Which word names melted rock and minerals found beneath Earth's crust?

A. lava B. rhyolite C. magma D. gabbro

The concentration of ammonia in the solution is calculated as 4.48*10⁻⁴ M.

In chemistry, the abundance of constituent divided by total volume of a mixture is known as concentration.

C₃H₇COOH + NH⁴⁺ ⇌ C₃H₇COOH⁻ + NH⁴⁺

The propanoic acid (C3H7COOH) is a weak acid with known Ka value (1.3*10^-5), so we use the Henderson-Hasselbalch equation to calculate concentration of the acetate ion (C3H7COO-) in the solution:

pKa = -log(Ka) = -log(1.3*10⁻⁵) = 4.89

pH = pKa + log([C₃H₇COO-]/[C₃H₇COOH])

[C₃H₇COOH] = 0.18 M

[C₃H₇COOH-] = Ka*[C₃H₇COOH]/[H+] = (1.310⁻⁵)(0.18)/10^-pH

Kb = [ NH⁴⁺][OH⁻]/[NH₃]

Kb = [NH⁴⁺][OH⁻]/[NH₃] ≈ [NH⁴⁺][OH⁻]/0

[OH⁻] = Kb*[NH₃]/[NH⁴⁺] = (1.7610⁻⁵)[NH3]/0.18

[H⁺][OH-] = 1.0*10⁻¹⁴

[H⁺] = 10^-pH

NH₃] = [OH⁻] = 1.010^-14/[H⁺] - 2.4910⁻⁷

[NH₃] = 4.48*10⁻⁴ M

Therefore, the concentration of ammonia in the solution is 4.48*10⁻⁴ M.

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Answer:The atom being mostly empty space. A small number of alpha particles were deflected by large angles (> 4°) as they passed through the foil. There is a concentration of positive charge in the atom. Like charges repel, so the positive alpha particles were being repelled by positive charge

Assuming a similar number of molecules, the matter that occupies the most space is gas. Option C is correct.

This is because gases have no definite shape or volume, and their molecules are spread out, moving freely in all directions. As a result, gases tend to occupy the entire volume of their container and expand to fill the available space. This is known as the "kinetic molecular theory" of gases.

In contrast, solids and liquids have a definite volume and shape. Solids have a fixed shape and their molecules are packed closely together, while liquids have a variable shape and their molecules are less closely packed. As a result, both solids and liquids occupy less space than gases.

It is worth noting that the volume of a solid or liquid can change under certain conditions, such as changes in temperature or pressure. However, even under these conditions, the space occupied by a solid or liquid is still less than that occupied by a gas. Option C is correct.

The complete question is

Which of the following matters occupies more space, assuming similar number of molecules?

A. Solid

B. Liquid

C. Gas

D. Solid and gas

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

The unbalanced chemical equation is

K

2

Cr

2

O

7

+HCl→KCl+CrCl

3

+H

2

O+Cl

2

Balance all atoms except H and O.

K

2

Cr

2

O

7

+10HCl→2KCl+2CrCl

3

+H

2

O+Cl

2

Assign oxidation numbers.

K

2

+6

Cr

2

O

7

+10H

−1

Cl

→2KCl+2

+3

Cr

Cl

3

+H

2

O+

0

Cl

2

The oxidation number of Cr decreases from +6 to +3. Total decrease in the oxidation number of two Cr atoms is 6. The oxidation number of Cl increases from -1 to 0. Total increase in the oxidation number of 2 Cl atoms is 2.

Balance increase in oxidation number with decrease in oxidation number by using appropriate coefficients.

K

2

Cr

2

O

7

+14HCl→2KCl+2CrCl

3

+H

2

O+3Cl

2

Balance O atoms by adding six water molecules on products side.

K

2

Cr

2

O

7

+14HCl→2KCl+2CrCl

3

+7H

2

O+3Cl

2

H atoms are balanced.

K

2

Cr

2

O

7

+14HCl→2KCl+2CrCl

3

+7H

2

O+3Cl

2

This is balanced chemical equation.

The sum of the coefficients of the products is 2+2+7+3=14

Gas stations often post safety warnings about static electricity or other sparks because gasoline is volatile and gasoline vapors are flammable. Option C is correct.

Gasoline is a type of liquid which is toxic and highly flammable that is can easily catch the fire and the vapors produced by the burning of it is called gasoline vapors.

It produces nitrogen oxide and carbon monoxide while burning which is not favorable for the environment and also produces unburned hydrocarbons.

Therefore, the gasoline vapors are flammable Gas stations often post safety warnings about static electricity or other sparks. Option C is correct.

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There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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Answer:

1.904 ppm

Explanation:

Concentration of drug in units of ppm = mass of solute / (mass of solution ) × 1000000

mass of blood = density of blood × volume = 1.05 g / ml × 5000 ml = 5250  g

mass of solution = mass of blood + mass of solute ( statin) = 5250 + 0.01 g  = 5250.01 g

Concentration of drug in units of ppm = (0.01 g / 5250.01 g) × 1000000 = 1.904 ppm

I hope this helps!!

When measuring heat transfer, the sign of the delta T (ΔT) and the heat transfer (q) values is significant.

The negative sign indicates that the heat flow is in the opposite direction from the expected direction based on the given temperature gradient. When a negative sign is present in the delta T value or heat value, it implies that heat is being absorbed rather than being given off.  For example, when a substance absorbs heat, the temperature difference between the two regions decreases, resulting in a negative delta T value. When the surroundings absorb heat, the object's temperature drops, resulting in a negative heat value. The opposite is true for positive signs. When an object loses heat, its temperature drops, and the temperature difference between two regions increases, resulting in a positive delta T value. The heat transfer is said to be positive if heat is given off by the system to the surroundings. When heat flows from the surroundings to the system, the heat transfer is negative. The negative sign is significant since it shows that the energy flow is in the opposite direction from the expected direction based on the given temperature gradient.The amount of heat transferred by the system is proportional to the absolute value of the heat value and the delta T value.

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The mass (in grams) of chlorine gas is needed to react with 251 grams of iron is 479 grams. Option C.

To determine the mass of chlorine gas needed to react with 251 grams of iron, we need to use the stoichiometry of the balanced chemical equation:

2Fe + 3Cl2 → 2FeCl3

From the balanced equation, we can see that 2 moles of iron (Fe) react with 3 moles of chlorine gas (Cl2) to produce 2 moles of iron(III) chloride (FeCl3).

To calculate the mass of chlorine gas, we can follow these steps:

Step 1: Convert the given mass of iron (Fe) to moles.

Using the molar mass of iron (Fe), which is approximately 55.85 g/mol, we can calculate the number of moles of iron:

moles of Fe = mass of Fe / molar mass of Fe

moles of Fe = 251 g / 55.85 g/mol

moles of Fe ≈ 4.5 mol (rounded to one decimal place)

Step 2: Use the mole ratio from the balanced equation to find the moles of chlorine gas (Cl2) needed.

From the balanced equation, we know that 2 moles of Fe react with 3 moles of Cl2. Therefore, the moles of Cl2 can be calculated as:

moles of Cl2 = (moles of Fe / 2) * 3

moles of Cl2 = (4.5 mol / 2) * 3

moles of Cl2 ≈ 6.75 mol (rounded to two decimal places)

Step 3: Convert the moles of chlorine gas to grams.

Using the molar mass of chlorine gas (Cl2), which is approximately 70.90 g/mol, we can calculate the mass of chlorine gas:

mass of Cl2 = moles of Cl2 * molar mass of Cl2

mass of Cl2 = 6.75 mol * 70.90 g/mol

mass of Cl2 ≈ 479 grams (rounded to the nearest whole number) Option C is correct.

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Taking into account definition of reaction stoichiometry, 1.6442 grams of Fe₂O₃ can be produced if 1.15 g of iron is heated and placed in a bottle containing 0.0219 mol of oxygen gas.

In first place, the balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety and the chemical reaction will stop, determining the amount of product in the reaction.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of O₂ reacts with 223.4 grams of Fe, 0.0219 moles of O₂ reacts with how much mass of Fe?

mass of Fe= (0.0219 moles of O₂×223.4 grams of Fe)÷ 3 moles of O₂

mass of Fe= 1.63 grams

But 1.63 grams of Fe are not available, 1.15 grams are available. Since you have less mass than you need to react with 0.0219 moles of O₂, Fe will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 223.4 grams of Fe form 319.4 grams of Fe₂O₃, 1.15 grams of Fe form how much mass of Fe₂O₃?

mass of Fe₂O₃= (1.15 grams of Fe× 319.4 grams of Fe₂O₃)÷ 223.4 grams of Fe

mass of Fe₂O₃= 1.6442 grams

Then, 1.6442 grams of Fe₂O₃ can be produced if 1.15 g of iron is heated and placed in a bottle containing 0.0219 mol of oxygen gas.

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The intermolecular force between bromine and benzene is primarily a van der Waals force known as London dispersion forces.

London dispersion forces occur due to temporary fluctuations in electron distribution, creating temporary dipoles in molecules. In the case of bromine and benzene, both molecules are nonpolar, meaning they have no permanent dipole. However, they still experience London dispersion forces.

Benzene is a cyclic aromatic hydrocarbon with a hexagonal ring structure. It consists of delocalized π electrons above and below the plane of the molecule. Bromine is a halogen element with seven valence electrons, which forms diatomic molecules. In the solid or liquid state, bromine molecules exist as Br2.

The London dispersion forces between bromine and benzene arise from the temporary shifts in electron density within their electron clouds. The π electrons in benzene induce temporary dipoles in the bromine molecules, resulting in attractive forces between them. These temporary dipoles continuously form and break due to electron movements, resulting in an overall attractive force between the bromine and benzene molecules.

While London dispersion forces are generally weaker than other intermolecular forces like dipole-dipole interactions or hydrogen bonding, they still contribute to the stability of the system and affect properties such as boiling points and melting points.

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The elements in the 4th period on the periodic table are arranged in order of increasing their atomic number.

The modern periodic table can be defined as the arrangement of chemical elements. Elements are orderly arranged according to their increasing atomic number and similar chemical properties. This periodic table is organized in the forms of columns and rows which are named periods and groups.

The 118 elements are present in 18 groups and 7 periods in the modern periodic table. The elements placed in the same group and possessing the same valence electronic configuration possess identical chemical properties. Whereas the elements placed in the same period possess an increasing order of their valence electrons but the electrons are occupied in the same electron shell.

Therefore,  in the modern periodic table, the elements are organized as the periodic function of their atomic number. The number of valence electrons is not increased continuously throughout the period of moving left to right.

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Answer: FeO

Explanation:

Answer:

This is not worth 50 points liar

Explanation:

The rate law and the value of k for the given reaction is 1.7×103 M⁻²s⁻¹. Therefore, option D is correct.

The word "rate law" refers to an expression that expresses reaction rate as the product of the stoichiometric coefficient of the reacting species in a balanced chemical equation multiplied by the molar concentration of the reactants, with each term raised to a power.

