The rate of the faster plane is 860 km/h, and the rate of the slower plane would be 860 - 87 = 773 km/h.
Let's denote the rate of the faster plane as r (in km/h). According to the given information, the rate of the slower plane would be r - 87 (km/h) since it is traveling 87 km/h slower than the faster plane.
To solve the problem, we can use the formula: distance = rate × time.
For the faster plane, the distance it travels in 7 hours would be 7r km.
For the slower plane, the distance it travels in 7 hours would be 7(r - 87) km.
Since the two planes are traveling in opposite directions, their distances should add up to the total distance of 11,417 km.
So, we can set up the equation: 7r + 7(r - 87) = 11,417.
Simplifying the equation: 7r + 7r - 609 = 11,417.
Combining like terms: 14r - 609 = 11,417.
Adding 609 to both sides: 14r = 12,026.
Dividing both sides by 14: r = 860.
Therefore, the rate of the faster plane is 860 km/h, and the rate of the slower plane would be 860 - 87 = 773 km/h.
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Which of these is one of six most common elements found in the human body??
Answer: Oxygen
Explanation: Oxygen is the most common element in the human body. It makes up 65% of the body.
Two 120v light bulbs, one 25w and one 200w, were connected in series across a 240v line. It seemed like a good idea at the time, but one bulb burned out almost instantaneously. Which one burned out, and why?.
The 25w bulb burned out.
Both bulbs (200w and 25w) are connected in series to the 240v line, the same current is expected to flow in them. The expected resistance of the 200W bulb will be less than 25W. Therefore more potential difference than 120V will be developed in 25W bulb hence it will fuse.
As per the question:
Voltage, V = 120 V
Power of bulb 1, P = 25 W
Power of bulb 2, P' = 200 W
Voltage in series, V' = 240 V
Now,
When the two bulbs are connected in parallel, voltage across them is same and the current in the two branches is different.
Using P= V²/R to calculate the respective resistances of the two bulbs:
25 = 120²/R
R = 120²/25
R = 576Ω
100 = 120²/R
R = 120²/100
R' = 144Ω
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The 25W bulb burned out almost instantaneously when the two light bulbs were connected in series across a 240V line because the voltage across it is much more than its rated voltage.
Two lights bulbs, one 25w and another 200w, to find the bulb that burn out almost instantaneously, we first find the following:
Resistance R=V^2/P
For the bulb of 25W
Resistance=120^2/25
=576.0Ω
For the bulb of 200W
Resistance=120^2/200
=72.0Ω
Net resistance of the circuit:
R=R25W+R200W
=576.0+72.0
=648.0Ω
Current, I
I=E/R
=240/648.0
=0.370A
Voltage across 25W bulb
Voltage=I*R
=0.370*576.0
=213.12V
Voltage across 200W bulb
Voltage=I*R
=0.370*72.0
=26.64V
Since voltage across 25W bulb is much more than its rated voltage of 120V, 25W bulb will burn out.
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A 16.0 kg canoe moving to the left at 10 m/s makes a head-on collision with a 19.0 kg raft moving to the right at 7.0 m/s. After
the collision, the canoe moves to the right at 1 m/s. What is the velocity of the raft after the collision?
Answer:
Approximately \(2.3\; {\rm m\cdot s^{-1}}\) to the left.
Explanation:
When an object of mass \(m\) travels at a velocity of \(v\), the momentum \(p\) of that object will be \(p = m\, v\).
Denote motions to the right with a positive sign.
Before the collision:
Velocity of the canoe was \((-10)\; {\rm m\cdot s^{-1}}\) since the canoe was moving to the left (opposite to the positive direction.) Momentum of the canoe was \(p(\text{canoe, before}) = (16.0\; {\rm kg})\, (-10\; {\rm m\cdot s^{-1}}) = 160\; {\rm kg \cdot m\cdot s^{-1}}\).Velocity of the raft was \(19.0\; {\rm m\cdot s^{-1}}\) since the raft is moving to the right (towards positive direction.) Momentum of the raft was \(p(\text{raft, before}) = (19.0\; {\rm kg})\, (7.0\; {\rm m\cdot s^{-1}}) = 133\; {\rm kg \cdot m\cdot s^{-1}}\).After the collision:
Velocity of the canoe becomes \(1\; {\rm m\cdot s^{-1}}\) (to the right, towards the positive direction.) Momentum of the canoe becomes \(p = (16.0\; {\rm kg})\, (1\; {\rm m\cdot s^{-1}}) = 16.0\; {\rm kg \cdot m\cdot s^{-1}}\).Velocity of the raft after the collision needs to be found.Immediately after the collision, momentum \(p\) of the canoe and the raft will be conserved. In other words:
\(\begin{aligned}& p(\text{canoe, before}) + p(\text{raft, before}) \\ =\; & p(\text{canoe, after}) + p(\text{raft, after})\end{aligned}\).
Rearrange to find \(p(\text{raft, after})\) (momentum of the raft immediately after the collision.)
\(\begin{aligned}& p(\text{raft, after}) \\ =\; & p(\text{canoe, before}) \\ & + p(\text{raft, before}) \\ & - p(\text{canoe, after}) \\ =\; & (-160\; {\rm kg \cdot m\cdot s^{-1}}) \\ &+ (133\; {\rm kg \cdot m\cdot s^{-1}}) \\ & - (16.0\; {\rm kg \cdot m\cdot s^{-1}}) \\ =\; & (-43)\; {\rm kg \cdot m\cdot s^{-1}} \end{aligned}\).
(Momentum of the raft is negative since the raft is moving to the left, away from the positive direction.)
Divide the momentum of the raft by the mass of the raft to find the velocity of the raft:
\(\begin{aligned} \frac{(-43\; {\rm kg\cdot m\cdot s^{-1}})}{(19.0\; {\rm kg})} \approx (-2.3)\; {\rm m\cdot s^{-1}}\end{aligned}\).
A cheetah can run at a maximum speed 105 km/h and a gazelle can run at a maxi- mum speed of 73.5 km/h. if both animals are running at full speed, with the gazelle 99 m ahead, how long before the cheetah catches its prey?
If both animals are running at full speed, with the gazelle 99 m ahead, cheetah will catch its prey after 331 m
v = d / t
v = Velocity
d = Distance
t = Time
Let the distance covered by the gazelle be x.
For cheetah,
v = 105 km / h
d = ( 99 + x ) m
t = d / v
t = 105 / ( 99 + x ) s
For gazelle,
v = 73.5 km / h
d = x m
t = d / v
t = 73.5 / x
The time taken by both cheetah and gazelle will be the same when the cheetah catches its prey.
105 / ( 99 + x ) = 73.5 / x
105 x = 7276.5 + 73.5 x
31.5 x = 7276.5
x = 231 m
Distance travelled by cheetah = ( 99 + x ) m
Distance travelled by cheetah = ( 99 + 231 ) m
Distance travelled by cheetah = 331 m
Therefore, the cheetah will catch its prey after 331 m
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Two bodies of masses M and m(M>m) are allowed to fall from the same height. If
the air resistance for each be the same then will both the bodies reach the earth
simultaneously?
\(\sf{\pink{\underline{\underline{\blue{QUESTION:-}}}}}\)
✨ ASSERTION :-Two bodies of masses M and m (M>m) are allowed to fall from the same height . If the air resistance for each be the same then both the bodies will reach the earth simultaneously .✨ REASON :-For same air resistance, acceleration of both the bodies will be same .[A] If both assertion and reason are true and reason is the correct explanation of assertion .
[B] If both assertion and reason are true but reason is not the correct explanation of assertion .
[C] If assertion is true but reason is false
[D] If both assertion and reason are false
\(\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}\)
✍️ The force acting on the body of mass M are [its weight] ‘Mg’
Mg are acting vertically downwards And air resistance F acting vertically upward .Hence,
\(\rm{\green{Acceleration\:of\:the\:body\:(a)\:=\:\dfrac{Mg\:-\:F}{M}\:}}\)
\(\rm{\implies\:Acceleration\:of\:the\:body\:(a)\:=\:g\:-\:\dfrac{F}{M}\:}\)
⚡ Now, M > m therefore, the body with larger mass will have greater acceleration and it will reach the ground first .
\(\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\purple{\therefore\:[D]\:Both\:Assertion\:and\:Reason\:\atop{are\:incorrect\:.}}}}}}\)
Un zapato de golf tiene 10 tacos cada uno con un área de 0.0 pulgadas en contacto con el piso suponga que al caminar hay un instante en que los tacos soportan el peso completo de una persona de 180 libras ¿cuál es la presión ejercida por los tacos sobre el suelo?
Pregunta completa :
Un zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que al caminar hay un instante en que los tacos soportan el peso completo de una persona de 180 libras ¿cuál es la presión ejercida por los tacos sobre el suelo?
Responder:
12230825.435 pascal
Explicación:
Dado que:
Peso (W) = 180 libras
Número de tacos = 10
Área por montante = 0.01 in²
Área total (10 * 0.01) = 0.1 pulg²
Usando la calculadora de conversión:
180 libras = 81.647 kg
0.1 pulg² = 6.452 × 10 ^ -5 m²
Recordar :
Presión = Fuerza (Newton) / Área (m²)
Fuerza = masa * aceleración debida a la gravedad
Aceleración por gravedad = 9,8 m / s²
Presión = (81.647 * 9.8) / (6.452 * 10 ^ -5)
Presión = 800.1406 / 6.452 * 10 ^ -5
Presión = 12230825.435 pascal
using the generalized mass m* and generalized stiffness k*, and the appropriate shape function, determine the fundamental period t. in g
The mass matrix M (p) describes the generalized mass and inertia of the system as a function of the vehicle pose.
What is generalized mass?The term "generalized mass" usually refers to a representation of the "physical" mass matrix that has been transformed from "physical" (also known as "nodal" in FE) coordinates to generalised (also known as "modal") coordinates.
The eigenvalue analysis yields eigenvalues, which are related to the system's natural frequencies (2*pi*f2), and eigenvectors, which are the mode shapes associated with each of those frequencies. When all of these eigenvectors are combined into one matrix, with each column of the matrix representing one eigenvector, we have the system's "modal matrix." You can scale each column however you want. The columns are frequently scaled so that each has a maximum value of 1.
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an electromagnetic wave in vacuum has an electric field amplitude of 531 v/m. calculate the amplitude of the corresponding magnetic field.
The amplitude of the corresponding magnetic field is B= 1.77x10^-6 T
Briefly:-It is given that,
The amplitude of an electromagnetic wave, E = 10 V/m
Formula for the relationship between magnetic field and electric field amplitude are given by;-B = E/c
c being the speed of light
B = 531/3.0x10⁸
B= 1.77x10^-6 T
How is the magnitude of an electromagnetic wave determined?The equation k = 2/, where is the wave's wavelength, yields the wave number. The formula for the frequency of a wave is f = /2, where is the angular frequency. The speed of each periodic wave is determined by multiplying its wavelength by its frequency. v = λf.
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A machinist bores a hole of diameter 1.30 cm in a steel plate at a temperature of 27.0 ∘ C .
Part A
What is the cross-sectional area of the hole at 27.0 ∘ C .
Express your answer using four significant figures.
Part B
What is the cross-sectional area of the hole when the temperature of the plate is increased to 175 ∘ C ? Assume that the coefficient of linear expansion remains constant over this temperature range.
Express your answer using four significant figures.
The final cross-sectional area comes out to be 1.34 cm^2
Part A: The cross-sectional area of the hole at 27.0 ∘ C can be calculated using the formula A=πr^2, where r is the radius of the hole. Since the diameter of the hole is given as 1.30 cm, the radius is 0.65 cm. Substituting this value in the formula, we get A=3.14*(0.65 cm)^2 = 1.33 cm^2 (rounded to four significant figures).
Part B: When the temperature of the plate is increased to 175 ∘ C, the steel plate and the hole will expand due to the coefficient of linear expansion. Assuming that the coefficient of linear expansion remains constant, we can use the formula ΔL = αLΔT, where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length, and ΔT is the change in temperature. Since we know the initial and final temperatures and the original diameter of the hole, we can calculate the final diameter using ΔL = (2r)αΔT and then use the formula A=πr^2 to find the cross-sectional area. The final cross-sectional area comes out to be 1.34 cm^2 (rounded to four significant figures).
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You are looking at a current carrying loop of wire laying flat on the table. As viewed from above, the current is moving in a clockwise direction.
a. Magnetic field in the center of this loop is directed:
(i) To the right part of the loop
(ii) Down
(iii) Zero.
(iv) To the left part of the loop
(v) Up
b. The magnetic field outside (say, to the right) of this loop is directed:
(i) Away from the loop
(ii) Up
(iii) is zero
(iv) Towards the loop
(v) Down
The direction of the magnetic field inside and outside a current carrying loop of wire depends on the direction of the current flow. If the current in the loop is moving in a clockwise direction, the magnetic field in the center of the loop is directed zero, while the magnetic field outside the loop is directed towards the loop.
a. The magnetic field in the center of this loop is directed zero, as the magnetic fields produced by each side of the loop cancel each other out in the center.
b. The magnetic field outside (to the right) of this loop is directed towards the loop. This is because the current in the loop creates a magnetic field that circulates around the wire. When viewed from above, the magnetic field lines are clockwise inside the loop and counter-clockwise outside the loop. Therefore, the magnetic field outside the loop is directed towards the loop.
The direction of the magnetic field inside and outside a current carrying loop of wire depends on the direction of the current flow. When viewed from above, if the current in the loop is moving in a clockwise direction, the magnetic field in the center of the loop is directed zero, as the magnetic fields produced by each side of the loop cancel each other out. Outside the loop, the magnetic field is directed towards the loop, as the current in the loop creates a magnetic field that circulates around the wire.
In conclusion, the direction of the magnetic field inside and outside a current carrying loop of wire depends on the direction of the current flow. If the current in the loop is moving in a clockwise direction, the magnetic field in the center of the loop is directed zero, while the magnetic field outside the loop is directed towards the loop.
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a rectangular tank measures 12.5 metres long 10.0 wide and 2.0 metre high calculate the mass of the water in the tank when it is full the density of water 1000 kg per metre cube assume the measurement are internal
Answer:
250000kg
Explanation:
Mass =density * volume
Density=1000kg/m³
Volume=l*w*h
12.5*10.0*2.0=250m³
Mass=1000 *250
=250000kg
differences between distance and displacement.
A vector starts at the point (0, 0) and ends at (3, 1). What is the magnitude and direction of the displacement?
Answer:
tbh vector does not have any direction at all the answer is 0
Why is acceleration due to gravity low in the space?
Answer:
Explanation:
actually , the acceleration due to gravity depends on the distance from it's center of the earth.
when the distance from the earth increases , the acceleration due to gravity decreases as a result . The value of gravity in space is zero.
s dispersion dispersion
, refraction
Answer:
If you want definition, here it is:
Dispersion is defined to be the spreading of white light into its full spectrum of wavelengths. Refraction is responsible for dispersion in rainbows and many other situations. The angle of refraction depends on the index of refraction, as we saw in The Law of Refraction.
????????????????what’s the answer
Answer:
I don't know what do u. mean
What phase of matter is sometimes categorized as a crystal and what is a crystal?
Explanation:
A crystal or crystalline solid is a solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.
rank the time required for the crates to return to their initial positions from largest to smallest.
To rank the time required for the crates to return to their initial positions from largest to smallest, you first need to calculate the time taken for each crate to return to its original position. This can be done using the formula:
Time = (2 × Length of Spring) ÷ (Acceleration due to Gravity × Mass of Crate)Once you have the time taken for each crate to return to its original position, you can rank them from largest to smallest.
Compare the values in the list and rank them from largest to smallest. The highest value in the list will be the first, followed by the second highest value, and so on.
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mixtures cannot be physically separated true or false
Answer: False
Explanation: You'll be able continuously tell a blend, since each of the substances can be isolated from the group in numerous physical ways. You'll be able continuously get the sand out of the water by sifting the water absent. Some of the time a blend partitioned on their possess eg. water & cooking oil.
It takes Josh 8 seconds to slow down from 39 m/s to 21 m/s. Calculate his acceleration
a: acceleration
Δv: change in velocity
t: time
a = Δv/t = (21-39)/8 = -18/8 m/s^2 = -2.25 m/s^2
Protons are______
charged particles.
Answer: Protons are positively charged particles
Explanation:
10.4. Two spheres are made of the same metal and have the same radius, but one is hollow and the other is solid. The spheres are taken through the same temperature increase. Which sphere expands more
The two spheres will expand equally since they are made of the same metal.
What is volume expansivity?
Volume expansivity is the fractional increase in the volume of an object at a given temperature.
\(\frac{\Delta V}{V_0} = \gamma \Delta T\)
where;
γ is cubic expansivityΔT is change in temperatureThe cubic expansivity of the two spheres is same since they are of same metal.
Thus, the two spheres will expand equally since they are made of the same metal.
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what is 2+2? I’m in geometry
A football is kicked at 55o at 15 m/s.
How long is it in the air?
How far does it travel to go through the is at the same height as when it started?
I dont even really need the answer I just need the formula to get the answer
Answer:
A.) T = 1.25s
B.) H = 7.7m
Explanation:
Given that a football is kicked at 55o at 15 m/s.
How long is it in the air?
Let's use the formula below:
V = UsinØ - gt
V = 0 at maximum height.
0 = UsinØ - gt
UsinØ = gt
Substitute all the parameters into the formula
15sin55 = 9.8t
9.8t = 12.29
t = 12.29/9.8
t = 1.25 seconds
How far does it travel to go through the is at the same height as when it started?
That will be the maximum height.
Using the third equation of motion
V^2 = U^2 sin^2ø - 2gH
At maximum height, V = 0
(UsinØ)^2 = 2gH
(15sin55)^2 = 2 × 9.8H
(12.29)^2 = 19.6H
H = 150.97/19.6
H = 7.7 m
Can someone do my physics work for $150?
Answer:
sure
Explanation:
what/where is the work
what are two things that are infinite?
Answer:
Infinity = Never ending
Explanation:
The universe could be infinite, both in terms of space and time, but there is currently no way to test whether it goes on forever or is just very big. The part of the universe we are able to observe is finite, measuring about 46 billion light years in diameter.
The set of natural numbers is an infinite set. This kind of infinity is, by definition, called countable infinity. All sets that can be put into a bijective relation to the natural numbers are said to have this kind of infinity. This is also expressed by saying that the cardinal number of the set is aleph-naught (ℵ0).
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STARS ARE INFINITE , NUMBERS ARE INFINITE
Explanation:
Find the potential energy of a 0.75 kg hammer when its raised 0.35 meters.
Answer:
the potential energy = 2.625
Explanation:
potential energy = mass× acceleration due to gravity × height
mass = 0.75kg
acceleration due to gravity =10m/s²
height =0.35 meters
potential energy = 0.75kg× 10m/s² × 0.35m =2.625 N
Why can elastic band particles stay together
Answer:
The particles are held rigidly in place by all the other particles around them so they can't slip past one another or move apart. This gives solids a fixed shape and a fixed volume.
I cannot find scince so can someone please help me out
The three statements which provide evidence of universe expansion that supports the Big Bang Theory include the following:
Galaxies are moving away from each other.The temperature of the universe is decreasing.An enormous amount of weak background radiation has been detected in the universe.What is the Big Bang Theory?The Big Bang Theory simply refers to an explanation that was given by astronomers to describe how the universe was formed, which describes a well-detailed information on how the universe started (its origin).
According to the Big Bang Theory, the whole universe stretched from a single point and then expanded to its present state and this is typically supported by the following evidence:
Red shift of galaxies due to Doppler effect.Cosmic background radiation.Decrease in the temperature of the universe.Universe is expanding.The movement of galaxies apart.Existence of quasars.Read more on Big Bang Theory here: https://brainly.com/question/24926549
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Complete Question:
Which provides evidence of universe expansion that supports the Big Bang Theory? Select the three correct answers. (2 points)
An enormous amount of weak background radiation has been detected in the universe.
The temperature of the universe is decreasing.
The temperature of Cosmic Microwave Background radiation varies widely from one part of the universe to another
Galaxies are moving away from each other.
The universe is undergoing a cycle of contraction and expansion
The temperature of the universe is increasing.
A dog walks 14 meters to the west and then 20 meters back
to the east.
Answer 34
Explanation:
Answer:
The dog moved 6 meters west and 34 meters total
Explanation: