write each mixed number as an improper fraction :

2 3/7​

When procedures are mandated by third party payers, the modifier -32 (mandated services) is used. This modifier is used to indicate that a service or procedure is mandated by a third party payer, such as Medicare or Medicaid.

It is used to ensure that the service or procedure is reimbursed appropriately and to avoid denials. The use of the -32 modifier is important to accurately reflect the requirements of the payer and to avoid any potential billing or coding errors. It is important to check with the specific payer to determine if the use of this modifier is required for a particular service or procedure.

When procedures are "mandated" by third-party payers, you would use the modifier -32. This modifier indicates that a service or procedure is being performed due to specific requirements from a third-party payer. It helps to provide the necessary information for reimbursement and ensures that the claim is processed correctly by the payer. Remember to attach the modifier -32 to the appropriate procedure code on the claim form when submitting it to the third-party payer. This will help avoid any potential delays or denials in payment due to insufficient documentation.

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Michael needs to analyze the population data, demographics of the city, and the competition in the area to determine whether or not to open a new store.

Michael is trying to determine where to open two new store locations. He has population data to determine the amount of revenue he will receive for each location.

He is charged a $1000 fee for opening a new store at a certain location. However, he is unsure whether the population of the city would be large enough to warrant opening a new store at that location.

The first step that Michael needs to take is to analyze the population data that he has.

Based on the population data, he needs to make an informed decision about whether or not to open a new store at that location. This would require him to take into consideration the average income of the population as well as the demographics of the city.

Another important factor that Michael needs to take into consideration is the competition in the area. If there are already several stores in the area, then opening a new store might not be a good idea.

This is because the competition would be too high and he would not be able to generate enough revenue to make up for the cost of opening a new store.

However, if there are no stores in the area, then Michael might consider opening a new store. This would require him to invest a significant amount of money, but he could also generate a significant amount of revenue in return.

Additionally, he needs to take into consideration the cost of opening a new store and whether or not he can generate enough revenue to make up for that cost.

Overall, Michael needs to carefully analyze all the data that he has before making an informed decision about where to open new store locations.

In conclusion, Michael needs to analyze the population data, demographics of the city, and the competition in the area to determine whether or not to open a new store. If the population is large enough and there is no competition in the area, then he should consider opening a new store. However, if there is already a significant amount of competition in the area, then he should avoid opening a new store.

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The best linear approximation to the function f(x) = e^x near x = 0 is L(x) = x + 1.

The given function is f(x) = e^x near x = 0.

To find the best linear approximation, L(x), we use the formula:

L(x) = f(a) + f'(a)(x-a),

where a is the point near which we are approximating.

Let a = 0, so that a is near the point x = 0.

f(a) = f(0) = e^0 = 1

f'(x) = d/dx (e^x) = e^x;

so f'(a) = f'(0) = e^0 = 1

Substituting these values into the formula: L(x) = 1 + 1(x-0) = x + 1

Therefore, the best linear approximation to f(x) = e^x near x = 0 is L(x) = x + 1.

For instance, linear approximation is used to approximate the change in a physical quantity due to a small change in another quantity that affects it.

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Answer:

1. D

2. A

3. B

4. C

5. i am not sure

Step-by-step explanation:

Hope This Helps!!!

The correct option is A. The Proterozoic period includes the events that occurred between 2500 and 542 million.

Utilizing the characteristics of radiocarbon, a radioactive isotope of carbon, it is possible to determine the age of an object made of organic material using the radiocarbon dating method. Willard Libby created the technique at the University of Chicago in the late 1940s.

Here, we have

Given:

Following statements and we have to find the example of numerical date.

There are two types of dating that we usually see. First is relative dating and second is numerical dating. Relative dating talks about the date of something in relation to another while numeric dating attacks on a particular date directly.

Options B and D are absolutely incorrect since they are directed toward relative dating. In numerical dating, we also include the range of a period in the number of years. Hence option A is correct. Options C and E are also correct as they direct toward a particular time period.

Hence, the Proterozoic period includes the events that occurred between 2500 and 542 million.

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Question: Which of the following is an example of a numerical date? CHOOSE ALL THAT APPLY.

A. The ash layer is younger than the shale.

B. The caldera formed before the Holocene.

C. The limestone formed at the end of the Ordovician.

D. The sandstone is older than the Mesozoic basalt.

E. The pumice is 43 million years old.

Answer:

1.6(10-5)2= 1.6(5)2= (8)(2)=16

Step-by-step explanation:

Answer:

40

Step-by-step explanation:

     Substitute x = 10 and y = 5 in the expression.

1.6(x - y)² = 1.6(10 - 5)²

               = 1.6 * (5)²

               = 1.6 * 25

               = 40

Given,

The Fibonacci sequence is F(n) = F(n-1) + F(n-2).

F(8) = 21 and F(9) = 34

To find: Which of the following is true.

Solution:

In a Fibonacci series, the sum of first two terms is equal to the third term.

The next term will always be the sum of the previous two terms.

Hence, the given option D is correct.

The normal vector to the tangent plane is the opposite of this gradient, which is:

\(n = (-14e^{64}, 4, -1)\)

The gradient of the surface is given by:

∇z = ( ∂z/∂x, ∂z/∂y, ∂z/∂z )

where ∂z/∂x and ∂z/∂y are the partial derivatives of z with respect to x and y, respectively.

The gradient of the surface at that point must first be determined before we can determine the normal vector to the tangent plane of the surface \(z=7e^{x^{2} } -4y\) at the point (8, 16, 7).

Taking the partial derivatives, we get:

\(∂z/∂x = 14e^{x^{2} }\)

∂z/∂y = -4

Plugging in the values x=8 and y=16, we get:

∂z/∂x = \(14e^{(8)^2} = 14e^{64}\)

∂z/∂y = -4

Therefore, the gradient of the surface at the point (8, 16, 7) is:

∇z = ( \(14e^{64}, -4,\)∂z/∂z )

The last component of the gradient (∂z/∂z) is always equal to 1, so we have:

∇z = ( \(14e^{64},\) -4, 1 )

This gradient is perpendicular to the tangent plane of the surface at the point (8, 16, 7). Therefore, the normal vector to the tangent plane is the opposite of this gradient, which is:

n =\((-14e^{64}, 4, -1)\)

The component of the normal vector in the z-direction is -1, as given in the problem statement.

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The missing factor in the second equation is 1, and the completed equation is: -24y + (-5) = -4(6y + 5/4)

We know that the GCF of -24y and -20 is 4. To find the missing factor in each equation, we can divide both terms by the GCF of 4.

For the first equation, we have:

-24y = 4 * (-6y)

Dividing both sides by 4, we get:

-6y = -24/4

Simplifying, we get:

-6y = -6

Therefore, the missing factor in the first equation is -1, and the completed equation is:

-24y + 20 = -4(6y - 5)

For the second equation, we have:

-20 = 4 * (-5)

Dividing both sides by 4, we get:

-5 = -20/4

Simplifying, we get:

-5 = -5/1

Therefore, the missing factor in the second equation is 1, and the completed equation is:

-24y + (-5) = -4(6y + 5/4)

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Answer:

x = 9

Step-by-step explanation:

5x + 6 = 6x - 3

Simplify from there:

6x - 5x = 6 + 3

x = 9

To find the coefficient of the term with t^6 in the expansion of (x - 2)^12 without expanding the entire binomial, we can use the binomial theorem.

The binomial theorem states that the term at index k in the expansion of (a + b)^n can be calculated using the formula: C(n, k) * a^(n-k) * b^k. where C(n, k) represents the binomial coefficient, given by: C(n, k) = n! / (k! * (n - k)!). In this case, a = x and b = -2. We are interested in finding the term with t^6, so we need to find the k value that satisfies n - k = 6.

In the expansion of (x - 2)^12, the term with t^6 will have the following form: C(12, k) * x^(12-k) * (-2)^k. To find the k value that corresponds to t^6, we solve the equation n - k = 6: 12 - k = 6. Simplifying, we find: k = 12 - 6 = 6. Therefore, the term with t^6 in the expansion of (x - 2)^12 is given by: C(12, 6 ) * x^(12-6) * (-2)^6. C(12, 6) represents the binomial coefficient, which is calculated as: C(12, 6) = 12! / (6! * (12 - 6)!). Plugging in the values, we have: C(12, 6) = 924. Therefore, the term with t^6 in the expansion of (x - 2)^12 is: 924 * x^6 * (-2)^6. Simplifying further, we get: 924 * x^6 * 64. Finally, the simplified expression is: 59040 * x^6

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Answer:

x=−5

Step-by-step explanation:

−3x+5=20

Step 1: Subtract 5 from both sides.

−3x+5−5=20−5

−3x=15

Step 2: Divide both sides by -3.

−3x/-3 = 15/-3

\(\huge\text{Hey there!}\)

\(\large\text{-3x + 5 = 20}\\\large\text{SUBTRACT by 5 to BOTH SIDES}}\\\large\text{-3x + 5 - 5 = 20 - 5}\\\large\text{Cancel out: 5 - 5 because that gives you 0}\\\large\text{Keep: 20 - 5 because it gives you 15 and it helps us solve for x}\\\large\text{20 - 5 = 15}\\\large\text{New equation: -3x = 15}\\\large\text{DIVIDE by -3 to BOTH SIDES}\)

\(\bold{\dfrac{-3}{-3}=\dfrac{15}{-3}}\\\\\bold{Cancel\ out: \dfrac{-3}{-3}\ because\ it\ gives\ you\ 1}\\\\\bold{Keep: \dfrac{15}{-3}\ because\ it\ gives\ you\ x}\)

\(\bold{x = \dfrac{15}{-3}}\)

\(\boxed{\boxed{\bold{Answer: x = -5}}}\huge\checkmark\)

\(\large\textsf{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

The graph of the data has been plotted and attached below.

What is a graph?

A diagram or pictorial representation of facts or values that is ordered might be referred to as a graph in mathematics. The relationship between two or more items is commonly depicted by graph points.

In the question, we are given the data relating to the distance covered in the specific time duration.

Using this data, a graph has been obtained which has been attached below.

On the x - axis, time is shown and on the y - axis, distance has been shown.

Hence, the graph of the data has been plotted.

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Answer: Coordinate (1,6)

Step-by-step explanation: Because it is located on one of the corners already if you count the spaces! I hope this helped!! :D

Answer:

the person above me is right its (1,6) its the only one thats located on a corner

Step-by-step explanation:

Answer:

Use a graphing calculator.

Step-by-step explanation:

Use at least 3 points to graph.

Use a graphing calculator

The vertical asymptotes for the function f(x) = (x^2)(x-6)(x+3)^-1 are x=6 and x=-3.

The vertical asymptotes for the function f(x) = (x^2)(x-6)(x+3)^-1 are x=6 and x=-3. This is because the denominator can be factored into two linear expressions: x-6 and x+3. When either of these expressions equals 0, the fraction becomes undefined and a vertical asymptote is created. To find the asymptotes, set each linear expression in the denominator equal to 0 and solve for x. For x-6, x=6; for x+3, x=-3. Therefore, the vertical asymptotes of the function are x=6 and x=-3. When x is close to either of these values, the fraction will become very large, making the graph approach the vertical asymptotes without ever touching them.

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The limits are  `(i + (3/2)j - k)`

We need to substitute the value of t in the function and simplify it to get the limits. Substitute `π/2` for `t` in the function`lim_(t→π/2)(cos(2t)i−4sin(t)j+2tπk)`lim_(π/2→π/2)(cos(2(π/2))i−4sin(π/2)j+2(π/2)πk)lim_(π/2→π/2)(cos(π)i-4j+πk).Now we have `cos(π) = -1`. Hence we can substitute the value of `cos(π)` in the equation,`lim_(t→π/2)(cos(2t)i−4sin(t)j+2tπk) = lim_(π/2→π/2)(-i -4j + πk)` Answer: `(-i -4j + πk)` Now let's evaluate the second limit`lim_(t→ln2)(2eti6e−tj−4e−2tk)`.We need to substitute the value of t in the function and simplify it to get the answer.Substitute `ln2` for `t` in the function`lim_(t→ln2)(2eti6e−tj−4e−2tk)`lim_(ln2→ln2)(2e^(ln2)i6e^(-ln2)j-4e^(-2ln2)k) Now we have `e^ln2 = 2`. Hence we can substitute the value of `e^ln2, e^(-ln2)` in the equation,`lim_(t→ln2)(2eti6e−tj−4e−2tk) = lim_(ln2→ln2)(4i+6j−4/4k)` Answer: `(i + (3/2)j - k)`

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56 over 15

hope this help yoooooooooooooooooooo

Answer:

22/15

Step-by-step explanation:

(1/3 + 2/5) x (2 - 1/2) ÷ 3/4

=(5/15 + 5/15) x (4/2 - 1/2) ÷ 3/4

=11/15 x 3/2 ÷ 3/4

=11/15 x 3/2 x 4/3

=22/15

Hope this helps! Have a nice day!

There are 3,003 ways to select a committee of five from the 15 students in the student council.

To calculate the number of ways to select a committee of five from a group of 15 students, we can use the combination formula. The formula for combination, denoted as "n choose r," calculates the number of ways to choose r items from a set of n items without considering the order.

In this case, we want to choose a committee of five from a group of 15 students. Using the combination formula, we can calculate it as:

C(15, 5) = 15! / (5! * (15-5)!)

where "!" denotes factorial. Simplifying the expression:

C(15, 5) = 15! / (5! * 10!)

