Why is it important to know gas properties at STP?

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

Answer:

0.725 kg

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the softball

We will use the following expression.

K = 1/2 × m × v²

m = 2 K / v²

m = 2 × 145 J / (20.0 m/s)²

m = 0.725 kg

The mass of the softball is 0.725 kg.

Answer:

A) Using the ideal gas law, we can calculate the number of moles of gas present:

```

PV = nRT

```

where:

* P = pressure (atm) = 1 atm

* V = volume (L) = 5.6 L

* n = number of moles of gas

* R = ideal gas constant = 0.08206 L atm / mol K

* T = temperature (K) = 273.15 K

Solving for n, we get:

```

n = (P * V) / RT

```

```

n = (1 atm * 5.6 L) / (0.08206 L atm / mol K * 273.15 K)

```

```

n = 0.25 mol

```

Therefore, there are 0.25 moles of gas present.

B) The molar mass of the gas can be calculated by dividing the mass of the gas (8.0 g) by the number of moles of gas (0.25 mol):

```

Molar mass = Mass / n

```

```

Molar mass = 8.0 g / 0.25 mol

```

```

Molar mass = 32 g/mol

```

The molar mass of the gas is 32 g/mol.

C) The common atmospheric gas with a molar mass of 32 g/mol is oxygen (O2). Therefore, the gas that was collected is oxygen.

Explanation:

Answer: D

Explanation:

The reason it is D is because a balanced chemical equation will always have the same number of atoms on both sides. In answer d, both sides have a total of 4 atoms, so it it balanced.

Answer:

amine

Explanation:

We have to bear in mind that amines are basic compounds. This idea will be very important in attempting to answer this question.

So, when she adds 5% HCl solution in order to extract the organic layer, the amine forms a hydrochloride salt which is contained in the aqueous layer.

The addition of a base such as NaOH leads to the formation of a white precipitate of the amine.

Answer:

y = 2x pv = 13 z = (2/x) 4 = (y/x) h = (9g/5) Inverse variation is represented by the equation y = k/x, where k is a constant.

The value of S2 is S₂ = 2.1 g/L.Approximately 2.1 g of the gas will dissolve in 2 L of water at 0.6 ATM, assuming the temperature remains constant.

To determine the amount of gas that will dissolve in 2 L of water at 0.6 ATM, we can use Henry's law, which states that the solubility of a gas is directly proportional to the partial pressure of the gas above the liquid.

According to Henry's law, the solubility of a gas can be represented as:S₁/P₁ = S₂/P₂,,where S₁ and S₂ are the solubilities of the gas at the respective pressures P₁ and P₂.Given that 7 g of the gas dissolves in 1 L of water at 2.0 ATM, we can consider this as our initial condition, denoted by S₁/P₁.

Now, we need to find the solubility at 0.6 ATM in 2 L of water, denoted by S₂/P₂.Since the temperature remains constant, we can assume that the solubility of the gas does not change. Therefore, we can rewrite the equation as:

S₁/P₁ = S₂/P₂,

Substituting the known values, we have:

(7 g/1 L)/(2.0 ATM) = S₂/(0.6 ATM),

Solving for S₂, we get:

S₂ = (7 g/1 L) * (0.6 ATM)/(2.0 ATM),

S₂ = 2.1 g/L.

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The mole ratio that can be used to obtain the amount of the CuO formed from 3.95 g of oxygen is 2 mol CuO/3 mol O2.

Mole ratio is the ratio in moles of any two compounds that participate in a chemical reaction. It is determined by balancing a chemical equation and looking at the coefficients in front of each compound.

Mole ratios are used in stoichiometric calculations to determine the amount of one substance that reacts with another based on a balanced equation.

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When scientists say that a theory can never be proven, they mean that it is not possible to conclusively demonstrate its truth. The word "theory" in science refers to a body of knowledge that has been well-established through rigorous testing and observation. However, this does not mean that it is an absolute truth.

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In this question, we have a dilution situation, in which we have an amount of volume of a solution, and we are diluting it with more water, which will then cause the concentration of the substance to decrease.

We have 100 mL and 12% KCl, which for a better understanding we can read 12 grams of KCl

We are adding 200 mL:

100 mL = 12 % or grams

300 mL = x % or grams

100x = 0.04

x = 0.04/100

x = 4.0%, therefore the correct answer will be letter E

The mass percentage is an important method to determine the concentration of a solution. Here among P₂O₃ and P₂O₅, the oxide P₂O₃ contains higher percentage of phosphorous.

The mass percentage of a component can be defined as the ratio of the mass of that particular component in the compound to the total mass of the compound. It can be expressed as:

Mass percentage = Mass of the component / Total mass of the component × 100

Molar mass of P₂O₃ = 110 g/mol

Molar mass of P₂O₅ = 142 g/mol

a. % of 'P' in P₂O₃ = 2 × 31 / 110 × 100 = 56.4 %

   % of 'P' in P₂O₅ = 2 × 31 / 142 × 100 = 43.66 %

Thus P₂O₃ has higher percentage of 'P'.

b. 1 mol O₂ × 4 P /3 O₂ × 31.0 P / 1 mol P = 41.3 g P

c. P₄O₁₀

d. Aluminium oxide - Al₂O₃

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hope it helps:)

\(a. \: Ca + Cl _{2} → CaCl _{2} \\

\\ b. \: Cl _{2}+H _{2} O+ NaOH → \\ NaCl+ H _{2}O \\ \\

c. \: \: \: H _{2} SO _{4} +CaCO _{3} → \\ CaSO _{4} +H _{2}O+CO _{2} \\ \\

d. \: \: Fe+Cu(NO _{3}) _{2} → \\ Fe(NO _{3} ) _{2}+Cu\)

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The compound would have a molecular formula of C5H10O2.

The empirical formulas is the simplest formula of a compound.

We know that;

Mass  of the carbon = 14.03 * 12/44 = 3.82 g

Moles of C = 3.82 g/12 g/mol = 0.32 moles

Mass of water = 3.83 * 2/18 = 0.43 g

Moles of H =  0.43 g/1 g/mol =  0.43  moles

Mass of oxygen = 8.5 - (3.82 + 0.43)

= 4.25 g

Moles of oxygen = 4.25 g/16 g/mol = 0.27 moles

We can now divide through by the lowest ratio;

C - 0.32    H - 0.43    O - 0.27

C - 1   H - 2  O - 1

The empirical formula is CH2O

The molecular formula is;

[12 + 2+ 16]n = 160

n = 160/30

n = 5

The molecular formula is;

C5H10O2

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The functional group of molecules as follows :

Molecule 1. is aldehyde and ketone, Molecule 2 is acid and thio, Molecule 3 is acid and amide, Molecule 4 is alcohol and ether, Molecule 5 is Alcohol and acid. The image attached below show the functional group and molecules are labeled.

The polar compounds are those compound having different positive and negative charge, therefore the bonding with atoms such as nitrogen, oxygen, or sulfur.

A buffer is a solution the can control the pH change along with the addition of an acidic or basic substance. It is able to neutralize small amounts of added acid or base, So it maintains the pH of the solution. This is important to maintain pH ranges.

Thus, Molecule 1. is aldehyde and ketone, Molecule 2 is acid and thio, Molecule 3 is acid and amide, Molecule 4 is alcohol and ether, Molecule 5 is Alcohol and acid.

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Answer:

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Vitamin A is a fat-soluble vitamin and an essential nutrient for humans. It is a group of organic compounds that includes retinol, retinal (also known as retinaldehyde), retinoic acid, and several provitamin A carotenoids (most notably beta-carotene (β-carotene).

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Answer:

27: B or 2

28: E or 5

29: D or 4

Explanation:

We are requested to solve the concentration of the solutions given.

The unit of concentration is given as M which can also be written as mol/L.

From the first question, let us calculate the number of moles of CaCl₂ in the solution.

Number of moles = mass /molar mass

mass = 277.5g

molar mass can be calculated as

Let's proceed to solve for the number of moles

Using this number of moles, we can calculate the concentration of the solution.

C = n/V

c = concentration

n = number of moles

v = volume

substituting the values and solving for concentration

The concentration of CaCl₂ is 0.1818M

b

From dilution formula,

where c and v represents the concentration and volume respectively.

Let's write out the values and solve for the concentration.

substituting the values and solving for c2

The new concentration is 0.3636M

NB; I converted the volumes from mL to L, but you don't need to and can simply plug in the values just as they have been given and you would get the same answer.

c.

Let's solve for concentration of solution B in 100ml beaker.

Using dilution formula

Substitute the values and solve for C2

From the calculations above, the concentrations are 0.1818M, 0.3636M and 0.909M respectively.

Answer:

A.

Explanation:

Opposite charged particles attract.

Particles of same charge are repelled.

Answer:

attracts opposites (a)

Explanation:

The relationship between tissues and organs is one of interdependence. Tissues work together to form organs, and organs rely on the different types of tissues to function properly.

The relationship between tissues and organs is an important one, and it is particularly exemplified in the case of the heart. The heart is an organ, and like all organs, it is made up of various types of tissues that work together to allow it to function properly. In the case of the heart, these tissues include muscle tissue, connective tissue, epithelial tissue, and nervous tissue.
Muscle tissue is particularly important in the heart, as it contracts to pump blood to the body. Without muscle tissue, the heart would not be able to perform its vital function. Connective and epithelial tissues are also important in the heart, as they hold the muscle cells together and in place in the chest. Without these tissues, the muscle cells would not be able to work together efficiently, and the heart would not be able to function properly.
Finally, nervous tissue plays a crucial role in the heart, as it coordinates how fast and hard the muscle cells contract. This coordination is essential for the heart to function properly and maintain the circulation of blood throughout the body.  In the case of the heart, the different types of tissues work together seamlessly to allow the heart to perform its vital function of pumping blood throughout the body.

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Answer: A

Explanation:

I got C wrong

la tierra nuestro planeta es el único del sistema solar que sabe que mantiene vida: vida que es increíblemente diversa,

The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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Hence, 8.12 days had passed because the initial sample is made according to the isotopes.

Atoms that have the same protons and neutrons but different quantities of neutrons are called isotopes. Despite having almost equal chemical properties, they have different masses, which affects their physical characteristics.

This allows us to write: N/N0 (= 0.956 = (1/2)(t/T).

When we take the logarithmic of both sides, we obtain:

t/T*log(1/2) = log(0.956) = log(0.956)

When we solve for t/T, we get:

t/T = log(0.956)/log(1/2)=0.110

By dividing both sides by T, we can finally find t:

t = (0.110) (0.110) * T

Iridium-192 has a 73.83-day half-life. Therefore:

t = (0.110) (0.110) 8.12 days divided by 73.83 days.

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At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

a) Magnetic Quantum Number

b) Principal Quantum Number

c) Electron Spin Quantum Number

d) Orbital Angular Momentum Quantum Number

Quantum numbers are the number used to describe the energy levels available to atoms or molecules.

There are four types of quantum numbers in chemistry namely;

• Principal Quantum number (n)

• Angular momentum Quantum number(ℓ)

• Magnetic moment (mℓ) and;

• Electron spin quantum number (ms).

a) The orientation of the orbital space is classified under the Magnetic Quantum Number. This quantum number determines the number of orbitals and their orientation within a subshell. Its value also depends on the orbital angular momentum quantum number (l)

b) The size of the orbital is classified under the Principal Quantum number. This quantum number designates the principal electronic shells with a minimum ground state of n = 1. The state n = 1 designates the first principal shell (the innermost shell). Note that n cannot be equal to zero because there is no atom with zero or a negative amount of energy levels/principal shells. n = 2 connotes the second principal shell and so on.

c) The magnetic moment is classified under the Electron Spin Quantum Number. This quantum number does not depend on another quantum number.

This quantum number connotes the direction of the electron spin. It may have a spin of +1/2, represented by an arrow pointing upwards ↑(spin-up), or –1/2, represented by a downward arrow ↓ (spin down).

d) The shape of the orbital is classified under the Orbital Angular Momentum Quantum Number. This quantum number determines the shape of an orbital and the angular distribution. The angular node is known to be equal to the angular momentum quantum number (l).

Each value of "l" indicates a specific s, p, d, f subshell and is dependent on the principal quantum number "n". The value of "l" can be equal to zero and a positive integer compared to the principal quantum number "n" that cannot be equal to zero

A buffer is a solution that mitigates against changes in acidity/alkalinity.

A buffer consists of a weak acid and its conjugate base. Also, a buffer can be formed from a weak base and its conjugate acid. A buffer is a solution that helps to mitigate against changes in acidity and alkalinity.

Let us now examine the solution mixtures listed in the question:

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The electron affinity of the 5th group increases down the groups of the periodic table because the electrons are placed in a higher energy level far from the nucleus.

Electron affinity is the energy released when an electron is attached to an atom or molecule.

Electron affinity is used as a measure of its ability to form an anion.

The electron affinity of elements decrease down the group and increase from left to right across the periodic table because the electrons are placed in a higher energy level far from the nucleus.

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Answer:

71.3 g

Explanation:

molar mass of C₇H₆O₃ = 138.13 g

molar mass of \(C_{9}H_{8}O_{4}\) = 180.17 g

find the moles of reactant: C₇H₆O₃

C₇H₆O₃ that reacted = mass/molar mass = 57.6 g C₇H₆O₃ / 138.13 g C₇H₆O₃

= 0.417 mol \(C_{7}H_{6}O_{3}\)

From the reaction equation, 1 mole of C₇H₆O₃ yields one mole of aspirin

find theoretical yield of aspirin:

0.417 mol C7H6O3 x 180.17 g C9H8O4 / 1 mol C9H8O4\(\frac{0.417 mol C_{7}H_{6}O_{3}}{} x \frac{180.17 g C_{9}H_{8}O_{4}}{1 mol C_{9}H_{8}O_{4}}\)

= 75.1 g C9H8O4

Actual yield= % yield × theoretical yield/100

Actual yield = 95.0 × 75.1/100

Actual yield = 71.3 g

Taking into account the reaction stoichiometry and actual yield, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.

The balanced reaction is:

22 C₇H₆O₃ (s) + 32 C₄H₆O₃ (s) → 24 C₉H₈O₄ (s) + 33 HC₂H₃O₂ (aq)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The mass molar of each compound is:

Then by reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 3036 grams of C₇H₆O₃ produce 3264 grams of C₉H₈O₄, 57.6 grams of C₇H₆O₃ will produce how many mass of C₉H₈O₄?

\(mass of C_{9} H_{8} O_{4} =\frac{57.6 grams of C_{7} H_{6} O_{3} x3264 gramsof C_{9} H_{8} O_{4} }{3036 grams of C_{7} H_{6} O_{3}}\)

mass of C₉H₈O₄= 60.03 grams

On the other side, actual yield is the amount of product actually obtained from a reaction. Assuming 95.0% yield  and considering the previously calculated mass the maximum amount of product that can be produced in the reaction, you can apply the following rule of three:  If 100% equals 60.03 grams of the compound produced, 95% equals how much mass of the compound?

\(mass of C_{9} H_{8} O_{4} =\frac{95 percentx60.03gramsof C_{9} H_{8} O_{4} }{100 percent}\)

mass of C₉H₈O₄= 57.0285 grams

Finally, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.

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