Why would theoretical muzzle velocity be lower than measured muzzle velocity?

Givens.

• The mass of the ballon is 2.30 kg.

• The height is 35.65 m.

First, find the final velocity when the balloon is at the bottom. Use a formula that relates height, initial speed, final speed, and gravity.

Where

• v_0 = 0 because the balloon starts from rest.

• Gravity is g = 9.8 m/s^2.

• h = 35.65 m.

Use all these magnitudes to find the final velocity v_f

Once we have the velocity at the bottom, find the kinetic energy using its formula.

Where m = 2.30 kg, and v = 26.4m.s.

Therefore, the kinetic energy at the bottom is 801.5 J.

Answer:

The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.

Explanation:

Answer:  The car starts moving in the positive direction at x = 0.2 seconds. Initially it moves very little, but it covers a greater distance with each time increment.

Explanation: edmentum sample answer

Answer:

Approximately \(1000 \; {\rm N}\) (assuming that \(g = 10\; {\rm N \cdot kg^{-1}}\).)

Explanation:

The buoyant force on an object is equal to the weight of the liquid that this object has displaced.

In this example, the object displaced \(V = 0.1\; {\rm m^{3}}\) of water. The density of water is \(\rho = 1.00 \times 10^{3}\; {\rm kg \cdot m^{-3}}\). Thus, the mass of the water displaced would be \(m = \rho\, V = 1.00 \times 10^{2}\; {\rm kg}\).

Since \(g = 10\; {\rm N \cdot kg^{-1}}\) by assumption, the weight of that \(m = 1.00 \times 10^{2}\; {\rm kg}\) of water would be \(m\, g = 1.00 \times 10^{3}\; {\rm N}\). Hence, the buoyant force on this object would be \(1.00 \times 10^{3}\; {\rm N}\), which is \(1000\; {\rm N}\) when rounded to one significant figure (as in volume.)

It is reasonable to conclude that science teachers generally agree that practical science is beneficial. Therefore, option (A) is correct.

Practical science refers to hands-on activities, experiments, and applications of scientific concepts in real-world settings. Science teachers, who are experts in their field and experienced in teaching science, understand the importance of practical science in facilitating students' understanding, engagement, and application of scientific principles.

Practical science allows students to develop critical thinking, problem-solving, and inquiry skills, as well as promoting a deeper understanding of scientific concepts. It also fosters curiosity, creativity, and a passion for science, making it an effective and essential component of science education.

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Answer:

conduction

Explanation:

The equal and the opposite force is the person's force of gravity pulls up on the elevator. Option A

We know that the elevator is the kind of device that can be used when we are going up or down a high rise building. We have to note that the elevator that we talking about will also work based on the law of Newton.

We have to note that for every force there is an equal and an opposite force and the same is true when you are using the elevator to move up or down as we can see here.

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Answer:

It will go up to 93.75 m before it is moving at 20 m/s

Explanation:

As we know that

\(v^2 - u^2 = 2aS\)

here v is the final speed i.e 20 m/s

u is the initial speed i.e 5 m/s

a is the acceleration due to gravity i.e 2 m/s^2

Substituting the given values in above equation, we get -

\(20^2 - 5^2 = 2*2*S\\S = 93.75\)meters

To find:

Is the given statement true?

Explanation:

For the electrons to move through a material a certain amount of energy is required. This energy is supplied to them through the work done on them. The potential difference across a material provides the necessary work required to move the electrons.

Thus without the potential difference electrons will not move.

Final answer:

Thus the given statement is true.

The displacement is defined as the shortest distance between the starting and ending point along with the direction. Thus, option D is correct.

The displacement is defined as the shortest distance between the starting and ending point. The displacement is the vector quantity. It is also defined as the distance traveled by the object along with a particular direction. The distance is the scalar quantity and the displacement is the vector quantity. The SI unit of distance is a meter. The rate of change of displacement gives rise to velocity and the rate of distance gives rise to distance.

From, the given displacement is defined as the shortest length and direction from a starting and ending point. Thus, the correct option is D.

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The statement" The direction of the force on the charge placed in the electric field is upward" is false because the direction of the force on a negative charge (-6 C) placed in an upward-directed uniform electric field of magnitude 24 N/C would be downward.

The direction of the force on a charged particle placed in an electric field is determined by the charge of the particle and the direction of the electric field. In this case, a charge of -6 C is placed in an electric field directed upward with a magnitude of 24 N/C.

The force on a charged particle in an electric field can be calculated using the formula:

F = q * E

Where F is the force, q is the charge of the particle, and E is the electric field.

Since the charge q in this case is negative (-6 C) and the electric field E is directed upward, we can substitute the values into the formula:

F = (-6 C) * (24 N/C)

F = -144 N

The negative sign in the force value indicates that the force is in the opposite direction to the electric field. Therefore, the force on the charge placed in the electric field is downward, not upward.

The force on a negative charge is always opposite to the direction of the electric field. This is because negative charges experience an attractive force towards positive charges, and electric fields are directed from positive charges to negative charges.

Therefore, the statement "The direction of the force on the charge placed in the electric field is upward." is false.

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Answer:

A. The frequency decrease

Answer:

it would make 9790 J of energy

Mitosis is an essential mechanism for life, according to a National Human Genome Research Institute publication. A single cell divides into two genetically identical daughter cells during mitosis.

Multicellular organisms require this mechanism for growth, repair, and reproduction.

Because it doesn't use gametes or fertilization to create genetically identical daughter cells, mitosis is a type of asexual reproduction.

"Mitosis is a type of asexual reproduction that is essential for the growth and development of multicellular organisms," the National Center for Biotechnology Information explains.

Because it is essential for tissue growth and repair, mitosis is a vital process for all living things. The growth and repair of tissues as well as some organisms' asexual reproduction depend on mitosis, according to the American Society of Hematology.

Mitosis enables the expansion of tissues throughout development as well as the generation of new cells that can replace harmed or dying cells in the body.

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The athlete must leave the ground with a speed of 6.33m/s.

To calculate the initial speed, with the information of height and final speed, we can use the following expression that uses the kinetic energy and potential energy:

                               \(mgh_1 + \frac{1}{2}mv_1^{2}= mgh_2 + \frac{1}{2}mv_2^{2}\)    

Applying the values ​​given by the statement we have:

                           \(9.81\times 0 + \frac{1}{2}v_1^{2} = 9.81 \times 2 + \frac{1}{2}(0.95)^{2}\)      

                                             \(v_1 = 6.33m/s\)

So, the athlete must leave the ground with a speed of 6.33m/s.

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The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

That depends on the circle's radius, which you neglected to mention.

If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.

If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.

Answer:

4161 J/kg·°C

Explanation:

We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.

Let's first calculate the heat lost by the tea:

Q(tea) = mcΔT

Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)

Q(tea) = 6555 J

where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.

Next, let's calculate the heat gained by the milk:

Q(milk) = mcΔT

Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)

Now we can equate the two expressions:

Q(tea) = Q(milk)

6555 J = (0.02 kg)(c)(79.0°C)

Solving for c, we get:

c = 4161 J/kg·°C

Therefore, the specific heat of milk is approximately 4161 J/kg·°C.

When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.

The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.

Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:

Mass of air = Mass of filled container - Mass of empty container

= 0.428 kg - 0.419 kg

= 0.009 kg

Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:

Volume of air = Volume of perplex box * Number of times air inside

= 1000 cm³ * 7.2

= 7200 cm³

Convert the volume of air to cubic meters (m³) by dividing by 1000000:

Volume of air = 7200 cm³ / 1000000

= 0.0072 m³

Calculate the density of air using the formula:

Density = Mass / Volume

Density = 0.009 kg / 0.0072 m³

≈ 1.25 kg/m³

Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.

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Convergent boundaries occur when two plates move in the opposite direction until they collide and create mountains and volcanoes. In the image, the arrows direction is horizontal and oposite to each other.

Collision area between two plates. The collition might occur between,

When two oceanic plates collide, magma rises to the surface by crevices, creating volcanic arches. In these boundaries occur vertical movements and might originate from protruding areas. There is compressional stress between plates.

In the image, the arrows direction is horizontal and oposite to each other.

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The force of buoyancy acting on the sample is 2.65 N.

If the sample's supporting string is cut, it will float to the surface of the water.

a. The buoyant force acting on the sample can be calculated using the formula Fb = ρVg, where ρ is the density of water, V is the volume of the submerged part of the sample, and g is the acceleration due to gravity. Since the sample is immersed in water, its volume is equal to the volume of water it displaces, which can be calculated using the formula V = l × w × h, where l, w, and h are the dimensions of the submerged part of the sample. Since the sample is cubical, all sides have the same length of 3.0 cm. Thus, the submerged part of the sample has a volume of V = 3.0 cm × 3.0 cm × 3.0 cm = 27.0 cm³ = 0.027 m³. The density of water is ρ = 1000 kg/m³, and the acceleration due to gravity is g = 9.81 m/s². Therefore, the buoyant force acting on the sample is:

Fb = ρVg = 1000 kg/m³ × 0.027 m³ × 9.81 m/s² ≈ 2.65 N

b. The sample will float to the surface of the water if its supporting string is cut. This is because the buoyant force acting on the sample is greater than its weight, which means that there is a net upward force on the sample. This net force causes the sample to accelerate upward, and it will continue to accelerate until it reaches the surface of the water. At the surface, the upward force is balanced by the weight of the sample, and it will float on the water.

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Complete question:

2. Suppose the metal sample in Figure 10.2 is immersed in water, is cubical with side 3.0 cm, and has a mass of 54 g. a. Calculate the buoyant force acting on the sample. b. Describe the behavior of the sample if its supporting string is cut. Explain how you arrive at your answer. balance arm water metal sample water overflow can beaker Figure 10.2 MEASUREMENTS

Tthe force, F, acting upwards on the student's hands during the push-up is 0N.

Since the student is doing a push-up, there is an additional force, F, acting upwards on his hands as he presses against the ground. This force must balance the downward forces for the student to be in equilibrium.

Therefore, the force, F, can be calculated as:

F + Normal force = Weight

F + Normal force = 600N

However, the value of the normal force is equal to the weight of the student since it is acting in the opposite direction. Therefore:

F + 600N = 600N

By solving this equation, we find:

F = 0N

So, the force, F, acting upwards on the student's hands during the push-up is 0N. This implies that the student is not exerting any additional force with their hands and is relying solely on their body weight for the exercise.

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Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.

Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:

You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.

You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.

You could argue that a different reading would imply that the speaker is the one being dumped by her lover.

You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.

But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.

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Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Answer: B

Explanation: A P E X

The sentence best describes how the concentration of the reactant changed is it decreased gradually as the reaction progressed.

The correct option is B.

The chemical reaction is the reaction between two reactants which led to the formation of products.

The products are substances which forms after reaction. The reactants are the substances which are original materials.

This graph shows how the concentration of a reactant changed during a chemical reaction.

The sentence best describes how the concentration of the reactant changed is it decreased gradually  as the reaction progressed.

Thus, the correct option is B.

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The water particles moving perpendicular to the source of the sound wave best describes the direction of the water particles.

These are the types of waves whose oscillations are perpendicular of the wave motion.

A sound wave traveling through water will cause ripples to form which are perpendicular to the source of the sound wave due to it being a transverse wave.

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Answer:

Explanation:

From the question we are told that

    The radius is  \(r = 1.4 \ mm = 1.4 *10^{-3} \ m\)

     The  current is  \(I = 4.5 \ A\)

Generally the electric field is mathematically represented as

         \(E = \frac{J}{\sigma }\)

Where \(\sigma\) is the conductivity of  aluminum with value \(\sigma = 3.5 *10^{7} \ s/m\)

J is the current density which mathematically represented as  

      \(J = \frac{I}{A}\)

Here A is the cross-sectional area which is mathematically represented as  

       \(A = \pi r^2\)

       \(A = 3.142 * (1.4*10^{-3})^2\)

       \(A = 6.158*10^{-6} \ m^2\)

So

    \(J = \frac{ 4.5 }{6.158*10^{-6}}\)

    \(J = 730757 A/m^2\)

So

       \(E = \frac{ 730757}{3.5*10^{7} }\)

       \(E = 0.021 \ N/C\)

The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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