witch number is the one tenth the value of 26,000

Step-by-step explanation:

8x13 kkkxkgkgxkgxkkkxkkk

Answer:

108

Step-by-step explanation:

When the lines cut through by a transversal are parallel, alternate interior angles are congruent. angle 4 = angle 6 = 108

For the fractions, the calculation of 3/5 of 2/3 of 3/4 of 560 is equal to 168.

To calculate 3/5 of 2/3 of 3/4 of 560, break it down step by step:

Step 1: Calculate 3/4 of 560:

3/4 × 560 = (3 × 560) / 4 = 1680 / 4 = 420

Step 2: Calculate 2/3 of the result from Step 1:

2/3 × 420 = (2 × 420) / 3 = 840 / 3 = 280

Step 3: Calculate 3/5 of the result from Step 2:

3/5 × 280 = (3 × 280) / 5 = 840 / 5 = 168

Therefore, 3/5 of 2/3 of 3/4 of 560 is equal to 168.

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6 tables are required. Each prime number attender should serve 3 customers each.

The prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97.

All the numbers other than prime numbers are composite numbers.

The composite numbers from 1 to 100 are: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.

Now, as there are 25 primes and 75 composites in the group that visited the restaurant, we can calculate the number of tables required by dividing the number of people by the seating capacity of each table.

Each table has a seating capacity of 15, so the number of tables required will be: Number of tables = (Number of customers)/(Seating capacity of each table)Number of customers = 25 (the number of primes) + 75 (the number of composites) = 100Number of tables = 100/15 = 6 tables

Therefore, 6 tables are required.

Now, as each prime number attender has to serve an equal number of customers, we need to calculate how many customers each one should serve.

Each prime attender has to serve 75/25 = 3 customers each, as there are 75 composites and 25 primes.

Thus, each prime number attender should serve 3 customers each.

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(i) This allocation satisfies the condition for efficiency because there is no other allocation that can make one agent better off without making another agent worse off.
(ii) This allocation is envy-free because neither agent would prefer the allocation of the other agent to their own.

(iii) This allocation satisfies both the conditions for efficiency and envy-free, as neither agent would prefer the allocation of the other agent to their own and there is no other allocation that can make one agent better off without making another agent worse off.

An allocation is Pareto efficient if there is no other allocation that can make one agent better off without making another agent worse off. Similarly, an allocation is envy-free if no agent would prefer the allocation of another agent to their own.

(i) A Pareto efficient allocation would be one where Agent A receives 10 units of x and Agent B receives 5 units of y. This allocation satisfies the condition for efficiency because there is no other allocation that can make one agent better off without making another agent worse off.

(ii) An envy-free allocation other than equal division would be one where Agent A receives 7 units of x and 2 units of y, and Agent B receives 3 units of x and 3 units of y. This allocation is envy-free because neither agent would prefer the allocation of the other agent to their own.

(iii) To identify an envy-free and efficient allocation, we can solve the problem graphically. We can draw the indifference curves for each agent and find the maximum indifference curve attainable for each agent given the indifference curve for the other agent. For Agent A, the maximum attainable indifference curve is where they receive 10 units of x and 0 units of y. For Agent B, the maximum attainable indifference curve is where they receive 0 units of x and 5 units of y. The vertices of these indifference curves lie at (10, 0) and (0, 5), respectively. Each agent's expansion path is the set of all of its vertices, which are (10, 0) for Agent A and (0, 5) for Agent B. An envy-free and efficient allocation would be one where Agent A receives 8 units of x and 1 unit of y, and Agent B receives 2 units of x and 4 units of y. This allocation satisfies both the conditions for efficiency and envy-free, as neither agent would prefer the allocation of the other agent to their own and there is no other allocation that can make one agent better off without making another agent worse off.

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On solving the provided question, by the help of BODMAS we can say that - Subtract 22 from both sides is the answer to the given question.

BODMAS and PEDMAS are both names for it in various places. This stands for exponents, parenthesis, division, multiplication, addition, and subtraction. The BODMAS rule states that parentheses must be answered before powers or roots (that is, of), divisions, multiplications, additions, and lastly subtractions. The BODMAS rule states that the degree (52 = 25), parenthesis (2 + 4 = 6), any division or multiplication (3 x 6 (bracket response) = 18), and any addition or subtraction (18 + 25 = 43) come before any other operations.

\(f/3 +22 = 17\)

\(f/3 +22 -22 = 17 -22\) Subtracting the same value from both sides keeps the equation equal.  

Then simplify. The \(+22 and -22= 0\) They "cancel"   \(17-22 = -5\)

\(f/3 = -17 f/3\) is now isolated-- by itself-- in the equation.

If we have to solve  f, the next step we to take is to multiply on the both sides by  3.

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Its a weird problem but I think u should use formula:

(a+b)^2=a^2+2ab+b^2

5(q+p+3)=5q+15+5p=(√5q+√5p)^2

it is only thing u can do.

To solve this problem, we need to find the lengths of the two pieces when the wire is cut into two parts. Let's denote the length of each leg of the triangle as\(\(x\).\)

The perimeter of the triangle is the sum of the lengths of its three sides. Since the two legs are equal in length, the perimeter can be expressed as \(\(2x + x = 3x\).\)

The length of the wire is given as 71 cm, so we have the equation \(\(3x = 71\).\)

Solving for\(\(x\),\) we divide both sides of the equation by 3:

\(\(x = \frac{71}{3}\).\)

Now that we know the length of each leg of the triangle, we can proceed to the next part of the problem.

The circumference of a circle is given by the formula \(\(C = 2\pi r\)\), where\(\(C\)\)is the circumference and r is the radius. In this case, the wire of length xis bent into the shape of a circle, so we can set the circumference equal to x and solve for the radius r:

\(\(x = 2\pi r\).\)

Substituting the value of x we found earlier, we have:

\(\(\frac{71}{3} = 2\pi r\).\)

Solving for r, we divide both sides of the equation by \(\(2\pi\):\)

\(\(r = \frac{71}{6\pi}\).\)

Therefore, the two pieces of wire will have lengths\(\(\frac{71}{3}\)\)cm and the radius of the circle will be\(\(\frac{71}{6\pi}\)\) cm.

In summary, when the 71 cm wire is cut into two pieces, one piece will have a length o\(\(\frac{71}{3}\)\)cm, which can be bent into the shape of an equilateral triangle with legs of equal length, and the other piece can be bent into the shape of a circle with a radius of \(\(\frac{71}{6\pi}\)\) cm.

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The greatest common divisor of 5! and 7! is 840.

To find the greatest common divisor (GCD) of 5! and 7!, we need to calculate the prime factorization of both numbers.

First, let's calculate the prime factorization of 5!:

5! = 5 * 4 * 3 * 2 * 1 = 120.

The prime factorization of 120 is 2^3 * 3 * 5.

Now, let's calculate the prime factorization of 7!:

7! = 7 * 6 * 5! = 7 * 6 * 120 = 5040.

The prime factorization of 5040 is 2^4 * 3^2 * 5 * 7.

To find the GCD of 5! and 7!, we need to find the common factors in their prime factorizations. We take the smallest exponent for each prime factor that appears in both factorizations.

From the prime factorizations above, we can see that the common factors are 2^3, 3, 5, and 7. Multiplying these factors together gives us:

GCD(5!, 7!) = 2^3 * 3 * 5 * 7 = 8 * 3 * 5 * 7 = 840.

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Answer:

22m

Step-by-step explanation:

You're welcome, just trust me it's right.

The vertex of point A' in the dilated triangle A'B'C' is (6, 4.5).

1. Start by calculating the distance between the vertices of the original triangle ABC:

  - Distance between A(4, 3) and B(3, -2):

    Δx = 3 - 4 = -1

    Δy = -2 - 3 = -5

    Distance = √((-\(1)^2\) + (-\(5)^2\)) = √26

  - Distance between B(3, -2) and C(-3, 1):

    Δx = -3 - 3 = -6

    Δy = 1 - (-2) = 3

    Distance = √((-6)² + 3²) = √45 = 3√5

  - Distance between C(-3, 1) and A(4, 3):

    Δx = 4 - (-3) = 7

    Δy = 3 - 1 = 2

    Distance = √(7² + 2²) = √53

2. Apply the scale factor of 1.5 to the distances calculated above:

  - Distance between A' and B' = 1.5 * √26

  - Distance between B' and C' = 1.5 * 3√5

  - Distance between C' and A' = 1.5 * √53

3. Determine the coordinates of A' by using the distance formula and the given coordinates of A(4, 3):

  - A' is located Δx units horizontally and Δy units vertically from A.

  - Δx = 1.5 * (-1) = -1.5

  - Δy = 1.5 * (-5) = -7.5

  - Coordinates of A':

    x-coordinate: 4 + (-1.5) = 2.5

    y-coordinate: 3 + (-7.5) = -4.5

4. Thus, the vertex of point A' in the dilated triangle A'B'C' is (2.5, -4.5).

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Answer:

a) 0.3125 per hour

b) 2.225 hours

c) 8.9 hours

d) 12.1 hours

e) 80%

Step-by-step explanation:

Given that:

mean time = 3.2 hours, standard deviation (σ) = 2 hours

The  mean service rate in jobs per hour (λ) = 2 jobs/ 8 hour = 0.25 job/hour

a) The average number of jobs waiting for service (μ)= 1/ mean time = 1/ 3.2 = 0.3125 per hour

b) The average time a job waits before the welder can begin working on it (L) is given by:

\(L=\frac{\lambda^2\sigma^2+(\lambda/\mu)^2}{2(1-\lambda/\mu))} =\frac{0.25^2*0.2^2+(0.25/0.3125)^2}{2(1-0.25/0.3125)}=2.225\ hours\)

c) The average number of hours between when a job is received and when it is completed (Wq) is given as:

\(W_q=\frac{L}{\lambda}=2.225/0.25=8.9\ hours\)

d) The average number of hours between when a job is received and when it is completed (W) is given as:

\(W=W_q+\frac{1}{\mu} =8.9+\frac{1}{0.3125}=12.1 \ hours\)

e) Percentage of the time is Gubser's welder busy (P) is given as:

\(P=\frac{\lambda}{\mu}=0.25/0.3125=0.8=80\%\)

Answer:

\(T = 600\)

Step-by-step explanation:

Represent the table with T, couch with C an umbrella with U

We have the following:

\(2C + U + T = 1875\)

\(C + T = 1075\)

\(2C + U = 1275\)

Required

Determine the cost of a table

Make T \(the\ subject\\) \(in\ the\) first equation

\(T = 1875 - (2C + U)\)

In the third equation, we have that: \(2C + U = 1275\)

By substituting 1275 for 2C + U

\(T = 1875 - (2C + U)\) becomes

\(T = 1875 - 1275\)

\(T = 600\)

Hence, a table costs $600

The degree of the polynomial is 14

The polynomial is given as:

y^2+7x^14-10x^2

Here, we assume that the variable of the polynomial is x

The highest power of x in the polynomial y^2+7x^14-10x^2 is 14

Hence, the degree of the polynomial is 14

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Answer:

x = 10.6

Step-by-step explanation:

Use trig functions

In this case you would use sin

so it would be sin(62) = x/12

multiply 12 on both sides to isolate the x and ur left with approximately 10.6

The table that represents a linear equation is the first one, and the line can be:

y = -4x - 1

A general linear function can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Now, notice that if we evaluate the line in x + 1, we will get:

y = a*(x + 1) + b

y = a*x + a + b

So, for an increase of one unit on the variable x, we have a constant increase in the y value.

Now, if you look at the first table, you can see that for each increase of 1 unit on the value of x, the value of y decreases by 4.

So that is the table that can represent a linear function.

And the line is:

y = -4x - 1

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Answer:

Y=X+3

Step-by-step explanation:

Answer:

B 49/3

Explanation:

I did the work, unlike your lazy ahh! :)

The inequality represented by the graph is given as follows:

y > 3x - 4.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which:

The graph crosses the y-axis at y = -4, hence the intercept b is given as follows:

b = -4.

When x increases by 1, y increases by 3, hence the slope m is given as follows:

m = 3.

Hence the equation of the line is:

y = 3x - 4.

The inequality is composed by the values to the right (greater) of the line, and has an open interval due to the dashed line, hence:

y > 3x - 4.

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Answer:

A

Step-by-step explanation:

To simplify the expression 3 11 5 ÷ 3 − 9 5, let's break it down step by step:

First, let's simplify the division 3 11 5 ÷ 3:

3 11 5 ÷ 3 = (3 × 115) ÷ 3 = 345 ÷ 3 = 115.

Next, let's subtract 9 5 from the result we obtained:

115 - 9 5 = 115 - (9 × 5) = 115 - 45 = 70.

Therefore, the simplified expression is 70.

The correct answer is A. 70.

Tthese three values from least to greatest is 41. 43 and 51

Percentage can be defined as the fraction of a number and 100.

It is represented with the symbol, %.

From the information given, we have that;

This is represented as;

60/100 × 80

Multiply the values

48

82/100 × 50

Multiply the values

41

170/100 × 30

Mutiply the values

51

Hence, the values are 41, 48 and 51

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Step-by-step explanation:

you can find the answer by vertical opposite angle

if the value of x is computed and it's equal to 78 you will find the answer

78=(12x+18)^

78=(12×5+18)

78=(60+18)

78=78 the problem is solved

may u get branliest please please

The expression to represent how much Jamie spends in all. we may state,0.40x + 0.40y is 8, 0.30x + 0.30y is 6

Set variables to represent the amounts we wish to identify.

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The p-value for the given information is 0.247.

The p value refers to a number which is calculated from a statistical test and describes how likely a researcher is to have found a particular set of observations if the null hypothesis were true.

According to the provided information,

Sample size, n = 100

Sample proportion p’ = 47/100 = 0.47

The null hypothesis is: H0 - p = 0.5

The alternative hypothesis is: Ha - p > 0.5

Probability to be tested p = 0.5

Standard deviation = √p(1 – p)/n = √0.5(1 - 0.5)/100 = 0.05

z-test statistics is given by

z = (p’ – p)/σ = (0.47 – 0.5)/0.05 = - 0.6

From the table,

P value = 0.247

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Answer:

The area of this triangle is (1/2)(9)(8) = 36.

There is a probability of 94/315 that the problem will be solved.

We are given that P has a chance of solving the problem of 2/7, Q has a chance of solving the problem of 4/7, and R has a chance of solving the problem of 4/9. To find the probability that the problem is solved, we need to consider all possible scenarios in which the problem can be solved.

The probability of this scenario is 2/7. If P solves the problem, then it does not matter whether Q or R solve it, the problem is already solved. Therefore, the probability of the problem being solved in this scenario is 2/7.

The probability of this scenario is 4/7. If Q solves the problem, then it does not matter whether P or R solve it, the problem is already solved. Therefore, the probability of the problem being solved in this scenario is 4/7.

The probability of this scenario is 4/9. If R solves the problem, then it does not matter whether P or Q solve it, the problem is already solved. Therefore, the probability of the problem being solved in this scenario is 4/9.

The probability of this scenario is (1-2/7) * (1-4/7) * (1-4/9) = 3/35. This is because the probability of P not solving the problem is 1-2/7, the probability of Q not solving the problem is 1-4/7, and the probability of R not solving the problem is 1-4/9. To find the probability of none of them solving the problem, we multiply these probabilities together.

To find the probability of the problem being solved, we need to add the probabilities of all the scenarios in which the problem is solved. Therefore, the probability of the problem being solved is:

2/7 + 4/7 + 4/9 = 94/315

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The original annual simple interest rate, rounded to two decimal places, is 3.79%

What is the formula for simple interest?

The simple interest on a loan or deposit is determined as the principal multiplied by the simple interest rate and time

I=PRT

The first loan:

P=12 850.00

R=r(assume it is r)

T=4 years

I=12 850.00*r*4

I=51400r

The second loan was taken after 14 quarters the first was taken out, which is the same as after 3.5 years, hence, the interest on the second loan is only for a half a year

P=3 273.00

R=0.5r( half of the interest on the first loan)

T=0.5 years

I=3 273.00*0.5r*0.5

I= 818.25r

Total interest=51400r+818.25r

Total interest=52218.25r

total interest paid=1 980.00

1 980.00=52218.25r

r=1 980.00/52218.25

r=3.79%

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Answer:

-3

Step-by-step explanation:

Plug in 3 for the X value. -4*3= -12. add 9 and you grt f(x) = -3

Answer:

B is the correct anwser.......