write one general properties of non contact force​

Answer:

It is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle is not constant

Explanation:

The motion of a particle under constant acceleration, 'a', is be given by the following kinematic equations;

v² = u² + 2·a·s

v = u + a·t

Where;

v = The final velocity of the particle

u = The initial velocity of the particle

a = The acceleration of the particle

s = The distance through which the particle travels

t = The time of motion of the particle

By simplifying the above equation, we have;

v² - u² = 2·a·s

(v² - u²)/(2·a) = s

(v - u) × (v + u)/(2 × a) = s

((v - u)/a) × ((v + u)/2) = s

From v = u + a·t, we have;

t = (v - u)/a

∴ ((v - u)/a) × ((v + u)/2) = t × ((v + u)/2) = s

∴ ((v + u)/2) = s/t

The average velocity = (Total distance traveled by the particle) ÷ (The time of travel of the particle)

∴ The average velocity = s/t = ((v + u)/2) = Half the sum of the initial and final velocity

However, it is not still true that the average velocity of the particle is equal to half the sum of the initial and final velocities when the acceleration of the particle, 'a', is not constant, as the velocity time graph is no longer a straight line graph and the distance traveled by the particle, 's', which is the area under the velocity time graph, 'A', (given by the sum of area of the triangle and the rectangle given by the area under straight line graph for constant velocity) cannot be given directly by the product of the time and the average velocity.

" 50 W " means " 50 Watts "  or  " 50 Joules per second ".

(500,002 J) / (50 J/sec)  =  10,000.04 seconds

(That's 2 hours 46 minutes 40.04 seconds.)

If the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.

The gravitational force between two objects is determined from Newton's second law of universal gravitation.

F = GmM/R²

where;

when the distance halved

F = GmM/(0.5R)²

F = GmM/(0.25R²)

F = 100GmM(25R²)

F = 4GmM/R²

Fnet = 4F

Thus, if the spaceship stops halfway between the planet and point P, the net gravitational force is four times as great.

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The correct answer to the question is option D (It increases when the planet approaches the sun, and decreases when it moves farther away).

Rotational kinetic energy (K) of an object is given by:

K = 1/2 Iω²

where, I = Moment of inertiaω = Angular velocity of the object.

A planet orbits the Sun in an elliptical orbit. The gravitational force acting between the Sun and the planet is known as centripetal force. This force is responsible for keeping the planet in a circular orbit around the Sun. Neglecting frictional effects, the total mechanical energy of the planet in an elliptical orbit remains constant.

However, the kinetic energy (K) and potential energy (U) vary with distance.

Let's say that when the planet is closest to the sun, its distance is rmin. Similarly, when the planet is farthest away from the Sun, its distance is rmax. At the closest distance to the Sun (r = rmin), the kinetic energy of the planet is minimum. This is because the planet moves the slowest at this point. When the planet moves away from the Sun, it moves faster and its kinetic energy increases.

The kinetic energy is maximum when the planet is farthest away from the Sun (r = rmax). As the planet continues to move away from the Sun, its speed decreases and so does its kinetic energy.

Therefore, the kinetic energy of the planet increases when the planet approaches the Sun and decreases when it moves farther away from the Sun.

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Answer:

the answer is letter D.

Explanation:

i hope this is help

Answer:

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Explanation:

Answer: 40.311 m

Explanation:

Given

Ant walks 15 m east

then 40 m North and finally 20 m west

from the figure, ant is 40 m North and 5 m west

Using Pythagoras, we can write

\(\Rightarrow d=\sqrt{40^2+5^2}\\\Rightarrow d=\sqrt{1625}=40.311\ m\)

Answer:

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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

\(B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }\)

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

\(B(0) = \frac{\mu_{o} i}{2R}\)

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

\(\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}\)

\(2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }\)

\(4R^{6} = (r^{2} +R^{2} )^{3}\)

\(r^{2} =0.587R^{2}\)

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

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280N(Newton) of force would it take to push another, larger friend who has a mass of 70g to accelerate at the same rate of 4 m/s².

A force is an influence that has the power to alter an object's motion. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull.

