Answer:
That is just the way volume counts units. Using cubic units, it is much easier to find the volume by just counting cubes on a square, for instance.
What is the slope of the line that passes through the points (-9, -9) −6,−12)?
Answer:
m = -1
Step-by-step explanation:
Slope = (y2-y1)/(x2-x1)
Therefore,
slope = (-12-(-9))/(-6-(-9))
= -3/3
=-1
according to city reports, it was found that the mean age of the prison population in the city was 26 years. marc wants to test the claim that the mean age of the prison population in his city is less than 26 years. he obtains a random sample of 25 prisoners and finds a mean age of 24.4 years and a standard deviation of 9.2 years. at a significance level of 0.05, what should his conclusion be? note: the p-value
The value of P0.05 < 0.19658. We do not reject the null hypothesis. There is not sufficient evidence that the mean age is less than 26 years.
According to the question we will set up Hypothesis
Null, H0: U=26
Alternate, H1: U<26
Test Statistic
Population Mean(U)=26
Sample X(Mean)=24.4
Standard Deviation(S.D)=9.2
Number (n)=25
we use Test Statistic (t) = x-U/(s.d/√(n))
to =24.4-26/(9.2/√(25))
to =-0.87
| to | =0.87
Critical Value
The Value of |t α| with n-1 = 24 d.f is 1.711
We got |to| =0.87 & | t α | =1.711
According to this, we have to make a decision
Hence Value of |to | < | t α |
P-Value: Left Tail -Ha : ( P < -0.8696 ) = 0.19658
Hence Value of P0.05 < 0.19658
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Need help ASAP. For Finals
Answer:
a. \(50b + 250 \leq 3000\)
b. 55 boxes
c. 5 trips
Step-by-step explanation:
a. Each box weighs 50lbs and the number of boxes is our variable. If you add the worker's weight (180) and the cart's weight (70) you get a constant weight of 250. All of this cannot weigh more than 3000, therefore it can weigh equal to or less than it. Therefore, the equation is \(50b + 250 \leq 3000\).
b. Solve the equation to find the maximum amount of boxes that he can move in one trip, like this:
\(50b + 250 \leq 3000\\50b \leq 2750\\b \leq 55\)
Therefore, the greatest number of boxes that the worker can move is 55 boxes.
c. Divide the total number of boxes (275) by the amount of boxes that can be taken in one trip (55) to find how many trips it will take. Like this:
275/55 = 5
The worker needs to make 5 trips in order to deliver 275 boxes.
I hope this helps!!
- Kay :)
Answer:
a.) 3000 *no more than symbol* 180 + 70 +50b
What is 5x-3 equal to
Answer:
-15
Step-by-step explanation:
Answer:
-15 hdbdudbdjsbakznzbzjzbzbz
In the figure below, =m∠EBD 23°, BC bisects ∠ABD, and BE bisects ∠CBD. Find m∠ABC.
The value of m∠ABC is 46°.
We know that BC bisects ∠ABD. Therefore, m∠CBD = m∠ABD = 23° *4 = 92°.
We also know that BE bisects ∠CBD.
Therefore, m∠EBD = m∠EBC + m∠CBD. Since we know that m∠EBD = 23°
and m∠CBD = 2*m∠EBD = 46°,
we can solve for m∠EBC:
23° = m∠EBC°
m∠EBC = 23°
Now we can find m∠ABC:
m∠ABC = m∠ABD - m∠CBD = 92° - 46° = 46°
Therefore, m∠ABC is 46°.
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The second angle of the triangle is 25 degrees larger than the first, while the third angle of the triangle is 3 times the second. How big is the first angle? Remember, the sum of the angles in any triangle is 180 degrees.
Answer: look at the image for the answer and the explanation
Step-by-step explanation:
Answer: 16 degrees
Step-by-step explanation:
Let X and Y denote the tarsus lengths of male and female grackles, respectively. Assume that X is N(,) and Yis N(4,²). Given that the sample number of X and Y are n=m=25, and X = 33.8, S=3.9,Y=32.5, S=5.1. Use these observations to give a level a=0.05 test for H₁:μx = μy VS Hoxy. Give the p-value of this test. (10 pts)
To test the hypothesis H₁: μx = μy versus Hoxy, where μx and μy represent the means of X and Y respectively, we can perform a two-sample t-test. The test compares the means of two independent samples to determine if they are significantly different from each other.
The given information provides the sample means (X = 33.8, Y = 32.5) and the sample standard deviations (Sx = 3.9, Sy = 5.1). The sample sizes for both X and Y are n = m = 25.
Using this information, we can calculate the test statistic, which is given by:
t = (X - Y) / sqrt((Sx^2 / n) + (Sy^2 / m))
Plugging in the values, we get:
t = (33.8 - 32.5) / sqrt((3.9^2 / 25) + (5.1^2 / 25))
Next, we need to determine the degrees of freedom for the t-distribution. Since the sample sizes are equal (n = m = 25), the degrees of freedom for the test is given by (n + m - 2).
Using the t-distribution table or software, we can find the critical value corresponding to a significance level of α = 0.05 and the degrees of freedom.
Finally, we compare the calculated test statistic with the critical value. If the test statistic falls within the rejection region (i.e., the absolute value of the test statistic is greater than the critical value), we reject the null hypothesis. The p-value can also be calculated, which represents the probability of observing a test statistic as extreme or more extreme than the calculated value, assuming the null hypothesis is true.
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Find the value of x in each case. PLEASE HELP
Answer:
x = 23
Step-by-step explanation:
∠ ABE = ∠ BEF = 4x ( alternate angles )
Since DBF is a straight line then the 3 angles sum to 180°, that is
x + 4x + 65 = 180
5x + 65 = 180 ( subtract 65 from both sides )
5x = 115 ( divide both sides by 5 )
x = 23
Someone please help me I’m stuck with this question
Answer:
second one
Step-by-step explanation:
Three triangles are shown on the centimetre grid.
A
B
C
(a I already did)
b)
Work out the area of this triangle.
Give your answer as a decimal.
Answer:
C has the largest area. It is 4.5 square units.
Step-by-step explanation:
A:
area = bh/2 = 2 * 3/2 = 3
B:
area = bh/2 = 2 * 3/2 = 3
C:
area = bh/2 = 3 * 3/2 = 4.5
C has the largest area. It is 4.5 square units.
Peter is going to carpet a room that measured 9 x 13 feet. The carpet costs $18.75 a square foot. How much will peter spend
Answer:
$2193.75
Step-by-step explanation:
9 times 13
times 18.75
what is the differents between 3/4 and 1 1/2
Answer:
1 1/12 has part of a whole number but 3/4 doesn't have a whole number.
Step-by-step explanation:
1 1/12 is also greater than 3/4
Answer:
3/4 is the difference
Step-by-step explanation:
A tree casts a 249 centimeter shadow. A person next to the tree casts a 91 centimete
shadow. If the person is 169 centimeters tall, how tall is the tree to the nearest
centimeter?
what is the answer?
x+y=15
-2x+5y=-2
(x-3)^3+3-x giup tôi với
Answer:3 tháng 8 lúc 13:04. Tìm x. a) (4x-1)²-(4x-5)(4x+5)=3. b) (x+2)³-(x³+8)=0. Đọc tiếp... Toán lớp 8. 1. んuリ イ ( ✎﹏IDΣΛ亗 ) CTV. 3 tháng 8 lúc 16:17.
Step-by-step explanation:
an air plane is flying at a height of 6 miles on a flight path that will take it directly over a radar tracking station. the distance d between them is decreasing at a rate of 400 miles per hour when the distance between them is 10 miles. what is the speed of the plane?
500 mph is the speed of the plane.
This creates a right triangle, with the distance between the plane and the radar station serving as the hypotenuse (s). Let y represent the plane's height and x represent its flight route.
s2 = y2 + x2
Given: the constant value of y = 6
negative since decreasing, ds/dt = -400
Trying to locate dx/dt
Taking the implicit derivative of the above equation's two sides
0 + 2xdx/dt = 2sds/dt
(S/X) ds/dt = dx/dt
When x = 8
s = √(62+82) = √100 = 10
dx/dt = (10/8)(-400) = -500 mph, or 500 mph traveling toward the radar station at a distance of 6 miles.
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The radius of a circle is 4 m. Find its area in terms of
π
π.
Answer:
16π
Step-by-step explanation:
Given:
\(\text{Radius of circle}: 4 \ \text{m}\)
Formula:
\(\text{Area of circle} = \pi r^{2}\)
Replace the radius in the formula:
\(\implies \text{Area of circle} = \pi (4)^{2}\)
Evaluate the area:
\(\implies \text{Area of circle} = \pi (4)(4)\)
\(\implies \text{Area of circle} = 16\pi\)
Since the question says to determine the area in terms of π, the final answer is 16π.
a ramp goes from a doorway of a building to the ground. the end of the ramp connected to the doorway is foot above the ground. the horizontal distance from the bottom of the ramp to the building is feet. what is the angle of elevation of the ramp to the nearest degree?
On the basis of given informations and values the angle of elevation of the ramp is calculated to be approximately 22 degrees.
We can use the tangent function to find the angle of elevation of the ramp. Let's call the height of the ramp "h" and the horizontal distance from the bottom of the ramp to the building "d". Then the tangent of the angle of elevation θ is given by:
tan θ = h/d
Substituting the given values, we get:
tan θ = 6/15
Simplifying this expression, we get:
tan θ = 0.4
To find the angle θ, we can take the inverse tangent (or arctan) of both sides of the equation:
θ = tan⁻¹ (0.4)
Using a calculator, we get:
θ ≈ 21.8 degrees
Therefore, the angle of elevation of the ramp to the nearest degree is 22 degrees.
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Which statement about 192° is correct?
A.
tan 192° < 0
B.
cos 192° > 0
C.
sin 192° < 0
Answer:
Step-by-step explanation:
192° is in quadrant III, so sin(192°) < 0, cos(192°) < 0, tan(192°) > 0
Answer:
C. sin 192° < 0
Step-by-step explanation:
see image below
an spc chart shows that a process has an overall average measurement of 12.5 and an average moving range of 0.5. what are the control limits for the x chart? a ucl
The Upper Control Limit (UCL) for the X-chart is approximately 14.028.
To calculate the control limits for the X-chart (also known as the process mean chart) in a Statistical Process Control (SPC) chart, we need the average moving range (MR-bar).
The control limits for the X-chart can be determined using the following formulas:
\(Upper $ Control Limit (UCL) = X-double-bar + A2 \times MR-bar\)
\(Lower $ Control Limit (LCL) = X-double-bar - A2 \times MR-bar\)
In these formulas:
X-double-bar represents the overall average measurement.
MR-bar represents the average moving range.
A2 is a constant that depends on the sample size.
The value of A2 can be obtained from statistical tables or calculated using the following formula for sample sizes greater than or equal to 2:
\(A2 = 3.267 - (0.15 \times \sqrt{(N)} )\)
In your case, the overall average measurement is 12.5, and the average moving range is 0.5.
Assuming you have a sample size greater than or equal to 2, we can calculate the value of A2 as follows:
\(A2 = 3.267 - (0.15 \times \sqrt{(N)} )\)
\(= 3.267 - (0.15 \times \sqrt{(2)} ) (assuming N = 2, the $ minimum sample size)\)
\(\approx 3.267 - (0.15 \times 1.414)\)
≈ 3.267 - 0.2121
≈ 3.0559
Now, we can calculate the control limits for the X-chart:
\(UCL = X-double-bar + A2 \times MR-bar\)
\(= 12.5 + 3.0559 \times 0.5\)
= 12.5 + 1.52795
≈ 14.028
Therefore, the Upper Control Limit (UCL) for the X-chart is approximately 14.028.
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How many integers between 2020 and 2400 have four distinct digits arranged in increasing
order? (For example 2957 is one such integer)
(B) 10
(C) 15
(D) 21
e 28
Answer:
the answer is E
Step-by-step explanation:
We want to find how many integers are between 2020 and 2400 such that a criteria is meet, and the criteria is that the four digits are different and are arranged in increasing order.
We will see that there are 15 of these numbers between 2020 and 2400, so the correct option is C.
---------------------------
To count the number of digits that meet the given criteria, we first need to analyze how the criteria is.
If the numbers must be in increasing order, then the smallest number that can be in the hundreds place is 3 (the smaller integer larger than 2).
so we have:
23__
The number next to the 3 can be a 4, for example:
234_
And the final number can be any number larger than 4, so we have {5, 6, 7, 8, 9} a total of 5 options.
If instead of a 4, the number next to the 3 is a 5, we have:
235_
And the number next to the five can be any digit larger than 5, so now we have 4 options.
If instead of a 5, we have a 6, we will have 3 options to put after the 6.if instead of a 6, we have a 7, we will have 2 optionsif instead of a 7, we have an 8, we will have 1 option.Now, we can't have another number than a 3 in the hundreds place, because if we put a 4 there, we are out of the range, and 3 is the smallest digit that we can use there.
Then we already saw all the possible numbers that we can make, adding the numbers of options that we got above we will get:
5 + 4 + 3 + 2 + 1 = 15
This means that are 15 of these numbers between 2020 and 2400. Then the correct option is C.
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Which of these equations are linear functions that go
through the point (0, 6)? Explain your reasoning.
y = 6x
y = x + 6
y = x2 +6
y = 2x + 6
Answer:
its B: Y= x + 6
Step-by-step explanation:
hope this helps
What is the measure of ∠R?
Answer:
∠ R ≈ 36.9°
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos R = \(\frac{adjacent}{hypotenuse}\) = \(\frac{RT}{RS}\) = \(\frac{8}{10}\) , thus
∠ R = \(cos^{-1}\) (\(\frac{8}{10}\) ) ≈ 36.9° ( to 1 dec. place )
Assume y varies directly with x . If y=-3 when x=-2/5, what is x when y is 45 ?
Using the constant proportionality we get the value of x as 6 when y is 45.
Given that y varies directly with x.
If y=-3 when x=-2/5, then we can find the constant of proportionality by using the formula:
`y = kx`.
Where `k` is the constant of proportionality.
So we have `-3 = k(-2/5)`.To solve for `k`, we will isolate it by dividing both sides of the equation by `(-2/5)`.
Therefore we get `k = -3/(-2/5) = 7.5`
Now we can find x when y = 45 using the formula `y = kx`.
Therefore, `45 = 7.5x`.To solve for `x`, we will divide both sides by 7.5.
Therefore, `x = 6`.So when y is 45, x is 6. Hence, the answer is `6`.
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A fair 6-sided die is rolled 300 times. What is a reasonable prediction for the number of times the event of landing on an odd number will occur?
A. 150
B. 50
C. 175
D. 100
Answer:
A. 150
Step-by-step explanation:
Calculate the probability of landing on an odd number: 1/2.
Multiply the probability by the number of trials: (1/2) * 300.
Simplify the expression: 150.
Therefore, a reasonable prediction is that the event of landing on an odd number will occur 150 times out of the 300 rolls of the fair 6-sided die.
Which of the type directions lie in the (110) plane? [101] [110] [o īl] (110
The type directions that lie in the (110) plane are Crystal planes are equivalent planes that represent a group of crystal planes with a common set of atomic indexes.
Crystallographers use Miller indices to identify crystallographic planes. A crystal is a three-dimensional structure with a repeating pattern of atoms or ions.In a crystal, planes of atoms, ions, or molecules are stacked in a consistent, repeating pattern. Miller indices are a mathematical way of representing these crystal planes.
Miller indices are the inverses of the fractional intercepts of a crystal plane on the three axes of a Cartesian coordinate system.Let us now determine which of the type directions lie in the (110) plane.[101] is not in the (110) plane because it has an x-intercept of 1, a y-intercept of 0, and a z-intercept of 1. So, this direction does not lie in the (110) plane.[110] is in the (110) plane since it has an x-intercept of 1, a y-intercept of 1, and a z-intercept of 0.
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Solve
X =
4-x
(21/7) ¹-*
-x = 92x-1
Answer:
☆ -10 ☆ is your correct answer!
5 1/4 divided by 5/8
Answer: 8.5
Step-by-step explanation: we was doing this in class
Answer:
8.4
Step-by-step explanation:
Center middle school open the boys basketball team has had the same record every season the team has won a total of 84 games while losing only six games find the constant of a personality of winds to loses
The constant of Proportionality of wins to loses is 12.
Given, The total no. of games won by team is 84 and the team loses 6 games in the season.
When two or more parameters are directly or indirectly proportional to one another, their relationship is expressed as a = kb or a = k/b, where k indicates how the two variables are related. This k is known as the proportionality constant.
So, let a = Total no. of games won by team
and b = no. of games lost by team
So, proportionality constant (k) = Total no. of games won by team(a) / no. of games lost by team(b)
k = 84/6
k = 12.
Hence, the proportionality constant is 12.
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evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.
We have
\(\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt\)
and
\(\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k\)
\(\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k\)
so the line integral is equilvalent to
\(\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt\)
\(\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt\)
\(\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt\)
\(\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}\)
\(\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}\)