Why is crystal of oxalic acid regarded as a primary standard solution ?

One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns.

During El Niño years, Christchurch may experience cooler air temperatures due to several factors associated with the El Niño phenomenon.

El Niño is characterized by the abnormal warming of the surface waters in the eastern tropical Pacific Ocean, which has global climatic implications. While El Niño is primarily associated with changes in oceanic conditions, its effects can extend to atmospheric patterns, leading to altered weather patterns and temperature variations.

One possible reason for cooler air temperatures in Christchurch during El Niño years is the shift in atmospheric circulation patterns. El Niño can disrupt the normal global atmospheric circulation, resulting in changes in the positioning and intensity of weather systems.

This can lead to the advection of cooler air masses from the south or southeast towards Christchurch, resulting in cooler temperatures.

Another factor is the influence of El Niño on regional rainfall patterns. El Niño often leads to drier conditions in the South Island of New Zealand, including Christchurch.

Reduced cloud cover and less moisture in the air can contribute to cooler temperatures as there is less insulation from the sun's radiation and less evaporative cooling. Additionally, the absence of significant rainfall can result in less moisture in the soil, leading to cooler conditions as less energy is used for evaporation.

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Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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The metal X has an approximate molar mass of 42.36 g/mol and the metal is most likely calcium.

The molar mass of the metal carbonate XCO₃ and identify the metal X, we need to calculate the number of moles of XCO₃ and CO₂ using the given masses and molar masses.

The molar mass of CO₂ (carbon dioxide) is 12.011 g/mol (for carbon) + 2 * 15.999 g/mol (for oxygen) = 44.01 g/mol.

The number of moles of CO₂ can be calculated using the formula:

moles of CO₂ = mass of CO₂ / molar mass of CO₂

moles of CO₂ = 0.855 g / 44.01 g/mol

moles of CO₂ ≈ 0.01944 mol

Since the reaction stoichiometry is 1:1 between XCO₃ and CO₂, the number of moles of XCO₃ is also approximately 0.01944 mol.

molar mass of XCO₃ = mass of XCO₃ / moles of XCO₃

molar mass of XCO₃ = 2.012 g / 0.01944 mol

molar mass of XCO₃ ≈ 103.38 g/mol

The molar mass of XCO₃ is approximately 103.38 g/mol.

To determine the metal X:

molar mass of X = molar mass of XCO3 - molar mass of CO3

molar mass of X = 103.38 g/mol - (12.011 g/mol + 3 * 15.999 g/mol)

molar mass of X ≈ 42.36 g/mol

Metal X is most likely Calcium that has a molar mass of 40 g/mol

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Answer:

Robert Delaunay's Homage to Blériot (1914) was inspired by the first flight across the English channel.

Answer:

hi

Explanation:

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and what is this about?

 This should bring you to the periodic table Can i Please have Brainliest

Answer:

gguhg

Explanation:

no te es caso drama me están muy una las y y que las te

Answer:

0.110625 g of Ni

Explanation:

The first step in solving this problem is to put down the accurate chemical reaction equation.

Ni(s) + 2HCl(aq) ---> NiCl2(aq) + H2(g)

Secondly, we obtain the amount of HCl that reacted from the information provided.

Volume of HCl (V)= 25 ml

Concentration of HCl (C)= 0.15 mol/L

Then, to find the number of moles of HCl (n);

n= CV

Substitution values

n= 25/1000 × 0.15

n= 3.75 ×10^-3 moles

Mass of 3.75 ×10^-3 moles of HCl = number of moles × molar mass

Molar mass of HCl= 36.5 gmol-1

Therefore;

Mass of HCl = 3.75 ×10^-3 moles × 36.5 gmol-1

Mass of HCl= 0.136875 g of HCl

Thirdly we determine the mass of Ni reacted;

If 1 mole of Ni reacted with 2 moles of HCl according to the reaction equation

Then x moles of Ni reacts with 3.75 ×10^-3 moles of HCl

x= 1 × 3.75 ×10^-3 moles/ 2

x= 1.875 × 10^-3 moles of Ni

Mass of Ni= 1.875 × 10^-3 moles of Ni × 59 gmol-1

Mass of Ni= 0.110625 g of Ni

When a chemical reaction releases energy it is called Exothermic Reaction.

hope it helps!

When a chemical reaction energy releases then this type of reaction is called exothermic reaction. In this reaction energy is release to the atmosphere.

In chemistry there are various type of reaction out of which the two main types are the exothermic reaction and endothermic reaction.

Exothermic reaction is the one in which energy releases in form of heat respiration reaction is an example of exothermic reaction. In respiration food that we eat are broken down in glucose with release of energy.

Endothermic reaction is the one in which energy is taken out during the reaction. Photosynthesis is an example of endothermic reaction where sunlight energy is taken by the plants to make food.

Thus when a chemical reaction releases energy these reactions are called exothermic reaction.

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The mass of the rectangular piece of copper is 18,869 g (approx).In conclusion, the mass of a rectangular piece of copper with dimensions 24.4cm x 11.4 cm x 7.9 cm and a density of 8.92 g/cm³ is 18,869 g (approx.).

The given dimensions of the rectangular piece of copper are:Length = 24.4 cmWidth = 11.4 cmHeight = 7.9 cmThe formula to calculate the mass of an object is given by;

Mass = Density x Volume

Here, the density of copper is given as 8.92 g/cm³.

Therefore, the first step is to calculate the volume of the rectangular piece of copper.The formula to calculate the volume of a rectangular object is given by:

Volume = Length x Width x Height

So,Volume = 24.4 cm x 11.4 cm x 7.9 cm= 2115.432 cm³Now we will use the mass formula:

Mass = Density x Volume= 8.92 g/cm³ x 2115.432 cm³= 18,869.27824 g= 18,869 g (approx.)

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Answer:

Characteristics of oxygen are as follows:

Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic.

Marks that might link a bullet to a specific weapon include striations, which are unique patterns and imperfections left on the bullet's surface as it passes through the barrel of a firearm. These striations are caused by the unique characteristics of the rifling inside the barrel, such as the number of lands and grooves, their width, depth, and the direction of twist. Comparing the striations on a recovered bullet to test-fired bullets from a suspected weapon can help determine if they match, indicating a potential link.

As for the fingerprints found, it depends on the context of the investigation. Fingerprints can be categorized into three main types: latent, patent, and plastic. Latent fingerprints are invisible and require development techniques such as powder or chemical methods to make them visible. Patent fingerprints are visible prints left on a surface, such as blood or dirt. Plastic fingerprints are three-dimensional impressions left on soft surfaces like clay or wax.

Without specific information on the crime scene or the type of fingerprints found, it is not possible to determine which type the investigator has encountered.

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Answer:

.. ..

:O = C - Cl:

.. | ..

:Cl:

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Answer:

Wing, in aeronautics, an airfoil that helps lift a heavier-than-air craft. When positioned above the fuselage (high wings), wings provide an unrestricted view below and good lateral stability. Parasol wings, placed on struts high above the fuselage of seaplanes, help keep the engine from water spray.

Answer:

covalent bonds

Explanation:

covalent bonds hold together the hydrogen and oxygen atoms of individual H2O molecules. Covalent bonds occur when two atoms share electrons with each other.

Answer:

Brainliest pls

Explanation:

Dichotomous keys are exceptionally valuable since they permit non-master clients to distinguish living beings by guiding them to check the known, significant creatures out

Answer:

C. 65 percent

Based on the information provided, we have a reaction between hydrogen iodide (HI) gas and hydrogen gas (H₂) to form iodine gas (I₂). The equilibrium is represented by the equation:

2HI(g) = H₂(g) + I₂(g)

The concentration values given in the table correspond to the concentrations of H₂ and HI at different times.

a) From t=0 s to t=5 s: Without the specific graph mentioned in Figure 7.10, it is difficult to provide a precise explanation of the physical situation in the container during this time period. However, based on the equilibrium reaction given, we can make some general observations. At the start (t=0 s), the concentrations of H₂ and HI may be high. As time progresses, the reaction proceeds, and the concentrations of H₂ and HI may decrease while the concentration of I₂ increases. The specific behavior will depend on the rate of the forward and reverse reactions.

b) External factor altered at t=5 s: To bring about a change in the shape of the graph at t=5 s, some external factor must have been altered. The most likely factor is the total pressure within the container. Since the reaction involves gases, changes in pressure can affect the equilibrium position. However, according to the information given, a change in pressure will not affect equilibrium in this case since the number of moles of gas is the same on both sides of the equation. Therefore, if the shape of the graph changes at t=5 s, some other external factor, such as temperature or the addition of a catalyst, must have been altered.

c) Calculation of K at t=3 s: The equilibrium constant (K) can be calculated at any given time using the concentrations of the reactants and products. However, the concentrations of H₂ and HI at t=3 s are not provided in the information given. Without the necessary data, it is not possible to calculate K at t=3 s.

Lastly, the statement "1 dm³ COCI, decomposes" seems incomplete. If you provide additional information or clarify the question, I'll be happy to assist you further.

The synthesis of the 3,4-dimethylhexane from 1-bromobutane occurs by the Wurtz reaction as shown.

We know that synthesis is one of the key components of organic chemistry. In the process of the synthesis of compounds, we are going to have the combination of two or more reactants so as to obtain the products that we are looking for.

In this case, we are trying to carry out the synthesis of an alkane compound. The alkane that we want to produce in this case is the compound that is known as 1-bromobutane and we are going to use  3,4-dimethylhexane to carry out the reaction.

This can be done by the use of the Wurtz reaction that is going to involves the reaction of sodium metal with an alkyl halide in dry conditions.

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The last statement is correct

They both have seven protons in the nucleus.

it's wrong because they have six protons in the nuclear

They both have the same mass number.

it's wrong because Carbon-12 has mass number 12 but Carbon-13 has mass number 13

They both have seven neutrons in the nucleus.

it's wrong because Carbon-12 has six  in the nucleus but Carbon-13 has seven  in the nucleus

They both have the same atomic number.

It's true. They have the atomic number - 6

Answer:

D. They both have the same atomic number.

Explanation:

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Answer:

Explanation:

Antacids reduce the amount of stomach acid, relieving your heartburn. These medications can also be used to soothe stomach upset, indigestion and other pains in your stomach. Some antacids contain simethicone, which reduces gas. Antacids that you can get without a prescription include:

Answer:

A. 444.5 pm

Explanation:

We know that:

\(Density = \dfrac{mass \ of \ atoms \ in \ unit \ cell}{total \ volume \ of \ unit \ cell}\)

i.e.

\(\rho = \dfrac{n*M}{v_c * N_A}\)

\(\rho = \dfrac{n*M}{a^3 * N_A}\)

in a face-centered cubic crystal, the number of atoms per unit cell is (n) = 4

The molar mass of manganese (II) oxide \([Mn(11)O] = 70.93 \ g/mol\)

Density \(\rho\) is given as 5.365 g/cm³

Avogadro constant \(N_A\) = 6.023 × 10²³ atoms/mol

∴

\(\rho = \dfrac{n*M}{a^3 * N_A}\)

Making th edge length "a" the subject, we get:

\(a^3 = \dfrac{n*M}{\rho* N_A}\)

\(a^3 = \dfrac{4*70.93 \ g/mol}{5.365 \ g/cm^3 *6.023 * 10^{23} \ atoms/mol }\)

\(a^3= 8.78 \times 10^{-23} \ cm^3\)

\(a= \sqrt[3]{8.78 \times 10^{-23} \ cm^3}\)

a = 4.445 × 10⁻⁸ cm

a = 444.5 pm

The unit cell edge length of manganosite is equal to: A. 444.5 pm

Given the following data:

We know that the molar mass of manganese (ll) oxide is equal to 70.93 g/mol.

Avogadro constant = \(6.02 \times 10^{23}\)

Since the rock salt is face-centered cubic crystal, the number of atoms per unit cell, n = 4

To find the unit cell edge length of manganosite:

For a crystal structure, density is given by the formula:

\(Density = \frac{Mass\; of\;atoms\;in\;a\;unit\;cell}{Total\;volume\;of\;a\;unit\;cell}\)

\(\rho = \frac{nM}{N_Aa^3}\)

Where:

Making "a" the subject of formula, we have:

\(a=\sqrt[3]{\frac{nM}{\rho N_A} }\)

Substituting the parameters into the formula, we have;

\(a=\sqrt[3]{\frac{4 \times 70.93}{5.365 \times 6.02 \times 10^{23} }}\\\\a=\sqrt[3]{\frac{283.72}{3.23 \times 10^{24} }}\\\\a=\sqrt[3]{8.79 \times 10^{-23} }}\\\\a = 4.445 \times 10^{-8}\; meters\)

Unit cell edge length, a = 444.5 pm

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People can categorize the various types of interactions that take place in the environment thanks to organizational levels.

Organizational level is defined as organelles, cells, tissues, organs, organ systems, organisms, populations, communities, ecosystems, and biosphere are the biological stages of structure of living things, listed from the simplest to the most complex. The set of cells that make up the tissue level of organization cooperate to carry out one or more particular functions.

To make sure that every cell receives what it needs to carry out life tasks, large, complex organisms need multiple levels of structure. The cell is where the body's system organization starts. Organ systems are created when organs work together to build tissues, tissues to create organs, and organs to create organs.

Thus, people can categorize the various types of interactions that take place in the environment thanks to organizational levels.

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Answer:

\(\Large \boxed{\sf 0.714 \ moles}\)

Explanation:

Avogadro's number can be used as a conversion factor from atoms to moles or moles to atoms.

\(\displaystyle \frac{4.3 \times 10^{23}}{6.022 \times 10^{23} } =0.714048\)

Answer:

Weight 0.4326 g of sodium bicarbonate and 0.5141 g of sodium carbonate, dissolve it in distilled water and then bring the solution to a final volume of 50.0 mL using distilled water.

Explanation:

The pH of a buffered solution can be calculated using the Henderson-Hasselbalch equation:

\( pH = pKa + log(\frac{[Na_{2}CO_{3}]}{[NaHCO_{3}]}) \)  

We have that pH = 10.3 and the Ka is 4.7x10⁻¹¹, so:

\( 10.3 = -log(4.7 \cdot 10^{-11}) + log(\frac{[Na_{2}CO_{3}]}{[NaHCO_{3}]}) \)  

\( \frac{[Na_{2}CO_{3}]}{[NaHCO_{3}]} = 0.94 \)  (1)

Also, we know that:

\( [Na_{2}CO_{3}] + [NaHCO_{3}] = 0.20 M \)    (2)

From equation (2) we have:

\( [Na_{2}CO_{3}] = 0.20 - [NaHCO_{3}] \)   (3)

By entering (3) into (1):

\( \frac{0.20 - [NaHCO_{3}]}{[NaHCO_{3}]} = 0.94 \)

\( 0.94*[NaHCO_{3}] + [NaHCO_{3}] = 0.20 \)

\( [NaHCO_{3}] = 0.103 M \)  

Hence, the [Na_{2}CO_{3}] is:

\( [Na_{2}CO_{3}] = 0.20 - [NaHCO_{3}] = 0.20 M - 0.103 M = 0.097 M \)  

Now, having the concentrations and knowing the volume of the buffer solution we can find the mass of the sodium carbonate and the sodium bicarbonate, as follows:

\(m_{Na_{2}CO_{3}} = C*V*M = 0.097 mol/L*0.050 L*105.99 g/mol = 0.5141 g\)

\(m_{NaHCO_{3}} = C*V*M = 0.103 mol/L*0.050 L*84.007 g/mol = 0.4326 g\)

Therefore, to prepare 50.0 mL of a 0.20 M solution that is buffered to a pH of 10.3 we need to weight 0.4326 g of sodium bicarbonate and 0.5141 g of sodium carbonate, dissolve it in distilled water and then bring the solution to a final volume of 50.0 mL using distilled water.      

I hope it helps you!

Answer:by testing it on animals

Explanation:

Answer: Copper (II) Sulfate! (CuSO4)

Explanation:

This is because compared to the other salts, it is the visible color blue. The other ones are plain white. Happy holidays! Don’t stress :)