The correct equation of the line that is perpendicular to 2x - 5y = 5 and passes through the point (2, -9) is y = (-5/2)x - 4.
Here,
Let's go through the steps again and find the correct equation for the line that is perpendicular to 2x - 5y = 5 and passes through the point (2, -9).
Step 1: Convert the given equation into slope-intercept form.
2x - 5y = 5
Subtract 2x from both sides:
-5y = -2x + 5
Now, divide everything by -5 to isolate y:
y = (2/5)x - 1
So, the slope of the given line is 2/5.
Step 2: Find the slope of the line perpendicular to the given line.
For two lines to be perpendicular, their slopes must be negative reciprocals of each other.
The negative reciprocal of 2/5 is -5/2.
Step 3: Write the equation of the line using the point-slope form.
Now that we have the slope (-5/2) and a point (2, -9), we can use the point-slope form of the linear equation:
\(y - y_1 = m(x - x_1)\)
where m is the slope, and \((x_1, y_1)\)is the given point.
Substitute m = -5/2 and \((x_1, y_1)\) = (2, -9):
y - (-9) = (-5/2)(x - 2)
Simplify:
y + 9 = (-5/2)x + 5
Now, isolate y by subtracting 9 from both sides:
y = (-5/2)x + 5 - 9
y = (-5/2)x - 4
So, the correct equation of the line that is perpendicular to 2x - 5y = 5 and passes through the point (2, -9) is y = (-5/2)x - 4.
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in 1906, san franciso had an earthquake on a richter scale rating of 8.3 in 1989, san franciso had an earthquake measuring 7.1 on the richter scale. to the nearest tenth, how many more times intense was the 1906 earthquake?
The amount of seismic energy released increases by around 32 times for every whole-number increase in magnitude. In other words, a magnitude 7 earthquake is 32 times stronger than a magnitude 6 earthquake and produces 32 times more energy.
According to Jones, a magnitude 8 earthquake is 1,000 times more energetic than a magnitude 6, but it also spreads out and lasts longer.
In 1906 initially, it was estimated that the accident had claimed the lives of 700 individuals, but the actual death toll is now understood to have topped 3,000. Additionally, about 250,000 people were left homeless; those who survived tented in Golden Gate Park and the dunes west of the city or ran away to nearby cities. Within a short period of time, food and clothing relief shipments arrived in the city, while overseas donors from the Americas, Europe, Japan, and China sent numerous tens of millions of dollars in financial assistance. Despite receiving insurance money in the neighborhood of $300 million, the arduous job of rehabilitation was kept going by the bravery and perseverance of the locals.
A magnitude 6.9 earthquake that struck the San Francisco Bay Area on October 17, 1989, claimed 67 lives and left more than $5 billion in damages. The number of fatalities was very low despite the catastrophe being one of the most damaging and strong earthquakes to ever strike a populous area in the United States. Due to its location close to Loma Prieta Peak in the Santa Cruz Mountains, the event is also referred to as the San Francisco-Oakland earthquake and the Loma Prieta earthquake.
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candice scored 74 on an exam that had normally distributed results with a mean of 66 and a standard deviation of 4. erin scored 58 on an exam that had normally distributed results with a mean of 42 and a standard deviation of 7. who scored better?
Candice's z-score is lower than Erin's z-score, this means that Candice performed better relative to the rest of her peers than Erin did relative to hers. Therefore, Candice scored better on the exam than Erin did.
To explain, we can use the concept of z-scores, which allow us to compare scores from different normal distributions. The z-score for Candice's score of 74 is calculated as: z = (74 - 66) / 4 = 2
This means that Candice's score is two standard deviations above the mean for her exam. The z-score for Erin's score of 58 is calculated as: z = (58 - 42) / 7 = 2.29
This means that Erin's score is 2.29 standard deviations above the mean for her exam. Hence, Candice scored better on the exam.