A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.

Force = Mass * Acceleration

          = 70 g * 4

          = 280 Newton.

Therefore, 280N(Newton) of force would it take to push another, larger friend who has a mass of 70g to accelerate at the same rate of 4 m/s².

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Answer:

Explanation:

57.8 m/s

The heaviest bowling ball that will float in a fluid of specific gravity is 77.1066N

r = Radius of ball = 0.134 m

ρ = Density of fluid =  1.1× \(10^{3}\)(Assumed)

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of ball

V = Volume of  ball = 4/3 π \(r^{3}\)

The weight of the bowling ball will balance the buoyant force

W = Fb

mg = V ρg

m = Vρ

m = 4/3 π 0.134^3 ×  1.1× \(10^{3}\)

m = 7.156 kg

The mass of the bowling ball will be  7.156 kg

Weight will be   7.156 × 9.81 = 77.1066N

A measurement of a substance's density in relation to water's density is its specific gravity, which is more officially known as relative density. In general, specific gravity is calculated for solids and liquids in respect to water in its densest condition (at a temperature of 4 Celsius or 39.2 Fahrenheit), and for gases in proportion to air at room temperature. It is not stated with units because it is a ratio. SG or Sp. Gr. are abbreviations for specific gravity.

Temperature and air pressure affect how dense an object is. For precise measurements of specific gravity, it is necessary for scientific reasons to regulate and display the temperature and pressure.

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Magnesium has two valence electrons in its outermost energy level. Therefore, option (b) is correct.

Alkaline earth metals are the elements of Group 2 in the modern periodic table. These metals include elements which are Beryllium, Magnesium, calcium, strontium, Barium, and Radium

The alkaline earth metals contain smooth, silver metals with a less metallic character than the alkali metals of group 1.  The general electronic configuration of alkaline earth metals or group 2 elements is ns². Therefore, all alkaline earth metals carry two electrons in their valence shell. They easily lose electrons to produce compounds through ionic bonds.

While Cesium, Boron, and Argon have 1, 3, and 8 electrons in their valence or outermost shell. As magnesium is alkaline earth metal so it has two electrons in its valence shell.

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Answer:

Kinda? Depends what the question is fully asking

Explanation:

Acceleration is a change in velocity. So I guess if the velocity of something is -2 m/s and its positively accelerating at a value of +1 m/s, then that means every second its velocity changes by +1m/s.

So that -2 m/s thing after one second will be going -1 m/s.

After another second it'll be going 0 m/s.

After another itll be going +1 m/s and so on.

So at one point for a brief moment, it can have an acceleration but be at 0 m/s velocity.

For a successful final touch of a construction venture, key stakeholders consisting of the consumer/proprietor, architect/layout group, and creation contractor are crucial. Risk management is necessary to perceive and mitigate capacity risks, ensuring project success and minimizing disruption

The 3 important stakeholders for the development of a new mall in Alexandra are:

During the construction of an avenue in a particular network, the network is represented by:

Local Authorities: The local authorities, which include the municipal or city council, represent the community's pastimes. Their duties consist of engaging with the network to apprehend their needs and issues associated with the road construction project.

Before any sort of Civil Engineering mission is executed, the subsequent steps want to be taken to ensure the viability of the challenge:

The hierarchy of running for a contractor sporting out the development of a bridge typically consists of the subsequent degrees:

To draw the bar chart (also referred to as a Gantt chart) for a 50 km street creation undertaking with a duration of 10 days, the chart could represent the obligations and their respective intervals. However, a standard bar chart for an avenue creation undertaking may also include duties including surveying, excavation, laying subbase, paving, and street markings, amongst others.

The horizontal axis represents the timeline (in days), and the vertical axis represents the responsibilities. Each undertaking is represented with the aid of a horizontal bar that suggests its length.

Question 2 (10):

2.1 Risk control is vital in a venture for the following motives:

Overall, change management is important for figuring out, analyzing, and responding to risks in a systematic and proactive manner. It enables ensuring task success by using lowering uncertainties and maximizing opportunities for task delivery within the preferred parameters.

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Energy is NEVER destroyed making this an interesting topic. In reality this energy is just isolated from that system and just changes states. You could do anything for your story, just make sure to include those points.

Hope this helped :)

To calculate the nuclear binding energy of 5525 Mn 2555 Mn, we need to use the formula E = mc^2, where E is the energy, m is the mass, and c is the speed of light.

First, we need to convert the given masses into kilograms. The atomic mass of manganese (Mn) is approximately 55.845 grams/mol. Therefore, the mass of 5525 Mn is 5525 grams/mol, which is equal to 5.525 kilograms/mol. Similarly, the mass of 2555 Mn is 2555 grams/mol, which is equal to 2.555 kilograms/mol.

Next, we calculate the energy using the formula E = mc^2. The speed of light (c) is approximately 3 x 10^8 meters/second.

For 5525 Mn:
E = (5.525 kg/mol) * (3 x 10^8 m/s)^2
E = 4.9725 x 10^17 kg * m^2/s^2

For 2555 Mn:
E = (2.555 kg/mol) * (3 x 10^8 m/s)^2
E = 2.2995 x 10^17 kg * m^2/s^2

To find the nuclear binding energy, we subtract the energy of 2555 Mn from the energy of 5525 Mn:
Nuclear binding energy = (4.9725 x 10^17 kg * m^2/s^2) - (2.2995 x 10^17 kg * m^2/s^2)
Nuclear binding energy = 2.673 x 10^17 kg * m^2/s^2

To express the answer numerically in joules, we need to convert kg * m^2/s^2 to joules. Since 1 Joule is equal to 1 kg * m^2/s^2, the nuclear binding energy is 2.673 x 10^17 Joules.

Therefore, the nuclear binding energy of 5525 Mn 2555 Mn is more than 120 Joules, specifically 2.673 x 10^17 Joules.

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Answer:

Nebulas

Explanation:

Nebulae are made of dust and gases—mostly hydrogen and helium. ... Eventually, the clump of dust and gas gets so big that it collapses from its own gravity. The collapse causes the material at the center of the cloud to heat up-and this hot core is the beginning of a star.

The pulley system to the right will be in static equilibrium at an unknown angle of 90 degrees.

An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. First, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.

The 80 N weight is fastened to a freely rotating pulley in this setup.

As a result, the cable's tension is also 80 N.

The tensions' x components must be balanced against one another:

T1x = T2x

Since T1x = T1 cos(θ) and T2x = 0 (because the cable attached to the wall is vertical), we have:

T1 cos(θ) = 0

Therefore, cos(θ) = 0, which means that θ = 90 degrees.

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Therefore, the center of mass of the system is approximately located at x ≈ 3.28 m.

The center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point at any given time where the weighted relative position of the distributed mass sums to zero.

For x-axis:

xcom=m1x1+m2x2+m3x3+...m1+m2+m3+...

For y-axis:

ycom=m1y1+m2y2+m3y3+...m1+m2+m3+...

xcom

and ycom

together will give the coordinates for the Centre of Mass of a system. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.

To find the center of mass of the system, we need to consider the masses and their respective positions. The center of mass (x_com) can be calculated using the formula:

x_com = (m1 * x1 + m2 * x2 + m3 * x3) / (m1 + m2 + m3)

where m1, m2, and m3 are the masses, and x1, x2, and x3 are the corresponding positions.

Given:

Mass 1 (m1) = 12 kg, positioned at x1 = -3 m (3 m to the left)

Mass 2 (m2) = 15 kg, positioned at x2 = 2 m (2 m to the right)

Mass 3 (m3) = 20 kg, positioned at x3 = 8 m (8 m to the right)

Substituting these values into the formula, we have:

x_com = (12 kg * (-3 m) + 15 kg * (2 m) + 20 kg * (8 m)) / (12 kg + 15 kg + 20 kg)

x_com = (-36 kgm + 30 kgm + 160 kg*m) / 47 kg

x_com = 154 kg*m / 47 kg

x_com ≈ 3.28 m

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The time T is identical to 0.50 seconds since one whole wave completes in 0.50 seconds. F = 1/D = 1/0.5 = 2 Hz, where T = 0.5 Frequency.

A wave, according to Webster's dictionary, is a perturbation or variation that gradually transfers energy from one place to another inside a medium. It can be a multiple and complex or a change in pressure, magnetic or electrical strength, electric potential, or heat.

Water moves in a circular pattern as a result of energy traveling through it, creating waves. Water does not, however, literally move in waves. Without obstruction, waves can potentially flow across the ocean, transmitting energy rather than water.

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Answer:

(1) 2.25m/s^2

(2) 45.6m

Explanation:

(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds

Therefore the average acceleration can be calculated as follows

a = 39-12/12

a = 27/12

a= 2.25m/s^2

(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds

u= 4

a= 1.2

t= 6

Therefore the distance can be calculated as follows

S= ut + 1/2at^2

= 4×6 + 1/2 × 1.2 × 6^2

= 24 + 1/2 × 1.2 × 36

= 24 + 1/2 × 43.2

= 24 + 21.6

S = 45.6m

Hence the butterfly travels at 45.6m

Answer:

A

Explanation:

You have to give energy away for B. You have to think about that carefully. The CO2 starts out with a great deal of energy (mostly KE) and has to slow down to go from gas to a solid. Not B

In general C is the same way. Water has more energy than ice. Not C

Same principle in D.  Not D.

So it's A

Here are some ideas for setting up the barber's salon based on the size of the space and the products available: The wooden chair should be positioned in the middle of the space, facing a wall.

The barber's workspace will be this. The room's other three walls should be covered with the three enormous mirrors. This will give the impression that there is more space present and enlarge the room. The mirrors should be angled to reflect both the client in the chair and the barber's work area. Over the chair, suspend the lightbulb from the ceiling. The barber salon will be able to operate in enough lighting thanks to this.The wooden chair should be positioned in the middle of the space,  The barber can set up a white sheet or a reflecting surface to improve illumination even further.

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Answer:

4/5=n

Explanation:

hah I have the same homework :0

One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.

UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.

UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.

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To determine the forces in all the members, we have to consider as follows:

1. Draw the truss and label all the members and joints.
2. Determine the support reactions by solving the equilibrium equations (sum of vertical forces, horizontal forces, and moments should be zero).
3. Using the Method of Joints or Method of Sections, analyze each joint or section by applying the equilibrium equations.
4. For each member, calculate the force and determine if it is in tension or compression based on the direction of the force acting on the member.
5. Organize your results in a table with columns for the member label, force value, and whether the force is tension or compression.
6. Finally, show the results on the truss by indicating the force magnitudes and whether each member is in tension or compression.

Remember that for a more accurate answer, I need more details about the truss you are analyzing.

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Answer:

After the dielectric is inserted the capacitance is increased hence the stored energy is also increased . It may be noted here that since voltage between the capacitor V0 is constant the electric field between the plates also remains constant .

We must first determine the amount of force needed to lift the boxes against gravity. The weight of the boxes is calculated as follows: 30 boxes x 6 kg/box = 180 kg

Work = Force x Distance Work = 1765.8 N x 1.5 m Work = 2648.7 Joules Force = Weight x Gravitational Acceleration Force = 180 kg x 9.81 m/s2 Force = 1765.8 N

The total work required to raise thirty 6 kilogram boxes onto a 1.5 m high shelf is therefore 2648.7 Joules.

Hence, the gravitational pull between two objects grows as their respective masses do as well. The force of gravity between two objects is equal to their respective masses multiplied by two. To put it another way, the gravitational potential energy directly relates to how high an item is above the earth. Consequently, an item needs be elevated higher in order to enhance its gravitational potential energy. The gravitational potential energy increases with height.

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Answer:

600 Coulomb

Explanation:

Electric Current refers to the charge passing through unit cross section of a wire per second.

Current ( C / sec) = 5A = 5C / sec

So, 5C charge passes through the wire in one second, then, amount of charge passing through a cross section of the wire in 120 seconds is :

5C * 120 = 600 Coulumb