\(\rm Rate = k \times [NO]^{n} x [O_{2}]^ {m}\)

Thus, m must = 1

\(\rm Rate\ 1 = k \times [NO 1]^ {m} x [O_{2} 1]^ {n}\\Rate\ 2 = k \time [NO 2]^ {m} x [O_2 2]^ {n}\)

Rearranging this equation

\(Rate1 / [O_2 1]^{n} = k x [NO1]^ {m}Rate2 / [O_2 2]^{n} = k x [NO2]\)

but  [NO 1] = [NO 2]

Hence,

\(Rate1 / [O_2 1]^ {n}= Rate2 / [O_2 2]^{n}\)

Rearranging and substituting in the values

\(([O_2 2] / [O_2 1])^{n} = Rate2 / Rate 1\)

\(2^{n} = 2\)

So, n = 1

Same from run 1 to 3

[NO] doubled

[O₂] stayed constant

Rate quadrupled

\((2)^{n} = 4\)

n = 2

we know that rate = k x [NO]² x [O₂]

Substitute in any value for [NO], [O₂] and rate and calculate K

k = rate / [NO]² x [O₂]

= (8.55x10⁻³ M / sec) / ((0.030M)² x (0.0055M))

= 1.7×103 M⁻²s⁻¹

Thus, option D is correct.

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Your question is incomplete, most probably complete question is

Determine the rate law and the value of k for the following reaction using the data provided.

2 NO(g) + O2(g) 2 NO2(g)

[NO]i (M) [O2]i (M) Initial Rate (M-1s-1)

0.030 0.0055 8.55 x 10-3

0.030 0.0110 1.71 x 10-2

0.060 0.0055 3.42 x 10-2

A. Rate = 57 M-1s-1[NO][O2]

B. Rate = 3.8 M-1/2s-1[NO][O2]1/2

C. Rate = 3.1×105 M-3s-1[NO]2[O2]2

D. Rate = 1.7×103 M-2s–1[NO]2[O2]

Answer:

Explanation:

Determine the treatments you’ll be using on your eggs, and prepare the substances you’ll need. You can make salt-water solutions by dissolving different amounts of table salt in containers of water (e.g. 100g, 200g, 300g of salt (NaCl) per liter). You can make solutions of food coloring by adding a few drops of each color into containers of  

The Eggsperiment with Vinegar solution. The first experiment conducted was the egg placed in vinegar solution which allowed the egg to become soft and bouncy . Vinegar is a weak acid which is 5% acetic acid in water (meaning vinegar is largely just water). The egg has a shell that is made up of calcium carbonate   an air cell forms at the large end of the egg. While the embryo is growing, the shell membranes surround and contain the white or albumen of the egg. The albumen provides the liquid medium in which the embryo develops, and it also contains a large amount of the protein necessary for proper development. I hope this was hopeful

The molar specific heat, Cv, of a gas in which each molecule has degrees of freedom γ is  \(C_v= (s*r)/2 J/mol*K\)

The molar heat capacity of a chemical substance is the quantum of energy that must be added, in the form of heat, to one operative of the substance in order to beget an increase of one unit in its temperature.

Alternately, it's the heat capacity of a sample of the substance divided by the quantum of substance of the sample; or also the specific heat capacity of the substance times its molar mass. The SI unit of molar heat capacity is joule per kelvin per operative, JK⁻¹

The largest number of logically independent values—that is, values with the freedom to change—in the data sample is referred to as the degree of freedom. If there is a remaining requirement for the data sample, particular data sample items must be picked after the degrees of freedom quantity has been decided.

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Complete question:

Thermodynamics deals with the macroscopic properties ofmaterials. Scientists can make quantitative predictions about thesemacroscopic properties by thinking on a microscopic scale. Kinetictheory and statistical mechanics provide a way to relate molecularmodels to thermodynamics. Predicting the heat capacities of gasesat a constant volume from the number of degrees of freedom of a gasmolecule is one example of the predictive power of molecularmodels.

The molar specific heatC_vof a gas at a constant volume is thequantity of energy required to raise the temperatureTof one mole of gas by one degree while thevolume remains the same. Mathematically,

\(C_{\rm v}= \frac{1}{n}\,\frac{dU}{dT},\)

wherenis the number of moles of gas,dUis the change in internal energy, anddTis the change in temperature.

Kinetic theory tells us that the temperature of a gas isdirectly proportional to the total kinetic energy of the moleculesin the gas. The equipartition theorem says that each degree offreedom of a molecule has an average kinetic energy equal to\(\frac{1}{2}k_}{\rm BT\),  wherek_Bis Boltzmann's constant\(1.38 \times 10^{-23} \rm {J/K}\) . Whensummed over the entire gas, this gives\(\frac{1}{2}nR\)T, where \(R=8.314\; {\rm \frac{J}{mol\cdot K}}\) is the ideal gas constant, for each molecular degree offreedom.

Part A

Using the equipartition theorem, determine the molar specific heat,C_v, of a gas in which eachmolecule hassdegrees of freedom.

Express your answer in terms ofRands.

Part B

Given the molar specific heatC_vof a gas at constant volume, you candetermine the number of degrees of freedomsthat are energetically accessible.

For example, at room temperature cis-2-butene,\rm C_4 H_8, has molar specific heat \(C_v=70.6\;{\rm \frac{J}{mol \cdot K}\)}. How many degrees of freedom of cis-2-butene areenergetically accessible?

Express your answer numerically to the nearest integer.

(A)1s22p63s23p6  Gases classified as inert are those that do not react with any other substances or elements due to their stability

Inert gases don't participate in the combustion process and don't interact with other substances A room or small area filled with an inert gas will have less oxygen which will slow the fire's ability to burn. In order to prevent water damage inert gases are employed in extinguishing systems in places like rooms containing electrical equipment. Depending on the parameters taken into consideration different categorization schemes for dangerous gases may be considered Here two concepts chemical and toxicological classifications are utilised The nature of the components that make up gases, such as carbon nitrogen, sulphur phosphorus halogen compounds and halogenated compounds, etc is generally used to classify chemicals Chemical categorization of toxins

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(A)1s22p63s23p6  Gases classified as inert are those that do not react with any other substances or elements due to their stability

Inert gases don't participate in the combustion process and don't interact with other substances A room or small area filled with inert gas will have less oxygen which will slow the fire's ability to burn. In order to prevent water damage inert gases are employed in extinguishing systems in places like rooms containing electrical equipment. Depending on the parameters taken into consideration different categorization schemes for dangerous gases may be considered Here two concepts chemical and toxicological classifications are utilized The nature of the components that make up gases, such as carbon-nitrogen, sulfur phosphorus halogen compounds and halogenated compounds, etc is generally used to classify chemicals Chemical categorization of toxins

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Answer:

a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.

Explanation:

Answer:

0.0135 dg

Explanation:

Answer: 0.0135 dg

Explanation:

(Can I have Brainlist)?

Answer:

2C4H10 + 13O2 —> 8CO2 + 10H2O. Oxidation reaction

8 (4 moles CO2 per mole butane)

Explanation:

could be written C4H10 + 6 1/2 O2 —> 4CO2 + 5H2O

Answer: The crust and the upper layer of the mantle together make up a zone of rigid, brittle rock called the Lithosphere . The layer below the rigid lithosphere is a zone of asphalt-like consistancy called the Asthenosphere . The asthenosphere is the part of the mantle that flows and moves the plates of the Earth.

Explanation:

Answer: I think oxygen is the most abundant element on earth crust.

Answer:

oxygen

Explanation:

We use prefixes in ionic compounds Don't use numeric prefixes like mono, di, tri, etc. when naming ionic compounds - they are used only to denote covalent molecular compounds.

Being a higher order consumer than a primary consumer is less efficient because approximately 50% of the energy in food (and maybe as much as 90%) is lost when a creature consumes it at each trophic level.

The flow of nutrients and energy through an ecosystem is described by a food chain. Energy is first produced by plants at the most fundamental level, and then it is used by higher-level species like herbivores.

90% of an organism's energy is typically required for its vital functions, whereas just 10% is transferred to its trophic level-up predator.

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