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SOMEONE PLEASE HELP ME ON THIS ASAP. I'LL RATE AS BRAINLIEST. PLS PLS PLS PLS
Answer:
I think the answer is city B
Step-by-step explanation:
Hope this helps
The expression 2.5a+2b gives the cost (in dollars) for a DVDs and b CDs at a moving sale. a. The cost for 1 DVD is $ and the cost for 1 CD is $ . b. The total cost for 4 DVDs and 4 CDs is $ . Question 2 c. Is $20 enough to buy 6 DVDs and 3 CDs?
Answer/Step-by-step Explanation:
Given:
a = no. of DVDs
b = no. of CDs
Total cost ($) for DVDs and CDs = \( 2.5a + 2b \)
a. The cost for 1 DVD = 2.5(a) = 2.5(1) = $2.5
The cost for 1 CD = 2(b) = 2(1) = $2
b. Total cost for 4 DVDs and 4 CDs:
Substitute a = 4, and b = 4 into the equation.
\( 2.5(4) + 2(4) \)
\( 10 + 8 = 18 \)
Total cost for 4 DVDs and 4 CDs = $18
c. To find out if $20 would be enough to buy 6 DVDs and 3 CDs, substitute a = 6, and b = 3 into the equation. Solve for the total cost to see if it equals $20 or is less than $20. If it's greater than $20, then it won't be enough.
\( 2.5(6) + 2(3) \)
\( 15 + 6 = 21 \)
6 DVDs and 3 CDs cost more than $20, therefore, $20 is not enough.
Find the vertex of the function if x=1
options:
(1,24)
(1,30)
(1,32)
(1,41)
Answer:
(1, 41)Step-by-step explanation:
h = 1
k = p(h) = 4·1² + 24·1 + 13 = 4 + 24 + 13 = 41
The radius of the circle is 6 inches. What is the area of the shaded sector? Express the answer in terms of Pi. A circle with a radius of 6 inches. The shaded sector has an angle measure of 110 degrees. Recall that Area of the sector = StartFraction n degrees over 360 degrees EndFraction (pi) (r squared). 11 pi inches squared 12 pi inches squared 36 pi inches squared 66 pi inches squared
Answer:
I believe its 11 so sorry if wrong
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
what is a exactly 1/4 of a full rotation
Answer: A quarter or 1/4 rotation is 90°.
Step-by-step explanation:
A full rotation is 360 degrees, usually written as 360°. Half a rotation is then 180° and a quarter rotation is 90°.
Ray XP is the angle bisector of Angle RXQ. Given the measure of Angle RXP 12x and Angle PXQ = 8x +12, What is the measure of Angle PXQ?
Question given
Ray XP is the angle bisector of Angle RXQ. Given the measure of Angle RXP 12x and Angle PXQ = 8x +12, What is the measure of Angle PXQ?
Solution
Since XP is the angle bisector of the angle RXQ then we can conclude that the angle RXP is equal to PXQ so we can do the following operation:
\(12x=8x+12\)And we can solve for the value of x and we got:
\(4x=12\)\(x=\frac{12}{4}=3\)And then we can solve for the value of the angle PXQ and we got:
\(\text{PXQ}=8(3)+12=36\)
xa³+ ya² + za = 0
In the equation above, x, y, and z are constants. If the equation has roots -6, 0, and 4, which of the following is a factor of xa³+
ya² + za ?
The factor of the equation xa³ + ya² + za is (a + z).
If the equation xa³ + ya² + za = 0 has roots -6, 0, and 4, we can use these values to find a factor of the expression.
Substituting -6 into the equation:
(-6)a³ + y(0)² + z(-6) = 0
-6a³ - 6z = 0
Dividing the equation by -6:
a³ + z = 0
Similarly, substituting 0 and 4 into the equation:
(0)a³ + y(0)² + z(0) = 0
4a³ + 4z = 0
Dividing by 4:
a³ + z = 0
From the above equations, we can see that a³ + z = 0 for all three roots -6, 0, and 4.
Therefore, the factor of xa³ + ya² + za is (a + z).
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C
\qquad m \angle AOC
m∠AOC
m, angle, A, O, C
is a straight angle.
m
∠
A
O
B
=
8
x
+
5
1
∘
\qquad m \angle AOB = 8x + 51^\circ
m∠AOB=8x+51
∘
m, angle, A, O, B, equals, 8, x, plus, 51, degrees
m
∠
B
O
C
=
6
x
−
2
5
∘
\qquad m \angle BOC = 6x - 25^\circ
m∠BOC=6x−25
∘
m, angle, B, O, C, equals, 6, x, minus, 25, degrees
Find
m
∠
A
O
B
m\angle AOB
m∠AOB
m, angle, A, O, B
:
Answer:
m∠AOB=139°Step-by-step explanation:
m∠AOB+m∠BOC=180°
m∠AOB=8x+51°
m∠BOC=6x-25°
~
\(\tt 8x+51+6x-25=180\)
\(\tt 14x+26=180\)
\(\tt 14x=180-26\)
\(\tt \cfrac{14x}{14} =\cfrac{154}{14}\)
\(\tt x=11\)
m∠AOB:-
\(\tt 8(11)+51\)
\(\tt =88+51\)
\(\tt =139^{o}\)
Therefore, m∠AOB=139°
La Sra.Elena y el Sr.Eulalio,abortan taxis diferentes de la misma empresa el costo del servicio es un importe fijo de salida (banderazo) mas otra cantidad por los kilometros recorridos.Si la SraElena paga $190 por recorrer 8 km y el Sr Eulalio paga $130 por correr 5 km calcular el costo de banderazo y el costo por kilometro recorrido
Answer:
$ 30
$ 20
Step-by-step explanation:
Sea el costo fijo xy el costo por km sea y suponiendo que es el mismo para ambos taxis.
De la pregunta obtenemos las dos ecuaciones
\(x+8y=190\quad ...(i)\)
\(x+5y=130\quad ...(ii)\)
Aplicando \((i)-(ii)\)
\(8y-5y=190-130\\\Rightarrow 3y=60\\\Rightarrow y=\dfrac{60}{3}\\\Rightarrow y=20\)
Sustituyendo en \((ii)\)
\(x+5y=130\\\Rightarrow x+5\times 20=130\\\Rightarrow x=130-100\\\Rightarrow x=30\)
Entonces, el costo fijo es de $ 30 y el costo por km es de $ 20.
help me with this question please
Answer:
N+1
Step-by-step explanation:
It begins with = 2
then n+1=3
then n+2=4 and so on it is n+1
If g(x)=2ln(x+1) and f is a differentiable function of x, what is equivalent to the derivative of f(g(x)) with respect to x?
The equivalent expression for the derivative of f(g(x)) with respect to x is (f'(g(x))) (g'(x)), according to the chain rule.
Given that g(x) = 2ln(x+1) and f(x) is a differentiable function, we want to find the derivative of f(g(x)) with respect to x. We can use the chain rule to determine an equivalent expression for this derivative.
According to the chain rule, if we have a composite function y = f(g(x)), then the derivative of y with respect to x is given by the product of the derivative of f with respect to its argument multiplied by the derivative of g with respect to x.
In this case, g(x) is the inner function and f(u) is the outer function. Applying the chain rule, we have:
d/dx [f(g(x))] = f'(g(x)) g'(x)
Here, f'(u) represents the derivative of f with respect to its argument, and g'(x) represents the derivative of g with respect to x.
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please help! with work please Zeroes of polynomials. will give brainliest!
Answer: 4k^2 - 9k - 9 = 0
Step-by-step explanation:
lmk if i was right please and ty
PLEASE HELP ASAP!!!
Answer:
a. 1 is a right angle because x equals to 10 because of the pythagorean theorem.
b. 1 is an obtuse angle because x could be greater than 10, making 1 an obtuse angle.
c. 1 is an acute angle because x could be less than 10, making 1 an acute angle.
d. x could be 8, making the triangle isoceles.