The factorial of a number is the product of all positive integers less than or equal to that number. In this case:

15! = 15 * 14 * 13 * 12 * 11 * 10!

Cancelling out the common terms:

C(15, 5) = (15 * 14 * 13 * 12 * 11) / (5 * 4 * 3 * 2 * 1)

Simplifying the expression further:

C(15, 5) = 3,003

Therefore, there are 3,003 ways to select a committee of five from the 15 students in the student council.

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Answer:

no

Step-by-step explanation:

The three angles of a triangle are 180, but the sum of the three angles in the figure is 200.so its impossible .

Answer:

=[(2

2

)

3

×3

6

]×5

6

=2

6

×3

6

×5

6

=64×729×15625

=729000000

=3

6

×10

6

=30

6

Answer:

What are the equivalent expressions?

Two expressions are said to be equivalent if they have the same value regardless of the value of the variable(s) in them.

Step-by-step explanation:

We will prove this statement using mathematical induction.

Base case: For n = 4, we have 3n = 3(4) = 12 and (n+1)! = 5! = 120. Clearly, 12 ≤ 120, so the statement is true for the base case.

Induction hypothesis: Assume that the statement is true for some non-negative integer k ≥ 4, i.e., 3k ≤ (k+1)!.

Induction step: We need to prove that the statement is also true for k+1, i.e., 3(k+1) ≤ (k+2)!.

Starting with the left-hand side:

3(k+1) = 3k + 3

By the induction hypothesis, we know that 3k ≤ (k+1)!, so:

3(k+1) ≤ (k+1)! + 3

We can rewrite (k+1)! + 3 as (k+1)(k+1)! = (k+2)!, so:

3(k+1) ≤ (k+2)!

This completes the induction step.

Therefore, by mathematical induction, we have proven that for any non-negative integer n ≥ 4, 3n ≤ (n+1)!.

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Answer:

(0, 5 )

Step-by-step explanation:

The y- intercept is where the function crosses the y- axis.

This occurs when x = 0 , thus

From the table when x = 0 , f(x) = 5 , thus

y- intercept is (0, 5 )

y- intercept is (0, 5 )

If we have coins = [1, 2, 5] and amount = 5, then the function should return 4, because there are four combinations of coins that make up an amount of 5: [1, 1, 1, 1, 1], [1, 1, 1, 2], [1, 2, 2], and [5].

This problem can be solved using dynamic programming. Let's define dp[i][j] as the number of combinations of coins using the first i coins to make up an amount j. Then we can use the following recurrence relation:

dp[i][j] = dp[i-1][j] + dp[i][j-coins[i]]

The first term on the right-hand side of the equation corresponds to the case where we don't use the i-th coin, while the second term corresponds to the case where we use the i-th coin at least once. Note that we only need to consider cases where j >= coins[i], because it's impossible to make up an amount less than the value of the i-th coin using that coin.

We can initialize dp[0][0] = 1, because there is exactly one way to make up an amount of zero using no coins. Finally, the answer to the problem is dp[n][amount], where n is the total number of coins.

Here's the Python code:

def change(amount, coins):

   n = len(coins)

   dp = [[0] * (amount+1) for _ in range(n+1)]

   dp[0][0] = 1

   for i in range(1, n+1):

       dp[i][0] = 1

       for j in range(1, amount+1):

           dp[i][j] = dp[i-1][j]

           if j >= coins[i-1]:

               dp[i][j] += dp[i][j-coins[i-1]]

   return dp[n][amount]

For example, if we have coins = [1, 2, 5] and amount = 5, then the function should return 4, because there are four combinations of coins that make up an amount of 5: [1, 1, 1, 1, 1], [1, 1, 1, 2], [1, 2, 2], and [5].

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Answer:

144a^2

Step-by-step explanation:

8×9×2=144

144a^1×a

144a^1×a^1

144a^1+1

144a^2

The required area of the figure is 5 square yards.

Area of rectangle is defined as product of the length and width.

Suppose a rectangle and a square has been removed from rectangle.

Length of rectangle = 3  yards

Width of rectangle 2 yards

Length of square = 1 yards

Area of rectangle = 3 × 2 = 6 square yards

Area of square = 1 × 1 = 1 square yards

The required area of the figure = area of rectangle - area of square

Substitute the values

The required area of the figure = 6 - 1

The required area of the figure = 5 square yards

Hence, the required area of the figure is 5 square yards.

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Answer:

imma just assume your asking how many students she has so 20

Step-by-step explanation: