While you push a box you begin to decrease the force you are exerting on the box. When will the box reach equilibrium?

A. When the force you are exerting on the box is equal to 0.

B. When Fyou on box = -Fbox on you.

C. When the force of the box becomes Fyou on box < Fbox on you

D. The box will never reach equilibrium.

Peak expiratory flow readings are higher when patients are well, but lower when a  patient's airway is constricted.

This term is used in medicine to refer to the maximum rate of a person's exhalation or to how fast and how long can they exhale.

This rate is measured by using the peak expiratory flow test that requires you to deeply inhale and then exhale as fast as hard as possible.

This rate is closely related to the amount of air flowing out of the lungs. This implies the peak expiratory flow is lower if there is a disease such as asthma that can constrict the airways.

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Answer:

Sulfur (Has six valence electrons). It has maximum valency due to belonging to VI groups of the Periodic Table.

Explanation:

The electrons found in an element's outermost atomic shell are known as valence electrons.

Sulfur, which has an atomic number of 16, has an electrical configuration of 2, 8, 6, meaning it has six electrons in its outermost shell. As a result, its valence electrons will also be six.

However, in its natural condition, sulfur exists as the S8 molecule, which has the classic chair structure where each sulfur atom is covalently connected to two other sulfur atoms. In that sense, there will be 8 valence electrons.

Consequently, the answer will be 6 if you're asking about the "sulphur atom," but 8 if you're talking about sulfur in general.

Thank you ,

Eddie

Answer:

Gravity

Explanation:

The distance traveled by the Spacecraft is  2.3 x 10² m.

To have a constant velocity, the change in velocity or speed of the object must be zero.

Constant speed will elapse equal distance in an identical period of time as a result is an example of steady speed.

For a Spacecraft is traveling in inner planetary space at a constant velocity and a given time of motion, the distance traveled by the Spacecraft is calculated as follows;

Distance = speed x time

the speed is given as 24.21 m/s

the time of motion is given as 9.5 seconds

distance = 24.21 m/s  x 9.5 s

distance = 2.3 x 10² m

Thus, the distance traveled by the Spacecraft is  2.3 x 10² m.

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The complete question is below;

Spacecraft is traveling in inner planetary space at a constant velocity of 24.1 m/s. What it estimated distance traveled by the spacecraft in 9.50 seconds?

Answer:

this is the answer

Explanation:

hope it helps

Answer:

There are four types of compounds, depending on how the constituent atoms are held together: molecules held together by covalent bonds. ionic compounds held together by ionic bonds. intermetallic compounds held together by metallic bonds.

Explanation:

Answer:

Explanation:

Quarter 1 - 10,000 units

Quarter 2 - 12,000 units

Quarter 3 - 16,000 units

Quarter 4 - 14,000 units

Quarter 5 - 10,000 units

Quarter 6 - 8,000 units

Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.

Acceleration is the change in velocity over time. We can calculate the acceleration of the bicyclist during the time 2.0 s to 5.0 s using the formula acceleration = (final velocity - initial velocity) / time.

The initial velocity of the bicyclist at 2.0 s is 2.0 m/s and the final velocity at 5.0 s is 8.0 m/s. The time interval between 2.0 s and 5.0 s is 3.0 s.

Substituting these values into the formula, we get acceleration = (8.0 m/s - 2.0 m/s) / 3.0 s = 6.0 m/s / 3.0 s = 2.0 m/s^2.

So, the acceleration of the bicyclist during the time 2.0 s to 5.0 s was 2.0 m/s^2.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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Answer:

The first law of motion describes the principle of law of inertia.

Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.

This question is incomplete, the complete question is;

Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.

Which of the following is NOT one of the lowest three energy levels of an electron in this model?

a. 283 eV

b. 339 eV

c. 113   eV  

d. 226 eV        

Answer:

the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Explanation:

Given the data in the question;

Three dimension cube or particle in a cubic box

the energy value is given by;

\(E_{nx,ny,nz\) = \(( n_x^2 + n_y^2 + n_z^2 )\) × π²h"² / 2ml²

where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )

m is mass of electron ( 9.1 × 10⁻³¹ kg )

l is length of side of box ( 1.0 × 10⁻¹⁰ m )

for ground level ( \(n_x = n_y = n_z = 1\) )

so

\(( n_x^2 + n_y^2 + n_z^2 )\) ×  π²h"² / 2ml²

since h" = h/2π

\(( n_x^2 + n_y^2 + n_z^2 )\) × π²h² / (2π)²2ml²

so we substitute

\(E_{111\) = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]

\(E_{111\) = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]    

\(E_{111\) = 3 × [ 6.03082165 × 10⁻¹⁸ ]

Now, we know that electric charge = 1.602 x 10⁻¹⁹

so

\(E_{111\) = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]

\(E_{111\) = 3 × [ 37.645578 ]

\(E_{111\) = 112.9 ≈ 113 eV

\(E_{211\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{211\) = ( 1² + 1² + 2² ) × [ 37.645578 ]

\(E_{211\) = 6 × [ 37.645578 ]

\(E_{211\) = 225.87 ≈ 226 eV

\(E_{221\) = \(( n_x^2 + n_y^2 + n_z^2 )\)  × π²h² / (2π)²2ml²

we substitute

\(E_{221\) = ( 2² + 2² + 1² ) × [ 37.645578 ]

\(E_{211\) = 9 × [ 37.645578 ]

\(E_{211\) = 338.8 ≈ 339 eV

Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation:

The formula you mentioned is known as the dot product formula or the scalar product formula. It is used to find the angle between two vectors u and v.

Let's start by defining the vectors u and v. Suppose we have two vectors u and v in a two-dimensional space.

u = (u1, u2)

v = (v1, v2)

The dot product of these vectors is defined as:

u . v = |u| |v| cos(β)

where |u| and |v| are the magnitudes of the vectors u and v respectively, and β is the angle between the vectors u and v.

Now, let's derive this formula. The dot product of two vectors u and v is given by:

u . v = (u1 × v1) + (u2 × v2)

The magnitude of a vector is given by:

|u| = sqrt(u1² + u2²)

|v| = sqrt(v1² + v2²)

We can use the dot product and magnitude equations to obtain:

cos(β) = (u . v) / (|u| × |v|)

Multiplying both sides by |u| × |v| gives us:

|u| × |v| × cos(β) = u . v

Therefore, we have derived the dot product formula:

u . v = |u| × |v| × cos(β)

This formula can be used to find the angle between two vectors u and v in any two-dimensional or three-dimensional space.

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The complete question is-

Write the proof of the formula

u.v=|u||v|cosβ

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

The mass of a pure platinum disc can be gotten by multiplying the density with the volume.

Therefore the mass is 2418.2 grams or 2.4182 kilograms.

A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.

The kilogram is the primary mass unit in the SI.

The resistance of the body to acceleration in the presence of a net force can be measured as mass.

Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.

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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.

Give your answer in grams and kilograms.

This question involves the concepts of density, volume, and mass.

The approximate diameter of a magnesium atom is "3.55 x 10⁻¹⁰ m".

It is given that:

Mass of one mole = 24 grams

Mass of 6 x 10²³ atoms = 24 grams

Mass of 1 atom = \(\frac{24\ grams}{6\ x\ 10^{23}\ atoms}\) = 4 x 10⁻²³ grams

\(\rho = \frac{m}{V}\\\\V=\frac{m}{\rho}\)

where,

Therefore,

\(V=\frac{4\ x\ 10^{-23}\ grams}{1.7\ grams/cm^3}\)

V = 2.35 x 10⁻²³ cm³

The atom is in a spherical shape. Hence, its Volume can be given as follows:

\(V =\frac{\pi d^3}{6}\\\\d=\sqrt[3]{ \frac{6V}{\pi}}\\\\d=\sqrt[3]{ \frac{6(2.35\ x\ 10^{-23}\ cm^3)}{\pi}}\)

d = 0.355 x 10⁻⁷ cm = 3.55 x 10⁻¹⁰ m

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Answer:

Inertia

Explanation:

Your body is naturally resisting turning left, as it wants to continue straight. So if feels like you are going right.

Answer:

Because my body tries to continue in the rectilinear motion it was experiencing before the turn.

Explanation:

The body tries to continue in the rectilinear motion it was having before the hard left turn, in which a centripetal force is experienced. This is in agreement with Newton's first Law of motion:

"An object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force."

ANSWER

EXPLANATION

To find the amount left after 160 days, we have to apply the formula for the amount of a substance remaining using its half-life:

where N0 = initial amount of the substance

t = time elapsed

T = half-life

Therefore, we have that the amount of Cerium left after 160 days is:

Hence, 2,634 grams of Cerium will be left.

Answer:

100

Explanation:

F = m * a

Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):

F = 0.02 kg * 5 m/s^2 = 0.1 N

So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.

Answer:

The evaporation of water is an example of a change in Pysical Change .

Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

Answer:

In my opinion, ''A" would be the longest wavelength.

Explanation:

The Earth has a solid inner core

The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.

The initial volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:

V = π(0.5 cm)²(40 cm)

V = 31.4 cm³

The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:

β = ΔV/(VΔT)

where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:

ΔV = βVΔT

We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:

ΔV = π(0.5 cm)²(40 cm - 37 cm)

ΔV = 0.59 cm³

Plugging in all the values, we get:

0.59 cm³ = β(31.4 cm³)(-10°C)

β = 0.002

To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:

ΔT = ΔV/(βV)

We know that ΔV is the difference between the initial volume and the volume at the new height, which is:

ΔV = π(0.5 cm)²(49 cm - 40 cm)

ΔV = 6.86 cm³

Plugging in all the values, we get:

ΔT = 6.86 cm³/(0.002)(31.4 cm³)

ΔT = 109.5°C

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