or small circles. It is similar to a simplified histogram or bar graph in that the height of the bar made up of points represents the numerical value of each variable. Dot plots are used to represent small amounts of data.

From the given dot plot, we see the number of times for each height of rainfall.

Thus, we see that the highest number of times of rainfall height was from that of 5 and 6 inches.

Thus, we conclude those were the highest heights for the daily rainfall.

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