e. x could be less that 3, making the triangle not possible
what is the hexadecimal equivalent of the decimal number 256
hexadecimal equivalent of the decimal number 256 is \(100_{16}\)
what is hexadecimal value?The hexadecimal number system is a type of number system, that has a base value equal to 16.It is also pronounced sometimes as 'hex'. Hexadecimal numbers are represented by only 16 symbols. These symbols or values are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F. Each digit represents a decimal value the hexadecimal (also base 16 or simply hex) numeral system is a positional numeral system that represents numbers using a radix (base) of 16Unlike the decimal system representing numbers using 10 symbols, hexadecimal uses 16 distinct symbols, most often the symbols "0"–"9" to represent values 0 to 9, and "A"–"F" (or alternatively "a"–"f") to represent values from 10 to 15.Step 1: Divide (256)10 successively by 16 until the quotient is 0:
\(\frac{256}{16}\) = 16, remainder is 0
\(\frac{16}{16}\) = 1, remainder is 0
\(\frac{1}{16}\) = 0, remainder is 1
Step 2: Read from the bottom (MSB) to top (LSB) as 100. So, 100 is the hexadecimal equivalent of decimal number 256 .
hexadecimal equivalent of the decimal number 256 is \(100_{16}\)
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Sarah said that 26÷8 is the same as/equal to 14÷4 and the answers are "3r2". What did Sarah do wrong? 5th grade math help fir my daughter. I think Sarah meant: 26÷8 is the same as or equal to 13÷4 instead of 14÷4 which is what she did wrong?
Answer:
Yes
Step-by-step explanation:
Yes, that is exactly what Sarah did wrong. Apparently, she tried to divide both the numerator and denominator in this problem by 2 (half) but divided the numerator incorrectly. 26 divided by 2 would equal 13 but Sarah mistakenly calculated it as 14 which would give her a totally different value when divided by the new denominator. If were to have divided correctly it would give her \(\frac{13}{4}\) which is the same as \(\frac{26}{8}\)
Use the method of Lagrange multipliers to find the dimensions of the rectangle of the greatest area that can be inscribed in the ellipse x^2/16+y^2/9=1 with sides parallel to the coordinate axes.
The dimensions of the rectangle with the largest area that can be inscribed in the ellipse using the Lagrange multipliers approach are 2a = 2x = 16/√(145) and 2b = 2y = 12/√(145).
We want to find the dimensions of a rectangle with sides parallel to the coordinate axes that have the greatest area and can be inscribed in the ellipse x²/16 + y²/9 = 1. Let the rectangle's measurements be 2a and 2b, where an as well as b are the lengths of the ellipse's semi-axes.
The area of the rectangle is A = 4ab. We want to maximize A subject to the constraint x²/16 + y²/9 = 1.
We set up the Lagrangian function L(x,y,λ) = 4ab + λ(x²/16 + y²/9 - 1), where λ is the Lagrange multiplier. Taking the partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we get:
∂L/∂x = 2λx/16 = 0
∂L/∂y = 2λy/9 = 0
∂L/∂λ = x²/16 + y²/9 - 1 = 0
The first two equations give x = y = 0, or λ = 0. However, these are not the maximum points, since they correspond to a rectangle with zero areas.
We solve the third equation for λ in terms of x and y: λ = 16/(16x²/9 + 9y²/16). Substituting this into the first two equations, we get:
x/8 = y/6
x²/16 + y²/9 = 1
Solving these equations simultaneously, we get x = ±8/√(145) and y = ±6/√(145). Hence, 2a = 2x = 16/√(145) and 2b = 2y = 12/√(145) are the dimensions of the rectangle with the largest area that can be inscribed in the ellipse (145).
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a bag contains 2 gold marbles, 10 silver marbles, and 20 black marbles. someone offers to play this game: you randomly select one marble from the bag. if it is gold, you win $4. if it is silver, you win $2. if it is black, you lose $1. what is your expected value if you play this game? $ round your answer to the nearest cent.
The expected value if you play this game is 25 cents.
What is probability?
The ratio of good outcomes to all possible outcomes of an event is known as probability.
Formula
Probability(Event) = Favorable Outcomes/Total Outcomes.
The total number of marbles is 2+10+20 = 32 marbles
The total probability of getting gold marble is P(g) = 2/32 = 0.0625
The total probability of getting silver marble isP(s) = 10/32 =0.3125
The total probability of getting black marble isP(b) = 20/32 =0.625
By multiplying the price by the likelihood and adding them together with the price for each scenario, we can determine the game's expected value.
E= 4P(g) + 2P(s) - 1P(b)
E= 4*0.0625 + 2*0.3125 - 1* 0.625
E= $0.25 or
E=25 cents
Hence, the expected value if you play this game is 25 cents.
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(50 POINTS) What transformation takes the graph of g(x)=x^2−5 to the graph of h(x)=x^2−1?
translation 4 units up
translation 1 unit up
translation 1 unit down
translation 4 units down
Answer:
translation 4 unites up
Step-by-step explanation:
the thing that is changing is the y intercept and the y intercept went up by 4 therefore it is a translation 4 units up
hope this helps (:
The transformation from the function g(x)=x²-5 to h(x)=x²-1 is translation 4 units up. Therefore, option A is the correct answer.
What is a transformation?A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation.
The given functions are g(x)=x²-5 and h(x)=x²-1.
From the function g(x)=x²-5 to h(x)=x²-1, the translation by 4 units up.
Now, g(x)=x²-5+4
So, h(x)=x²-1
Therefore, option A is the correct answer.
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The box plots show the weights, in pounds, of the dogs in two different animal shelters.One-half of the dogs in each shelter are between which weights?
One-half of the dogs in each shelter are between the weights represented by the first and third quartiles, which are approximately 20-55 pounds for the first shelter and 25-65 pounds for the second shelter, respectively.
A box plot is a visual representation of a set of data that shows the median, quartiles, and outliers of the data. The box represents the middle 50% of the data, with the bottom and top edges of the box representing the first and third quartiles, respectively. The line inside the box represents the median, or the middle value of the data set. The "whiskers" extend from the edges of the box to the minimum and maximum values of the data set, but outliers beyond the whiskers are represented as individual points.
Now, let's look at the two box plots showing the weights of dogs in two different animal shelters. One-half of the dogs in each shelter are between the first and third quartiles, which are represented by the edges of the box in each plot.
If we take the first box plot, we can see that the first quartile is approximately 20 pounds and the third quartile is approximately 55 pounds. Therefore, one-half of the dogs in this shelter weigh between 20 and 55 pounds.
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Determine the number of significant figures in each measurement. Then, choose the representation of the number where x is in place of the estimated digit from the measurement.a) 14.8mb) $10.25c) 0.05 Ld) 1.000 g/mLe) 6200cmf) 403 kg
Significant figures with representation of x are a) 14.8 m = 14.x m. b) $10.25 = 10.2x. c) 0.05 L = 0.0x L. d) 1.000 g/mL = 1.00x g/mL. e) 6200cm = 6200x cm. f) 403 kg = 40x kg.
a) 14.8m has 3 significant figures. Representation with x in place of estimated digit: 14.x m. b) $10.25 has 4 significant figures. Representation with x in place of estimated digit: 10.2x. c) 0.05 L has 1 significant figure. Representation with x in place of estimated digit: 0.0x L. d) 1.000 g/mL has 4 significant figures. Representation with x in place of estimated digit: 1.00x g/mL. e) 6200cm has 2 significant figures. Representation with x in place of estimated digit: 6200x cm. f) 403 kg has 3 significant figures. Representation with x in place of estimated digit: 40x kg. Significant figures are the digits in a measurement that are reliable and accurate. They provide an indication of the precision of a measurement, and allow us to communicate the level of certainty we have in a particular value. When determining the number of significant figures in a measurement, we typically follow a set of rules. Non-zero digits are always significant, zeros between non-zero digits are significant, and trailing zeros to the right of the decimal point are significant. Zeros at the beginning of a number or to the left of a non-zero digit are not significant. The use of significant figures is important in science and engineering to ensure accurate and reliable measurements. When performing calculations with measurements, the result should be reported with the same number of significant figures as the least precise measurement used in the calculation. In addition, when rounding a number, the last digit should be rounded to the nearest value consistent with the number of significant figures being used. Understanding significant figures is an important part of scientific and mathematical communication, and can help to ensure accuracy and consistency in the reporting of data and calculations.
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i need help with this please
Answer:
n= -1.2
Step-by-step explanation:
I think because if you use slope equation to find the slope which is 3/5 and then you use point slop equation to find out what the equation would be. y=3/5x and then you substitue y for 18 and solve/simplify the equation to get -1.2.
Design a situation where the probability of one event is 1/5 and another event is 1/10
We have designed a situation where the probability of one event (event A) is 1/5 and the probability of another event (event B) is 1/10.
How to quantify probability?To quantify the probability of each event, we can define the following events:
Event A: selecting a unit of product A at random and finding that it is defective.Event B: selecting a unit of product B at random and finding that it is defective.Then, the probability of event A is 1/5, since 1 in every 5 units of product A is defective. Similarly, the probability of event B is 1/10, since 1 in every 10 units of product B is defective.
Now, let's consider a scenario where the company receives an order for 100 units of products, with 60 units of product A and 40 units of product B. The company wants to determine the probability of the following events:
Event C: selecting a unit from the order at random and finding that it is defective.Event D: selecting a unit from the order at random and finding that it is not defective.To calculate the probability of event C, we need to consider the probability of selecting a defective unit from product A and from product B, and the proportion of each product in the order. Since the order has 60 units of product A and 40 units of product B, the probability of selecting a unit of product A is 60/100 = 3/5, and the probability of selecting a unit of product B is 40/100 = 2/5.
Using the probabilities of event A and event B, we can calculate the probability of selecting a defective unit from product A or from product B as follows:
Probability of selecting a defective unit from product A: 1/5Probability of selecting a defective unit from product B: 1/10Therefore, the probability of event C can be calculated as follows:
P(C) = P(A) * P(A in order) + P(B) * P(B in order)
= (1/5 * 3/5) + (1/10 * 2/5)
= 3/25
So the probability of selecting a defective unit from the order is 3/25.
To calculate the probability of event D, we can use the complement rule, which states that the probability of an event and its complement (i.e., the event not happening) add up to 1. Therefore, the probability of event D can be calculated as follows:
P(D) = 1 - P(C)
= 1 - 3/25
= 22/25
So the probability of selecting a unit from the order at random and finding that it is not defective is 22/25.
In summary, we have designed a situation where the probability of one event (event A) is 1/5 and the probability of another event (event B) is 1/10. We have also calculated the probability of two other events (event C and event D) in a scenario where a manufacturing company produces two types of products, with different probabilities of defects, and receives an order with a certain proportion of each product.
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(1 point) F Let F(x) = f(f(z)) and G(x) = F2(x) You also know that f(8) -5, f(5)= 3, f'(5) = 5, and f'(8) = 15. Find F'(8) and G² (8) =
(1 point) Let f(x) 5x² (1-4x)³ Find the equation of the line
F'(8) = 450 and G²(8) = 202,500.
What are the derivatives of F(8) and G²(8)?To find F'(8) and G²(8), we need to apply the chain rule and use the given information about f(x). Let's start with F(x) = f(f(z)). Since F(x) is composed of nested functions, we can use the chain rule to find its derivative. Applying the chain rule, we have:
F'(x) = f'(f(z)) * f'(z)
Now, we need to find F'(8). From the information given, f'(8) = 15. To find f'(z), we can use f'(5) = 5, since f(5) = 3. Using the chain rule, we can calculate f'(z) as follows:
f'(z) = f'(5) * f'(z)
= 5 * f'(z)
Since f'(8) = 15, we can substitute these values into the equation for F'(x) to find F'(8):
F'(8) = f'(f(z)) * f'(z)
= f'(f(8)) * f'(8)
= f'(3) * 15
= 5 * 15
= 75
Thus, F'(8) = 75.
Next, we need to find G²(8). Given that G(x) = F²(x), we can express G²(8) as (F²(8)). Using the chain rule, we can calculate (F²(x))' as follows:
(F²(x))' = 2 * F(x) * F'(x)
Substituting F(x) = f(f(z)) and F'(x) = F'(8) = 75, we can find (F²(8))':
(F²(8))' = 2 * F(8) * F'(8)
= 2 * f(f(8)) * F'(8)
To find f(f(8)), we can substitute f(8) = -5 into f(x):
f(f(8)) = f(-5)
= 5(-5)²(1-4(-5))³
= 5 * 25 * 9
= 1125
Plugging in the values, we can calculate (F²(8))':
(F²(8))' = 2 * 1125 * 75
= 2250 * 75
= 168,750
Finally, to find G²(8), we square (F²(8))':
G²(8) = (F²(8))'²
= 168,750²
= 202,500
Therefore, G²(8) = 202,500.
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What is the volume of the cube shown???
Answer:
Hello! answer: 11 25/64
Step-by-step explanation:
Volume is just length × width × height since its a cube all of those will be the same so...
2 1/4 × 2 1/4 × 2 1/4 = 11 25/64 Hope that helps!
Answer:
11 25/64
Step-by-step explanation:
To find the volume of a cube, you have to cube the side length.
2 1/4^3=2 1/4•2 1/4•2 1/4=9/4•9/4•9/4=729/64=11 25/64.
Q3 Find the electric field a distance y above the midpoint between two equal and opposite charges, q and −q, that are a distance d apart as shown in Fig. 1 below. Consider ONLY a case where (y>>). (i) E ˉ = 4πε 0 1 y 3 qd x^
(ii) E ˉ = 4πε 0 1[y 2 +( 2 d ) 2 ] 3/2 qd x^
(iii) E ˉ= 4πε 01 y 3 /2qd x^
(iv) None of the above
The electric field at point P due to the charges q and -q is zero. Option (iv) None of the above is the correct answer.
The electric field a distance y above the midpoint between two equal and opposite charges, q and −q, that are a distance d apart as shown in Fig. 1 above can be found as follows:
Since, the distance between the charges is d, the distance from the midpoint to either of the charges would be d/2. According to the principle of superposition, the electric field due to the two charges would be the vector sum of the electric fields due to the charges q and -q at point P. Let's consider the electric field due to the charge q at point P and the electric field due to the charge -q at point P.
Electric field due to the charge q: Using Coulomb's law, we can write the electric field due to the charge q at point P as:
E1 = kq/r1²,
where k is Coulomb's constant, q is the charge, and r1 is the distance between the charge q and point P.
The distance r1 can be calculated as:
r1 = [(d/2)² + y²]^1/2
Since the electric field is a vector quantity, we can represent it in terms of unit vector i as follows:
E1 ˉ= kq/[(d/2)² + y²]^1/2 iˉ
Electric field due to the charge -q:
Similarly, the electric field due to the charge -q at point P can be written as:
E2 ˉ= - kq/[(d/2)² + y²]^1/2 iˉ (because the charge is negative)
Therefore, the net electric field at point P can be obtained by taking the vector sum of the electric fields due to the two charges:
E ˉ= E1 ˉ + E2 ˉ= [kq/[(d/2)² + y²]^1/2 - kq/[(d/2)² + y²]^1/2] iˉ= 0
Thus, the electric field at point P due to the charges q and -q is zero. Option (iv) None of the above is the correct answer.
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what is the area of this parallelogram?
30 inches squared or 30 in^2
All you have to do to find area of a parallelogram is length times width
So 5 times 6 is 30
Don’t forget the unit, which in this case is inches, and anytime you have area, you have to have a squared, or an exponent 2
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Solve x2 − 12x + 23 = 0 by completing the square.
a (x − 12)2 = 23; x = −11, x = 35
b (x − 6)2 = 13; x = −7, x = 19
c (x − 12)2 = 23
Answer:
\( {x}^{2} - 12x + 23 = 0\)
\( {x}^{2} - 12x = - 23\)
\( {x}^{2} - 12x + 36 = 13\)
\( {(x - 6)}^{2} = 13\)
x - 6 = +√13
x = 6 + √13
Use technology to find points and then graph the function y=√x - 4 following the instructions below.
Answer:
See below
Step-by-step explanation: