with the aid of a string, a gyroscope is accelerated from rest to 35 rad/s in 0.29 s. (a) what is its angular acceleration in rad/s2? rad/s2 (b) how many revolutions does it go through in the process? rev

Answer:

Explanation:

Newton's Law Of Gravity states two masses will have an attraction force that is proportional to their masses and inversely proportional to the square of their separating distance.

Mathematically it is expressed as Force = G * M1 * M2 / d^2 where

G is the gravitational constant, M1 and M2 are the masses and d is the separating distance.

Answer: I think a

Explanation:

Answer:

Explanation:

The answer is Climate

Answer:

climate

Explanation:

Climate is defined as an area's long-term weather patterns. The simplest way to describe climate is to look at average temperature and precipitation over time.

(1.) The Phenomena of Refraction Occurs when a Ray (Here Light) enters a Relatively Denser or Rarer Medium and Due to the Change in Density, the Speed of the Incident Ray Decreases or Increases Respectively.

(2.) If a light ray projected through a diamond, the light would refract drastically.

Globalization alludes to the expanded interconnectedness between various regions of the planet. The interaction is a kind of shared trade of values, standards, and contemplations. All of the cooperating societies are profited from the culture.

Globalization has various numerous actual signs as confirmed by the consistent development of items, products, and administrations that cross worldwide boundaries consistently. The Worldwide South which sends its wares into an unpredictable market, and gives modest work to the world's large companies, has long voiced its mistake at the unfairness of inconsistent exchange relations and global administrative associations.

The obtrusive improvement in the South to support the development based economies in the North has a negative relationship with a reasonable climate (Iqbal). Hence, they see firsthand the social and ecological repercussions that a culture of utilization makes on the planet.

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The dark color suggests that there must be at least one other pigment present that absorbs the green light.

When we perceive an object as having a certain color, it is because the object absorbs certain wavelengths of light and reflects or transmits others. The color we see is the result of the wavelengths that are reflected or transmitted by the object.

In the case of a dark-colored object, such as a dark green leaf or a black material, it appears dark because it absorbs a significant amount of light across the visible spectrum. For example, if we observe a dark green object, it means that the object is absorbing most of the wavelengths of visible light, including green light.

Green light has a wavelength of approximately 520-570 nanometers. For an object to appear dark green, it must absorb a significant amount of green light. This absorption of green light suggests the presence of pigments in the object that have the ability to absorb or reflect specific wavelengths of light.

Therefore, to achieve a dark green color, there must be at least one other pigment present in addition to those responsible for reflecting or transmitting green light. These additional pigments likely absorb the green light, contributing to the overall dark appearance of the object.

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Magnetic field is stronger at the poles whereas weaker at the center.

The magnetic field on the bar magnet is strongest at the poles because the field lines are most concentrated at the poles while on the other hand, the magnetic field is weaker in the central part of magnet.

Magnetic field has equal amount of strength at both the poles so in my opinion as well as scientific point of view, magnet field is stronger at the poles and weaker at the center of magnet.

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Answer:

Average velocity = 360km/h due Northeast.

Explanation:

Given the following data;

Distance = 1260km

Time = 3.5h.

Velocity =?

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

\(Velocity = \frac{distance}{time}\)

\(V = \frac{d}{t}\)

Substituting into the above equation;

\(V = \frac{1260}{3.5}\)

Velocity, V = 360km/h.

Since velocity is a vector quantity, it must have both magnitude and direction.

Hence, the average velocity of the airplane is 360km/h due Northeast.

Answer:

sun is the main source while the other object reflect light on the sun

Explanation:

nasa libro yans

Explanation

the force between 2 charges is given by the formula:

then,we can check every option and compare the result to the original, hence

Step 1

a)option A

reduce one particle's charge by a factor of 16

so

now, replace

therefore, option A works

Step 2

v_a = 178.74 m/s

using Bernoulli's theorem :-

P_a + ½ρ(v_a)² = P_b + ½ρ(v_b)²

Where;

P_a is pressure above wings

P_b is pressure below wings

v_a is speed above wings

v_b is speed below wings

ρ is density of air

We want to find V_a, so let's make V_a the subject;

v_a = √[(2(P_b - P_a)/ρ) + (v_b)²]

Now, we don't know (P_b - P_a)

(P_b - P_a) = Force/Area

(P_b - P_a) = mg/Area

We are given m = 2.5 × 10^(6) kg and area = 1600 m²

Thus, (P_b - P_a) = (2.5 × 10^(6) × 9.81)/1600 = 15328.125 N/m²

Density of air will be taken as 1.2 kg/m³

Thus;

v_a = √[(2(15328.125)/1.2) + (80)²]

v_a = √31946.875

v_a = 178.74 m/s.

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For an object that is only 150 years old, there would still be a significant amount of carbon-14 present in the sample, which would make it difficult to accurately determine the age of the object. The age of the sample is 23,108 years.

We know that;

0.693/t1/2 = 2.303/t log (No/N)

0.693/5700 = 2.303/t log (80/5)

0.693/5700 = 2.773/t

1.2 * 10^-4 = 2.773/t

t = 2.773/1.2 * 10^-4

t = 23,108 years

Carbon-14 dating is a radiometric dating method used to determine the age of organic materials up to approximately 50,000 years old. Carbon-14 (14C) is a radioactive isotope of carbon that decays over time, and the amount of 14C remaining in a sample can be used to determine its age.

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We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)

(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.

The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.

Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).

(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).

(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.

(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.

(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.

As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.

This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.

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Answer:

d a

Explanation:

B. Doubling The Distance Between Capacitor Plates Will Reduce The Capacitance Two-Fold.  

Capacitor is an electrical device used to store energy. It is composed of two conducting plates separated by an insulating material called the dielectric. When a voltage is applied to the two plates, an electric field forms between them, storing energy in the form of an electrical charge. Capacitors are used in a variety of applications, such as in filter circuits, timing circuits, and power supply circuits.

The capacitance of a capacitor is directly proportional to the area of the plates and inversely proportional to the distance between the plates. Therefore, when the distance between the plates is doubled, the capacitance is halved.

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Answer:

Solid and liquid

Explanation:

In solid state, the particles are tightly packed together hence forming a regular shape.

In liquid state, the particles are tightly packed together with some degree of movement.

In gaseous state, the particles are loosely packed and free to move randomly.

Since the particles of both solid and liquid state are tightly packed together, their corresponding density will only show a slight difference and hence almost similar.

Answer:

the answer is letter D.

Explanation:

i hope this is help

Answer:

great answer warstep8! add me on disc colludy#8415

Explanation:

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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To lift an 875 lb block using friction tongs, we need to find the smallest allowable coefficient of friction between the blocks at d and e. Let's call this coefficient of friction "μ".

The force required to lift the block is equal to its weight, which is 875 lbs. This force is exerted on the friction tongs at point e. The force required to lift the block is balanced by the force of friction between the block and the tongs at point d.

The force of friction between the block and the tongs is equal to the coefficient of friction "μ" multiplied by the normal force between the block and the tongs. The normal force is equal to the weight of the block, which is 875 lbs.

So, the force of friction between the block and the tongs at point d is equal to μ x 875 lbs.

To lift the block, the force required at point e must be greater than or equal to the force of friction at point d. Therefore, we have:

μ x 875 lbs ≤ F

where F is the force required at point e to lift the block.

To find the smallest allowable coefficient of friction, we need to solve for μ. We can rearrange the above equation as:

μ ≤ F / 875 lbs

Substituting F = 875 lbs, we get:

μ ≤ 1

Therefore, the smallest allowable coefficient of friction between the blocks at d and e to lift the block is 1.

To find the smallest allowable coefficient of friction between the blocks at points D and E to lift an 875 lb block using friction tongs, follow these steps:

1. Identify the force acting on the block: The weight of the block is 875 lb.
2. Determine the force needed to lift the block: Since friction tongs rely on friction to lift the block, the force applied by the tongs (F) must be equal to or greater than the block's weight (W). So, F ≥ W = 875 lb.
3. Apply the friction formula: The force of friction (F_friction) is determined by multiplying the normal force (N) by the coefficient of friction (μ). In this case, F_friction = μ * N.
4. Determine the normal force (N): In the case of friction tongs, the normal force is equal to the force applied by the tongs, which we've determined is 875 lb. So, N = 875 lb.
5. Solve for the coefficient of friction (μ): Since we're looking for the smallest allowable coefficient of friction, we can set F_friction equal to the force needed to lift the block (875 lb). So, μ * N = 875 lb, and μ = 875 lb / N.
6. Plug in the value for N: μ = 875 lb / 875 lb.
7. Calculate the smallest allowable coefficient of friction: μ = 1.

Therefore, the smallest allowable coefficient of friction between the blocks at points D and E to lift the 875 lb block using friction tongs is 1.

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Answer:

Hertz

Explanation:

How long is a sound wave? Sound frequency (pitch) is measured in Hertz. 1 Hz is one cycle per second.

Ten devices that use batteries are: smartphones, laptops, flashlights, digital cameras, portable speakers, electric toothbrushes , remote controls, electric shavers, handheld game consoles, and electronic toys

What are the batteries?

Here are ten devices that use cells or batteries:

Whether or not the cells or batteries used in these devices are the best choice depends on various factors such as the device's power requirements, energy efficiency, cost, and environmental impact.

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To find the moments of inertia Ix, Iy, I0 for the given lamina, we first need to calculate its mass and centroid. The density at any point is proportional to the square of its distance from the origin,

so the mass element dm can be expressed as kr^2dA, where k is the coefficient of proportionality, r is the distance from the origin, and dA is the differential area element. Using polar coordinates, we can express the given region as 0 ≤ r ≤ 6 and 0 ≤ θ ≤ π/2. Integrating dm over this region, we get the total mass of the lamina as: M = ∫∫ kr^2dA = k ∫∫ r^2dA = k ∫θ=0..π/2 ∫r=0..6 r^2r dr d = k ∫θ=0..π/2 [r^4/4]_r=0..6 dθ = (3/5)πk(6^5) To find the centroid of the lamina, we can use the formulae: x_c = (1/M) ∫∫ xdm, y_c = (1/M) ∫∫ ydm Simplifying, we get: x_c = (1/M) k ∫∫ xr^2dA, y_c = (1/M) k ∫∫ yr^2dA.

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Answer:

D

Explanation:

im pretty sure

That quasars were at large cosmological distances yet appeared like ordinary faint stars meant they must be very large. they must be producing very large quantities of energy

The correct answer would be:  they must be producing very large quantities of energy

Astronomers measure extreme cosmological distances using Hubble’s Law

The correct answer would be: Hubble’s Law

If the average mass density of the Universe were half the critical density, and there were zero dark energy density, the Universe stop expanding but not collapse.

The correct answer would be: stop expanding but not collapse.

The statement "That quasars were at large cosmological distances yet appeared like ordinary faint stars meant..." indicates that despite their apparent faintness, quasars are actually situated at large distances. Given this information, we can deduce that "they must be producing very large quantities of energy." Quasars are incredibly luminous and are powered by supermassive black holes at the centers of galaxies. These black holes accrete mass from surrounding material, releasing vast amounts of energy in the process.

Astronomers measure extreme cosmological distances using various methods. Among the options provided, "Hubble's Law" is the most relevant. Hubble's Law states that the recessional velocity of a galaxy is directly proportional to its distance from Earth. By observing the redshift of light from distant galaxies, astronomers can determine their velocities and, subsequently, their distances.

If the average mass density of the Universe were half the critical density and there were zero dark energy density, the Universe would eventually stop expanding but not collapse. In this scenario, the gravitational pull of matter would slow down the expansion, causing it to approach a point of equilibrium. However, it would not be sufficient to cause the Universe to collapse under its own gravitational attraction. This hypothetical state is known as a "flat" Universe, where the expansion reaches a steady-state without accelerating or collapsing.

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Answer:

Within the nucleus, DNA molecules, the cell's genetic machinery, are stored, repaired, transcribed and eventually replicated. Around the outside of the nucleus is an envelope consisting of two layers of membrane.

Explanation:

hope this was what you were looking for

The speed of the lower part of the Variegated Glacier on June 9, 1983, was approximately 0.00074 meters per second.

The speed of the lower part of the Variegated Glacier in Alaska is 0.64 meters per second.
To convert the glacial speed from feet per day to meters per second, first, we need to convert feet to meters and then days to seconds.

On June 9, 1983, the lower part of the Variegated Glacier in Alaska was observed to be moving at a rate of 210 feet per day.

1 foot = 0.3048 meters
210 feet = 210 * 0.3048 = 64.008 meters

1 day = 24 hours = 24 * 60 minutes = 24 * 60 * 60 seconds = 86,400 seconds
Now, we can find the speed in meters per second:
Speed = (64.008 meters) / (86,400 seconds) ≈ 0.00074 m/s

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The material with the lowest refractive index is air. The correct option is D. Air.

Light waves are a type of electromagnetic wave that travel through space at the speed of light.

In this case, the light wave is traveling through glass and then strikes the boundary with a second medium at a 45° angle, refracting away from the boundary. For the light wave to refract away from the boundary, the second medium must have a lower refractive index than glass.

Out of the options given, the material with the lowest refractive index is air. Therefore, the correct answer is D. Air.

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The suggestion for communicating with a seriously ill two year old child is A. Provide maximum physical relief and comfort.

When a child is sriosly ill, it is very neccessary for the parent as ll as th caregiver to make the move to seek for the best way to relief the child.

However suggestion for communicating with a seriously ill two year old child can be seen in he act of giving out maximum physical relief  which coud be from the caregiver as ell as the parent so that th child will be be freed from the sickness.

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After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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