Why does a power plant generator produce alternating current and not direct
current?

Answer:

207

Explanation:

For the box to move at a constant velocity, the applied force must cancel the force due to kinetic friction.

F = mu_k * N

N = normal force = weight (= mg) if sliding horizontally

F = mu_k * mg = (0.48)(44 kg)(9.8 m/s^2) = 207 N

Answer:

\(\mu=41.5\textdegree\)

Explanation:

From the question we are told that:

Water index of refraction \(i_w=1.33\)

Glass index of refraction \(i_g=1.50\)

Generally the equation for Brewster's law is mathematically given by

 \(\theta=tan^{-1}(\frac{i_g}{i_w})\)

 \(\theta=tan^{-1}(\frac{1.50}{1.33})\)

 \(\theta=48.44 \textdegree\)

Therefore Angle of incident to plane  \mu (normal at 90 degree to the surface)

 \(\mu=90\textdegree-\theta\)

 \(\mu=90\textdegree-48.44\textdegree\)

 \(\mu=41.5\textdegree\)

The coefficient of kinetic friction on material B is greater than material A, causing an increase in net force on block 2.

The coefficient of kinetic friction between block 1 and material B is greater than that between block 1 and material A, which causes an increase in the net force acting on block 2 as block 1 slides from material A to material B.

This is because the increased friction on material B results in a greater opposing force to the motion of block 1, which in turn causes a greater tension force on the string and therefore a greater net force on block 2.

This effect is due to the properties of the different materials and the interaction between the materials and the block, which ultimately determine the amount of friction present and the resulting force acting on the system.

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The net force on q1 is 9.94 N.

From Coulomb's Law, the force between two point charges is given by:

where;

All the charges have the same charge and magnitude and are separated by the same distance.

The force between q1 and q2 is:

F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

Similarly, the force between q2 and q3 is:

(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

The net force on q1 will be:

Fnet = F12 + F23

Fnet = 4.97 N + (4.97)

Fnet = 9.94 N

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Venus has a very hot, dense atmosphere. You couldn't breathe the atmosphere, you would be crushed under the weight of the atmosphere, and you would burn up in temperatures

on the surface that were hot enough to melt lead. After the Sun and the Moon, Venus is the brightest object in the sky. In the morning or evening sky, Venus can occasionally be mistaken for a bright star. The planet is comparable to Earth on the inside and is a tad smaller than Earth. Venus's surface is atmosphere by dense clouds, so we can't see it from Earth.

The NASA spacecraft Mariner 2 successfully flew by and examined Venus, the first planet to be explored by a spacecraft.

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The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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The type of dispersion in the Debye model is linear.

When it is at the longer wavelength limit, the density of states is referred to as quadratic.

D(ω) = [3ω²/2π²c³] s rad⁻¹m⁻³

This has a maximum frequency ωD, known as the Debye frequency. In the three dimensions, there are 3 degrees of freedom per atom.

So, the number of phonon modes present here is 3n.

3n = (0→ωD)∫D(ω)dω

Where n is known as the atomic density of the phonon.

We know that, for a frequency that is above the Debye frequency there will be no phonon modes present.

The Debye frequency,

ω³D = 6π²nc³

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Answer:

4.2

Explanation:

Answer:

A.

Explanation:

Im in 10th grade so i just know this stuff

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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The formula for efficiency of  original Carnot engine is e(12) = 1 - TC/TH

e = 1 - T(C) /T(H) ——— eq 1

The efficiency is;

e(12) = (W1 + W2)/Q(H1)

Where W1 is work done by 1st engine; W2 is work done by second engine and Q(H1) is the heat input to the first engine.

W = Q(H) + Q(C)

e(12) = [Q(H1) + Q(C1) + Q(H2) + Q(C2)] / Q(H1)

QH2 = -QC1

e(12) = [Q(H1) + Q(C1) - Q(C1) + Q(C2)] / Q(H1)

So e(12) = [Q(H1) + Q(C2)] / Q(H1)

So e(12) = 1 + [Q(C2)/Q(H1)] ———eq 2

Also,

Q(C2) /Q(H2) = (-Tc/T')

Q(C2) = -Q(H2) (Tc/T')

This is also equal to Q(C1) (TC/T')

But Q(C1) is also equal to;

-Q(H1) (T'/TH)

Q(C2) = -Q(H1) (T'/TH)(TC/T')

Q(C2) = -Q(H1)(TC/TH)

Replacing this with Q(C2) in eq 2 to obtain;

e(12) = 1 + [[-Q(H1)(TC/TH)] /Q(H1)]

e(12) = 1 - TC/TH

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Answer:

B

Explanation:

quantization of energy is only seen in atoms

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun"  is not true about gravity.

Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.

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Answer:

B. Must eat to get energy

Explanation:

The common characteristics of all consumers is that they must eat to get energy. This way, they are termed heterotrophs.

Heterotrophs are organisms that cannot make their own food. They must eat other organisms to obtain nutrition for energy needs.

Plants do not do this. They are autotrophs in that they simply make their own food.

They use this food to obtain energy for their living activities.

Answer:

The speed of the particle is proportional to:

c. t²

Explanation:

Given;

initial velocity of the particle, u = 0

let the net force on the object = F

Work done on the particle is given by;

W = F x d

W ∝ t

\(Fd \ \alpha \ t\\\\\frac{mv}{t}d \ \ \alpha \ t\\\\mvd \ \ \alpha \ t^2\\\\v \ \ \alpha \ t^2\)

Therefore, the speed of the particle is proportional to t²

The speed of the particle is proportional to t.

It should be noted that work is a change in kinetic energy. Therefore, power will be calculated as:

Power = Work / Time = force × velocity

Power is proportional to t. Since force is a constant, then the velocity will be proportional to t. Therefore, the speed of the particle is proportional to t.

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D. The frequency of the wave is determined 1.2 Hz.

The frequency of a wave describes the number of waves that pass a fixed place in a given amount of time.

General wave equation;

y = A cos(ωt)

where;

From the given wave equation;

x(t) = 0.65 cos(7.4t)

ω = 2πf

7.4 = 2πf

f = 7.4/2π

f = 1.18 Hz

f = ≈ 1.2 Hz

Thus, the frequency of the wave is determined 1.2 Hz.

The correct option is D.

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Answer:

B

Explanation:

i think

Answer:

D. makes rules for other banks

Explanation:

The work done by using a lever with an effort arm of 12 meters and a load arm of 6 meters is 72 Joules. The force must have applied is 1600 N.

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Answer:

10

Explanation:

lyezurzup?y?ur if fk kgs7rsjzkgzitz

An orbital projectile should be launched with such a horizontal speed exceeding 8000 m/s. Determine the speed of the a satellite inside an orbit 1000 km, M is 5.98x1024 kg, and R is 6.4x10m. [Ans x 10 = 7.34 m/s].

At 328,084 feet, the barrier between earth and space is the highest point you have probably ever gone and is around 11 times greater than Mount Everest. Consider that for a second. If looking at this image doesn't inspire awe in you, perhaps contemplating it in a different way would.

A: At low earth orbit, an object must travel at a speed of roughly 28,000 km/h (17,500 mph) in order to orbit the Earth. At this speed, the object would be able to leave Earth's atmosphere and keep a steady orbit around it at a height of about  325 km (200 km).

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It is to be noted that the magnitude of the electric flux through the hemisphere surface  is πR²E. (Option D)

The characteristic of an electric field known as electric flux may be thought of as the quantity of electric lines of force (or electric field lines) that cross a certain region.

According to this theory, electric field lines begin with positive electric charges and end with negative charges.

Recall  that the A hemispherical surface (half of a spherical surface) of radius R.

In order to derive the Magnitude of the electric flux we use the following formula:

Ф = ∈ x Area of the Curve Surface

⇒ Ф = ∈ x πR²

⇒ Ф = πR²∈

Thus, option D is the correct answer.

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Full Question:

A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface?

A) 2πR²∈

B) 0

C) 4 πR²∈/3

D) πR²∈